f(x) = x^2 + x − 6 Determine the x-intercepts and the y-intercept. And can you please explain how you got your answer

Answer:

page 10

Step-by-step explanation:

10+11+12+13+14+15=75

1: The question asks for the first and last names of everyone in your group, including yourself. You can tell any group or personal identity.

2: The question involves solving the initial value problem (IVP) dy/dx = cos(x + y), y(0) = π/4 using an appropriate substitution. The steps include substituting u = x + y, differentiating u with respect to x, substituting the values into the differential equation, separating the variables, integrating both sides, and finally obtaining the solution y = C / (μ sin(x)), where C is the constant of integration.

3: The question asks to solve the differential equation cos(x) dx + (1 + 1/y) sin(x) dy = 0 by finding an appropriate integrating factor. The steps include determining the coefficients, multiplying the equation by the integrating factor, recognizing the resulting exact differential form, integrating both sides, and solving for y to obtain the solution y = C / (μ(x) sin(x)), where C is the constant of integration.

2. Let's consider the name " X" for the purpose of clarity in referring to the question.

For Question X:

X: Solve the differential equation cos(x) dx + (1 + 1/y) sin(x) dy = 0 by finding an appropriate integrating factor.

i. Identify the coefficients of dx and dy in the given differential equation. Here, cos(x) and (1 + 1/y) sin(x) are the coefficients.

ii. Compute the integrating factor (IF) by multiplying the entire equation by an appropriate function μ(x) that makes the coefficients exact. In this case, μ(x) = [tex]e^\int\limits^a_b \ (1/y) sin(x) dx.[/tex]

iii. Multiply the differential equation by the integrating factor:

μ(x) cos(x) dx + μ(x) (1 + 1/y) sin(x) dy = 0.

iv. Observe that the left-hand side is now the exact differential of μ(x) sin(x) y. Therefore, we can write:

d(μ(x) sin(x) y) = 0.

v. Integrate both sides of the equation:

∫d(μ(x) sin(x) y) = ∫0 dx.

This simplifies to:

μ(x) sin(x) y = C,

where C is the constant of integration.

vi. Solve for y by dividing both sides of the equation by μ(x) sin(x):

y = C / (μ(x) sin(x)).

Hence, the solution to the given differential equation cos(x) dx + (1 + 1/y) sin(x) dy = 0 using the integrating factor method is y = C / (μ(x) sin(x)).

3. Solve the IVP using an appropriate substitution: dy/dx = cos(x + y), y(0) = π/4

i. Substitute u = x + y. Differentiate u with respect to x: du/dx = 1 + dy/dx.

ii. Substitute the values into the given differential equation: 1 + dy/dx = cos(u).

iii. Rearrange the equation: dy/dx = cos(u) - 1.

iv. Separate the variables: (1/(cos(u) - 1)) dy = dx.

v. Integrate both sides: ∫(1/(cos(u) - 1)) dy = ∫dx.

vi. Use the substitution v = tan(u/2): ∫(1/(cos(u) - 1)) dy = ∫dv.

vii. Integrate both sides: v = x + C.

viii. Substitute u = x + y back into the equation: tan((x + y)/2) = x + C.

Therefore, the solution to the IVP dy/dx = cos(x + y), y(0) = π/4 using the appropriate substitution is tan((x + y)/2) = x + C.

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The given system of equations is inconsistent and has no solution.

To solve the system of equations using augmented matrix methods, we can represent the system in matrix form as:

[tex]\left[\begin{array}{cc}1&2\\2&4\end{array}\right][/tex]  [tex]\left[\begin{array}{ccc}x_1\\x_2\end{array}\right][/tex]  = [tex]\left[\begin{array}{ccc}-4\\8\end{array}\right][/tex]

Augmented Matrix

We can write the augmented matrix as:

[tex]\left[\begin{array}{cc|c}1&2&4\\2&4&-8\end{array}\right][/tex]

Row Operations

We'll perform row operations to transform the augmented matrix into row-echelon form or reduced row-echelon form.

R2 = R2 - 2R1 (Multiply the first row by -2 and add it to the second row)

[tex]\left[\begin{array}{cc|c}1&2&4\\0&0&-16\end{array}\right][/tex]

Interpret the Result

From the row-echelon form of the augmented matrix, we can see that the second equation simplifies to 0 = -16, which is not a valid equation.

