For reaction: 2 C + O2 --> 2 CO2 If 5.50 g C was reacted with enough O2, what would be the volume (in liter) of the CO2 generated at STP? (0 C and 1 atm)

Answer:

Here's what I get from one source.

Explanation:

[tex]\begin{array}{lc}\textbf{Source} &\textbf{Contribution \%} \\\text{Space heating }& 45\\\text{Water heating} &18\\\text{Space cooling} & 9 \\\text{Computers/Electronics} & 6 \\\text{Lighting} & 6 \\\text{Cooking} & 4 \\\text{Refrigeration} & 4 \\\text{Wet cleaning} & 3 \\\text{Other} & 5 \\\end{array}[/tex]

The pie chart is in the Figure below.

The single mark placed on the sidewalk by Julie has been acting as the reference point for detecting the motion of the snail. Thus, option D is correct.

The snail has been the shelled animal that has been mostly residing in the resting condition with limited movement. To evaluate the movement of the snail, there has been the consideration of a point that was the starting point from the movement.

The line that has been set across the sidewalk has been acting as the reference, and the distance traveled has been calculated from that point. Thus, option D is correct.

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Carbon 14 would be your answer, however if it's more than one answer it would also be Carbon 12, so yeah. Your best bet would be Carbon 14.

Answer:

25 g

Explanation:

Mass percent implies the mass of solute dissolved in a solution

Mass percent = mass of solute/mass of solute + mass of solvent × 100/1

Since mass percent concentration= 20%

Mass of solvent = 100g

Let mass of solute = x

Hence;

20 = x/x +100 ×100/1

20/100= x/x + 100

0.2 = x/x + 100

0.2(x + 100) = x

0.2x + 20 = x

20 = x - 0.2x

20 = 0.8x

x= 20/0.8

x= 25 g

Answer:

The solubility of KCl is 1.93 mol/dm³

Explanation:

The information given are;

The mass of the potassium chloride, KCl = 144 g

The volume of the water solvent = 1000 cm³ = 1 dm³

The temperature of the solvent = 90 °C

The atomic mass of potassium, K = 39 u

The atomic mass of chlorine, Cl = 35.5 u

The number of moles of potassium in one mole of potassium chloride, KCl = 1 mole

The number of moles of chlorine in one mole of potassium chloride, KCl = 1 mole

The molar mass of the potassium chloride = 39 + 35.5 = 74.5 g/mol

The number of moles, n, of potassium chloride, KCl in 144 g of potassium chloride, KCl is given as follows

n = Mass/(Molar mass) = 144/74.5 = 1.93 moles

1.93 moles will dissolve in 1 dm³

Therefore, the solubility of KCl is 1.93 mol/dm³.

Answer:

D. two-stroke cylinder engine.

Explanation:

Two-stroke cylinder engine: In chemistry, the term "two-stroke cylinder engine" is described as one of the types of "internal combustion engine" that tends to complete a single "power cycle" possessing two different strokes of the "piston" during a particular "crankshaft revolution".

It generally consists of two different strokes that are being often known as power or exhaust and suction stroke.

In the question above, the given statement signifies the "two-stroke cylinder engine".

Answer:

Option B. K = 1.3×10⁴, product favored

Explanation:

Data obtained from the question include:

O2(g) + 2SO2(g) <==> 2SO3(g)

Concentration of O2, [O2] = 0.024 M

Concentration of SO2, [SO2] = 0.015 M

Concentration of SO3, [SO3] = 0.26 M

Equilibrium constant, K =..?

The equilibrium constant, K is simply defined as the ratio of the concentration of products raised to their coefficient to the concentration of the reactants raised to their coefficient.

The equilibrium constant for the above reaction can be written as

K = [SO3]² / [O2] [SO2]²

Inputing the values of [SO3], [O2] and [SO2] the equilibrium constant, K is:

K = [SO3]² / [O2] [SO2]²

K = 0.26² / 0.024 × 0.015²

K = 1.3×10⁴

Therefore, the equilibrium constant K is 1.3×10⁴.

