Find the volume and round to the nearest hundredths if you need too

Answer:

Options A, C, E

hope it helps

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Step-by-step explanation:

Answer:

a) The linear function that models the volume of hydrogen in the balloon at any time [tex]t[/tex] is [tex]V(t) = 2 + 0.5\cdot t[/tex].

b) 26 seconds are needed to completely fill the balloon.

Step-by-step explanation:

The statement has a mistake, the correct form is described below:

Weather balloons are filled with hydrogen and released at various sites to measure and transmit data about conditions such as air pressure and temperature. A weather balloon is filled with hydrogen at the rate of [tex]0.5\,\frac{ft^{3}}{s}[/tex]. Initially, the balloon has [tex]2\,ft^{3}[/tex] of hydrogen.

a) The volume of weather balloons is increasing linearly in time ([tex]t[/tex]), in seconds, since the rate of change of volume ([tex]\dot V[/tex]), in cubic feet per second, is stable. The linear function of the volume of the weather balloon in terms of time is:

[tex]V(t) = V_{o} + \dot V\cdot t[/tex] (1)

Where:

[tex]V(t)[/tex] - Current volume, in cubic feet.

[tex]V_{o}[/tex] - Initial volume, in cubic feet.

If we know that [tex]V_{o} = 2\,ft^{3}[/tex] and [tex]\dot V = 0.5\,\frac{ft^{3}}{s}[/tex], then the volume as a function of time is:

[tex]V(t) = 2 + 0.5\cdot t[/tex]

b) If we know that [tex]V(t) = 2 + 0.5\cdot t[/tex] and [tex]V(t) = 15\,ft^{3}[/tex], then the time taken to fill the balloon is:

[tex]V(t) = 2 + 0.5\cdot t[/tex]

[tex]V(t) - 2 = 0.5\cdot t[/tex]

[tex]t = \frac{V(t) - 2}{0.5}[/tex]

[tex]t = \frac{15-2}{0.5}[/tex]

[tex]t = 26\,s[/tex]

26 seconds are needed to completely fill the balloon.

Answer:

[tex]Area = 337[/tex]

Step-by-step explanation:

Given

[tex]a = 42.5[/tex]

[tex]c = 35.5[/tex]

[tex]B = 153.5^\circ[/tex]

Required

Area of triangle

This is calculated as:

[tex]Area = 0.5 *a* c * \sin(B)[/tex]

This gives:

[tex]Area = 0.5 *42.5* 35.5 * \sin(153.5)[/tex]

[tex]Area = 0.5 *42.5* 35.5 * 0.4462[/tex]

[tex]Area = 336.602125[/tex]

[tex]Area = 337[/tex] --- approximated

Answer:

It's Sin.

Thumbs-up (^_-)

Step-by-step explanation:

the answer is A ,since the unknown side is opposite while the known side is the hypotenuse

Answer:

A. Ms harris was the fastest considering she finished 2.5 miles under 14.5 minutes

Step-by-step explanation:

Answer:

A =16.25 cm^2

Step-by-step explanation:

The area of a triangle is given by 1/2 bh where b is the base and h is the height

A = 1/2 (5) * 6.5

A =16.25 cm^2

Answer: c is your answer hope this helped

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Step-by-step explanation:

Answer:

90 degree

Step-by-step explanation:

think of a 90 degree turn                            

 thats only a quarter turn

but a full angle is 360

so divide 360 by 4

Step-by-step explanation:

perimeter = 2×(7+5) = 2×12= 24 units

area = 7×5 = 35 sq. units

Answer:

A

Step-by-step explanation:

Draw a circle and cut it into 3 equal parts. shade 1 part

hope this helps please mark as brainliest

Draw a circle and cut it into 3 equal parts best describe to show 1/3 shaded, option A is correct

Since 1/3 represents one out of three equal parts, drawing a circle and dividing it into 3 equal parts allows you to shade one of those parts to accurately represent 1/3.

This method ensures that each part represents an equal fraction of the whole, which is necessary to accurately show 1/3 shaded.

Hence, one-way to show 1/3 shaded is draw a circle and cut it into 3 equal parts. shade 1 part.

