g Suppose you're on a hot air balloon ride, carrying a buzzer that emits a sound of frequency f. If you accidentally drop the buzzer over the side while the balloon is rising at constant speed, what can you conclude about the sound you hear as the buzzer falls toward the ground

Answers

Answer 1

Answer:

the observed frequency will reduce but the wavelength will increase

Explanation:

As we know

fo = fs (v/(v-vs))

fo = observed frequency

vs = velocity of source

As per this equation,  

When an observer moves away from the stationary source, the observed frequency reduces. Since the observer in the balloon is moving away from the source which itself is moving in opposite direction, the observed frequency will reduce.  

Since wavelength = V/fs . The source frequency is unchanged but the velocity is increasing as it is moving in downward direction. Hence, the wavelength will increase


Related Questions

please help, im having trouble can you please explain how to do it

Answers

Answer:

independent and the second one with the (-8, 1, -3)

using the image provided, which moon phase is next?

Answers

Answer:

Waning Crescent

Answer: waxing crescent

Explanation:

whats is the purpose of the

(1) Armature winding

(2) the commutator

(3) the fan ​

Answers

here's your correct answer.. please copy it..

a spring has a spring constant of 330 n/m. how far is the spring compressed when 150 newtons of force are used?
a. 0.0014 meters
b. 0.45 meters
c. 2.2 meters
d. 5.0 meters
show your work​

Answers

Answer:

I think its B

Explanation:

what is the value of 3 in
24.635​

Answers

Answer:

3 tens

Explanation:

The value

of 3 in 24.635 is at 3 tens place as the place is two to the left.

The correct answer to the given is question is "0.03".

What is Place Value?The value of each digit in a number is known as place value.For example the 2 in 125 represent 2 tens or 20, however the 2 in 2103 represent 2 thousands or 2000.Frequently, they will only include the letters like Millions, Hundred Thousands, Ten Thousands, Thousands, Hundreds, Tens, Ones, tenths, hundredths, and so on to denote each place.

How to solve this question?

Let's display the number 24.635 using a place value chart.

Tens -> 2   Ones -> 4   Tenth -> 6   Hundredths -> 3   Thousandths -> 5

The 3 is in Hundredths Place or the value of 3 in 24.635​ is 0.03.

Thus, we can conclude that the value of 3 in 24.635​ is 0.03 after solving the question.

Learn more about Place Value here:

https://brainly.com/question/569339

#SPJ2

Solve the following problem. A force of 5N is being applied to the right, and a force of
3N is being applied to the left. What is the net force?

A- 15 N
B- 8 N
C- 7N
D- 2N

Answers

Answer:

D 2N

Explanation:

these are opposite forces so one becomes negative and the other positive that is

-3+5=2 or 5-3=2

A 1 kg flashlight is dropped from rest and falls to the floor without air resistance . At the point during its fall, when it is 0.7 meters above the floor, its potential energy exactly equals its kinetic energy. How fast is the flashlight moving at this point, in m/s 3.7

Answers

Answer:

The speed of the flashlight at that point is 3.7 m/s

Explanation:

When an object of mass M is at a height H above the ground, the potential energy of the object is:

U = M*H*g

Where g is the gravitational acceleration, g = 9.8 m/s^2

And for an object with velocity v, the kinetic energy is:

K = (M/2)*v^2

We know that when the flashlight of mass  1kg is 0.7 meters above the ground, the potential energy is equal to the kinetic energy, then:

M = 1kg

H = 0.7m

g = 9.8 m/s^2

Replacing these in the equations, we get:

U = K

(1kg)*(0.7m)*(9.8 m/s^2) = ((1kg)/2)*v^2

As the mass factor appears in both sides, we can remove it:

(0.7 m)*(9.8 m/s^2) = (v^2)/2

Now we can multiply both sides by 2:

2*(0.7 m)*(9.8 m/s^2) = v^2

Now let's apply the square root to both sides:

√(2*(0.7 m)*(9.8 m/s^2)) = v = 3.7 m/s

g hoop rolls without slipping on a horizontal surface. The hoop has a mass m and radius r. What is the ratio of the hoop's translational kinetic energy to the hoop's rotational kinetic energy, KT /KR

Answers

Answer:

[tex]\frac{K.E_t}{K.E_r} = 1[/tex]

Explanation:

The translational kinetic energy of the hoop is given as:

[tex]K.E_t = \frac{1}{2} mv^2[/tex]      ---------------------- equation (1)

where,

[tex]K.E_t[/tex] = translational kinetic energy

m = mass of hoop

v = linear speed of hoop

The rotational kinetic energy of the hoop is given as:

[tex]K.E_r = \frac{1}{2} I\omega^2[/tex]

where,

[tex]K.E_r[/tex] = rotational kinetic energy of the hoop

I = Moment of Inertia of the hoop = mr²

r = radius of the hoop

ω = angular speed of hoop = [tex]\frac{v}{r}[/tex]

