Answer:
[tex]\displaystyle \left(\frac{-(m^{2}-1)\, x + 2\, m\, y - 2\, m \, c}{m^{2} + 1},\, \frac{(m^{2} - 1)\, y + 2\, m \, x + 2\, c}{m^{2} + 1}\right)[/tex].
Step-by-step explanation:
Consider the line that is perpendicular to [tex]y = m\, x + c[/tex] and goes through [tex](x,\, y)[/tex].
Both [tex](x,\, y)[/tex] and the reflection would be on this new line. Besides, the two points would be equidistant from the intersection of this new line and line [tex]y = m\, x + c[/tex].
Hence, if the vector between [tex](x,\, y)[/tex] and that intersection could be found, adding twice that vector to [tex](x,\, y)\![/tex] would yield the coordinates of the reflection.
Since this new line is perpendicular to line [tex]y = m\, x + c[/tex], the slope of this new line would be [tex](-1/m)[/tex].
Hence, [tex]\langle 1,\, -1/m\rangle[/tex] would be a direction vector of this new line.
[tex]\langle m,\, -1\rangle[/tex] (a constant multiple of [tex]\langle 1,\, -1/m\rangle[/tex] would also be a direction vector of this new line.)
Both [tex](x,\, y)[/tex] and the aforementioned intersection are on this new line. Hence, their position vectors would differ only by a constant multiple of a direction vector of this new line.
In other words, for some constant [tex]\lambda[/tex], [tex]\langle x,\, y \rangle + \lambda\, \langle m,\, -1 \rangle = \langle x + \lambda \, m,\, y - \lambda \rangle[/tex] would be the position vector of the reflection of [tex](x,\, y)[/tex] (the position vector of [tex](x,\, y)\![/tex] is [tex]\langle x,\, y \rangle[/tex].)
[tex]( x + \lambda \, m,\, y - \lambda )[/tex] would be the coordinates of the intersection between the new line and [tex]y = m\, x + c[/tex]. [tex]\lambda\, \langle m,\, -1 \rangle[/tex] would be the vector between [tex](x,\, y)[/tex] and that intersection.
Since that intersection is on the line [tex]y = m\, x + c[/tex], its coordinates should satisfy:
[tex]y - \lambda = m\, (x + \lambda \, m) + c[/tex].
Solve for [tex]\lambda[/tex]:
[tex]y - \lambda = m\, x + m^{2}\, \lambda + c[/tex].
[tex]\displaystyle \lambda = \frac{y - m\, x - c}{m^{2} + 1}[/tex].
Hence, the vector between the position of [tex](x,\, y)[/tex] and that of the intersection would be:
[tex]\begin{aligned} & \lambda\, \langle m,\, -1 \rangle \\= \; & \left\langle \frac{m\, (y - m\, x - c)}{m^{2} + 1},\, \frac{(-1)\, (y - m\, x - c)}{m^{2} + 1}\right\rangle \\ =\; &\left\langle \frac{-m^{2}\, x + m\, y - m\, c }{m^{2} + 1},\, \frac{-y + m\, x + c}{m^{2} + 1}\right\rangle \end{aligned}[/tex].
Add twice the amount of this vector to position of [tex](x,\, y)[/tex] to find the position of the reflection, [tex]\langle x,\, y \rangle + 2\, \lambda \,\langle m,\, -1 \rangle[/tex].
[tex]x[/tex]-coordinate of the reflection:
[tex]\begin{aligned} & x + 2\, \lambda\, m \\ = \; & x + \frac{-2\, m^{2}\, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1} \\ =\; & \frac{-(m^{2} - 1) \, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].
[tex]y[/tex]-coordinate of the reflection:
[tex]\begin{aligned} & y + (-2\, \lambda)\\ = \; & y + \frac{- 2\, y + 2\, m\, x + 2\, c}{m^{2} + 1} \\ =\; & \frac{(m^{2} - 1) \, y + 2\, m \, x + 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].
5. Refer to the figure shown. Determine the measure of
the unknown angle. Show or explain your thanking.
Answer:
you haven't posted any diagram
Step-by-step explanation:
In an article of 12200 you get Rs 3050 cash discount. Then find the discount percent
Answer:
25%discount
Step-by-step explanation:
List price=12200,
Discount=3050
[DISCOUNT%=(DISCOUNT/LIST PRICE)×100]
D%=(3050/12200)×100
D%=25%
A rectangle has an area of 81 square centimeters. Which of the following would be the rectangle's length and width? (Area = equals length×times width)
Answer:
length: 9cm
width: 9cm
Step-by-step explanation:
9×9=81
PRECAL QUESTION - please help thanks
Answer:
203/169 -183i/169
"A"
Step-by-step explanation:
[tex]\frac{9-19i}{12-5i}[/tex]
[tex]\frac{9-19i}{12-5i}[/tex] * [tex]\frac{12+5i}{12+5i}[/tex]
12^2 - (5i)^2 = 144 + 25 = 169
FOIL: 108 +45i - 228i + 95
203 -183
If possible, find AB. & State the dimension of the result.
