Answer:
Its..... friction and normal force, have a good day AheadAnswer:
yo mama
Explanation:
Sort the balloons based on the kinds of charges they carry.
first one is negative
second is none
third is posotive
last one is negative
left to right order
Answer:
Explanation:
thats the answer
Big Ben, a large artifact in England, has a mass of 1x10^8 kilograms and the Empire State Building 1x10^9 kilograms. The distance between them is about 5,000,000 meters. What is the force exerted by Big Ben on the Empire State Building?
Answer:
The force, exerted by Big Ben on the Empire State Building is 2.66972 × 10⁻⁷ N
Explanation:
The question relates to the force of gravity experienced between two bodies
The given parameters are;
The mass of Big Ben, M₁ = 1 × 10⁸ kg
The mass of the Empire State Building, M₂ = 1 × 10⁹ kg
The distance between the two Big Ben and the Empire State Building, r = 5,000,000 meters
By Newton's Law of gravitation, we have;
[tex]F=G \times \dfrac{M_{1} \times M_{2}}{r^{2}}[/tex]
Where;
F = The force exerted by Big Ben on the Empire State Building and vice versa
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
M₁, M₂, and r are the given parameters
By plugging in the values of the parameters and the constant into the equation for Newton's Law of gravitation, we have;
[tex]F=6.67430 \times 10^{-11} \times \dfrac{1 \times 10^8 \times 1 \times 10^9}{(5,000,000)^{2}} = 2.66972 \times 10^{-7}[/tex]
The force, 'F', exerted by Big Ben on the Empire State Building is F = 2.66972 × 10⁻⁷ N.
In an experiment involving pendulums, you want to see how changing the mass of the bob affects the period (amount of time) of a pendulum swing. What would be your dependent variable?
Answer:
The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.
Explanation:
guys please helpp!!!!1
Answer:
Position A/Position E
[tex]K = E[/tex], [tex]U = 0[/tex]
Position B/Position D
[tex]K = (1-x)\cdot E[/tex], [tex]U = x\cdot E[/tex], for [tex]0 < x < 1[/tex]
Position C
[tex]K = 0[/tex], [tex]U = E[/tex]
Explanation:
Let suppose that ball-Earth system represents a conservative system. By Principle of Energy Conservation, total energy ([tex]E[/tex]) is the sum of gravitational potential energy ([tex]U[/tex]) and translational kinetic energy ([tex]K[/tex]), all measured in joules. In addition, gravitational potential energy is directly proportional to height ([tex]h[/tex]) and translational kinetic energy is directly proportional to the square of velocity.
Besides, gravitational potential energy is increased at the expense of translational kinetric energy. Then, relative amounts at each position are described below:
Position A/Position E
[tex]K = E[/tex], [tex]U = 0[/tex]
Position B/Position D
[tex]K = (1-x)\cdot E[/tex], [tex]U = x\cdot E[/tex], for [tex]0 < x < 1[/tex]
Position C
[tex]K = 0[/tex], [tex]U = E[/tex]