find the exact value of tan30⁰ × cos30⁰
give your answer in its simplest form​

Answer:

parabola

Step-by-step explanation:

Answer:

x = 8

Step-by-step explanation:

Central angle = measure of intercepted arc

Central angle = 47°

Arc measure = 7 + 5x

Therefore:

7 + 5x = 47

Subtract 7 form both sides

5x = 47 - 7

5x = 40

Divide both sides by 5

x = 40/5

x = 8

Answer:

I'm not sure if this is a real problem and I don't think it is but the answer is 6.5

Step-by-step explanation:

first you have to add -2 and 2, then plus 3 and 2 and subtract 2 from it and then and 2+4 and subtract -5 and divide 2 and add 3 and add the answer to al of that to 2 + 3 and subtract - 10 and you get your answer of 6.5

I think it is A)2 because 3^2 = 9 and 9×4 = 36

Answer:

the answer is B (graph a and c)

just did the test on edg 21

Step-by-step explanation:

i hope this helps!! have an amazing day <3

If a graph is reflected across y = x then it will be an inverse graph so graphs B and C will be inverse.

The inverse of a function is basically a reverse function or undo of the function.

For example y = f(x) then inverse will be x = f(y).

It means in the inverse function we need to interchange x and y.

Another example y = 3x² ⇒ x = √(y/3) will be the inverse.

An inverse function is a reflection of graph across y = x and due to that coordinate will interchange its that ;

( x ,y ) → ( y , x )

Since graph A is rotated about the x-axis to make graph B

Now,

Graph A is rotated( which is B ) and reflected across the axis y = x to form Graph C.

So B and C will be the inverse of each other.

Hence "If a graph is reflected across y = x then it will be an inverse graph so graphs B and C will be inverse".

For more information about the inverse of a function,

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The given question is incomplete complete question is ;

Which graphs are inverses of one another? Graph A and B Graph A and C Graph B and C none of the graphs shown On a coordinate plane, graph A is in quadrants 1, 2, and 3. Graph A is rotated across the x-axis to form graph B. Graph A is rotated and reflected across the axis y = x  to form Graph C.

Answer:

y=-3x-13

Step-by-step explanation:

Answer:

1 .  

Step-by-step explanation:        

Answer:

El lado del cuadrado es de 20 my el área del cuadrado es de 400 metros cuadrados. Paso a paso ... El perímetro de un cuadrado es 80 m. ¿Cuál es la longitud de cada lado del cuadrado ... Para celosía & lt; L, * & gt; si a, b, ce L thena + (a e b) = a se llama.

Step-by-step explanation:

Answer:

r1 and r2 are the radii of two concentric circles

To find:

The length of the chord of the larger circle.

Solution:

We have given the two concentric circles which means both the circles have the same centre.

The chord of the larger circle toches the inner circle so the chord of the larger circle will be the tangent of the smaller circle.

And we know that the radius of the circle is perpendicular to the tangent of the circle.

Let 2x be the length of the chord of the circle.

r1 is the radius of the larger circle.

r2 is the radius of the smaller circle.

So by the Pythagoras theorem,

The length of the half of the chord is given by:

r1² = x² + r2²

x² = r1² - r2²

x = √r1² - r2²

So,

The length of the chord will be 2x = 2√r1² - r2² units

Step-by-step explanation:

Answer:

The answer is 6

Step-by-step explanation:

[tex]\lim_{x \to 4} \frac{x^3 - 64}{x^2 - 16} \\\\= \lim_{x \to 4} \frac{x^3 - 64}{(x + 4)(x - 4)} \\\\=\lim_{x \to 4} \frac{(x^2 + 4x + 16)(x - 4)}{(x + 4)(x - 4)} \\\\= \lim_{x \to 4} \frac{(x^2 + 4x + 16)}{(x + 4)} \\\\= (16 + 16 + 16) / 8\\= 48 / 8\\= 6[/tex]

Answer:

You know that 5 g of sugar form 12%. Let x g be the amount of water needed. The total amount of syrup will be x+5 g. Then

5 g - 12%,

x+5 g - 100%.

mathematically you can write a proportion;

5/x+5=12/100

=>500=12(x+5)

,500=12x+60

,12x=400,

x=440/12

=110/3

36.66 grams of water is added  to make 12% sugar syrup using 5g sugar.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

Let the amount of water is added be 'x'.

Amount of sugar = 5 g

We need to make 12% of sugar syrup.

x grams of water is added to 5 g of sugar, to 12% of sugar syrup.