Answer:
The answer is "[tex]AB= \left[\begin{array}{cc} -2 &51 \\-8&33\\0&27&\end{array}\right][/tex]"
Step-by-step explanation:
If the value of A and B is:
[tex]A= \left[\begin{array}{cc}-1&6\\-4&5\\0&3\end{array}\right][/tex]
[tex]B=\left[\begin{array}{cc}2&3\\0&9\end{array}\right][/tex]
Find the value of A[tex]\times[/tex]B:
[tex]AB =\left[\begin{array}{cc}-1 \times 2+6 \times 0 &-1 \times 3+6 \times 9\\ -4 \times 2+5 \times 0& -4 \times 3+5 \times 9\\ 0 \times 2+3 \times 0&-1 \times 2+3\times 9\end{array}\right] \\ \\\\AB =\left[\begin{array}{cc}-2+0 &- 3+54\\ -8+0& -12+45\\ 0+ 0&-2 +27\end{array}\right] \\ \\[/tex]
[tex]AB= \left[\begin{array}{cc} -2 &51 \\-8&33\\0&27&\end{array}\right][/tex]
if f(x)=3-2x and g(x)= 1/x+5 what is the value of (f/g) (8)
Answer:
Step-by-step explanation:
(f/g) = (3 - 2x ) / (1/x + 5) You could go to the trouble to simplify all of this, but the easiest way is to just put in the 8 where you see an x
(f/g)8 = (3 - 2*8) / (1/8 + 5)
(f/g)/8 = (3 - 16 / (5 1/8) 1/8 = 0.125
(f/g) 8 = - 13 / ( 5.125)
(f/g)8 = - 2.54
Policeman A and Policeman B hand out 70 speeding tickets in a month.
Policeman A hands out 4 times as many speeding tickets as Policeman B.
Policeman A handed out ? Speeding tickets.
Answer:
Policeman A = 56 tickets
Step-by-step explanation:
Policemen A + B = 70
If Policeman B hands out x no of tickets...
Then Policeman A hands out 4x no of tickets
meaning...
x + 4x = 70
5x = 70
x = 70/5
x = 14
Therefore Policeman A hands out..
4x = 4 × 14 = 56 tickets
what's the equation that represents the new path
Answer:
A: y= 1/4x - 7
if it is perpendicular, then it creates 4 right angles. so that new line would pass through (0,-7) and something else that isnt important. but the slope, or m, would be 1/4, and the y intercept would be -7. so the new equation is y=1/4x-7
If f(x) = 4x + 3 and g(x) = 22 – 3, then f(g(4)) = ???
Answer:
f(g(4))=79
Step-by-step explanation:
given:
f(x) = 4x + 3
g(x) = 22 – 3
g(x) = 19
the x in parentheses represents x's value. if it is just x then example f(x)=3x would be 3x. if f(x) was f(2)=3x, then x would be 2 and f(2)=3x would be 3*2=6
f(g(4))
first solve g(4)
g(x) = 19
g(4)=19 because there are no x
then substitute
f(g(4))
f(19)
f(19) = 4x + 3
all x become 19
f(19) = 4(19) + 3
=76+3
=79
hope this helps.
If average of the numbers 3,9,5,7 and Q is 5 times the value of Q, find the value of Q
Answer:
q=6
Step-by-step explanation:
3+9+5+7+Q=5Q
5Q-Q=24
Q=6
PLEASE HELP ! (4/5) - 50 POINTS -
Answer:
[tex]\large \boxed{\sf A) \ 12}[/tex]
Step-by-step explanation:
Frequency of a specific data value at an interval is the number of times the data value repeats in that interval.
Cumulative frequency is found by adding each frequency to the frequency that came before it.
cStep-by-step explanation:
Help please! it’s due soon
Answer:
33. That means (A) can be any number and b times any number wilo get 0 so any numbr will do
34.It is wrong because if x equals 40 anything multiply that will be more than that and so isnt a good reasoning
3 ratios that are equivalent to 6:12
Answer:
1:3
2:4
3:6
Step-by-step explanation:
we can divide both sides by 6 and get 1:2
we can divide both sides by 3 and get 2:4
we can divide both sides by 2 and get 3:6
Answer:
12:24, 3:6, 2:4
Step-by-step explanation:
What we are looking for here is a ratio that, when you divide/multiply the same constant on both parts of the ratio, you get 6:12.
