for laminar flow of air over flat plates with uniform surface temperature, the curve that most closely describes how the average heat transfer coefficient changes with the length of the plate is

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Answer 1

For a laminar airflow over flat plates with a constant surface temperature, the curve that best represents how the average heat transfer coefficient declines with plate length increases.

In fluid dynamics, laminar flow is characterized by fluid particles passing each other in layers along straight paths with little to no mixing in between. When the fluid is traveling at moderate speeds, it tends to Laminar flow without lateral mixing, which causes adjacent layers to slip past one another like playing cards. The heat transfer coefficient measures the convective heat transfer between a fluid medium (a fluid) and the surface (a wall) it flows over. The Newton-Richmann relation shows the heat transfer coefficient as a proportionality factor.

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the aorta carries blood away from the heart and eventually branches into a large number of capillaries that distribute the blood to various body organs. if for an average person, the aorta has a radius of 1.2 cm and blood travels through it at a speed of 36 cm/s and the capillaries have an average radius of 5.0 10-4 cm and blood travels through them at a speed of 0.008 cm/s, determine the approximate number of capillaries in the human body.

Answers

13.7 × [tex]10^{8}[/tex], the approximate number of capillaries in the human body, that are carrying blood from the aorta.

What is Aorta?

A huge, cane-shaped blood channel called the aorta carries oxygen-rich blood to your body. It travels across the chest and belly after beginning in the lower left corner of the heart. Blood arteries leave the aorta along the way and extend to the organs and supporting tissue.

What are the Calculations?

The speed of the blood in the aorta is  v = 35cm/s

the radius of the aorta is r = 1.1 cm

the area of the cross-section of the aorta is A =π[tex](1.1cm^{2} )[/tex]

the speed of the blood in  the capillary v ' = 0.078 cm/s

radius of the capillary is r = 6.3 × [tex]10^{-4}[/tex]cm

Now area of cross-section of capillary is A' = Π[tex](6.3 * 10^{-4}) ^{2}[/tex]

Let  there be N number of capillaries

The volume rate of flow in the aorta is the total sum of the volume rate of flows in the capillaries.

Then  Av  = N*A' *v'

    Π(1.1cm)² (35 cm/s)   = N * (Π[tex](6.3 * 10^{-4}) ^{2}[/tex])* 0.078 cm/s

N = 13.7 × [tex]10^{8}[/tex]

Hence, 13.7 × [tex]10^{8}[/tex], the approximate number of capillaries in the human body, that are carrying blood from the aorta.

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in comparing two unequal forces on a rigid body, is it possible to have the larger force produce less torque than the smaller force?

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Different torques can be generated by the same force. When the force and lever arm are both large, greater torques are generated.

Explain about the torques?

A torque is a linear force's reciprocating rotating counterpart. Distance travelled over a predetermined period of time is referred to as speed. Torque and speed are related to one another inversely in proportion. Numerically describing the torque of a rotating object is done by dividing power by angular velocity.

Torque is the unit of measurement for the force that may rotate an item around an axis. The acceleration of an item in linear kinematics is caused by force. An angular acceleration is caused by torque in a manner similar to this. It follows that torque might be viewed as the rotational counterpart to force.

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an automobile engine provides 508 joules of work to push the pistons and generates 2277 joules of heat that must be carried away by the cooling system. calculate the change in the internal energy of the engine. e

Answers

Answer:

Explanation:

Given:

Q = 2277 J

A = 508 J

__________

ΔU - ?

ΔU = Q - A

ΔU = 2277 - 208 = 2069 J

a novelty clock has a 0.014-kg mass object bouncing on a spring that has a force constant of 1.6 n/m. (a) what is the maximum velocity of the object if the object bounces 3.45 cm above and below its equilibrium position?

Answers

Answer: The maximum velocity of the object if the object bounces 3.45 cm above and below its equilibrium position is 4.62 m/s.

