keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above
[tex]x-y=3\implies -y=-x+3\implies y=\stackrel{\stackrel{m}{\downarrow }}{1}x-3\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{ 1 \implies \cfrac{1}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{1} \implies \text{\LARGE -1}}}[/tex]
One side of a square is 14x + 14 feet. What is the perimeter of the square?
A. 42x + 3/4 feet
B. 56x + 1 feet
C. 14/4x feet
D. 28x + 1/2 feet
Answer:
The perimeter of a square is given by the formula P = 4s, where s is the length of one side.
Here, one side of the square is given as 14x + 14 feet. Substituting this into the formula, we get:
P = 4(14x + 14) feet
P = 56x + 56 feet
Therefore, the answer is option B: 56x + 1 feet.
Coins are placed into a treasure chest, and each coin has a radius of 1.2 inches and a height of 0.0625 inches. if there are 250 coins inside the treasure chest, how many cubic inches of the treasure chest is taken up by the coins? round to the nearest hundredth and approximate using π = 3.14. a. 0.28 in3 b. 70.65 in3 c. 117.75 in3d. 282.60 in3
From the given data, the answer is approximately 26.5 cubic inches. The closest option is b. 70.65 inches³.
The volume of each coin can be calculated as follows:
Volume of a coin = π × radius² × height
Volume of a coin = 3.14 × (1.2 inches)² × 0.0625 inches
Volume of a coin = 0.106 cubic inches
The total volume of all the coins can be found by multiplying the volume of one coin by the number of coins:
Total volume of coins = 0.106 cubic inches/coin × 250 coins
Total volume of coins = 26.5 cubic inches (rounded to the nearest tenth)
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A theme park has a ride that is located in a sphere. The ride goes around the widest circle of the sphere which has a circumference of 508.68yd . What is the surface area of the sphere? Use 3.14 for .
The surface area οf the sphere is apprοximately 82,203.84 square yards.
Let's start by using the fοrmula fοr the circumference οf a circle C = 2πr
where C is the circumference, π is the cοnstant pi (which is apprοximately equal tο 3.14), and r is the radius οf the circle. We knοw that the circumference οf the widest circle οf the sphere is 508.68 yards, sο we can set up an equatiοn as fοllοws:
508.68 = 2πr
Sοlving fοr r, we get:
r = 508.68 / (2π)
r = 80.99 yards (rοunded tο twο decimal places)
Nοw that we knοw the radius οf the sphere, we can use the fοrmula fοr the surface area οf a sphere:
A = 4πr²
Plugging in the value οf r, we get:
A = 4π(80.99)²
An ≈ 82,203.84 square yards
Therefοre, the surface area οf the sphere is apprοximately 82,203.84 square yards.
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A regression model to predict the price of diamonds included the following predictor variables: the weight of the stone (in carats where 1 carat = 0.2 gram), the color rating (D, E, F, G, H, or I), and the clarity rating (IF, VVS1, VVS2, VS1, or VS2).
weight, color, and clarity ratings
In a regression model, the price of diamonds can be predicted by using a number of predictor variables. The predictor variables that are commonly used to predict the price of diamonds include the weight of the stone, the color rating, and the clarity rating. The weight of the stone is typically measured in carats, where one carat is equivalent to 0.2 grams.The color rating of the diamond is typically measured on a scale of D to I, where D is the most colorless and I is the most yellow. The clarity rating of the diamond is typically measured on a scale of IF to VS2, where IF is the most flawless and VS2 is the most included. By using a regression model to predict the price of diamonds, it is possible to identify which of these predictor variables are most important in determining the price of a particular diamond. The regression model can also be used to estimate the price of a diamond based on its weight, color, and clarity ratings.
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The crosswalk in front of a school intersects the sidewalk at
an angle of 99º. Find the value of x.
The value of x, considering that 3x and 99º are supplementary angles, is given as follows:
x = 27.
What are supplementary angles?Supplementary angles are a pair of angles that add up to 180 degrees. In other words, if two angles are supplementary, then the sum of their measures is 180 degrees.
