The skin oils from the finger will deposit on smooth surfaces in the pattern of the closely spaced ridges when the finger contacts them.
What is diffraction ?The Huygens-Fresnel principle, which views each point in a propagating wave front as a collection of unique spherical wavelets, describes the diffraction phenomenon in classical physics. When a wave from a coherent source (such a laser) comes into contact with a slit or aperture that is roughly the same size as its wavelength, the characteristic bending pattern is most noticeable.
There are numerous closely spaced ridges and swirls on the skin of a fingertip. The skin oils from the finger will deposit on smooth surfaces in the pattern of the closely spaced ridges when the finger contacts them. In order to create a crude diffraction grating and create a coloured spectrum of the light travelling through or reflecting from the glass surface, open intervals between the lines of deposited oil can be used as slits.
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a 40kg child takes a ride on a ferris wheel that rotates fouyr times each minute and has a diameter of 18m what is the centripetal acceleration
The centripetal acceleration is [tex]1.58m/s^2[/tex]
What is centripetal acceleration?
Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any object moving in a circle with an acceleration vector pointing in the direction of the circle's center.
It is calculated by
ac = rω^2
where
ac = centripetal acceleration
r = radius
ω = angular velocity
Given,
ω = 4 revolution,
diameter = 18m so, radius r = 9m
Subsituting the values in equaion
ac = [tex][9m] [[4.0\frac{rev}{min} ][\frac{2\pi rad}{rev} ][\frac{1 min}{60s} ]]^2[/tex]
ac = [tex]1.58m/s^2[/tex]
The centripetal acceleration is [tex]1.58m/s^2[/tex]
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when bulb c is removed from the circuit, what happens to the brightness of bulb a ? when bulb is removed from the circuit, what happens to the brightness of bulb ? the brightness of bulb a stays the same. the brightness of bulb a increases. the brightness of bulb a decreases.
The brightness of bulb A will not be affected, but the brightness of bulbs B and D will become brighter.
In the given circuit, the bulbs B, C, and D are connected in series, whereas bulb A is connected in parallel.
All parts of a series circuit are wired together end to end to create a single path for current flow.
A series circuit of incandescent bulbs would have reduced brightness and increased life when a bulb is added. When a bulb is removed from the series combination, the brightness of the other bulbs will increase. Each bulb acts as a resistor reducing the current through each bulb. In a series circuit, when one bulb burns out, it acts as an open switch, and all bulbs go out.
The given question is incomplete as there is no given circuit diagram.
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Choose the correct measuring device for gathering data from the list of tools in the drop-down menu. Heartbeats per minute time distance across the pond.
Measuring devices are used as follows -1. Thermometer, 2. Heart monitor, 3. Measuring cylinder, 4. Clock, 5. Tape measure
What are measuring devices?
The instruments that are used for the measurements of various specific items based on the laws and the theories of measurement are called measuring devices.
Specific measurements have specific measurement devices. These measure the value based on the specific unit of the measurement.
For example, an inch tape measures the length of something in inches. It also has scales of centimetres and meters.
For the measurement of length, scales and tape measures are used.
For the measurement of time, clocks are used.
For the measurement of volumes, graduated cylinders are used.
For the measurement of temperature, thermometers are used.
Therefore, the measuring devices vary according to the function it needs to perform. In this case, 1. Thermometer, 2. Heart monitor, 3. Measuring cylinder, 4. Clock, 5. Tape measure.
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Answer:
Answer:heart monitor
Stopwatch
Digital tape measure
Thermometer
Graduated cylinder
Explanation:
A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of v i
=18.0m/s. The cliff is h=50.0m above a body of water as shown in above figure. (a) What are the coordinates of the initial position of the stone? (b) What are the components of the initial velocity of the stone? (c) What is the appropriate analysis model for the vertical motion of the stone? (d) What is the appropriate analysis model for the horizontal motion of the stone? (e) Write symbolic equations for the x and y components of the velocity of the stone as a function of time. (f) Write symbolic equations for the position of the stone as a function of time. (g) How long after being released does the stone strike the water below the cliff? (h) With what speed and angle of impact does the stone land?
a) The starting speed of the stone was 18.0 m/s, and the cliff's height was 50.0 m.
The expression for the stone's initial x-coordinate
[tex]x_{i}[/tex] = 0
The stone's initial x-coordinate is shown here.
the definition of the top of the cliff's initial y-coordinate
[tex]y_{i}[/tex] = 50m
The stone's initial y-coordination is seen here.