Reason:

The maximum velocity of the object is 4.62 m/s. This can be calculated by using the equation v = sqrt(2 * g * x), where g is the acceleration due to gravity (9.8 m/s2) and x is the displacement from the equilibrium position (3.45 cm), or 0.0345 m.

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what is the wavelength of light that is deviated in the first order through an angle of 15.0 ∘ by a transmission grating having 5000 slits/cm ? assume normal incidence.

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The wavelength of light will be  5.17 x10⁻⁷ m

Since we are given the angle of  15.0, and transmission grating having 5000 slits/cm, for a normal incidence

since we know the diffraction of first-order formula is :

d sineθ =nλ ,and the separation os the slits are : d= 1/N

=>d=1/ 5000  = 2x 10^-6 m

Now subsituing the value of d in the main formula of diffraction, where we get the wavelength of :

λ = dsine θ/ n

since here n is 1

λ=  2x 10 *sine 15.0/ 1

λ = 2x 10^-6 *0.2588   = 5.17 x10⁻⁷ m

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An infinitely long wire carrying a current of 3.10 A is bent at a right angle as shown in the figure. Determine the magnitude and direction of the magnetic field at the point P a distance
a = 23.9 cm
from each leg of the right angle bend.
magnitude ? T
direction ?

Answers

The direction of the magnetic field depends on the direction of the current in the wire.

What is magnetic field?
A magnetic field is indeed a vector field which explains the magnetic influence on moving electrical charges, electric currents, as well as magnetic materials. A force perpendicular to the charge's own motion and the magnetic field acts on it when the charge is moving through a magnetic field. The magnetic field of a permanent magnet pulls on magnetic material like iron and attracts as well as repels other magnets. The three other magnetic effects of paramagnetism, diamagnetism, as well as antiferromagnetism also exert minute forces on "nonmagnetic" materials in a nonuniform magnetic field, though these forces are typically so minute that they can only be discovered by laboratory equipment. Electric currents, like those used in electromagnets, as well as electric fields that change over time produce magnetic fields that surround magnetised materials.

The magnitude of the magnetic field at P can be determined using the equation B = μ0I/2πr, where μ0 is the permeability of free space, I is the current, and r is the distance from the wire. Thus, the magnetic field at P is:
B = (4π x 10-7 T•m/A) x (3.10 A) / (2π x 0.239 m) = 0.817 T
The direction of the magnetic field depends on the direction of the current in the wire. If the current is flowing in the clockwise direction, then the magnetic field will be directed out of the plane of the paper at P. If the current is flowing in the counterclockwise direction, then the magnetic field will be directed into the plane of the paper at P.

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a 2.0 kg , 20-cm-diameter turntable rotates at 140 rpm on frictionless bearings. two 510 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick.
What is the turntable's angular velocity, in rpm, just after this event?

Answers

The turntable's angular velocity, in rpm, just after this event is 39,72 rad/m

How to determine angular velocity?

We can use the law of conservation of angular momentum.

Its a law that states the amount of momentum before and after producing is equal or constant collision.

The equation:

L₁ = L₂

I₁ x ω₁ = I₂ x ω₂

We have,

Mass of the table = 2.0 kg ⇒ m₁

Diameter of the table = 20 cm = 0.2 m ⇒ d, so R = 0.1

Angular speed = 140 rpm = 14.65 rad/s ⇒ ω₁

Mass of the blocks = 520 g = 0.52 kg ⇒ m₂

So,

I₁ x ω₁ = I₂ x ω₂

(½ mR²) ω₁ = (½ mR² + m₁R² + m₂R²)  ω₂

(½ (2.0) (0.1)² (14.65) = (½ (2.0) (0.1)² + (2.0) (0.1)² + (0.52) (0.1)²  ω₂

0.1465 = (0.01 + 0.02 + 0.02 + 0.0052) ω₂

ω₂ = 4.16 rad/s ⇒ 39,72 rad/m

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According to the principle of continuity, the velocity of a fluid multiplied by the cross section through which it flows at one point will equal the product ofA) velocity and cross section at another point.B) velocity and pressure at another point.C) a constraint factor.D) none of the above

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According to the principle of continuity, the velocity of a fluid multiplied by the cross-section through which it flows at one point will equal the product of velocity and cross-section at another point.