To learn more on Fractions click:

https://brainly.com/question/10354322

The complete question is:

which best describe one-way to show 1/3 shaded?​

(A) Draw a circle and cut it into 3 equal parts. shade 1 part

(B) Draw a circle and cut it into 3 unequal parts. shade 1 part

Answer:

B

Step-by-step explanation:

Use quadratic formula

Answer:

The expected cost is $8.75

Step-by-step explanation:

Given

[tex]Time = \{1pm, 2pm, 3pm, 4pm\}[/tex]

[tex]C_1 = \$5[/tex] --- If Bob and Anna meet

[tex]C_2 = \$10[/tex] --- If Bob and Anna do not meet

Required

The expected cost of  Bob's meal

First, we list out all possible time both Bob and Anna can select

We have:

[tex](Bob,Anna) = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3)[/tex][tex],(3,4),(4,1),(4,2),(4,3),(4,4)\}[/tex]

[tex]n(Bob, Anna) = 16[/tex]

The outcome of them meeting at the same time is:

[tex]Same\ Time = \{(1,1),(2,2),(3,3),(4,4)\}[/tex]

[tex]n(Same\ Time) = 4[/tex]

The probability of them meeting at the same time is:

[tex]Pr(Same\ Time) = \frac{n(Same\ Time)}{n(Bob,Anna)}[/tex]

[tex]Pr(Same\ Time) = \frac{4}{16}[/tex]

[tex]Pr(Same\ Time) = \frac{1}{4}[/tex]

The outcome of them not meeting:

[tex]Different = \(Bob,Anna) = \{(1,2),(1,3),(1,4),(2,1),(2,3),(2,4),(3,1),(3,2)[/tex]

[tex],(3,4),(4,1),(4,2),(4,3)\}[/tex]

[tex]n(Different) = 12[/tex]

The probability of them meeting at the same time is:

[tex]Pr(Different) = \frac{n(Different)}{n(Bob,Anna)}[/tex]

[tex]Pr(Different) = \frac{12}{16}[/tex]

[tex]Pr(Different) = \frac{3}{4}[/tex]

The expected cost is then calculated as:

[tex]Expected = C_1 * P(Same) + C_2 * P(Different)[/tex]

[tex]Expected = \$5 * \frac{1}{4} + \$10 * \frac{3}{4}[/tex]

[tex]Expected = \frac{\$5}{4} + \frac{\$30}{4}[/tex]

Take LCM

[tex]Expected = \frac{\$5+\$30}{4}[/tex]

[tex]Expected = \frac{\$35}{4}[/tex]

[tex]Expected = \$8.75[/tex]

The expected cost is $8.75

the area of a rectangle is the product of its length and width.

Answer:

3 shares

Step-by-step explanation

9514 1404 393

Answer:

  a.hx()→−∞as x→−∞and hx()→−∞as x→∞

Step-by-step explanation:

The negative leading coefficient tells you the function tends toward -∞ as x gets large. The even degree tells you it goes the same direction as x tends toward -∞.

  h(x) → -∞  for x large or small . . . . matches A

Answer:

12n-10=14, n=2

Step-by-step explanation:

( Twelve times of a number decreased by 10 is equal to 14 ) This sentence can be written mathematically to be: 12n-10=14

The answer: Add 10 to both sides: 12n-10=14 > 12n-10+10=14+10 > 12n=24

Divide both sides by 12: 12n=24 > [tex]\frac{12n}{12} =\frac{24}{12}[/tex] > n=2

Answer:

D.f(x)=2x-9and g(x)=X+9/2

Answer:

3) (I) Numeric , and (II) Numeric

Step-by-step explanation:

Numeric variable:

The variable assume number values.

Categorical values:

The variable assumes labels. Examples are yes/no, good/bad.

(I) Fuel economy (miles per gallon) of used car

(II) Number of auto insurance claims in a month

Both of these variables are numbers, none have labels, so they are both numeric. The correct answer is given by option 3).

Answer:

Part A: (-7,-4)

Part B: (3,-4)

Step-by-step explanation:

Answer:

2/10 I believe

Step-by-step explanation:

3/10 + 4/10= 7/10

9/10 - 7/10 = 2/10

Answer:

Hello! In this picture I marked the new dot for that point and reflected it across the x axis!

