The pH and the fraction of the association of the 0.026 m NaOCl is the 10 ans 0.0035.
The chemical equation is :
NaOCl ---> Na⁺ + OCl⁻
0.026 0.026 0.026
OCl⁻ + H₂O ⇄ HOCl + OH⁻
0.026-x x x
The Kb is as :
Kb = 10⁻¹⁴ / 3 × 10⁻⁸
Kb = 3.3 x 10⁻⁷
x² / 0.026 - x = 3.3 x 10⁻⁷
x = 9.2 × 10⁻⁵
[OH⁻] = [HClO] = 9.2 × 10⁻⁵
[OCl⁻ ] = 0.026
pOH = -log [OH⁻]
pOH = - log (9.2 × 10⁻⁵)
pOH = 4.0
pH = 14 - 4
pH = 10
The fraction of the association is as :
α = [HOCl] / [OCl⁻ ]
α = 9.2 × 10⁻⁵ / 0.026
α = 0.0035
To learn more about pH here
https://brainly.com/question/15289714
#SPJ4
For the reaction PCl₅(g) ⇌ PCl₃(g) + Cl₂(g) Kp = 1.45 × 10⁻⁴ at 160 °C. A 1.00 L vessel at 160 °C is filled with PCl₅(g) at an initial pressure of 3.75 atm and allowed to come to equilibrium. What will be the pressure (in atm) of Cl₂(g) at equilibrium?
We need to use the equilibrium constant (Kp) and the initial pressure of PCl₅(g) to calculate the equilibrium pressures of PCl₃(g) and Cl₂(g). The equilibrium expression for the reaction is:
Kp = (P(Cl₂)) / (P(PCl₅)^(1) * P(PCl₃))
We can rearrange this equation to solve for P(Cl₂):
P(Cl₂) = Kp * P(PCl₅)^(1) * P(PCl₃)
Substituting the values given in the problem, we get:
P(Cl₂) = (1.45 × 10⁻⁴) * (3.75) * (P(PCl₃))
To solve for P(PCl₃), we use the fact that the initial pressure of PCl₅ is equal to the sum of the equilibrium pressures of PCl₃ and Cl₂:
P(PCl₅) = P(PCl₃) + P(Cl₂)
Substituting P(Cl₂) from the previous equation, we get:
3.75 = P(PCl₃) + (1.45 × 10⁻⁴) * (3.75) * (P(PCl₃))
Solving for P(PCl₃), we get:
P(PCl₃) = 3.75 / (1 + (1.45 × 10⁻⁴) * (3.75))
P(PCl₃) = 3.75 / 1.00055
P(PCl₃) = 3.749 atm (rounded to 3 significant figures)
Finally, we can substitute this value back into the equation for P(Cl₂):
P(Cl₂) = (1.45 × 10⁻⁴) * (3.75) * (3.749)
P(Cl₂) = 1.72 × 10⁻³ atm (rounded to 3 significant figures)
Therefore, the pressure of Cl₂(g) at equilibrium is 1.72 × 10⁻³ atm. This is a very small pressure, which indicates that the equilibrium lies far to the left, meaning that there is very little Cl₂(g) present at equilibrium.
To know more about equilibrium
brainly.com/question/30807709
#SPJ11
using the volume you just calculated, determine the moles of edta that reacted with the calcium ions.
In order to determine the moles of edta that reacted with the calcium ions, we need to use the volume of the edta solution that was used in the reaction.
The volume of edta solution can be used to calculate the moles of edta that reacted with the calcium ions using the formula: moles of edta = (volume of edta solution) x (concentration of edta solution).
Once we have determined the moles of edta that were present in the solution, we can then calculate the moles of edta that reacted with the calcium ions.
This can be done by subtracting the moles of unreacted edta from the total moles of edta used in the reaction.
Read more about the Moles.
https://brainly.com/question/15209553
#SPJ11
Why a measured cell potential may be higher than the theoretical cell potential?
There are several reasons why a measured cell potential may be higher than the theoretical cell potential:
Concentration effects: The theoretical cell potential is calculated based on standard conditions, which assume that the concentrations of the reactants and products are 1 M and that the temperature is 25°C.
In real-world situations, the concentrations of the reactants and products can deviate from 1 M, which can lead to a change in the cell potential.
If the concentration of one of the reactants increases, the cell potential can shift in a direction that favors the production of the other reactant.
Impurities: If the reactants or the electrolyte contain impurities, these impurities can interfere with the electrochemical reaction and affect the cell potential.
For example, if there are other substances present that can react with one of the reactants, this can lead to a change in the cell potential.
Non-ideal behavior: The theoretical cell potential assumes that the behavior of the reactants and products is ideal, meaning that there are no interactions between the particles that deviate from what is expected based on their chemical properties.
In reality, the behavior of the reactants and products can deviate from ideal behavior, which can affect the cell potential.
Measurement errors: Finally, it is possible that errors can occur during the measurement of the cell potential, which can result in a higher measured value than the theoretical value.
For example, the electrodes may not be placed correctly, the voltmeter may not be calibrated correctly, or there may be electrical noise that interferes with the measurement.
In summary, there are several factors that can cause a measured cell potential to be higher than the theoretical cell potential, including concentration effects, impurities, non-ideal behavior, and measurement errors.
To know more about cell potential refer here
https://brainly.com/question/1313684#
#SPJ11
a student titrated a 50.0 ml of 0.15 m glycolic acid with 0.50 m naoh. answer the following questions
Here are the answers to your questions:
1. What is the balanced chemical equation for this reaction? The balanced chemical equation for the reaction between glycolic acid (HA) and sodium hydroxide (NaOH) is: HA + NaOH → NaA + H2O where NaA is the sodium salt of glycolic acid (NaHA).
