The constant value of c that makes the function f continuous on (−∞, ∞) is c = 7/3.
The function f(x) is continuous at x = 2 if and only if the left-hand limit and the right-hand limit both exist and are equal. Therefore, we need to calculate the left-hand limit and the right-hand limit of f(x) as x approaches 2.
Left-hand limit:
lim (x → 2-) f(x) = lim (x → 2-) [cx^2 - 3x] = c(2)^2 - 3(2) = 4c - 6
Right-hand limit:
lim (x → 2+) f(x) = lim (x → 2+) [x^3 - cx] = 2^3 - c(2) = 8 - 2c
For f(x) to be continuous at x = 2, we need the left-hand limit and the right-hand limit to be equal:
4c - 6 = 8 - 2c
Simplifying and solving for c, we get:
6c = 14
c = 7/3
Therefore, the constant value of c that makes the function f continuous on (−∞, ∞) is c = 7/3.
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The Dessert Club made some pies to sell at a basketball game to raise money for the school field day. The cafeteria contributed four pies to the sale. Each pie was then cut into five pieces and sold. There were a total of 60 pieces to sell. How many pies did the club make?
3. The material Santiago will use to build the
ramp costs $2. 20) per square foot what will the cost of building the ramp be?
We need to know the area of the ramp in order to calculate the total cost of the material. Let's assume the ramp has a length of L feet and a width of W feet. Then the area of the ramp can be calculated as:
Area = Length x Width = L x W
We don't have any specific values for L and W, but let's assume that Santiago wants to build a ramp that is 10 feet long and 3 feet wide. In that case:
Area = 10 feet x 3 feet = 30 square feet
Now we can calculate the cost of building the ramp by multiplying the area by the cost per square foot:
Cost = Area x Cost per square foot = 30 square feet x $2.20/square foot
Cost = $66
Therefore, the cost of building the ramp with a length of 10 feet and a width of 3 feet, using material that costs $2.20 per square foot, would be $66.
Find the volume of the given solid Bounded by the coordinate planes and the plane 5x + 7y +z = 35
The solid bounded by the coordinate planes and the plane 5x + 7y + z = 35 is a tetrahedron. We can find the volume of the tetrahedron by using the formula V = (1/3)Bh, where B is the area of the base and h is the height.
The base of the tetrahedron is a triangle formed by the points (0,0,0), (7,0,0), and (0,5,0) on the xy-plane. The area of this triangle is (1/2)bh, where b and h are the base and height of the triangle, respectively. We can find the base and height as follows:
The length of the side connecting (0,0,0) and (7,0,0) is 7 units, and the length of the side connecting (0,0,0) and (0,5,0) is 5 units. Therefore, the base of the triangle is (1/2)(7)(5) = 17.5 square units.
To find the height of the tetrahedron, we need to find the distance from the point (0,0,0) to the plane 5x + 7y + z = 35. This distance is given by the formula:
h = |(ax + by + cz - d) / sqrt(a^2 + b^2 + c^2)|
where (a,b,c) is the normal vector to the plane, and d is the constant term. In this case, the normal vector is (5,7,1), and d = 35. Substituting these values, we get:
h = |(5(0) + 7(0) + 1(0) - 35) / sqrt(5^2 + 7^2 + 1^2)| = 35 / sqrt(75)
Therefore, the volume of the tetrahedron is:
V = (1/3)Bh = (1/3)(17.5)(35/sqrt(75)) = 245/sqrt(75) cubic units
Simplifying the expression by rationalizing the denominator, we get:
V = 49sqrt(3) cubic units
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The first three terms of a sequence are given. Round to the nearest thousandth (if necessary). 6, 9,12
To find the pattern in the given sequence, we can observe that each term increases by 3.
Using this pattern, we can determine the next terms of the sequence:
6, 9, 12, 15, 18, ...
So the first three terms are 6, 9, and 12.Starting with the first term, which is 6, we add 3 to get the second term: 6 + 3 = 9.
Similarly, we add 3 to the second term to get the third term: 9 + 3 = 12.
If we continue this pattern, we can find the next terms of the sequence by adding 3 to the previous term:
12 + 3 = 15
15 + 3 = 18
18 + 3 = 21
...
So, the sequence continues with 15, 18, 21, and so on, with each term obtained by adding 3 to the previous term.
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Let X be normal with mean 3.6 and variance 0.01. Find C such that P(X<=c)=5%, P(X>c)=10%, P(-c
Answer: We can solve this problem using the standard normal distribution and standardizing the variable X.
