Find the perimeter of the rhombus below, given that a=9 and b=15. Round your answer to one decimal place, if necessary.

Answer:

Step-by-step explanation:

to find the answer you have to find the vulume and then divide by 450

Answer:

7 days

Step-by-step explanation:

vol = 20*15*10.5

vol = 3150

how many days  to drink 3150 cu.cm if Ben drinks 450 cu.cm per day?

3150 cu.cm / 450 cu.cm per day = 7 days

Answer:

Hello!

______________________

Peter samples her class by selecting 5 girls and 7 boys. This type of sampling is called?​

This type of sampling is called Stratified.

Hope this helped you!

:D

Answer:

b) 10

Step-by-step explanation:

In this case the frequency would be equal to the quotient between the sample that creative artists tell us (that is to say 120 people) and the amount of sastrological signs that there are (that is to say 12 signs), therefore it would be:

F = 120/12 = 10

Which means that the expected frequency for each category equal to 10.

So the answer is b) 10

Answer:

slope = 2/5   ,    y-intercept = -30

Step-by-step explanation:

-2x + 5y = -30

5y  = 2x - 30

y = 2/5x - 6

we know that the general form is:

y = (slope)*x + (y- intercept)

so, from our equation, we can say that...

slope = 2/5

y- intercept = -30

Answer:

C.

Step-by-step explanation:

When two lines are parallel, their slopes are the same.

Since the slope of line l is 2/7, the slope of its parallel line m must also be 2/7.

The answer is C.

Answer:

C. 2/7

Step-by-step explanation:

Parallel lines are lines that have the same slopes.

We know that line l is parallel to line m.

Therefore, the slope of line l is equal to the slope of line m.

[tex]m_{l} =m_{m}[/tex]

We know that line l has a slope of 2/7.

[tex]\frac{2}{7} =m_{m}[/tex]

So, line m also has a slope of 2/7. The answer is C. 2/7

Answer:

[tex]\mathbf{x(t) = \dfrac{ \sqrt 5}{2}e^{-t} }[/tex]

Step-by-step explanation:

Given that:

mass of the object = 2 kg

A force of 5nt is applied to move the object 0.5m from its equilibrium position.

i.e

Force = 5 newton

Stretchin (x) =0.5 m

Damping force = 1 newton

Velocity = 0.25 m/second

The object is pulled to the left until the spring is stretched lm and then released with the initial velocity of 2m/second to the right

SOLUTION:

If F = kx

Then :

5 N = k(0.5 m)

where ;

k = spring constant.

k = 5 N/0.5 m

k = 10 N/m

the damping force of the object sliding on the table is 1 newton when the velocity is 0.25m/second.

SO;

[tex]C \dfrac{dx}{dt}= F_d[/tex]

[tex]C* 0.25 = 1[/tex]

C = [tex]\dfrac{1 \ N }{0.25 \ m/s}[/tex]

C = 4 Ns/m

NOW;

[tex]m \dfrac{d^2x}{dt^2}+ C \dfrac{dx}{dt}+ kx = 0[/tex]

Divide through by m; we have;

[tex]\dfrac{m}{m}\dfrac{d^2x}{dt^2}+ \dfrac{C}{m} \dfrac{dx}{dt}+ \dfrac{k}{m} x= 0[/tex]

[tex]\dfrac{d^2x}{dt^2}+ \dfrac{C}{m} \dfrac{dx}{dt}+\dfrac{k}{m}x= 0[/tex]

[tex]\dfrac{d^2x}{dt^2}+ \dfrac{4}{2} \dfrac{dx}{dt}+\dfrac{10}{2}x= 0[/tex]

[tex]\dfrac{d^2x}{dt^2}+ 2 \dfrac{dx}{dt}+5x= 0[/tex]

we all know that:

[tex]x(t) = Ae^{(\alpha \ t)}[/tex]  ------ (1)

SO;

[tex]\alpha ^2 + 2\alpha + 5 = 0[/tex]

[tex]\alpha = \dfrac{-2 \pm \sqrt{(4)-(4*5)}}{2}[/tex]

[tex]\alpha = -1 \pm 2i[/tex]

Thus ;

[tex]x(t) = e^{-t}[A \sin (2t)+ B cos (2t)][/tex]   ------------ (1)

However;

[tex]\dfrac{dx}{dt} = e^{-t}[A \sin (2t)+ B cos (2t)]+ 2e ^{-t} [A \cos (2t)- B \ Sin (2t)][/tex]     ------- (2)

From the question ; we are being told that;

The object is pulled to the left until the spring is stretched 1 m and then released with the initial velocity of 2m/second to the right.

