Find total displacement. 10 points. Will give brainliest!

Find Total Displacement. 10 Points. Will Give Brainliest!

Answers

Answer 1

Answer:

20.5 m North East.

Explanation:

The attached photo gives the illustration of Alan's walk.

In the attached photo, d is the total displacement of Alan's walk.

Thus, we can obtain the value of by using the cosine rule as shown:

Angle D = 138°

Side opposite D = d

Side opposite C = 12 m

Side opposite E = 10 m

d² = c² + e² – 2ce Cos D

d² = 12² + 10² – 2 × 12 × 10 × Cos 138°

d² = 144 + 100 – 240 × Cos 138°

d² = 244 – – 178.355

d² = 244 + 178.355

d² = 422.355

Take the square root of both side

d = √422.355

d = 20.5 m.

Since his new position is on a bearing of 042°, Alan' total displacement is 20.5 m North East.

Find Total Displacement. 10 Points. Will Give Brainliest!

Related Questions

Which vector has an x-component with a length of 4?

Answers

Answer:

C.) vector C

Explanation:

From the graph provided:

Four vectors are present :

Vectors a, b, c and d.

The x-component of the vector is its magnitude along the x-axis.

Taking the coordinate of each vector:

Vector a = (1,4) : length of x- component = 1

Vector b = (1, 1) : length of x- component = 1

Vector c = (4, -4) : length of x- component = 4

Vector d = (-3, 4) : length of x- component = - 3

Therefore, vector c has an x-component length of 4

Indicar tipo de unión química que presentan los siguientes compuestos. Realizar a representación de Lewis, molecular o iónica, según corresponda: a-CH4 b-SrO c-HBr d-NH3 e-Cl2O f-Li2O g-CO2 h-MgCl2

Answers

Answer:

Explanation:

a. CH₄- Covalent bonding(ligação covalente)

b. SrO- ionic bonding (ligação iônica)

c. HBr- Polar Covalent bonding (ligação covalente polar)

d. NH₃ - covalent bonding(ligação covalente)

e. Cl₂O - Covalent bonding (ligação covalente)

f. Li₂O- ionic bonding (ligação iônica)

g. CO₂ - double covalent bonding (ligação covalente dupla)

h. MgCl₂- ionic bonding(ligação iônica)

Using the free-body diagram, calculate the net force acting on the sled. Is the sled in a state of dynamic equilibrium?

Answers

The net force acting on the sled is zero. The sled is in a state of dynamic equilibrium.

Explanation:

The two vertical forces, Fg and Fn, cancel each other out, but I choose to "ignore" them in my explenation, although they remain present at all times.

Since the net force acting on the sled is zero, the sled is in some state of equilibrium...

Whether the sled or a stationary equilibrium or in a dynamic equilibrium, depends on the the motion of the object. If the object is moving then it is a dynamic equilibrium and if the object is not moving, then there is a stationary equilibrium.

Look closely at the picture of the sled and the dogs, and try to find out if the sled is standing still or if the sled is moving with a constant speed.

From the movement of snow around the dogs, you can tell, the sled is moving. It clearly is not stationary or left standing still.

So in this case it must be a dynamic equilibrium. The combined pull of all dogs is shown by Ft = 225 N.

Apparently, the friction is displayed as an opposite force shown as Ff = - 225 N. These two horizontal forces cancel each other out.

Strangely enough, this can be compared with a situation like a "tug of war", in which both sides pull with equal force. Although there can be an enormous tension in the cord, nothing moves.... The same is true here although the sled is moving with a constant speed...

EXTRA

Given is that the sled is moving with a constant speed.

No imagine two situations and try to predict what will happen.... Here we go...

Situation 1 The friction force remains Ff = - 225 N but the dogs suddenly start to pull harder, say with a force of 275 N.

Now the net Force will be greater then zero. In that case it will be 275 - 225 = 50 N in favour of the dogs, which would result in an exeleration of the sled, and thus an increase of the speed...

Situation 2 The friction force becomes greater Ff = - 300 N, but the dogs pull with the same force of 225 N.