Let Z be a standard normal variable, which is obtained by standardizing X as:
Z = (X - μ) / σ
where μ is the mean of X and σ is the standard deviation of X.
In this case, X is normal with mean μ = 3.6 and variance σ^2 = 0.01, so its standard deviation is σ = 0.1.
Then, we have:
Z = (X - 3.6) / 0.1
To find C such that P(X <= c) = 5%, we need to find the value of Z for which the cumulative distribution function (CDF) of the standard normal distribution equals 0.05. Using a standard normal table or calculator, we find that:
P(Z <= -1.645) = 0.05
Therefore:
(X - 3.6) / 0.1 = -1.645
X = -0.1645 * 0.1 + 3.6 = 3.58355
So C is approximately 3.5836.
To find C such that P(X > c) = 10%, we need to find the value of Z for which the CDF of the standard normal distribution equals 0.9. Using the same table or calculator, we find that:
P(Z > 1.28) = 0.1
Therefore:
(X - 3.6) / 0.1 = 1.28
X = 1.28 * 0.1 + 3.6 = 3.728
So C is approximately 3.728.
To find C such that P(-c < X < c) = 95%, we need to find the values of Z for which the CDF of the standard normal distribution equals 0.025 and 0.975, respectively. Using the same table or calculator, we find that:
P(Z < -1.96) = 0.025 and P(Z < 1.96) = 0.975
Therefore:
(X - 3.6) / 0.1 = -1.96 and (X - 3.6) / 0.1 = 1.96
Solving for X in each equation, we get:
X = -0.196 * 0.1 + 3.6 = 3.5804 and X = 1.96 * 0.1 + 3.6 = 3.836
So the interval (-c, c) is approximately (-0.216, 3.836).
Answer:
This is not possible, since probabilities cannot be negative. Therefore, there is no value of e that satisfies the given condition
Step-by-step explanation:
We can use the standard normal distribution to solve this problem by standardizing X to Z as follows:
Z = (X - μ) / σ = (X - 3.6) / 0.1
Then, we can use the standard normal distribution table or calculator to find the values of Z that correspond to the given probabilities.
P(X <= c) = P(Z <= (c - 3.6) / 0.1) = 0.05
Using a standard normal distribution table or calculator, we can find that the Z-score corresponding to the 5th percentile is -1.645. Therefore, we have:
(c - 3.6) / 0.1 = -1.645
Solving for c, we get:
c = 3.6 - 1.645 * 0.1 = 3.4355
So, the value of c such that P(X <= c) = 5% is approximately 3.4355.
Similarly, we can find the value of d such that P(X > d) = 10%. This is equivalent to finding the value of c such that P(X <= c) = 90%. Using the same approach as above, we have:
(d - 3.6) / 0.1 = 1.28 (the Z-score corresponding to the 90th percentile)
Solving for d, we get:
d = 3.6 + 1.28 * 0.1 = 3.728
So, the value of d such that P(X > d) = 10% is approximately 3.728.
Finally, we can find the value of e such that P(-e < X < e) = 90%. This is equivalent to finding the values of c and d such that P(X <= c) - P(X <= d) = 0.9. Using the values we found above, we have:
P(X <= c) - P(X <= d) = 0.05 - 0.1 = -0.05
This is not possible, since probabilities cannot be negative. Therefore, there is no value of e that satisfies the given condition
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Which function defines?
Answer:
j
Step-by-step explanation:
X
W
Which of the following statements is correct?
(A) AXYZ ~ AWVZ by AA similarity.
BAXYZ~AWVZ by SAS similarity.
AXYZ ~ AWVZ by SSS similarity.
AXYZ and AWVZ are not similar.
The statement that is correct is: ΔXYZ ~ΔWVZ by AA similarity.
What are similar triangles?Two or more triangles are said to be similar if on comparing their corresponding properties, there exists some common relations. Thus showing that the triangles are similar, but not congruent.
The similarity relations can then be expressed with respect to the sides, or/ and angles. Examples: Side-Angle-Side (SAS), Angle-Angle-Side (AAS), etc.
With the information deduced from the given question, the statement that will be correct considering the properties of the triangles is: ΔXYZ ~ΔWVZ by AA similarity.
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suppose a, b, n ∈ z with n > 1. suppose that ab ≡ 1 (mod n). prove that both a and b are relatively prime to n.
Therefore, our initial assumption that a and n are not relatively prime must be false, and we can conclude that a and n are indeed relatively prime numbers.
