Find the equation of the regression line that relates the variable you chose in question 3 (use this variable as the x-value) to the total weight of discarded garbage (use this variable as the y-value). Write your equation in y = mx + b form, and round your values of m and b to two decimal places.

Answers

Answer 1

Answer:

See Explanation

Step-by-step explanation:

The question has missing details as no link is provided to the "question 3".

However, I'll give a worked solution on how to calculate the equation of a regression line.

Using the following data:

[tex]\begin{array}{cc}x & {y} & {43} & {99} & {21} & {65} \ \\ {25} & {79} & {42} & {75} \ \end{array}[/tex]

Calculate the equation of the regression line.

The equation is calculated using:

[tex]y = mx + b[/tex]

Where:

[tex]m = \frac{n(\sum xy ) - (\sum x)(\sum y)}{n(\sum x^2) - (\sum x)^2}[/tex]

and

[tex]b = \frac{(\sum y)(\sum x^2) - (\sum x)(\sum xy)}{n(\sum x^2) - (\sum x)^2}[/tex]

So, first we fill in the table with columns x^2, y^2 and xy

[tex]\begin{array}{ccccc}x & {y} & {xy} & {x^2} & {y^2 }& {43} & {99} & {4257} & {1849} & {9801} & {21} & {65} &{1365} &{441} & {4225}\ \\ {25} & {79} & {1975} & {625} & {6241}& {42} & {75} &{3150} & {1764} & {5625}\ \end{array}[/tex]

From the above table.

[tex]\sum x = 43+21+25+42[/tex]

[tex]\sum x = 131[/tex]

[tex]\sum y = 99+65+79+75[/tex]

[tex]\sum y = 318[/tex]

[tex]\sum xy = 4257+1365+1975+3150[/tex]

[tex]\sum xy = 10747[/tex]

[tex]\sum x^2 = 1849 + 441 + 625 + 1764[/tex]

[tex]\sum x^2 = 4679[/tex]

[tex]\sum y^2 = 9801 + 4225 + 6241 + 5625[/tex]

[tex]\sum y^2 = 25892[/tex]

[tex]n =4[/tex]

Solving for m

[tex]m = \frac{n(\sum xy ) - (\sum x)(\sum y)}{n(\sum x^2) - (\sum x)^2}[/tex]

[tex]m = \frac{4 * 10747 - 131*318}{4*4679 -(131)^2}[/tex]

[tex]m = \frac{1330}{1555}[/tex]

[tex]m = 0.86[/tex] --- approximated

Solving for b

[tex]b = \frac{(\sum y)(\sum x^2) - (\sum x)(\sum xy)}{n(\sum x^2) - (\sum x)^2}[/tex]

[tex]b = \frac{318*4679 - 131*10747}{4*4679-131^2}[/tex]

[tex]b = \frac{80065}{1555}[/tex]

[tex]b = 51.49[/tex]

The equation becomes:

[tex]y = mx + b[/tex]

[tex]y = 0.86x + 51.49[/tex]

Apply the above steps and you will arrive at a solution.


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