Now the net Force will be less then zero. In that case it will be 225 - 300 = -75 N in favour of the friction Force, which would result in slowing down the sled. Perhaps the sled operator applied the brake on the sled, which caused a deceleration of the sled, and thus the speed decreases.

Answer:

yes

Explanation:

edg 2020

A box is dragged across a floor by pulling on a rope attached to the crate and inclined 25 o above the horizontal. If the coefficient of static friction is 0.64, it requires a force of 350 N to just start it moving. What is the mass of the box

Answers

Answer:

[tex]m=35.58 kg[/tex]

Explanation:

Using the first Newton's equation

[tex]\Sum F_{T}=F-mgsin(25)-\mu mgcos(25)=0[/tex]

We just need to solve it for m:

[tex]m=\frac{F}{g(sin(25)+\mu cos(25))}[/tex]

[tex]m=\frac{350}{9.81(sin(25)+0.64cos(25))}[/tex]

[tex]m=35.58 kg[/tex]

I hope it helps you!

Wood has chemical energy which can be used to generate thermal and radiant energy when burned in a fire place which best explains what happens to the total amount of energy in this scenario

Answers

Answer:

c i took the test

Explanation:

The total amount of energy in this scenario is transformed into other forms of energy because of the burning process of the wood.

What happens to the total amount of energy in this scenario?

The energy present in the wood change into other forms of energy such as heat and radiant energy. We know that during a reaction, matter is transformed into another form with the release of different types of energy.

So we can conclude that he total amount of energy in this scenario is transformed into other forms of energy because of the burning process of the wood.

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What is the overall charge of the wall?

Answers

Answer:

The overall charge on the wall is zero.

Explanation:

Because the atoms making the wall are neutral i.e. number of positive charges are equal to number of negative charges.

What is the magnitude of these two vectors: 101 m 60.0 degrees 85.0 m

Answers

Answer:

85.0 please I don't understand

Two identical long wires of radius a = 2.80 mm are parallel and carry identical currents of i = 5.00 A in opposite directions. Their center-to-center separation is W = 19.0 cm. Neglect the flux within the wires but consider the flux in the region between the wires. What is the inductance per unit length of the wires?

Answers

Answer:

Inductance per unit length, [tex]\frac{L}{l} = 7.02 * 10^{-7} H/m[/tex]

Explanation:

Radius of the wire, a = 2.80 mm

Currents carried by each of the wires, i = 5.00 A

Center-to-Center Separation, W = 19.0 cm

The flux in the wires is given by the equation, ∅ = Li

The Net flux of the region between the wires  is given by the equation:

[tex]\phi = \frac{l \mu_0 i}{\pi} ln(\frac{W-a}{a})[/tex]

Divide both sides by l to get the net flux per unit length

[tex]\phi/l = \frac{ \mu_0 i}{\pi} ln(\frac{W-a}{a})\\\phi/l = \frac{ 4 \pi * 10^{-7} i}{\pi} ln(\frac{0.019-0.0028}{0.0028})\\\phi/l = 7.02 * 10^{-7} i\\\frac{Li}{l} = 7.02 * 10^{-7} i\\\frac{L}{l} = 7.02 * 10^{-7} H/m[/tex]

De acuerdo al calendario ecológico 2020, escriba cuanto CO2 produce el Ecuador y en un resumen máximo de 7 líneas, determine porque son importante los humedales en la biodiversidad.

Answers

Answer:

43,919.66 Kilotones de Co2 en 2016.

Explicación:

Ecuador produce 43,919.66 Kilotones de Co2 en 2016. Las tierras húmedas son muy importantes para la biodiversidad porque proporcionan hábitat a millones de animales. Alrededor del 35 por ciento de todas las especies amenazadas y en peligro vive en estas tierras húmedas. Estas tierras húmedas son altamente productivas y tienen la capacidad de mejorar la calidad del agua, prevenir la degradación del suelo y proporcionar alimentos a los animales que viven en estas tierras húmedas.

A test car is driving toward a solid crash-test barrier with a speed of 46 mi/h. Two seconds prior to impact, the car begins to brake, but it is still moving when it hits the wall. After the collision with the wall, the car crumples somewhat and comes to a complete stop. In order to estimate the average force exerted by the wall on the car, what information would you need to collect?