Consequently, the stone's starting position's coordinates are (0, 50.0m)
b) The expression for the stone's starting speed in the x direction
[tex]v_{ix}[/tex] = 18.0m/s
The stone's initial horizontal velocity [tex]v_{ix}[/tex] is seen here. The formula for the starting velocity in the y direction .
[tex]v_{iy}[/tex] = 0m/s
Here, [tex]v_{iy}[/tex] is the stone's initial vertical velocity.
Consequently, the initial component of the stone's speed are [tex]v_{ix}[/tex] = 18.0m/s and [tex]v_{iy}[/tex] = 0m/s.
c) A free fall motion with constant g-force governs the stone's vertical movement.
Particle motion with constant acceleration is what is happening in the y direction.
As a result, the acceleration in the y direction remains constant.
d) Because there is zero acceleration in the x-direction and no net force acting to modify the stone's inertia, the particle's velocity remains constant throughout the motion.
As a result, the motion in the y-direction is motion at a constant speed.
As a result, motion in the x-direction is caused by constant velocity motion.
e) Because the stone doesn't experience any acceleration in the x direction, its speed remains constant throughout the motion.
The stone's ultimate x-direction velocity is equal to its x-direction beginning velocity.
the relationship between the x-final direction's and beginning velocities,
[tex]v_{fx} = v_{ix}[/tex]
Here, [tex]v_{fx}[/tex] is the final horizontal velocity.
The speed in the x direction is independent of time.
The stone experiences a constant acceleration in the y direction, or g, which determines the stone's y-direction velocity.
The formula for the y-ultimate direction's velocity
[tex]v_{fy} = v_{iy} + at[/tex]
Here, [tex]v_{fy}[/tex] is the ultimate vertical velocity, and an is the vertical acceleration.
Substitute 0 for [tex]v_{iy}[/tex] and -g for a in the above equation to find [tex]v_{fy}[/tex]
[tex]v_{fy}[/tex] = -gt
Consequently, the velocity's x and y components are [tex]v_{fx} = v_{ix}[/tex] and [tex]v_{fy}[/tex] = -gt respectively.
f) The term for the stone's x-direction position
[tex]x_{f} = x_{i} + v_{ix}t + a_{x} t^{2}[/tex] (i)
Here, [tex]x_{f}[/tex] is the final horizontal position and [tex]a_{x}[/tex] is the acceleration in the x-direction.
The term for the stone's y-direction position
[tex]y_{f} = y_{i} + v_{iy} t + \frac{1}{2} at^{2}[/tex] (ii)
Here, [tex]y_{f}[/tex] is the final vertical position.
Substitute 0 for [tex]x_{i}[/tex] and 0 for [tex]a_{x}[/tex] in the equation (i)
[tex]x_{f} = 0 + v_{ix} t + 0\\ = v_{ix} t[/tex]
Substitute 0 for [tex]v_{iy}[/tex] and -g for a in the equation (ii)
[tex]y_{f} = y_{i} + 0 - \frac{1}{2} (g)t^{2}[/tex]
[tex]= y_{i} - \frac{1}{2} (g)t^{2}[/tex]
Consequently, the position's x and y components are [tex]v_{xi} t[/tex] and [tex]= y_{i} - \frac{1}{2} (g)t^{2}[/tex] respectively.
g) The formula to calculate time
t = [tex]\sqrt{\frac{2h}{g} }[/tex]
Substitute 50m for h and 9.8m/[tex]s^{2}[/tex] for g in above equation to find t.
t = [tex]\sqrt{\frac{2(50m)}{9.8m/s^{2} } }[/tex]
= 3.19s
As a result, the stone will hit the sea below the cliff in 3.19 seconds.
h) The expression to calculate velocity.
[tex]v_{fy}[/tex] = -gt
Substitute 3.19s for t and 9.8 m/[tex]s^{2}[/tex] Obtain for g in the previous equation [tex]v_{fy}[/tex].
[tex]v_{fy}[/tex] = (9.8m/[tex]s^{2}[/tex]) (3.19s)
= -31.26m/s
≈ - 31.3m/s
The method for estimating the speed of stone land
v = [tex]\sqrt{v^{2} _{fx} }+ \sqrt{v^{2} _{fx} }[/tex] (iii)
The speed of the stone when it lands in this case is v.