This implies that the system of equations is inconsistent and has no solution.

Therefore, the given system of equations:

x₁ + 2x₂ = 4

2x₁ + 4x₂ = -8

has no solution.

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The sample space for a roll of a 5-sided die is {1, 2, 3, 4, 5}.

In probability theory, the sample space refers to the set of all possible outcomes of an experiment. In this case, we are rolling a 5-sided die, which means there are 5 possible outcomes. The outcomes are represented by the numbers 1, 2, 3, 4, and 5, as these are the numbers that can appear on the faces of the die. Thus, the sample space for this experiment can be expressed as {1, 2, 3, 4, 5}.

It is important to note that each outcome in the sample space is mutually exclusive, meaning that only one outcome can occur on a single roll of the die. Additionally, the outcomes are collectively exhaustive, as they encompass all the possible results of the experiment. By identifying the sample space, we can analyze and calculate probabilities associated with different events or combinations of outcomes.

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It is not possible to find 7 odd numbers that add up to exactly 30 without involving decimals.

The sum of 7 odd numbers will always result in an odd number. However, 30 is an even number.

Therefore, it is not possible to find a combination of 7 odd numbers that adds up to 30 without introducing decimals or fractions.

If we consider the sum of 7 odd numbers, the resulting sum will be an odd number due to the odd number of odd terms being added.

In this case, the sum of the 7 odd numbers will always be greater or less than 30, but never equal to it.

Therefore, there is no solution involving 7 odd numbers that add up to exactly 30 without decimals or fractions.

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The fourier series is bn = (2/π) ∫[0,π] x sin(nπx/π) dx.

To sketch the odd periodic extension of the function f(x)=x with period 2π on the interval [0,π], we can first extend the function f(x) to the entire x-axis. The odd periodic extension of a function means that the extended function is odd, which means it has symmetry about the origin.
Since f(x)=x is already defined on the interval [0,π], we can extend it to the interval [-π,0] by reflecting it across the y-axis. This means that for x values in the interval [-π,0], the value of the extended function will be -x.
To extend the function to the entire x-axis, we can repeat this reflection for each interval of length 2π. For example, for x values in the interval [π,2π], the value of the extended function will be -x.
By continuing this reflection for all intervals of length 2π, we obtain the odd periodic extension of f(x)=x.
Now, let's consider the Fourier series of the odd periodic extension of f(x)=x with period 2π. The Fourier series represents the periodic function as a sum of sine and cosine functions.

For an odd function, the Fourier series consists of only sine terms, and the coefficients can be calculated using the formula:
bn = (2/π) ∫[0,π] f(x) sin(nπx/π) dx

In this case, the function f(x)=x on the interval [0,π] is odd, so we only need to calculate the bn coefficients.
Using the formula, we can calculate the bn coefficients:
bn = (2/π) ∫[0,π] x sin(nπx/π) dx

To find the integral, we can use integration by parts or tables of integrals.
Let's take n = 1 as an example:
b1 = (2/π) ∫[0,π] x sin(πx/π) dx
  = (2/π) ∫[0,π] x sin(x) dx
Using integration by parts, where u = x and dv = sin(x) dx, we can find the integral of x sin(x) dx.
After evaluating the integral, we can substitute the values of bn into the Fourier series formula to obtain the Fourier series of the odd periodic extension of f(x)=x with period 2π.

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im beginning to doubt that some of you guys are even in high school.

anyways,

each point or location on this plane (the whole grid thingy) has a coordinate. each coordinate is (x, y) or (units to the right, units going up)

our point T is on the coordinate (-1,-4)

'translated 4 units down' means that you take that whole triangle and move it down four times.

so our 'units going up' (the y in our coordinate) moves down 4 times.

(-4) - 4 = (-8)

the x coordinate is not affected so our answer is (-1, -8)

woohoo

None of the expressions 4d8, 4d³, 4³d8, 4d³, or 34d8 can be considered as a radical expression.

The correct answer is option F.

To determine the radical expression of the given options, let's analyze each expression:

1. 4d8: This expression does not contain any radical sign (√), so it is not a radical expression.

2. 4d³: This expression also does not contain a radical sign, so it is not a radical expression.