Answers

Answer:

we have to measure distances and time, possibly with an automated system since the values ​​are very small

Explanation:

For this exercise we can use the relationship between momentum and momentum

        I = ∫ F dt = Δp

        F t = m [tex]v_{f}[/tex] - mv₀

In the exercise they indicate that the final speed is zero

         F t = - m v₀

         F = -m v₀ / t

With this equation we can find what measurements should be carried out.

To find the speed with which the car collides with the wall, less measure the displacement and its time during the braking process before reaching the wall and from here find the speed with which it reaches the wall.

During the impact, we must find the time that the vehicle is in contact with the wall in the first approach is equal to the time that the car takes to reach the final speed of zero.

In summary we have to measure distances and time, possibly with an automated system since the values ​​are very small

calculate the wavelength of a wave if 5 complete waves occupy a length of 20m

Answers

the answer is 20 / 5 = 4

The wavelength of the wave will be 4 meters. when 5 complete waves occupy a length of 20m.

What is wavelength?

Wavelength is defined as the space between waves' crests, particularly between electromagnetic or sound wave points. A recurring event's frequency is measured by how many times it occurs in a unit of time. To underline the difference from spatial frequency, it is also occasionally referred to as temporal frequency.

There is an inverse relationship between the frequency and the wavelength of the waves as the wavelength increases the frequency decreases and if the wavelength decreases the frequency increases.

Given that a wave has 5 complete waves occupying a length of 20m. The wavelength of the wave will be calculated as below:-

λ = Distance / frequency

λ = 20 / 5

λ = 4 meters

Therefore, the wavelength of the wave will be 4 meters. when 5 complete waves occupy a length of 20m.

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The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of the ball before it hits the ground is 33 meters/second. Assuming that the ball experienced a constant acceleration throughout this descent, calculate the magnitude of the acceleration. A. 0.24 g

Answers

Answer:

Magnitude of the acceleration(g) = 9.7 meters/second²

Explanation:

Given:

Height of tower = 56 meter

Time taken = 3.4 second

Final velocity (v) = 33 meters/second

Initial velocity (u) = 0 meters/second

Find:

Magnitude of the acceleration(g)

Computation:

Using first equation of motion:

v = u + at

Magnitude of the acceleration(g)

v = u + gt

33 = 0 + g(3.4)

g = 33 / 3.4

g = 9.7 meters/second²

Magnitude of the acceleration(g) = 9.7 meters/second²

A boy of mass 45kg sits 109cm to the left of seesaw. Another boy of mass 29000g wants to balance the seesaw. At what distance he needs to sit?

Answers

Answer:

[tex]d_{2}[/tex] = 169 cm

Explanation:

Mass 1 = 45 kg   => Force = 450 N

Mass 2 = 29 kg   => Force = 290 N

According to principle of moments:

=> [tex]F_{1}d_{1} = F_{2}d_{2}[/tex]

Where [tex]F_{1}[/tex] = 450 N, [tex]d_{1}[/tex] = 109 cm and [tex]F_{2}[/tex] = 290 N

=> (450)(109) = 290[tex]d_{2}[/tex]

=> 49050 =  290[tex]d_{2}[/tex]

Dividing both sides by 290

=> [tex]d_{2}[/tex] = 169 cm

water is a nonpolar molecule true or false​

Answers

Answer:

Water is non-polar molecule False

Water is polar molecule because the electronegativity of Oxygen is much greater than electronegativity of hydrogen and it has also a bend shape that is why it is polar molecule.

Explanation:

I hope this will help you :)

False. Water is a polar molecule.

About water

Water (H2O) consists of two hydrogen atoms and one oxygen atom. The oxygen atom has a higher electronegativity, meaning it attracts electrons more strongly than hydrogen.

As a result, the shared electrons in the covalent bonds between hydrogen and oxygen are pulled closer to the oxygen atom, creating an uneven distribution of charge.

This leads to a partial negative charge (δ-) on the oxygen atom and partial positive charges (δ+) on the hydrogen atoms, making water a polar molecule.

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Swamp coolers are effective because _____.