5/5+x=12/100

Apply cross multiplication

5×100=12(5+x)

500=60+12x

Subtract 60 from both sides

440=12x

Divide both sides by 12

x=36.66

Hence, 36.66 grams of water is added  to make 12% sugar syrup using 5g sugar.

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Answer:

Your answer would be B. 3.2m and -m/5

Step-by-step explanation:

I did the test on edge and I got it right

Answer:

The person above is correct!

Step-by-step explanation:

Answer:

340

Step-by-step explanation:

Answer: 12≠6

False

Step-by-step explanation:

Answer:

x [tex]\geq[/tex] 5

Step-by-step explanation:

step 1: subtract 6 from both sides

step 2: divide both sides by 7

answer: x [tex]\geq[/tex] 5

interval notation: [5,∞)

Answer:

I think it's D

Step-by-step explanation:

Answer:

i think it's a or d

but d is more have percent

Answer:

The equation is y = (2/3)x + (4/3).

Step-by-step explanation:

First, you have to change the equation into slope-intecept formula to find its gradient (slope) :

[tex]3x + 2y = 12[/tex]

[tex]2y = - 3x + 12[/tex]

[tex]y = - \frac{3}{2}x + 6[/tex]

Given that when a line is perpendicular to the other line, their slope value multiplied, will form -1. Next, we have to find the slope for line :

[tex]m1 \times m2 = - 1[/tex]

[tex] - \frac{3}{2} \times m2 = - 1[/tex]

[tex]m2 = - 1 \div - \frac{3}{2} [/tex]

[tex]m2 = \frac{2}{3} [/tex]

Lastly, we have to subatitute the x and y values into the equation, to find its intercept value :

[tex]y = \frac{2}{3}x + b[/tex]

[tex]let \: x = 1,y = 2[/tex]

[tex]2 = \frac{2}{3} (1) + b[/tex]

[tex]b = 2 - \frac{2}{3} [/tex]

[tex]b = \frac{4}{3} [/tex]

[tex]y = \frac{2}{3} x + \frac{4}{3} [/tex]

Answer:

4 1/3(b-21) im pretty sure

Answer:

1 equals two of 1/2 which means you get the equation 1/3 x 2 for the answer

Answer:

a) x ≤ -8

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

-3 + x ≤ -11

Step 2: Solve for x

Here we see that any value x smaller than or equal to -8 would work as a solution to the inequality.

Answer:

Where's the cone at and I might be able to help

Step-by-step explanation:

Answer: Please put a picture of the cone underneath the question!

Step-by-step explanation:

Step-by-step explanation:

[tex] \underline{ \underline{ \text{Given}}} : [/tex]

[tex] \underline{ \underline{ \text{To \: find}}} : [/tex]

[tex] \underline{ \underline{ \text{Solution}}} : [/tex]

~ Plug the value of x and then multiply !

⇾ [tex] \tt{6x = 6 \times 6 \times = \boxed{36}}[/tex]

[tex] \red{ \boxed{ \boxed{ \text{Our \: final \: answer : \boxed{ \tt{36}}}}}}[/tex]

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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Answer:

60 divided by 8

Step-by-step explanation:

60 divided by 8

Answer:

(d+5)^2

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Because the the contract will be in verbal form. no matter if it is videotaped or recorded or both a "videoed verbal contract" not just written. so like paper thst is notarized or not this is still the same bc the the same rules apply the contract is still valid. the rest of the options are more like what they call gentlemens agreements which would be the handshake type of thing. and no matter what any agreement someone has to witness the transaction or contract. so definitely the answer is B

Given:

Score in first round = 5 points

Score in second, third and fourth rounds was identical.

A participant has to score a total of at least 30 points in the first four rounds combined to move on to the fifth and final round.

To find:

The inequality for the given problem.

Solution:

Let p be the number of points, p, that Steward scored in each of the second, third, and fourth rounds.

Score in first 4 rounds = Score of 1st round + Score of 2nd round + Score of  1s 3rd round + Score of 4th round

Score in first 4 rounds [tex]=5 + p + p + p[/tex]

                                     [tex]=5 +3p[/tex]

A participant has to score a total of at least 30 points in the first four rounds combined to move on to the fifth and final round. It means the total score in first 4 rounds must be greater than or equal to 30.

[tex]5+3p\geq 30[/tex]

Therefore, the correct option is A.

