![Find The PH Of A Solution With A [H+] Of 0.045M.](https://brainimage.s3.us-east-005.backblazeb2.com/contents/attachments/VRy6Ew2Y60ZemRmIjwniIimcYusQufhB.png)
Answers
Answer:
1.35Explanation:
The pH of a solution can be found by using the formula
[tex]pH = - log ([ {H}^{+} ])[/tex]
From the question
[H+] = 0.045 M
We have
[tex]pH = - log(0.045) \\ = 1.346787...[/tex]
We have the final answer as
1.35Hope this helps you
Answer:
1.35
Explanation:
Related Questions
If you diluted 120 mL of 1,049 M NaCl to 1,920 mL, what would
be the new concentration of NaCl? Don't put units into your
answer.
Answers
Answer:
65.56 M
Explanation:
Using the formula as follows:
C1V1 = C2V2
Where;
C1 = initial concentration (M)
C2 = final concentration (M)
V1 = initial volume (L)
V2 = final volume (L)
According to the information in this question,
C1 = 1,049 M
C2 = ?
V1 = 120 mL
V2 = 1,920 mL
Using C1V1 = C2V2
1049 × 120 = C2 × 1920
125880 = 1920C2
C2 = 125880 ÷ 1920
C2 = 65.56 M
I'm like a highway system in your body. I carry necessary supplies to the parts of your body that need llen, allu
carry away wastes so your body can get rid of them. I contain blood vessels and am a system with a lot of heart.
What system am I?
1:digestive system
2:circulatory system
3: muscular system
4:skeletal system
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Answers
Answer:
The circulatory system
Explanation:
Hope this helps
How much 0.05 M HCl solution can be made by diluting 2L of 10 M HCl?
Answers
Answer:
400 L
Explanation:
As this problem deals with a dilution process, we can use the following formula:
C₁V₁=C₂V₂Where subscript 1 stands for the concentrated concentration and volume, while 2 stands for the diluted values. Meaning that in this case:
C₁ = 10 MV₁ = 2 LC₂ = 0.05 MV₂ = ?We input the data:
10 M * 2 L = 0.05 M * V₂And solve for V₂:
V₂ = 400 LHow many atoms are in 1.204x10^22 moles of arsenic?
Answers
Answer:
0.02 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} \\[/tex]
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have
[tex]n = \frac{1.204 \times {10}^{22} }{6.02 \times {10}^{23} } \\ = 0.02[/tex]
We have the final answer as
0.02 molesHope this helps you