3. 4³d8: This expression consists of a number (4) raised to the power of 3 (cubed), followed by the variable d and the number 8. It does not involve any radical operations.

4. 4d³: Similar to the previous expressions, this expression does not include any radical sign. It represents the product of the number 4 and the variable d raised to the power of 3.

5. 34d8: Again, this expression does not involve a radical sign and represents the product of the numbers 34, d, and 8.

None of the given options represents a radical expression. A radical expression typically includes a radical sign (√) and a radicand (the expression inside the radical). Since none of the given options meet this criterion, we cannot identify a specific radical expression from the options provided.

Therefore, the option F is the correct choice as none of the following is an example of radical expression

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The question probable may be:

Which of the following is the radical expression of

A. 4d8

B. 4d³

C. 4³d8

D. 4d³

E. 34d8

F. None of the above

The LU-decomposition of the matrix A is L = [1 0; 5 1] and U = [19 0; -3 1].

The given problem involves finding the LU-decomposition of a matrix A and solving the equation Ax = b.

In the LU-decomposition process, the matrix A is decomposed into the product of two matrices, L and U, where L is a lower triangular matrix and U is an upper triangular matrix.

This decomposition allows for easier solving of linear systems of equations. Once the LU-decomposition of A is obtained, the equation Ax = b can be solved by first solving the system Ly = b for y using forward substitution, and then solving the system Ux = y for x using back substitution.

By performing these steps, the solution to the equation Ax = b can be determined.

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In the equation -1x³ + kx + 25 = 0, if 5 , Therefore, the value of k is 20.

substituting x = 5 into the equation should make it true.

To find the value of k, we can use the fact that if 5 is one of the roots of the equation, then substituting x = 5 into the equation should make it true.

Substituting x = 5 into the equation, we have:

-1(5)³ + k(5) + 25 = 0

Simplifying further:

-125 + 5k + 25 = 0

5k - 100 = 0

5k = 100

k = 20

Therefore, the value of k is 20.

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The name given to this type of design is a factorial design. A factorial design is a design in which researchers investigate the effects of two or more independent variables on a dependent variable.

In this study, two independent variables were used: room color (yellow, blue) and room temperature (20, 24, 28 degrees Celsius), while the dependent variable was happiness.

Each level of each independent variable was tested in conjunction with each level of the other independent variable. There are a total of six experimental conditions (two colors × three temperatures = six conditions), and twenty students were randomly assigned to each of the six conditions.

The researcher then examined how each independent variable and how the interaction of the two independent variables affected the dependent variable (happiness). Therefore, this study is an example of a 2 x 3 factorial design.

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The statement "The segment from the center of a square to the corner cannot be called the 'radius' of the square" is false.

The term "radius" is commonly used in the context of circles and spheres, not squares. In geometry, the radius refers to the distance from the center of a circle or a sphere to any point on its boundary. It is a measure of the length between the center and any point on the perimeter of the circle or sphere.

In the case of a square, the equivalent term for the segment from the center to the corner is called the "diagonal." The diagonal of a square is the line segment that connects two opposite corners of the square, passing through its center. It is twice the length of the side of the square.

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185 said they like dogs, 170 said they like cats, 86 said they liked both cats and dogs, and 74 said they don't like cats or dogs. The number of people who were surveyed is 515.

The number of people who were surveyed can be found by adding the number of people who liked dogs, the number of people who liked cats, the number of people who liked both, and the number of people who did not like either. So, the total number of people surveyed can be found as follows:

Total number of people who like dogs = 185

Total number of people who like cats = 170

Total number of people who like both = 86

Total number of people who do not like cats or dogs = 74

The total number of people surveyed = Number of people who like dogs + Number of people who like cats + Number of people who like both + Number of people who do not like cats or dogs

= 185 + 170 + 86 + 74= 515

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The solution of v = (17 - b) / (a + 4)

1. Start with the given equation: av + 17 = -4v - b.

2. Move all terms containing v to one side of the equation: av + 4v = -17 - b.

3. Combine like terms: (a + 4)v = -17 - b.

4. Divide both sides of the equation by (a + 4) to solve for v: v = (-17 - b) / (a + 4).

5. Simplify the expression: v = (17 + (-b)) / (a + 4).

6. Rearrange the terms: v = (17 - b) / (a + 4).

Therefore, the solution for v is (17 - b) / (a + 4).