The formula for calculating the stone land's angle
∅ = [tex]tan^{-1}[/tex] ( [tex]\frac{v_{fy} }{v_{fx} } )[/tex] (iv)
Substitute 18m/s for [tex]v_{fx}[/tex] and -31.3m/s for [tex]v_{fy}[/tex] in equation (iii) to find v.
v = [tex]\sqrt{(18m/s)^{2} }[/tex] + [tex]\sqrt{(-31.3m/s)^{2} }[/tex]
= 36.1m/s
As a result, the stone was moving at 36.1 m/s when it hit the ground.
Substitute 18m/s for [tex]v_{fx}[/tex] and -31.3m/s for [tex]v_{fy}[/tex] in equation (iv) to find ∅.
∅ = [tex]tan^{-1}[/tex] ([tex]\frac{-31.3m/s}{18m/s} )[/tex]
= -60.09°
≈ -60.1°
As a result, the stone terrain has an angle that is -60.1° below the horizontal.
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calculate the work w done by the gas during process 1→3→6 . express your answer in terms of p0 and v0 .
6P₀V₀ is the work done by the gas during process 1→3→6.
What is work done by gas?The work performed by a gas expanding against an external pressure is negative, analogous to the work performed by a system on its surroundings. In contrast, when a gas is compressed externally, V₀ and the work is positive because the environment exerts force on the system.
The gas must release some energy into the environment when it expands in response to an external pressure. The overall energy of the gas is thus reduced as a result of the negative work. When a gas is compressed, energy is transferred to it, increasing its energy as a result of positive work.
Let's consider,
Work done = -W (As the energy is released)
External pressure = P₀
Volume of gas = V₀
So, the work done can be calculated as follows:
W = P x (dV)
-W = P₀ × V₀
Now according to the process given:
1→3→6
Energy flow increases up to 6.
Hence, the energy of the system (work done) is:
-W = 6 × P₀ × V₀
-W = 6P₀V₀
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a particle is moving with a constant velocity in the x-direction. when the particle reaches the origin, a constant force is exerted on it in the y-direction. which of the following graphs best shows the path the particle will follow?
Parabolic Up. Since the force is in the y-direction, the particle will continue to move at a constant speed in the x-direction and accelerate in the y-direction. This creates a parabolic path around y-axis.
Force is the power that changes the motion of an item. A force can purpose an object with mass to alternate its pace. A force has both value and path, making it a vector quantity.
Pressure is the push or the pull that affects us in our daily lives because, without force, people might not be capable of opening and near stuff or lifting up their arms or legs.
Variety of Forces :
* Muscular Forces, muscular tissues feature to produce an ensuing force which is referred to as 'muscular force'.
* Frictional Forces, while an item modifications its national motion, 'frictional pressure' acts upon it.
* Carried out pressure.
* Tension force.
* Spring force.
* Gravitational pressure.
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46. what minimum friction force must exist between the tires and the road to prevent the car from skidding as it rounds the curve?
Daniel G. A=v2r calculates centripetal acceleration. The recommended minimum friction coefficient is 0.4.
How much friction must there be at a minimum for the car to stay on the road?Of course, the car won't slide if the coefficient of friction is higher than 0.141; this is the minimum value. The frictional force is parallel to the velocity, as you can see.
What level of frictional force is needed to prevent the car from swerving?A car needs a centripetal force of mV2/R, where m is the mass of the vehicle, V is the speed, and R is the radius of the circular portion of road, in order to maintain its position on the road without skidding. Fs/Fl = 4mV2/R / 2mV2/R is obtained by dividing Fs by Fl.
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let's say you use a heat pump to pump heat from room a to room b. the temperature in room a is 18.6 oc and in room b is 27.3 oc. if your goal is to cool space a, what is the theoretical cop limit?
The theoretical Coefficient of Performance (COP) to cool the room A is 33.52.
Temperature in room A = T₁ = 18.6 oc
Temperature in room B = T₂ = 27.3 oc
To convert temperatures in Kelvin,
= T₁ = 18.6 + 273 =
= T₁ = 291.6 K
and,
= T₂ = 27.3 + 273
= T₂ = 300.3 K
The COP value to cool room A =
= COP = T₁ / (T₂ - T₁)
= COP = 291.6 / (300.3 - 291.6 )
= COP = 291.6 / 8.7
= COP = 33.52
The theoretical coefficient of performance to cool room A is 33.52 when the temperature of room A is 18.6 oc and that of room B is 27.3 oc.