Since the value of the equilibrium constant, K is large and positive, therefore, the reaction favours the product.

Answer:

if your eyes are exposed to a hazardous chemical you should use the eye wash station. The first few seconds after exposure to a hazardous chemical are critical.

Answer:

the melting point T = 125.36°C

Explanation:

Given that:

The resistance of a platinum thermometer at  0°C is  [tex]R_o[/tex] = 160.0 ohms

The resistance of a platinum thermometer when immersed in a crucible containing a melting substance [tex]R_t[/tex] = 243.8 ohms

The temperature coefficient at room temperature  20°C = ∝ = 0.00392

The objective is to determine the melting point of this substance

To do that ; at 20°C, the resistance of the platinum thermometer can be calculated as follows:

[tex]R_{20} = R_o(1 + \alpha \Delta T)[/tex]

[tex]R_{20} = 160(1 + (0.00392 \times (20-0)^0C))[/tex]

[tex]R_{20} = 160(1 + (0.00392 \times (20))[/tex]

[tex]R_{20} = 160(1 + (0.0784)[/tex]

[tex]R_{20} = 160(1.0784)[/tex]

[tex]R_{20} = 172.544 \ ohms[/tex]

The resistance of the platinum thermometer at t°C , [tex]R_t[/tex] = [tex]R_{20}(1 + \alpha \Delta T)[/tex]

[tex]243.8 = 172.544(1 + 0.00392 \times (T-20)^0C}[/tex]

[tex]\dfrac{243.8}{ 172.544 }= (1 + 0.00392 \times (T-20)^0C}[/tex]

[tex]1.413 = (1 + 0.00392 \times (T-20)^0C}[/tex]

[tex]1.413-1 = 0.00392 \times (T-20)^0C}[/tex]

[tex]0.413 = 0.00392 \times (T-20)^0C}[/tex]

[tex]\dfrac{0.413 }{0.00392} = (T-20)^0C}[/tex]

105.36°C = (T - 20) °C

T = 105.36°C + 20 °C

T = 125.36°C

Answer:

Spraying perfume in one corner of the room and the smell travels to the other side of the room

Explanation:

The nuclei of atoms become unstable when the repelling forces of the protons cannot be balanced by the number of neutrons in the nucleus. It then re-arranges itself randomly to a more stable configuration by emitting any of a series of particles. During radioactive decay, an atom does not collapse.

Since an atom is mostly empty space - that is it’s nucleus is relatively distant from the electron shells so, in the presence of extreme forces such as gravity inthe collapse of a large star, the inward pressures on the atom overcome the natural balance of the atomic structure and the ‘empty space’ disappears as nuclei are mashed together by the intense pressures and a neutron star is formed. Under even more external pressure, even the neutron star can collapse to form a black hole.

Bohr describe the arrangement of particles within an atom by: O D. Protons and neutrons form the nucleus of the atom, with electrons orbiting it.

This hypothesis states that the atom's core is a small, compact, positively charged nucleus. Protons which have a positive charge and neutrons which are neutral are both found in the nucleus.

Specific energy levels or electron shells are where the negatively charged electrons orbit the nucleus. Due to the quantization of these energy levels, only a limited number of discrete energy states are accessible to electrons.

Therefore the correct option is D.

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[tex]7.408 \;X 10 ^ {-3} m^{-2} s^{-1}[/tex]  is rate of a reaction when k = 0.2, [A] = 3 M, [B] = 3 M, m = 1, n = 2 .

The rate at which the concentration of reactant or product participating in a chemical reaction alters is called the rate of reaction.