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The values of θ in degrees for the expression cosθ = -1 are 180° + 360°k, where k is an integer.

The unit circle is a circle with a radius of 1 centered at the origin of a coordinate plane. The cosine function represents the x-coordinate of a point on the unit circle. When the cosine value is -1, it means that the x-coordinate is -1.

In the unit circle, there is a point (-1, 0) on the x-axis that corresponds to an angle of 180° or π radians. This point satisfies the condition cosθ = -1.

Since the cosine function has a periodicity of 360° or 2π radians, we can add multiples of 360° to the angle to obtain other solutions. Therefore, the possible values for θ in degrees are 180° + 360°k, where k is an integer. This represents a full revolution around the unit circle starting from the point (-1, 0) and moving counterclockwise.

In conclusion, the values of θ in degrees for the expression cosθ = -1 are 180° + 360°k, where k is an integer.

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1. The minimum number of chickens you should purchase to be 95% confident you will have enough food for a night is 44 chickens

2. The probability of running out of food by the end of the night is approximately P(X > 40) ≈ 0.000000000007

To be 95% confident that you will have enough food for a night, you need to calculate the 95% confidence interval for the number of customers that will arrive.

The 95% confidence interval for the number of customers that will arrive is given by

CI = x ± zα/2 * σ/√n

where

x is the sample mean,

zα/2 is the critical value of the standard normal distribution for the desired confidence level (z0.025 = 1.96 for 95% confidence),

σ is the standard deviation of the Poisson distribution (σ = sqrt(λ) = sqrt(40) ≈ 6.325), and

n is the sample size.

Substitute the values

CI = 40 ± 1.96 * 6.325/√40 ≈ 40 ± 3.95

Thus, the minimum number of chickens you should purchase to be 95% confident you will have enough food for a night is 44 chickens.

If you have 10 chickens, the number of customers you can serve is limited to 40 (since each customer requires 4 chickens).

Therefore, the probability of running out of food by the end of the night is given by

P(X > 40) = 1 - P(X ≤ 40)

where X is the number of customers that arrive.

Using the Poisson distribution, we can calculate:

[tex]P(X \leq 40) = e^-\lambda* \sum(\lambda^k / k!)[/tex]

for k = 0, 1, 2, ..., 40.

P(X ≤ 40) = [tex]e^-40[/tex] * Σ([tex]40^k[/tex] / k!) ≈ 0.999999999993

Therefore, the probability of running out of food by the end of the night is approximately P(X > 40) ≈ 0.000000000007

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Question is incomplete, find the complete question below

Question 2 You are operating a Fried Chicken restaurant named "Chapman's Second Best Chicken and Waffles" In a given night you are open to customers from 5pm to 9pm When you are open, customers arrive at an average rate of 5 people every 30 minutes. Individuals are equally likely to arrive at any point in time, and previous arrivals do not impact the probability of additional arrivals. You can handle a maximum of 100 customers a night. On any given night, the amount that guests on average spend at your restaurant is uniformly distributed between $10 and $30 (to be clear, it is the overall average level of spending per guest which is uniformly distributed, not the spending of each individual guest) The distribution of spending per-person is statistically independent of the number of guests that arrive on a given night. 2.1 For every customer you need to purchase 4 chickens. What is the minimum amount of chickens should you purchase to be 95% confident you will have enough food for a night? (note, you can only purchase a whole number of chickens) 2.2 If you have 10 chickens, what is the probability that you will run out of food by the end of the night?

The diameter of the circle is approximately 8.2 inches.

To find the diameter of a circle given its area, we can use the formula:

A =π[tex]r^2[/tex]

where A represents the area of the circle and r represents the radius. In this case, we are given the area of the circle, which is 52 square inches.

We can rearrange the formula to solve for the radius:

r = √(A/π)

Plugging in the given area, we have r = √(52/π). To find the diameter, we double the radius:

diameter = 2r

               = 2 * √(52/π)

               = 2 * √(52/3.14159)

               = 8.231 inches.

Rounding to the nearest tenth, we get a diameter of approximately 8.2 inches.

