Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 39 in. by 21 in. by cutting congruent squares from the corners and folding up the sides. Then find the volume.

Answers

Answer 1

Answer:

Length=29.8 inches

Width=11.8 inches

Height=4.6 inches

Volume=1,617.54 cubic inches

Step-by-step explanation:

Let the side of congruent square cut =x inches

So the length of the rectangular box=(39-2x)

width = (21-2x)

height = x

The volume V=Length*Width*Height

= (39-2x)*(21-2x)*x

dV/dx= (39-2x)(21-4x)-2x(17-2x)=0

Simplify the equation above

819-156x-42x+8x^2-34x+4x^2=0

We have,

12x^2 -232 +819=0

Solve the quadratic equation using formula

a=12

b= -232

c=819

x= -b +or- √b^2-4ac/2a

= -(-232) +- √(-232)^2 - (4)(12)(819) / (2)(12)

= 232 +or- √53824 - 39312 / 24

= 232 +or- √14512 / 24

= 232 +or- 4√907 / 24

x= 232 / 24 + 4√907 / 24

=14.6861

Or

x=232 / 24 - 4√907 / 24

=4.64726

x=4.6 inches

Length=(39-2x)

={39-2(4.6)}

= 29.8 inches

Width=(21-2x)

={21-2(4.6)}

= 11.8 inches

Height=x= 4.6 inches

Volume=(39-2x)*(21-2x)*x

={39-2(4.6)}*{21-2(4.6)*4.6

=(39-9.2)*(21-9.2)*4.6

=29.8*11.8*4.6

=1,617.544

Approximately 1,617.54

Volume=1,617.54 cubic inches


Related Questions

The weights of steers in a herd are distributed normally. The standard deviation is 300lbs and the mean steer weight is 1100lbs. Find the probability that the weight of a randomly selected steer is between 920 and 1730lbs round to four decimal places.

Answers

Answer:

The probability that the weight of a randomly selected steer is between 920 and 1730 lbs

P(920≤ x≤1730) = 0.7078

Step-by-step explanation:

Step(i):-

Given mean of the Population = 1100 lbs

Standard deviation of the Population = 300 lbs

Let 'X' be the random variable in Normal distribution

Let x₁ = 920

[tex]Z = \frac{x-mean}{S.D} = \frac{920-1100}{300} = - 0.6[/tex]

Let x₂ = 1730

[tex]Z = \frac{x-mean}{S.D} = \frac{1730-1100}{300} = 2.1[/tex]

Step(ii)

The probability that the weight of a randomly selected steer is between 920 and 1730 lbs

P(x₁≤ x≤x₂) = P(Z₁≤ Z≤ Z₂)

                  = P(-0.6 ≤Z≤2.1)

                  = P(Z≤2.1) - P(Z≤-0.6)

                 = 0.5 + A(2.1) - (0.5 - A(-0.6)

                 =  A(2.1) +A(0.6)               (∵A(-0.6) = A(0.6)

                 =  0.4821 + 0.2257

                 = 0.7078

Conclusion:-

The probability that the weight of a randomly selected steer is between 920 and 1730 lbs

            P(920≤ x≤1730) = 0.7078

Answer:

0.7975

Step-by-step explanation:

pls help me pls pls​

Answers

Answer:

B

Step-by-step explanation:

the slope of parallel lines are equal

Quadrilateral DEFG is rotated 180° about the origin to create quadrilateral D'E'F'G'. In which quadrant does G' lie? A. I B. II C. III D. IV

Answers

Answer:

  B. II

Step-by-step explanation:

G is in quadrant IV. The quadrant that is across the origin from that is quadrant II.

  G' will lie in quadrant II

Answer:

B. 11

Step-by-step explanation:

Suppose that you collect data for 15 samples of 30 units each, and find that on average, 2.5 percent of the products are defective. What are the UCL and LCL for this process? (Leave no cells blank - be certain to enter "0" wherever required. Do not round intermediate calculations. Round up negative LCL values to zero. Round your answers to 3 decimal places.)

Answers

Answer:

The  UCL  is  [tex]UCL = 0.054[/tex]

The LCL  is  [tex]LCL \approx 0[/tex]

Step-by-step explanation:

From the question we are told that  

     The quantity of each sample is  n =  30

     The  average of defective products is  [tex]p = 0.025[/tex]

Now  the upper control limit [UCL] is  mathematically represented as

       

      [tex]UCL = p + 3 \sqrt{\frac{p(1-p)}{n} }[/tex]

substituting values  

      [tex]UCL = 0.025 + 3 \sqrt{\frac{0.025 (1-0.025)}{30} }[/tex]

      [tex]UCL = 0.054[/tex]