6:12 is the same thing as 1:2, so we can find ratios equivalent to 1:2 (the first value will be half the second).
Hope this helped!
Write a variable expression for a number w increased by 4 (A) 4 ÷ w (B) w + 5 (C) w + 4
Answer:
C) w+4
Step-by-step explanation:
w=the variable
+4= increased by 4
HOPE THIS HELPS!!!!!! :)
<33333333333
Which of the following is NOT a property of a paralleogram? * The opposite sides are equal. The opposite angles are equal. Each diagonal bisects the parallogram. The diagonals of all parallograms bisect each other at 90 degree angles. I will give brainliest
Answer:
The diagonals of all parallelograms do not bisect each other at 90 degree angles.
Step-by-step explanation:
Factorize p2-15q-5p+2pq
Hope it's help you!!!!!!
Claire has to go to the movie theater the movie starts at 4:15 pm it is a 25min walk to the theater from her home what time dose the have to leave the house to get there on time
Answer:
claire has to leave at 3:50 from her house.
Answer:
She needs to leave by 3:50 to get there on time.
Step-by-step explanation:
4:15 - 0:25 = 3:50.
Factor the polynomial: 11x− xy +11y−x2
[tex]11x- xy +11y-x^2=\\-x^2-xy+11x+11y=\\-x(x+y)+11(x+y)=\\-(x-11)(x+y)[/tex]
Answer:
(x - 11)(-x - y)
Step-by-step explanation:
To factor the polynomial 11x - xy + 11y - x² completely, let's group the terms and factor them separately.
Rearranging the terms, we have:
11x - xy + 11y - x²
Let's rearrange the terms again to group similar terms together:
x² + 11x - xy + 11y
Now, we can factor out the common factor from each pair of terms:
x(-x + 11) - y(x - 11)
Simplifying further, we can factor out -1 from the first pair of terms:
-x(x - 11) - y(x - 11)
Now, notice that we have a common factor of (x - 11) in both terms. Factoring out this common factor, we obtain:
(x - 11)(-x - y)
Therefore, the polynomial 11x - xy + 11y - x² can be factored completely as (x - 11)(-x - y).
This test statistic leads to a decision to...
reject the null
accept the null
fail to reject the null
As such, the final conclusion is that...
There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 88.9.
There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 88.9.
The sample data support the claim that the population mean is not equal to 88.9.
There is not sufficient sample evidence to support the claim that the population mean is not equal to 88.9.
Answer:
There is not sufficient sample evidence to support the claim that the population mean is not equal to 88.9.
Step-by-step explanation:
We are given the following hypothesis below;
Let [tex]\mu[/tex] = population mean.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 88.9 {means that the population mean is equal to 88.9}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 88.9 {means that the population mean is different from 88.9}
The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;
T.S. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean = 81.3
s = sample standard deviation = 13.4
n = sample size = 7
So, the test statistics = [tex]\frac{81.3-88.9}{\frac{13.4}{\sqrt{7} } }[/tex] ~ [tex]t_6[/tex]
= -1.501
The value of t-test statistics is -1.501.
Also, the P-value of the test statistics is given by;
P-value = P([tex]t_6[/tex] < -1.501) = 0.094
Since the P-value of our test statistics is more than the level of significance as 0.094 > 0.01, so we have insufficient evidence to reject our null hypothesis as the test statistics will not fall in the rejection region.
Therefore, we conclude that the population mean is equal to 88.9.
Zamba has found a little black dress on sale for 50% off the original price of $239.99. She also has a coupon offering free shipping and an additional 10% off of her entire online purchase. If she buys the dress and a pair of shoes costing $34.70, how much will she pay for her ensemble?
$108.00
$104.70
$94.23
$139.23
Answer:
$139.23
Step-by-step explanation:
50% off the original price of $239.99
= $239.99-(0.5*239.99)
= 239.99-119.995
= $119.995
She purchase a pair of shoes also worth $34.70
Total cost now= $119.995 + $34.70
Total cost now= $154.695
But she has a coupon that gives her 10% off her total sales
Now she wants pay
= $154.695 - 0.1(154.695)
= $154.695-15.4695
= $139.2255
Approximately $139.23
I buy 6 CDs costing £6.99.
How much change do I get from
£50?
Answer:
subtract the 6.99 from 50 and you get your answer
Step-by-step explanation:
Answer:
8.06
Step-by-step explanation:
Take the cost of a cd and multiply by 6
6.99 *6
41.94
Subtract this from 50.00
50.00 - 41.94
8.06
You will get 8.06 back
What is the correct standard form of the equation of the parabola? Enter your answer below. Be sure to show each step of your work.
