Find the two whole numbers that are the closest to square root 42. Explain your reasoning.

Answers

Answer 1

Answer: 6 and 7

Step-by-step explanation:

Find the square root of 42 = 6.48

Closest whole numbers to 6.48 are 6 and 7


Related Questions

describe the relationship between the variables in the graph and equation

Answers

The equation that describes the proportional relationship between the variables on the graph is given as follows:

y = 12x.

What is the proportional relationship?

The general format of a proportional relationship is defined as follows:

y = kx.

In which k is the constant of proportionality, and hence the output variable y is obtained as the multiplication of the input x and the constant of proportionality k.

One point from the graph given at the end of the answer is given as follows:

(8, 96).

Hence the constant of the proportional relationship is given as follows:

k = 96/8 = 12.

Then the equation is of:

y = 12x.

Meaning that the output variable y is obtained by the multiplication of the input variable x and the constant of proportionality k.

Missing Information

The graph is given by the image presented at the end of the answer.

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a local aquarium found that if the price of admission was $11$⁢11, the attendance was about 20002000 customers per week. when the price of admission was dropped to $7$⁢7, attendance increased to about 26002600 per week. write a linear equation for the attendance in terms of the price, p

Answers

The linear equation for the attendance in terms of the price, p is

2600= -150p + 3650

A =m*p + b

where A= attendance , m = slope , b = y-intercept and p = price

When p=11 then A=2000 , i  e , (11, 2000).

When p= 7 , then A=2600, i .e ,  (7 , 2600).

m= (b-d)/(a-c)

=> m = (2600-2000)/(7 - 11)

        = -150

Therefore , 2600= -150p + b

To get the value of b,

putting the value of p in the obtained equation,

we get,

2600= -150 * 7+ b

2600 = -1050 + b

b = 3650

Hence , our equation becomes

2600= -150p + 3650

Linear equations are equations of the first order. The linear equations are defined for lines in the coordinate system. When the equation has a homogeneous variable of degree 1 (i.e. only one variable), then it is known as a linear equation in one variable. A linear equation can have more than one variable. If the linear equation has two variables, then it is called linear equations in two variables and so on

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S

How could you show QR SR?

O A.

OB.

O C.

OD.

Use SAS to show triangle PRQ is congruent to triangle SRP

Use SAS to show triangle PRQ is congruent to triangle PRS

Use AAS to show triangle PRQ is congruent to triangle PRS

Use ASA to show triangle PRQ is congruent to triangle PRS

Answers

We prove that QR≅SR, using SAS to show triangle PRQ is congruent to triangle PRS. So option B is correct.

In the given question;

Given: PR bisects ∠QPS. PQ=12 units, and PS=12 units.

Prove: QR≅SR

We have to find how we prove QR≅SR.

As we can see that;

PQ = PS

Since PR is bisector.

So PR is common in both triangles PRQ and PRS.

PR=PR

Since PR is bisector.

So ∠PRQ=∠PRS

As we know that if two sides and one angle are congruent, then using the Side-Angle-Side (SAS) Theorem, the both triangle is congruent.

So ∠PRQ≅∠PRS

So QR≅SR

Hence, we prove that QR≅SR, using SAS to show triangle PRQ is congruent to triangle PRS. So option B is correct.

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a local amateur ice skater estimates that the probability she will place first in the next regional competition is 0.56. what are the odds she will win this competition? a) 14 to 39 b) 11 to 14 c) 33 to 17 d) 39 to 14 e) 14 to 11 f) none of the above.

Answers

The odds she will win this competition is 14 to 11.

What is probability?

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events. The degree to which something is likely to happen is basically what probability means. The potential outcomes for a random experiment using this fundamental theory of probability, which is also applied to the probability distribution. Knowing the total number of outcomes is necessary before we can calculate the likelihood that a specific event will occur.

Odds in favor of an event is ratio of probability of an event to its completion:

Probability =0.56 / 1-0.56

= 0.56/0.44

= 56/44

= 14/11

Hence, the odds she will win this competition is 14 to 11.

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Carmen made 6 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 6 necklaces was $31.80 . If the beads cost a total of $21.60, how much did each pendant cost?

Answers

Answer:

The answer is $1.70

Step-by-step explanation:

What I did is $31.80-21.60=$10.20. $10.20 is the amount of money for all 6 pendants, so to find how much 1 pendant is I just divided $10.20 by 6 which got me $1.70. Hope that helped you. :)

develop a class shapes 2d to represent all 2d geometric shapes excluding line. class should represent the name of the object (a string) the color of the objects (color) and methods that all subclasses should implement (abstract methods) including:

Answers

This is the UML diagram for the development of the program, in which Shapes 2D is the superclass and Circle, Square, Triangle, Rectangle, Rhombus, and Parallelogram are subclasses.