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A)The first partial derivatives of w at (1, -1, 0) are ∂w/∂x = -e²0 = -1,∂w/∂y = 1 × e²0 = 1,∂w/∂z = 1 ²(-1) ×e²0 = -1

B)The directional derivative of w at (1, -1, 0) along direction function is v = i + 2j + 2k is -1/3.

C)The expression for ∂w/∂t, without simplification, is 2(s - 2t)e²(3st) - 2(s + 2t)e²(3st) + 9s²s + 2t)(s - 2t).

To find all the first partial derivatives of w at (1, -1, 0), to find the partial derivatives with respect to each variable separately.

Given function: w = xy × e²z

∂w/∂x: Differentiating with respect to x while treating y and z as constants.

∂w/∂x = y × e²z

∂w/∂y: Differentiating with respect to y while treating x and z as constants.

∂w/∂y = x ×e²z

∂w/∂z: Differentiating with respect to z while treating x and y as constants.

∂w/∂z = xy ×e²z

(b) To find the directional derivative of w at (1, -1, 0) along the direction v = i + 2j + 2k,  to calculate the dot product of the gradient of w at (1, -1, 0) and the unit vector in the direction of v.

Gradient of w at (1, -1, 0):

∇w = (∂w/∂x, ∂w/∂y, ∂w/∂z) = (-1, 1, -1)

Unit vector in the direction of v:

|v| = √(1² + 2² + 2²) = √9 = 3

u = v/|v| = (1/3, 2/3, 2/3)

Directional derivative of w at (1, -1, 0) along direction v:

Dv(w) = ∇w · u = (-1, 1, -1) · (1/3, 2/3, 2/3) = -1/3 + 2/3 - 2/3 = -1/3

(c) To find ∂w/∂t using the chain rule,  to substitute the given expressions for x, y, and z into the function w = xy × e²z and then differentiate with respect to t.

Given: x = s + 2t, y = s - 2t, z = 3st

Substituting these values into w:

w = (s + 2t)(s - 2t) × e²(3st)

Differentiating with respect to t using the chain rule:

∂w/∂t = (∂w/∂x) × (∂x/∂t) + (∂w/∂y) ×(∂y/∂t) + (∂w/∂z) × (∂z/∂t)

Let's calculate each term separately:

∂w/∂x = (s - 2t) × e²(3st)

∂x/∂t = 2

∂w/∂y = (s + 2t) × e²(3st)

∂y/∂t = -2

∂w/∂z = (s + 2t)(s - 2t) × 3s

∂z/∂t = 3s

Now, substitute these values into the equation:

∂w/∂t = (s - 2t) × e²(3st) × 2 + (s + 2t) × e²(3st) ×(-2) + (s + 2t)(s - 2t) × 3s × 3s

∂w/∂t = 2(s - 2t)e²(3st) - 2(s + 2t)e²(3st) + 9s²(s + 2t)(s - 2t)

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The solution to the inequality is x > 7.

To remove the coefficient of "3" and isolate the variable x in the inequality -7 + 3x > 14, we need to perform inverse operations.

Since the coefficient of x is positive 3, we can eliminate it by dividing both sides of the inequality by 3. This ensures that we keep the inequality sign in the same direction.

The correct step to remove the coefficient of 3 and isolate x is:

C. Divide both sides by 3

Dividing both sides of the inequality by 3, we have:

(3x) / 3 > 21 / 3

x > 7

Therefore, the solution to the inequality is x > 7.

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Answer: The answer is D (2,3)

Step-by-step explanation:

We are given that triangle PQR lies in the xy-plane, and coordinates of Q are (2,-3).

Triangle PQR is rotated 180 degrees clockwise about the origin and then reflected across the y-axis to produce triangle P'Q'R',

We have to find the coordinates of Q'.

The coordinates of Q(2,-3).

180 degree clockwise  rotation about the origin  then transformation rule

The coordinates (2,-3) change into (-2,3) after 180 degree clockwise rotation about origin.

Reflect across y- axis the transformation rule

Therefore, when reflect across y- axis then the coordinates (-2,3) change into (2,3).

Hence, the coordinates of Q(2,3).

