Answer:
In a transverse wave, the motion of the medium (what the wave moves through—in this case, the spring) is perpendicular to the direction of the wave. So, each point of the spring moves up and down as the wave travels from left to right.
Explanation:
this is a very difficult to say
What is the material through which a wave travels?
Answer:
yes
Explanation:
yes
Answer:
medium
Explanation
The energy of a mechanical wave can travel only through matter. The matter through which the wave travels is called the medium (plural, media). The medium in the water wave pictured above is water, a liquid
2.Find the magnitude and direction of the resultant velocity vector for the following perpendicular velocities: a. a fish swimming at 3.0 m/s relative to the water across a river that moves at 5.0 m/s b. a surfer traveling at 1.0 m/s relative to the water across a wave that is traveling at 6.0 m/s
Answer:
a. The magnitude of the resultant velocity vector of the fish is approximately 5.83 m/s
The direction of the resultant velocity vector of the fish is approximately 30.93° relative to the direction of the river
b. The magnitude of the resultant velocity vector of the surfer is approximately 6.083 m/s
The direction of the resultant velocity vector of the surfer is approximately 9.46° relative to the direction of the wave
Explanation:
a. The given parameters of the fish and the river are;
The speed with which the fish is swimming across the river, v₁ = 3.0 m/s
The velocity with which the river is flowing, v₂ = 5.0 m/s
Therefore, in vector form, we have;
v₁ = 3.0·j
v₂ = 5.0·i
The resultant velocity, R = v₁ + v₂ = 5.0·i + 3.0·j
∴ R = 5.0·i + 3.0·j
The magnitude of the resultant velocity vector, [tex]\left | R \right |[/tex] = √(5.0² + 3.0²) =√34 ≈ 5.83
The magnitude of the resultant velocity vector, of the fish, [tex]\left | R \right |[/tex] ≈ 5.83 m/s
The direction of the resultant velocity of the fish, θ = arctan(3.0/5.0) ≈ 30.93°
Therefore, The direction of the resultant velocity vector of the fish, θ ≈ 30.93° relative to the direction of the river
b. The given parameters of the surfer and the wave are;
The speed with which the surfer is travelling, v₁ = 1.0 m/s
The speed of the wave travelling across, v₂ = 6.0 m/s
Therefore, in vector form, we have;
v₁ = 1.0·j
v₂ = 6.0·i
The resultant velocity, R = v₁ + v₂ = 1.0·i + 6.0·j
∴ R = 1.0·i + 6.0·j
The magnitude of the resultant velocity of the surfer, [tex]\left | R \right |[/tex] = √(1.0² + 6.0²) =√37 ≈ 6.083
The magnitude of the resultant velocity vector of the surfer, [tex]\left | R \right |[/tex] ≈ 6.083 m/s
The direction of the resultant velocity of the surfer, θ = arctan(1.0/6.0) ≈ 9.46°
Therefore, The direction of the resultant velocity vector of the surfer, θ ≈ 9.46° relative to the direction of the wave
The purpose of a cell phone cover is to protect your phone from impact forces. How does a cell phone case do this?
Answer:
the material of the phone case
The purpose of a cell phone cover is to protect your phone from impact forces. It is done by absorbing the impact of force by back cover.
What is Force ?
Force is responsible for the motion of an object. it produces acceleration in the body. According to newton's second law force is mass times acceleration i.e. F =ma. Its SI unit is N which is equivalent to kg.m/s².
The case is made in such a way that, if the cell phone is dropped, the cover will absorb the kinetic energy of the falling phone by the means of deforming without transferring the impact onto the phone.
Cell phone cover is made up of rubber which can restore the forces like a spring. when u apply force to the rubber it get displaced and applied force is stored in the rubber. when cell phone drops, rubber of the cover absorbs the energy of impact. it also provides shied protection to the phone.
Hence this is how cell phone case do this.
To know more about force, click :
https://brainly.com/question/13191643
#SPJ3.
Will give brainliest!! Pls answer! HELP ME!!!!!!
Answer:
See the explanation.
Explanation:
Q9. Irregular reflection happens when a set of parallel beams are reflected from non-smooth surface which results in non-parallel reflected beams.
Q10.
i) Periscope
ii) There are different types of periscopes but the main characteristic of this instrument is observation over the obstacles or in general objects that are not in the line-of-sight. Basic Periscope uses parallel angled mirrors to project objects that are above the surface in submarines.
Which of the following describes how a sound wave can bounce off a surface?