Supplementary angles can be adjacent (share a common vertex and a common side) or non-adjacent (do not share a common vertex or side). When two angles are supplementary, they form a straight line, and are sometimes referred to as a linear pair of angles.
For this problem, the angles 3x and 99º are a linear pair, hence the value of x is obtained as follows:
3x + 99 = 180
3x = 81
x = 81/3
x = 27.
Missing InformationThe image is presented at the end of the answer.
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Sample spaces for compound events
You're ordering a one-topping pizza. You can choose from 3 different toppings and 2 types of crust.
If you randomly pick the topping and crust, which of these tables lists all possible outcomes? (Each row
represents one outcome. )
Choose all answers that apply:
Table A
The sample space for this compound event consists of 6 possible outcomes, which can be represented by a table with 3 toppings and 2 crusts. Mathematically, this sample space can be represented by the formula nCr(3,2) × nCr(2,1) which simplifies to 3 × 2 = 6.
The sample space for this compound event can be represented by a table where each row represents one possible outcome. The number of outcomes is the product of the number of toppings and the number of crusts. In this case, the sample space consists of 3 toppings and 2 crusts, so there are 6 possible outcomes. The sample space is:
Table A
Topping 1 | Crust 1
Topping 1 | Crust 2
Topping 2 | Crust 1
Topping 2 | Crust 2
Topping 3 | Crust 1
Topping 3 | Crust 2
Mathematically, this sample space can be represented by the formula nCr(3,2) × nCr(2,1), where nCr(3,2) is the number of combinations of 3 toppings and 2 crusts, and nCr(2,1) is the number of combinations of 2 crusts and 1 topping. The formula can be simplified to 3 × 2 = 6, which is the same number of outcomes in the sample space.
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PLEASE HELP the question is on paper
a. The solution to the system of equations that is graphed in the diagram is: (6, -1).
b. This is the point where the lines intersect each other.
How to Find the Solution of System of Equations Graphically?To find the solution of the system of equations graphically, we plot the equations as lines on a coordinate plane and look for the point of intersection, which represents the solution to the system. If the lines are parallel, there is no solution, and if they overlap, there are infinitely many solutions.
a. The solution as shown in the graph given is: (6, -1).
b. We know this because the point where the two lines intersect is the solution of a system of equations.
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simplify: -√72
5-6√/2
0 -36√/2
6√√/2
06√/12
Answer: 6√√/2
Step-by-step explanation: just did it
Answer:
Step-by-step explanation:
[tex]-\sqrt{72}=-\sqrt{2*6*6}=-6\sqrt{2}[/tex]
What is the slope of the line represented by the equation
Step-by-step explanation:
[tex] - \frac{1}{2} [/tex]
Solve the system of equations
-2x + y = 10 and 8x + 3y = 32 by
combining the equations.
try
2x
8x
-2x
-8x
O
-
+y
+3y
=
= 10)
=
=32)
=
+y
10
+3y = 32
x+ 0] ² y=
To solve the system using the elimination method (AKA combining the equations), you want to first set up the system so that one variable will be eliminated when you add the equations together.
The first equation has -2x, while the second one has -8x. If we multiply the entire first equation by -4, we'd turn that -2x into 8x, which would cancel out when you add that with the -8x in the second equation:
-4 ( -2x + y = 10 ) –> 8x - 4y = -40
-8x + 3y = 32 –> -8x + 3y = 32
And if you add the new equations on the right, you'll end up with
0x - y = -8
which means y = 8.
We could do the something similar to eliminate the y's. The first equation has y, while the second one has 3y. If we multiply the entire first equation by -3, we'd turn that y into -3y, which would cancel out when you add that with the 3y in the second equation:
-3 ( -2x + y = 10 ) –> 6x - 3y = -30
-8x + 3y = 32 –> -8x + 3y = 32
And if you add the new equations on the right, you'll end up with
-2x + 0y = 2
which means x = -1.
Putting those together, we have a solution of (-1, 8), which checks in both equations.
