For a science project, Janet performs four experiments that are supposed to show a chemical reaction. She displays her results in a table.A 4-column table with 4 rows. The first column titled experiment has entries 1, 2, 3, 4. The second column titled substances has entries water + heat, vinegar + baking soda, cabbage juice + lemon juice, liquid A + liquid B. The third column titled evidence of reaction has entries gas formation, gas formation, color change, precipitate formation. The fourth column titled Chemical Reaction ? has entries yes, yes, yes, yes.In the column titled "Chemical reaction?,” which experiment’s data should be changed to "No”?Experiment 1Experiment 2Experiment 3Experiment 4

Answer: look at the explanation and try to work it

Explanation: in contrast, our atmosphere blocks most ultraviolet light (UV) and all X-rays and gamma-rays from reaching the surface of Earth. Because of this, astronomers can only study these kinds of light using detectors mounted on weather balloons, in rockets, or in Earth-orbiting satellites.

Answer: Type A are cardiac muscles Type B are skeletal muscles, and Type C are smooth muscles.

Explanation: sub to technoblade :P

Answer:

compounds D and A

Explanation:

The ionic compound can conduct electricity therefore, the compounds A and D are most likely ionic. Therefore, option (4) is correct.

Ionic compounds can be defined as crystalline solids produced by closely packed ions with opposite charges. The formation of an Ionic compound takes place when metal reacts with non-metal.

In ionic compounds, the ions of the compound are generally linked together by ionic bonds. The ions of an atom are formed by gaining or losing electrons in order to get the noble gas electronic configuration.

In a reaction, the metals are generally electropositive so they can lose electrons to complete their octet while non-metals will gain electrons from the metals to complete their octet.

Ionic compounds can conduct electricity in a molten state and aqueous solution because then they have free ions that can move from one place to another to conduct an electric current.

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Answer:

T = 82 K

Explanation:

The computation of the final temperature is shown below;

Given that

T_0 denotes the initial temperature of the gas i.e. 74 K

T denotes the final temperature of the gas = ?

n denotes number of moles of monoatomic gas i.e. 1.00 mol

R denotes universal gas constant = 8.314

c denotes the heat capacity at constant volume i.e.

= (1.5) R = (1.5) (8.314)

= 12.5

Q denotes the Amount of heat absorbed i.e 100 J

We know that

Amount of heat absorbed is provided as

Q = n c (T - T_0)

100 = (1) (12.5) (T - 74)

T = 82 K

Answer:

17188 years

Explanation:

Recall the formula;

0.693/t1/2 = 2.303/t log(No/N)

t1/2 = half life of 14C

No = initial activity of 14C

N = activity of 14C at time t

t = age of the sample

Substituting values

0.693/5730= 2.303/t log(160/ 20)

1.21 * 10^-4= 2.0798/t

t = 2.0798/1.21 * 10^-4

t = 17188 years

Answer: C2H6O

Explanation: It is C2H6O with a molar mass of 46.07 g/mol.

Answer:

Its D  

Explanation:

Did it on edge

According to the reaction: H₂S0₄ + Ca(OH)₂ → CaSO₄+ 2H₂O, the base is Ca(OH)₂.

Base is defined as a substance which can accept protons or any chemical compound that yields hydroxide ions (OH-) in solution.

Generally, base are substances that produces hydroxide ion when dissolve in water.  

Base are substances that reacts with acid to produce salt and water. Example of base includes sodium hydroxide, potassium hydroxide, magnesium hydroxide, calcium hydroxide etc.

Therefore, according to the reaction:

H₂S0₄ + Ca(OH)₂ → CaSO₄+ 2H₂O

The base is Ca(OH)₂.

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Answer:

B. Dividing the number by 1,000

Explanation:

Every time you move the decimal ,add a zero.Since the decimal is moved three times ,there are three zeroes. When you move left ,the number is getting smaller so it is division.

n = 0.0395 mol Xe

Explanation:

Use the ideal gas law:

PV = nRT

n = PV/RT

= (1.15 atm)(0.786 L)/(0.08205 L-atm/mol-K)(279K)

= 0.0395 mol Xe

Explanation:

If bunsen burner gave a luminous flame then there will deposition of soot at the bottom of the test tube which is actually pure carbon.

This deposition of soot actually depicts that there is incomplete combustion reaction that has taken place.

Also, the deposition of soot will provide a limited supply of oxygen to the reaction that has been calculated.

Therefore, in order to avoid any formation of soot it is advisable to adjust the burner flame till it produces a blue flame.