The principle of continuity, also known as the continuity equation, is the fluid mechanic's principle. Simply put, what flows into a defined volume over a specified period of time minus what flows out of that volume over that specified period of time must accumulate in that volume. The substance in that volume is depleted if the accumulation's sign is negative.

This is so that our eyes, once they start to follow anything, will keep moving in that direction until they come across another thing or object. A line with an arrow at the end of it, for instance, is a great illustration of the continuity concept.

Note that three conditions must be met for a function to be continuous at a point: At that time, the limit must exist.

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how much net work is required to accelerate it from rest to a rotation rate of 1.00 revolution per 8.00 s ? assume it is a solid cylinder.

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The net work required is equal to (1/2)mr^2 x 1/8 x 360 = 90mr^2.

What is work?
Work in physics is the energy that is transmitted to or from a object when a force is applied along a displacement. In its simplest form, it equals this same product of a force's magnitude and the distance travelled for a constant force directed in the same direction as the motion. When a force is applied, it is said to have a component that moves the point of application, or it is said to have positive work. If the component of a force at the point of application is in the opposite direction of the displacement, the force is said to do negative work.

The net work required to accelerate a solid cylinder from rest to a rotation rate of 1 revolution per 8.00 s is equal to the torque multiplied by the angle of rotation. Since the angle of rotation is 360 degrees, the net work required is equal to the torque multiplied by 360 degrees.

The torque is equal to the moment of inertia of the cylinder multiplied by its angular acceleration. The moment of inertia of a solid cylinder is equal to (1/2)mr^2, where m is the mass of the cylinder and r is its radius. The angular acceleration is equal to the change in angular velocity divided by the time interval. In this case, the angular velocity is 1 revolution per 8.00 seconds, so the angular acceleration is 1/8 rad/s^2.

Therefore, the net work required is equal to (1/2)mr^2 x 1/8 x 360 = 90mr^2.

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a bicycle and ridder together have a momentum of 318 kg*m/s and are moving at 8 m/s l. what is their combined mass?

Answers

Answer: 39.75 kg

Explanation:

p = mv where,

p = momentum

m = mass

v = velocity

Given p=318 kg*m/s

v=8 m/s

therefore, 318=8*m

or, m= 318/8= 39.75

in each figure, a magnet is located beneath a conducting loop and along its central axis. a velocity vector drawn near the magnet indicates that the magnet is moving, and a velocity vector drawn near the loop indicates that the loop is oving. for each case, indicate the direction of the induced current in the wire loop. the clockwise and counterclockwise directions are defined with respect to an observer viewing the loop from below.

Answers

Counterclockwise, Because north pole of magnet is moving towards loop and emf is induced in counterclockwise. b) Clockwise; Because north pole of magnet is moving away from the loop and flux is decreasing through loop so clockwise emf is induced.

Anything that creates a magnetic field is considered to be a magnet. The most noteworthy characteristic of a magnet—a force that pulls on other ferromagnetic elements like iron, steel, nickel, cobalt, etc.—is caused by this invisible magnetic field, which also attracts or repels other magnets.

A piece of equipment built from a substance that has been magnetized and produces a consistent magnetic field is called a permanent magnet. A typical illustration is a fridge magnet used to keep notes on the door of the refrigerator. Ferromagnetic materials are those that are both capable of magnetization and are attracted to magnets strongly (or ferrimagnetic).

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Objects A and B interact with each other via both conservative and nonconservative forces. Let KA and KB be the kinetic energies, U be the potential energy, and Eint be the thermal energy. If no external agent does work on the objects then:
A. KA + U is conserved
B. KA + U + Eint is conserved
C. KA + KB + Eint is conserved
D. KA+KB+Uisconserved
E. KA +KB +U +Eint is conserved

Answers

(D) Since both conservative and non-conservative forces are involved, so the sum of all of them will be conserved. The kinetic energy, potential energy and thermal energy all together is conserved in the system.