A. the water is colder than the air.
B. the water pulls heat from the room to undergo a phase change.
C. the thermal energy of the water is decreasing.
D. the water's latent heat of vaporization is being pulled from the air.​

Answers

Answer:

D. the water's latent heat of vaporization is being pulled from the air.

Explanation:

A swamp cooler also generally referred to as the evaporative cooler is an electronic device that uses moisture to cool air. This simply means that, the electronic device works on the principle of evaporation of water to cool the surrounding air.

In swamp coolers, water absorbs large amount of warm air via the evaporative wet cooler pad, so as to evaporate and consequently cooling the air effectively and efficiently.

Swamp coolers are effective because the water's latent heat of vaporization is being pulled from the air.

The latent heat of vaporization can be defined as the energy that is being absorbed by water during evaporation.

The swamp coolers are typically made up of the following essential components, these are;

1. Float.

2. Blower.

3. Pump.

4. Evaporative pad.

5. Water supply valve.

Hence, through the principle of evaporative cooling (latent heat of vaporization), swamp coolers reduces or lower the air temperature in its surroundings.

Answer:

B and D

Explanation:

What do you observe as you immerse the empty jug in a bucket which contains water? Explain why you observe this phenomenon. ​

Answers

Answer:

The jug drowns because the density of the jug is more than that of the density of water.

Answer:

it gets force upwards .

as there is presence of atmospheric pressure in it which causes upthrust and push upwards.

Differences Between light year and astronomical unit in two points .

Answers

Answer:

A light year is the distance light travels in a year. ... And an astronomical unit is the average distance between the earth and the sun. So the distance to the sun is by definition one AU. A parsec is the distance at which one astronomical unit subtends an angle of one second of arc.

Answer: A light year is the distance light travels in a year. ... And an astronomical unit is the average distance between the earth and the sun. So the distance to the sun is by definition one AU. A parsec is the distance at which one astronomical unit subtends an angle of one second of arc

Explanation:

A projectile is fired with an initial speed of 60.3 m/s at an angle of 34.2 above the horizontal on a long flat firing range.

Part A: Determine the maximum height reached by the projectile.

Part B: Determine the total time in the air.

Part C: Determine the total horizontal distance covered (this is, the range).

Part D: Determine the speed of the projectile 1.20 s after firing.

Part E: Determine the direction of the projectile 1.20 s after firing.

Answers

Answer:

A.) H = 58.6 m

B.) T = 6.92 s

C.) 345.12 m

D.) V = 22.13 m/s

E.) Ø = 32.1 degree

Explanation:

Given that the

initial speed U = 60.3 m/s

Angle Ø = 34.2 degree

A.) At maximum height, final velocity V is equal to zero.

Using the third equation of motion under gravity.

V^2 = U sin Ø^2 - 2gH

Substitute for U and g. Where g = 9.8 m/s^2

0 = (60.3 sin 34.2)^2 - 2 × 9.8 × H

1148.78 = 19.6 H

H = 1148.78/19.6

H = 58.6 m

B.) To Determine the total time in the air, let us use the formula

V = UsinØ - gt

At maximum height, V = 0

t = UsinØ/g

Total time T = 2t

Therefore, T = 2UsinØ/g

T = (2 × 60.3 × sin 34.2)/9.8

T = 67.79/9.8

T = 6.92 s

C.) To determine the total horizontal distance covered which is the range, we will use second equation of motion.

S = UcosØT - 1/2gt^2

Where S = range R

g = 0, since the range is not a vertical distance

T = total time

Substitute all the parameters into the formula

R = 60.3 cos 34.2 × 6.92

R = 345.12 m

D.) After 1.2 s firing,

V = UsinØ - gt

Where t = 1.2 s

Substitute into the formula

V = 60.3 × sin34.2 - 9.8 × 1.2

V = 33.89 - 11.76

V = 22.13 m/s

Therefore the speed of the projectile 1.20 s after firing is 22.13 m/s

E.) The direction will be determined by using the formula

t = VsinØ/ g

Cross multiply

VsinØ = gt

Make SinØ the subject of formula

SinØ = gt/V

SinØ = (9.8×1.2)/22.13

Sin Ø = 11.76/22.13

Sin Ø = 0.53

Ø = sin^-1( 0.53 )

Ø = 32.1 degree

The standard wave format for any wave is wave. When depicting wave in standard wave format, the direction of motion must be rotated by 90 degrees. Only one of two waves is shown at a time when placing wave in standard wave format.

