Find the length of the side labeled x. Round intermediate values to the nearest tenth. Use the rounded values to calculate the next value. Round your final answer to the nearest tenth.

Answer:

A=3244.8 dollars

Step-by-step explanation:

A=p(1+r)^t

A=3000(1+0.04)^2

A=3244.8 dollars

Answer:

144 codes are possible

Step-by-step explanation:

Okay for the first digit, we shall be selecting one out of 3,4,5,6.

Meaning we are selecting one out of four choices

The number of ways this can be done is 4C1 ways = 4 ways

For the second digit, we have 5,6,7 or 8, we are still selecting 1 out of 4 selections and the number of ways we can do this is also 4 ways

And lastly , we can choose any digit for the last number expect 5 , so from 0 to 9, we are removing 1 which means we are left with 9 choices

So the number of different area codes possible are ; 9 * 4 * 4 = 144 codes

Answer:

The vertex of the graph moves to a point twice as far from the y-axis.

Step-by-step explanation:

How does the graph of y = a(x – h)2 + k change if the value of h is doubled?

The vertex of the graph moves to a point twice as far from the x-axis.

because the role of h is to indicate the distance of the vertex from the y-axis.

The vertex of the graph moves to a point half as far from the x-axis.

The vertex of the graph moves to a point half as far from the y-axis.

Transformation involves changing the position of a function.

When h is doubled in [tex]\mathbf{y = a(x - h)^2 + k}[/tex], the vertex of the graph moves to a point twice as far from the y-axis.

The function is given as:

[tex]\mathbf{y = a(x - h)^2 + k}[/tex]

When the value of h is doubled, the new function becomes:

[tex]\mathbf{y' = a(x - 2h)^2 + k}[/tex]

Rewrite as:

[tex]\mathbf{y' = a(x - h- h)^2 + k}[/tex]

The above equation means that:

Function y will be translated to the right by h units

Assume the vertex is:

[tex]\mathbf{Vertex = (2,5)}[/tex]

The new vertex will be:

[tex]\mathbf{Vertex = (4,5)}[/tex]

Comparing the vertices, it means that:

The new function will have its vertex twice as far from the y-axis

Hence, option (b) is correct.

Read more about transformation at:

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Answer:

17

Step-by-step explanation:

3m-(m + 5)

Distribute the minus sign

3m -m -5

Combine like terms

2m -5

Let m =11

2*11 -5

22-5

17

Answer:

[tex]17[/tex]

Step-by-step explanation:

[tex]3m-(m + 5)[/tex]

[tex]m= 11[/tex]

Plug m as 11 in the expression.

[tex]3(11)-(11+5)[/tex]

Evaluate.

[tex]33-16[/tex]

[tex]=17[/tex]

Answer:

4 liters

Step-by-step explanation:

Let's assume that the side lengths of the cubical block are 2 inches.

This means that one of the sides area is 4 in².

Multiplying this by 6 (for there are 6 sides) gets us 24 in².

So one liter of paint covers 24 in².

Now if the side lengths (edge) of the second block is doubled, that means that the side lengths are [tex]2\cdot2 = 4[/tex] inches.

So the area of one side is 16 in².

Multiplying this by 6 (as there are 6 sides) gets us 96 in².

To find how many liters of paint this will take, we divide 96 by 24.

[tex]96\div24=4[/tex]

So 4 liters of paint will be needed for the second cubical block.

Hope this helped!

Answer:

Volume of the sphere is 66.67r/h

Step-by-step explanation:

Hello,

Volume of a sphere = ⁴/₃πr³

Volume of a cylinder = πr²h

The volume of the cylinder = 50ft³

But the cylinder and sphere both have the same radius and height

Volume of a cylinder = πr²h

50 = πr²h

Make r² the subject of formula

r² = 50/πh

Volume of a sphere = ⁴/₃πr³

Put r² into the volume of a sphere

Volume of a sphere = ⁴/₃π(50/πh)r

Volume of a sphere = ⁴/₃ × 50r/h

Volume of a sphere = ²⁰⁰/₃ r/h

Volume of a sphere = 66.67r/h

The volume of the sphere is 66.67r/h

Answer:

6c1;   [tex]Area = 81.12m^2[/tex]

6cii:  See Explanation

Step-by-step explanation:

Given

[tex]A = 3p^2[/tex]

[tex]0 \leq p \leq 6[/tex]

Where A represents Area and P represents Width

Required

Solve 6c

Please note that because you only need 6c, I'll solve using calculations;

Solving 6ci:

Area of the cage, when width is 5.2m

Substitute 5.2m for p in[tex]A = 3p^2[/tex]

[tex]A = 3 * 5.2m^2[/tex]

[tex]A = 3 * 27.04m^2[/tex]