Rate of reaction = [tex]\frac{change \;in \;concentration}{time}[/tex] =  (mol/litre)/time.

m= 1 and n = 2

[tex]rate = K [A] [B]^2[/tex]

[tex]0.2 = K X 3 X 3 ^2[/tex]

K =   [tex]\frac{0.2 }{27 }[/tex]

K =   [tex]7.408 \;X 10 ^ {-3} m^{-2} s^{-1}[/tex]

Hence, [tex]7.408 \;X 10 ^ {-3} m^{-2} s^{-1}[/tex]  is rate of a reaction when k = 0.2, [A] = 3 M, [B] = 3 M, m = 1, n = 2 .

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Answer: 7.4 10-3

Explanation:

7.4 10-3 this is right ong

Answer:

B. reflection

Explanation:

Rigid transformations are methods involved in changing the dimensions or orientation of a given figure. The methods are; dilation, rotation, translation and reflection.

Reflection is the process in which a given figure is turned or flipped with respect to a point or line of reference.

In the given question,

ΔDEF ≅ ΔD'EF' (Side-Side-Side congruence property)

This implies that ΔDEF was reflected about point E to produce ΔD'EF'. Thus the required rigid transformation is reflection.

Answer:

Is C - Rotation

Explanation:

I have right on my test

Answer:

Blue wave.

Explanation:

Answer:

The correct option is;

The reaction pathway for the trials is different

Explanation:

The effect of a catalyst in a chemical reaction is to increase the rate of a reaction by changing the pathway or mechanism of the reaction and/or to lower the transition state's energy thereby lowering the activation energy of the reaction

The pathway of the reaction is changed by the catalyst by the formation of intermediate compounds by the catalyst which require lower activation energy to form the products than the original non-catalyzed reactants. In the process the catalyst is regenerated, thereby, not taking part in the reaction.

Answer:

Concept of chemi-fluorescence

Explanation:

A glow stick usually consists of two chemicals in a larger plastic tube: , a base catalyst (mostly sodium salicylate), and a suitable dye (sensitizer, or fluorophor). This creates an exergonic reaction when mixed together.

When a glow stick is bent, the flurophor which is a chemical that easily re-emits light upon excitation in smaller capsules is released into the other substance, there by causing it to emit radiation/light in the uv-visible region. The brightness and longevity of the glow stick is determined by varying the concentration of these chemicals.

I hope this explanation clarifies things.

Answer:

See explanation

Explanation:

Charles law gives the relationship between volume and temperature of a gas. Charles law States that, the volume of a given mass of gas is directly proportional to its temperature at constant pressure.

Theoretically, it is assumed that when the absolute zero temperature has been achieved, the volume of any ideal gas will be found to be equal to zero. If the volume of the gas is zero, it now implies that all molecular motion will be stopped. This does not happen in real gases as all gases are found to condense to solids or liquids when this temperature is exceeded.

When volume is plotted against temperature, volume of the gas approaches zero at t = −273.15 °C, which is the x-intercept of the Charles law graph. Below this temperature, we can only get negative values of volume which does not exist hence, −273.15 °C is the lowest attainable temperature also known as the absolute zero.

Answer:  [tex]CH_3CH_2CH_2CHO[/tex] has aldehyde functional group.

Explanation:

Functional groups are specific group of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules.

A.  [tex]CH_3CH_2CH_2COCH_3[/tex] has ketone [tex]C=O[/tex] functional group .

B.  [tex]CH_3CH_2CH_2COOH[/tex] has carboxylic acid [tex]COOH[/tex] functional group .

C.  [tex]CH_3CH_2CH_2CHO[/tex] has  aldehyde [tex]H-C=O[/tex] functional group .

D. [tex]CH_3CH_2CH_2COOCH_3[/tex] has ester [tex]RO-C=O[/tex] functional group .

Thus [tex]CH_3CH_2CH_2CHO[/tex] has aldehyde (CHO) group.