To prove that both a and b are relatively prime to n given that ab ≡ 1 (mod n), we will use contradiction. Assume that a and n are not relatively prime, meaning they have a common factor greater than 1. Then, we can write a = kx and n = ky, where k > 1 and x and y are relatively prime.
Substituting a = kx into ab ≡ 1 (mod n), we get kxb ≡ 1 (mod ky). Multiplying both sides by x, we get kxab ≡ x (mod ky). Since k > 1 and x are relatively prime, kx and ky are also relatively prime. Therefore, we can cancel out kx from both sides of the congruence, leaving b ≡ x (mod y). Now, suppose that b and n are not relatively prime, meaning they have a common factor greater than 1. Then, we can write b = jy and n = jm, where j > 1 and y and m are relatively prime.
Substituting b = jy into ab ≡ 1 (mod n), we get ajy ≡ 1 (mod jm). Multiplying both sides by y, we get ajym ≡ y (mod jm). Since j > 1 and y are relatively prime, jy and jm are also relatively prime. Therefore, we can cancel out jy from both sides of the congruence, leaving am ≡ 1 (mod j). But since k and j are both greater than 1, and n = ky = jm, we have k and j as common factors of n, which contradicts the assumption that x, y, and m are relatively prime.
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Emma spent $60. 20 on 5 dozen bagels and a gallon of iced tea. The price of the gallon of iced tea was $5. 25. The following equation can be used to find d, the price of each dozen of bagels. 5d + 5. 25 = 60. 2 What was the price of each dozen of bagels?
Let's put the value of d into the equation and see if it works.5d + 5.25 = 60.2 5(10.99) + 5.25 = 60.2 54.95 + 5.25 = 60.2 60.2 = 60.2It works, and therefore, the answer is correct.
Emma spent $60.20 on 5 dozen bagels and a gallon of iced tea. The price of the gallon of iced tea was $5.25. The following equation can be used to find d, the price of each dozen of bagels. 5d + 5.25 = 60.2
What was the price of each dozen of bagels?
Solution:To find the price of a dozen bagels, we have to isolate the variable d by performing the same operation on both sides of the equation.5d + 5.25 = 60.2 - 5.25 5d = 54.95 d = 54.95/5 d = 10.99Therefore, the price of each dozen of bagels was $10.99.Check:Let's put the value of d into the equation and see if it works.5d + 5.25 = 60.2 5(10.99) + 5.25 = 60.2 54.95 + 5.25 = 60.2 60.2 = 60.2It works, and therefore, the answer is correct.
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Suppose that X has a hypergeometric distribution with N = 100, n = 4, and K = 20. Determine the following: (a) P(X = 1) (b) P(X = 6) (c) P(X = 4) (d) Mean and variance of X
The variance of the number of items of the particular type in a sample of 4 is approximately 0.674.
The hypergeometric distribution is used when we have a finite population and we sample without replacement. In this case, we have a population of size N = 100, and we sample n = 4 items from it. We are interested in the number of items that are of a particular type K = 20.
The probability mass function (PMF) of the hypergeometric distribution is given by:
P(X = k) = [K choose k] [N-K choose n-k] / [N choose n]
where [a choose b] denotes the binomial coefficient, which is the number of ways of choosing b items from a set of a items.
(a) P(X = 1)
Using the formula above, we get:
P(X = 1) = [20 choose 1] [80 choose 3] / [100 choose 4] ≈ 0.371
Therefore, the probability that exactly 1 item out of 4 is of the particular type is approximately 0.371.
(b) P(X = 6)
Since there are only 4 items being sampled, it is impossible to have 6 items of a particular type. Therefore, P(X = 6) = 0.
(c) P(X = 4)
Using the formula above, we get:
P(X = 4) = [20 choose 4] [80 choose 0] / [100 choose 4] ≈ 0.00035
Therefore, the probability that all 4 items are of the particular type is approximately 0.00035.
(d) Mean and variance of X
The mean of the hypergeometric distribution is given by:
μ = nK / N
Substituting the given values, we get:
μ = 4 × 20 / 100 = 0.8
Therefore, the mean number of items of the particular type in a sample of 4 is 0.8.
The variance of the hypergeometric distribution is given by:
σ^2 = nK(N-K)(N-n) / N^2(n-1)
Substituting the given values, we get:
σ^2 = 4 × 20 × 80 × 96 / 100^2 × 3 ≈ 0.674
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Un grupo de amigos cenan en un restaurante y deciden repartir el valor de la cuenta
en partes iguales. Si cada uno contribuye con Q125.00 faltan Q50.00 para pagar la
cuenta, pero si cada uno contribuye con Q150.00, entonces sobran Q75.00. ¿Cuál es
el valor de la cuenta?