So ;

[tex]x(0) = -1 \ m[/tex]

[tex]\dfrac{dx}{dt}|_{t=0} = 2 \ m/s[/tex]

x(0) ⇒ B = -1

[tex]\dfrac{dx}{dt}|_{t=0} =- B +2A[/tex]

[tex]=- 1 +2A[/tex]

1 = 2A

A = [tex]\dfrac{1}{2}[/tex]

From (1)

[tex]x(t) = e^{-t}[A \sin (2t)+ B cos (2t)][/tex]  

[tex]x(t) = e^{-t}[\dfrac{1}{2} \sin (2t)+ (-1) cos (2t)][/tex]

[tex]x(t) = e^{-t}[\dfrac{1}{2} \sin (2t)-cos (2t)][/tex]

Assuming;

[tex]A cos \ \phi = \dfrac{1}{2}[/tex]

[tex]A sin \ \phi = 1[/tex]

Therefore:

[tex]A = \sqrt{\dfrac{1}{4}+1}[/tex]

[tex]A = \sqrt{\dfrac{1+4}{4}}[/tex]

[tex]A = \sqrt{\dfrac{5}{4}}[/tex]

[tex]A ={ \dfrac{ \sqrt5}{ \sqrt4}}[/tex]

[tex]A ={ \dfrac{ \sqrt5}{ 2}}[/tex]

where;

[tex]\phi = tan ^{-1} (2)[/tex]

Therefore;

[tex]x(t) = \dfrac{\sqrt 5}{2}e^{-t} \ sin (2 t - \phi)[/tex]

From above ; the amplitude is ;

[tex]\mathbf{x(t) = \dfrac{ \sqrt 5}{2}e^{-t} }[/tex]

Answer:

i think option c must be correct because it has formed the grops on the basis of length of time and made the group by random selection.

Answer:

The test statistic value is, t = -5.245.

The effect size using estimated Cohen's d is 2.35.

Step-by-step explanation:

A paired t-test would be used to determine whether the remedial tutoring has been effective for the statistics tutor's five students.

The hypothesis can be defined as follows:

H₀: The remedial tutoring has not been effective, i.e. d = 0.

Hₐ: The remedial tutoring has been effective, i.e. d > 0.

Use Excel to perform the Paired t test.

Go to Data → Data Analysis → t-test: Paired Two Sample Means

A dialog box will open.

Select the values of the variables accordingly.

The Excel output is attached below.

The test statistic value is, t = -5.245.

Compute the effect size using estimated Cohen's d as follows:

[tex]\text{Cohen's d}=\frac{Mean_{d}}{SD_{d}}[/tex]

                [tex]=\frac{0.54}{0.23022}\\\\=2.34558\\\\\approx 2.35[/tex]

Thus, the effect size using estimated Cohen's d is 2.35.

By "slope" I assume you mean slope of the tangent line to the parabola.

For any given value of x, the slope of the tangent to the parabola is equal to the derivative of y :

[tex]y=ax^2+bx+c\implies y'=2ax+b[/tex]

The slope at x = 1 is 5:

[tex]2a+b=5[/tex]

The slope at x = -1 is -11:

[tex]-2a+b=-11[/tex]

We can already solve for a and b :

[tex]\begin{cases}2a+b=5\\-2a+b=-11\end{cases}\implies 2b=-6\implies b=-3[/tex]

[tex]2a-3=5\implies 2a=8\implies a=4[/tex]

Finally, the parabola passes through the point (2, 18); that is, the quadratic takes on a value of 18 when x = 2:

[tex]4a+2b+c=18\implies2(2a+b)+c=10+c=18\implies c=8[/tex]

So the parabola has equation

[tex]\boxed{y=4x^2-3x+8}[/tex]

Using function concepts, it is found that the parabola is: [tex]y = 4x^2 - 3x + 14[/tex]

----------------------------

The parabola is given by:

[tex]y = ax^2 + bx + c[/tex]

----------------------------

Slope 5 at x = 1 means that [tex]y^{\prime}(1) = 5[/tex], thus:

[tex]y^{\prime}(x) = 2ax + b[/tex]

[tex]y^{\prime}(1) = 2a + b[/tex]

[tex]2a + b = 5[/tex]

----------------------------

Slope -11 at x = -1 means that [tex]y^{\prime}(-1) = -11[/tex], thus:

[tex]-2a + b = -11[/tex]

Adding the two equations:

[tex]2a - 2a + b + b = 5 - 11[/tex]

[tex]2b = -6[/tex]

[tex]b = -\frac{6}{2}[/tex]

[tex]b = -3[/tex]

And

[tex]2a - 3 = 5[/tex]

[tex]2a = 8[/tex]

[tex]a = \frac{8}{2}[/tex]

[tex]a = 4[/tex]

Thus, the parabola is:

[tex]y = 4x^2 - 3x + c[/tex]

----------------------------

It passes through the point (2, 18), which meas that when [tex]x = 2, y = 18[/tex], and we use it to find c.

