Find the projection of u onto v
URGENT HELP

Find The Projection Of U Onto VURGENT HELP

Answers

Answer 1

Given:

Two vectors are:

[tex]u=\left <0,6\right>[/tex]

[tex]v=\left <2,17\right>[/tex]

To find:

The projection of u onto v.

Solution:

Magnitude of a vector [tex]v=\left <a,b\right>[/tex] is:

[tex]|v|=\sqrt{a^2+b^2}[/tex]

Dot product of two vector [tex]v_1=\left <a_1,b_1\right>[/tex] and [tex]v_2=\left <a_2,b_2\right>[/tex] is:

[tex]v_1\cdot v_2=a_1a_2+b_1b_2[/tex]

Formula for projection of u onto v is:

[tex]Proj_vu=\dfrac{u\cdot v}{|v|^2}v[/tex]

[tex]Proj_vu=\dfrac{\left <0,6\right>\cdot \left <2,17\right>}{(\sqrt{2^2+17^2)^2}}\left <2,17\right>[/tex]

[tex]Proj_vu=\dfrac{0\cdot 2+6\cdot 17}{4+289}\left <2,17\right>[/tex]

[tex]Proj_vu=\dfrac{0+102}{293}\left <2,17\right>[/tex]

On further simplification, we get

[tex]Proj_vu=\dfrac{102}{293}\left <2,17\right>[/tex]

[tex]Proj_vu=\left <\dfrac{102}{293}\cdot 2,\dfrac{102}{293}\cdot 17\right>[/tex]

[tex]Proj_vu=\left <\dfrac{204}{293},\dfrac{1734}{293}\right>[/tex]

Therefore, the projection of u onto v is [tex]Proj_vu=\left <\dfrac{204}{293},\dfrac{1734}{293}\right>[/tex].


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Answer:

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Answers

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answer:

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Step-by-step explanation:

Answer:

The cube of first six natural numbers are

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Answers

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Answers

Answer:

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✄----------------

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10

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Answer:

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Answers

Answer:

15 + 5w ≥ 75

Step-by-step explanation:

Let the number of weeks be represented as w.

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Charles is saving $5 each week from his allowance. He already saved $15 from the money he earned from mowing his neighbor's lawn.

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Answers

Answer:

x = -96/55

Step-by-step explanation:

Given that 2x + (5 /3)x + 7 = 3/5

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Step-by-step explanation:

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