A. Reflection
B. Absorption
C. Diffraction
Answer:
a
Explanation:
Answer: reflection
Explanation:
A hydrogen atom is isolated in a vacuum chamber, the electron is now separated from the proton and moved to a distance 1 cm away. Let Fg be the magnitude of the gravitational force between the proton and electron, and let Fe be the magnitude of the electric force between the proton and electron. How does the ratio Fg/Fe change as the particles are separated
Answer:
hello your question is incomplete attached below is the complete question
answer: Fg / Fe does not change ; it is the same nonzero value for all separations ( A )
Explanation:
Given that distance between proton and electron is 1 cm
Fg = Gm1m2 / r^2
where :
G ( gravitational constant )= 6.67 * 10^-11 Nm^2 / kg^2
m1 ( mass of proton ) = 1.67 * 10^-27 kg
m2 ( mass of electron ) = 9.11 * 10^-31 kg
Electrical force
Fe = kq1q2 / r^2
k = 9*10^9
hence ;
Fg / Fe = (Gm1m2 / r^2) / (kq1q2 / r^2 )
= Gm1m2 / kq1q2
a brown bear runs at the speed of 9.0m/s with 23,000 j of kinetic energy
A spring with a spring constant of 500 N/m is stretched 1 meter in length. How much elastic potential energy does the spring have stored in it?
Answer:
E =250 J
Explanation:
Given that,
The spring constant of the spring, k = 500 N/
It is stretched to a distance of 1 m
We need to find how much elastic potential energy does the spring have stored in it.
The energy stored in the spring is called elastic potential energy. It is given by the formula as follows :
[tex]E=\dfrac{1}{2}kx^2\\\\E=\dfrac{1}{2}\times 500\times 1^2\\\\E=250\ J[/tex]
So, 250 J of energy is stored in the spring.
A cube has sides of length 10 cm and weighs 10 N.
Calculate the pressure when it rests on one side ....N/cm2
Answer:
P = r g h where r here is the density m / V and then P is the pressre.
W (weight) = m g
m = 10 N / 9.8 m / s^2 = 1.02 kg
r (density) = m / V = 1.02 kg / 1000 cm^3 = .00102 kg/cm^3
P = .00102 kg / cm3 * 9.8 m/s^2 * 10 cm
P = .1 kg m / (s^2 cm^2)
Since 1 N = kg m / s^2 then P = .1 N / cm^2
More simply P = F / A = 10 N / 100 cm^2 = .1 N / cm^2
Jennifer and katie stand and lean on each other. Jennifer weighs 150 pounds and katie weighs 120 pounds.
Answer:
Jennifer
Explanation:
she has more mass which means she is using more force
Which of the following is not a step toward planning your goal? A. Set a target date. B. Disregard o goal if you don’t achieve it. C. Set both short- and long-term goals. D. Reward yourself for a small accomplishment.
Answer:
B
Explanation:
Disregard a goal if you don't achieve it
if you reduce friction between objects what also is reduced?
Answer:
Use of lubricants: In machines, friction can be reduced by applying lubricants between the contact surfaces to fill the fine pores or depressions in the surfaces and make them smooth thereby reducing friction. Polishing : unevenness of the surfaces can be reduced by polishing, thereby reducing the friction.
Explanation:
A 4 m long, 500 kg steel beam extends horizontally from the point where it is bolted to the frame of a building. A 70 kg man stands on the far end of the beam. What is the magnitude of the torque at the point where the beam attaches to the building
Answer:
12556.8Nm
Explanation:
A 4 m long, 500 kg steel beam extends horizontally from the point where it is bolted to the frame of a building. A 70 kg man stands on the far end of the beam. What is the magnitude of the torque at the point where the beam attaches to the building
Step one:
Given data
Length of steel x =4m
Mass of steel m1=500kg
Mass of man m2=70kg
The center of the mass of the steel is from the center
Cm=x/2
Cm=4/2= 2m
Torque =force*perpendicular distance
Force =mg
The total torque =torque due to weight of steel +torque due to the man's weight
Total torque = 500*9.81*2+70*9.81*4
Total torque =9810+2746.8
Total torque =12556.8Nm
calculate the net force and the acceleration the block
Answer:
The net force is 20 N and the acceleration of the block is [tex]5\ m/s^2[/tex]
Explanation:
Given that,
Mass of the block, m = 4 kg
Force in right side = 30 N
Force in left side = 10 N
We need to find the net force and the acceleration of the block.
