Formulas for the compounds below.
Sulfur Trioxide
Sodium hydroxide

Answer:

An increase in temperature typically increases the rate of reaction because an increase in temperature will raise the average kinetic energy of the reactant molecules. Therefore, a greater proportion of molecules will have the minimum energy necessary for an effective collision.Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

Explanation:

Can you please give this answer a brainliest answer please

Answer:

Explanation:

Using the ideal gas equation as follows:

PV = nRT

Where:

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

Based on the information provided in this question;

P = 1.6atm

n = 4.4 moles

R = 0.0821 L*atm/mol*K

T = 32.9°C = 32.9 + 273 = 305.9K

V = ?

Answer:

Metal

Non-metal

Explanation:

CaF2 is an ionic compound. Ionic compounds are mostly composed of a metal and a non metal. Metals donate electrons to non-metals to form ionic compounds.

Calcium is a divalent ion of group two in the periodic table while F is a univalent nonmetal of group 17 in the periodic table. Hence the compound CaF2 is composed of a metal and a nonmetal.

Answer:

Br

Explanation:

Answer:

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2 F atoms

Explanation:

A Ca atom has a valence number of +2, which means that when ionized, it will give up two electrons. In turn, a F atom has a valence number of -1, which means it can only accept 1 electron when ionized. So to accommodate the two electrons from Ca atom, we need 2 F atoms.

Answer:

22.54 moles of NaBr are needed

Explanation:

The reaction of Cl2 with NaBr occurs as follows:

Cl2 + 2NaBr → 2NaCl + Br2

Where 1 mole of Cl2 requires 2 moles of NaBr for a complete reaction

As in the problem, we have 11.27 moles of Cl2, the moles of NaBr required are:

11.27mol Cl2 * (2mol NaBr / 1mol Br2) =

Answer:

a bacterium with a rigid spiral structure,found in stagnant water and something causing disease

Answer:

The molar mass and molecular weight of CCI2F2 is 315.8271.

Explanation:

Answer:

The correct answer is -

3. Butyne

4. Pentene

Explanation:

The names of such organic compounds are classified on the number of the carbon atoms and based on a number these prefixes are attached -

Meth - one carbon

Eth - two carbons

Prop - three carbons

But - four carbons

Pent - five carbons, and so on

The bonds can be identified by names of an organic compound by their suffixes -

- ane = single bond

- ene = double bond

-yne = triple bond

Thus, for question 3, carbon numbers are 4 and triple bond so Butyne, and similarly for question 4, 5 carbon atoms and double bond so Pentene.

Answer:

mixture of four compounds

mixture of two elements and two compounds

Explanation:

Answer:

crust

Discuss with the whole class what the relative thicknesses of the layers are — that the inner core and outer core together form the thickest layer of the Earth and that the crust is by far the thinnest layer.

Explanation:

Discuss with the whole class what the relative thicknesses of the layers are — that the inner core and outer core together form the thickest layer of the Earth and that the crust is by far the thinnest layer.

Answer:

A

Explanation:

Rock sand sun arent living.  cactus lizard sam and snake are living or biotic

Answer:

chung long

Explanation:

cause 3 plus 2 =9

Explanation:

222.01758 g/mol

3.1Computed Properties

the pH numbers that are acidic above is 3 and 5

Answer:

[tex]\boxed {\boxed {\sf 19 \ M}}[/tex]

Explanation:

Molarity is a measure of concentration in moles per liter, so the formula is:

[tex]molarity= \frac{moles \ of \ solute}{liters \ of \ solution}}[/tex]

This solution has 9.0 moles of solute and 462 milliliters of solution. We must convert milliliters to liters. Remember that 1 liter contains 1000 milliliters.

Create a ratio.

Multiply by the value we are converting: 462 milliliters

[tex]0.462 \ L[/tex]

Now we know both values and we can solve for the molarity.

[tex]molarity= \frac{9.0 \ mol}{ 0.462 \ L}[/tex]

Divide.

[tex]molarity= 19.4805195 \ mol/L[/tex]

The original measurements of moles and milliliters have 2 and 3 significant figures respectively. We have to round our answer to the least number of sig figs, which is 2 in this case.

For the number we found, that is the ones place. The 4 in the tenths place (19.4805195) tells us to leave the 9 in the ones place.

[tex]molarity= 19 \ mol/L[/tex]

1 mole per liter is equal to 1 molar or M, so our answer is equal to 19 M.

[tex]molarity \approx 19 \ M[/tex]

The molarity of the solution is approximately 19 M.

