Examine the steps used to solve the equation.
Negative 3 y + two-thirds = 2 y minus 4. 1. Two-thirds = 5 y minus 4. 2. StartFraction 14 Over 3 EndFraction = 5 y. 3. (one-fifth) StartFraction 14 Over 3 EndFraction = (one-fifth) 5 y.
Evaluate the steps used to solve the equation, and then describe each step.
Step 1:
Step 2:
Step 3:
What is the solution to the equation?
y =
Answer:
can confirm guy or girl above me
Step-by-step explanation:
The solution to the equation is y=14/15.
The given equation is -3y+2/3=2y-4.
What is an equation?In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
Now, transpose -3y to RHS and simplify.
That is, 2/3=5y-4
Transpose -4 to LHS and simplify.
That is, 14/3=5y
Multiply by 1/5 on both sides of the equation.
So, 14/3×1/5=5y×1/5
⇒y=14/15
Therefore, the solution to the equation is y=14/15.
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Find tan(B) in the triangle.
Answer:
3/4
Step-by-step explanation:
The value of tangent ratio [tex]tan \beta[/tex] in the triangle is [tex]\frac{3}{4}[/tex].
What is trigonometric ratio?Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle. The ratios of sides of a right-angled triangle with respect to any of its acute angles are known as the trigonometric ratios of that particular angle.
Review all six trigonometric ratios: sine, cosine, tangent, cotangent, secant, & cosecant.
Tangent ratioTangent ratio is yet another trigonometric ratio for right-angled triangles. Tangent ratio is the ratio of opposite side to adjacent side of a right triangle.
According to the triangle ABC
<C = [tex]90^{0}[/tex], <B = [tex]\beta[/tex], AB = 5, BC = 4, AC = 3
Tangent ratio is the ratio of opposite side to adjacent side of a right triangle.
Tangent ratio is one of the trigonometric ratios.
[tex]tan \beta=\frac{AC}{BC} = \frac{3}{4}[/tex]
Hence,
The value of [tex]tan \beta[/tex] in the triangle is [tex]\frac{3}{4}[/tex].
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Students at a major university are complaining of a serious housing crunch. Many of the university's students, they complain, have to commute too far to school because there is not enough housing near campus. The university officials respond with the following information:
The mean distance commuted to school by students is 17.1 miles, and the standard deviation of the distance commuted is 3.7 miles. Assuming that the university officials' information is correct, complete the following statements about the distribution of commute distances for students at this university.
1) According to Chebyshev's theorem, at least 36% of the commute distances lie between miles and miles. (Round your answer to 1 decimal place.)
2) According to Chebyshev's theorem, at least of the commute distances lie between 9.7 miles and 24.5 miles.
a) 56%
b) 75%
c) 84%
d) 89%
3) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately of the commute distances lie between 9.7 miles and 24.5 miles.
a) 68%
b) 75%
c) 95%
d) 99.7%
4) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately 68% of the commute distances lie between miles and miles.
Answer:
1) Between 12.5 miles and 21.7 miles.
2) b) 75%
3) c) 95%
4) Between 13.7 miles and 20.5 miles.
Step-by-step explanation:
Empirical Rule:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviations of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
Chebyshev Theorem:
The Chebyshev Theorem can also be applied to non-normal distribution. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]P = 100(1 - \frac{1}{k^{2}})[/tex].
1) According to Chebyshev's theorem, at least 36% of the commute distances lie between miles and miles.
Within k standard deviations of the mean, and k is found when [tex]P = 36[/tex]. So
[tex]P = 100(1 - \frac{1}{k^{2}})[/tex]
[tex]36 = 100 - \frac{100}{k^2}[/tex]
[tex]\frac{100}{k^2} = 64[/tex]
[tex]64k^2 = 100[/tex]
[tex]k^2 = \frac{100}{64}[/tex]
[tex]k = \sqrt{\frac{100}{64}}[/tex]
[tex]k = \frac{10}{8}[/tex]
[tex]k = 1.25[/tex]
Within 1.25 standard deviations of the mean.