The x-coordinate of relative minimum is -1. The x-coordinate of relative maximum is 0.5.The interval(s) on which f is increasing: (-1, 0.5)The interval(s) on which f is decreasing: (-∞, -1) and (0.5, ∞)The inflection points of f, if any: None.The interval(s) on which f is concave upward: (-1, ∞)The interval(s) on which f is concave downward: (-∞, -1)

Given Function:

f(x) = 3x^4 - 4x^3 - 12x^2 + 3

To find out the following points:

i) The x-coordinate of the relative (local) minima/maxima using the first derivative test

ii) The interval(s) on which f is increasing and the interval(s) on which f is decreasing

iii) The x-coordinate of the relative (local) minima/maxima using the second derivative test, if possible

iv) The inflection points of f, if any

v) The interval(s) on which f is concave upward and the interval(s) on which f is downward.

The first derivative of the given function:

f'(x) = 12x^3 - 12x^2 - 24x

Step 1:

To find the x-coordinate of critical points:

3x^4 - 4x^3 - 12x^2 + 3 = 0x^2 (3x^2 - 4x - 4) + 3

= 0x^2 (3x - 6) (x + 1) - 3

= 0

Therefore, we get x = 0.5, -1.

Step 2:

To find the interval(s) on which f is increasing and the interval(s) on which f is decreasing, make use of the following table:

X-2-1.51.5F'

(x)Sign(-)-++-

The function is decreasing from (-∞, -1) and (0.5, ∞). And it is increasing from (-1, 0.5).

Step 3:

To find the x-coordinate of relative maxima/minima, make use of the following table:

X-2-1.51.5F'

(x)Sign(-)-++-F''

(x)Sign(+)-++-

Since, f''(x) > 0, the point x = -1 is the relative minimum of f(x),

and x = 0.5 is the relative maximum of f(x).

Step 4:

To find inflection points, make use of the following table:

X-2-1.51.5F''

(x)Sign(+)-++-

The function has no inflection points since f''(x) is not changing its sign.

Step 5:

To find the intervals on which f is concave upward and the interval(s) on which f is downward, make use of the following table:

X-2-1.51.5F''

(x)Sign(+)-++-

The function is concave upward on (-1, ∞) and concave downward on (-∞, -1).

Therefore, The x-coordinate of relative minimum is -1. The x-coordinate of relative maximum is 0.5.The interval(s) on which f is increasing: (-1, 0.5)The interval(s) on which f is decreasing: (-∞, -1) and (0.5, ∞)The inflection points of f, if any: None.The interval(s) on which f is concave upward: (-1, ∞)The interval(s) on which f is concave downward: (-∞, -1)

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Answer:

[tex]\textsf{A)} \quad \cos 2 \theta=\dfrac{41}{49}[/tex]

Step-by-step explanation:

To find the value of cos 2θ given sin θ = 2/7 where 90° < θ < 180°, first use the trigonometric identity sin²θ + cos²θ = 1 to find cos θ:

[tex]\begin{aligned}\sin^2\theta+\cos^2\theta&=1\\\\\left(\dfrac{2}{7}\right)^2+cos^2\theta&=1\\\\\dfrac{4}{49}+cos^2\theta&=1\\\\cos^2\theta&=1-\dfrac{4}{49}\\\\cos^2\theta&=\dfrac{45}{49}\\\\cos\theta&=\pm\sqrt{\dfrac{45}{49}}\end{aligned}[/tex]

Since 90° < θ < 180°, the cosine of θ is in quadrant II of the unit circle, and so cos θ is negative. Therefore:

[tex]\boxed{\cos\theta=-\sqrt{\dfrac{45}{49}}}[/tex]

Now we can use the cosine double angle identity to calculate cos 2θ.

[tex]\boxed{\begin{minipage}{6.5 cm}\underline{Cosine Double Angle Identity}\\\\$\cos (A \pm B)=\cos A \cos B \mp \sin A \sin B$\\\\$\cos (2 \theta)=\cos^2 \theta - \sin^2 \theta$\\\\$\cos (2 \theta)=2 \cos^2 \theta - 1$\\\\$\cos (2 \theta)=1 - 2 \sin^2 \theta$\\\end{minipage}}[/tex]

Substitute the value of cos θ:

[tex]\begin{aligned}\cos 2\theta&=2\cos^2\theta -1\\\\&=2 \left(-\sqrt{\dfrac{45}{49}}\right)^2-1\\\\&=2 \left(\dfrac{45}{49}\right)-1\\\\&=\dfrac{90}{49}-1\\\\&=\dfrac{90}{49}-\dfrac{49}{49}\\\\&=\dfrac{90-49}{49}\\\\&=\dfrac{41}{49}\\\\\end{aligned}[/tex]

Therefore, when 90° < θ < 180° and sin θ = 2/7, the value of cos 2θ is 41/49.

