For each of the following compounds, decide whether the compound's solubility in aqueous solution changes with pH. If the solubility does change, pick the pH at which you'd expect the highest solubility.

a. Ca(OH)2
b. CuBr
c. Ca3(PO4)2

Answer:

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significance

/sɪɡˈnɪfɪk(ə)ns/

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noun

1.

the quality of being worthy of attention; importance.

"adolescent education was felt to be a social issue of some significance"

Similar:

importance

import

noteworthiness

consequence

substance

seriousness

gravity

weight

weightiness

magnitude

moment

momentousness

memorableness

unforgettableness

pronounced nature

remarkableness

outstanding nature

markedness

obviousness

conspicuousness

strikingness

distinction

impressiveness

uncommonness

unusualness

rarity

extraordinariness

exceptionalness

specialness

cruciality

Opposite:

insignificance

2.

the meaning to be found in words or events.

"the significance of what was happening was clearer to me than to her"

Similar:

meaning

sense

signification

import

thrust

drift

gist

burden

theme

implication

tenor

message

essence

substance

relevance

Answer:

1. Cr₂O₇²−(aq) + 14H+ (aq) + 6e- ---->⟶2 Cr³+(aq) + 7H₂O (l)

2. CrO₄²− (aq)⟶+ 4H+ (aq) + 3e- ---> Cr(OH)₄ −(aq)

3. Bi³+ (aq) + 3H₂O (l) ---> BiO₃− (aq) + 6 H+ (aq) + 2 e-

4. CIO −(aq)⟶+ 2H+ (aq) + 2e- ---> Cl −(aq) + H₂O

Explanation:

The given equations are redox reaction equations expressed as as half reactions.

The first step is to identify whether the half-reaction is oxidation reduction.

Then the number of electrons gained or lost are added on the right side of the equation.

Appropriate H+ ions and water molecules are added where necessary since the reaction takes place in acidic environment

The atoms of elements involved in the reaction are balanced by adding the correct coefficients.

1. (acidic) Cr2O7 2−(aq)⟶Cr 3+(aq)

The half-reaction is reduction as the oxidation number of chromium changes from +6 to +3. Two Cr⁶+ ions accepts 3 electrons each to form Cr³+ ions

Cr₂O₇²−(aq) + 6e- ---->⟶2 Cr³+(aq)

Cr₂O₇²−(aq) + 14H+ (aq) + 6e- ---->⟶2 Cr³+(aq) + 7H₂O (l)

2. (acidic) CrO₄²− (aq)⟶---> Cr(OH)₄ −(aq)

The half-reaction is a reduction. One Cr⁶+ accepts 3 electrons to become Cr³+

CrO₄²− (aq)⟶+ 3e- ---> Cr(OH)₄ −(aq)

CrO₄²− (aq)⟶+ 4H+ (aq) + 3e- ---> Cr(OH)₄ −(aq)

3, (acidic) Bi³+ (aq)⟶---> BiO₃− (aq)

The half-reaction is an oxidation. One Bi³+ ion gives up two electrons to become Bi⁵+

Bi³+ (aq)⟶---> BiO₃− (aq) + 2e-

Bi³+ (aq) + 3H₂O (l) ---> BiO₃− (aq) + 6 H+ (aq) + 2 e-

4. (acidic) CIO −(aq)⟶---> Cl −(aq)

The half-reaction is a reduction. One Cl+ ion accepts two electrons to become Cl- ion.

CIO −(aq) + 2e-⟶---> Cl −(aq)

CIO −(aq)⟶+ 2H+ (aq) + 2e- ---> Cl −(aq) + H₂O

Answer:there different from the rocky like planets gas giants don't have such a firm surface like rocky terrestrial planets

Explanation:

Answer:

0.22M

Explanation:

We will be using the law of dilutions. We are simply increasing the amount of solvent to create a larger volume of solution.

So: moles before dilution = moles after dilution & [tex]moles_{concentrated} = moles_{dilute}[/tex]. And M = moles/liter of solution, so if we express this as moles = M x [tex]L_{soln}[/tex].

That is how we derive the formula we will be using: [tex]M_{concentrated} * Vol_{conc} = M_{dilute} * Vol_{dilute}[/tex]

or

[tex]M_{1} * Vol_{1} = M_{2} * Vol_{2}[/tex]

Applying this formula to our problem, we can substitute the variables with the given values to find the molarity of the dilute solution.

M1 = 3.5M

V1 = 18.8mL

M2 = ?

V2 = 296.6mL

Equation: (3.5M)(18.8mL) = (296.6mL)(M2)

==> 65.8M*mL = 296.6mL * M2

==> M2 = (65.8 M*mL)/296.6mL

==> M2 = 0.22M

Answer: a. Cathode

b. Galvanic cell

c. Anode

d. Electrolytic cell

e. half reaction

Explanation:

Galvanic cell or Electrochemical cell is defined as a device which is used for the conversion of the chemical energy produced in a spontaneous redox reaction into the electrical energy.

Electrolytic cell is a device where electrical energy is used to drive a non spontaneous chemical reaction.

In the electrochemical cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.  Thus the electrons are produced at anode and travel towards cathode.

