find the torque when the work done to more through an angel of 1/4π radians is 3j​

Answer: The maximum displacement the spring is stretched or compressed from its equilibrium position is its AMPLITUDE.

Explanation:

In simple harmonic motion, the restoring force which pulls the oscillating body back towards its rest position is proportional in magnitude to the displacement of the body from the rest position.

The simple harmonic motion in terms of MASS AND SPRING, simple pendulum and loaded test tube is the motion or movement of a particle in a to and fro movement along a straight line under the influence of force.

Mass and spring: This means when a string of suspended mass, M, with initial level of the spring is at rest, the spring will start moving upward and downward due to the imbalance of the suspended mass.

The maximum displacement as the spring is stretched or compressed from its equilibrium position is its AMPLITUDE. This is measured in units of meter.

Answer:

7.35..kg

Explanation:

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Answer:

V = f x λ

Explanation:

The options are confusing

Answer:

When atoms from different elements are joined together in groups, they form molecules. The atoms in molecules bind together chemically, which means that the atoms cannot be separated again by physical means, such as filtration. The molecule has different properties from the elements from which is was made.

Explanation:

Answer:

2

Explanation:

wave length is the distance between corresponding points of two consecutive waves

3. hertz

300

could i get brainiest

Answer:

0.125 volts

Explanation:

The induced emf can be sufficient to stimulate neuronal activity.

One such device generates a magnetic field within the brain that rises from zero to 1.5 T in 120 ms.

We need to find the induced emf within a circle of tissue of radius 1.6 mm and that is perpendicular to the direction of the field. The formula for the induced emf is given by :

[tex]\epsilon=-\dfrac{d\phi}{dt}[/tex]

Where

[tex]\phi[/tex] is magnetic flux

So,

[tex]\epsilon=-\dfrac{d(BA)}{dt}\\\\=2\pi r\times \dfrac{dB}{dt}\\\\=2\pi \times 1.6\times 10^{-3}\times \dfrac{1.5-0}{120\times 10^{-3}}\\\\=0.125\ V[/tex]

So, the induced emf is equal to 0.125 volts.

Answer:

Velocity can be directly added or subtracted.

For example, if a boat has a velocity V in still water.

And now you put the boat in a river with a current that has a velocity V'

The total velocity of the boat in that river is just the addition of these two velocities.

Velocity in the river  = V + V'

Where the only tricky part is that the velocity is a vector, so you need to take in account the directions of each vector.

In this case, we have a plane with a maximum velocity of 160km, let's assume a direction for this velocity, let's say that is in the positive x-direction.

Then we can write the velocity in the vector form:

velocity  = (vel in x-axis, vel in y-axis)

The velocity of the plane can be written as:

v = (160km/h, 0)

Now we add a crosswind of 30km/h

crosswind means that it is perpendicular, then it acts on the y-axis.

Then the total velocity of the plane will be:

velocity = (160km/h, 0) + (0, 30km/h)

velocity = (160km/h, 30km/h)

Now you can compute the total velocity of the airplane as the module of that vector.

Remember that for a vector (x, y) the module is:

mod = √(x^2 + y^2)

Then the module of the velocity is:

v = √( (160km/h)^2 + (30km/h)^2) = 162.8 km/h

Answer:

Energy moves between the particle of the medium.

Explanation:

Answer:

ij

Explanation:

Answer:

 α = 2.13 10⁻⁵ C⁻¹    ,  the closest material is ALUMINUM

Explanation:

The expression for thermal expansion is

          ΔL = α L₀ ΔT

temperatures are

         ΔT = 85 - 10 = 75 ° C

the length of the rod is L₀ = 125 m and L_f = 125.20 m

        ΔL = 125.20 - 125 = 0.20 m

        α = [tex]\frac{1}{L_o} \frac{\Delta L }{\Delta T}[/tex]

        α = [tex]\frac{ 1}{125} \ \frac{0.20 }{75}[/tex]

        α = 2.13 10⁻⁵ C⁻¹

When reviewing the table, the closest material is ALUMINUM

Answer:

Perpendicular ; Parallel

Answer:

-17.5 nC

Explanation:

charge A = -30 nC

charge B = -5 nC

After adding them it would be the average of the two charges because of the getting same voltage difference. so

c = (-30+(-5)) / 2 nC

c= -17.5 nC

answer is -17.5 nC

Answer:

  I = 1.8 N s,  it is directed towards the right  

Explanation:

For this exercise we use the relationship between momentum and moment

         I = Δp

         F t = p_f - p₀

in this case the initial velocity is v₀ = - 2,0 m / s and final velocity v_f = 10,0 m / s, we assume the positive right direction

          I = m (v_f - v₀)

let's calculate

         I = 0.150 (10.0 - (-2.0))

         I = 0.150 (10 + 2)

         I = 1.8 N s

as the impulse is positive it is directed towards the right

Answer:

Ferromagnetism is a kind of magnetism that is associated with iron, cobalt, nickel, and some alloys or compounds containing one or more of these elements. It also occurs in gadolinium and a few other rare-earth elements.

Explanation:

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Explanation:

transfer to babes are always at your advice by a particular motion being a particular wave motion along didn't wave is a wave which particular is a medium move a direction parallel to the direction of the wave moves something that is similar in the surveys on the medium moves of the same direction and bathe an accident to one or two Dimensions do in London killing babe attacks in one dimension and transverse waves attacks in two Dimensions the Waze cannot be paralyzed or organized

Answer:

False.

Explanation:

An aurora is a natural electric phenomenon that creates bright and colorful light displays in the sky. These dramatic and colorful lights are created when electrically charged particles from solar winds enter the Earth's atmosphere and interact with gases in the atmosphere.

Answer:

2000J

Explanation:

The formula for work is W=Force x Distance

W=FxD

W=500N x 4m

W=2,000 Joules

Answer:

The magnitude of the magnetic force acting on the conductor is 0.75 Newton

Explanation:

The parameters given in the question are;

The length of the straight segment of wire, L = 25 cm = 0.25 m

The current carried in the wire, I = 5 A

The orientation of the wire with the magnetic field = Perpendicular

The strength of the magnetic field in which the wire is located, B = 0.60 T

The magnetic force, 'F', is given by the following formula;

F = [tex]\underset{I}{\rightarrow }[/tex]·L×[tex]\underset{B}{\rightarrow }[/tex] = I·L·B·sin(θ)

Where;

[tex]\underset{I}{\rightarrow }[/tex] = The current flowing, I

L = The length of the wire

[tex]\underset{B}{\rightarrow }[/tex] = The magnetic field strength, B

θ = The angle of inclination of the conductor to the magnetic field

Where I = 5 A, L = 0.25 m, B = 0.60 T, and θ = 90°, we get;

F = 5 A × 0.25 m × 0.60 T × sin(90°) = 0.75 N

Therefore

The magnitude of the magnetic force, F = 0.75 N.

Solution :

Given :

Force, F = 500 N

Let [tex]$ \vec F = F_x\ \hat i + F_y\ \hat j$[/tex]

      [tex]$|\vec F|=\sqrt{F_x^2+F_y^2}$[/tex]

∴ [tex]$F_x=F \cos 60^\circ = 500 \ \cos 60^\circ = 250 \ N$[/tex]

  [tex]$F_y=-F \cos 30^\circ = -500 \ \cos 30^\circ = -433.01 \ N$[/tex]   (since [tex]$F_y$[/tex] direction is in negative y-axis)

[tex]$F=250 \ \hat i - 433.01 \ \hat j$[/tex]

So scalar components are : 250 N and 433.01 N

     vector components are : [tex]$250 \ \hat i$[/tex] and [tex]$-433.01\ \hat j$[/tex]

1.  Scalar components along :

 x' axis = 500 N, since the force is in this direction.

 [tex]$F_{x'}= F \ \cos \theta = 500\ \cos \theta$[/tex]

  Here, θ = 0° , since force and axis in the same direction.

So, cos θ = cos 0° = 1

∴ [tex]$F_{x'}=500 \times 1=500\ N$[/tex]

[tex]$F_{y'}= F \ \sin \theta = 500\ \sin 0^\circ=500 \times 0=0$[/tex]

[tex]$F_{y'}=F\ cos \theta$[/tex] but here θ is 90°. So the force ad axis are perpendicular to each other.