The quotient is 3x - 5 + (-5) + 12, which simplifies to 3x + 2.

To find the quotient, we need to perform polynomial long division. The dividend is 3x² - 2x + 7, and the divisor is x + 1.

 3x - 5

x + 1 | 3x² - 2x + 7

We start by dividing the highest degree term of the dividend (3x²) by the divisor (x), which gives us 3x. We then multiply the divisor (x + 1) by the quotient (3x) and subtract it from the dividend:

       3x - 5

    ____________

x + 1 | 3x² - 2x + 7

- (3x² + 3x)

____________

- 5x + 7

We continue the process by dividing the next term (-5x) of the resulting polynomial (-5x + 7) by the divisor (x + 1). This gives us -5.

            -5

    ____________

x + 1 | 3x² - 2x + 7

- (3x² + 3x)

____________

- 5x + 7

- (- 5x - 5)

____________

12

Finally, we divide the remaining term (12) by the divisor (x + 1), which gives us 12.

                  12

    ____________

x + 1 | 3x² - 2x + 7

- (3x² + 3x)

____________

- 5x + 7

- (- 5x - 5)

____________

12

- 12

____________

0

The quotient is 3x + 2 and can be written as 3x + 5 + (-5) + 12.

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Answer:

Please repost this question/problem.

Step-by-step explanation:

The function y(t) = (6/5) - (6/5) is a valid explicit solution to the differential equation dy/dt = 20y = 24, and it satisfies the equation for the specified interval of definition.

To verify that the function y(t) = (6/5) - (6/5)[tex]e^(-20t)[/tex] is an explicit solution of the differential equation dy/dt = 20y, we need to substitute the function into the differential equation and check if it satisfies the equation.
First, let's find dy/dt using the given function:
dy/dt = d/dt [(6/5) - (6/5)[tex]e^(-20t)[/tex]]
      = 0 + (6/5)(20)[tex]e^(-20t)[/tex] [Applying the chain rule]
      = 24[tex]e^(-20t)[/tex]
Now let's substitute this expression for dy/dt back into the differential equation:
24[tex]e^(-20t)[/tex] = 20[(6/5) - (6/5)e^(-20t)]
We can simplify this equation:
24[tex]e^(-20t)[/tex] = 24 - 24[tex]e^(-20t)[/tex]
Rearranging the equation, we have:
24[tex]e^(-20t)[/tex] + 24[tex]e^(-20t)[/tex] = 24
Combining like terms, we get:
48[tex]e^(-20t)[/tex] = 24
Dividing both sides by 48, we find:
[tex]e^(-20t)[/tex] = 1/2
Taking the natural logarithm of both sides, we have:
-20t = ln(1/2)
Solving for t, we get:
t = (1/20)ln(1/2)
Therefore, the function y(t) = (6/5) - (6/5)[tex]e^(-20t)[/tex]is a valid explicit solution to the differential equation dy/dt = 20y = 24, and it satisfies the equation for the specified interval of definition.

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1.The equation of the least squares regression line is y=745.0195 - 93.10345x, b) The demand when the price is $3.90 is estimated to be 3745.7202 gallons.

a.)The given table shows daily sales y (in gallons) for three different prices:

Price, x $3.50 $3.75 $4.00Demand, y 4400 3650 3200The formula for the least square regression line is given as: y=a+bx Where a is the y-intercept and b is the slope.

For computing the equation of the least square regression line, use the following steps:

1. Calculate the means of X and Y2.

Calculate the deviations of XY3.

Calculate the slope b = ∑xy/∑x²4.

Calculate the y-intercept a = y - bx

Using the above formula, the solution for the given problem is as follows:

1. Calculation of means of X and Y:Mean of x= ∑x/n = (3.50 + 3.75 + 4.00)/3 = 3.75Mean of y= ∑y/n = (4400 + 3650 + 3200)/3 = 3750.002.