Answer:

[tex]2C _{6}H _{14} + 19O _{2}→12CO _{2} +14H _{2} O[/tex]

Answer:

Gamma rays and X-rays

Explanation:

All the things she said

All the things she said

Running through my head

Running through my head

Running through my head

All the things she said

All the things she said

Running through my head

Running through my head

All the things she said

This is not enough

This is not enough

Answer:

[tex]\boxed {\boxed {\sf 2. \ 157 \ kPa}}[/tex]

Explanation:

Since temperature remains constant, the only variables that change are volume and pressure. Therefore, we are using Boyle's Law. This states that the pressure is inversely proportional to the volume. The formula is:

[tex]P_1V_1=P_2V_2[/tex]

We know the gas starts with a volume of 20.0 liters at a pressure of 275 kPa. We can substitute these values into the left side of the formula.

[tex]275 \ kPa *20.0 \ L=P_2V_2[/tex]

We know the gas expands to a volume of 35.0 Liters, but we do not know the pressure.

[tex]275 \ kPa *20.0 \ L=P_2* 35.0 \ L[/tex]

Since we are solving for the new pressure, we must isolate the variable P₂. It is being multiplied by 35.0 Liters and the inverse of multiplication is division. Divide both sides by 35.0 L.

[tex]\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}= \frac{P_2*35.0 \ L}{35.0 \ L}[/tex]

[tex]\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}=P_2[/tex]

The units of liters cancel.

[tex]\frac {275 \ kPa * 20.0 }{ 35.0 }=P_2[/tex]

[tex]\frac {5500}{35.0} \ kPa= P_2[/tex]

[tex]157.142857 \ kPa=P_2[/tex]

The original measurements of pressure and volume have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.

The 1 in the tenths place (157.142857) tells us to leave the 7 in the ones place.

[tex]157 \ kPa= P_2[/tex]

If the gas expanded to a volume of 35.0 liters while the temperature remained constant, the pressure in container was approximately 157 kilopascals.

Answer:

0.603J/g°C is the specific heat of the metal object

Explanation:

To solve this question we must know the heat given by the metal is equal to the heat absorbed by the water. The change in heat follows the equation:

Q = m*S*ΔT

Where Q is heat in Joules, m is the mass of the substance, S its specific heat and ΔT change in temperature

The equation to solve the problem is:

m(Object)*S(Object)*ΔT(Object) = m(Water)*S(Water)*ΔT(Water)

Where:

m(Object) = 29.0g

S(Object) = ??

ΔT(Object) = (97.0°C - 23.7°C = 73.3°C)

m(Water) = 95.8g

S(Water) = 4.184J/g°C

ΔT(Water) = (23.7°C - 20.5°C = 3.2°C)

29.0g*S(Object)*73.3°C = 95.8g*4.184J/g°C*3.2°C

S (Object) * 2125.7g°C = 1282.6J

S(Object) = 0.603J/g°C is the specific heat of the metal object

Answer: 1.09 Liers

Explanation:

I did the problem and got it correct.

Answer:

A. 1.09

Explanation:

I did the Chemistry Exam

Answer:

1618.2

Explanation:

235+75=310×75=1618.2

Answer:

nucleotides

Explanation:

The four types of nitrogen bases found in nucleotides are: adenine (A), thymine (T), guanine (G) and cytosine (C). The order, or sequence, of these bases determines what biological instructions are contained in a strand of DNA. ... DNA is made of chemical building blocks called nucleotides.

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Answer:

Step 1;

q = w = -0.52571 kJ, ΔS = 0.876 J/K

Step 2

q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ

Explanation:

The given parameters are;

[tex]P_i[/tex] = 100 N·m

[tex]T_i[/tex] = 327 K

[tex]P_f[/tex] = 90 N·m

Step 1

For isothermal expansion, we have;

ΔU = ΔH = 0

w = n·R·T·ln([tex]P_f[/tex]/[tex]P_i[/tex]) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71

w ≈ -0.52571 kJ

At state 1, q = w = -0.52571 kJ

ΔS = -n·R·ln([tex]P_f[/tex]/[tex]P_i[/tex]) = -1 × 8.314 × ln(90/100) ≈ 0.876

ΔS ≈ 0.876 J/K

Step 2

q = 0 for adiabatic process

ΔU = 25×(27 - 327) = -7,500

w = ΔU = -7.5 kJ

ΔH = ΔU + n·R·ΔT

ΔH = -7,500 + 8.3142 × 300 = -5,005.74

ΔH = ΔU = -5.00574 kJ

Answer:

D. the capacity to do work

Explanation:

the basic definition of energy is the ability to do work