Therefore,

[tex]K.E_r = \frac{1}{2} (mr^2)(\frac{v}{r} )^2\\\\K.E_r = \frac{1}{2} mv^2[/tex]------------------- equation (2)

dividing equation (1) and equation (2), we get:

[tex]\frac{K.E_t}{K.E_r} = \frac{\frac{1}{2}mv^2 }{\frac{1}{2}mv^2 }\\\\\frac{K.E_t}{K.E_r} = 1[/tex]

An electrical appliance draws 9.0 amperes of current when connected to a 120-volt
source of potential difference. What is the total amount of power dissipated by this
appliance?
1100 W
110 W
13 W
130 W

Answers

Answer:

The correct answer is "1080 W".

Explanation:

Given:

Current,

I = 9.0 A

Potential difference,

V = 120 volt

As we know,

⇒ [tex]Power=IV[/tex]

On substituting the values, we get

⇒             [tex]=120\times 9.0[/tex]

⇒             [tex]=1080 \ W[/tex]

A parallel beam of light of wavelength 4.5 x 10^-7 m is incident on a pair of slits that are 5.0 x 10^-4 m apart. The interference pattern is focused on a screen 2.0 m from the slits. The separation between two adjacent bright fringes is most nearly:_________

Answers

Answer:

1.8x10⁻³m

Explanation:

From the question above, the following information was used to solve the problem.

wavelength λ = 4.5x10⁻⁷m

Length L = 2.0 meters

distance d = 5 x 10₋⁴m

ΔY = λL/d

= 4.5x10⁻⁷m (2) / 5 x 10₋⁴m

= 0.00000045 / 0.0005

= 0.0000009/0.0005

= 0.0018

= 1.8x10⁻³m

from the solution above The separation between two adjacent bright fringes is most nearly 1.8x10⁻³m

thank you!

A golf club rotates 215 degrees and has a length (radius) equal to 29 inches. The time it took to swing the club was 0.8 seconds. What is the average linear velocity (inches/second) of the golf club

Answers

Answer:

The average linear velocity (inches/second) of the golf club is 136.01 inches/second

Explanation:

Given;

length of the club, L = 29 inches

rotation angle, θ = 215⁰

time of motion, t = 0.8 s

The angular speed of the club is calculated as follows;

[tex]\omega = (\frac{\theta}{360} \times 2\pi, \ rad) \times \frac{1}{t} \\\\\omega = (\frac{215}{360} \times 2\pi, \ rad) \times \frac{1}{0.8 \ s} \\\\\omega = 4.69 \ rad/s[/tex]

The average linear velocity (inches/second) of the golf club is calculated as;

v = ωr

v = 4.69 rad/s  x  29 inches

v = 136.01 inches/second

Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second

Light with a single wavelength falls on two slits separated by 0.510 mm. In the resulting interference pattern on a screen 2.24 m away, adjacent bright fringes are separated by 2.88 mm.What is the wavelength of the light that falls on the slits

Answers

Answer: 655.7 nm

Explanation:

Given

The slits are separated by [tex]d=0.510\ mm[/tex]

Distance between slits and screen is [tex]D=2.24\ m[/tex]

Adjacent bright fringes are [tex]\beta =2.88\ mm[/tex] apart

Also, the distance between bright fringes is given by  

[tex]\Rightarrow \beta =\dfrac{\lambda D}{d}\quad [\lambda=\text{Wavelength of light}]\\\\\text{Insert the values}\\\\\Rightarrow 2.88\times 10^{-3}=\dfrac{\lambda \cdot 2.24}{0.510\times 10^{-3}}\\\\\Rightarrow \lambda =\dfrac{2.88\times 10^{-3}\times 0.510\times 10^{-3}}{2.24}\\\\\Rightarrow \lambda =0.6557\times 10^{-6}\ m\\\Rightarrow \lambda =655.7\ nm[/tex]

During an auto accident, the vehicle's air bags deploy and slow down the passengers more gently than if they had hit the windshield or steering wheel. According to safety standards, the bags produce a maximum acceleration of 60g, but lasting for only 32 ms (or less). How far does a person travel in coming to a complete stop in 32 ms at a constant acceleration of 60g

Answers

Answer:

s = 0.3 m

Explanation:

In order to calculate the distance traveled by the person, we will use the second equation of motion:

[tex]s = v_it + \frac{1}{2}at^2[/tex]

where,

s = distance traveled = ?

vi = initial speed = 0 m/s

t = time = 32 ms = 0.032 s

a = acceleration = 60g = (60)(9.81 m/s²) = 588.6 m/s²

Therefore,

[tex]s = (0\ m/s)(0.032\ s)+\frac{1}{2}(588.6\ m/s^2)(0.032\ s)^2[/tex]

s = 0.3 m

state Newton's first law of motion in words

Answers

Answer:

An unmoving object will remain unmoving and a moving object in motion will continue to be in motion with the same velocity unless an external force acts upon it.