Net force = Right force - left force (as both are opposite to each other)
= 30 N - 10 N
= 20 N
Formula for net force,
F = ma
a is acceleration
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{20\ N}{4\ kg}\\\\a=5\ m/s^2[/tex]
Hence, the net force is 20 N and acceleration of the block is [tex]5\ m/s^2[/tex].
A child and sled with a combined mass of 26.3 kg slide down a frictionless hill. The sled starts from rest and acquires a speed of 5.34 m/s by the time it reaches the bottom of the hill. What is the height (in m) of the hill?
Answer:
12 m/s
Explanation:
The purpose of a cell phone cover is to protect your phone from impact forces. How does a cell phone case do this?
Answer:
it covers your phone so when you drop it it reduces the chance and breaking
which rock is most likely phyllite
Answer/Explanation:
Phyllite is a very common metamorphic rock, found in many parts of the world. It forms when sedimentary rocks are buried and mildly altered by the heat and directed pressure of regional metamorphism.
Answer:
metamorphic rock
Explanation:
Phyllite is a very common metamorphic rock, found in many parts of the world. It forms when sedimentary rocks are buried and mildly altered by the heat and directed pressure of regional metamorphism.
a chuck wagon with an initial velocity of 4 m/s and a mass of 35 kg gets a push with 350 joules of force. what is the wagon's final velocity?
Answer:
the final velocity of the wagon is 6 m/s.
Explanation:
Given;
initial velocity of the wagon, u = 4 m/s
mass of the wagon, m = 35 kg
energy applied to the wagon, E = 350 J
The final velocity of the wagon is calculated as;
E = ¹/₂m(v² - u²)
[tex]m(v^2-u^2) = 2E\\\\v^2-u^2 = \frac{2E}{m} \\\\v^2 = \frac{2E}{m} + u^2\\\\v = \sqrt{\frac{2E}{m} + u^2} \\\\v = \sqrt{\frac{2(350)}{35} + (4)^2}\\\\v = 6 \ m/s[/tex]
Therefore, the final velocity of the wagon is 6 m/s.
Given:
Wagon's initial velocity,
u = 4 m/sMass,
m = 35 kgApplied energy,
E = 350 JWe know,
→ [tex]E = \frac{1}{2} m(v^2-u^2)[/tex]
→ [tex]m(v^2-u^2) = 2E[/tex]
or,
→ [tex]v^2-u^2 = \frac{2E}{m}[/tex]
→ [tex]v= \sqrt{\frac{2E}{m} +u^2}[/tex]
By substituting the values,
[tex]= \sqrt{\frac{2(350)}{35}+(4)^2 }[/tex]
[tex]= 6 m/s[/tex]
Thus the answer above is correct.
Learn more about mass here:
https://brainly.com/question/22256985
Why would it be incorrect to say that the bulb supplies 60 J of light energy energy each second
Answer:
Explanation:
A 60W bulb , consumes electrical energy of 60 J per second but it does not give out all the energy in the form of light . Most of the energy consumed by it is wasted in the form of heat . Only a fraction of energy is converted into light energy .
Hence, it is wrong to say that bulb supplies 60 J of light energy each second .
in which medium does the speed of air is the greatest? explain why?
The speed of air greatest in a medium with high pressure. Air is moving from high pressure to low pressure areas called the winds.
What are winds?The natural movement of air or other gases in relation to a planet's surface is referred to as wind. There are many different sizes of winds, ranging from thunderstorm flows that last only a few minutes to local breezes.
Large-scale atmospheric circulation is primarily brought on by the planet's rotation and the difference in temperature between the equator and the poles (Coriolis effect).
The air can move through a medium as well through vacuum. Air blows with the highest speed when the medium have higher temperature and pressure.
Find more on winds:
brainly.com/question/616790
#SPJ6
how temperature, surface tension and the diameter of the tube affect capillary action.
The surface tension acts to hold the surface intact. Capillary action occurs when the adhesion to the surface material is stronger than the cohesive forces between the water molecules. ... Water wants to stick to the glass and surface tension will push the water up, until the force of gravity prevents further rise.
Narrower tube openings allow capillary action to pull water higher
QUESTION 2 DOK 3 A Thompson's gazelle has a maximum acceleration of 4.5 m/s2 At this acceleration, how much time is required for it to reach a speed of 40 km/h?
Answer:
2.47 s
Explanation:
Convert the final velocity to m/s.
40 km/h → 11.1111 m/sWe have the acceleration of the gazelle, 4.5 m/s².
