Find the value of x in the isosceles triangle shown below.
5
5
C
6
Choose
answer:
= 761
x = V11
x = 15

Answer:

4

9/8

Step-by-step explanation:

Given the fraction a/b, the reciprocal is expressed as 1/(a/b) = b/a

For 1/4;

1/4

= 1÷1/4

= 1 * 4/1

= 4

Hence the reciprocal is 4

b) 8/9

= 1 ÷ 8/9

= 1 * 9/8

= 9/8

Hence the reciprocal of 8/9 is 9/8

-8

Step-by-step explanation:

you subtract all for numbers to get your solution

Answer:8n-4

Step-by-step explanation:

Answer:

n=1/2

Step-by-step explanation:

Step1: 2n-n-4+7n

Step2: 8n-4

Step3: 8n=4

Step4: n=4/8

Step5: n=1/2

Answer:

im doing that too </3 plz

Step-by-step explanation:

i think the question is not correct write it again or attach the pic ic

The mean of a data set is the sum of all data elements divided by its count.

The mean weight of the 19 girls is 33.4 kg

Let

[tex]b \to[/tex] boys

[tex]g \to[/tex] girls

[tex]n \to[/tex] the total population

So:

[tex]b = 11[/tex]

[tex]\bar x_b = 31.9[/tex]

[tex]g = 19[/tex]

[tex]n = 30[/tex]

[tex]\bar x = 32.85[/tex]

The mean of all students is calculated as follows:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x = \frac{\bar x_b \times b + \bar x_g \times g}{n}[/tex]

Substitute known values

[tex]32.85 = \frac{31.9 \times 11 + \bar x_g \times 19}{30}[/tex]

[tex]32.85 = \frac{350.9 + \bar x_g \times 19}{30}[/tex]

Multiply through by 30

[tex]30 \times 32.85 = 350.9 + \bar x_g \times 19[/tex]

[tex]985.5 = 350.9 + \bar x_g \times 19[/tex]

Collect like terms

[tex]985.5 -350.9 = \bar x_g \times 19[/tex]

[tex]634.6 = \bar x_g \times 19[/tex]

Divide through by 19

[tex]33.4 = \bar x_g[/tex]

[tex]\bar x_g = 33.4[/tex]

Hence, the mean weight of the girls is 33.4 kg

Read more about mean at:

https://brainly.com/question/2018505

Answer:

A= (1/2)(X)(2X)

(1/2)(2X^2)

= (2X^2)/2

Answer:

The last one

Step-by-step explanation:

Answer:

If the shipping is for all books then the total cost is 164.95

Answer:

tienes que hacer cuadritos

Answer:

59

Step-by-step explanation:

Given

f(x) = 2x² + 9

f ( -5) = 2 * ( -5)² + 9

= 25 * 2 + 9

= 50 + 9

= 59

════════ ∘◦❁◦∘ ════════

════════════════════

f(x) = 2x² + 9

════════════════════

f(-5) = ?

════════════════════

#as you the x inside the (x) changed into (-5) it means that you need to change the x into -5.

f(-5) = 2(-5)² + 9

= 2 × 25 + 9

= 50 + 9 = 59

#So f(-5) = 59

════════════════════

Answer:

Your answer is.......

x^3 + 2x^2 + 4x + 8=0 Note.. if x=-2 then whole equation is 0

So, (x+2) is one factor.

x^3 + 2x^2 + 4x + 8

=x^2(x+2)+4(x+2)

(x+2)(x^2+4)

Mark my answer as brainlist. pls pls pls

Answer:

it is 3mm i had the test

Step-by-step explanation:

edge 2021

Answer:

3mm! -w-

Step-by-step explanation:

Answer:

29

Step-by-step explanation:

Answer: Depends on the number of grades

Step-by-step explanation:

School has up to 6th grade: 15

School has up to 7th grade: 12

School has up to 8th grade: 11

School has up to 9th grade: 10

School has up to 10th grade: 9

Need more grades? Comment please

Answer:

Step-by-step explanation:

7 hr/3 pumps

So first we want to find the unit rate which would be...

5.25 hr/1 pump

Now that we found the unit rate we are going to multiply it by 2 because there are 2 pumps...

5.25*2=10.5

So our answer is 10.5 hr/ 2 pumps

                                                                                    YOUR WELCOME!

                                                                                     BRAINLIEST?????

Answer →→→→ 12

Hope this helps you

God bless

Answer:

p(8p + 7)

Step-by-step explanation:

Factorise is when you find the product of the question before taking away the brackets.

so, if you go p(8p + 7), you times p with everything inside the brackets giving you 8p^2 + 7

therefore, the answer is p(8p + 7)

Hope this helped :)

Answer:

Ambitious Ambitious Ambitious Ambitious

Answer:

27 /35

Step-by-step explanation:

Para sumar fracciones, busque el LCD y luego combinar.