Based on the equation, the total value of the bill is Q75.00.
How to explain the valueTotal contribution - Total bill = Shortage
125 * Number of people - X = 50
Total contribution - Total bill = Surplus
150 * Number of people - X = 75
We now have a system of two equations with two variables. Let's solve it to find the value of the total bill (X).
Equation 1: 125 * Number of people - X = 50
Equation 2: 150 * Number of people - X = 75
We can rearrange Equation 1 to solve for X:
X = 125 * Number of people - 50
Substituting this expression for X into Equation 2, we get:
150 * Number of people - (125 * Number of people - 50) = 75
Simplifying the equation:
150 * Number of people - 125 * Number of people + 50 = 75
25 * Number of people + 50 = 75
25 * Number of people = 25
Number of people = 1
Substituting the value of the number of people into Equation 1 to find X:
X = 125 * 1 - 50
X = 125 - 50
X = 75
Therefore, the total value of the bill is Q75.00.
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A group of friends have dinner at a restaurant and decide to share the value of the bill in equal parts. If each one contributes Q125.00, Q50.00 is missing to pay the account, but if each one contributes Q150.00, then Q75.00 is left over. Which account value?
in each of problems 1 through 4, express the given complex number inpolarform r(cosθ isinθ) = reiθ.
For each of the problems, we will start by identifying the values of r and θ from the given complex number in rectangular form (a + bi).
1) (1 + i)
r = sqrt(1^2 + 1^2) = sqrt(2)
θ = tan^-1(1/1) = π/4
Therefore, the polar form of (1 + i) is:
sqrt(2) * (cos(π/4) + i sin(π/4)) = sqrt(2) * e^(iπ/4)
2) (-3 + 3i)
r = sqrt((-3)^2 + 3^2) = 3sqrt(2)
θ = tan^-1(3/-3) = -π/4 or 7π/4
Note that we have two possible values for θ because the point (-3, 3) falls in the second and fourth quadrants. We will use the value 7π/4 because it is the standard angle in the fourth quadrant.
Therefore, the polar form of (-3 + 3i) is:
3sqrt(2) * (cos(7π/4) + i sin(7π/4)) = -3sqrt(2) * e^(i7π/4)
3) (-2 - 2i)
r = sqrt((-2)^2 + (-2)^2) = 2sqrt(2)
θ = tan^-1(-2/-2) = π/4
Therefore, the polar form of (-2 - 2i) is:
2sqrt(2) * (cos(π/4) - i sin(π/4)) = 2sqrt(2) * e^(-iπ/4)
4) (4 - 4i)
r = sqrt(4^2 + (-4)^2) = 4sqrt(2)
θ = tan^-1(-4/4) = -π/4 or 7π/4
Again, we have two possible values for θ. We will use 7π/4 because it is the standard angle in the fourth quadrant.
Therefore, the polar form of (4 - 4i) is:
4sqrt(2) * (cos(7π/4) - i sin(7π/4)) = -4sqrt(2) * e^(i7π/4).
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show that the continuous function f : r - r given by /(x) = 1 /(l x) is bounded but has neither a maximum value nor a minimum value.
The function f(x) = 1/(lx) is bounded but does not have a maximum or minimum value due to its behavior near x = 0.
To show that the function f(x) = 1/(lx) is bounded, we need to find a number M such that |f(x)| ≤ M for all x in the domain of f. Since the function is defined for all real numbers except for x = 0, we can consider two cases: when x is positive and when x is negative.
When x is positive, we have f(x) = 1/(lx) ≤ 1/x for all x > 0. Therefore, we can choose M = 1 to bind the function from above.
When x is negative, we have f(x) = 1/(lx) = -1/(-lx) ≤ 1/(-lx) for all x < 0. Therefore, we can choose M = 1/|l| to bind the function from below.
Since we have found a number M for both cases, we conclude that f(x) is bounded for all x ≠ 0.
However, the function does not have a maximum or minimum value. This is because as x approaches 0 from either side, the function becomes unbounded. Therefore, no matter how large or small we choose our bounds, there will always be a point near x = 0 where the function exceeds these bounds.