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what is the debroglie wavelength in picometers (10-12m) of an electron that is traveling at 79.1% of the speed of light?
The debroglie wavelength in picometers (10-12m) of an electron that is traveling at 79.1% of the speed of light is 2.8 × [tex]10^{-12}[/tex]
Mass of electron m = 9.1 × [tex]10^{-31}[/tex]kg
speed of electron v = 3 ×[tex]10^{8}[/tex] m/s * (79.1/100) = 2.37 × [tex]10^{8}[/tex] m/s
debroglie wavelength λ = h/mv
λ = 6.626 [tex]10^{-34}[/tex]/9.1 × [tex]10^{-31}[/tex] × 2.37 × [tex]10^{8}[/tex]
λ = 2.8 × [tex]10^{-12}[/tex]
In many branches of physics, the speed of light in a vacuum, commonly abbreviated as c, plays a crucial role. Exactly 299,792,458 meters per second is the speed of light, or c. [Note 3] The speed at which common matter or energy can travel through space (and, consequently, any signal carrying information) is limited to c, according to the special theory of relativity.
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an inflated bicycle tire is 2.2 cm in diameter and 2.0 m in circumference. a small leak causes the pressure inside of the tire to decrease from 760 kpa to 550 kpa on a day when the temperature is 20 o c. what mass of air is lost?
Answer: 0.0016 kg
Explanation: To solve this problem, we need to use the ideal gas law, which states that the pressure of a gas is directly proportional to its temperature and the number of moles of gas present. The ideal gas law is given by the following equation: PV = nRT
where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas present, R is the ideal gas constant, and T is the temperature of the gas.
In this case, we are given the pressure of the gas inside the tire (760 kPa and 550 kPa), the temperature of the gas (20 °C), and the diameter and circumference of the tire (2.2 cm and 2.0 m). We need to use this information to calculate the mass of air that was lost from the tire.
First, we need to find the volume of the gas inside the tire. Since the circumference of the tire is 2.0 m and the diameter is 2.2 cm, we can use the formula for the circumference of a circle to calculate the radius of the tire:
C = 2 * pi * r
2.0 m = 2 * pi * r
r = 0.3 m
Next, we can use the formula for the volume of a circle to calculate the volume of the gas inside the tire:
V = pi * r^2 * h
V = pi * (0.3 m)^2 * 2.2 cm
V = 0.0183 m^3
Now that we have the volume of the gas inside the tire, we can use the ideal gas law to calculate the number of moles of air inside the tire:
PV = nRT
n = PV / RT
n = (760 kPa * 0.0183 m^3) / (8.314 J/molK * 293 K)
n = 0.0059 mol
Next, we can use the ideal gas law to calculate the number of moles of air lost from the tire when the pressure decreased from 760 kPa to 550 kPa:
n = PV / RT
n = (550 kPa * 0.0183 m^3) / (8.314 J/molK * 293 K)
n = 0.0043 mol
Finally, we can use the molar mass of air to calculate the mass of air that was lost from the tire:
m = n * M
m = (0.0059 mol - 0.0043 mol) * 28.97 g/mol
m = 0.0016 kg
Therefore, the mass of air lost from the tire when the pressure decreased from 760 kPa to 550 kPa is 0.0016 kg.
A .530 kg block slides on a frictionless horizontal surface with a speed of 1.10 m/s. The block encounters an unstretched spring and compresses it 20.0 cm before coming to rest. Part A) What is the force constant of this spring? k=________N/m
Part B) For what length of time is the block in contact with the spring before it comes to rest?
t=________sec
Part C) If the force constant of the spring is increased, does the time required to stop the block increase, decrease, or stay the same.
Choices:
A) Increases
B) Decreases
C) Stays the same
The force constant of this spring is 16.03N/m; the length of time block is in contact with the spring before it comes to rest is 1.14s; If the force constant of the spring is increased, the time required to stop the block will decrease.
What happens if a block slides on a frictionless horizontal surface?
When a block slides over a horizontal surface without friction, it has kinetic energy. Before coming to rest, it runs into an untensioned spring and compresses it.
The energy is purely kinetic when the mass first comes into contact with the spring. Energy is transformed into spring potential energy as the spring is squeezed. To find the spring force constant, equate the energies. One-fourth of a period is represented by the motion. A stiffer spring will result in a smaller stopping distance for the mass, which will result in a faster stopping time.