The  upper control limit (LCL) is mathematically represented as

       [tex]LCL = p - 3 \sqrt{\frac{p(1-p)}{n} }[/tex]

substituting values  

      [tex]LCL = 0.025 - 3 \sqrt{\frac{0.025 (1-0.025)}{30} }[/tex]

       [tex]LCL = -0.004[/tex]

        [tex]LCL \approx 0[/tex]

       

The head of maintenance at XYZ Rent-A-Car believes that the mean number of miles between services is 3639 3639 miles, with a variance of 145,161 145,161 . If he is correct, what is the probability that the mean of a sample of 41 41 cars would differ from the population mean by less than 126 126 miles

Answers

Answer:

96.6% probability that the mean of a sample would differ from the population mean by less than 126 miles

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

A reminder is that the standard deviation is the square root of the variance.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

[tex]\mu = 3639, \sigma = \sqrt{145161} = 381, n = 41, s = \frac{381}{\sqrt{41}} = 59.5[/tex]

Probability that the mean of the sample would differ from the population mean by less than 126 miles

This is the pvalue of Z when X = 3639 + 126 = 3765 subtracted by the pvalue of Z when X = 3639 - 126 = 3513. So

X = 3765

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{3765 - 3639}{59.5}[/tex]

[tex]Z = 2.12[/tex]

[tex]Z = 2.12[/tex] has a pvalue of 0.983

X = 3513

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{3513 - 3639}{59.5}[/tex]

[tex]Z = -2.12[/tex]

[tex]Z = -2.12[/tex] has a pvalue of 0.017

0.983 - 0.017 = 0.966

96.6% probability that the mean of a sample would differ from the population mean by less than 126 miles

A car is traveling on Michigan Street towards Ward Street. The car planes to turn right into Ward Street. what is the angle measure of the turn.


Pls help ASAP

Answers

Answer : the angle is 105 degree
Explanation:
Since 75+x = 180 (a straight line)

Then x = 180-75=105

evaluate -x+4 when x = -2

Answers

Answer:

6

Step-by-step explanation:

f(x)=-x+4

f(-2)=-(-2)+4

f(-2)=+2+4

f(-2)=6

Answer:

6

Step-by-step explanation:

-(-2)+4=___

+(+2)+4=6

Find a parabola with equation y = ax2 + bx + c that has slope 5 at x = 1, slope −11 at x = −1, and passes through the point (2, 18).

Answers

By "slope" I assume you mean slope of the tangent line to the parabola.

For any given value of x, the slope of the tangent to the parabola is equal to the derivative of y :

[tex]y=ax^2+bx+c\implies y'=2ax+b[/tex]

The slope at x = 1 is 5:

[tex]2a+b=5[/tex]

The slope at x = -1 is -11:

[tex]-2a+b=-11[/tex]

We can already solve for a and b :

[tex]\begin{cases}2a+b=5\\-2a+b=-11\end{cases}\implies 2b=-6\implies b=-3[/tex]

[tex]2a-3=5\implies 2a=8\implies a=4[/tex]

Finally, the parabola passes through the point (2, 18); that is, the quadratic takes on a value of 18 when x = 2:

[tex]4a+2b+c=18\implies2(2a+b)+c=10+c=18\implies c=8[/tex]

So the parabola has equation

[tex]\boxed{y=4x^2-3x+8}[/tex]

Using function concepts, it is found that the parabola is: [tex]y = 4x^2 - 3x + 14[/tex]

----------------------------

The parabola is given by:

[tex]y = ax^2 + bx + c[/tex]

----------------------------

Slope 5 at x = 1 means that [tex]y^{\prime}(1) = 5[/tex], thus:

[tex]y^{\prime}(x) = 2ax + b[/tex]

[tex]y^{\prime}(1) = 2a + b[/tex]

[tex]2a + b = 5[/tex]

----------------------------

Slope -11 at x = -1 means that [tex]y^{\prime}(-1) = -11[/tex], thus:

[tex]-2a + b = -11[/tex]

Adding the two equations:

[tex]2a - 2a + b + b = 5 - 11[/tex]

[tex]2b = -6[/tex]

[tex]b = -\frac{6}{2}[/tex]

[tex]b = -3[/tex]

And

[tex]2a - 3 = 5[/tex]

[tex]2a = 8[/tex]

[tex]a = \frac{8}{2}[/tex]

[tex]a = 4[/tex]

Thus, the parabola is:

[tex]y = 4x^2 - 3x + c[/tex]

----------------------------

It passes through the point (2, 18), which meas that when [tex]x = 2, y = 18[/tex], and we use it to find c.

