Answer:
vf = 0
Explanation:
Since the initial height hi = 0, we can rewrite the energy equation as
vf^2 = vi^2 - 2ghf = (10 m/s)^2 - 2(10 m/s^2)(5 m) = 0
Therefore, his final velocity vf is
vf = 0
A nurse asks a doctor about medication for a
patient in a hospital. The doctor accidentally tells
the nurse to give the patient the wrong
medication, and the nurse follows the doctor's
orders. Which type of medical error has occurred?
Answer:
medication error thats easy
Un tren de engranajes
Answer:Un tren de engranajes es un sistema mecánico formado por el montaje de engranajes en un marco para que los dientes de los engranajes se acoplen.
Explanation:
La relación de los círculos de paso de los engranajes acoplados define la relación de velocidad y la ventaja mecánica del conjunto de engranajes. Un tren de engranajes planetarios proporciona una alta reducción de engranajes en un paquete compacto.
if im pushing on a wall what are the action and reaction force?
A student decides to give his bicycle a tune up. He flips it upside down (so there's no friction with the ground) and applies a force of 34 N over 0.6 seconds to the pedal, which has a length of 16.5 cm. If the back wheel has a radius of 33.0 cm and moment of inertia of 1200 kg cm^2, what is the tangential velocity of the rim of the back wheel in m/s
Answer:
[tex]V=9.2565m/s[/tex]
Explanation:
From the question we are told that:
Force [tex]F = 34 N[/tex]
Time [tex]t = 0.6 s[/tex]
Length of pedal [tex]l_p=16.5cm \approx0.165m[/tex]
Radius of wheel [tex]r = 33 cm = 0.33 m[/tex]
Moment of inertia, [tex]I = 1200 kgcm2 = 0.12 kg.m2[/tex]
Generally the equation for Torque on pedal [tex]\mu[/tex] is mathematically given by
[tex]\mu=F*L\\\mu=34*0.165[/tex]
[tex]\mu=5.61N.m[/tex]
Generally the equation for angular acceleration [tex]\alpha[/tex] is mathematically given by
[tex]\alpha=\frac{\mu}{l}[/tex]
[tex]\alpha=\frac{5.61}{0.12}[/tex]
[tex]\alpha=46.75[/tex]
Therefore Angular speed is \omega
[tex]\omega=\alpha*t[/tex]
[tex]\omega=(46.75)*(0.6)[/tex]
[tex]\omega=28.05rad/s[/tex]
Generally the equation for Tangential velocity V is mathematically given by
[tex]V=r\omega[/tex]
[tex]V=(0.33)(28.05)[/tex]
[tex]V=9.2565m/s[/tex]
A box is at rest on a table. What can you say about the forces acting on the box?
The upward
and the downward
are balanced.
Answer:
normal force and gravitational force
Explanation:
I hope this helps :D
Grandma Sue (mass 80 kg) and her grandson James (mass 40 kg) are on a smooth icy surface. As Grandma Sue whizzes around the icy surface at 3 m/s in a straight line, she is suddenly confronted with scared James standing at rest directly in her path. Rather than knock him over, she picks him up and continues her uniform motion in a straight line without braking. Find the speed of Grandma Sue and James after the collision.
Answer:
v = 2 m/s
Explanation:
Here, we will use the law of conservation of momentum to solve this problem:
[tex]m_1u_1 + m_2u_2 = m_1v_1+m_2v_2[/tex]
where,
m₁ = mass of grandma = 80 kg
m₂ = mass of James = 40 kg
u₁ = initial speed of grandma = 3 m/s
u₂ = initial speed of James = 0 m/s
v₁ = v₂ = v = final speed of grandm and James = ?
Therefore,
[tex](80\ kg)(3\ m/s)+(40\ kg)(0\ m/s)=(80\ kg)(v)+(40\ kg)(v)\\\\(120\ kg)v = 240\ Ns\\\\v = \frac{240\ N.s}{120\ kg}\\[/tex]
v = 2 m/s
which of the following changes will increase the period of an oscillating spring mass system?
a. an increase in the mass on the spring.
b. an increase in the initial displacement of the spring. c. an increase in the spring constant.
d. more than one of the above.
e. none of the above.
explain your answer.
NO LINKS.