(a)Equations: Conservation of energy using a spring.
Ei=Ef
1/2mvo2 = 1/2kA2
A= vo√m/k
K is force constant
k is 16.03N/m
(b) Time
T = 2∏√m/k
T = 1.14s
(c) The time to stop reduces as the force constant rises. A stronger spring and a greater stopping force result from a higher force constant, and a shorter stopping time follows. The compressed spring contains all of the energy left behind after the spring has stopped the block. The block will be accelerated back the way it came when the spring pushes back on it. The block will leave the spring moving in the opposite direction from where it first came into contact with it, but at the same speed. Equal to the stopping time is the accelerating time.
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what is the minimum angular spread of a 633-nm wavelength he-ne laser beam that is originally 1.00 mm in diameter? (answer in degrees)
The diffraction-induced minimum angular spread is 633 10 9 meters.
What is diffraction-induced propagation?When the hole is illuminated by a parallel ray of light of wavelength lambda, it is believed that the dispersal of the spot (gotten on the left wall of the video) equals the sum of its geometrical dispersal and the spread induced by diffraction.
Diffraction is the term used to describe the spreading out of waves when they pass through an apertures or around objects. It occurs when the aperture's or obstruction's size and the incident wave's wavelength are of same magnitude. At very small aperture diameters, the most of the wave is blocked.
Briefing : Minimum angular spread due to diffraction (θ) = λ/b
Given.
Wavelength = 633nm = 633×10⁻⁹m
Beam diameter is 1mm.
Minimum angular spread due to diffraction (θ) = 633×10⁻⁹m/1
Minimum angular spread due to diffraction (θ) = 633×10⁻⁹m.
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a 21 g bullet is accelerated in a rifle barrel 66.5 cm long to a speed of 968 m/s. use the work energy theorem to find the average force exerted on the bullet while it is being accelerated. answer in units of N.
The force on the bullet of mass 21 g is 14795.12 N.
What is force?Force is the product of mass and acceleration.
To calculate the force exerted on the bullet while it is being accelerated, we use the work energy relation below
Formula:
F = mv²/2d...........Equation 1Where:
F = Forcem = Mass of the bulletv = Velocity of the bulletd = DistanceFrom the question,
Given:
m = 21 g = 0.021 kgv = 968 m/sd = 66.5 cm = 0.665 mSubstitute these values into equation 1
F = 0.021×968²/(2×0.665)F = 14795.12 NHence, the force on the bullet is 14795.12 N.
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A student has an ohmic lightbulb connected to a battery that has significant internal resistance. As the student connects other identical lightbulbs in parallel to the first lightbulb, which of the following would be a reasonable observation about the brightnesses of the lightbulbs?
a. Each lightbulb gets brighter as more lightbulbs are added.
b. Each lightbulb gets dimmer as more lightbulbs are added.
c. When each lightbulb is added, it is the same brightness as the first lightbulb, which remains the same brightness throughout.
d. The first lightbulb remains the same brightness, but each added lightbulb is brighter than the original.
e. The first lightbulb remains the same brightness, but each added lightbulb is dimmer than the original.
Based on the information provided regarding the parallel circuit, reasonable observation about the brightness of the lightbulbs would be that when each lightbulb is added, it is the same brightness as the first lightbulb, which remains the same brightness throughout. (Option C)
A parallel circuit refers to a circuit that comprises of branches so that the current divides and only part of it flows through any branch. The voltage, or potential difference, across each branch is the same. Two or more bulbs in a simple parallel circuit have full voltage of the battery, hence the brightness of each bulb remains unchanged.
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what is the moment of inertia of the object starting from rest if it has a final velocity of 5.4 m/s? express the moment of inertia as a multiple of mr2 , where m is the mass of the object and r is its radius.
The moment of inertia of is the object starting from rest if it has a final velocity of 5.4 m/s is 0.344 M R²
You can then use the energy conservation equation to calculate the moment of inertia of an object that starts at rest and has terminal velocity.
Then Ek1 + Ep1 = Ek2 + Ep2, where
Ek1 = kinetic energy of the object before rolling
Ep1 = potential energy of the object
Ek2 = kinetic energy when the object falls
Ep2 = potential energy of the object below.
