g You and your friend both send documents to the printer, but the printer can only print one document at a time. What does it do with the other document

Answers

Answer 1

Answer:

It places the document in a buffer

Explanation:

Since the printer can only print a document at a time, the other document is going to be placed in a buffer.

The print buffer can be described as a location in memory that has the function of holding data that is going to be sent to a computers printer. A print job such as in this scenario may remain in the buffer because another document is to be printed first.

Sometimes a document could be put in the buffer because the computer is waiting for the printer to respond. This is just another reason why documents are placed in a buffer.


Related Questions

Which best explains the workplaces of employees in the Energy career cluster?

Employees work outdoors.
Employees can work in a wide variety of places.
Employees can work in a limited number of places.
Employees work indoors.

Answers

Answer: It’s Letter (B) the other ones just don’t fit.

Explanation:

Mark me as brainlest please?!!

Answer:

b

Explanation:

Vector testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit.

Answers

Question:

Vector testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit. Ex: If testGrades = {101, 83, 107, 90}, then sumExtra = 8, because 1 + 0 + 7 + 0 is 8.

#include <iostream>

#include <vector>

using namespace std;  

int main() {

  const int NUM_VALS = 4;

  vector<int> testGrades(NUM_VALS);

  int i = 0;

  int sumExtra = -9999; // Assign sumExtra with 0 before your for loop  

  testGrades.at(0) = 101;

  testGrades.at(1) = 83;

  testGrades.at(2) = 107;

  testGrades.at(3) = 90;

   /* Your solution goes here  */

  cout << "sumExtra: " << sumExtra << endl;

  return 0;

}

Answer:

Replace /* Your solution goes here  */  with the following lines of code

sumExtra = 0;

do{

if(testGrades.at(i) > 100){

sumExtra = sumExtra + (testGrades.at(i) - 100);

}

i++;

}

while(i<NUM_VALS);

Explanation:

In the complete question posted,  the variables sumExtra and i have already been declared an initialized.

So, the first thing we do in the solution is:

set  sumExtra to 0 using sumExtra = 0;

Then iterate through vector testGrades using i as the iterating variable

Here, I made used of a do while loop and the explanation is as follows:

do{

This line checks if current element of the vector is greater than 100

if(testGrades.at(i) > 100){

If yes, the extra digits above 100 is added to the sumExtra

sumExtra = sumExtra + (testGrades.at(i) - 100);

}

The counter is increased, here

i++;

}

The loop is continued while the iterating variable i is less than NUM_VALS which is 4

while(i<NUM_VALS);

Allison is writing a program in Java and keeps getting an error. Which line of code is causing the error?

A. Int a = 0, b = 3, c;
B. for(i = 0, i <= 13, i++) {
C. c = (a * 2) + i;
D. System.out.println(c);

}

Answers

B will cause an error.

Allison needs to declare a type for variable i and use semi-colons.

The for statement should be for(int i = 0; i <=13; i++){

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