We can assume the gazelle starts at an initial velocity of 0 m/s in order to determine how much time it requires to reach a final velocity of 11.1111 m/s.
We want to find the time t.
Find the constant acceleration equation that contains all four of these variables.
v = v₀ + atSubstitute the known values into the equation.
11.1111 = 0 + (4.5)t 11.1111 = 4.5t t = 2.469133333The Thompson's gazelle requires a time of 2.47 s to reach a speed of 40 km/h (11.1111 m/s).
A wave has frequency of 5 Hz and a speed of 25 m/s. What is the wavelength of the wave?
Answer:
A wave has a wavelength of 5 meters and a frequency of 3 hertz.
Explanation:
Why can you see an apple as green and not red?
Answer:
A lot of Dietary Fiber.
Explanation:
Answer:
Red apples get their color from anthocyanins. These are pigments, or natural colorings, that develop as the apple grows. ... It absorbs all the colors of the rainbow—except for red. The red light reflects off the apple and our brain and eyes work together to let us know what color we are seeing.
can some one explain me big bang theory ?
Answer:
The Big Bang Theory is the leading explanation about how the universe began. At its simplest, it says the universe as we know it started with a small singularity, then inflated over the next 13.8 billion years to the cosmos that we know today.
Earth travels fastest in January and slowest in July. What is the most likely explanation for this?
A. Earth is nearest the Sun in July and farthest away in January.
B. Earth is nearest the Sun in January and farthest away in July.
C. Earth is nearest the Sun in April and farthest away in October.
D. Earth is nearest the Sun in October and farthest away in April.
Answer:
Earth is nearest the Sun in July and farthest away in July.
Explanation:
Answer:
Correct Answer: B.
Explanation:
Earth is nearest the Sun in January and farthest away in July. Explanation: According to Kepler's Second Law, a planet travels fastest when it is nearest its sun. This means that Earth is actually closest to the Sun in January, when it is winter in the northern hemisphere!
What is the magnitude and direction of the momentum of a 1200 kg truck traveling at 20m/s towards the east
Given :
A 1200 kg truck traveling at 20 m/s towards the east.
To Find :
The magnitude and direction of the momentum.
Solution :
We know, momentum is given by :
Momentum, P = mv
P = 1200 × 20 kg m/s
P = 24000 kg m/s
Now, we know, direction of momentum is same as the direction of velocity.
Therefore, momentum of truck is 24000 kg m/s and direction is towards the east.
A force of 90N is applied to each cart below, which one will accelerate the fastest?
Mass: 5 kg
Mass: 6 kg
mass: 8 kg
Mass: 9 kg
Answer:
5kg
Explanation:
The cart with the least amount of mass will result in the fastest acceleration.
The cart with the fastest acceleration is 5 kg cart because its mass is the smallest.
The given parameters;
applied force, F = 90 Nmass of cart: 5kg, 6kg, 8 kg, 9 kgAccording to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma
The acceleration of the 5 kg cart is calculated as follows;
[tex]a = \frac{F}{m} \\\\a = \frac{90}{5} = 18 \ m/s^2[/tex]
The acceleration of the 6 kg cart is calculated as follows;
[tex]a = \frac{F}{m} \\\\a = \frac{90}{6} = 15 \ m/s^2[/tex]
The acceleration of the 8 kg cart is calculated as follows;
[tex]a = \frac{F}{m} \\\\a = \frac{90}{8} = 11.25 \ m/s^2[/tex]
The acceleration of the 9 kg cart is calculated as follows;
[tex]a = \frac{F}{m} \\\\a = \frac{90}{9} = 10 \ m/s^2[/tex]
Thus, the cart with the fastest acceleration is 5 kg cart because its mass is the smallest.
Learn more here:https://brainly.com/question/11657305
A 60 kg swimmer suddenly dives from a 150 kg raft with a speed of 1.5 m/s. The raft is initially at
rest. What is the speed of the raft immediately after the diver jumps if the water has negligible
effect on the raft?
Answer:
v2 = 0.6 m/s in opposite direction
Explanation:
The computation of the speed of the raft is as follows
The center of system mass would be remains at the same place also it has no external force applied
Therefore
V = 0
So,
M1.V1= - (M2.V2)
where,
M1 = 60 kg, V1 = 1.5 m/s
M2 = 150 kg
Now
60 × 1.5 = - 150 × v2
v2 = -0.6 m/s
v2 = 0.6 m/s in opposite direction
I WILL GIVE BRAINLIEST....
Determine the value of F...