Find the value of y. *


40
80
140

The interquartile range of the data-set is of 5.5, which means that the middle 50% kindergarten classes has a number of students that differ by at most 5.5.

For this problem, the ordered data-set is given by:

18, 18, 18, 20, 21, 22, 23, 23, 24, 24.

There are 10 elements, hence:

Then the IQR is:

Q3 - Q1 = 23.5 - 18 = 5.5.

The IQR is of 5.5, which means that the middle 50% kindergarten classes has a number of students that differ by at most 5.5.

More can be learned about the interquartile range of a data-set at https://brainly.com/question/17083142

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Answer:

see below

Step-by-step explanation:

Consider the year 2000 to be year 0. This would make year 2028 year 8.

Population growth or decay function: [tex]A = Pe^{rt}[/tex]

where A is the final amount, P is the principal amount, r is the rate, and t is time.

[tex]A = 18,500e^{(0.048)(8)}[/tex]

This can be simplified to

[tex]A = 18,500e^{0.384}[/tex]

Hopefully this is what the question is asking!

Answer:

B I'm pretty sure.

Step-by-step explanation:

Answer:

It really depends on how much percent of your overall grade tests count as. But, usually they count for about 60% of your grade (depending on what grade you are in). You have about 65% at the lowest and a 75% at the highest. But, I'm just going by what my school does, I don't know how your school grades tests.

Step-by-step explanation:

Answer:

43.96

Step-by-step explanation:

To find Circumference the formula is

2*3.14*R=C

replace R with your radious which is 7

2*3.14*7=43.96

Answer:

2.[tex]-2m^4-6m^2+4m+9[/tex]

3.[tex]-2m^4-6m^2-4m+9[/tex]

Step-by-step explanation:

In general we can write a polynomial in standard form as

[tex]ax^n+bx^n^-^1+cx^n^-^2+...+px+q[/tex]

Given [tex]4m-2m^4-6m^2-4m+9[/tex]

Combine the like terms: 4m and -4m

4m-4m=0

We have 4m-4m=0

So, write the remaining terms

[tex]-2m^4-6m^2+9+0[/tex]

= [tex]-2m^4-6m^2+9[/tex]

This is in decreasing order of powers.

Hence the answer is the standard form is

[tex]-2m^3-6m^2+9[/tex]

But in the given options, you can choose option 2 and option 3 are in standard form.

Because they are in decreasing order of powers.

In other two options, the constants term is first and the highest power term is at the last. So, they are not in standard form.

-2m^4-6m^2+4m+9

-2m^4-6m^2-4m+9

I hope this helps you.

And please comment if I need to do corrections.

Please let me know if you have any questions.

Answer:

2n + 20

Step-by-step explanation:

The solution set for the quadratic equation (2x - 7)² = 25 is 6 and 1.

A quadratic equation is an algebraic expression in the form of variables and constants.

A quadratic equation has two roots as its degree is two.

The solution set for a quadratic equation is the roots of the quadratic equation.

Given, (2x - 7)² = 25.

2x - 7 = ± 5.

2x = ± 5 + 7.

x = (± 5 + 7)/2.

x = 12/2 Or 2/2.

x = 6 or 1.

learn more about quadratic equations here :

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Answer:

B

Step-by-step explanation:

Answer:

Step-by-step explanation: so

First you should have paired attention and I don’t understand either sorry!

Answer:

wait what

Step-by-step explanation:

Answer:

y = x - 2

Step-by-step explanation:

Find the slope using rise over run

(y2 - y1) / (x2 - x1)

Plug in the points:

(y2 - y1) / (x2 - x1)

(-5 - 4) / (-3 - 6)

-9 / -9

= 1

Using y = mx + b, plug in the slope and a point to solve for b:

y = mx + b

4 = 1(6) + b

4 = 6 + b

-2 = b

Plug in the slope and b to y = mx + b

y = 1x - 2

y = x - 2

So, the equation of the line is y = x - 2

Answer:

B.

Step-by-step explanation:

edge2020

Answer:

B

Step-by-step explanation:

the blue parabola shows (1/4x)^2, the red shoes x^2, you can see the horizontal stretch, hope this helps :)

Answer:

It's 3 and 177.

Step-by-step explanation:

Let the angle be x°. Then its supplementary is 59x°.