What is Kinetic energy?

A moving object or particle has kinetic energy, which depends on both its mass and its rate of motion. The type of motion can be vibration, rotation on an axis, translation (or travel along a path from one place to another), or any combination of these.

What is Thermal energy?

Heat is the transfer of thermal energy, whereas thermal energy is the entire internal energy of a system's temperature.

Hence, the kinetic energy, potential energy and thermal energy all together is conserved in the system.

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according to the special theory of relativity, all laws of nature are the same group of answer choices in all reference frames. in all uniformly moving reference frames. for both linear or circular motion. all of the above none of the above

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According to the special theory of relativity, all laws of nature are the same in all uniformly moving reference frames. Option B.

Einstein's Special Theory of Relativity states that the same laws of physics apply to all inertial frames of reference and that the speed of light is the same for all observers. The basic laws of physics are the same for all inertial frames of reference.

Because otherwise, we wouldn't call it a fundamental law. Call them contingency laws and look for deeper fundamental laws that are invariant under a larger set of symmetries. Describes the propagation of matter and light at high speed. It is based on the constancy of the speed of light and the relativity principle in all inertial frames of reference.

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A force of 570 N keeps a certain ideal spring stretched a distance of 0.900 m.
Part A:
What is the potential energy of the spring when it is stretched 0.900 mm?
Express your answer with the appropriate units.
Part B:
What is its potential energy when it is compressed 9.00 cm?
Express your answer with the appropriate units.

Answers

The potential energy of the spring when it is stretched 0.900 mm is 228 J. The potential energy when it is compressed is 2.88J.

Hooke's law states that the elongation of a material is proportional to the applied stress within the elastic limits of the material.

Using Hooke's law

F = kx

570 = k * 0.9

k = 712.5 N/m

(a) energy at x = 0.8 m

U = 0.5 k x^2 = 0.5* 712.8* 0.8^2

U = 228 J

(b) U = 0.5 * 712.8* 0.09^2

U = 2.887 J

Elastic potential energy is the potential energy released as a result of the deformation of an elastic body. B. Spring extension is stored. This is equal to the work done to stretch the spring, which depends on the spring constant k and the stretched distance. The force exerted by the spring is the restoring force that helps return the spring to its equilibrium length.

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A 2. 00 kg, frictionless block is attached to an ideal spring with force constant 300 n/m. At t = 0 the block has velocity -4. 00 m/s and displacement +0. 200 m away from equilibrium.

Answers

Position of the mass as a function of time is:

x(t) = 0.3829cos(12.247×t +58.511∘) m

When a mass m is connected to a spring of spring constant k the system executes a simple harmonic motion with angular frequency ω =

[tex]\sqrt{k/m[/tex]

The location of the mass at any given time t is given by

x(t) = A cos (ωt+Ф)

Where Ф = Initial phase

A = amplitude

solving our question:

mass of block m = 2 kg

spring constant k = 300 n/m

At t = 0, the velocity of the block v(0) = -4.00m/s

displacement x(0) = -0.200 m

angular frequency w = [tex]\sqrt{k/m[/tex] = 300/2 = 12.247 [tex]radian^{-1[/tex]

So, position of the mass at time t is written as

x(t) = A cos ( 12.247×t+Ф)

     0.2 = A cosФ

and v(t) = -12.247×A×sin(12.247 t +Ф)

-4 = -12.247 A sinФ

A sinФ = 0.3266

squaring and adding the two equations

[tex]A^{2}[/tex] = [tex]0.3266^{2}[/tex] + [tex]0.2^{2}[/tex]

and cosФ = 0.2/0.3829

Ф = 58.511

Therefor position of the mass is

x(t) = 0.3829cos(12.247×t +58.511∘) m

The given question is incomplete, the complete question is

A 2.00-kg, frictionless block is attached to an ideal spring with force constant 300 N/m. At t = 0, the block has velocity -4.00 m/s and displacement +0.200 m. Write an equation for the position as a function of time.