Mgh = Iv² +Mv²
2R² 2
19.6M = 14.58 I + 14.58 M
R²
5.02 M R² = 14.58 I
0.344 M R² = I
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what is the maximum speed of a 330 kg car if the spring is compressed the full amount? express your answer with the appropriate units.
A fully compressed spring may move at a maximum speed of 4.993 m/s, according to the question.
What is speed and what is its unit in physics?The pace at which a distance changes over time is referred to as speed. It includes a dimension of time-distance. As a result, the fundamental unit of time and also the basic unit if length are combined to form the High silica content of speed. Thus, the meter per second is the SI unit for speed.
Briefing:K.E = 3RT/2 - (i)
K.E = mv²/2 - (ii)
eq(i) = eq(ii)
comparing
3RT = mv²
v² = 3RT/m
T/m = 1
v = [tex]\sqrt{3R}[/tex]
v = [tex]\sqrt{3*8.31}[/tex]
4.993m/s
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A ball is thrown vertically upward with an initial velocity of 64 feet per second.
A ball is thrown vertically upward with an initial velocity of 64 feet per second.So, from 0.5 seconds to 3.5 seconds, the ball is at the height of 28 feet above the ground.
What is the straightforward definition of velocity?velocity. . swiftness, quickness, or the speed of motion, activity, or operation A measurement of a body's rate of motion in physics is the rate at which its location changes over time in a specific direction.
What is the definition of velocity using an example?Simply said, velocity is the rate of movement in a specific direction. including the speed of a car driving north on a road or the pace at which a rocket takes off. Since the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.
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A helium-neon laser emits light with a wavelength of 633 nm. What is the frequency of this light.
Answer:
The frequency of light beam is 4.74 x 10^(14) s^(-1)
Explanation:
In this problem we use the formula C=F x ( lamda )
here c= the speed of light
f =the frequency of light beam
lamda = wavelength
c=3 x 10^8 m/s ( universally same)
lamda = 633nm = 633 * 10^(-9) m
Therefore f = c/ ( lamda )
or; f = 3 x 10^8 / 633 * 10^(-9)
f= 4.74 x 10^(14) s^(-1) .
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What is the power needed to change the speed of a 1600-kg sport utility vehicle from 15. 0 m/s to 40. 0 m/s in 4. 00 seconds?.
2725 Watt, is the power needed to change the speed of a sport utility vehicle.
What is the Power?
The quantity of energy moved or converted per unit of time is known as power. The watt, or one joule per second, is the unit of power in the International System of Units also it is a scalar quantity.
What are the Calculations?
Mass of the sport utility = 1600kg
Initial velocity ([tex]v1[/tex]) - 15m/s, ([tex]15^{2}[/tex] = 225)
Final velocity ([tex]v2[/tex]) - 40m/s, ( [tex]40^{2}[/tex] = 1600)
To find the energy required, Kinetic energy (K.E) = [tex]\frac{1}{2}[/tex] [tex]mv^{2}[/tex]
K.E = final K.E - initial K.E
= [tex]\frac{1}{2} (v2 - v1 )[/tex]
= [tex]\frac{1}{2} 1600 * (1600 - 225)[/tex]
= 80 * 1375
= 11000 J
Power = [tex]\frac{Energy (E)}{Time (t)}[/tex] = [tex]\frac{1100 joule}{ 4 sec}[/tex]
= 2725Watt.
Hence, 2725Watt, is the power needed to change the speed.
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5. consider a charge, - 2q, placed a distance a above the xy plane and a charge 4q placed a distance 3a above the xy plane. if the xy plane is grounded, determine the force on the -2q charge.
If the xy plane is grounded, Then the force on the -2q charge is derived from F=1/4πE* q²/d² Z
So magnitude of the image charge = - 29
and location is distance d from origion at-2 axis as shown.
The charge 2q is attracted toward the plate because of the negative induced charge. Now force felt by charge 2q All to new configuration force is
F=1/4πE*( 2q ) ( - 2q ) /2d² Z
or
F=1/4πE* q²/d² Z.
An object experiences a push or pull as a result of interacting with another object. any time there is a relationship between two objects. The result of the interaction between two objects, force is a push or a pull. It has both magnitude and direction because it is a vector quantity. Normal and gravitational force are the most typical types of forces. The attraction between two mass-containing objects is created by the gravitational force, which is a non-contact force.
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A particle accelerator accelerates an electron to a kinetic energy of 6.5 MeV. a) How fast is the electron moving? b) How many times is its mass greater than its rest mass?