[tex]y = 4x^2 - 3x + c[/tex]

[tex]18 = 4(2)^2 - 3(4) + c[/tex]

[tex]c + 4 = 18[/tex]

[tex]c = 14[/tex]

Thus:

[tex]y = 4x^2 - 3x + 14[/tex]

A similar problem is given at https://brainly.com/question/22426360

Quadrilateral W X Y Z is shown. Diagonals are drawn from point W to point Y and from point Z to point X and intersect at point C. The lengths of W C and C Y are congruent. Which best explains if quadrilateral WXYZ can be a parallelogram? WXYZ is a parallelogram because diagonal XZ is bisected. WXYZ is not necessarily a parallelogram because it is unknown if CZ = CY. WXYZ is a parallelogram because ZC + CX = ZX. WXYZ is not necessarily a parallelogram because it is unknown if WC = CY.

Answers

Answer: The answer is D

Step-by-step explanation:

Edge 2021

The true statement is (d) WXYZ is not necessarily a parallelogram because it is unknown if WC = CY.

What are quadrilaterals?

Quadrilaterals are shapes with four sides

What are parallelograms?

Parallelograms are quadrilaterals that have equal and parallel opposite sides

The quadrilateral is given as:

WXYZ

Also, we have:

WC = CY

The given parameters are not enough to determine if the quadrilateral is a parallelogram or not

Hence, the true statement is (d) WXYZ is not necessarily a parallelogram because it is unknown if WC = CY.

Read more about quadrilaterals and parallelograms at:

https://brainly.com/question/1190071

A heavy rope, 30 ft long, weighs 0.4 lb/ft and hangs over the edge of a building 80 ft high. Approximate the required work by a Riemann sum, then express the work as an integral and evaluate it.How much work W is done in pulling half the rope to the top of the building

Answers

Answer:

180 fb*lb

45 ft*lb

Step-by-step explanation:

We have that the work is equal to:

W = F * d

but when the force is constant and in this case, it is changing.

 therefore it would be:

[tex]W = \int\limits^b_ a {F(x)} \, dx[/tex]

Where a = 0 and b = 30.

F (x) = 0.4 * x

Therefore, we replace and we would be left with:

[tex]W = \int\limits^b_a {0.4*x} \, dx[/tex]

We integrate and we have:

W = 0.4 / 2 * x ^ 2

W = 0.2 * (x ^ 2) from 0 to 30, we replace:

W = 0.2 * (30 ^ 2) - 0.2 * (0 ^ 2)

W = 180 ft * lb

Now in the second part it is the same, but the integral would be from 0 to 15.

we replace:

W = 0.2 * (15 ^ 2) - 0.2 * (0 ^ 2)

W = 45 ft * lb

Following are the calculation to the given value:

Given:

[tex]length= 30 \ ft\\\\mass= 0.4 \ \frac{lb}{ft}\\\\edge= 80 \ ft \\\\[/tex]

To find:

work=?

Solution:

Using formula:

[tex]\to W=fd[/tex]

[tex]\to W=\int^{30}_{0} 0.4 \ x\ dx\\\\[/tex]

[tex]= [0.4 \ \frac{x^2}{2}]^{30}_{0} \\\\= [\frac{4}{10} \times \frac{x^2}{2}]^{30}_{0} \\\\= [\frac{2}{10} \times x^2]^{30}_{0} \\\\= [\frac{1}{5} \times x^2]^{30}_{0} \\\\= [\frac{x^2}{5}]^{30}_{0} \\\\= [\frac{30^2}{5}- 0] \\\\= [\frac{900}{5}] \\\\=180[/tex]

Therefore, the final answer is "[tex]180\ \frac{ lb}{ft}[/tex]".

Learn more:

brainly.com/question/15333493

Find all solutions to the equation.

7 sin2x - 14 sin x + 2 = -5

If yall can help me for Pre-Calc, that would be great.
-Thanks.

Answers

If the equation is

[tex]7\sin^2x-14\sin x+2=-5[/tex]

then rewrite the equation as

[tex]7\sin^2x-14\sin x+7=0[/tex]

Divide boths sides by 7:

[tex]\sin^2x-2\sin x+1=0[/tex]

Since [tex]x^2-2x+1=(x-1)^2[/tex], we can factorize this as

[tex](\sin x-1)^2=0[/tex]

Now solve for x :

[tex]\sin x-1=0[/tex]

[tex]\sin x=1[/tex]

[tex]\implies\boxed{x=\dfrac\pi2+2n\pi}[/tex]

where n is any integer.

If you meant sin(2x) instead, I'm not sure there's a simple way to get a solution...

The surface area of an open-top box with length L, width W, and height H can be found using the
formula:
A = 2LH + 2WH + LW
Find the surface area of an open-top box with length 9 cm, width 6 cm, and height 4 cm.

Answers

Answer:

174 square cm

Step-by-step explanation:

2(9×4) + 2(6×4)+ 9×6

2(36) + 2(24) + 54

72 + 48 + 54

120 + 54

174

Which equation should be used to find the volume of the figure?