​​​​​​​This is the program in C++ demonstrating the above classes.

#include<iostream>

using namespace std;

class shapes

{

public:

   string name;

   string color;

   virtual void getAttributes()=0;

};

class Circle: public shapes

{

public:

   float radius;

   Circle(string n,string c, float r)

   {

       name=n;

       color=c;

       radius=r;

   }

   float getPerimeter()

   {

       return(2*(3.142)*radius);

   }

   float getArea()

   {

       return((3.142)*(radius*radius));

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Square:public shapes

{

public:

   float side;

   Square(string n,string c, float s)

   {

       name=n;

       color=c;

       side=s;

   }

   float getPerimeter()

   {

       return(4*side);

   }

   float getArea()

   {

       return(side*side);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Triangle:public shapes

{

public:

   float base;

   float height;

   float side1;

   float side2;

   float side3;

   Triangle(string n,string c)

   {

       name=n;

       color=c;

   }

   float getPerimeter()

   {

       cout<<"Enter side1\n";

       cin>>side1;

       cout<<"Enter side2\n";

       cin>>side2;

       cout<<"Enter side3\n";

       cin>>side3;

       return(side1+side2+side3);

   }

   float getArea()

   {

       cout<<"Enter base\n";

       cin>>base;

       cout<<"Enter height\n";

       cin>>height;

       return((0.5)*base*height);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Rectangle:public shapes

{

public:

   float length;

   float breadth;

   Rectangle(string n,string c, float l,float b)

   {

       name=n;

       color=c;

       length=l;

       breadth=b;

   }

   float getPerimeter()

   {

       return(2*(length+breadth));

   }

   float getArea()

   {

       return(length*breadth);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Rhombus:public shapes

{

public:

   float diagonal1;

   float diagonal2;

   float side;

   Rhombus(string n,string c)

   {

       name=n;

       color=c;

   }

   float getPerimeter()

   {

       cout<<"Enter Side\n";

       cin>>side;

       return(4*side);

   }

   float getArea()

   {

       cout<<"Enter diagonal 1\n";

       cin>>diagonal1;

       cout<<"Enter diagonal 2\n";

       cin>>diagonal2;

       return((0.5)*diagonal1*diagonal2);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Parallelogram:public shapes

{

public:

   float base;

   float height;

   Parallelogram(string n,string c, float b,float h)

   {

       name=n;

       color=c;

       base=b;

       height=h;

   }

   float getPerimeter()

   {

       return(2*(base+height));

   }

   float getArea()

   {

       return(base*height);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

int main()

{

   int choice;

   while(1)

   {

       cout<<"\n\nEnter your choice :";

       cout<<"\n1 for Circle\n";

       cout<<"2 for Square\n";

       cout<<"3 for Triangle\n";

       cout<<"4 for Rectangle\n";

       cout<<"5 for Rhombus\n";

       cout<<"6 for Parallelogram\n";

       cin>>choice;

       system("cls");

       switch(choice)

       {

       case 1:

           {

               float r;

               cout<<"Enter radius\n";

               cin>>r;

               Circle c("Circle","Yellow",r);

               c.getAttributes();

               cout<<"Perimeter : "<<c.getPerimeter()<<endl;

               cout<<"Area : "<<c.getArea()<<endl;

           }break;

       case 2:

           {

               float side;

               cout<<"Enter side\n";

               cin>>side;

               Square s("Square","Red",side);

               s.getAttributes();

               cout<<"Perimeter : "<<s.getPerimeter()<<endl;

               cout<<"Area : "<<s.getArea()<<endl;

           }break;

       case 3:

           {

               Triangle t("Triangle","Green");

               t.getAttributes();

               cout<<"Perimeter : "<<t.getPerimeter()<<endl;

               cout<<"Area : "<<t.getArea()<<endl;

           }break;

       case 4:

           {

               float l,b;

               cout<<"Enter Length and breadth\n";

               cin>>l>>b;

               Rectangle r("Rectangle","Blue",l,b);

               r.getAttributes();

               cout<<"Perimeter : "<<r.getPerimeter()<<endl;

               cout<<"Area : "<<r.getArea()<<endl;

           }break;

       case 5:

           {

               Rhombus r("Rhombus","Purple");

               r.getAttributes();

               cout<<"Perimeter : "<<r.getPerimeter()<<endl;

               cout<<"Area : "<<r.getArea()<<endl;

           }break;

       case 6:

           {

               float b,h;

               cout<<"Enter base\n";

               cin>>b;

               cout<<"Enter height\n";

               cin>>h;

               Parallelogram p("Parallelogram","Pink",b,h);

               p.getAttributes();

               cout<<"Perimeter : "<<p.getPerimeter()<<endl;

               cout<<"Area : "<<p.getArea()<<endl;

           }break;

       }

   }

}

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state a recursive definition for 2, -2, 2, -2

Answers

Answer:

Step-by-step explanation:

Chinese people eat beans so it would be Chinese

people

Which of the following binary operations are closed? a. subtraction of positive integers b. division of nonzero integers c. function composition of polynomials with real coefficients d. multiplication of 2×2 matrices with integer entries ​

Answers

The goal is to determine whether or not the following binary operations are closed.

A. Subtraction of positive integers: Under normal substation operation, a set of positive integers is not near. Since 1∈Ζ⁺ and 2∈Ζ⁺ but (2-1) = ₋1∉Z⁺.

B. A division of nonzero integers: Non-zero integer set Z/{0} is not closed under the operation. Since 1∈Z/{0} and 2∈ Z/{0} but 1/2 ∉ Z/{0}.

C.  Function composition of polynomials with real coefficients: The set of polynomials with real coefficients is closed when using the typical binary operator. Use the obvious conclusion that a polynomial is a combination of two polynomials [tex]f(x)[/tex] and [tex]g(x)[/tex]. Since every polynomial coefficient is real, every polynomial's composition will also have real coefficients.

D. The multiplication of 2×2 matrices with integer entries: Under the action of standard matrix multiplication Μ₂ₓ₂ (Z), the collection of matrices with integer elements, is close.

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I’ll give you points and brainlest answer if you answer with a legit answer!

Answers

answer:

(1/y)^3(1/z)^4

step-by-step explanation:

negative exponents just move the number to the denominator. so all you have to do is move the y & z to the denominator to change the exponents to positive. hope that helps!

In the first week of​ July, a record 1,060 people went to the local swimming pool. In the second​ week,105 fewer people went to the pool than in the first week. In the third​ week, 145 more people went to the pool than in the second week. In the fourth​ week, 199 fewer people went to the pool than in the third week. What is the percent decrease in the number of people who went to the pool over these four​ weeks?

Answers

The percent decrease in the number of people who went to the pool over these four weeks is 15%.

How to calculate the percentage?

A percentage is a value or ratio that may be stated as a fraction of 100. If we need to calculate a percentage of a number, we should divide it's entirety and then multiply it by 100.

The number of people by the fourth week will be:

= 1060 - 105 + 145 - 199

= 901

The percentage decrease will be:

= (1060 - 901) / 1060 × 100

= 159/1060 × 100

= 15%

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a rectangular package to be sent by a postal service can have a maximum combined length and girth (perimeter of a cross section) of 120 inches (see figure). find the dimensions of the package of maximum volume that can be sent. (assume the cross section is square.)

Answers

The dimensions of the package of maximum volume that can be sent are 20 inches by 40 inches.

Let us represent the length of the square cross-section of the postal package with x, and the width of the package with y.

So, the perimeter is given by the equation -

y + 4x = 120

y = 120-4x    -----------(1)

the volume will be

V = [tex]x^{2} y[/tex]        -----------(2)

Now, substitute (1) in (2), and we get,

V = [tex]x^{2}[/tex] (120-4x)

V = 120[tex]x^{2}[/tex] - 4[tex]x^{3}[/tex]

Differentiating with respect to x, we get,

V' = 240x - 12[tex]x^{2}[/tex]

V'=0

hence, 240x - 12[tex]x^{2}[/tex] = 0

12[tex]x^{2}[/tex] = 240x

dividing by 120x on both sides,

hence, x=20

Now, we know that,

y = 120 - 4x

y = 120-4(20)

y = 120-80

y=40

Hence, the dimensions that maximize the volume of the package are 20 inches by 40 inches.

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Christopher says that whenever you multiply a whole number by a fraction the product is either greater or less than the whole number. Do you agree with Christopher? Why or why not. If not provide an example.

Answers

Christopher's statement "whenever you multiply a whole number by a fraction the product is either greater or less than the whole number" is correct.

What is a Fraction?