We know,

x+ 59x=180

or, x = 3°

and another angle, 59x°= 177°

Answer:

1) [tex]sin \left(\dfrac{- \pi}{12} \right) = \dfrac{(\sqrt{2} - \sqrt{6} }{4}[/tex]

2) [tex]tan\left(\dfrac{ \pi}{12} \right) = 2 - \sqrt{3}[/tex]

3) [tex]tan\left(\dfrac{ 5\cdot \pi}{12} \right) = 2 + \sqrt{3}[/tex]

Step-by-step explanation:

1) [tex]sin \left(\dfrac{- \pi}{12} \right) = sin(-15^{\circ})[/tex]

sin(-15°)  = sin(30° + (- 45°)) = sin(30°)cos(-45°) + cos(30°)sin(-45°)

sin(30°)cos(-45°) + cos(30°)sin(-45°) = 1/2 × (√2)/2 + (√3)/2 × (-√2)/2

1/2 × √2/2 + √3/2 × -√2/2 = (√2)/4 - (√6)/4 = ((√2) - (√6))/4

sin(-15°)  = ((√2) - (√6))/4

[tex]sin \left(\dfrac{- \pi}{12} \right) = sin(-15^{\circ}) = \dfrac{(\sqrt{2} - \sqrt{6} }{4}[/tex]

2) [tex]tan\left(\dfrac{ \pi}{12} \right) = tan(15^{\circ})[/tex]

tan(15°)  = tan(45° + (-30°)) = (tan(-30°) + tan(45°))/(1 - tan(-30°)×tan(45°))

(tan(-30°) + tan(45°))/(1 - tan(-30°)×tan(45°)) = ((-1/√3) + 1)/(1 - (-1/√3))

((-1/√3) + 1)/(1 - (-1/√3)) = (3 - √3)/(3 + √3) = (3 - √3)·(3 -√3)/((3 - √3)·(3 + √3))

(3 - √3)·(3 -√3/((3 - √3)·(3 + √3)) = (9 - 6·√3 + 3)/(9 - 3) = (12 - 6·√3)/6

(2 - √3)

[tex]tan\left(\dfrac{ \pi}{12} \right) = tan(15^{\circ}) = 2 - \sqrt{3}[/tex]

3) [tex]tan\left(\dfrac{ 5\cdot \pi}{12} \right) = tan(75^{\circ})[/tex]

tan(75°)  = tan(30° + 45°) = (tan(30°) + tan(45°))/(1 - tan(30°)×tan(45°))

(tan(30°) + tan(45°))/(1 - tan(30°)×tan(45°)) = ((1/√3) + 1)/(1 - 1/√3)

((1/√3) + 1)/(1 - 1/√3) = (3 + √3)/(3 - √3) = (3 + √3)·(3 +√3/((3 - √3)·(3 + √3))

(3 + √3)·(3 +√3/((3 - √3)·(3 + √3)) = (9 + 6·√3 + 3)/(9 - 3) = (12 + 6·√3)/6

(12 + 6·√3)/6 = 2 + √3

[tex]tan\left(\dfrac{ 5\cdot \pi}{12} \right) = tan(75^{\circ}) = 2 + \sqrt{3}[/tex]

Answer: C

Step-by-step explanation:

992/4=165

846/6=141

165+141=306

(992/4) + (846/6) = 306 total calories consumed

The answer has to be 30.

Correct me if I am incorrect but I would believe I am correct. Have a good one!

It's A. B doesn't really make sense ("derivative of the differential equation" is somewhat nonsensical, "derivative of an equation" is not meaningful).

More to the point: Slope fields are used to visualize solutions to differential equations of the form

y' = f(x, y)

You take some point (x, y) and evaluate y' at the point. This gives the slope of the line tangent to the particular solution to the DE that passes through the point (x, y ).

Sample several points and evaluate y' at those points and you get several different slopes.

Simple example:

y' = x ² - y ² = (x + y ) (x - y )

Let's take the points (1, 1), (-1, 0), and (2, -2), at which we get slopes

y' = f (1, 1) = 0

y' = f (-1, 0) = 1

y' = f (2, -2) = 0

From here, you can get particular solutions that pass through a certain point by interpolating the slopes of the tangents to the solution. I've attached a slope field for the example here at the points listed above. (In the order red, green, black). Each light gray arrow in the background shows the slope of the tangent line.

If you're still unsure how the slope field is generated, I suggest looking up videos on the subject. The process is a bit difficult to describe without a dynamic visual aid.

Answer:

so this is clearly a division problem

the equation will be

5 ÷1/3     Keep switch flip

according to KSF the equation will change to this

5*3  = 15

So she will be able to cut 15 peices.

Thank you, Hope it helps

Answer:

the value of x equals to 20 thats is solution okay

Answer: im in 100% sure but i think its yes

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

I used photomath