Answers

Answer:

Transverse wave  and Longitudinal wave  and Electromagnetic wave

Explanation:

An inverted wave is a wave in which the vibrations of the particles are perpendicular to the direction of wave motion. Longitudinal waves, on the other hand, are waves in which the vibrations of the particles are parallel to the direction of wave motion. Electromagnetic waves are waves that do not require medium media for transmission, including radio waves, microwaves, UV lights, etc. Most electromagnetic waves are transverse in nature.

Answer:

Transverse wave  and Longitudinal wave  and Electromagnetic wave

Explanation:

You are launching a 2 kg potato out of a potato cannon. The cannon is 1.7 m long and is aimed 35 degrees above the horizontal. It exerts a 40 N force on the potato. What is the kinetic energy (in J) of the potato as it leaves the muzzle of the potato cannon?

Answers

Answer:

Explanation:

work done by force exerted by canon = force x displacement

= 40 x 1.7 =  68 N

This energy would have been added to the potato .

Increase in potential energy of potato = mgh

= mg sin 35 x 1.7  = 2 x 9.8 x sin 35 x 1.7 = 19.11 J

Increase in kinetic energy = 68 - 19.11

= 48.89 J

Two straight, parallel wires a and b carry currents in opposite directions, and are separated by a distance d. The magnitude of the force exerted by each wire on a segment of length L of the other wire is F. The vector sum of these forces is

Answers

Answer:

Zero

Explanation:

The magnetic field due to the first wire on the second wire with current i₁ in the first wire at a distance d from the second wire is B₁ = μ₀i₁/2πd.

The magnetic force due to this field on the second wire of length segment, L and current i₂ is F₁ = Bi₂L = (μ₀i₁/2πd)i₂L = μ₀i₁i₂L/2πd = F

The magnetic field due to the second wire on the first wire with current i₂ in the first wire at a distance d from the second wire is B₂ = μ₀i₂/2πd.

The magnetic force due to this field on the first wire of length segment, L and current i₁ is F₂ = Bi₁L = (μ₀i₂/2πd)i₁L = μ₀i₁i₂L/2πd = F

Since their magnetic fields are in opposite directions, according to the right hand rule, their forces would also be in opposite directions.

So F₁ = F and F₂ = -F

So their vector sum F₁ + F₂ = F +(-F) = F - F = 0

Neptune moves in an elliptical orbit with the sun at one of the foci. The length of half of the major axis is kilometers, and the eccentricity is 0.0086. Find the perihelion distance of Neptune from the sun. Round your answer to the nearest kilometers.

Answers

Given that,

Eccentricity = 0.0086

Suppose, The length of half of the major axis is [tex]1\times10^{9}\ km[/tex]

We need to calculate the distance from the center to the foci

Using formula of eccentricity

[tex]e=\dfrac{c}{a}[/tex]

[tex]c=e\times a[/tex]

Where, e = eccentricity

a = major axis

c = the distance from the center to the foci

Put the value in to the formula

[tex]c=0.0086\times1\times10^{9}[/tex]

[tex]c=8600000[/tex]

We need to calculate the perihelion distance of Neptune from the sun

Using formula of distance

[tex]d=a-c[/tex]

Put the value into the formula

[tex]d=1\times10^{9}-0.0086\times10^{9}[/tex]

[tex]d=991400000\ km[/tex]

Hence, The perihelion distance of Neptune from the sun is 991400000 km.

alculate the potential difference if 20J of energy are transferred by 8C of charge.

Answers

Answer:

V = 2.5 J/C

Explanation:

Given:

Energy = E = 20 J

Charge = Q = 8 C

Required:

Potential Difference = V = ?

Formula:

V = [tex]\frac{E}{Q}[/tex]

Solution:

V = 20/8

V = 2.5 J/C

Answer:

Given :

✧ Energy transferred = 20J ✧ Charge = 8C

To Find :

✧ Potential difference

Using Formula :

We know that the electric potential difference is also known as voltage (v).