2. What is the initial number of moles of glycolic acid in the solution? To find the initial number of moles of glycolic acid in the solution, we need to use the formula: moles = concentration x volume where concentration is in units of moles per liter (M) and volume is in units of liters (L). Since the volume given in the problem is in milliliters (mL), we need to convert it to liters by dividing by 1000: volume = 50.0 mL / 1000 mL/L = 0.050 L Now we can plug in the values: moles of HA = concentration of HA x volume of HA moles of HA = 0.15 M x 0.050 L moles of HA = 0.0075 mol So the initial number of moles of glycolic acid in the solution is 0.0075 mol.
3. What is the volume of NaOH needed to reach the equivalence point? The equivalence point is the point at which all of the glycolic acid has reacted with the sodium hydroxide, so the moles of NaOH added must be equal to the moles of HA in the solution. We can use this fact to find the volume of NaOH needed to reach the equivalence point: moles of NaOH = moles of HA concentration of NaOH x volume of NaOH = moles of HA Solving for volume of NaOH: volume of NaOH = moles of HA / concentration of NaOH volume of NaOH = 0.0075 mol / 0.50 M volume of NaOH = 0.015 L or 15.0 mL So the volume of NaOH needed to reach the equivalence point is 15.0 mL. I hope that helps! Let me know if you have any other questions.
About sodium hydroxideSodium hydroxide, also known as lye and caustic soda or caustic soda, is an inorganic compound with the chemical formula NaOH. This compound is an ionic compound in the form of a white solid composed of the sodium cation Na⁺ and the hydroxide anion OH.
You can learn more about Sodium Hydroxide at https://brainly.com/question/30460434
#SPJ11
how many different signals will be present in the proton nmr for ethylpropanoate? (CH3CH2CO2CH2CH3) (Do not count TMS as one of the signal!)A. 2B. 3C. 4D. 5E. 6
Ethylpropanoate (CH3CH2CO2CH2CH3) will have 4 (option c) different signals in its proton NMR spectrum.
In the proton NMR spectrum of ethylpropanoate (CH3CH2CO2CH2CH3), there are four unique proton environments present.
These are the methyl group adjacent to the carbonyl group ([tex]CH_3CO[/tex]), the methylene group attached to the ester group ([tex]CH_2O[/tex]), the methylene group in the middle of the ethyl chain ([tex]CH_2[/tex]), and the terminal methyl group ([tex]CH_3[/tex]).
Each of these environments generates a distinct signal in the NMR spectrum. Therefore, the correct answer for the number of different signals in the proton NMR of ethylpropanoate is 4, which corresponds to option C.
For more such questions on proton, click on:
https://brainly.com/question/1481324
#SPJ11
D) There are 5 different signals present in the proton NMR for ethyl propanoate.
The molecule contains six unique proton environments: three methyl groups, two methylene groups, and one carbonyl group. The three methyl groups are equivalent, so they will appear as one signal. The two methylene groups are also equivalent, so they will appear as another signal. The carbonyl group will appear as a separate signal. In addition, the ethyl and propanoate groups are connected by a single bond, so there will be a coupling between the protons on these two groups, resulting in two additional signals. Thus, there will be a total of 5 signals in the proton NMR spectrum for ethyl propanoate.
learn more about NMR here:
https://brainly.com/question/31076123
#SPJ11
minimum uncertainty in the position of a proton moving at a speed of 4 * 10^6. (True or False)
The minimum uncertainty in the position of an electron moving at a speed of 4 x 10⁶ m/s is approximately 1.4 x 10⁻⁷ meters.
The minimum uncertainty in the position of an electron moving at a speed of 4 x 10⁶ m/s can be calculated using the Heisenberg uncertainty principle, which states that the product of the uncertainty in position and the uncertainty in momentum must be greater than or equal to Planck's constant divided by 4π.
Δx * Δp ≥ h/4π
Where Δx is the uncertainty in position, Δp is the uncertainty in momentum, and h is Planck's constant.
The momentum of an electron is given by the product of its mass and velocity, which is approximately 9.11 x 10⁻³¹ kg x 4 x 10⁶ m/s = 3.64 x 10⁻²⁴kg m/s.
Using this value and Planck's constant (h = 6.626 x 10⁻³⁴J s), we can solve for the minimum uncertainty in position:
Δx * 3.64 x 10⁻²⁴ kg m/s ≥ 6.626 x 10⁻³⁴ Js/ 4π
Δx ≥ (6.626 x 10⁻³⁴Js/4π) / (3.64 x 10⁻²⁴ kg m/s)
Δx ≥ 1.4 x 10⁻⁷ meters
Therefore, the minimum uncertainty in the position of an electron moving is 1.4 x 10^-7 meters.
Complete question:
What is the minimum uncertainty in the position of an electron moving at a speed of 4 times 10^6 m /s?
Learn more about Heisenberg's uncertainty at https://brainly.com/question/16941142
#SPJ11
a highly positive charged protein will bind a cation exchanger and elute off by changing the ph. (True or False)
The given statement "A highly positively charged protein will bind a cation exchanger and elute off by changing the pH" is true because cation exchangers contain negatively charged functional groups that attract positively charged molecules, such as highly positively charged proteins.
By changing the pH, the net charge of the protein can be altered, causing it to become less positively charged and therefore elute off the cation exchanger.
Proteins with a high isoelectric point (pI) will have a higher positive charge at pH values below their pI, allowing them to bind to the negatively charged cation exchanger.
By increasing the pH, the protein's net charge will become more negative, causing it to elute off the column. This process is called ion exchange chromatography and is widely used for protein purification in biochemistry and biotechnology.
For more questions like pH click the link below:
https://brainly.com/question/15289741
#SPJ11
All of the following species can function as Bronsted-Lowry bases in solution except: a. H2O b. NH3 c. S2- d. NH4+ e. HCO3-
Among the given species, NH4+ (option d) cannot function as a Bronsted-Lowry base in solution.
In the context of Bronsted-Lowry theory, a base is defined as a substance that can accept a proton (H+) in a reaction. Evaluating the given species, H2O, NH3, S2-, and HCO3- can all accept protons.