1.25*3.7 = 4.6 miles
17.1 - 4.6 = 12.5 miles
17.1 + 4.6 = 21.7 miles
Between 12.5 miles and 21.7 miles.
2) According to Chebyshev's theorem, at least of the commute distances lie between 9.7 miles and 24.5 miles.
17.1 - 9.7 = 24.5 - 17.1 = 7.4 miles, so within 2 standard deviations of the mean, which is 75%, option B.
3) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately of the commute distances lie between 9.7 miles and 24.5 miles.
Within 2 standard deviations of the mean, by the Empirical Rule, which is 95%, option c.
4) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately 68% of the commute distances lie between miles and miles.
Within 1 standard deviation of the mean.
17.1 - 3.4 = 13.7
17.1 + 3.4 = 20.5
Between 13.7 miles and 20.5 miles.
What is 23x56÷67-68?
Hurry plz
Me give brainliest
Thanks in advance
Answer:
-48.4328358209
Step-by-step explanation:
hope this helps!!!
Answer:
If you meant 68-67 then it would be 1288
But if you meant 67-68 it is -1288
(I really hope this isn't hard to understand).
f(x) = 2x² + 4x - 5
g(x) = 6x3 – 2x2 + 3
Find (f – g)(x).
A. (f – g)(x) = –6x3 + 4x2 + 4x – 2
B. (f - g)(x) = 6x + 4x – 2
C. (f - g)(x) b= 6x? – 4x² - 4x + 8
D. (f - g)(x) = –6x2 + 4x2 + 4x – 8
The required difference in the expression (f – g)(x) is - 6x³+ 4x² + 4x - 8
Given the following functions
f(x) = 2x² + 4x - 5
g(x) = 6x³ – 2x² + 3
In order to get the required function (f-g)(x), we will have to take the difference of the function as shown:
(f – g)(x) = f(x) - g(x)
Substitute the given parameters into the expression
(f – g)(x) = 2x² + 4x - 5 - (6x³ – 2x² + 3)
Expand
(f – g)(x) = 2x² + 4x - 5 - 6x³ + 2x² - 3
Collect the like terms
(f – g)(x) = 2x²+2x²- 6x³ + 4x -5 -3
(f – g)(x) = - 6x³+ 4x² + 4x -5 -3
(f – g)(x) = - 6x³+ 4x² + 4x - 8
Hence the required difference in the expression (f – g)(x) is - 6x³+ 4x² + 4x - 8
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a patient needs fluid and carbohydrates for nutrition. which fluids is the patient likely to be administered
Answer:
5% Dextrose
Step-by-step explanation:
Dextrose is primarily used as a carbohydrate for nutrition and as a source of fluid. Whereas Sodium chloride is primarily used as a source of fluid and electrolytes.
A patient needs fluid and carbohydrates for nutrition. The fluid that the patient is likely to be administered is TNP. The patient needs fluid and carbohydrates for nutrition. The correct option is b.
What is TNP?Total parenteral nutrition (TPN) is a feeding technique that omits the digestive system. The majority of the body's nutritional requirements are met by a specific formula administered intravenously.
When a person cannot or shouldn't receive feedings or fluids orally, the technique is utilized. The term "parenteral nutrition," sometimes known as "total parenteral nutrition," refers to the practice of administering a unique type of food through a vein (intravenously).
The treatment's aim is to treat or stop malnutrition. TPN is made up of many components that are mixed together. These components include dextrose, lipid emulsions, amino acids, vitamins, electrolytes, minerals, and trace elements.
Therefore, the correct option is b, total parenteral nutrition.
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The question is incomplete. Your most probably complete question is given below:
a. protein
b. total parenteral nutrition.
c. iodine
d. fats
Solve the equation: p2 - 4p + 4 = 0.