The original coordinates are: 5, -3

and the new coordinates are: 5, 3

Hope that helps!

Answer: North Africa is separated from the Iberian Peninsula by the Strait of Gibraltar, which connects the Mediterranean Sea with the Atlantic Ocean.

Answer:

By the straight of Gibraltar

Answer:

The tank must remain intact for 1183 years.

Step-by-step explanation:

Exponential equation for decay:

The amount of a substance after t years is given by:

[tex]A(t) = A(0)e^{rt}[/tex]

In which A(0) is the initial amount and r is the decay rate.

A storage tank contains a liquid radioactive element with a half-life of 96 years.

This means that [tex]A(96) = 0.5A(0)[/tex], and we use this to find r.

[tex]A(t) = A(0)e^{rt}[/tex]

[tex]0.5A(0) = A(0)e^{96r}[/tex]

[tex]e^{96r} = 0.5[/tex]

[tex]\ln{e^{96r}} = \ln{0.5}[/tex]

[tex]96r = \ln{0.5}[/tex]

[tex]r = \frac{\ln{0.5}}{96}[/tex]

[tex]r = -0.0072[/tex]

So

[tex]A(t) = A(0)e^{-0.0072t}[/tex]

It will be relatively safe for the contents to leak from the tank when 0.02% of the radioactive element remains. How long must the tank remain intact for this storage procedure to be safe?

This is t for which [tex]A(t) = 0.0002A(0)[/tex]. So

[tex]A(t) = A(0)e^{-0.0072t}[/tex]

[tex]0.0002A(0) = A(0)e^{-0.0072t}[/tex]

[tex]e^{-0.0072t} = 0.0002[/tex]

[tex]\ln{e^{-0.0072t}} = \ln{0.0002}[/tex]

[tex]-0.0072t = \ln{0.0002}[/tex]

[tex]t = -\frac{\ln{0.0002}}{0.0072}[/tex]

[tex]t = 1183[/tex]

The tank must remain intact for 1183 years.

Answer:

we have

secθ = 2

[tex] \frac{1}{cos θ} [/tex]=2

Cosθ =[tex] \frac{1}{2 }[/tex]

[tex] \frac{b}{h }=\frac{1}{2 }[/tex]

b=1

h=2

p=[tex] \sqrt{2²-1} = \sqrt{3} [/tex]

again

Cot θ=[tex] \frac{b}{p }[/tex]

Cot θ=[tex] \frac{1}{ \sqrt{3}} [/tex]

Cot θ=[tex] \frac{\sqrt{3}}{3} [/tex]

It lies in Quadrant III cot is positive

Cot θ=[tex] \frac{\sqrt{3}}{3} [/tex]

b. (sqrt 3)/3

9514 1404 393

Answer:

  16 miles

Step-by-step explanation:

The problem can be modeled by a right triangle with one angle of 7° and the side opposite being 10,000 ft. The distance needed is the hypotenuse of the triangle, so the relevant trig relation is ...

  Sin = Opposite/Hypotenuse

  Hypotenuse = Opposite/Sin

  air distance = (10,000 ft)/sin(7°) ≈ 82,055 ft

At 5,280 ft per mile, that is ...

  (82,055 ft)/(5,280 ft/mi) ≈ 15.54 mi

The plane's air distance to the airport is about 16 miles.

3x−2y=12;−3x+8y=−6

Step: Solve3x−2y=12for x:

3x−2y=12

3x−2y+2y=12+2y(Add 2y to both sides)

3x=2y+12

3x

3

=

2y+12

3

(Divide both sides by 3)

x=

2

3

y+4

Step: Substitute

2

3

y+4forxin−3x+8y=−6:

−3x+8y=−6

−3(

2

3

y+4)+8y=−6

6y−12=−6(Simplify both sides of the equation)

6y−12+12=−6+12(Add 12 to both sides)

6y=6

6y

6

=

6

6

(Divide both sides by 6)

y=1

Step: Substitute1foryinx=

2

3

y+4:

x=

2

3

y+4

x=

2

3

(1)+4

x=

14

3

(Simplify both sides of the equation)

Answer:

x=

14

3

and y=1