From two cities that are 500 mi apart, two cars left simulaneously moving towards each other. The speed of one car was 10 mph greater than the speed of the other car. In 5 hours the cars met. Find the speed of each car.

Answers

Answer 1

Given:

Distance between to cities = 500 mi

Two cars left simultaneously moving towards each other.

The speed of one car was 10 mph greater than the speed of the other car.

They meet in 5 hours.

To find:

The speed of each car.

Solution:

Let x mi/h be the speed of one car.

So, speed of second car = (x + 10) mi/h

Two cars left simultaneously moving towards each other.

So, their relative speed = x + (x+10) = (2x+10) mi/h

We know that,

[tex]Speed =\dfrac{Distance}{Time}[/tex]

On substituting the values, we get

[tex]2x+10=\dfrac{500}{5}[/tex]

[tex]2x+10=100[/tex]

[tex]2x=100-10[/tex]

[tex]2x=90[/tex]

Divide both sides by 2.

[tex]x=\dfrac{90}{2}[/tex]

[tex]x=45[/tex]

Now,

Speed of one car = 45 mi/h

Speed of other car = 45+10

                                = 55 mi/h

Therefore, the speeds of two cars are 45 mi/h and 55 mi/hr.


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Complete question :

Lilian purchased a violin form smash music stores. It regularly sold for $670, but wa son slaw for 10% off. She also had to pay 8% sales tax. She bought it on the installment plan and paid 15% of the total cost with tax as a down payment. Her payments were $58 per month for one year. What is her sales tax?

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Complete question :

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