2. A force of magnitude 44 N compresses a spring 0.69 m from equilibrium. What is the value of the spring constant?
60 N/m
64 N/m
32 N/m
49 N/m

Answers

Answer:

Spring constant = 63.77 N/m

Explanation:

Given the following data;

Force = 44 N

Extension = 0.69 m

To find the spring constant;

Force = spring constant * extension

Substituting into the formula, we have;

44 = spring constant * 0.69

Spring constant = 44/0.69

Spring constant = 63.77 N/m

The temperature of a body is from 200 to 300C.The change of temp at absolute scale is

Answers

Answer:

mark me brainliest

Explanation:

The change of temperature at absolute scale is. A. 3.73 K

Answer:

373K

Explanation:

300°c - 200°c =100°c

Absolute scale means Kelvin scale so

0°c= 273°c

100°c = 100 + 273

=373K

Select the correct answer. A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds of its travel. What is its average speed during the time from t = 5 seconds to t = 10 seconds? A. 2 meters/second B. 3 meters/second C. 4 meters/second D. 5 meters/second E. 6 meters/second

Answers

Answer:

2 m/s

Explanation:

...........................

Answer:

A:2 m/s

Explanation:

Plato

En una carga de prueba de 2 microcoulomb se sitúa en un punto en el que la intensidad del campo eléctrico es de 5 * 10 / 2 N/C cuál es la fuerza de la magnitud que actúa sobre ella?

Answers

Answer:

Fuerza, F = 0.001 Newton

Explanation:

Dados los siguientes datos;

Intensidad del campo eléctrico = 5 * 10² N/C

Carga = 2 microculombios = 2 * 10^{-6} culombios

Para encontrar la fuerza que actúa sobre la carga;

Matemáticamente, la intensidad del campo eléctrico viene dada por la fórmula;

Intensidad del campo eléctrico = fuerza/carga

F = E * Q

F = 5 * 10² * 2 * 10^{-6}

Fuerza, F = 0.001 Newton

g A meteoroid is in a circular orbit 600 km above the surface of a distant planet. The planet has the same mass as Earth but has a radius that is 90 % of Earth's (where Earth's radius is approximately 6370 km ). What is the gravitational acceleration of the meteoroid

Answers

Answer:

Explanation:

gravitational acceleration of meteoroid

=  GM / R²

M is mass of planet , R is radius of orbit of meteoroid from the Centre of the planet .

R = (.9 x 6370 + 600 )x 10³ m

= 6333 x 10³ m

M , mass of the planet = 5.97 x 10²⁴ kg .

gravitational acceleration of meteoroid

=  GM / R²

=  (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ kg  / (6333 x 10³ m)²

9.92m/s²

Question 15 of 25
You feel warm sitting next to a bright light. Which type of heat transfer are
Experiencing?

Answers

Answer: conduction :it transfers heat between objects that are in direct contact with eachother

Answer:

radiation

Explanation:

PLEASE HELP I WILL MARK BRAINLYIST!!!!!!!!!
All of the matter in the universe formed after the big bang. Scientists
predicted that hydrogen and helium would be the most abundant elements.
What did scientists discover?
A. The universe has 73% hydrogen and 25% helium, which does not
support the big bang theory
B. Planets are made mostly of other elements, which does not
support the big bang theory
C. Stars are made mostly of other elements, which supports the big
bang theory
D. The universe has 74% hydrogen and 24% helium, which supports
the big bang theory.

Answers

Answer:

The answer is D. Here is proof . Plz mark brainliest

Explanation:

A current of 5 a flows in a copper wire for 20 s. how many coulombs of charge passed through the wire in this time?

Answers

Answer:

I think so too

Explanation:

:*

Monochromatic light with wavelength 633 nn passes through a narrow slit and a patternappears on a screen 6.0 m away. The distance on the screen between the centers of thefirst minima on either side of the screen is 32 mm. How wide (in mm) is the slit

Answers

Answer:

Explanation:

screen distance D = 6 m .

wavelength of light λ = 633 nm.

slit width = d .

Distance between first minima on either side is width of central maxima

= 2 x λD /d

Given

32 x 10⁻³ = 2 x λD /d

d = 2 x λD /32 x 10⁻³

= 2 x 633 x 10⁻⁹ x 6 / 32 x 10⁻³

= 237.37 x 10⁻⁶ m

= .23737 x 10⁻³ m

= .24 mm .