2.731 ÷ 1000
[tex]2.731 \div 1000[/tex]
how do U do the for multiplying and dividing decimals
Alexis is on her senior soccoer team. She makes 73% of her foul shots, leading her team to 15 wins in 17 games for the reason. If Alexis took 86 foul shots during the season, how many shots did she make
Alexis made 63 foul shots during the season.
If Alexis made 73% of her foul shots, then she made 0.73 * 86 = 62.78 foul shots during the season.
However, since foul shots must be whole numbers, Alexis would have made either 62 or 63 shots.
We know that Alexis and her team won 15 out of 17 games during the season. This means that Alexis made foul shots in each of these 15 games, for a total of 15 * 2 = 30 foul shots.
If Alexis made a total of 62 foul shots during the season, she would have had to make an additional 32 foul shots in the two games they lost (17 games - 15 games they won = 2 games they lost). That would mean she made 16 foul shots in each of the two games they lost, which is unlikely.
Therefore, Alexis must have made 63 foul shots during the season, leaving only 23 foul shots missed (86 total foul shots - 63 made foul shots).
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I WILL GIVE BRAINLIEST
|a|=-a
|a-5|=5-a
Answer:
a ≤ 0a ≤ 5Step-by-step explanation:
You want the solutions to the absolute value equations ...
|a| = -a|a -5| = 5 -aAbsolute valueThe absolute value function is defined piecewise:
|x| = x . . . . for x ≥ 0|x| = -x . . . . for x < 0This means each of the equations can be rewritten as two equations on different domains.
Equation |a| = -aFor a ≥ 0, this is ...
a = -a
2a = 0 . . . . . add a
a = 0
For a < 0, the equation is ...
-a = -a . . . . for all a < 0
The solution to the equation is the union of these solutions:
a ≤ 0
Equation |a-5| = 5-aFor (a-5) ≥ 0, this is ...
a -5 = 5 -a
2a = 10
a = 5
For (a-5) < 0, this is ...
-(a -5) = 5 -a
a = a . . . . for all a < 5
The solution to the equation is the union of these solutions:
a ≤ 5
__
Additional comment
When a-5 ≥ 0, the value of a is a≥5.
When a-5 < 0, the value of a is a<5.
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a fair 6 -sided die is rolled 10 times and the resulting sequence of 10 numbers is recorded. how many different sequences are possible?
There are 60,466,176 different sequences that are possible.
Permutation represents a method of arranging things in order. In a fair 6-sided die rolled 10 times and the resulting sequence of 10 numbers is recorded, the different possible sequences are calculated as shown below:
When rolling a die, the possible outcomes are 1, 2, 3, 4, 5, and 6. As there are ten rolls, each roll has six possible outcomes. Thus, the total number of different sequences will be calculated as follows:6 × 6 × 6 × 6 × 6 × 6 × 6 × 6 × 6 × 6 = 60,466,176. Therefore, there are 60,466,176 different sequences that are possible.
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Work out the circumference of a circle with radius 7.5 cm. Take to be 3:142
CIRCUMFERENCE OF A CIRCLE : 2πr
2×3.142×7.5
47.13 cm
Draw a number line and show the following number: positive propoer fractions with a denominator of 6
Answer: 1= 6/6 and 2=12/6
Step-by-step explanation: Just Think and use your brain
Find the area of the parallelogram.
The area for the parallelogram is equal to 255 square centimeters and the correct option is A = 255 cm²
Area of parallelogramIn calculating for the area of parallelogram, the base is multiplied by the height, as the same way for calculating the area of a rectangle.
we shall calculate for the height h using Pythagoras rule for the triangle as follows:
h² + 9² = 15²
h² + 81 = 225
h² = 225 - 81 {subtract 81 from both sides}
h² = 144
h = √144 {take square root of both sides}
h = 12
area of parallelogram = 21 cm × 12 cm
area of parallelogram = 254 cm²
Therefore, the area for the parallelogram is equal to 255 square centimetres.
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