[tex]y = 4x^2 - 3x + c[/tex]

[tex]18 = 4(2)^2 - 3(4) + c[/tex]

[tex]c + 4 = 18[/tex]

[tex]c = 14[/tex]

Thus:

[tex]y = 4x^2 - 3x + 14[/tex]

A similar problem is given at https://brainly.com/question/22426360

Answer:

  6 mL

Step-by-step explanation:

It is a matter of units conversion.

  volume = (mass) × (dose/mass) ÷ (dose/volume)

  (132 lb)/(2.2 kg/lb) × (0.05 mg/kg) / (0.05 mg/0.1 mL) = 6 mL

Answer:

174 square cm

Step-by-step explanation:

2(9×4) + 2(6×4)+ 9×6

2(36) + 2(24) + 54

72 + 48 + 54

120 + 54

174

==========================================================

Explanation:

We're going to be using the slope formula a bunch of times.

Find the slope of the line through points A and C

m = (y2 - y1)/(x2 - x1)

m = (-12-9)/(9-2)

m = -21/7

m = -3

The slope of line AC is -3. The slopes of line AB and line BC must also be the same for points A,B,C to be collinear. The term collinear means all three points fall on the same straight line.

-------

Let's find the expression for the slope of line AB in terms of k

m = (y2 - y1)/(x2 - x1)

m = (k-9)/(4-2)

m = (k-9)/2

Set this equal to the desired slope -3 and solve for k

(k-9)/2 = -3

k-9 = 2*(-3) ..... multiply both sides by 2

k-9 = -6

k = -6+9 .... add 9 to both sides

k = 3

If k = 3, then B(4,k) updates to B(4,3)

-------

Let's find the slope of the line through A(2,9) and B(4,3)

m = (y2 - y1)/(x2 - x1)

m = (3-9)/(4-2)

m = -6/2

m = -3 we get the proper slope value

Finally let's check to see if line BC also has slope -3

m = (y2 - y1)/(x2 - x1)

m = (-12-3)/(9-4)

m = -15/5

m = -3 we get the same value as well

Since we have found lines AB, BC and AC all have slope -3, we have proven that A,B,C fall on the same straight line. Therefore, this shows A,B,C are collinear.

Answer:

Step-by-step explanation:

Mean & median of 6 packages:

15, 17, 19, 31, 33 , 35

Median =  [tex]\frac{19+31}{2}[/tex]

            = [tex]\frac{50}{2}[/tex]

           = 25

[tex]Mean = \frac{15+17+19+31+33+35}{6}\\\\=\frac{150}{6}\\=25[/tex]

Mean & median of 7 packages:

15,17,19,31,33,35,39

Median = 31

[tex]Mean=\frac{19+15+35+17+33+31+39}{7}\\\\=\frac{189}{7}\\\\=27[/tex]

After including 39 ounce package, Median will increase more

Answer:

  A(8, 10)

Step-by-step explanation:

Vertex A is on the vertical line x=8, so we can find the y-coordinate by solving the boundary equation ...

  5x +8y = 120

  5(8) +8y = 120 . . . use the x-value of the vertical line

  5 + y = 15 . . . . . . . divide by 8

  y = 10 . . . . . . . . . . subtract 5

Point A is (8, 10).

Answer:

[tex]log_35=x[/tex]

Step-by-step explanation:

I am going to assume you meant [tex]5=3^x[/tex]

When converting exponential equations into logarithmic form, remember this: [tex]y = log_bx[/tex] is equivalent to [tex]x = b^y[/tex]

Answer:

Option B - False

Step-by-step explanation:

Critical value is a point beyond which we normally reject the null hypothesis. Whereas, P-value is defined as the probability to the right of respective statistic which could either be Z, T or chi. Now, the benefit of using p-value is that it calculates a probability estimate which we will be able to test at any level of significance by comparing the probability directly with the significance level.

For example, let's assume that the Z-value for a particular experiment is 1.67, which will be greater than the critical value at 5% which will be 1.64. Thus, if we want to check for a different significance level of 1%, we will need to calculate a new critical value.