[tex]{\star{\small{\underline{\boxed{\sf{\red{ V =\dfrac{E}{Q}}}}}}}}[/tex]

✧ Potential difference ✧ E = Energy transferred✧ Q = Charge

Solution :

Substituting the given values in the formula to find potential difference :

[tex]{\dashrightarrow{\small{\pmb{\sf{ V =\dfrac{E}{Q}}}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{ V =\dfrac{20}{8}}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{ V = \cancel{\dfrac{20}{8}}}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{ V = {\dfrac{10}{4}}}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{ V = \cancel{\dfrac{10}{4}}}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{\underline{\underline{\purple{V = 2.25}}}}}}}[/tex]

Hence, the potential difference is 2.25V.

[tex]\underline{\rule{220pt}{3pt}}[/tex]

Consider a transition at 5000 Å with a width of 1 Å and a cavity 2 cm3 in volume. How many electromagnetic modes exist in this frequency band for this cavity?

Answers

Answer:

total number of modes is 8

Explanation:

attached here is the calculations

why is urbanization a contribution to pollution?

Answers

Answer:

people in urban areas strip the soil of nutrition and makes it difficult to grow crops. people of urban areas consume more energy,food,and water. people in urban areas remove minerals and metals from the ground so, urbanization is a contribution to pollution .

Explanation:

it may help you and give me brainliest

Answer:

pollution and loss of trees not to mention how much electricity we use which doesnt benefit the world.

Explanation: because when we urbanize things we get rid of natural resources around us

Please someone to help me with this will be very grateful In a light bulb, how is electrical energy transformed into light? and in an LED, will it be the same?

Answers

Answer:

LED;

      The energy of photons emitted by an LED is dictated by the band gap of the semiconductor used – the energy required to make an electron–hole pair. When an electron and hole recombine in a radiative process, a photon carries away the extra energy.

BULB

        In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy. ... 1, chemical potential energy is converted to electrical energy, which is immediately converted to light energy and heat energy

       This flow of charge converts chemical potential energy into electrical energy. In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy. bulb have a fillament but LED have no filament they produce energy through clod process but bulb have a filament and they produce energy through hot process

Explanation:

This progression of charge changes over substance expected vitality into electrical vitality. In the light, the progression of charge through the fiber warms it up and makes it shine. Along these lines, the light believers electrical vitality to warm vitality and light vitality.

hope soo u can understand my point

What is the function of the uterus during embryo development?

Answers

Answer:

The uterus plays a significant part in the pregnancy, menstruation, zygote implantation, conception, labor, and delivery of the baby along with other essential reproductive system organs.

Explanation:

The uterus is a female reproductive organ that is pare shaped and situated between the urinary bladder and the rectum ins the pelvis.  The placenta develops links with the uterine blood vessels that provide the embryo with nutrition through an umbilical cord. When this happens, the uterus delivers signals to the brain to adjust the secretion of the hormone such that releases of more eggs (i.e. ovulation) are halted and the menstrual cycle momentarily stops, thereby verifying the pregnancy. In pregnancy the uterus provides the space and an adequate atmosphere for the fetus to develop safely, it provides feedback to the brain which regulates hormones release. The uterus forms a link between the mother and the baby through the placenta and umbilical cord not only to provide the requisite nutrients and oxygen but also to extract the waste products and purify the blood of the fetus before the fetal organs take over.

What will be the resistance Rstretched of the wire if it is stretched to twice its original length? Assume that the density and resistivity of the material do not change when the wire is stretched.

Answers

Answer:

Hence, the resistance of the stretched wire will be four times that of the original wire.

Explanation:

The resistance of a material is expressed as R = ρL/A

Volume of the original material V = Area * Length = A*L

ρ is the resistivity of the material

R is the resistance

A is the cross sectional area

L is the length of the wire.

If the wire is stretched o twice its original length then new length of the wire L₂ = 2L. Note that an increase in the length of wire will affect its area but its volume and density will not change.