Answer:

10.65 moles

Explanation:

O2:H2O

8:6

14.2:x

x= 10.65 moles

Answer:

The heat capacity of the metal underneath the gold is 0.431 J/g°C

Explanation:

Using the formula as outlined in the image:

Q = m × c × ∆T

Where;

Q = amount of heat energy (J)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

According to the information in this question;

Q = 503.9J

m = 23.02g

c = ?

∆T = 74°C - 23.2°C = 50.8°C

Using Q = m × c × ∆T

c = Q ÷ m∆T

c = 503.9 ÷ (23.02 × 50.8)

c = 503.9 ÷ 1169.42

c = 0.431 J/g°C

From the above heat capacity of the metal underneath the gold, it is obvious that the metal is not pure gold (c = 0.129J/g°C)

Answer:

I think it is 7.60 X 1

but if it's not srry

Answer:

A. Orange light

Explanation:

According to the band spectrum of white light ( ROYGBIV )

Answer:

I think it blue light is higher

Answer:

covalent

valence electrons

Explanation:

The attraction between two atoms that share a pair of valence electrons is known as a covalent bond. The nuclei of both atoms are drawn to the shared electrons. This results in a molecule with two or more atoms. Covalent bonds are formed solely between nonmetal atoms.

Between atoms of the same element or between atoms of different elements, covalent bonds can form. A new substance termed a covalent compound is formed when atoms of various elements create covalent bonds.

Answer:

[tex]yes[/tex]

Explanation:

Iodine is present in salt which makes it salty:)

Answer:

Option A. The specific heat is 0.897 J/gºC, The Substance is aluminum.

Explanation:

We'll begin by calculating the change in temperature of the substance. This can be obtained as follow:

Initial temperature (T₁) = 20.0 °C

Final temperature (T₂) = 40.0 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 40 – 20

ΔT = 20 °C

Finally, we shall determine the specific heat capacity of the substance. This can be obtained as follow:

Mass (M) = 136 g

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 2440 J

Specific heat capacity (C) =?

Q = MCΔT

2440 = 136 × C × 20

2440 = 2720 × C

Divide both side by 2720

C = 2440 / 2720

C = 0.897 J/gºC

Comparing the specific heat capacity (i.e 0.897 J/gºC) of the substance with those in the table above, the substance is Aluminum.

Thus, option A gives the correct answer to the question.

Answer:

Total pressure of the mixture = 1 atm

Partial pressure of He = 0.863 atm

Partial pressure of Ar  = 0.0173 atm

Partial pressure of Ne = 0.1197 atm

We confirm that the sum of partial pressure of each gas valu

Explanation:

STP conditions are:

1 atm of pressure and

273K of T°

We can also say that those value reffers to 1 mol.

We determine the moles of each:

5 g . 1mol / 4g = 1.25 moles of He

1g . 1mol / 39.9 g = 0.0250 moles of Ar

3.5g . 1mol / 20.18 g = 0.173 moles of Ne

Total pressure of a mixture can be obtained from the Ideal Gases Law.

P . V = n . R . T

Total moles: 1.25 + 0.025 + 0.173 = 1.448 moles

But now, we need the volume. We know that 1 mol is contained at 22.4L at STP.

1.448 mol . 22.4L / 1 mol = 32.4 L

That's the volume for our mixture. We replace:

32.4 L . P  = 1.448 mol . 0.082 . 273K

P = (1.448 mol . 0.082 . 273K) / 32.4L = 1 atm

Now we can obtained the partial pressure of each gas from mole fraction

Mol of gas / Total pressure = Partial pressure of gas / Total pressure

Partial pressure of He = (1.25 / 1.448) . 1 atm = 0.863 atm

Partial pressure of Ar = (0.025 / 1.448) . 1 atm = 0.0173 atm

We know that sum of partial pressure is 1 - (Mole fraction He + Mole fr. Ar)

Partial pressure of Ne = 1 - (0.863 + 0.0173) = 0.1197 atm

We confirm that the sum of partial pressure of each gas values the total pressure of the mixture: 0.863 + 0.0173 + 0.1197 = 1

To solve this we must be knowing each and every concept related to  chemical formula. Therefore, in the above given ways the chemical formula for the molecule can be written.

A chemical formula is a scientific notation that uses atomic symbol and numerical subscripts to represent the number and types of elements contained in a molecule. A chemical formula seems to be a concise written description of an existing three-dimensional molecule.

A chemical formula characterizes a material to the atomic level. There are three sorts of chemical formulas: empirical, molecular, and structural.