[tex]A = 81.12m^2[/tex]

Hence, the area of the cage is 81.12m²

Solving 6cii:

Area of the cage, when width is 40m

From the range of value of p:   [tex]0 \leq p \leq 6[/tex], 40m is out of range of the values of p

However, if the range is extended; the value of Area is as follows;

Substitute 40m for p

[tex]A = 3 * 40m^2[/tex]

[tex]A = 3 * 1600m^2[/tex]

[tex]A = 4,800m^2[/tex]

Answer:

6/35

Step-by-step explanation:

add ¹/7+¹/5 =12/35

divide 12/35 by 2

=6/35

Answer:  see graph (attached)

Step-by-step explanation:

Plot coordinates for each line. You MUST include the boundary points.

y = 3x - 5       x ≤ 1    

Choose x = -2, then y = 3(-2) - 5 = -11

Must include x = -1, then y = 3(-1) - 5 = -8

Draw a line starting at (-1, -8) and passing through (-2, -11)

y = -2x + 3      -1 < x < 4

Must include x = -1, then y = -2(-1) + 3 = 5

Must include x = 4, then y = -2(4) + 3 = -5

Draw a line segment starting at (-1, 5) and ending at (4, -5).

Note that both are strictly less than so must have open dots.

y = 2      x ≥ 4

Must include x = 4, then y = 2

Choose x = 5, then y = 2

Draw a line starting at (4, 2) and passing through (5, 2)

Answer:

its a! sorry im so late

Step-by-step explanation:

Answer:

[tex]y\geq 0\\y\geq \frac{3}{2}x-3\\ y\leq -x+3[/tex]

Step-by-step explanation:

The region R is surrounded by 4 lines, the first one is y=x+1, the second one is y=0 or the axis x, and the third and fourth one need to be calcualted.

To find the equation of a line through the points (x1,y1) and (x2, y2) we can use the following equation:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

Then, our third line is going to be the line that passes through the points (2,0) and (4,3), so the equation is:

[tex]y=\frac{3-0}{4-2}(x-2)\\y=\frac{3}{2}x-3[/tex]

Our fourth line is the line that passes through the points (3,0) and (0,3), so the equation is:

[tex]y=\frac{3-0}{0-3}(x-3)\\y=-x+3[/tex]

Then we can say that the other three inequalities are:

[tex]y\geq 0\\y\geq \frac{3}{2}x-3\\ y\leq -x+3[/tex]

Answer:

-58.41509433

Step-by-step explanation:

0.4+8(5-0.8*5/8)-5/(2.5)=34.4

[0.4+8(5-4/8)-(2)]=

[0.4+8(40-4)/8)-2=34.4 ( nominator)

15-(8.9-2.6/(2/3))*34*2/5 =-53

15-(8.9-3.9)*68/5

15-5*68/5=

15-68=-53 ( denominator)

(34.4/-53) *90

-58.41509433

Answer:

x + 2y ≤ 12

x + 2y = 12

Step-by-step explanation:

The teachers can not give more than 12 hours of homework so this is the answer. those are the 2 equations you can use. It under 12 hours or equal to 12 hours.

Answer:

Part A: x + 2y ≤ 12.

Part B: y = -1/2x + 6.

Part C: (0, 0).

Step-by-step explanation:

Part A: The total hours of homework have to be 12 hours, and it has to be either 12 hours or less. So, we have ≤ 12.

They take 1 math course with x hours of homework, so in total, that is 1 * x = x hours of math homework.

They take 2 science courses with y hours of homework, so in total, that is 2 * y = 2y hours of science homework.

The inequality would then be x + 2y ≤ 12.

Part B: x + 2y = 12

2y = -x + 12

y = -1/2x + 6

You can  use the Math is Fun: Function Grapher and Calculator to find the graph of the line, shown below.

Part C: Since the inequality uses a ≤ symbol, we know that the shading will be underneath the line. An appropriate point below the line includes (0, 0). We will test out whether it works as a point included in the inequality.

x + 2y ≤ 12

0 + 2 * 0 ≤ 12

0 + 0 ≤ 12

0 ≤ 12

Since this is a true statement, (0, 0) holds true for the inequality.

Hope this helps!

Answer:

x = -7/9; y = 4/3.

Step-by-step explanation:

I will assume that the top equation is 6x + 2y = -2, and the bottom one is 3x - 2y = -5.

If you add the two...

(6x + 3x) + (2y + (-2y)) = (-2 + (-5))

9x + 0 = -7

9x = -7

x = -7/9

6(-7/9) + 2y = -2

-42/9 + 2y = -18/9

2y = 24/9

y = 24/18

y = 12/9

y = 4/3

Hope this helps!