Answer:

Ankara is the capital of Turkey! Hope this helped you out! :)

Explanation:

The capital of Turkey is Ankara

hopefully this helped :3

Answer:

d

Explanation:

i got it right

Gas A is likely to have the lowest temperature.  Hence, option A is correct.

The smallest particle of a substance has all of the physical and chemical properties of that substance. Molecules are made up of one or more atoms.

In a gas, the kinetic energy is directly proportional to the temperature under constant pressure and volume.

As you can see in the problem, the average of A has low kinetic energy. But the average is increasing between B, C and D.

As gas A has the lowest average kinetic energy:

Gas A is likely to have the lowest temperature

Hence, option A is correct.

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Answer:

C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O

Explanation:

Let's start by counting how many molecules we have on each side.

Reactants

C - 5

H - 12

O - 2

Products

C - 1

O - 3

H - 2

We have to balance both sides. Since we have 5 carbon atoms on the reactants side and 1 carbon atom on the products side, we'll start with that. Write 5 as the coefficient for CO₂ to balance the carbons.

C₅H₁₂ + O₂ → 5CO₂ + H₂O

Now that the carbons are balanced, let's look at the hydrogens. There's 12 on the reactants side and 2 on the products side. To balance the hydrogens, we have to write 6 as the coefficient for H₂O.

C₅H₁₂ + O₂ → 5CO₂ + 6H₂O

Now the hydrogens are balanced. All that's left to do is balance the oxygens. Let's start by counting how many atoms we have on each side.

Reactants

C - 5

H - 12

O - 2

Products

C - 5

H - 12

O - 16

So, to balance the number of atoms on both sides, write 8 as the coefficient for O₂.

C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O

Lastly, let's check to make sure everything is balanced.

Reactants

C - 5

H - 12

O - 16

Products

C - 5

O - 16

H - 12

Both sides are balanced. Therefore, the balanced chemical equation is: C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O.

Hope that helps.

Answer:

[tex]\boxed{C_{5}H_{12} + 8O_{2} -->5CO_{2} + 6H_{2}O}[/tex]

Explanation:

Part 1: Count the number of atoms on each side per element

To start, count the number of atoms per element on both sides of the equation.

Left Side

C - 5 atoms

H - 12 atoms

O - 2 atoms

Right Side

C - 1 atom

H - 2 atoms

O - 3 atoms

Part 2: Balance carbon atoms

Now, with this information, you can begin finding out how to properly balance both sides of the equation.

You need 5 carbon atoms on the left, so place a coefficient of 5 in front of the [tex]CO_{2}[/tex] product. This will balance the carbons. Do not place a coefficient in front of the [tex]C_{5}H_{12}[/tex] reactant - none are necessary!

Then, you can update your counts for your atoms.

Left Side

C - 5 atoms

H - 12 atoms

O - 2 atoms

Right Side

C - 5 atoms

H - 2 atoms

O - 11 atoms

The updated equation will look like this:

[tex]\boxed{C_{5}H_{12}+O_{2} --> 5CO_{2} + H_{2}O}[/tex]

Part 3: Balance hydrogen atoms

Now, balance the hydrogen atoms. Place a coefficient of 6 in front of the [tex]H_{2}O[/tex] product. This will balance the hydrogen atoms.

Once again, update the atom counts:

Left Side

C - 5 atoms

H - 12 atoms

O - 2 atoms

Right Side

C - 5 atoms

H - 12 atoms

O - 16 atoms

The updated equation will look like this:

[tex]\boxed{C_{5}H_{12} +O_{2}--> 5CO_{2} +6H_{2}O}[/tex]

Part 4: Balance oxygen atoms

To fully balance the equation, place a coefficient of 8 in front of the [tex]O_{2}[/tex] reactant. This will equalize the amount of oxygen atoms on both sides of the equation.

The updated equation will look like this:

[tex]\boxed{C_{5}H_{12} + 8O_{2} --> 5CO_{2} + 6H_{2}O}[/tex]

Part 5: Check the equation and atom counts

Now, update the atom counts one last time to make sure they are equal.