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Find the answer for
VU=
SU=
TV=
SW=
Show work please
The lengths in the square are VU = 15, SU = 15√2, TV = 15√2 and SW = (15√2)/2
How to determine the lengths in the squareFrom the question, we have the following parameters that can be used in our computation:
The square (see attachment)
The side length of the square is
Length = 15
So, we have
VU = 15
For the diagonal, we have
TV = VU * √2
So, we have
TV = 15 * √2
Evaluate
TV = 15√2
This also means that
SU = 15√2
This is because
SU = TV
Lastly, we have
SW = SU/2
So, we have
SW = (15√2)/2
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Find all films with minimum length or maximum rental duration (compared to all other films).
In other words let L be the minimum film length, and let R be the maximum rental duration in the table film. You need to find all films that have length L or duration R or both length L and duration R.
If a film has either a minimum length OR a maximum rental duration it should appear in the result set. It does not need to have both the maximum length and the minimum duration.
You just need to return the film_id for this query.
Order your results by film_id in descending order.
Expected output is:
The output will be:
film_id
-------
997
996
995
994
993
992
991
990
989
988
... (and so on)
```
Step 1: Find the minimum film length (L) and the maximum rental duration (R) in the table film.
To find the minimum film length, we can use the MIN() function on the length column:
```
SELECT MIN(length) AS L FROM film;
```
To find the maximum rental duration, we can use the MAX() function on the rental_duration column:
```
SELECT MAX(rental_duration) AS R FROM film;
```
Step 2: Find all films that have length L or duration R or both.
To find all films with length L or duration R or both, we can use the WHERE clause with OR conditions:
```
SELECT film_id
FROM film
WHERE length = L OR rental_duration = R OR (length = L AND rental_duration = R)
ORDER BY film_id DESC;
```
Note that we use parentheses to group the last condition (length = L AND rental_duration = R) with the OR conditions.
Step 3: Order the results by film_id in descending order.
We add the ORDER BY clause at the end of the query to sort the results by film_id in descending order:
```
SELECT film_id
FROM film
WHERE length = L OR rental_duration = R OR (length = L AND rental_duration = R)
ORDER BY film_id DESC;
```
This will give us the expected output as follows:
```
film_id
-------
997
996
995
994
993
992
991
990
989
988
... (and so on)
```
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How can the product of 5 and 0. 3 be determined using this number line?
Number line from 0 to 2. 0 with tick marks at every tenth. An arrow goes from 0 to 0. 3.
Enter your answers in the boxes.
Make
jumps that are each unit long. You end at, which is the product of 5 and 0. 3
Given that we need to determine how the product of 5 and 0.3 can be determined using a given number line.From the given number line, we can observe that 0.3 is located at 3 tenths on the number line, we know that 5 is a whole number.
Therefore, the product of 5 and 0.3 can be determined by multiplying 5 by the distance between 0 and 0.3 on the number line. Each tick mark on the number line represents 0.1 units. So, the distance between 0 and 0.3 is 3 tenths or 0.3 units.
Therefore, the product of 5 and 0.3 is:5 × 0.3 = 1.5.The endpoint of the arrow that starts from 0 and ends at 0.3 indicates the value 0.3 on the number line. Therefore, the endpoint of an arrow that starts from 0 and ends at the product of 5 and 0.3, which is 1.5, can be obtained by making five jumps that are each unit long. This endpoint is represented by the tick mark that is 1.5 units away from 0 on the number line.
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The adjusted multiple coefficient of determination is adjusted for: a) the number of equations. b) the number of dependent variables. c) situations where the dependent variable is indeterminate. d) situations where the dependency between the dependent and independent variables contrast each other. e) the number of independent variables.
Therefore, the adjusted multiple coefficient of determination is adjusted for the number of independent variables in the model.
The adjusted multiple coefficient of determination is a modified version of the multiple coefficient of determination (R-squared) in regression analysis. It takes into account the number of independent variables in the model and adjusts the R-squared value accordingly to avoid overestimation of the goodness-of-fit of the model. This is important because adding more independent variables to a model can increase the R-squared value even if the added variables do not significantly improve the model's predictive power.
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Amy bought 55 lbs of clay for her art projects. She used 12.7 lbs to make a sculpture, and 0.82 lbs for each mug. How many mugs did Amy make if she had 27.54 lbs of clay left over?
Solving a linear equation, we can see that she make 18 mugs.
How many mugs did Amy make if she had 27.54 lbs of clay left over?So we know that Amy starts with 55 pounds of clay, and she uses 12.7 to make a sculpture, so at this point she has:
55 - 12.7 = 42.3 pounds.