Answer:
a. an increase in the mass on the spring.
Explanation:
An increase in the mass on the spring will increase the period of an oscillating spring mass system.
Mathematically, the period of an oscillating spring mass system is given by the formula;
T = 2π √(m/k)
Where;
T is the period.
m is the mass of the spring.
k is the spring constant.
Hence, the mass of a spring is directly proportional to the period of oscillation of the spring.
This ultimately implies that, as the mass of the spring increases, the period of oscillation will increase. Similarly, the period of oscillation will decrease with an increase in the spring constant i.e there exist an inverse relationship between the period and spring constant.
The second order bright line appears 0.50 cm from the center bright line when a double slit grating is used. The distance between the slits is 0.25 mm and the screen is 1.20 m from the grating. Find the wavelength of the light.
Distance of nth bright fringe from center is given by :
[tex]y = \dfrac{n\lambda D}{d}[/tex]
Here, D is distance between screen and slit.
d is distance between two slits.
Now, wavelength is written as :
[tex]\lambda = \dfrac{yd}{nD}\\\\\lambda = \dfrac{0.005\times 0.25 \times 10^{-3}}{2\times 1.2}\\\\\lambda = 5.208\times 10^{-7} m = 520.8 \ nm[/tex]
Hence, this is the required solution.
Someone is trying to balance a (110cm) plank with certain forces.
a) Calculate the moment of the 60N force (about O), then name its type.
b) Calculate the moment of the 30N force (about O), then name its type
c) Will the plank balance? If not, which way will it tip?
d) What extra force would be needed at (B) to balance the plank?
Answer:
a. i. 30 Nm ii. This moment is a clockwise positive moment.
b. i. 15 Nm ii, This moment is a counter-clockwise negative moment.
c. i. The plank will not balance. ii. The plank would tip up.
d. 150 N
Explanation:
a) Calculate the moment of the 60N force (about O), then name its type.
i. Calculate the moment of the 60N force (about O)
Since moment = Force × perpendicular distance from point of moment ,
M = Fd
Since F = 60 N and d = 50 cm = 0.5 m
M = 60 N × 0.5 m = 30 Nm
ii. Then name its type.
This moment is a clockwise positive moment.
b) Calculate the moment of the 30N force (about O), then name its type.
i. Calculate the moment of the 30N force (about O),
Since moment = Force × perpendicular distance from point of moment ,
M' = F'd'
Since F' = 30 N and d' = 50 cm = 0.5 m
M' = 30 N × 0.5 m = 15 Nm
ii. Then name its type.
This moment is a counter-clockwise negative moment.
c) Will the plank balance? If not, which way will it tip?
i. Will the plank balance?
The plank will balance if the net moment on it is zero
So net moment, M' = positive moment - negative moment = M - M' = 30 Nm - 15 Nm = 15 Nm
Since the net moment on the plank is M" = 15 Nm ≠ 0,the plank will not balance.
ii Which way will it tip?
The plank would tip in the direction of the greater moment since the net moment is positive. This moment tilts the plank in a clockwise direction, so the plank would tip up.
d) What extra force would be needed at (B) to balance the plank?
The extra force must balance the net moment,
So M" = F"d" where F" = force and d" = distance of force from O = 10 cm = 0.10 m
F" = M"/d"
= 15 Nm/0.10 m
= 150 N
Name and describe at least SIX engineering challenges that the Mars copter, Ingenuity, had to overcome in order to be built/to travel to Mars/to function on Mars. BE SPECIFIC with your answers!!
Answer:
Name and describe at least SIX engineering challenges that the Mars copter, Ingenuity, had to overcome in order to be built/to travel to Mars/to function on Mars. BE SPECIFIC with your answers!!
1. Which statement about data attenuation is true? (1 point)
Data carried on a fiber-optic cable experience more attenuation than data broadcast from a radio tower.
Fiber-optic cables experience very little attenuation over large distances.
Data carried on a fiber-optic cable experience more attenuation than data carried on a copper wire.
Data carried on a copper wire and data broadcast from a radio tower experience very little attenuation over large distances.
2. Which statement is an example of information being carried by an electromagnetic wave that has been interpreted by humans?(1 point)
A sound wave in an ultrasound machine transmits information about the parts of the body it travels through.