Left Side

C - 5 atoms

H - 12 atoms

O - 16 atoms

Right Side

C - 5 atoms

H - 12 atoms

O - 6 atoms

They are equal, so you may proceed.

Part 6: Check if reductions are necessary

If the equations coefficients can all be divided by a common divisor (i.e., 3), follow up with that step. However, any equation that has a reactant or product without a coefficient, skip this step entirely.

This equation falls into that category, so you may proceed past it.

Your final equation will look like this: [tex]\boxed{C_{5}H_{12} + 8O_{2} -->5CO_{2} + 6H_{2}O}[/tex]

Answer:

neutrons :

Explanation:

Protons are positively charged, while electrons are negatively charged. Neutrons are electrically neutral, as the name suggests. The electric charge, noted Q , is a physical quantity.

Answer:

Na3 Po4

Explanation:

Na+1

Na+1

Na+1 = Na3

Po4 =

Na3Po4

Na[tex]_3[/tex]Po[tex]_4[/tex] is the formula for sodium phosphate. Sodium phosphates have a wide range of uses in food and water treatment.

Sodium phosphate is indeed a catch-all phrase for a number of sodium (Na+) as well as phosphate (PO43) salts. Phosphate also forms di-, tri-, tetra-, as well as polyphosphate families or condensed anions. The majority of these salts exist across both anhydrous (water-free) as well as hydrated forms. Hydrates are more prevalent than anhydrous forms.

Sodium phosphates have a wide range of uses in food and water treatment. Sodium phosphates, for example, are frequently employed particularly emulsifying agent (as in processed cheese), smoothing agents, especially leavening agents in baked products. Na[tex]_3[/tex]Po[tex]_4[/tex] is the formula for sodium phosphate.

Therefore, Na[tex]_3[/tex]Po[tex]_4[/tex] is the formula for sodium phosphate.

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Answer:

A. increased competition for resources

Explanation:

Answer:

0.020g de sulfato de plomo se requieren

La concentración de la solución diluida es de 3ppm

Explanation:

Las partes por millón (ppm) son definidas como:

miligramos soluto / 1L solución.

Si deseas preparar una solución a 100ppm de sulfato de plomo (II) necesitas 100mg de este sulfato en 1L. En 200mL = 0.200L vas a necesitar:

0.200L × (100mg / 1L) = 20mg de sulfato de plomo (II).

Como 1000mg = 1g,

20mg × (1g / 1000mg) = 0.020g de sulfato de plomo se requieren.

Ahora, se van a tomar 30mL de esta solución y se diluirán a 1000mL. Se diluye la solución:

1000mL / 30mL = 33.33 veces.

Como la solución inicial es de 100ppm, esta dilución genera una solución de concentración:

100ppm / 33.33 = 3ppm

Answer:

A

Explanation:

civil deals with desighning, construction work of natural or physical environment and a fits guess

Answer:

Protons and neutrons have almost the same mass and are both located in the nucleus of the atom

Answer:

Protons and neutrons have almost the same mass and are both located in the nucleus of the atom. Protons are charged particles. Neutrons are neutral particles. ... The positive charge of the protons in the nucleus is balanced by the negative charge of the electrons.

The two terms apply to oceanic crust rather than continental crust C. Denser and D. Younger in age

Oceanic Crust Oceanic crust, extending 5-10 kilometers (3-6 kilometers) beneath the ocean floor, is mostly composed of different types of basalts. Geologists often refer to the rocks of the oceanic crust as “sima.” Sima stands for silicate and magnesium, the most abundant minerals in oceanic crust.

Oceanic crust is thin (6 km thick) and dense (about 3.3 g/cm), consisting of basalt, gabbro, and peridotite. They include oceanic sediments (e.g. radiolarites, turbidites) and oceanic crust (e.g. basalt, pillow lava).

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