Perfect square trinomial
[tex] \boxed{ a^2 \pm 2ab+b^2 = (a \pm b)^2 } [/tex]
Using the perfect square trinomial
[tex] p^2 - 4p + 4 = 0 [/tex]
[tex] p^2 - 2(2p) + (2)^2 = 0 [/tex]
[tex] (p-2)^2 = 0 [/tex]
[tex] (p-2) = 0 [/tex]
[tex] p = 2 [/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\bold{p^2-4p+4=0}[/tex]
[tex]\text{FACTOR the LEFT side of your equation}\\\bold{(p-2)(p-2)=0}[/tex]
[tex]\text{SET each of your FACTORS TO EQUAL to 0}\\\bold{p-2=0\ or\ p-2=0}[/tex]
[tex]\text{SIMPLIFY the equations\ above and you will have your answer}[/tex]
[tex]\boxed{\boxed{\bold{Answer: \large\text{\bf{p = 2}}}}}\huge\checkmark[/tex]
[tex]\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
how do you describe the graph of |x| < 12 brainly
Answer:
Describe the two functions f(x) and g(x) , using the terms increasing, decreasing, maxima and minima. The graph of f(x) is periodic.
Answer:
Step-by-step explanation:
In the year 2001, a person bought a new car for $15500. For each consecutive year after that, the value of the car depreciated by 5%. How much would the car be worth in the year 2005, to the nearest hundred dollars?
Answer:
$12,000.
Step-by-step explanation:
Given that in the year 2001, a person bought a new car for $ 15500, and for each consecutive year after that, the value of the car depreciated by 5%, to determine how much would the car be worth in the year 2005, to the nearest hundred dollars, the following calculation must be performed:
100-5 = 95
15,500 x 0.95 x 0.95 x 0.95 x 0.95 x 0.95 = X
14.725 x 0.95 x 0.95 x 0.95 x 0.95 = X
13,988.75 x 0.95 x 0.95 x 0.95 = X
13,289.3125 x 0.95 x 0.95 = X
12,624.846875 x 0.95 = X
11.993.60453125 = X
Thus, to the nearest hundred dollars, the cost of the car after 5 years will be $ 12,000.
let f(x)=x^2 +2 and g(x)=1-3x. find each function value: (fg)(-1)
Answer:
12
Step-by-step explanation:
so basically
(x^2+2)*(1-3x)=-3x^3+x^2-6x+2
now plug in -1
-3(-1)^3+(-1)^2-6(-1)+2=12
hope this helped :)
The correct value of (fg)(-1) is "12". A further solution of the given query is provided below.
Given functions are:
[tex]f(x) = x^2+2[/tex]
[tex]g(x) = 1-3x[/tex]
Now,
⇒ [tex](fg) = (x^2+2)(1-3x)[/tex]
By applying multiplication, we get
[tex]=x^2+2-3x^3-6x[/tex]
[tex]=-3x^3+x^2-6x+2[/tex]...(equation 1)
By substituting the value "-1" in place of "x" in equation 1, we get
⇒ [tex](fg)(-1) = -3(-1)^3+(-1)^2-(6)(-1)+2[/tex]
[tex]=-3(-1)+1+6+2[/tex]
[tex]=3+1+6+2[/tex]
[tex]=12[/tex]
Thus the right answer is (fg)(-1) = 12.
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Little help ?please 5 points
Tawna and Donnie Milled cartons with bottles, Tawna put in 10 bottles and Bonnie put in a bottles, How many bottles does each carton hold?
Answer:
I Think E But Im Not Sure About It
1) Find all the critical numbers of the given function
f(x) = X 1 - 4
-
3
Answer:
(0,-4)
Step-by-step explanation:
Given
[tex]f(x) = x^\frac{1}{3} - 4[/tex]
Required
Determine the critical numbers
[tex]f(x) = x^\frac{1}{3} - 4[/tex]
Differentiate:
[tex]f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}[/tex]
[tex]f'(x) = \frac{1}{3}x^{-\frac{2}{3}}[/tex]
Equate to 0
[tex]f'(x) = \frac{1}{3}x^{-\frac{2}{3}} = 0[/tex]
[tex]\frac{1}{3}x^{-\frac{2}{3}} = 0[/tex]
Multiply through by 3
[tex]3 * \frac{1}{3}x^{-\frac{2}{3}} = 0*3[/tex]
[tex]x^{-\frac{2}{3}} = 0[/tex]
[tex]x = 0[/tex]
Substitute 0 for x in [tex]f(x) = x^\frac{1}{3} - 4[/tex]
[tex]f(0) = 0^\frac{1}{3} - 4[/tex]
[tex]f(0) = 0- 4[/tex]
[tex]f(0) = - 4[/tex]
Hence, the critical point is: (0,-4)
Is 13:15 and 30:26 a pair of equivalent ratios and why?