This means V = V₂

A*L = = A₂*L₂

A*L = A₂*(2 L)

A = 2 A₂

A₂ = A/2

The new resistance of the material Rf = ρL₂/A₂

R₂ = ρ(2 L)/(A/2)

Rf =  2ρL * 2/A

Rf = 4(ρL/A)

Since R = ρL/A

R₂ = 4R

Hence, the resistance of the stretched wire will be four times that of the original wire.

If the wire is stretched to twice its original length, the new resistance would be quadrupled.

The resistance (R) of a wire is given by:

[tex]R=\rho\frac{L}{A} \\\\where\ L\ is\ length\ of\ wire, A\ is\ the\ cross\ sectional\ area\ and\ \rho\ \\is\ the\ resistivity[/tex]

Since the wire is stretched, the new length (L₁) is twice its original length, hence:

L₁ = 2L

An increase in length affects the area, the new area (A₁) is:

initial volume = volume after stretch

AL = A₁L₁

AL = A₁(2L)

A₁ = A/2

The resistance of the stretched wire (R₁) is:

[tex]R_1=\rho\frac{L_1}{A_1} \\\\R_1=\rho\frac{2L}{A/2} \\\\R_1=4\rho\frac{L}{A}=4R[/tex]

Therefore if the wire is stretched to twice its original length, the new resistance would be quadrupled.

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Please!!! I need some help!!! I will give Brainliest To anyone who truly helps.
Determine the net force charge acting at q1 (+ 2.0 × 10-5C), caused by q2 (-4.0 × 10-5 C) and q3 (-4.0 × 10-5 C). Be sure to include a free body diagram representing the force acting at q1 in your solution. Determine the net electric field acting at q1.

Answers

Answer:

Please INCLUDE a picture.

Explanation:

You did not include a picture, so there is no way to tell how the charges will interact with each other.

Please INCLUDE a picture.

The net force acting on q1 is 3.2 N to the right.

The force on q₁ due to q₂ is:

F1 = k * q₁ * q₂ / r²

where:

k is Coulomb's constant, which is 8.98755 × 10⁹ N m² C⁻²

q₁ is the charge of q₁, which is +2.0 × 10⁻⁵ C

q₂ is the charge of q₂, which is -4.0 × 10⁻⁵ C

r is the distance between q₁ and q₂, which is 0.1 m

Plugging in the values, we get:

F₁ = 8.98755 × 10⁹ N m² C⁻² * 2.0 × 10⁻⁵ C * -4.0 × 10⁻⁵ C / (0.1 m)²

= 6.4 N

The force on q₁ due to q₃ is:

F₂ = k * q₁ * q₃ / r²

where:

k is Coulomb's constant, which is 8.98755 × 10⁹ N m² C²

q₁ is the charge of q₁, which is +2.0 × 10⁻⁵ C

q₃ is the charge of q₃, which is -4.0 × 10⁻⁵ C

r is the distance between q₁ and q₃, which is 0.2 m

Plugging in the values, we get:

F₂ = 8.98755 × 10⁹ N m² C⁻² * 2.0 × 10⁻⁵ C * -4.0 × 10⁻⁵ C / (0.2 m)²

= 16 N

The net force on q₁ is the sum of F₁ and F₂:

Fnet = F₁ + F₂

= 6.4 N + 16 N

= 22 N

The net force on q1 is to the right because both F₁ and F₂ are to the right.

Net electric field

The net electric field acting on q1 is 3.2 N/C to the right.

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HELPPPP!!!!!

At which point does the satellite have the most gravitational potential energy?
O A. Point A
O B. Point B
O C. Point
OD. Point D

Answers

Answer:

Since gravitational potential is generally defined to be zero at infinity

and gravity does work as an object moves from infinity in a gravitational field,  

(the potential becomes more negative)  the farther the satellite is from the attractive force the greater is its gravitational potential. Since point E is most distant from the attractive force it has the most gravitational potential.

The Gravitational potential energy connected to a planet's position within the gravitational field of a central object, such as a star or a larger planet, is referred to as its gravitational energy.

The gravitational potential energy is given by:

PE = -G × (M × m) ÷ r

Here, (G) is the gravitational constant, (M) is the mass of a planet, (m)  is the mass of a planet, and distance (r).

From the given figure, points E and A are the farthest.

Hence, at points E and A satellite have the most gravitational potential energy

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