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a block of mass 100kg falls down a waterfall. the waterfall is 5m high. calculate: a) the potential energy of the block at the top of the waterfall. b) the kinetic energy of the block at the bottom of the waterfall. c) the magnitude of the velocity of the block at the bottom of the waterfall.

Answers

(a) Potential energy can be calculated using the formulae

[tex]P= mgh[/tex]

where,

[tex]m[/tex] is the mass of block

[tex]g[/tex] is acceleration due to gravity

[tex]h[/tex] is height

Therefore,

[tex]P= (100)(9.8)(5)[/tex]

[tex]P=4900[/tex]

(b) Kinetic Energy can be calculated using the formulae

[tex]\frac{1}{2} mv^{2}[/tex]

for this velocity ([tex]v[/tex]) can be calculated using

[tex]v=\sqrt{2gh}[/tex]

[tex]v=\sqrt{(2)(9.8)(5)}[/tex]

[tex]v=9.899[/tex]

now,

[tex]k=\frac{1}{2}mv^{2}[/tex]

[tex]k=-\frac{1}{2}(100)(9.8)^{2}[/tex]

[tex]k=-5000J[/tex]

(c) Velocity ([tex]v[/tex]) can be calculated using

[tex]v=\sqrt{2gh}[/tex]

[tex]v=\sqrt{(2)(9.8)(5)}[/tex]

[tex]v=9.899[/tex]

What is Potential energy?

Potential energy is a type of energy that results from a change in position or state.

What is kinetic energy?

The kinetic energy of something is the amount of work it can do due to its motion.

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A 45. 0 kg woman stands up in a 60. 0 kg canoe 5. 00 m long. She walks from a point 1. 00 m from one end to a point 1. 00 m from the other end (fig. P8. 92). If you ignore resistance to motion of the canoe in the water, how far does the canoe move during this process?.

Answers

The distance that the canoe moves in this process is 1.29 meters.

We first have to find the center of mass

X = MsXs + McXc/ Mw+Mc

Where

Ms = Woman's mass = 45

Mc = Canoe's mass = 60kg

Xs = position from left= 1 cm

Xc = position from left end of canoe's mass = 2.5cm

When we put these values into the equation we have:

X= 1.857

The center of gravity lies at the center of this boat. Therefore,

3.14 metres

To get the distance that is moved by this canoe distance = 3.143-1.857

= 1.286

≈ 1.29 meters

Thus, The distance that the canoe moves in this process is 1.29 meters.

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if the collision is elastic, what are the final velocities v1 and v2 of particles 1 and 2? give the velocity v1 of particle 1 followed by the velocity v2 of particle 2, separated by a comma. express each velocity in terms of v.

Answers

Velocities V1 and V2 will exchange in general. Velocity may increase or decrease. If V1 decreases, then V2 increases. The angle between velocities also gets changed.

For a head-on elastic collision for two equal masses, the velocities gets exchanged. For a non-head-on elastic collision for two equal masses, the angle between the velocities is always 90 degrees.

Where the projectile is much heavier than the target, the velocity of the given target particle changes to about twice that of the projectile after the collision. And the projectile velocity will remain unchanged. In this case, the angle between the projectile and the target remains less than 90 degrees.

In the case of a head-on elastic collision, when there is a small projectile and a much more heavy target, the projectile will bounce back with the same speed, and the massive target will gain a very small velocity. In this case, the angle of the path of the projectile will be more than 90 degrees.

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on a keyboard, you strike middle c, whose frequency is 256 hz. a) what is the period of one vibration of this tone? (in ms)

Answers

The period of the vibration is 3.9ms

What is Period of a vibration?