Whereas, if we calculate the p-value for say 1.67, it will give a value of about 0.047. This p-value can be used to reject the hypothesis at 5% significance level since 0.047 < 0.05. But with a significance level of 1%, the hypothesis can be accepted since 0.047 > 0.01.

Thus, it's clear critical values are different from P-values and they can't be used interchangeably.

Answer:

a) 4 cm

b) 5 cm

c) 10 cm

Step-by-step explanation:

The side lengths of the reflected square are equal to the original, and the distance from the axis(2) also remains the same.  From there, it is just addition.

Hope it helps <3

Answer:

A) 4

B) 5

C) 10

Step-by-step explanation:

edge2020

Answer:

Step-by-step explanation:

confidence level for the proportion of all American youngsters who are seriously overweight is (0.137, 0.163)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue

Read

Answer:

No solution.

Step-by-step explanation:

Because the equations are combined but the final answers are not equal, the equations have no solution. This is because "no matter what value is plugged in for the variable, you will ALWAYS get a contradiction".

Hope this helps!

Answer:

yes it is correct

Step-by-step explanation:

plz give brainliest.

Answer:

IT'S NOT -15 FOR SUREEE

Step-by-step explanation:

I Believe it's 15

The closest we get is the addition property, which was used in step 2. This is a fairly similar idea because subtraction is effectively adding on a negative number. Example: 5-7 = 5+(-7). Though because your teacher is making a distinction between addition property of equality and subtraction property of equality, it's safe to say that the subtraction property is not used.

Answer:

[tex]F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2[/tex]

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have [tex]n_2 -1 =16-1=15[/tex] and for the denominator we have [tex]n_1 -1 =16-1=15[/tex] and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

[tex]p_v =2*P(F_{15,15}>2.2)=0.138[/tex]

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

Step-by-step explanation:

Information given

[tex]n_1 = 16 [/tex] represent the sampe size 1

[tex]n_2 =16[/tex] represent the sample 2

[tex]s^2_1 = 2.5[/tex] represent the sample deviation for 1

[tex]s^2_2 = 5.5[/tex] represent the sample variance for 2

[tex]\alpha=0.10[/tex] represent the significance level provided

The statistic is given by:

[tex]F=\frac{s^2_2}{s^2_1}[/tex]

Hypothesis to test

We want to test if the variations in terms of the variance are equal, so the system of hypothesis are:

H0: [tex] \sigma^2_1 = \sigma^2_2[/tex]

H1: [tex] \sigma^2_1 \neq \sigma^2_2[/tex]

The statistic is given by:

[tex]F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2[/tex]

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have [tex]n_2 -1 =16-1=15[/tex] and for the denominator we have [tex]n_1 -1 =16-1=15[/tex] and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

[tex]p_v =2*P(F_{15,15}>2.2)=0.138[/tex]

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

Answer:

False

Step-by-step explanation:

No esta verdad.

8716/4 = 2179 (divisible por 4)

Answer:

(C) 25,35 and 175,35

Answer:

but I can do it if you want but I don't you too too y u your help and you have time can you

Step-by-step explanation:

guy who was it that you are not going to be able to make it to the meeting tonight but I can tomorrow if you have time can you come to my house

Answer:

5i² - 25ij +ji-5j²

Step-by-step explanation:

Use distributive property

Answer:

Step-by-step explanation:

A = (5i+j)

B = (i-5j)

A × B is

( 5i + j) ( i - 5j)

Expand

We have

5i² - 25ij + ij - 5j²

The final answer is

5i² - 24ij - 5j²

Hope this helps you.

Answer:

1  [tex]\mu = 100[/tex]

2 [tex]\sigma = 16[/tex]

3 [tex]\mu_x = 100[/tex]

4 [tex]\sigma _{\= x } = 2.309[/tex]

Step-by-step explanation:

From the question

    The population mean is  [tex]\mu = 100[/tex]

    The standard deviation is [tex]\sigma = 16[/tex]

     The sample mean is  [tex]\mu_x = 100[/tex]

     The sample size is  [tex]n = 48[/tex]

     The mean standard deviation is  [tex]\sigma _{\= x } = \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

     [tex]\sigma _{\= x } = \frac{16 }{\sqrt{48} }[/tex]

     [tex]\sigma _{\= x } = 2.309[/tex]

Answer:

16 km due west

Step-by-step explanation:

The bearing of the school p from school q is 16 km due west.

To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.

Since p is directly west of q, then it implies that q must be directly east of p.

We now know the direction.

Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.

Hence, the bearing of q from p is 16 km due west.