Answer:

(-3, -11)

i needed to put more characters so here

Answer:

C

Step-by-step explanation:

0.1(x - 100)² + 250

0.1[(x - 100)(x - 100)] + 250

0.1(x² -200x + 10000) + 250

0.1x² - 20x + 1000 + 250

0.1x² - 20x + 1250

0.1x² - 25x + 5x + 1250

0.1x(x - 250) + 5(x + 250)

∴ (0.1x + 5)(x - 250) or (0.1x + 5)(x + 250)

Answer:

[tex] (0, 8\sqrt{3}) [/tex]  and  [tex] (0, -8\sqrt{3}) [/tex] are both 14 units from points (-2, 0) and (2, 0).

Step-by-step explanation:

distance formula

[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

We want the distance, d, from points (-2, 0) and (2, 0) to be 14.

Point (-2, 0):

[tex] 14 = \sqrt{(x - (-2))^2 + (y - 0)^2} [/tex]

[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]

Point (2, 0):

[tex] 14 = \sqrt{(x - 2)^2 + (y - 0)^2} [/tex]

[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]

We have a system of equations:

[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]

[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]

Since the right sides of both equations are equal, we set the left sides equal.

[tex] \sqrt{(x + 2)^2 + y^2} = \sqrt{(x - 2)^2 + y^2} [/tex]

Square both sides:

[tex] (x + 2)^2 + y^2 = (x - 2)^2 + y^2 [/tex]

Square the binomials and combine like terms.

[tex] x^2 + 4x + 4 + y^2 = x^2 - 4x + 4 + y^2 [/tex]

[tex] 4x = -4x [/tex]

[tex] 8x = 0 [/tex]

[tex] x = 0 [/tex]

Now we substitute x = 0 in the first equation of the system of equations:

[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]

[tex] \sqrt{(0 + 2)^2 + y^2} = 14 [/tex]

[tex] \sqrt{4 + y^2} = 14 [/tex]

Square both sides.

[tex] y^2 + 4 = 196 [/tex]

[tex] y^2 = 192 [/tex]

[tex] y = \pm \sqrt{192} [/tex]

[tex] y = \pm \sqrt{64 \times 3} [/tex]

[tex] y = \pm 8\sqrt{3} [/tex]

The points are:

[tex] (0, 8\sqrt{3}) [/tex]  and  [tex] (0, -8\sqrt{3}) [/tex]

Answer:

P((1 or 2) and Tail) = 1/6 = StartFraction 1 over 6

Step-by-step explanation:

A six-sided die and a coin.

Probability of getting <3 and tail.

P((1 or 2) and Tail)

= 2/6 * 1/2

= 1/6

Answer:

1/6

Step-by-step explanation:

Answer:

Symmetry is the property of an object to retain its shape even if it is turned or turned.

The three corporate logos are McDonald, Shell, Snapcaht

McDonald company logo is symmetrical and it is a reflective symmetry.

Shell logo is symmetrical and it is also reflective symmetry.

Snaphcat logo is symmetrical and it is also reflective symmetry.

Answer:

C

Step-by-step explanation:

1:draw a very simple Cartesian plane for the graph

2:label the quadrants 1-4 from top right round to bottom right as 4

3:then apply x>0 (1,2) is top right and y<0 is bottom right (-1,-2)

Answer:

The percentage that of people who gave the movie a rating between 6.8 and 8.8

P(6.8≤X≤8.8)  = 83.9≅ 84 percentage

Step-by-step explanation:

Step(i):-

Mean of the Population = 8.3 points

Standard deviation of the Population = 0.5 points

Let 'X' be the random variable in normal distribution

Let X = 6.8

[tex]Z = \frac{x-mean}{S.D} = \frac{6.8-8.3}{0.5} = -3[/tex]

Let X = 8.8

[tex]Z = \frac{x-mean}{S.D} = \frac{8.8-8.3}{0.5} = 1[/tex]

The probability that of people who gave the movie a rating between 6.8 and 8.8

P(6.8≤X≤8.8) = P(-3≤Z≤1)

                     = P(Z≤1)- P(Z≤-3)

                    =  0.5 + A(1) - ( 0.5 -A(-3))

                   = A(1) + A(3)       (∵A(-3)=A(3)

                  =  0.3413 +0.4986    (∵ From Normal table)

                 = 0.8399

Conclusion:-

The percentage that of people who gave the movie a rating between 6.8 and 8.8

P(6.8≤X≤8.8)  = 83.9≅ 84 percentage

Answer:

-x^2 +2x +8

Step-by-step explanation:

f(x) = 2x + 1

g(x) = x^2 – 7,

(f – g)(x) = 2x +1 - ( x^2 -7)

Distribute the minus sign

             = 2x+1 - x^2 +7

Combine like terms

             = -x^2 +2x +8

Answer:

its not true. Answer is (f + g)(x) = x2 + 2x - 6

Step-by-step explanation:

Trust me. Good luck.