The period (T) of a vibration is the time to complete one oscillation or revolution and is measured in seconds. The period of vibration is given as

T= 1/F

For example, if the period of a vibration is 0.1 second (one vibration takes 0.1 second), then the frequency of the vibration is 1/0.1=10 vibrations per second or 10 hertz.

Similarly if the frequency of a vibration is 256hz, the period T= 1/F= 1/256=0.0039s

1second= 1×10³ms

therefore 0.0039s = 0.0039×10³= 3.9ms

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the shanghai maglev train takes 8 minutes to travel a distance of 30.5 kilometres.work out the average speed of the train. give your answer in kilometres per hour.

Answers

The average speed is 228.75 km/h.

What is speed?

Speed is the time rate at which an object is travelling along a route. To put it another way, velocity is a vector, whereas speed is a scalar value.

What is the speed-distance formula?

Speed is equal to distance traveled and time spent.

Distance is determined by multiplying the time and the speed.

Time is determined by speed and distance.

Given:

Distance = 30.5 kilometers

Time= 8 minutes

= 8/60 hour = 2/15 hour

Now, average speed equals distance / time.

= 30.5 x 15/2

= 228.75 Km/ h

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light inside an optical fiber tube hits the wall between the tube and air. we find that if the incident light makes and angle of 30 degrees with respect to the tube wall it is totally internally reflected, but if the angle is greater, it is not. what is the index of refraction of the tube?

Answers

The total internal reflection is the complete reflection of a ray of light within a medium such as water or glass from the surrounding surfaces back into the medium. The phenomenon occurs if the angle of incidence is greater than a certain limiting angle, called the critical angle.

This is an internal total reflection exercise, the equation that describes this process is

        sin θ = n₂ / n₁

where n₂ is the index of the incident medium and n₁ the other medium must be met n₁> n₂

       θ = sin⁻¹ n₂ / n₁

let's calculate

      30⁰ = sin⁻¹ (n₂ / n₁)

Therefore, if the angle is greater then the totally internal reflection also increases.

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(a) find the work done by f in moving an object from a point p1 along a path to a point p2 in terms of the distances d1 and d2 from these points to the origin. (b) an example of an inverse square field is the gravitational field f

Answers

The strength of gravitational or electrostatic fields is frequently determined using the inverse square law as an illustration, the Earth's surface has a gravitational field strength of about 9.8 N/kg.

Take note that the field F(r) is a vector along the ray passing through each point in space with the coordinates r=(x, y, z) and coming from the coordinate center. So you can visualize the entire field as a blast from a single central point. Picture two points A and B on a sphere with radius |A| that are both located at the same distance from 0 and a path that connects them. You would expend no energy to move a particle along this path because you are always orthogonal to the force's direction. Work accounted for is the work along the path from distance |P2| to distance |P1| along this ray. For all intents and purposes, the points P1 and P2 can be located on the same ray emanating from the origin (while preserving only their distances from it). This is conservative as per physics forums.

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what do we mean by dimension in the context of relativity? what do we mean by dimension in the context of relativity? the number of sides that we can see when we look at an object the size of an object the letter used to represent length mathematically the number of independent directions in which movement is possible

Answers

The number of independent directions in which movement is possible  dimension in the context of relative motion.

To discuss relative motion in one or more dimensions, the idea of reference frames was initially developed. When we refer to an object's velocity, we are referring to it in relation to the so-called reference frame. When measuring an object's velocity in daily life, the ground or the earth is assumed to be the reference frame.

As an illustration, if you are travelling in a train that is moving at 100 km/h, then from the perspective of another passenger in the train, you are moving at a speed of zero. He says you're standing still. However, if a bystander sees you standing on the ground outside the train, he claims that you are going with the train.

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At a construction site, a 22.0 kg bucket of concrete is connected over a very light frictionless pulley to a 375 N box on the roof of a building. There is no appreciable friction on the box, since it is on roller bearings. The box starts from rest.
A. Find the acceleration of the bucket.
B. How fast is the bucket moving after it has fallen 1.50 m (assuming that the box has not yet reached the edge of the roof)?