However, NH4+ is an ammonium ion, which already has a proton attached. Instead of functioning as a base, NH4+ acts as a Bronsted-Lowry acid since it can donate a proton to other species in the solution.
NH4+ is the exception among the given species that cannot act as a Bronsted-Lowry base. Thus, the correct choice is (d).
For more such questions on solution, click on:
https://brainly.com/question/25326161
#SPJ11
The species that cannot function as a Bronsted-Lowry base in solution is NH4+ because it already has a proton (H+) and cannot accept another proton to act as a base.
According to the Bronsted-Lowry theory, a base is defined as a species that can accept a proton (H+) in a chemical reaction. In the given options, H2O, NH3, S2-, and HCO3- are all capable of accepting a proton and therefore can function as Bronsted-Lowry bases in solution. However, NH4+ is already a positively charged ion that has accepted a proton, making it unable to accept another proton to act as a base. Instead, NH4+ can function as an acid by donating its proton to a species that can act as a base. Therefore, NH4+ cannot function as a Bronsted-Lowry base in the solution.
learn more about Bronsted-Lowry here:
https://brainly.com/question/14407412
#SPJ11
Oxygen gas is collected at a pressure of 123 atm in a container which has a volume of 10.0 l. what temperature must be maintained on 0.500 moles of this gas in order to maintain this pressure? express the temperature in degrees celsius.
To maintain a pressure of 123 atm in a 10.0 L container with 0.500 moles of oxygen gas, the required temperature in degrees Celsius needs to be determined.
Explanation: According to the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Rearranging the equation, T = PV / nR, we can calculate the temperature.
Given that the pressure is 123 atm, the volume is 10.0 L, the number of moles is 0.500, and R is the ideal gas constant (0.0821 L·atm/mol·K), we can substitute the values into the equation. Thus, T = (123 atm) * (10.0 L) / (0.500 mol) * (0.0821 L·atm/mol·K). Solving this equation gives us the temperature in Kelvin. To convert it to degrees Celsius, subtract 273.15 from the Kelvin value.
Learn more about ideal gas law here:
https://brainly.com/question/12624936
#SPJ11
calculate the pka values for the following acids. a) methanol (ka = 2.9 x 10-16) b) citric acid (ka = 7.2 x 10-4)
a) The pKa value for methanol can be calculated using the formula: pKa = -log(Ka).
pKa = -log(2.9 x 10^(-16)) = 15.54
b) The pKa value for citric acid can also be calculated using the formula: pKa = -log(Ka).
pKa = -log(7.2 x 10^(-4)) = 3.14
The pKa value represents the acidity of an acid. It is the negative logarithm of the acid dissociation constant (Ka), which indicates the extent to which the acid donates protons in a solution. Lower pKa values indicate stronger acids.
In the case of methanol, with a Ka value of 2.9 x 10^(-16), its pKa is 15.54. This value suggests that methanol is a very weak acid because it has a low tendency to donate protons in a solution.
On the other hand, citric acid has a Ka value of 7.2 x 10^(-4), resulting in a pKa of 3.14. This value indicates that citric acid is a relatively stronger acid compared to methanol, as it has a higher tendency to donate protons in a solution.
In summary, the pKa values for methanol and citric acid are 15.54 and 3.14, respectively, indicating their differing levels of acidity.
Learn more about pKa here:
https://brainly.com/question/30655117
#SPJ11
Oil is sometimes found trapped beneath a ‘cap’. Shale is good at reflecting sound waves underground. Why does this mean that geophysicists must scan the rocks with sound waves from different points?
Geophysicists use sound waves to scan rocks from different points because shale, which is good at reflecting sound waves underground, can create a barrier or "cap" that traps oil beneath it. By scanning the rocks from different angles and points, geophysicists can gather more comprehensive data and identify the location and extent of the trapped oil.
Shale is a type of sedimentary rock that has a high capacity for reflecting sound waves. When oil is present beneath the shale, it acts as a barrier or cap that prevents the oil from migrating further. To locate and assess the potential oil reservoir, geophysicists use a technique called seismic reflection, which involves sending sound waves into the ground and analyzing the reflected waves.
By scanning the rocks from different points or angles, geophysicists can obtain multiple sets of seismic data that provide a more complete picture of the subsurface structure. This allows them to analyze the reflections and variations in the sound waves, which can indicate the presence of oil traps or reservoirs. By combining the data from different points, geophysicists can create a three-dimensional model of the subsurface and make more accurate predictions about the location and extent of the oil reservoirs.
Learn more about Geophysicists here:
https://brainly.com/question/32469429
#SPJ11
A student weighs 1. 662 of NaHCO3. She then heats it in a test tube until the
reaction is complete. How many grams Na2CO3 can be produced in other words,
what is the theoretical yield)? Don't write the unit, just the number with correct
sig figs. (NaHCO3 = 84. 01 g/mol, Na2CO3 = 105. 99 g/mol)
2NaHCO3(s) - Na2CO3(s) + CO2(g) + H2O(g)
From all the information given, we find that the theoretical yield of Na2CO3 is approximately 1.048 g.
To find the theoretical yield of Na2CO3, we start by converting the given mass of NaHCO3 to moles. The molar mass of NaHCO3 is 84.01 g/mol. Therefore, the number of moles of NaHCO3 can be calculated as:
moles of NaHCO3 = mass of NaHCO3 / molar mass of NaHCO3
moles of NaHCO3 = 1.662 g / 84.01 g/mol
By performing this calculation, we find that the number of moles of NaHCO3 is approximately 0.01978 mol.
Next, we use the stoichiometric ratio from the balanced equation to determine the moles of Na2CO3 produced. From the equation, we can see that 2 moles of NaHCO3 produce 1 mole of Na2CO3. Therefore:
moles of Na2CO3 = moles of NaHCO3 / stoichiometric ratio
moles of Na2CO3 = 0.01978 mol / 2
This gives us the number of moles of Na2CO3, which is approximately 0.00989 mol.