A boy stands between two vertical walls and fires a rifle. Under what condition will he hear a single echo from both walls? Calculate the distance between the walls if the single echo is heard six seconds later.​

Answers

Answer:

d = 1,029 m

Explanation:

When the young man shoots the rifle the sound travels in all directions, if the young man is at the same distance from the two walls, as the speed of the wave is constant, he takes the same time to go to the wall and return for which he hears a single echo.

To calculate the distance let's use the uniform motion relationships

        v = d / t

        d = v t

As the speed is constant, the time to reach the wall is the same as it takes to go from the wall to the young man,

         t = to / 2

         t = 6/2

         t = 3 s

         d = 343 3

         d = 1,029 m

Which of the following statements about asexual reproduction is NOT true? A Only one parent sex cell is needed. B The offspring are copies of the parent. C Most single-celled organisms reproduce this way. Dit results in more variation in species than does sexual reproduction

Answers

Answer:

D

Explanation:

D is false because asexual reproduction produces offspring much more similar to the parent than that produced in sexual reproduction.

In a double-slit experiment, the third-order maximum for light of wavelength 510 nm is located 17 mm from the central bright spot on a screen 1.6 m from the slits. Light of wavelength 670 nm is then projected through the same slits. Part A How far from the central bright spot will the second-order maximum of this light be located

Answers

Answer:

14.9 mm

Explanation:

We know dsinθ = mλ where d = separating of slit, m = order of maximum = 3 and λ = wavelength = 510nm = 510 × 10⁻⁹ m

Also tanθ = L/D where L = distance of m order fringe from central bright spot = 17 mm = 0.017 m and D = distance of screen from slit = 1.6 m

So, sinθ = mλ/d

Since θ is small, sinθ ≅ tanθ

So,

mλ/d = L/D

d = mλD/L

Substituting the values of the variables into the equation, we have

d = 3 × 510 × 10⁻⁹ m × 1.6 m/0.017 m

d = 2448 × 10⁻⁹ m²/0.017 m

d = 144000 × 10⁻⁹ m

d = 1.44 × 10⁻⁴ m

d = 0.144 × 10⁻³ m

d = 0.144 mm

Now, for the second-order maximum, m' of the 670 nm wavelength of light,

m'λ'/d = L'/D where m' = order of maximum = 2, λ' = wavelength of light = 670 nm = 670 × 10⁻⁹ m, d = slit separation = 0.144 mm = 0.144 × 10⁻³ m, L' = distance of second order maximum from central bright spot and D = distance of screen from slit = 1.6m

So, L' = m'λ'D/d

So, substituting the values of the variables into the equation, we have

L' = 2 × 670 × 10⁻⁹ m × 1.6 m/0.144 × 10⁻³ m

L' = 2144  × 10⁻⁹ m²/0.144 × 10⁻³ m

L' = 14888.89 × 10⁻⁶ m

L' = 0.01488 m

L' ≅ 0.0149 m

L' = 14.9 mm

The power output of a car engine running at 2500 rpm is 500 kW . You may want to review (Pages 574 - 577) . Part A How much work is done per cycle if the engine's thermal efficiency is 20.0 %

Answers

Answer:

Explanation:

2500 rpm = 2500 / 60 rps ( revolution per second )

= 41.67 rps .

power output = 500 kW

thermal efficiency = 20 %

power input = (100 /20) x 500 kW

= 2500 kW .

work done per second = 2500 kJ

work done per cycle = 2500 / 41.67

= 60 kJ .

We have that the  workdone per cycle is mathematically given as

Wc=12.00KJ

 Workdone per cycle of engine

Question Parameters:

The power output of a car engine running at 2500 rpm is 500 kW

Generally the work done per cycle  is mathematically given as

Wc=500*1/41.666

Where

=2500rev/60sec

=41.666

Meaning one cycle takes 1/41.666

Hence

Wc=500*1/41.666

Wc=12.00KJ

For more information on work

https://brainly.com/question/756198

b. Why are the resources listed in part (a) considered "renewable"?

Answers

Answer:

I would need to see the part a to be more specific but this may help:

resources like solar, water, wind are considered renewable because they will never run out, they can be replenished over and over again. There will always be a sun (and if there wasn't then we'd have bigger conserns than renewable energy) and the wind will always blow. It can never run out because you use too much unlike coal and fossil fuels.

Hope this helps!

Which of the following phase changes occurs at point B on the phase diagram shown below? (choose all that apply)
solid
liquid

gas
T
melting
sublimating
boiling
condensing

Answers

Answer:

Condensation and Melting

Explanation:

Gas to liquid = Condensation

Solid to liquid = Melting

If two connected points objects pass through the same set of three points, the shapes created by each will be identical, regardless of the order in which each object was plotted. True False

Answers

Answer:

True

Explanation:

It Depends on the order in which each object was plotted, if two connected points objects pass through the same set of three points, the shapes created by each point may be different

Other Questions
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