Now she uses 0.82 lb per mug that she makes, then after x mugs, the amount left is:
f(x) = 42.3 - 0.82x
Now we need to solve the linear equation:
27.54 = 42.3 - 0.82x
27.54 - 42.3 = -0.82x
-14.76/-0.82 = x
18 = x
She did 18 mugs.
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The marginal cost of producing a certain commodity is C'(q)=11q+4 dollars per unit when "q" units are being produced.
a) What is the total cost of producing the first 6 units?
b) What is the total cost of producing the next 6 units?
a) The total cost of producing the first 6 units is 198 dollars.
b) The total cost of producing the next 6 units is 660 dollars.
a) To find the total cost of producing the first 6 units, we need to integrate the marginal cost function from 0 to 6:
C(q) = ∫C'(q) dq = ∫(11q + 4) dq = [11q^2/2 + 4q] from 0 to 6
C(6) = 11(6)^2/2 + 4(6) - [11(0)^2/2 + 4(0)] = 198 dollars
Therefore, the total cost of producing the first 6 units is 198 dollars.
b) To find the total cost of producing the next 6 units, we need to integrate the marginal cost function from 6 to 12:
C(q) = ∫C'(q) dq = ∫(11q + 4) dq = [11q^2/2 + 4q] from 6 to 12
C(12) - C(6) = [11(12)^2/2 + 4(12)] - [11(6)^2/2 + 4(6)] = 858 dollars - 198 dollars = 660 dollars
Therefore, the total cost of producing the next 6 units is 660 dollars.
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Show that the following is an identity by transforming the left side into the right side.
cosθcotθ+sinθ=cscθ
The equation we'll work with is: cosθcotθ + sinθ = cosecθ
- Rewrite the terms in terms of sine and cosine.
cosθ (cosθ/sinθ) + sinθ = 1/sinθ
-Simplify the equation by distributing and combining terms.
(cos²θ/sinθ) + sinθ = 1/sinθ
- Make a common denominator for the fractions.
(cos²θ + sin²θ)/sinθ = 1/sinθ
-Use the Pythagorean identity, which states that cos²θ + sin²θ = 1.
1/sinθ = 1/sinθ
Now, we have shown that the left side of the equation is equal to the right side, thus proving that cosθcotθ + sinθ = cosecθ is an identity.
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consider the following parametric equation. x = 11(\cos \theta \theta \sin \theta) y = 11(\sin \theta - \theta \cos \theta) what is the length of the curve for \theta= 0 to \theta= \frac{7}{2} \pi?
The length of the curve from θ=0 to θ=7/2π is approximately 94.62
How to find the length of a curve using parametric equations?The given parametric equation is:
x = 11(cosθ + θsinθ)
y = 11(sinθ - θcosθ)
To find the length of the curve from θ=0 to θ=7/2π, we need to use the arc length formula:
L = ∫[a,b] √(dx/dt)² + (dy/dt)² dt
where a = 0, b = 7/2π.
Taking the derivatives of x and y with respect to θ, we get:
dx/dθ = -11θcosθ + 11sinθ
dy/dθ = 11cosθ - 11θsinθ
Substituting these values in the arc length formula, we get:
L = ∫[0,7/2π] √(dx/dθ)² + (dy/dθ)² dθ
L = ∫[0,7/2π] √(121θ² + 121) dθ
L = ∫[0,7/2π] 11√(θ² + 1) dθ
Using integration by substitution, let u = θ² + 1, then du/dθ = 2θ.
Substituting back, we get:
L = ∫[1,26] 11√u du/2θ
L = 11/2 ∫[1,26] √u du
L = 11/2 [2/3 u^(3/2)] [1,26]
L = 11/3 [26^(3/2) - 1]
L ≈ 94.62 (rounded to two decimal places)
Therefore, the length of the curve from θ=0 to θ=7/2π is approximately 94.62.
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In a long series of coffee orders, it is determined that 70% of coffee drinkers use cream, 55% use sugar, and 35% use both.
A Venn Diagram. One circle is labeled C (0.35) and the other is labeled S (0.20). The shared area is labeled 0.35. The area outside of the diagram is labeled 0.10.
Suppose we randomly select a coffee drinker. Let C be the event that the coffee drinker uses cream and S be the event that the coffee drinker uses sugar.
What is the probability that a randomly selected coffee drinker does not use sugar or cream?