Answer:
Step-by-step explanation:
eq. of directrix is y=4 or y-4=0
perpendicular distance of (x,y) from directrix =distance of (x,y) from focus (-3,2)
[tex]| \frac{y-4}{1}|=\sqrt{(x+3)^2+(y-2)^2} \\squaring~both~sides\\y^2-8y+16=(x+3)^2+(y-2)2\\(x+3)^2=y^2-8y+16-(y-2)^2\\(x+3)^2=y^2-8y+16-(y^2-4y+4)\\(x+3)^2=y^2-8y+16-y^2+4y-4\\(x+3)^2=-4y+12\\(x+3)^2=-4(y-3)[/tex]
Determine what type of decimal each is.
8.54
●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●
Hi my lil bunny!
❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙
[tex]8.54 \div 100 = 0.0854[/tex]
(what do you mean by Determine what type of decimal each is: 8.54 because there is only one decimal there )
❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙
●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●
Have a great day/night!
❀*May*❀
Which is the simplified form of (StartFraction 2 a b Over a Superscript negative 5 Baseline b squared EndFraction) Superscript negative 3? Assume a not-equals 0, b not-equals 0. StartFraction b cubed Over 8 a Superscript 18 Baseline EndFraction StartFraction b squared Over 8 a Superscript 45 Baseline EndFraction StartFraction a Superscript 6 Baseline Over 4 b EndFraction StartFraction 2 a Superscript 6 Baseline Over b Superscript 5 Baseline EndFraction
Answer:
[tex]\dfrac{b^3}{8a^{18}}[/tex] matches the first choice
Step-by-step explanation:
[tex]\left(\dfrac{2 a b}{a^{-5}b^2}\right)^{-3}=(2a^{1-(-5)}b^{1-2})^{-3}=(2a^6b^{-1})^{-3}\\\\=2^{-3}a^{6(-3)}b^{-1(-3)}=8^{-1}a^{-18}b^3=\boxed{\dfrac{b^3}{8a^{18}}}[/tex]
__
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
a^-b = 1/a^b
Answer:
A
Step-by-step explanation:
just took the pretest! good luck!
What is the correct answer and how can this be solved?
Answer:
[tex]$\mathbf{\frac{1}{19} }[/tex]
Step-by-step explanation:
[tex]$$\bullet \Nth \ Term;\\$$$\frac{n+2}{2n^{2} +3n-2}[/tex]
[tex]$$\bullet U_{10} \ Term;\\\\$$\boxed{\frac{(10+2) }{2*10^{2} +3*10-2}= \frac{1}{19} }[/tex]
Answer:
[tex]\boxed{\displaystyle \frac{1}{19}}[/tex]
Step-by-step explanation:
[tex]\displaystyle \frac{n+2}{2n^2 +3n-2}[/tex]
Replace n with 10 to find the 10th term.
[tex]\displaystyle \frac{10+2}{2(10)^2 +3(10)-2}[/tex]
Evaluate.
[tex]\displaystyle \frac{12}{2(100) +30-2}[/tex]
[tex]\displaystyle \frac{12}{200 +30-2}[/tex]
[tex]\displaystyle \frac{12}{228}[/tex]
Simplify.
[tex]\displaystyle \frac{1}{19}[/tex]
For the right angle, find the missing quantity indicated below the figure.
Answer:
The Answer is 28.........
Which number is divisible by 10? 148 99 121 100
Answer:
100
Step-by-step explanation:
100/ 10
= 10
An experimental probability is ______ likely to approach the theoretical probability if the number of trials simulated is larger. A. as B. more C. less D. not
Answer:
I believe your answer is b. the more trials you conduct, the more information you have
An experimental probability is more likely to approach the theoretical probability if the number of trials simulated is larger. Then the correct option is B.
What is probability?Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.
Experimental probability: A probability that is established from the findings of several iterations of a test.
Theoretical probability: The proportion of positive consequences to all potential outcomes. The ratio of the favorable event to the total event.
An experimental probability is more likely to approach the theoretical probability if the number of trials simulated is larger.
Then the correct option is B.
More about the probability link is given below.
https://brainly.com/question/795909
#SPJ2
On Monday the temperature is 0F on Tuesday it is seven degrees warmer what is the temperature?
Answer:
7F
Step-by-step explanation:
Add 7 to 0
0+7 = 7F
Answer:
obviously 7F
Step-by-step explanation:
Just add 7 to the zero and its 7F
The Bookstall Inc. is a specialty bookstore concentrating on used books sold via the Internet. Paperbacks are $1.35 each, and hardcover books are $3.50. Of the 60 books sold last Tuesday morning, 55 were paperback and the rest were hardcover. What was the weighted mean price of a book? (Round your answer to 2 decimal places.)
Answer:
dddddd okaksy ogvurn
Step-by-step explanation:
d