Given:
The two ratios are 13:15 and 30:26.
To find:
Whether the given ratios are equivalent or not.
Solution:
Two ratios are equivalent if the values of the ratio are equal after simplification.
[tex]13:15=\dfrac{13}{15}[/tex]
And,
[tex]30:26=\dfrac{30}{26}[/tex]
[tex]30:26=\dfrac{15}{13}[/tex]
[tex]30:26=15:13[/tex]
The first ratio is 13:15 and the value of second ratio after simplification is 15:13 both ratios are different, so,
[tex]\dfrac{13}{15}\neq \dfrac{30}{26}[/tex]
Therefore, the required answer is "No", the given ratios are not a pair of equivalent ratios.
If there are 125 boxes of prescription bottle labels at the beginning of inventory cycle, and 25 3/4 remain ,how many boxes of labels remain?
Answer:
Rounded to the nearest integer, there are 32 boxes of labels left.
Step-by-step explanation:
Since there are 125 boxes of prescription bottle labels at the beginning of inventory cycle, and 25 3/4 remain, we can determine how many boxes of labels remain through the following mathematical operations:
3/4 = 0.75
100 = 125
25.75 = X
25.75 x 125/100 = X
3218.75 / 100 = X
32.1875 = X
Thus, rounded to the nearest integer, there are 32 boxes of labels left.
The sum of 3 and
twice the number n
Find the distance between (-5,6)and (3,2).
Answer:
[tex]\displaystyle d = 4\sqrt{5}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Coordinates (x, y)Algebra II
Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Step-by-step explanation:
Step 1: Define
Point (-5, 6) → x₁ = -5, y₁ = 6
Point (3, 2) → x₂ = 3, y₂ = 2
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
Substitute in points [Distance Formulas]: [tex]\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}[/tex][Distance] [√Radical] (Parenthesis) Add/Subtract: [tex]\displaystyle d = \sqrt{(8)^2+(-4)^2}[/tex][Distance] [√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{64+16}[/tex][Distance] [√Radical] Add: [tex]\displaystyle d = \sqrt{80}[/tex][Distance] [√Radical] Simplify: [tex]\displaystyle d = 4\sqrt{5}[/tex]what is the volume of a cube with 2 1/4 inch sides
Answer:11.39
Step-by-step explanation:
Line DCE is parallel to line AB
a) Find the size of angle ABC
b) Find the size of angle DCA
c) Calculate the size of angle ACB
Answer:
Angle DCA = Angle CAB. (Alternate Interior Angle)
Angle DCA = 68°
Angles(DCA + ACB + BCE) = 180°. (Linear Pair)
Angle ACB + 68° + 33° = 180°
Angle ACB = 79°
Therefore,
Angle ABC = 33°. (Alternate Interior Angle)
Simplify the expression 1 + 4.25n + 3/2p -3 + (-2p) + 5/4n
Answer:
5.5n -2 -0.5p
Step-by-step explanation:
Make Everything to either decimals or fractions.
then simplify as shown
1 1/3+2 3/4 simplified
Answer:
4 1/12
Step-by-step explanation:
Answer: 4 1/2
cause it is
Ms.Gallegos burns 236 calories
The safety officers of a mining company take an SRS of 500500500 employees and finds that 15\, percent of the sampled employees wear contact lenses. The safety officers may take several more samples like this. Suppose it is really 12\, percent of the approximately 34{,}00034,00034, comma, 000 employees in the company who wear contact lenses. What are the mean and standard deviation of the sampling distribution of the proportion of employees who wear contact lenses
Answer:
The mean of the sampling distribution of the proportion of employees who wear contact lenses is 0.12 and the standard deviation is 0.0145.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
12% of the employees wear contact lenses.