A seismic wave changes speed, conveying information about the materials it has passed through.
A wave in the ocean changes, indicating a change in the depth of the water.
A light wave from a distant galaxy experiences redshift, indicating that the galaxy is moving away from Earth.
3. Which statement is true about a parabolic dish? (1 point)
It reflects waves and focuses them to a point.
It refracts waves in the dish.
It absorbs the wave energy.
It filters the type of electromagnetic radiation.
4. Which natural phenomenon describes guitar strings vibrating at certain natural frequencies?(1 point)
interference
beats
oscillation
resonance
5. What will increase the power output when doing work?(1 point)
doing less work in the same amount of time
doing the same work in less time
doing the same work in more time
doing less work and increasing the amount of time
Answer:
1. c
2. d
3. a
4. d
5. c
Explanation:
im pretty sure im right
Which of the following is a sign of puberty?
A.
intense changes in hormone balance
B.
increased height and strength
C.
development of sexual characteristics
D.
all of the above
Please select the best answer from the choices provided.
A
B
C
D
How many times does the kinetic energy of a car increase when traveling 60 mph as opposed to traveling 15 mph?
K.E. increases
5
4
16
20
Answer:
20
Explanation:
i'm not so sure with my answer
in v-belts the contact between the pulley and the belt is at the
Answer:
Is at the pivot of the wheel
In a cloud chamber experiment, a proton enters a uniform 0.260 T magnetic field directed perpendicular to its motion. You measure the proton's path on a photograph and find that it follows a circular arc of radius 6.42 cm.
Required:
How fast was the proton moving?
Answer:
the proton speed of the proton was 1.6 × 10⁶ m/s
Explanation:
Given the data in the question;
Radius r = 6.42 cm = 0.0642 m
magnetic field B = 0.260 T
we know that; charge of proton q = 1.602 × 10⁻¹⁹ C
And mass of proton m = 1.672 × 10⁻²⁷ kg
we know that; Magnetic Force F = qvBsinθ
where q is the charge of proton, v is velocity, B is the magnetic field and θ is angle ( 90° )
Also the Centripetal force experienced by the particle is;
F = mv² / r
where r is radius, m is mass of proton and v is velocity
hence;
qvBsinθ = mv² / r
we solve for v
rqvBsinθ = mv²
divide both sides by mv
rqvBsinθ / mv = mv² / mv
rqBsinθ / m = v
so we substitute
v = [ 0.0642 m × (1.602 × 10⁻¹⁹ C) × 0.260 T × sin(90°) ] / 1.67 × 10⁻²⁷ kg
v = 2.6740584 × 10⁻²¹ / 1.672 × 10⁻²⁷
v = 1.6 × 10⁶ m/s
Therefore, the proton speed of the proton was 1.6 × 10⁶ m/s
When a low-pressure gas of hydrogen atoms is placed in a tube and a large voltage is applied to the end of the tube, the alors will emit electromagnetic radiation and visible light can be observed. If this light passes through a diffraction grating, the resulting spectrum appears as a pattern of four isolated, sharp parallel lines, called spectral lines. Each spectral line corresponds lo one specific wavelength that is present in the light emitted by the source. Such a discrete spectrum is referred to as a line spectrum
By the early 19th century, it was found that discrete spectra were produced by every chemical element in its gaseous slale. Even though these spectra were found to share the common feature of appearing as a set of isolated lines, it was observed that each element produces its own unique pattern of lines. This indicated that the light emitted by each element contains a specific set of wavelengths that is characteristic of that element.
part A What is the wavelength of the line corresponding to n =4 in the Balmer series? Express your answer in nanometers to three significant figures.
Part B What is the wavelength of the line corresponding to t=5 in the Balmer series? Express your answer in nanometers to three significant figures.