A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.

The statement made by Christopher is correct, this is because a fraction is always either greater or lesser than 1. And multiplying a fraction to a whole number will give result either greater or less than the whole number, depending upon the type of fraction it is.

If the fraction is a proper fraction, than the result will be less than the whole number.If the fraction is a improper fraction, than the result will be greater than the whole number.

For example let's take the number 100,

Let's take a proper fraction, 2/5. Therefore, the result will be,

100 × (2/5) = 40

Let's take an improper fraction, 7/5. Therefore, the result will be,

100 × (7/5) = 140

Hence, Christopher's statement is correct.

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Complete the program so that it takes in 4 integers (a, b, c, and d) as arguments, stores them in the 2D array nums, and then prints their row, column, and total sums. The program should print the integers according to this formula:
(a) (b) (a+b)
(c) (d) (c+d)
(a+c) (b+d) ((a+b)+(c+d)+(a+c)+(b+d))
// (a+b) is the first row's sum
// (c+d) is the second row's sum
// (a+c) is the first column's sum
// (b+d) is the second column's sum.
// ((a+b)+(c+d)+(a+c)+(b+d)) is the total sum of all rows and columns

Answers

The program should print the integers according to this formula is

nums[0][0]=a;

nums[0][1]=b;

nums[1][0]=c;

nums[1][1]=d;

nums[0][2]= nums[0][0] + nums[0][1]; //a+b

nums[1][2]= nums[1][0] + nums[1][1]; //c+d

nums[2][0] = nums[0][0] + nums[1][0]; //a+c

nums[2][1] = nums[0][1] + nums[1][1]; //b+d

//sum = (a+b) + (c+d) + (a+c) + (b+d)

nums[2][2] = nums[0][2] + nums[1][2] + nums[2][0] + nums[2][1];

The nums array is 2 dimensional as shown below.

row, column column 0 column 1 column 2

row 0 a b a+b

row 1 c d c+d

row 2 a+c b+d (a+b)+(c+d)+(a+c)+(b+d)

The first index of an array always starts from 0.

Thus, nums[rows][columns] is used to access each element of the array.

The sum of first row elements is to be stored in the last index of row0, that is in nums[1][2].

Thus we equate nums[0][2] = nums[0][0] + nums[0][1]

Similarly, for 2nd row; nums[1][2] = nums[1][0] + nums[1][1]

The sum of first column is to be stored in last index of column0.

Thus, nums[2][0] = nums[0][0] + nums[1][0]

and for 2nd column,

nums[2][1] = nums[0][1] + nums[1][1].

Thus, the answer is--  

-------------------------------------------------------------------------------------------------------------------------------------

nums[0][0]=a;

nums[0][1]=b;

nums[1][0]=c;

nums[1][1]=d;

nums[0][2]= nums[0][0] + nums[0][1]; //a+b

nums[1][2]= nums[1][0] + nums[1][1]; //c+d

nums[2][0] = nums[0][0] + nums[1][0]; //a+c

nums[2][1] = nums[0][1] + nums[1][1]; //b+d

//sum = (a+b) + (c+d) + (a+c) + (b+d)

nums[2][2] = nums[0][2] + nums[1][2] + nums[2][0] + nums[2][1];

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What is the average rate of change of the functionf(x)=20(14)x from x = 1 to x = 2? enter your answer, as a decimal, in the box. Do not round your answer.

Answers

The average rate of change of the function f(x) from x = 1 to x = 2 is, -3.75 when the function f(x)=20(1/4)ˣ.

Given that,

We have to find what is the function f(x)=20(1/4)ˣ average rate of change from x = 1 to x = 2.

We know that,

Average rate of change(A(x)) of f(x) over a interval [a,b] is given by:

A(x)=(f(b)-f(a))/b-a

We get the function:

f(x)=20(1/4)ˣ

Now, the average rate of change from x = 1 to x= 2

At x = 1

Then;

f(1)=20(1/4)¹=5

At x = 2

Then;

f(2)=20(1/4)²=1.25

Substitute these in above formula we have;

A(x)=f(2)-f(1)/2-1=-3.75

Therefore, The average rate of change of the function f(x) from x = 1 to x = 2 is, -3.75 when the function f(x)=20(1/4)ˣ.

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If a circular flower bed has a diameter of 18ft.
What is the area of the flower bed?

Answers

It is 254.34 square feet.

Please! I don't understand this question! Help!
Zachary purchased a computer for ​$ on a payment plan. months after he purchased the​ computer, his balance was ​$. months after he purchased the​ computer, his balance was ​$. What is an equation that models the balance y after x​ months?