Answer: 50%

Step-by-step explanation:

In 2010 the percentage of fatal accidents was 16%.

This is 34% less than it was in 2000 because the text says that the 2010 percentage was 16% after being reduced by 34% from 2010.

The percentage of fatal accidents in 2000 is therefore:

= 2010 fatal percentage + Percentage reduced from 2000

= 16% + 34%

= 50%

Answer:

Area of shaded region is 18π square unit

Step-by-step explanation:

Please mark brainliest

Answer:

18π cm²

Step-by-step explanation:

The shaded region is calculated as

A = area of circle × fraction of circle

   = πr² × [tex]\frac{80}{360}[/tex] ( r is the radius of the circle )

   = π × 9² × [tex]\frac{2}{9}[/tex]

   = 81π × [tex]\frac{2}{9}[/tex]

   = 9π × 2

   = 18π cm²

Answer:

16.67% less

or

she only made 83% of her anticipated $18,000

Step-by-step explanation:

3000/18000 = 0.1666 or 16.67% less

15000/18000 = 0.8333 or 83%

Answer:

Ok I will help you

Answer:

Step-by-step explanation:

common factor of 2a² and 10ab= 2a

Answer:

One solution, x=-18/11.

Step-by-step explanation:

y=1/2x-7

y=6x+2

---------------

1/2x-7=6x+2

1/2x-7-6x=2

1/2x-6x=2+7

1/2x-12/2x=9

-11/2x=9

x=9/(-11/2)

x=(9/1)(-2/11)

x=-18/11

Answer:

Step-by-step explanation:

[tex]\frac{6}{\frac{3}{4}}\\ \\ 6\left(\frac{4}{3}\right)\\ \\ 8\ pieces[/tex]

Answer:

x=-2

Step-by-step explanation:

2 = 3x+14/4

2x4 = 4x4    4 cancels

8 = 3x+14

8-14 = 14-14    14 cancels

-6 = 3x

-6/3 = 3/3   3 cancels and you're left with x

-2=x

Answer:

18a^7

Step-by-step explanation:

Find the product:-

[tex] \tt \dfrac{18}{30} \times \dfrac{5}{4} [/tex]

[tex] = \tt \dfrac{18 \times 5}{30 \times 4} [/tex]

[tex] = \tt \cancel\dfrac{18 \times 5}{30 \times 4} = \boxed{\tt\dfrac{ \: \: 3 \: \: }{4}} \: \: \: \: \: \: \: \: \: [/tex]

Multiply:-

[tex] \tt4 \: \dfrac{1}{8} \times \dfrac{1}{9} [/tex]

[tex] = \tt \dfrac{25}{8} \times \dfrac{1}{9} [/tex]

[tex] = \tt\dfrac{25}{8} \times \dfrac{1}{9} [/tex]

[tex] = \tt \cancel\dfrac{25 \times 1}{8 \times 9} = \cancel{ \tt\dfrac{ \: \: 25 \: \: }{72}} [/tex]

[tex] = \boxed{\tt\dfrac{ \: \: 1 \: \: }{3 }} [/tex]

Find the product:-

[tex] \tt \dfrac{15}{18} \times \dfrac{6}{9} \times \dfrac{27}{21} [/tex]

[tex] = \tt \cancel\dfrac{15 \times 6 \times 27}{18 \times 9 \times 25} [/tex]

[tex] = \boxed{\tt \dfrac{ \: \: 5 \: \: }{7}} [/tex]

Multiply:-

[tex] \tt \: 3 \: \dfrac{7}{70} [/tex]

[tex] = \tt \cancel\dfrac{3 \times 7}{1 \times 70} = \boxed{ \tt\dfrac{ \: \: 3 \: \: }{10}} [/tex]

Solve:-

[tex] \tt(6 \times \dfrac{1}{4}) \times \dfrac{1}{2} \times \dfrac{1}{2} [/tex]

[tex] = \tt \cancel{( \dfrac{3 \times 1}{1 \times 2} )} \times \dfrac{1}{2} \times \dfrac{1}{2} [/tex]

[tex] = \tt(\dfrac{3}{ \: \: 2 \: \: }) \times \dfrac{1}{2} \times \dfrac{1}{2} [/tex]

[tex] = \tt\dfrac{3}{ 2 } \times \dfrac{1}{2} \times \dfrac{1}{2} \: \: \: \: \: \: \: \: = \boxed{ \tt \dfrac{ \: \: 3 \: \: }{8}} [/tex]