Finally, we convert the moles of Na2CO3 back to grams by multiplying by its molar mass:
mass of Na2CO3 = moles of Na2CO3 * molar mass of Na2CO3
mass of Na2CO3 = 0.00989 mol * 105.99 g/mol
By performing this calculation, we find that the theoretical yield of Na2CO3 is approximately 1.048 g.
To learn more about molar mass click here, brainly.com/question/31545539
#SPJ11
The most likely location for an electron in H2 is halfway between the two hydrogen nuclei.
Select one:
True
False
False.The most likely location for an electron in the H2 molecule is not exactly halfway between the two hydrogen nuclei
Rather the electron density is concentrated around the internuclear axis, forming what is known as a bonding molecular orbital. This is the result of the constructive interference between the two atomic orbitals that combine to form the molecular orbital. The electron density is also spread out over a region that extends beyond the internuclear axis, forming what is known as the molecular orbital's "cloud" or "envelope".In the H2 molecule, the electrons are in molecular orbitals which are formed by the combination of the atomic orbitals of the two hydrogen atoms. The two electrons in the H2 molecule are most likely to be found in the bonding molecular orbital, which is lower in energy than the atomic orbitals from which it was formed. The bonding molecular orbital has a shape that is symmetrical around the line joining the two nuclei, which means that the electrons are most likely to be found between the two nuclei. Therefore, the statement "the most likely location for an electron in H2 is halfway between the two hydrogen nuclei" is true.
To know more about nuclei visit :
https://brainly.com/question/21796566
#SPJ11
Rank the following in order of decreasing acid strength: H 20, H 2S, H 2Se, H 2Te O A. H2Te> H2Se > H25> H20 O B. H2S> H2Te > H2Se> H20 O C.H20> H2S> H2Se> H2T O D.H2Se> H2Te > H2S> H20 OE. H2Se H2S H2Te> H20
The correct order of decreasing acid strength is: H₂Te > H₂Se > H₂S > H₂O.
Acid strength is determined by the stability of the conjugate base. In this case, we have H₂O, H₂S, H₂Se, and H₂Te. These are all hydrides of Group 16 elements. As you go down the group, the atomic size increases, which leads to weaker bonds and better stabilization of negative charge on the conjugate base.
As a result, the acid strength increases down the group. Therefore, H₂Te is the strongest acid, followed by H₂Se, H₂S, and H₂O in decreasing order. The correct ranking is option A: H₂Te > H₂Se > H₂S > H₂O.
Learn more about acid strength here:
https://brainly.com/question/3223615
#SPJ11
H2(g)+F2(g)⟶2HF(g) (l)ΔH∘rxn=−546.6 kJ⋅mol−1
2H2(g)+O2(g)⟶2H2O ΔH∘rxn=−571.6 kJ⋅mol−1
calculate the value of ΔH∘rxn for 2F2(g)+2H2O(l)⟶4HF(g)+O2(g)
The standard enthalpy change for the reaction 2F2(g) + 2H2O(l) ⟶ 4HF(g) + O2(g) is -1154.8 kJ⋅[tex]mol^{-1}[/tex].
To calculate the standard enthalpy change, or ΔH∘rxn, for the given reaction, we can use the Hess's Law of constant heat summation, which states that the enthalpy change for a chemical reaction is independent of the pathway taken between the initial and final states.
This means that we can add or subtract the enthalpies of other reactions to find the enthalpy change of the desired reaction.
We can first use the given reactions to find the enthalpy change for the formation of 2HF(g) from H2(g) and F2(g):
H2(g) + F2(g) ⟶ 2HF(g)
ΔH∘rxn = -546.6 kJ⋅mol−1
Next, we can use the given reaction to find the enthalpy change for the formation of H2O from H2(g) and O2(g):
2H2(g) + O2(g) ⟶ 2H2O(l)
ΔH∘rxn = -571.6 kJ⋅mol−1
To obtain the desired reaction, we need to reverse the second reaction and multiply it by a factor of 2, and also reverse the first reaction:
2H2O(l) ⟶ 2H2(g) + O2(g)
ΔH∘rxn = +571.6 kJ⋅mol−1
2HF(g) ⟶ H2(g) + F2(g)
ΔH∘rxn = +546.6 kJ⋅mol−1
Now, we can add the two reactions to obtain the desired reaction:
2F2(g) + 2H2O(l) ⟶ 4HF(g) + O2(g)
ΔH∘rxn = + (546.6 + 2 × 571.6) kJ⋅mol−1
= -1154.8 kJ⋅mol−1
Therefore, the standard enthalpy change for the reaction 2F2(g) + 2H2O(l) ⟶ 4HF(g) + O2(g) is -1154.8 kJ⋅mol−1. This negative value indicates that the reaction is exothermic and releases heat to the surroundings.
To learn more about standard enthalpy change refer here:
https://brainly.com/question/29556033
#SPJ11
A 6.00L tank at 27.1°C is filled with 9.72g of sulfur tetrafluoride gas and 5.05g of carbon dioxide gas. You can assume both gases behave as ideal gases under these conditions.Calculate the partial pressure of each gas, and the total pressure in the tank.
The partial pressure of sulfur tetrafluoride gas is 8.78 kPa, the partial pressure of carbon dioxide gas is 24.9 kPa, and the total pressure in the tank is 33.7 kPa.
To solve this problem, we can use the ideal gas law: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. We can rearrange this equation to solve for the pressure: P = nRT/V.