The balanced two-half reactions will be:

Oxidation half reaction : [tex]M\rightarrow M^{n+}+ne^-[/tex]

Reduction half reaction : [tex]N^{n+}+ne^-\rightarrow N[/tex]

Thus the overall reaction will be: [tex]M+N^{n+}\rghtarrow M^{n+}+N[/tex]

Answer:

4.74

Explanation:

pH= -log[H+]

pH= -log(1.8 x 10^-5)= 4.74

Answer:

Label A shows cold area on the mug, while label B shows a warm area.

Explanation:

Have a good day

Answer:

Hello There!!

Explanation:

I think the answer is possibly C. It identified the charge on a single electron.

hope this helps,have a great day!!

~Pinky~

[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]

C. It identified the charge on a single electron.

The full question is shown in the image attached

Answer:

See explanation

Explanation:

In naming an alkane, the first thing we do is to obtain the parent chain by counting the number of carbon atoms in the chain.

When we obtain that, then we identify the substituents and number them in such a way that they have the lowest numbers. The compounds shown have the following names according to the order in which the structures appear in the image attached;

1. 2-methyl propane

2. 2,4-dimethyl heptane

3. 2,2,3,3-tetramethyl butane

4. 5-ethyl-2,4-dimethyl octane

Answer:

Mitochondria

Hydraulic Dams

Ribosomes

Small Shops

Nucleus

Town Hall

Endoplasmic Reticulum

Railroad Tracks

Golgi Bodies

Post Office

Cytoplasm

Clean Air and Water

Protein

Widget

Cell Membrane

Fence

Lysosomes

Scrap Yard

Nucleolus

Carpenter's Union

Vacoule

Warehouse

here is some ideas

3:6:2 is the correct answer

Answer:

Sodium becomes a positive ion and chlorine becomes a negative ion. ... Each atom is neutrally charged, which means that each atom has the same number of protons and electrons.

Explanation:

Answer:

Explanation:

We have the three equations:

[tex]NH_{3(g)} + HCl_{(g)} => NH_4Cl_{(s)} ..... \Delta H = ? (1)\\2HCl_{(g)} => H_{2(g)} + Cl_{2(g)} .... \Delta H = +184.6 kJ (2)\\2H_{2(g)} + 1/2N_{2(g)} + 1/2Cl_{2(g)} => NH_4Cl_{(s)} ..... \Delta H = -314.2 kJ (3)\\ N_{2(g)} + 3H_{2(g)} => 2NH_{3(g)} .... \Delta H = +184.6kJ (4)[/tex]

(can you double check that it is 184.6kJ for both equations 2 and 4 because it seems unlikely). We need to solve for equation 1 by addition and changing equations 2, 3 and 4. After possibly some trial and error, we can find that if we flip equations 4, multiply equation 3 by 2, add the equations together, and then finally divide by 2, we can get equation 1. We will get the answer of -314.2 kJ. However, I am again skeptical about the delta H values for equation 2 and 4 so double check that. This method might be super confusing and it is really hard to explain. So what I would suggest you to watch videos on Hess' law.

Answer:

phototropism

Explanation:

since photo is (light?

The Lewis base that we can see in the equation is [tex]H_{2} O[/tex]

We have to bear in mind that the Lewis base is the substance that is able to donate a pair of electrons. The substances that is able to accept the pair of electrons is what we call the Lewis acid.

The Lewis acid must possess a space for the addition of an electron pair while the Lewis base would have to be a specie that has a lone pair of electrons or has a negative charge. Thus the water molecule would serve as a Lewis base in this regard.

Learn more about Lewis base;https://brainly.com/question/15570523

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Answer:

6 upper H subscript 2 upper O plus UPper C r (upper H subscript 2 upper O) subscript 6 superscript 3 plus.

✔ H2O or A.)

Cr3+

Cr(H2O)63+

Answer:  molecular weight of CUSO4 or grams. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CUSO4, or 346.10221 grams. Note that rounding errors may occur, so always check the results.

Explanation:

Answer:

A its a step by step equation the answer is A

Answer: 1123000 Joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point

Explanation:

Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.

Amount of heat required to vaporize 1 mole of lead =  177.7 kJ

Molar mass of lead = 207.2 g

Mass of lead given = 1.31 kg = 1310 g       (1kg=1000g)

Heat required to vaporize 207.2 of lead = 177.7 kJ

Thus Heat required to vaporize 1310 g of lead =[tex]\frac{177.7}{207.2}\times 1310=1123kJ=1123000J[/tex]

Thus 1123000 Joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point

Answer:

The answer to the question is A. :)

The correct answer is Option A.

Protons and neutrons are found in the nucleus.

To learn more about atoms nucleus refer to :

https://brainly.com/question/1268608

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Answer:

D and E

Explanation:

The other answers don't support steel, they support iron or are supporting both, and the question is why steel alloys are more often used

C supports both

B supports how iron's strength

A supports iron being easily shaped and bent

hope this helps

[tex](normality \: of \: acid)×(volum \: of \: acid) = (normality \: of \: base)×(volum \: of \: base)[/tex]

0.15N × 50mL = 0.2N × (Vbase)

75mL = Volum of base

37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid to the endpoint.