This means that [tex]p = 0.12[/tex]
Samples of 500:
This means that [tex]n = 500[/tex]
What are the mean and standard deviation of the sampling distribution of the proportion of employees who wear contact lenses?
Mean:
[tex]\mu = p = 0.12[/tex]
Standard deviation:
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.12*0.88}{500}} = 0.0145[/tex]
The mean of the sampling distribution of the proportion of employees who wear contact lenses is 0.12 and the standard deviation is 0.0145.
What is the area of the fire pit? (Use 3.14 for pi.)
Answer:
[tex]Area = 65.94[/tex]
Step-by-step explanation:
I will assume that the shaded region is the fire pit
Given
[tex]R = 5[/tex]
[tex]r = 2[/tex]
Required
Determine the area of the fire pit
First, calculate the area of the big circle.
[tex]A_2 = \pi R^2[/tex]
Area of the small is:
[tex]A_1 = \pi r^2[/tex]
The area of the pit is:
[tex]Area = A_2 - A_1[/tex]
[tex]Area = \pi R^2 - \pi r^2[/tex]
[tex]Area = \pi (R^2 - r^2)[/tex]
[tex]Area = 3.14 (5^2 - 2^2)[/tex]
[tex]Area = 3.14 (25 - 4)[/tex]
[tex]Area = 3.14 * 21[/tex]
[tex]Area = 65.94[/tex]
Use the diagram below to find x and each missing angle.
Pls answer ASAP it’s due tomorrow
Answer:
729
Step-by-step explanation:
Doughnuts are sold in bag and cartons. A bag holds 4 doughnuts and a carton holds 10 doughnuts. Tome buys b bags of doughnuts and c cartons of doughnuts. He buys a total of t doughnuts. Write down the formula for t in terms of b and c
Answer:
[tex]t = 4b + 10c[/tex]
Step-by-step explanation:
Given
1 bag = 4 doughnuts
1 carton = 10 doughnuts
Required
Determine the amount of doughnuts in b bags and c cartons
If 1 bag contains 4 doughnuts, then b bags contain 4b doughnuts
If 1 carton contains 10 doughnuts, then c cartons contain 10b doughnuts
So, the total (t) is calculated by adding up the amount of doughnuts in the cartons and the bags:
i.e.
[tex]t = 4b + 10c[/tex]
Verify that parallelogram ABCD with vertices A(-5, -1), B(-9, 6), C(-1, 5), and D(3, is a rhombus by showing that it is a parallelogram with perpendicular diagonals.
multiplication of the gradients of the two diagonals is equals to -1 if they are perpendicular
In ΔDEF, the measure of ∠F=90°, the measure of ∠E=41°, and FD = 79 feet. Find the length of DE to the nearest tenth of a foot.
Answer:
120.4ft
Step-by-step explanation:
Find the diagram in the attachment.
The triangle shown is a right angled triangle with the side DE as the hypotenuse, EF is adjacent side while DF is the opposite side.
To get DE, we will use the SOH CAH TOA trigonometry identity
Using CAH which is defined as:
Cos(theta) = Adjacent/Hypotenuse
Cos 79°= 23/Hypotenuse
Hypotenuse = 23/cos79°
Hypotenuse = 23/0.191
Hypotenuse = 120.4feet
DE = 120.4feet (to nearest tenth)
4. Marlie made her last monthly interest-only payment on December 1. Her next payment is due on
January 1. What will be the amount of that interest-only payment?
en
Answer:
ella tiene que pagar 10 por mes. lo siento si no es así, esa no es la respuesta correcta.
Step-by-step explanation:
Evaluate the expression: 16.2 x 2 + 1/2 x 8.5 x 12
Answer:
83.4
Step-by-step explanation:
16.2 x 2
=
32.4 +
1/2 x 8.5 x 12
=
51 + 32.4 = 83.4
Hope this helps!