(a) The speed of the electron is 1.5 x 10⁹ m/s.
(b) The mass of the electron is 12.75 times greater than the rest mass energy.
What is the speed of the electron?
The speed of the electron is calculated by applying the following equation;
K.E = ¹/₂mv²
where;
m is mass of electronv is the speed of the electronv² = 2K.E/m
v = √(2K.E/m)
where;
K.E is the kinetic energy = 6.5 MeV = 6.5 x 10⁶ x 1.6 x 10⁻¹⁹ J = 1.04 x 10⁻¹² J
v = √(2 x 1.04 x 10⁻¹²/9.11 x 10⁻³¹)
v = 1.5 x 10⁹ m/s
The rest mass energy of an electron is 0.51 MeV
0.51x = 6.5
x = 6.5/0.51
x = 12.75
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would the balloon hit the ground before or after 1.0 s of falling? which equation did you use to decide, and what comparison did you make to determine that it would or would not hit the ground by then?
The first equation will be used to determine that it would hit the ground after 1.0s of falling (in 1.56 s).
Equation of motion are a mathematical formula that describes the position, velocity or acceleration of a body relative to a given frame of reference
The first equation to be used will be second equation of motion
x = v₀t + 1/2at²
where, x = distance
a = uniform acceleration
t = time
12 = 1/2*9.8 *t²
24 = 9.8 * t²
t = 1.56 s.
The balloon will hit the ground after 1.0s of falling.
The 1st equation was used because of the values provided which included the distance and the acceleration due to gravity. The 2nd equation has final velocity and initial velocity which couldn't be compared from the data given.
The given question is incomplete complete question is:
A student holds a water balloon outside of an open window and lets go. The window is 10 meters above the ground, and the balloon is falling under the acceleration of gravity, which is 9.8 m/s2. There are two equations that can be used to describe its motion over time:
x=x0+v0t+12at2
v=v0+at
Would the balloon hit the ground before or after 1.0 s of falling? Which equation did you use to decide, and what comparison did you make to determine that it would or would not hit the ground by then?
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A sports car is accelerated from 0 to 100 km per hour in 3 s. What is the acceleration of the car?.
The automobile accelerates at 0.9g.
Describe acceleration.acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight forward is accelerated when it accelerates or decelerates.
1 g equals 9.8 m/s2, as we are aware. Therefore, we must first convert 100 km/h to m/s. So that we may compare units like meters and seconds (we'll deal with s2 eventually).
100 km/h * (1 km) * (1 hour) * (1 minute) * (60 sec) = 27.778 m/s.
We are aware that this automobile needed three seconds to reach this speed. Since acceleration is a change in velocity, and we know that the car's velocity increased from 0 to about 27.8 m/s in 3 seconds, we may calculate the accelerationknow that our acceleration is:
(27.8 m/s - 0 m/s) / (3 s) = 9.259 m/s^2.
Now to find how many g’s, we know that 1 g = 9.8 m/s^2.
So we know that 9.259 m/s^2 / 9.8 m/s^2 = about 0.9. This will be 0.9 of 1 g, which is just 0.9 g.
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is it possible to use the reflection from this corner cube to send a sunbeam onto the wall in a room from the sun's rays entering the room through a window?
Yes, but only up to a certain height since the corner cube maintains the angle of the light's incidence. No, as any position of a corner cube sends the beam back to the window. Yes, the beam is parallel to itself when the cube travels slightly.
What are corner cubes and how do they function?An optical element having the exceptional capability of returning an entering beam of light straight at its place of origin irrespective of the beam's angle of entry is a corner cube, often called as a retroreflector.
A corners cube retroreflector (CCR) is what, exactly?Three adjacent, mutually orthogonal plane-reflecting surfaces make up a corner cube retroreflector, also called as a CCR or trihedral prism, which is an optical structure an angle of a cube. Independent of the prism, the corner cube returns an incident ray at a certain angle.
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a perfume bottle has a straw the goes from the nozzle into the fluid. the other end of the nozzle is connected to a bulb that when squeezed pushes air out. explain how the perfume makes its way out of the bottle given this configuration.
The liquid is drawn up into the feed tube and forced through the nozzle by the vacuum produced by the airflow.
What exactly is a vacuum?A vacuum is indeed a space that is devoid of all substance, sometimes known as "free-space." Only complete vacuums are actually feasible in real life. An incandescent lightbulb has a vacuum inside. The vacuum in space is almost ideal. The Moon, Mercury, or Mars have no atmospheres at all.