[tex]$F_{y'}=F\ \cos 90^\circ= 500 \ \cos 90^\circ = 500 \times 0=0$[/tex]

∴ [tex]$F_{x'}= 500\ N \text{ and}\ F_{y'}=0\ N$[/tex]

2. Scalar components of F along:

x-axis :

[tex]$F_x=F\ \cos \theta$[/tex],   here θ is the angle between x-axis and F = 60°.

[tex]$F_x=500 \times \cos60^\circ=250\ N$[/tex]

y'-axis :

[tex]$F_{y'}=F\ \cos \theta$[/tex],   here θ is the angle between y'-axis and F = 90°.

[tex]$F_{y'}=500 \times \cos90^\circ=500\times 0=0\ N$[/tex]

∴ [tex]$F_{x}= 250\ N \text{ and}\ F_{y'}=0\ N$[/tex]

Answer:

it goes up until we help it to but the moment we stop support it gets affected by gravity and goes back

Explanation:

Answer:

The SI unit of time is second (s) and temperature is Kelvin (K)

Explanation:

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Answer:

They generate electricity by contact.

Explanation:

The observation presented by the question above shows an example of electricity generated by the contact, which can also be called triboelectrification. This type of electricity is created when two objects made of different materials come into contact with each other, and that contact is interrupted soon afterwards, as occurs when someone, wearing woolen socks, walks over the carpet.

For triboelectrification to occur, it is necessary that at least one of the objects involved is electrically charged. This object, when in contact with another object, will transfer electrons carrying the neutral object, until the two objects have the same electrical potential. When interrupting the contact between the objects, the two are left with equal loads of energy.

Answer:

74.88N

Explanation:

From the question,

F = ma................... Equation 1

Where F = force exerted on the ball, m = mass of the ball, a = acceleration

But,

v² = u²+2as.............. Equation 2

Where v = final velocity, u = initial velocity, s = distance.

Given: v = 12 m/s, u = 0 m/s (from rest), s = 5.0 m

Substitute into equation 2 and solve for a

12² = 0²+2×a×5

144 = 10a

10a = 144

a = 144/10

a = 14.4 m/s²

Also Given: m = 5.2 kg,

Substitute into equation 1

F = 5.2×14.4

F = 74.88 N

Hence the force exerted on the ball is 74.88 N

Answer:

Part A

The power to turn on the lamp, ∑P = 3.36 W

Part B

The Resistor required is approximately 8.04 Ohms

Part C

The time for all the lights to go out is approximately 21.43 hours

Explanation:

The input voltage of the motor battery , V = 12 V

The capacity of the battery, Q = 6 Ah

The number of lamps in parallel = 8 lamps

The maximum voltage of each lamp,  = 3 V

The electric current in each lamp = 140 mA

The energy available in a battery, E = Q × V

For the battery, we have;

E = 6 Ah × 12 V = 72 Wh

The energy available in a battery, E = 72 Wh

Part A

The power used by the lamps, [tex]P_i[/tex] = [tex]I_i[/tex] × [tex]V_i[/tex]

∴ The total power used by the lamp, ∑P = 8 × 0.14 A × 3 V = 3.36 W

The power to turn on the lamp, ∑P = 3.36 W

Part B

The resistance required, is given as follows;

Resistor required = (Battery voltage - Lamp voltage)/(The sum of bulb current)

∴ Resistor required = (12 V - 3 V)/(8 × 0.14 A)

The Resistor required = 8.03571429 Ohms

The Resistor required ≈ 8.04 Ohms

Part C

The time for all the lights to go out = The time for the lamps to use all the power available in the battery

The time for all the lights to go out, t = E/∑P

∴ t = 72 Wh/(3.36 W) = 21.4285714 h

∴ The time for all the lights to go out, t ≈ 21.43 h

The time for all the lights to go out = The time for the lamps to use all the power available in the battery = t ≈ 21.43 h

∴ The time for all the lights to go out ≈ 21.43 hours.

Answer:

I = 1.666... amps

Explanation:

P = I*V or Power = Current * Voltage

(100 watts) = I * (60 Volts)

I = 1.666... amps