Answers

A. The acceleration of the bucket is 3.58 m/[tex]s^{2}[/tex].

B. bucket is moving with a velocity of 3.28 m/s.

What is acceleration?

If an object's velocity changes, it is said to have been accelerated. An object's velocity can alter depending on whether it moves faster or slower or in a different direction. A falling apple, the moon orbiting the earth, and a car stopped at a stop sign are a few instances of acceleration. Through these illustrations, we can see that acceleration happens whenever a moving object changes its direction or speed, or both.

What is Velocity?

The direction in which a body or an object is moving.

What are the calculations?

Given that the mass of bucket m = 22.0 kg

Weight of the box W = 375 N

Then the mass of box M = W / g

      = 375 / 9.8 m/[tex]s^{2}[/tex]

      = 38.27 N

Let T be the tension in the string

Let a be the acceleration of the bucket

Apply Newton's second law to the bucket

                    mg - T = ma

                            T = m (g - a)             ....... (1)

Apply Newton's second law to the box

                            T = Ma                     ....... (2)

From equations (1) and (2) we get

                         Ma = m (g-a)

              ( m+ M )a = m g

                            a = m g / (M + m)

= (22.0 kg) (9.8 m/[tex]s^{2}[/tex]) / (22.0 kg + 38.27 kg )

= 3.58 m/[tex]s^{2}[/tex]

Initial velocity of the bucket u = 0

Let  v be the final velocity of the bucket after displacement s = 1.5 m

From equation of motion

                  v2 - u2 = 2as

                  v2 - 0 = 2as

                       v  = √2as

                       v  = √2(3.58 m/[tex]s^{2}[/tex])(1.5 m)

                       v  = 3.28 m/s

Hence, the acceleration of the bucket is 3.58 m/[tex]s^{2}[/tex] and the bucket is moving with a velocity of 3.28 m/s.

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the air in an inflated balloon (defined as the system) warms over a toaster and absorbs 115 j of heat. as it expands, it does 77 kj of work. what is the change in internal energy for the system? (ans: -77 kj)

Answers

ΔU = q+w The system does work, which gives a negative value: -77kJ

The heat absorbed is q, which is 115J = 0.115kJ

Change of internal energy= 0.115kJ + (-77kJ) = -76.885kJ

Taking two sig figs: -77kJ

What is internal energy and an illustration?

The term "internal energy" describes the power contained in all of the chemical bonds that hold a system's molecules together as well as the kinetic energy of the molecules themselves. Every time heat, work, and internal energy interact, there is a transfer of energy and a conversion.

What makes it internal energy?

W. Thomson first used the word in thermodynamics in 1852. (the later Lord Kelvin). Because certain energy contributions are ignored, the adverb "internal" is used. For instance, the entire system possesses kinetic energy when it is moving uniformly.

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If a simple pendulum oscillates with small amplitude and its length is doubled, what happens to the frequency of its motion?.

Answers

The frequency of simple pendulum will become 1/√2 times of original frequency  if length of simple pendulum is doubled.

We know that frequency of simple pendulum is given by the formula

=>f=(1/2π)×√g/√l

where f is the frequency of simple pendulum,

l is the length of simple pendulum

and g is the acceleration due to gravity

We can see that frequency is directly proportional to length of pendulum and inversely proportional of acceleration due to gravity. Since value of  acceleration due to gravity  remains same on observations, therefore only factor where frequency gets changed when length of simple pendulum gets changed. 1/2π is constant value, it does not affected on changing the length of simple pendulum.

So, if we double the length of simple pendulum, new frequency will become

New Frequency=(1/2π) × (√g / √2l)

=>New Frequency=(1/√2)×[(1/2π×√g/√l)]

=>New Frequency=(1/√2)f.

Hence, new frequency will become 1/√2 times of original frequency.

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a 185 g185 g object is attached to a spring that has a force constant of 78.5 n/m.78.5 n/m. the object is pulled 8.25 cm8.25 cm to the right of equilibrium and released from rest to slide on a horizontal, frictionless table. calculate the maximum speed ????maxvmax of the object.