What is the vacuum unit?Scales and vacuum units commonly used. In vacuum systems, pressure is still measured in mm or inches of mercury. The Torr (from Torricelli) unit of pressure measurement is based on millimeters of mercury, and mmHg (Hg being heavy metals in the periodic table).
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which of the following is considered to be a boundary between two different air masses? group of answer choices cold front warm front both warm front and cold front none of these
A front denotes the separation of two air masses with dissimilar characteristics in terms of temperature, wind, and moisture.
Distinguish between warm and cold fronts.
Both warm and cold fronts are intricate weather phenomena, necessitating a thorough explanation in order to fully comprehend their similarities and distinctions. A cold front develops on the edge of a cold air mass flowing into a warmer area, whereas a warm front develops on the edge of a warm air mass moving into a colder area. A cold front is often linked to a low-pressure system, whereas a warm front is linked to a high-pressure system.
Hence, the answer is both warm and cold front, since a front denotes the separation of two air masses with dissimilar characteristics in terms of temperature, wind, and moisture.
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what makes astronomers think that impact rates for the moon must have been higher earlier than 3.8 billion years ago? a.the ancient sea basins on the moon, whose water has since evaporated, show a lot more cratering b.all the large craters on the moon come in pairs, while all recent craters are single c.all the radioactive rocks found on the moon so far give ages much younger than that, so the moon must have formed less than 3.8 billion years ago d.there are ten times more craters on the older highlands than the younger maria e.we see many more craters on the moon that have been eroded by wind and rain
Option (4) is correct: There are ten times more craters on the older highlands than the younger maria.
Who are astronomers?
Astronomers are scientists in the field of astronomy, who focus their research on a particular problem or area outside the realm of the Earth. Observe celestial bodies such as stars, planets, moons, comets, and galaxies either by observation (by analyzing data) or by theoretical astronomy. Examples of topics and fields studied by astronomers include planetary science, solar astronomy, the origin and evolution of stars, and the formation of galaxies. A related but different field is physical cosmology, which studies the universe as a whole.
Therefore, Option (4) is correct: There are ten times more craters on the older highlands than the younger maria.
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A certain carbon monoxide molecule consists of a carbon atom of mass mc = 14 u and an oxygen atom of mass mo = 18 u that are separated by a distance of d = 122 pm, where "u" is an atomic unit of mass.
a. Write a symbolic equation for the location of the center of mass of the carbon monoxide molecule relative to the position of the oxygen atom. This expression should be in terms of the masses of the atoms and the distance between them.Â
b. Calculate the numeric value for the center of mass of carbon monoxide in units of pm.Â
(a) The formula for these two atoms' center masses in relation to the oxygen atom is. (b) The center of mass of monoxide has a numerical value of 53 pm.
The settings provided;
The carbon atom's mass is 12u.
The oxygen atom has a mass of 17 u and a spacing of 128 pm between its atoms.
These two atoms' center masses in relation to the oxygen atom are computed as follows;
where; is the atom's separation from the fixed reference point (the oxygen atom) (b) The following equation is used to calculate the center of mass of monoxide in measures of pm:
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consider the pictured representations of electromagnetic waves. which electromagnetic wave corresponds to each description?
Electromagnetic (EM) waves are waves that are related to both electricity and magnetism. These waves travel over space and are made up of time-varying electric and magnetic fields.
When electric and magnetic fields interact and change over time, electromagnetic waves are produced.These waves, which are linked to electricity and magnetism, would almost certainly travel beyond space.The magnetic field varies with time and gives rise to the electric field; the electric field changes with time and gives rise to the magnetic field again, and so on. When time-varying electric and magnetic fields are coupled and propagate together in space, electromagnetic waves are formed.To know more about electromagnetics visit:
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Once you set a ball rolling in a frictionless bowling alley, the force needed to keep it rolling is?.
None of the alternatives are correct
What would happen to a ball if was rolling on a frictionless surface ?It's crucial to keep in mind that rolling motion is impossible on a surface with no friction. It will just continue to slide along. The sphere will slide when something is rolling down an incline if the incline's angle is very large or its coefficient of friction is very low.
The ball will continue rolling in the absence of friction. Only friction would prevent it from rolling indefinitely if the second plane's angle of inclination were reduced to zero, making it perfectly horizontal.
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