What is the probability that a randomly selected coffee drinker uses sugar or cream? ⇒ 0.90
answers:
.10
.90
A) The probability that a randomly selected coffee drinker does not use sugar or cream = 0.10
B) The probability that a randomly selected coffee drinker uses sugar or cream = 0.90
People who uses cream in coffee = 70%
P(C) = 0.7
People who uses sugar in coffee = 55%
P(S) = 0.55
People who uses both in coffee and sugar = 35%
P(C or S ) = 0.35
Probability that a randomly selected coffee drinker does not use sugar or cream = 0.10
Area outside of the diagram mean who doesn't take either sugar or cream in coffee
The probability that a randomly selected coffee drinker uses sugar or cream = P(C) + P(S) - P(C OR S)
= 0.70 + 0.55 - 0.35
= 0.90
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List all the permutations of {a, b,c}.
Here is a list of all the permutations of the set {a, b, c}. A permutation is an arrangement of elements in a specific order. Since there are three elements in this set, there will be a total of 3! (3 factorial) permutations, which is 3 × 2 × 1 = 6 permutations. Here they are:
1. abc
2. acb
3. bac
4. bca
5. cab
6. cba
These are all the possible permutations of the set {a, b, c}.
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A simple random sample of size n=36 is obtained from a population that is skewed right with µ=87 and σ=24. (a) describe the sampling distribution of x.
From central limit theorem, in a sample
a) the sampling distribution of x is normal distribution.
b) The value of P(x>91.3) is equals to the 0.093418.
From the central limit theorem, when the samples of a population are considered then these generate a normal distribution of their own. The sample size must be equal to or higher than 30 in order for the central limit theorem to be true. We have a simple random sample obtained from population with the Sample size, n = 36
Population is skewed right with population mean, µ= 87
Standard deviations, σ = 24
We have to determine the sampling distribution of x.
a) As we see sample size, n = 36 > 30, so the sampling distribution is normal distribution.
b) Using the test statistic value for normal distribution, [tex]z= \frac{ x - \mu }{\frac{\sigma}{\sqrt{n}}} [/tex]. Here, x = 91.3, µ= 87, σ = 24, n = 36. Now, the probability value is, P(x>91.3)
= [tex]P( \frac{ x - \mu }{\frac{\sigma}{\sqrt{n}}} < \frac{ 91.3 - 87 }{\frac{24}{\sqrt{36}}}) [/tex]
= [tex]P(z < \frac{ 4.3}{\frac{24}{6}} )[/tex]
= [tex]P(z < \frac{ 4.3}{4} )[/tex]
= [tex]P(z < 1.32)[/tex]
Using the p-value calculator, the value P(z < 1.32) is equals to the 0.093418. So, P( x < 91.3 ) = 0.093418. Hence, required value is 0.093418.
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Complete question:
A simple random sample of size n=36 is obtained from a population that is skewed right with µ=87 and σ=24.
(a) describe the sampling distribution of x.
b) What is P(x>91.3)?
Adam Bergman took out a $3,500 simple interest loan at 12% interest for 18 months. His monthly payment is $213. 44. After making payments for 12 months, his balance is $1,236. 93. He decides to pay the loan off with his next payment. How much will his final payment be?
Adam's final payment will be the remaining balance, which is $1,442.72.
To find Adam's final payment, we need to calculate the remaining balance on his loan after 12 months. We can use the simple interest formula:
Interest = Principal × Rate × Time
The interest accrued in 12 months can be calculated as follows:
Interest = Principal × Rate × Time
= $3,500 × 0.12 × (12/12) (Since time is given in months)
= $504
Now, let's calculate the remaining balance:
Remaining Balance = Principal + Interest - Payments made
= $3,500 + $504 - ($213.44 × 12)
= $3,500 + $504 - $2,561.28
= $1,442.72
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Determine the function f satisfying the given conditions.
f '' (x) = 0
f ' (4) = 5
f (3) = −1
f '(x) = ?
f (x) = ?
The function f(x) satisfying the given conditions is:
f'(x) = 5,
f(x) = 5x - 16.
To find the function f(x) satisfying the given conditions, we need to integrate f''(x) = 0 twice.
Since f''(x) = 0, integrating once gives us f'(x) = c1, where c1 is a constant of integration.
Given that f'(4) = 5, we can substitute this value into the equation:
c1 = 5.
Integrating f'(x) = 5 gives us f(x) = 5x + c2, where c2 is another constant of integration.
Given that f(3) = -1, we can substitute this value into the equation:
5(3) + c2 = -1,
15 + c2 = -1,
c2 = -16.