Answer:

A

Step-by-step explanation:

Answer:

[tex](-2-2\sqrt{2},3+2\sqrt{2})\,,\,(-2+2\sqrt{2},3-2\sqrt{2})[/tex]

Step-by-step explanation:

Given:

[tex](x+2)^2+(y-3)^2=16\\x+y-1=0[/tex]

To find: value of [tex]x,y[/tex]

Solution:

[tex](x+2)^2+(y-3)^2=16\,\,\,...(i)\\x+y-1=0\,\,\,(ii)[/tex]

From (ii),

[tex]x=1-y[/tex]

Put this value of [tex]x[/tex] in (i)

[tex](1-y+2)^2+(y-3)^2=16\\(3-y)^2+(y-3)^2=16\\(y-3)^2+(y-3)^2=16\\2(y-3)^2=16\\(y-3)^2=8[/tex]

[tex]y-3=[/tex] ± [tex]\sqrt{8}[/tex] = ± [tex]2\sqrt{2}[/tex]

[tex]y=3[/tex] ± [tex]2\sqrt{2}[/tex]

At [tex]y=3[/tex] + [tex]2\sqrt{2}[/tex] ,

[tex]x=1-(3+2\sqrt{2})=1-3-2\sqrt{2}=-2-2\sqrt{2}[/tex]

At [tex]y=3-2\sqrt{2}[/tex] ,

[tex]x=1-(3-2\sqrt{2})=1-3+2\sqrt{2}=-2+2\sqrt{2}[/tex]

Solutions are [tex](-2-2\sqrt{2},3+2\sqrt{2})\,,\,(-2+2\sqrt{2},3-2\sqrt{2})[/tex]

Answer:

a. Negation of ∃x ∀y(P(x,y) → Q(x,y)) = ∀x  ∃y P(x,y)  ∧ ¬Q(x,y) ]

b. Negation of ∃x ∀y(P(x,y) → P(y,x)) = ∀x ∃y  [ ¬P(x,y) ∨ ¬P(y,x) ] ∧ [P(x,y) ∨ P(y,x)]

c. Negation of ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y) = ∀x ∀y ¬ [P(x,y)]  ∨ ∃x ∃y ¬ [Q(x,y)]

Step-by-step explanation:

a.∃x ∀y(P(x,y) → Q(x,y))

Negation = ¬ [ ∃x ∀y(P(x,y) → Q(x,y)) ]

                = ∀x  ¬ [ ∀y(P(x,y) → Q(x,y)) ]

                = ∀x  ∃y ¬ [ (P(x,y) → Q(x,y)) ]

                = ∀x  ∃y ¬ [  ¬P(x,y)  ∨ Q(x,y) ]

                = ∀x  ∃y P(x,y)  ∧ ¬Q(x,y) ]

Negation of ∃x ∀y(P(x,y) → Q(x,y)) = ∀x  ∃y P(x,y)  ∧ ¬Q(x,y) ]

b. ∃x ∀y(P(x,y) → P(y,x))

Negation = ¬ [ ∃x ∀y(P(x,y) → P(y,x)) ]

               = ∀x ¬ [ ∀y(P(x,y) → P(y,x)) ]

               = ∀x ∃y ¬ [ (P(x,y) → P(y,x)) ]

               = ∀x ∃y ¬ [ ( P(x,y) ∧ P(y,x) ) ∨ ( ¬P(x,y) ∧ ¬P(y,x) )]

               = ∀x ∃y ¬ [ P(x,y) ∧ P(y,x) ] ∧ ¬[ ¬P(x,y) ∧ ¬P(y,x) ]

               = ∀x ∃y  [ ¬P(x,y) ∨ ¬P(y,x) ] ∧ [ P(x,y) ∨ P(y,x) ]

∴ we get

Negation of ∃x ∀y(P(x,y) → P(y,x)) = ∀x ∃y  [ ¬P(x,y) ∨ ¬P(y,x) ] ∧ [P(x,y) ∨ P(y,x)]

c. ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y)

Negation = ¬ [ ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y) ]

                = ¬ [ ∃x ∃y P(x,y) ]  ∨ ¬ [ ∀x ∀y Q(x,y) ]

                = ∀x¬ [  ∃y P(x,y) ]  ∨ ∃x ¬ [ ∀y Q(x,y) ]

                = ∀x ∀y ¬ [ P(x,y) ]  ∨ ∃x ∃y ¬ [ Q(x,y) ]

∴ we get

Negation of ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y) = ∀x ∀y ¬ [ P(x,y) ]  ∨ ∃x ∃y ¬ [ Q(x,y) ]

Answer:

Perpendicular