Answer:

Relative frequencies:

Headaches = 23.55 %

Hypertension = 8.68%

Upper respiratory tract infections =24.79%

Nasopharyngitis = 21.07

Diarrhea = 21.09%

None of these adverse reactions appear to be much more common than the others.

Step-by-step explanation:

Compute frequency:

The number of adverse reactions categories:

Headaches

Hypertension

Upper respiratory tract infections

Nasopharyngitis

Diarrhea

Frequency of each adverse reaction:

Adverse reaction                                Frequency        

Headaches                                                 57                    

Hypertension                                              21

Upper respiratory tract infections             60

Nasopharyngitis                                          51

Diarrhea                                                       53

Compute total frequency

Total frequency is compute dby taking sum of all frequencies;

Sum of frequencies = 57 + 21 + 60 + 51 + 53

                                 = 242

Compute relative frequency:

In order to find if any one of these adverse reactions appear to be much more common than the others, we have to compute relative frequency using these adverse reactions.

By calculating relative frequency we are looking at the number of times a specific adverse reaction appears to be more common, compared to the others.

To calculate relative frequency, divide the frequency of each adverse reaction by the total frequency i.e. 242.

Relative frequency for Headache = 57 / 242

                                                        = 0.2355

                                                        = 23.55 %

Relative frequency for Hypertension = 21 / 242

                                                             = 0.0868

                                                             = 8.68 %

Relative frequency for Upper respiratory tract infections = 60 / 242

                                                                                              = 0.2497

                                                                                              = 24.97 %

Relative frequency for Nasopharyngitis = 51 / 242

                                                                  = 0.2107

                                                                   = 21.07 %

Relative frequency for Diarrhea    = 53 / 242

                                                        = 0.2190

                                                         = 21.90 %

If you observe the relative frequencies of all the adverse reactions, none of them appear to be much more common than the others. Relative frequencies of headaches, upper respiratory tract infections, nasopharyngitis and diarrhea are almost equally common however, relative of hypertension appears to be very less than the other three.

Answer:

Step-by-step explanation:

The values ​​of the cosine function are represented by the axis OX of the goniometric circumference (circumference centered at the origin and of radius 1). Therefore the cosine is zero for the 90º and 270º angles.

Answer:

c

Step-by-step explanation:

Answer:

9000

Step-by-step explanation:

the inital ammout which is 9k is the size of the loan

-200 because he years 200 dollars per month

but the start up number is 9000 and he repays the load at 200 dollars a month

Answer:

49

Step-by-step explanation:

[tex]3x^2+5x-2 = 0[/tex]

Apply discriminant formula : [tex]D = b^2- 4ac[/tex]

[tex]D=discriminant\\b=5\\a=3\\c=-2[/tex]

[tex]D = b^2- 4ac[/tex]

Plug in the values for a, b, and c.

[tex]D = 5^2- 4(3)(-2)[/tex]

Evaluate.

[tex]D = 25- 12(-2)[/tex]

[tex]D = 25- - 24[/tex]

[tex]D=25+24[/tex]

[tex]D=49[/tex]

Answer:

49

Step-by-step explanation:

3x²+5x-2 = 0

This is in the form

ax^2 + bx + c=0

a=3  b=5  c = -2

The discriminant is

b^2 -4ac

5^2 -4(3) (-2)

25 + 24

49

The discriminant is 49

Answer:

rectangular prism

Step-by-step explanation:

check by rotating the shape in images

Answer:

The answer would be zero. This is due to the fact that the tangent is a line on a point around the circle. These two circles share no common tangents.

Step-by-step explanation:

The number of the common tangent to the concentric circles is zero. Option D is correct.

Two concentric circles are given in the figure, and common tangents to the circles are to be determined.

The circle is the locus of a point whose distance from a fixed point is constant i.e center ( h, k ). The equation of the circle is given by[tex](x-h)^2 + (y-k)^ = r^2[/tex]. where h, k is the coordinate of the center of the circle on the coordinate plane and r is the radius of the circle.

Since the line passes through the circumference of the circle is known as a tangent to the circle and the common tangent of the concentric circle is not possible because the tangent to the inner circle results secant to the outer circle.

Thus, the number of the common tangent to the circles is zero. Option D is correct.

Learn more about circle here:

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#SPJ5

Answer:

[tex]\boxed{x=7, \: x=-13}[/tex]

Step-by-step explanation:

[tex]|3x+9|= 30[/tex]

Solve for absolute value.

There are two possibilities.

One possibility:

[tex]3x+9=30\\3x=21\\x=7[/tex]

Second possibility:

[tex]3x+9=-30\\3x=-39\\x=-13[/tex]