Answers

The maximum speed of the object is 1.28 m/s.

What is Speed?

Speed is described as the rate at which an object's position changes in any direction. Speed is defined as the distance traveled divided by the travel time. Speed is a scalar quantity because it only has a direction and no magnitude.

One meter per second is the speed of an object, for instance, if it starts at the origin and moves three meters in three seconds. Simple math can be used to calculate speed. time-distance ratio.

According to the given information:

Force constant K:78.5 n/m

Mass: 0.185 kg

The maximum speed of the object is,

[tex]$$\begin{aligned}v_{\mathbf{n} E} & =A \omega \\& =A \sqrt{\frac{k}{m}}\end{aligned}$$[/tex]

Here A is the amplitude, k is force constant, m is mass.

[tex]$$\begin{aligned}v_{\mathrm{ne:}} & =\left(6.25 \times 10^{-2} \mathrm{~m}\right) \sqrt{\frac{78.5 \mathrm{~N} / \mathrm{m}}{0.185 \mathrm{~kg}}} \\& =1.28 \mathrm{~m} / \mathrm{s}\end{aligned}$$[/tex]

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you discover a new cluster of galaxies, and the brightest galaxy in this new cluster has an infrared color ratio of 0.65. based on the data in the graph, what is the approximate distance to this new cluster?

Answers

The approximate distance to this new cluster is 1 billion light-years.

What is a Galaxy Cluster?

A galaxy cluster, also known as a cluster of galaxies, is a formation made up of a large number of gravitationally connected galaxies, typically with masses between 1014 and 1015 solar masses. Before superclusters were found in the 1980s, they were thought to be the largest known structures in the universe and are now the second-largest known gravitationally bound structures in the cosmos after galaxy filaments.

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The approximate distance to this new cluster is 1 billion light-years.

What is a Galaxy Cluster?

A galaxy cluster, also known as a cluster of galaxies, is a formation made up of a large number of gravitationally connected galaxies, typically with masses between 1014 and 1015 solar masses. Before superclusters were found in the 1980s, they were thought to be the largest known structures in the universe and are now the second-largest known gravitationally bound structures in the cosmos after galaxy filaments.

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a two-slit fraunhofer interference-diffraction pattern is observed with light of wavelength 660 nm. the slits have widths of 0.01 mm and are separated by 0.19 mm. how many bright fringes will be seen in the central diffraction maximum?

Answers

38 Bright fringes will be seen in the central diffraction maximum when a two-slit Fraunhofer interference-diffraction pattern is observed.

Diffraction is when waves such as light or sound spread as they travel around an object or through a slit.

As the light passes through each of the slits, it expands and overlaps with the light from the other slit. Through this overlap, a diffraction pattern of dark and light areas is created.

In case of diffraction , angular width of central maxima = 2 λ/d

λ is wave length of light  = 660 nm

d is slit width = 0.01 mm

In case of interference , angular width of each fringe = λ /D

D is distance between two slits = 0.19 mm

Number of interference fringe in central diffraction fringe can be calculated by the formula

=2 λ/d x D/λ

= 2 x D /d = 2 x .19/0.01

= 38

38 bright fringes will be seen in the central diffraction maximum.

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What is the maximum possible amplitude the end of the board can oscillate at, so that a pebble placed there never loses contact with the board at any point of the oscillation?.

Answers

If the pebble on the board do not want to lose contact with one another, so the maximum acceleration would be equal, rather would be equal to four pies square times the frequency squared times the amplitude and this has to be less than G.

Oscillation is defined as the process of repeating variations of any quantity or measure about its equilibrium value in time.Oscillation can also be defined as a periodic variation of a matter between two values or about its central value.However, oscillations also occur in dynamic systems or more accurately in every field of science. Even the beating of our heart creates oscillations.The amplitude of a wave is the maximum displacement of the particle of the medium from its equilibrium position.

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