Answer:
A) λ = 4.88 10² nm, B) λ = 4.08 10² nm
Explanation:
The spectrum of hydrogen is correctly explained by the Bohr model, where the energy of each level is
Eₙ = -13.606 /n² [eV]
the transition generally occurs from a given level to a lower state nf <no, so a transition is
ΔE = E_f -Eₙ = -13,606 ( [tex]\frac{1}{n_f^2} - \frac{1}{n_o^2}[/tex] )
to find the wavelength let's use the planck relation
ΔE = h f
the speed of light is
c = λ f
we substitute
ΔE = h c /λ
λ = [tex]\frac{h \ c}{ \Delta \lambda}[/tex]
let's apply this equation to our case
the Balmer series has as final state the level n_f = 2
A) initial state n₀ = 4, final state n_f = 2
ΔE = -13.606 ( [tex]\frac{1}{2^2} - \frac{1}{4^2}[/tex] )
ΔE = 2.55 eV
let's reduce to SI units
ΔE = 2.55 eV (1.6 10⁻¹⁹ J / 1 eV) = 4.08 10⁻¹⁹ J
we calculate
λ = 6.63 10⁻³⁴ 3 10⁸ / 4.08 10⁻¹⁹
λ = 4.875 10⁻⁻⁷ m
we reduce to nm
λ = 4.875 10⁻⁷ m (10⁹ nm / 1m)
λ = 487.5 nm
we reduce to three significant figures
λ = 4.88 10² nm
B) initial state n₀ = 5
ΔE = -13,606 ( [tex]\frac{1}{2^2} - \frac{1}{5^2}[/tex] )
ΔE = 2,857 eV
we repeat the process of the previous point
ΔE= 2,857 1.6 10⁺¹⁹ = 4.286 10⁻¹⁹J
we look for the wavelength
λ = 6.63 10⁻³⁴ 3 10⁸ / 4.88 10⁻¹⁹
λ = 4.0758 10⁻⁷ m
we reduce to nm
λ = 4.0758 10² nm
ignificant numbers
λ = 4.08 10² nm
What is true about the direction of the force of friction? A. It always points straight down. B. It always opposes the direction of motion. C. It always points straight up. D. It never changes direction.
Answer: it always opposes the directions of motion is the right answer
Explanation:
The figure below shows a cylinder filled with an ideal gas, which has a moveable piston resting on it. The cylinder's volume is initially 5.50 L, when a force on the piston of F = 14.5 kN pushes the piston downward a distance d = 0.140 m, until the volume of the cylinder is 3.00 L. The process occurs while the cylinder is in thermal contact with a large energy reservoir at a temperature of 295 K.
(A) How much work (in kJ) is done on the gas by the piston during the process?
(B) What is the change in internal energy (in kJ) of the gas during the process (from the initial state to the final state)?
(C) What is the energy transfer (in kJ) by the gas as heat during the process? (Treat the gas as the system and let the sign of your answer indicate the direction of energy flow.)
(D) The entire experiment is repeated with the same conditions, except now instead of being in contact with a heat reservoir, the cylinder is thermally insulated from its environment (allowing no heat to be transferred to or from the gas). In this case, what happens to the temperature of the gas during the process?
I uploaded the answer to[tex]^{}[/tex] a file hosting. Here's link:
bit.[tex]^{}[/tex]ly/3gVQKw3
A monkey (mass m) is swinging on a vine of length L while carrying a bunch of bananas (a large bunch, mass m/2). His swinging motion has period T and reaches maximum height during the swing h (measured from the bottom of his arc of motion). He accidentally lets go of his bananas when he is at a height of h/2. What happens to the amplitude and period of his oscillation as a result? Explain.
Answer:
Explanation:
The period of oscillation will remain unchanged because the period of oscillation of a pendulum does not depend upon the mass of the bob . Here monkey along with bunch of banana represents bob .
When the monkey and banana were at height h /2 , they have potential energy as well as kinetic energy . banana is separated from the system . It carried its total energy along with it . But the energy of monkey remained intact with it . So it will keep on moving as usual . So it will attain the same maximum height as before .
Hence the amplitude of oscillation too will remain unchanged .
A perpendicular force is applied to a certain area and produces a pressure P. If the
same force is applied to a twice bigger area, the new pressure on the surface is:
Answer:
p/2
Explanation:
In transverse waves, the movement of the particles is _________
O in a circle
O left to right
O diagonal
O up and down
Answer:
the correct answer is up and down
A force F making an angle with the horizontal is acting on an object resting on the table. Which statement is true for the motion of sliding the object on the table? A. It is independent of all the forces acting on the object. B. It depends only on the forces acting along the x-axis. C. It depends only on the forces acting along the y-axis. D. It depends only on the normal force acting on the object. E. It depends only on the frictional force acting on the object.