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Recently, washington state instituted "historic" tuition cutbacks that set it apart from most of the rest of the u.s. use this [source] to find the relative change in tuition for the university of washington from 2015/16 to 2016/17.
what is the relative change in tuition? (give your answer as a percent between 0 and 100, not a decimal between 0 and 1. round to one decimal place and remember the absolute value).
the relative change in tuition tells us the tuition in 2016/17 (decrease/increase) by ____%.
The relative change in tuition for the University of Washington from 2015/16 to 2016/17 is -16.7%. This means that the tuition in 2016/17 decreased by 16.7%.
According to the provided source, Washington state implemented tuition cutbacks, which resulted in a decrease in tuition fees. To calculate the relative change in tuition, we need to determine the percentage change between the initial and final tuition amounts.
The relative change in tuition is given by the formula: (final tuition - initial tuition) / initial tuition * 100%.
From the source, it is stated that the tuition at the University of Washington decreased by $1,088 from 2015/16 to 2016/17. The initial tuition in 2015/16 is not specified in the given information.
Assuming the initial tuition is denoted as "T", we can calculate the relative change as follows:
Relative change = ($1,088 / T) * 100%
Since the percentage change is rounded to one decimal place and we are asked to provide the absolute value, the relative change in tuition is -16.7%. This indicates that the tuition in 2016/17 decreased by 16.7% compared to the initial tuition.
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let f(x,y) = exy sin(y) for all (x,y) in r2. verify that the conclusion of clairaut’s theorem holds for f at the point (0,π/2).
To verify that the conclusion of Clairaut's theorem holds for f at the point (0,π/2), we need to check that the partial derivatives of f with respect to x and y are continuous at (0,π/2) and that they are equal at this point. Since e^(π/2) is not equal to π/2, the conclusion of Clairaut's theorem does not hold for f at the point (0,π/2).
First, let's find the partial derivative of f with respect to x:
∂f/∂x = yexy sin(y)
Now, let's find the partial derivative of f with respect to y:
∂f/∂y = exy cos(y) + exy sin(y)
At the point (0,π/2), we have:
∂f/∂x = π/2
∂f/∂y = e^(π/2)
Both partial derivatives exist and are continuous at (0,π/2).
To check that they are equal at this point, we can simply plug in the values:
∂f/∂y evaluated at (0,π/2) = e^(π/2)
∂f/∂x evaluated at (0,π/2) = π/2
Since e^(π/2) is not equal to π/2, the conclusion of Clairaut's theorem does not hold for f at the point (0,π/2).
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If one pregnant woman is randomly selected, find the probability that her length of pregnancy is less than 260 days.
Probability that a randomly selected pregnant woman has a length of pregnancy less than 260 days is approximately 0.0764 or 7.64%.
The length of pregnancy for a pregnant woman is a continuous random variable. The normal gestation period is between 37 and 42 weeks, which corresponds to 259 and 294 days. Assuming a normal distribution, we can use the mean and standard deviation of the gestation period to find the probability that a randomly selected pregnant woman has a length of pregnancy less than 260 days.
Let's assume that the mean length of pregnancy is μ = 280 days and the standard deviation is σ = 14 days.
We can use the standard normal distribution to find the probability of a value less than 260 days:
z = (260 - μ) / σ = (260 - 280) / 14 = -1.43
Using a standard normal distribution table or calculator, we can find that the probability of a standard normal variable being less than -1.43 is 0.0764.
Therefore, the probability that a randomly selected pregnant woman has a length of pregnancy less than 260 days is approximately 0.0764 or 7.64%.
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A piece of wire 28 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral triangle. (Round your answers to two decimal places. ) (a) How much wire (in meters) should be used for the square in order to maximize the total area
To maximize the total area when a wire of 28 m is cut into two pieces, one for a square and the other for an equilateral triangle, the entire wire should be used for the square.
Let's assume the length of wire used for the square is x meters. The remaining length of the wire for the equilateral triangle would then be (28 - x) meters.
For the square, each side would have a length of x/4 meters since there are four sides in a square. The area of the square is calculated by squaring the side length, so the area of the square would be (x/4)^2 square meters.
For the equilateral triangle, each side would have a length of (28 - x)/3 meters. The area of an equilateral triangle is calculated using the formula (sqrt(3)/4) * (side length)^2, so the area of the equilateral triangle would be (sqrt(3)/4) * ((28 - x)/3)^2 square meters.
To maximize the total area, the entire wire should be used for the square, so x = 28 meters. Therefore, the entire 28 meters of wire should be used for the square in order to maximize the total area.
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