Answers

It’s just asking at the starting rate (y dollars for 1 month) so an equation for it may be x:y

PLEASE HELP ME WITH THIS QUESTION!!!
QUESTION ATTACHED BELLOW
THANKS IN ADVANCE!

Answers

Answer:
y < 1/2x - 4

A classroom has seven blue chairs five green chairs 18 red chairs and yellow nine chairs if a chair is selected at random which color is the least likely to be chosen

Answers

Answer:

green

Step-by-step explanation:

green

HELP FAST WILL GIVE BRAINIEST

Answers

Answer:

first this is English

providential

slow congealed

innovative, effectual

more easy to

A local deli makes turkey sandwiches and salami sandwiches at a weekly ratio of 2 salami sandwiches for every 5 turkey sandwiches. If the deli makes 60 turkey sandwiches this week, how many salami sandwiches did they make?

1. 5 salami sandwiches
2. 16 salami sandwiches
3. 30 salami sandwiches
4. 24 salami sandwiches

Please answer :)

Answers

Answer:

1.5

Step-by-step explanation:

The sum of the elements in a tuple can be recursively calculated as follows: the sum of the elements in a tuple of size 0 is 0 otherwise, the sum is the value of the first element added to the sum of the rest of the elements write a function named sum that accepts a tuple as an argument and returns the sum of the elements in the tuple.

Answers

The following is a code in python.

What is Python and why it is used?

Python is a popular computer programming language used to create software and websites, automate processes, and analyze data. Python is a general-purpose language, which means it can be used to make many different types of programs and isn't tailored for any particular issues.

What are the advantages of Python?

One of Python's biggest benefits is the variety of libraries and frameworks it offers. Everything from data visualization, machine learning, data science, natural language processing, and complex data analysis uses the Python Library, from NumPy to TensorFlow.

#Specify the function in

DefinedSum(tu)

# Verify whether the tuple contains 0

if len(tu) == 0

#Then, give back 0

return 0

#Otherwise

else:

#invoke the recursive function.

return tu[0]+Sum (tu[1:])

Set a variable of the tuple type

tu=(2,5,1,8,10)

#print, then invoke the function.

 print("The total of tuple is:"), sum(tu),

Output:

The sum of tuple is: 26

Here, we define the method "sum()" and send the parameter "tu" to the function, which saves the value of the tuple type.

If the length of the tuple is 0, then the if conditional expression should verify the condition and return 0.

If not, invoke the function, return the tuple's total (which is determined recursively), and exit.

Last but not least, initialize the "tu" variable of the tuple type, print, then run the sum function.

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Given the following piecewise function,

f(3) =
f(8) =
f(-1) =

Answers

Answer:

f(3) = 5

f(8) = 3

f(-1) = 0

Step-by-step explanation:

Just plug in the number from the parentheses into the inequalities and whichever makes the inequality true plug into that equation so for example f(3) = ?

first plug 3 into the inequalities: 3 ≤ 0, 0 < 3 ≤ 5, 3 > 5

then find the one that's true which is: 0 < 3 ≤ 5  

then plug into the equation that corresponds to that inequality: 2(3) - 1 → 6 - 1 = 5

which inequality has –12 in its solution set?abcdx + 6 less-than negative 8x + 4 greater-than-or-equal-to negative 6x minus 3 greater-than negative 10x + 5 less-than-or-equal-to negative 4abcd

Answers

The inequality contain -12 in its solution is  x + 5 ≤ -4.

What is inequality?

The phenomenon of an unfair and/or unequal distribution of opportunities and resources among the people who make up a society is referred to as inequality. To different people and in various contexts, the word "inequality" may mean different things.

We have to find from the given inequalities which inequality has -12 in its solution.

Consider, the given inequalities

(1)  x + 6 < -8

⇒ x < - 8 - 6

⇒ x < -14

This inequality does not contain -12 in its solution.

(2) x + 4 ≥ - 6

⇒  x ≥ -6 - 4

⇒ x ≥ - 10

This inequality does not contain -12 in its solution.

(3) x - 3 > -10

⇒  x  > -10 + 3

⇒  x > -7

This inequality does not contain -12 in its solution.

(4) x + 5 ≤ -4

⇒  x ≤ - 4 - 5

⇒  x ≤ -9

This inequality contain -12 in its solution.

Hence, the inequality contain -12 in its solution is  x + 5 ≤ -4.