Calculation of deviations of XY: The deviation of X from mean= x - x¯

The deviation of Y from mean= y - y¯X = {3.5, 3.75, 4}, Y = {4400, 3650, 3200}So, the deviations of X and Y from their respective means is shown below.

Price, x $3.50 $3.75 $4.00

Demand, y 4400 3650 3200

Deviation of x (x - x¯) -0.25 0 0.25

Deviation of y (y - y¯) 649.998 -99.998 -549.998 X*Y -1624.995 0 -1374.9973.

Calculation of slope b:

The formula to calculate the slope of the least square regression line is given below:

Slope (b) = ∑xy/∑x²= (3.50*(-0.25)*4400 + 3.75*0*3650 + 4*(0.25)*3200)/(3.50² + 3.75² + 4²) = (-2175+0+800)/14.5= -93.10345.

Calculation of the y-intercept a:

The formula to calculate the y-intercept of the least square regression line is given below:

Intercept (a) = y¯ - b*x¯= 3750.002 - (-93.10345)*3.75= 745.0195

b.)Therefore, the equation of the least square regression line is:y = 745.0195 - 93.10345xNow, to estimate the demand when the price is $3.90, substitute the value of x = 3.90

into the above equation and solve for y:y = 745.0195 - 93.10345(3.90)= 3745.7202

Answer: The equation of the least squares regression line is y=745.0195 - 93.10345x and the demand when the price is $3.90 is estimated to be 3745.7202 gallons.

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The correct option is:

c. y¹ = 3 + √(x - 7)

To find the inverse function of y = (x - 3)^2 + 7 for x > 3, we can follow these steps:

Step 1: Replace y with x and x with y in the given equation:

x = (y - 3)^2 + 7

Step 2: Solve the equation for y:

x - 7 = (y - 3)^2

√(x - 7) = y - 3

y - 3 = √(x - 7)

Step 3: Solve for y by adding 3 to both sides:

y = √(x - 7) + 3

So, the inverse function of y = (x - 3)^2 + 7 for x > 3 is y¹ = √(x - 7) + 3.

Therefore, the correct option is:

c. y¹ = 3 + √(x - 7)

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Answer:

|2x - 9| > 13

2x - 9 < -13 or 2x - 9 > 13

2x < -4 or 2x > 22

x < -2 or x > 11

The correct answer is B.

The equations can be represented as follows:

[tex]\displaystyle x\cos\alpha +y\sin\alpha =p[/tex]

[tex]\displaystyle x\sin\alpha -y\cos\alpha =q[/tex]

where [tex]\displaystyle \alpha[/tex] represents an angle, [tex]\displaystyle x[/tex] and [tex]\displaystyle y[/tex] are variables, and [tex]\displaystyle p[/tex] and [tex]\displaystyle q[/tex] are constants.

[tex]\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}[/tex]

♥️ [tex]\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}[/tex]

The ratios that could be the lengths of the two legs in a 30-60-90 triangle are √3:3 (option E) and 12√3 (option D).

In a 30-60-90 triangle, the angles are in the ratio of 1:2:3. The sides of this triangle are in a specific ratio that is consistent for all triangles with these angles. Let's analyze the given options to determine which ones could be the ratio between the lengths of the two legs.

A. √2:√2

The ratio √2:√2 simplifies to 1:1, which is not the correct ratio for a 30-60-90 triangle. Therefore, option A is not applicable.

B. 15

This is a specific value and not a ratio. Therefore, option B is not applicable.

C. √√√√5

The expression √√√√5 is not a well-defined mathematical operation. Therefore, option C is not applicable.

D. 12√3

This is the correct ratio for a 30-60-90 triangle. The ratio of the longer leg to the shorter leg is √3:1, which simplifies to √3:3. Therefore, option D is applicable.

E. √3:3

This is the correct ratio for a 30-60-90 triangle. The ratio of the longer leg to the shorter leg is √3:1, which is equivalent to √3:3. Therefore, option E is applicable.

F. √2:√5

This ratio does not match the ratio of the sides in a 30-60-90 triangle. Therefore, option F is not applicable. So, the correct option is D. 1 √2.

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