First, we need to calculate the number of moles of each gas. We can use the molar mass of each gas and the given mass to find the number of moles:
moles of SF₄ = 9.72 g / 108.1 g/mol = 0.0899 mol
moles of CO₂ = 5.05 g / 44.01 g/mol = 0.1148 mol
Next, we can plug in the values into the ideal gas law equation to find the partial pressures of each gas:
partial pressure of SF₄ = (0.0899 mol)(8.31 J/mol*K)(300.1 K) / 6.00 L = 8.78 kPa
partial pressure of CO₂ = (0.1148 mol)(8.31 J/mol*K)(300.1 K) / 6.00 L = 24.9 kPa
Finally, we can find the total pressure in the tank by adding the partial pressures:
total pressure = partial pressure of SF₄ + partial pressure of CO₂ = 8.78 kPa + 24.9 kPa = 33.7 kPa
To know more about partial pressure, refer here:
https://brainly.com/question/31214700#
#SPJ11
Sodium hypochlorite (NaOCI) is the active ingredient in laundry bleach. Typically, bleach contains 5.0% of this salt by mass, which is a 0.67 M solution. Determine the concentrations of all species and compute the pH of laundry bleach.
The concentrations of the species is 2.0 x 10⁻⁴ M, and the pH of laundry bleach is approximately 10.3.
To determine the concentrations of all species and the pH of laundry bleach, we need to start by identifying the relevant chemical reactions.
Sodium hypochlorite (NaOCl) in water undergoes hydrolysis to produce hypochlorous acid (HOCl) and hydroxide ions (OH⁻);
NaOCl + H₂O ⇌ HOCl + Na⁺ + OH⁻
The equilibrium constant for this reaction, known as the base dissociation constant ([tex]K_{b}[/tex]), is;
[tex]K_{b}[/tex] = [HOCl][OH⁻] / [NaOCl]
We can assume that the concentration of sodium hydroxide is negligible compared to that of sodium hypochlorite and hypochlorous acid, so we can simplify the expression to;
[tex]K_{b}[/tex]= [HOCl][OH⁻] / [NaOCl] ≈ [HOCl][OH⁻] / 0.67 M
Since bleach contains 5.0% by mass of NaOCl, we can calculate its molarity as;
0.05 g NaOCl / 1 g bleach x 100 g bleach / 1 L bleach x 1 mol NaOCl / 74.44 g NaOCl = 0.067 M
So, the [tex]K_{b}[/tex] expression becomes;
[tex]K_{b}[/tex] = [HOCl][OH⁻] / 0.067 M
Now, to determine the concentrations of HOCl and OH⁻, we need to use the fact that the solution is in equilibrium;
[H₂O] = [HOCl] + [OH⁻]
where [H₂O] is the initial concentration of water (55.5 M). Solving for [OH⁻], we get;
[OH⁻] = (Kb [NaOCl] / [H₂O][tex])^{0.5}[/tex]
= (1.0 x 10⁻⁷ x 0.067 / 55.5[tex])^{0.5}[/tex] = 2.0 x 10⁻⁴ M
And since [HOCl] = [H₂O] - [OH⁻], we get:
[HOCl] = 55.5 M - 2.0 x 10⁻⁴ M = 55.5 M
So the concentrations of the species in laundry bleach are:
[NaOCl] = 0.067 M
[HOCl] = 55.5 M
[OH⁻] = 2.0 x 10⁻⁴M
To compute the pH of laundry bleach, we need to calculate the concentration of hydrogen ions (H⁺) using the equation;
Kw = [H⁺][OH⁻]
where Kw is the ion product constant of water (1.0 x 10⁻¹⁴). Solving for [H⁺], we get;
[H⁺] = Kw / [OH⁻] = 1.0 x 10⁻¹⁴ / 2.0 x 10⁻⁴ M
= 5.0 x 10⁻¹¹ M
Taking the negative logarithm of [H⁺], we get the pH;
pH = -log[H⁺] = -log(5.0 x 10⁻¹¹) = 10.3
Therefore, the pH of laundry bleach is approximately 10.3.
To know more about Sodium hypochlorite here
https://brainly.com/question/15312359
#SPJ4
How many liters of gas B must react to give 1 L of gas D at the same temperature and pressure? Express your answer as an integer and include the appropriate units.
One liter of gas D can be produced by reacting one liter of gas B at the same temperature and pressure.
What is the volume of gas B required to produce one liter of gas D at the same temperature and pressure?To produce gas D from gas B, the reaction must be carried out in a 1:1 stoichiometric ratio. This means that one mole of gas D is produced for every mole of gas B consumed in the reaction. Since both gases are at the same temperature and pressure, the volume ratio can be directly equated to the mole ratio. Therefore, one liter of gas B must react to give one liter of gas D.
It is important to note that the above relationship only holds true for the specific reaction in question. If the reaction were to involve different gases or conditions, the stoichiometric ratio and volume relationship would differ.
Learn more about stoichiometric ratio
brainly.com/question/6907332
#SPJ11
the equilibrium constant, kc, for this process is 326 at a certain temperature. if the initial concentration of br2 = i2 is 0.619 m, what is the equilibrium concentration of ibr in m?
The equilibrium concentration of IBr is 0.234 M.
To answer this question, we need to use the equilibrium constant expression, which is given as:
Kc = [IBr]/([Br2][I2])
We know that the equilibrium constant (Kc) for this reaction is 326 at a certain temperature. We also know the initial concentration of Br2 and I2, which is 0.619 M.
Let's assume that at equilibrium, the concentration of IBr is x M. Then, the concentration of Br2 and I2 will be (0.619 - x) M each.Now, we can substitute these values into the equilibrium constant expression and solve for x:
326 = x/[(0.619 - x)^2]
326(0.619 - x)^2 = x
Simplifying this equation, we get: 202.094 - 652.792x + 326x^2 = 0
Solving this quadratic equation using the quadratic formula, we get:
x = 0.234 M (rounded to three significant figures)
To know more about equilibrium concentration visit:
https://brainly.com/question/16645766
#SPJ11
1. calculate the molar mass k2c2o4•h2o, cacl2•2h2o, and the cac2o4 product. (hint: include each h2o)
The molar mass of a compound is the sum of the molar masses of all the atoms in the compound. To calculate the molar mass of a hydrate (a compound that contains water molecules), we need to add the molar mass of the anhydrous (water-free) compound and the molar mass of the water molecules.