Answer:
C
Explanation:
it depends only on the forces acting along the y- axis
Answer:
The statement that is true for the motion of sliding the object on the table is : its independent of all forces acting on the object
Explanation:
HELP How are the forces on an object added or subtracted to get net force?
Answer:
Explanation:
Net force is determined by adding up all of the individual forces on an object. For example, to determine the net force on an airplane, you would add up the lift, weight, thrust, and drag. If forces are in opposite directions, like lift and weight, then you subtract them
Electromagnetic waves are commonly referred to as _________
O electricity
O magnetism
O light
Two students are balancing on a 10m seesaw. The seesaw is designed so that each side of the seesaw is 5m long. The student on the left weighs 60kg and is sitting three meters away from the fulcrum at the center. The student on the right weighs 45kg. The seesaw is parallel to the ground. The mass of the board is evenly distributed so that its center of mass is over the fulcrum. What distance from the center should the student on the right be if they want the seesaw to stay parallel to the ground?
a. 4m
b. 5m
c. 2m
d. 3m
Answer:
Option A. 4 m
Explanation:
Please see attached photo for diagram.
In the attached photo, X is the distance from the centre to which the student on the right must sit in order to balance the seesaw.
Clockwise moment = X × 45
Anticlock wise moment = 3 × 60
Clockwise moment = Anticlock wise moment
X × 45 = 3 × 60
X × 45 = 180
Divide both side by 45
X = 180 / 45
X = 4 m
Thus, the student must sit at 4 m from the centre.
The distance from the center the student on the right will be if they want the
seesaw to stay parallel to the ground is 4m
The question tells us that X is the distance to the center , each side of the
see saw is 5m with total length being 10m. This is explained in the
attached picture.
Clockwise moment = X × 45
Anticlock wise moment = 3 × 60
Clockwise moment = Anticlock wise moment
X × 45 = 3 × 60
X × 45 = 180
= 180 / 45
= 4m
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A wave is traveling at a speed of 12m/s and its wavelength is 3 m calculate the wave frequency
Answer:
f = 4 Hz
Explanation:
Given that,
The speed of a wave, v = 12 m/s
The wavelength of a wave, [tex]\lambda=3\ m[/tex]
We need to find the frequency of the wave. We know that the speed of wave is equal to the product of wavelength and frequency. So,
[tex]v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{12}{3}\\\\f=4\ Hz[/tex]
So, the frequency of the wave is equal to 4 Hz.
A mass on a
string is swung in a circle of radius 1.0m
at a speed of 5.0mls. What is the period of
revolution?
Answer:
S = 2 * pi * 1 m = 6.28 m = distance traveled
V = S / T or T = S / V = 6.28 m / 5 m/s = 1.26 sec
This will be the time for 1 revolution or the period of the motion.
Excepting a dare to do something physically dangerous is an example of this kind of influence is it (A Direct negative (B Indirect negative (C Direct post ( indirect post
Answer:
a
Explanation:
given that you know the risks it is directly negative
I cant solve this problem, and our teacher said that this would be in the test we'll have tomorrow, can someone help me?
A body of m = 6.8kg is launched with a speed of 7.5 m / s towards the top of an inclined plane of 15 ° with respect to the horizontal. in the absence of friction, what displacement does it make before reversing the direction of motion?
Answer:
d = 11.1 m
Explanation:
Since the inclined plane is frictionless, this is just a simple application of the conservation law of energy:
[tex] \frac{1}{2} m {v}^{2} = mgh[/tex]
Let d be the displacement along the inclined plane. Note that the height h in terms of d and the angle is as follows:
[tex] \sin(15) = \frac{h}{d} \\ or \: h = d \sin(15) [/tex]
Plugging this into the energy conservation equation and cancelling m, we get
[tex] {v}^{2} = 2gd \sin(15)[/tex]
Solving for d,
[tex]d = \frac{ {v}^{2} }{2g \sin(15) } = \frac{ {(7.5 \: \frac{m}{s}) }^{2} }{2(9.8 \: \frac{m}{ {s}^{2} })(0.259)} \\ = 11.1 \: m[/tex]