The chemical formula for the given molecules are:

2. H[tex]_2[/tex]O

3. O[tex]_3[/tex]

4. H[tex]_2[/tex]

5. CO[tex]_2[/tex]

6. CO

7. NO[tex]_2[/tex]

8. CH[tex]_4[/tex]

Therefore, in the above given ways the chemical formula for the molecule can be written.

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Answer:

We learned that waterhas three states: ice is the solid state, watervapor is the gaseous state, and wateris the liquid state. When water is heatedit evaporates, which means it turns into watervapor and expands. Secondly, does water expand when heated?

Explanation:

+HF is the answer

Explanation:

Answer:

molecules take up more space

Answer:

4.42x10⁻⁶ m³

Explanation:

Primero convertimos 100 gramos a kilogramos:

Ahora se puede calcular el volumen que ocuparán 0.100 kg de osmio, usando la densidad dada por el problema:

La respuesta es 4.42x10⁻⁶ m³.

Answer: There are [tex]16.14 \times 10^{23}[/tex] atoms of hydrogen are present in 40g of urea, [tex](NH_{2})_{2}CO[/tex].

Explanation:

Given: Mass of urea = 40 g

Number of moles is the mass of substance divided by its molar mass.

First, moles of urea (molar mass = 60 g/mol) are calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol[/tex]

According to the mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] atoms.

So, the number of atoms present in 0.67 moles are as follows.

[tex]0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms[/tex]

In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.

[tex]4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms[/tex]

Thus, we can conclude that there are [tex]16.14 \times 10^{23}[/tex] atoms of hydrogen are present in 40g of urea, [tex](NH_{2})_{2}CO[/tex].

Answer: False

Explanation:

Hope this help

Answer:

True.

Explanation:

Every child will contain the same number of chromosomes as the parents (otherwise they wouldn't be considered the same species). Additionally, animals can only mate with a species containing the same number of chromosomes as themselves. This means if the offspring of the parents had a different number fo chromosomes the offspring would be unable to mate with animals of it's own species.

The given question is incomplete, the complete question is:

A chemist must dilute 54.1 mL of 20.2 M aqueous silver perchlorate (AgC102) solution until the concentration falls to 3.00 M. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Round your answer to 3 significant digits.

Answer:

The correct answer is 0.364 L.

Explanation:

A solution is made less concentrated by diluting it with a solvent. There is no change in the number of moles when more solvent is added to the solution. In case, if the solution is diluted from V1 to V2, a change is noticed in the molarity of the solution based on the given equation,

M1V1 = M2V2

In the given case, the V1 or the volume of the original solution is 54.1 ml, M1 or the molarity of the original solution is 20.2 M.

The M2 or the molarity of the diluted solution is 3.00 M, there is a need to find the V2 or the volume of the diluted solution.

Now by putting the values in the equation we get,

= 20.2M * 54.1 ml = 3.0 M * V2

V2 = 364.27 ml

It is known that 1000 ml is equivalent to 1L, therefore, 1 ml = 0.001 L

Now, the value of V2 will be,

= 364.27 * 0.001 L = 0.36427 L or 0.364 L

Answer:

32.57g

Explanation:

mass = mole x molar mass

mass of LiBr = 0.375 x 86.85

mass = 32.57g

Answer: When fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.

Explanation:

The chemical energy present in fuels actually releases when these fuels are burned or by combustion.

Hence when fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.

For example, gasoline present in vehicles burns and undergoes chemical change which is then converted into thermal energy. This thermal energy then converts into mechanical energy due to which car moves.

Thus, we can conclude that when fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.

Answer: Electrons are taken up by [tex]PbO_2[/tex] and they are lost by [tex]HCl[/tex]

Explanation:

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously. It is also called the reaction where the exchange of electrons takes place.

An oxidation reaction is defined as the reaction in which a chemical species loses electrons takes place. In this reaction, the oxidation state of a substance gets increased.

A reduction reaction is defined as the reaction in which a chemical species gains electrons takes place. In this reaction, the oxidation state of a substance gets reduced.

For the given chemical reaction:

[tex]PbO_2+4HCl\rightarrow PbCl_2+Cl_2+2H_2O[/tex]

The half-reactions for this redox rection follows:

Oxidation half-reaction:  [tex]2HCl\rightarrow ClO_2 + 2e^-[/tex]

Reduction half-reaction:  [tex]PbO_2+2e^-\rightarrow PbCl_2[/tex]

Hence, electrons are taken up by [tex]PbO_2[/tex] and they are lost by [tex]HCl[/tex]