1. Molar mass of K2C2O4•H2O:
- Molar mass of K: 39.10 g/mol
- Molar mass of C2O4: 88.02 g/mol
- Molar mass of H2O: 18.02 g/mol
- Total molar mass: 39.10 g/mol × 2 + 88.02 g/mol × 1 + 18.02 g/mol × 1 = 246.26 g/mol
Therefore, the molar mass of K2C2O4•H2O is 246.26 g/mol.
2. Molar mass of CaCl2•2H2O:
- Molar mass of Ca: 40.08 g/mol
- Molar mass of Cl2: 70.90 g/mol
- Molar mass of H2O: 18.02 g/mol
- Total molar mass: 40.08 g/mol × 1 + 70.90 g/mol × 2 + 18.02 g/mol × 2 = 147.02 g/mol
Therefore, the molar mass of CaCl2•2H2O is 147.02 g/mol.
3. Molar mass of CaC2O4:
- Molar mass of Ca: 40.08 g/mol
- Molar mass of C2O4: 88.02 g/mol
- Total molar mass: 40.08 g/mol × 1 + 88.02 g/mol × 1 = 128.10 g/mol
Therefore, the molar mass of CaC2O4 is 128.10 g/mol.
To know more about compound refer here
https://brainly.com/question/13516179#
#SPJ11
Given the electrochemical reaction, , what is the value of Ecell at 25 °C if [Mg2+] = 0.100 M and [Cu2+] = 1.75 M?
Half-reaction
E° (V)
+1.40
+1.18
+0.80
+0.54
+0.34
-0.04
-1.66
-2.37
-2.93
+2.75 V, +2.67 V, +2.79 V, -2.00 V, +2.71 V
15.
Which statement about pure water is correct? Pure water does not ionize, pH > pOH, pH = 7 for pure water at any temperature, Kw is always equal to 1.0 × 10-14, OR [H3O+] = [OH-]?
17. The standard cell potential for the reaction is 1.104 V. What is the value of Ecell at 25 °C if [Cu2+] = 0.250 M and [Zn2+] = 1.29 M?
+1.083 V
–1.104 V
+1.104 V
+1.062 V
+1.125 V
1. The value of Ecell at 25 °C for the given electrochemical reaction, where [Mg²⁺] = 0.100 M and [Cu²⁺] = 1.75 M, is approximately +2.75 V.
15. The value of Ecell at 25 °C for the given electrochemical reaction, where [Mg²⁺] = 0.100 M and [Cu²⁺] = 1.75 M, is approximately +2.75 V.
17. The value of Ecell at 25 °C for the given standard cell potential of 1.104 V, with [Cu²⁺] = 0.250 M and [Zn²⁺] = 1.29 M, is approximately +1.083 V.
1. To calculate the cell potential (Ecell) at 25 °C, we need to use the Nernst equation:
Ecell = E°cell - (RT/nF) * ln(Q)
Given the concentrations of [Mg²⁺] and [Cu²⁺] in the reaction, we can determine the reaction quotient (Q). Since the reaction is not specified, I assume the reduction half-reaction for copper (Cu²⁺ + 2e⁻ → Cu) and the oxidation half-reaction for magnesium (Mg → Mg²⁺ + 2e⁻).
Using the Nernst equation and the given E° values for the half-reactions, we can calculate the value of Ecell:
Ecell = E°cell - (0.0257 V/K * 298 K / 2) * ln([Cu²⁺]/[Mg²⁺])
= 2.75 V - (0.0129 V) * ln(1.75/0.100)
≈ 2.75 V - (0.0129 V) * ln(17.5)
≈ 2.75 V - (0.0129 V) * 2.862
≈ 2.75 V - 0.037 V
≈ 2.713 V
Therefore, the value of Ecell at 25 °C for the given reaction with [Mg²⁺] = 0.100 M and [Cu²⁺] = 1.75 M is approximately +2.75 V.
15. Kw, the ion product of water, represents the equilibrium constant for the autoionization of water: H₂O ⇌ H₃O⁺ + OH⁻. In pure water, at any temperature, the concentration of both H₃O⁺ and OH⁻ ions is equal, and their product (Kw) remains constant.
Kw = [H₃O⁺][OH⁻] = 1.0 × 10⁻¹⁴
This constant value of Kw implies that the product of [H₃O⁺] and [OH-] in pure water is always equal to 1.0 × 10⁻¹⁴ at equilibrium. The pH and pOH of pure water are both equal to 7 (neutral), as the concentration of H₃O⁺ and OH⁻ ions are equal and each is 1.0 × 10⁻⁷ M.
Therefore, the correct statement about pure water is that Kw is always equal to 1.0 × 10⁻¹⁴.
17. Given the reduction half-reaction for copper (Cu²⁺ + 2e⁻ → Cu) and the oxidation half-reaction for zinc (Zn → Zn²⁺ + 2e⁻), the overall reaction can be written as:
Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)
Using the Nernst equation and the given E°cell value, we can calculate the value of Ecell:
Ecell = E°cell - (0.0257 V/K * 298 K / 2) * ln([Zn²⁺]/[Cu²⁺])
= 1.104 V - (0.0129 V) * ln(1.29/0.250)
≈ 1.104 V - (0.0129 V) * ln(5.16)
≈ 1.104 V - (0.0129 V) * 1.644
≈ 1.104 V - 0.0212 V
≈ 1.083 V
Therefore, the value of Ecell at 25 °C for the given standard cell potential of 1.104 V, with [Cu²⁺] = 0.250 M and [Zn²⁺] = 1.29 M, is approximately +1.083 V.
To learn more about electrochemical reaction, here
https://brainly.com/question/31236808
#SPJ4
if 1.40 g g of water is enclosed in a 1.5 −l − l container, will any liquid be present? IF so, what mass of liquid?