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I do not know
how to do fractions please help

Answers

Answer:

should be the first one because 12 is the common factor between the two of them(had to be 20 characters long so i could answer your question)

It’s A. It it’s full then it’ll be a whole number.

Give a big-o estimate for the number additions used in this segment of an algorithm. T := 0 for i := 1 to n for j := 1 to n t := t + i + j.

Answers

The big oh notation for the given algorithm that is T := 0 for i := 1 to n for j := 1 to n t := t + i + j will be O(n).

What is big oh notation?

Big O notation is a type of mathematical notation that expresses how a function limits itself when the argument goes to zero or infinity. Big O Notation is a technique for expressing how time-consuming an algorithm is. As the input increases, it calculates how long it will take to perform an algorithm. In other words, it determines an algorithm's worst-case time complexity. The maximum runtime of an algorithm is expressed using the Big O Notation in data structures.

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Write a linear function g with the values g(2) = 3 and g(6) = 5

Answers

Answer:

g(x)=1/2x+2

Step-by-step explanation:

the coordinates provided here are (2,3) and (6,5)
slope intercept form is g(x)=mx+b

m is slope and b is y intercept

We use slope formula to find slope y2-y1/x2-x1

5-3/6-2

2/4

1/2

Now we can find b by putting the values in

g(x)=1/2x+b

5=1/2(6)+b

5=3+b

-3 -3

2=b

g(x)=1/2x+2

Hopes this helps please mark brainliest

A group of friends wants to go to the amusement park. They have $69. 75 to spend on parking and admission. Parking is $17. 25, and tickets cost $17. 50 per person, including tax. Write and solve an equation which can be used to determine pp, the number of people who can go to the amusement park.

Answers

The equation to determine the number of persons is x/(y+z) and total 2 people are there in total.

What does a math equation mean?The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions.For instance, the equation 3x + 5 = 14 consists of the two expressions 3x + 5 and 14, which are separated by the 'equal' sign.

Given: Several buddies want to visit the theme park. Spending money for parking and entry totals $69.75. Tickets cost $17.50 per person, tax included, and parking is $17.25.

Let,

x = total amount for parking and admission fee

y = ticket per person

z = parking cost per person

Total number of people who can go to the amusement park is given as:

= x/(y+z)                                                                                               =69.75/(17.50+17.25)

= 2

Therefore, the equation to determine the number of persons is x/(y+z)   and total 2 people are there in total.

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what does it mean to say that two variables are negatively​ associated?what does it mean to say that two variables are negatively​ associated?

Answers

When two variables are correlated negatively, the other variable's value falls as the value of the first variable rises.

Express the term negative correlation?

When two variables are correlated negatively, the other variable's value falls as the value of the first variable rises.

The correlation coefficent, which expresses correlation on a scale from +1 to -1, is used. Values less than 0 indicate a negative connection. An increase in one variable confidently foretells a drop in the other when there is a perfect negative correlation, with a coefficient of -1. An rise or decrease inside one variable consistently forecasts the same directional shift for the second variable, according to a perfect positive correlation that has a coefficient of +1. Non-zero coefficients between -1 and +1 are used to show lower degrees of connection.

Zero denotes the absence of a correlation: There is no propensity is for variables to change simultaneously.

Thus, when two variables are correlated negatively, the other variable's value falls as the value of the first variable rises.

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If ƒ(x) = 2x³ – 11x² + 13x − 4 and x − 4 is a factor of f(x), then find all of the
zeros of f(x) algebraically.

Answers

Answer:

The zeros of ƒ(x) are 4, 1, and -2.

there are unknown number of oranges in a bag. seven oranges in the bag are stale. now you need to pick two oranges out of the bag. the probability to pick two stale oranges is 2/21. what is the total number of the orange in the bag?

Answers

The total number of oranges present in the bag was 21.

Explain the term probability?A probability is a numerical representation of the likelihood or chance that a specific event will take place. Both proportions ranging from 0 to 1 and percentages extending from 0% through 100% can be used to describe probabilities.

For the stated question.

Let the total number of oranges in the bag be 'x'.

Total stale oranges = 7.

Thus,

Probability (first orange is stale) = Total stale oranges/ Total oranges.

Probability (first orange is stale) = 7/x

Probability (second orange is stale) = 6/(x - 1).

But, probability to pick two stale oranges is 2/21

7/x . 6/(x - 1) = 2/21

On solving,

x ² - x - 441 = 0

x = 21

Thus, the total number of oranges present in the bag was 21.

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