The volume of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

0.2 × V1 = 0.150 × 50

0.2V1 = 7.5

V1 = 7.5/0.2

V1 = 37.5mL

Therefore, 37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 mL of 0.150 M HCI, strong acid to the endpoint.

Learn more about volume at: https://brainly.com/question/26416088

Answer:

1)2Na + Cl2 ----> 2NaCl

2)Ca + Br2 ---->CaBr2

3)K + H2O -----> KOH + H2

Answer:

[tex]T_2=484.8K[/tex]

Explanation:

Hello there!

In this case, according to the the variable temperature and pressure and constant volume, it turns out possible for us to calculate the new temperature via the Gay-Lussac's law as shown below:

[tex]\frac{T_2}{P_2} =\frac{T_1}{P_1}[/tex]

Thus, by solving for the final temperature, T2, we obtain:

[tex]T_2 =\frac{T_1P_2}{P_1}[/tex]

So we plug in the given data to obtain:

[tex]T_2 =\frac{303K*200atm}{125atm}\\\\T_2=484.8K[/tex]

Best regards!

Answer:

1. The energy of the reactant is 50 KJ

2. The energy of the product is 100 KJ

3. The activation energy of the forward reaction is 200 KJ.

4. The activation energy of the reverse reaction is 150 KJ.

5. The energy of the forward reaction is +50 KJ

6. The energy of the reverse reaction is –50 KJ

7. Endothermic reaction

8. Exothermic reaction

Explanation:

1. Determination of the energy of reactant.

From the diagram given above, the energy of the reactant is 50 KJ

2. Determination of the energy of product.

From the diagram given above, the energy of the product is 100 KJ.

3. Determination of the activation energy of the forward reaction.

The activation energy is the energy between the reactant and the peak. It can be obtained as follow:

Energy of reactant (Eᵣ) = 50 KJ

Energy at the peak (Eₕ) = 250 KJ

Activation energy (Eₐ) =?

Eₐ = Eₕ – Eᵣ

Eₐ = 250 – 50

Eₐ = 200 KJ

Thus, the activation energy of the forward reaction is 200 KJ

4. Determination of the activation energy of the reverse reaction.

Energy of reactant (Eᵣ) = 100 KJ

Energy at the peak (Eₕ) = 250 KJ

Activation energy (Eₐ) =?

Eₐ = Eₕ – Eᵣ

Eₐ = 250 – 100

Eₐ = 150 KJ

Thus, the activation energy of the reverse reaction is 150 KJ

5. Determination of the energy of the forward reaction.

Energy of reactant (Eᵣ) = 50 KJ

Energy of product (Eₚ) = 100 KJ

Enthalpy change (ΔH) =?

ΔH = Eₚ – Eᵣ

ΔH = 100 – 50

ΔH = +50 KJ

Thus, the energy of the forward reaction is +50 KJ

6. Determination of the energy of the reverse reaction.

Energy of reactant (Eᵣ) = 100 KJ

Energy of product (Eₚ) = 50 KJ

Enthalpy change (ΔH) =?

ΔH = Eₚ – Eᵣ

ΔH = 50 – 100

ΔH = –50 KJ

Thus, the energy of the reverse reaction is –50 KJ

7. The forward reaction is endothermic reaction because the energy of the product is higher than the energy of the reactant which leads to positive energy of the forward reaction (+50 KJ).

8. The reverse reaction is exothermic reaction because the energy of the product is lesser than the energy of the reactant which leads to negative energy of the reverse reaction (–50 KJ). In a nut shell, we can say that the energy of the reverse reaction is exothermic because its energy of reaction is –50 KJ.

Answer:

I  think it A

Explanation:

Answer:

its d i think

Explanation:

Answer:

[tex]n_{Cl_2}=0.3molCl_2[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reaction whereas the sodium chloride is in a 2:1 mole ratio with chlorine, the required moles of the later are computed as shown below:

[tex]n_{Cl_2}=0.6molNaCl*\frac{1molCl_2}{2molNaCl}[/tex]

So we cancel out the moles of NaCl to obtain:

[tex]n_{Cl_2}=0.3molCl_2[/tex]

Best regards!

Answer:

Highest occupied level of carbon is 3

Explanation:

its called Alkynes

Explanation:

Answer:

Mx will be less than My.

Explanation:

The correct option is - Mx will be less than My.

Because, liquid X have been higher viscosity and vapor pressure than liquid B.

Vapor pressure of liquid A is greater, so the amount of liquid X will vaporized greater and H2 gas has been displaced greater from the beaker as compared to liquid Y.

The amount of H2 in liquid Y remains greater in beaker as compared to liquid X.

So, Mx will be less than My.

Answer:

the density of the Gas at STP is 0.227 g/L .

Explanation:

This question involves the combined gas law . The equation for the combined gas law

Answer:

46.41%

Explanation:

Find the total r.m.m of AL(CLO3)3 put it equals to 100%.....The take 106.5,the total r.m.m of Cl and find the missing which is the percentage by cross multiplication