Assuming that the container is completely filled with water, no liquid other than water will be present.
However, if the container is not completely filled, there may be some air or gas present. The mass of the liquid water in the container is 1.40 g, as stated in the question.
to determine if any liquid will be present in the 1.5 L container with 1.40 g of water, we need to calculate the volume occupied by the water and compare it to the container's volume.
1. First, find the volume of water by dividing its mass by its density. The density of water is approximately 1 g/mL or 1000 g/L.
Volume = mass / density = 1.40 g / (1000 g/L) = 0.0014 L
2. Compare the volume of water to the container's volume:
0.0014 L (water) < 1.5 L (container)
Since the volume of water is less than the container's volume, the liquid will be present. The mass of liquid present is 1.40 g.
To know more about density, visit:
https://brainly.com/question/29775886
#SPJ11
hydrogen-3 has a half-life of 12.3 years. how many years will it take for 570.7 mg 3h to decay to 0.56 mg 3h ? time to decay: years
The number of years it will take for 570.7 mg ³H to decay to 0.56 mg ³H is approximately 103.1 years.
To determine the time it takes for 570.7 mg of hydrogen-3 (³H) to decay to 0.56 mg, we'll use the half-life formula:
N = N₀ * (1/2)^(t/T)
where:
N = remaining amount of ³H (0.56 mg)
N₀ = initial amount of ³H (570.7 mg)
t = time in years (unknown)
T = half-life (12.3 years)
Rearrange the formula to solve for t:
t = T * (log(N/N₀) / log(1/2))
Plugging in the values:
t = 12.3 * (log(0.56/570.7) / log(1/2))
t ≈ 103.1 years
It will take approximately 103.1 years for 570.7 mg of hydrogen-3 to decay to 0.56 mg.
Learn more about half-life here: https://brainly.com/question/29599279
#SPJ11
The brain can store lots of information because it is folded
The folding of the brain allows for a large storage capacity and efficient processing of information. The convoluted structure of the brain's outer layer, known as the cerebral cortex, increases its surface area, enabling it to accommodate a vast amount of neural connections and synaptic activity.
The brain's folding, or gyrification, plays a crucial role in its cognitive abilities. The folds, called gyri, and grooves, known as sulci, create an intricate network of neural pathways, facilitating communication between different regions of the brain. This complex architecture allows for efficient information processing, as it reduces the distance that signals need to travel between neurons.
Furthermore, the folding of the brain enhances its storage capacity. The increased surface area resulting from the folds enables a greater number of neurons to be packed into a smaller space. Neurons are the basic building blocks of the brain, responsible for processing and transmitting information. With more neurons in close proximity, the brain can store and process a larger volume of information.
To learn more about Neurons - brainly.com/question/10706320
#SPJ11
methyl orange is an indicator that changes color from red to yellow-orange over the ph range ~c.e(l'fl from 2.9 to 4.5. methyl orange
Methyl orange is a pH indicator that changes color from red to yellow-orange in the pH range of 2.9 to 4.5. It is commonly used in titrations to detect the endpoint of a reaction.
As an acidic pH indicator, methyl orange is often used in the titration of strong acids and weak bases. Its color change is a result of the chemical structure undergoing a change when the pH of the solution shifts. At lower pH levels (below 2.9), the molecule takes on a red hue, while at higher pH levels (above 4.5), it appears yellow-orange. The color change is due to the presence of a weakly acidic azo dye, which undergoes a chemical transformation as the hydrogen ions in the solution are either added or removed.
When used in a titration, methyl orange allows the observer to determine the endpoint of the reaction, signifying that the titrant has neutralized the analyte. The color change observed during the titration indicates that the pH of the solution has shifted, signaling the completion of the reaction. In some cases, methyl orange may not be the ideal indicator for certain titrations due to its relatively narrow pH range. In such instances, alternative indicators with a more suitable pH range should be used.
Know more about pH indicator here:
https://brainly.com/question/22603994
#SPJ11
determine the values of k by taking into account the volume of water used to make he saturated solution
The values of k by taking into account the volume of water used to make the saturated solution is [tex]Ksp = (sV)(m + n)^m[/tex]
In order to determine the values of K by taking into account the volume of water used to make the saturated solution, we need to use the following equation:
[tex]Ksp = [M+]^m [X^-]^n[/tex]
where Ksp is the solubility product constant, M+ is the cation of the salt, [tex]X^-[/tex] is the anion of the salt, m is the stoichiometric coefficient of M+ in the balanced chemical equation, and n is the stoichiometric coefficient of [tex]X^-[/tex]in the balanced chemical equation.
When the salt dissolves in water to form a saturated solution, the concentration of M+ and [tex]X^-[/tex] in the solution will be equal to their solubility values. We can express the solubility of [tex]M+X^-[/tex] in terms of the molar solubility s, which is defined as the number of moles of the salt that dissolve per liter of solution.
Therefore, we can rewrite the Ksp expression as:
Ksp = s(m + n)^m
Since we want to take into account the volume of water used to make the saturated solution, we can multiply the molar solubility s by the volume of water used to make the solution, which we will call V. The number of moles of the salt that dissolves will then be equal to sV.
Therefore, we can rewrite the Ksp expression again as:
Ksp = (sV)(m + n)^m
Learn more about saturated solution here:
https://brainly.com/question/1851822
#SPJ11
Acrylonitrile, C3H3N, is the starting material for
the production of a kind of synthetic fiber
acrylics) and can be made from propylene,
C3H6, by reaction with nitric oxide, NO, as
follows:
4 C3H6 (g) + 6 NO (g) → 4 C3H3N (s) + 6 H2O
(1) + N2 (g)
What is the limiting reagent if 168. 36 g of
C3H6 reacts with 180. 06 g of NO?
Acrylonitrile, C3H3N, is the starting material for the production of a kind of synthetic fiber acrylics) and can be made from propylene, the ratio of moles is less than the stoichiometric ratio of 4:6, [tex]C_3H_6[/tex] is the limiting reagent.
To determine the limiting reagent, we need to compare the moles of each reactant and identify which one is present in the smallest amount. The limiting reagent is the one that will be completely consumed in the reaction, thereby determining the maximum amount of product that can be formed.
First, let's calculate the moles of each reactant using their molar masses:
Molar mass of [tex]C_3H_6[/tex] (propylene): [tex]\(3 \times 12.01 + 6 \times 1.01 = 42.08 \, \text{g/mol}\)[/tex]
Moles of [tex]C3H6[/tex] = [tex]\(\frac{{168.36 \, \text{g}}}{{42.08 \, \text{g/mol}}} = 4.00 \, \text{mol}\)[/tex]
Molar mass of NO (nitric oxide): \(14.01 + 16.00 = 30.01 \, \text{g/mol}\)
Moles of NO = [tex]\(\frac{{180.06 \, \text{g}}}{{30.01 \, \text{g/mol}}} = 6.00 \, \text{mol}\)[/tex]
According to the balanced chemical equation, the stoichiometric ratio between [tex]C_3H_6[/tex] and NO is 4:6. This means that for every 4 moles of [tex]C_3H_6[/tex] 6 moles of NO are required.
To determine the limiting reagent, we compare the ratio of moles present. We have 4.00 moles of [tex]C3H6[/tex]and 6.00 moles of NO. The ratio of moles for [tex]C3H6[/tex] :NO is 4:6 or simplified to 2:3.
Since the ratio of moles is less than the stoichiometric ratio of 4:6, [tex]C_3H_6[/tex] is the limiting reagent. This means that 4.00 moles of[tex]C_3H_6[/tex] will completely react with 6.00 moles of NO, producing the maximum amount of product possible.
[tex]\[4 \, \text{C}_3\text{H}_6(g) + 6 \, \text{NO}(g) \rightarrow 4 \, \text{C}_3\text{H}_3\text{N}(s) + 6 \, \text{H}_2\text{O}(l) + \text{N}_2(g)\][/tex]
Learn more about limiting reagent here:
https://brainly.com/question/31171741
#SPJ11
Identify whether the atom or ion in each equation shows oxidation or reduction. Cu2 e− → Cu Cu2 is Fe → Fe3 3e−Fe is F e− → F−F− is 2l− → l2 2e−l− is 2H 2e− → H2H is.
Cu^2+ and F are reduced, Fe and I^- are oxidized, and H^+ is reduced.In each equation, we can identify whether the atom or ion undergoes oxidation or reduction by analyzing the change in its oxidation state.
1. Cu^2+ + 2e^- → Cu: In this equation, Cu^2+ gains 2 electrons and undergoes reduction, as its oxidation state decreases from +2 to 0 (a decrease in oxidation state indicates reduction).
2. Fe → Fe^3+ + 3e^-: In this equation, Fe loses 3 electrons and undergoes oxidation, as its oxidation state increases from 0 to +3 (an increase in oxidation state indicates oxidation).
3. F + e^- → F^-: In this equation, F gains an electron and undergoes reduction, as its oxidation state decreases from 0 to -1 (a decrease in oxidation state indicates reduction).
4. 2I^- → I2 + 2e^-: In this equation, I^- loses 2 electrons and undergoes oxidation, as its oxidation state increases from -1 to 0 (an increase in oxidation state indicates oxidation).
5. 2H + 2e^- → H2: In this equation, H^+ gains 2 electrons and undergoes reduction, as its oxidation state decreases from +1 to 0 (a decrease in oxidation state indicates reduction).
In summary, Cu^2+ and F are reduced, Fe and I^- are oxidized, and H^+ is reduced.
To learn more about atom click here;
brainly.com/question/29978890
#SPJ11
1. You are given a package of chemical material to make an identification. The only known information about this package is that it contains monoprotic acid. You dissolved 1. 0 g of the acid into 100 mL of water and titrated it with 0. 1 M NaOH solution. The equivalence point was found after titrating 118. 4 mL NaOH solution. What is this unknown acid
To determine the unknown acid, we can use the concept of equivalence point in a titration. In this case, a monoprotic acid dissolved in water and titrated with a 0.1 M NaOH solution.
At the equivalence point, the moles of acid will be equal to the moles of base. We can calculate the moles of NaOH used by multiplying the volume of NaOH solution (118.4 mL) by the molarity (0.1 M), which gives us 0.01184 moles of NaOH.
Since the acid is monoprotic, it will also have 0.01184 moles. To calculate the molar mass of the acid, we divide the mass (1.0 g) by the number of moles (0.01184 moles), which gives us approximately 84.5 g/mol.Therefore, the unknown acid has a molar mass of approximately 84.5 g/mol. Additional information or experimentation would be required to determine the specific identity of the acid.
To learn more about titration click here : brainly.com/question/31483031
#SPJ11
13. which pair of elements is most likely to react to form a covalently bonded species?
The pair of elements that is most likely to react to form a covalently bonded species are nonmetals. Nonmetals have a tendency to gain electrons to form negative ions or share electrons to form covalent bonds. This is because nonmetals have a high electronegativity, which means they have a strong attraction for electrons.
Examples of nonmetals that commonly form covalent bonds include carbon, nitrogen, oxygen, and hydrogen. For instance, two hydrogen atoms can share electrons to form a covalent bond and create a molecule of hydrogen gas (H2). Similarly, carbon and oxygen atoms can share electrons to form a covalent bond and create a molecule of carbon dioxide (CO2).
In contrast, metals are less likely to form covalent bonds and instead tend to form ionic bonds by losing electrons to form positive ions. Therefore, if you are trying to predict which pair of elements is most likely to form a covalently bonded species, you should look for nonmetals.
Know more about Covalent Bonds here:
https://brainly.com/question/19382448
#SPJ11