V=1/3(10)(6)(12)
V=1/2(10)(6)(12)
V=1/3(10)(6)(13)
V=1/2(10)(6)(13)

Answers

Answer:

The answer is option 1.

Step-by-step explanation:

Given that the volume of pyramid formula is:

[tex]v = \frac{1}{3} \times base \: area \times height[/tex]

The base area for this pyramid:

[tex]base \: area = area \: of \: rectangle[/tex]

[tex]base \: area = 10 \times 6[/tex]

Then you have to substitute the following values into the formula:

[tex]let \: base \: area = 10 \times 6 \\ let \: height = 12[/tex]

[tex]v = \frac{1}{3} \times 10 \times 6 \times 12[/tex]

Answer:

A. V = 1/3 (10)(6)(12)

Step-by-step explanation:

Just took the test and got it right

In a competition, two people will be selected from four finalists to receive the first and second prizes. The prize winners will be selected by drawing names from a hat. The names of the four finalists are Jim, George, Helen, and Maggie. The possible outcomes can be represented as follows: JG JH JM GJ GH GM HJ HG HM MJ MG MH Here, for example, JG represents the outcome that Jim receives the first prize and George receives the second prize. The event A is defined as follows: A = event that Helen gets first prize List the outcomes that comprise the event ~A (not A).

Answers

Answer:

1. JG (Jim gets first prize, George gets second prize)

2. JH (Jim gets first prize, Helen gets second prize)

3. JM (Jim gets first prize, Maggie gets second prize)

4. GH (George gets first prize, Helen gets second prize)

5. GJ (George gets first prize, Jim gets second prize)

6. GM (George gets first prize, Maggie gets second prize)

7. MJ (Maggie gets first prize, Jim gets second prize)

8. MG (Maggie gets first prize, George gets second prize)

9. MH (Maggie gets first prize, Helen gets second prize)

Step-by-step explanation:

The question asks for the list of outcomes in the event "Not A". We are looking for the reverse or negative of Event A.

The above given list is the list of outcomes in the event where Helen DOES NOT get first prize.

The Wall Street Journal recently ran an article indicating differences in perception of sexual harassment on the job between men and women. The article claimed that women perceived the problem to be much more prevalent than did men. One question asked to both men and women was: "Do you think sexual harassment is a major problem in the American workplace?" Some 24% of the men compared to 62% of the women responded "Yes." Suppose that 150 women and 200 men were interviewed. For a 0.01 level of significance, what is the critical value for the rejection region? a. 7.173 b. 2.33 c. 6.635 d. 7.106

Answers

Answer:

Critical value: b. 2.33

As the test statistic z=7.17 is greater than the critical value, it falls in the rejection region.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of women who think sexual harassment is a major problem in the American workplace is significantly higher than the proportion of men.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of women who think sexual harassment is a major problem in the American workplace is significantly higher than the proportion of men.

Then, the null and alternative hypothesis are:

[tex]H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0[/tex]

The significance level is 0.01.

The sample 1 (women), of size n1=150 has a proportion of p1=0.62.

The sample 2 (men), of size n2=200 has a proportion of p2=0.24.

 

The difference between proportions is (p1-p2)=0.38.

[tex]p_d=p_1-p_2=0.62-0.24=0.38[/tex]

The pooled proportion, needed to calculate the standard error, is:

[tex]p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{93+48}{150+200}=\dfrac{141}{350}=0.403[/tex]

The estimated standard error of the difference between means is computed using the formula:

[tex]s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.403*0.597}{150}+\dfrac{0.403*0.597}{200}}\\\\\\s_{p1-p2}=\sqrt{0.001604+0.001203}=\sqrt{0.002807}=0.053[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.38-0}{0.053}=\dfrac{0.38}{0.053}=7.17[/tex]

The critical value for a right-tailed test with a signficance level of 0.01 is zc=2.33 (see picture attached).

As the test statistic z=7.17 is greater than the critical value, it falls in the rejection region.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of women who think sexual harassment is a major problem in the American workplace is significantly higher than the proportion of men.

Eagle Outfitters is a chain of stores specializing in outdoor apparel and camping gear. They are considering a promotion that involves mailing discount coupons to all their credit card customers. This promotion will be considered a success if more than 10% of those receiving the coupons use them. Before going national with the promotion, coupons were sent to a sample of 100 credit card customers.
a. Develop hypotheses that can be used to test whether the population proportion of those
who will use the coupons is sufficient to go national.
b. The file Eagle contains the sample data. Develop a point estimate of the population
proportion.
c. Use αα= .05 to conduct your hypothesis test. Should Eagle go national with the
promotion?

Answers

Answer:

a) Alternative hypothesis: the use of the coupons is isgnificantly higher than 10%.

Null hypothesis: the use of the coupons is not significantly higher than 10%.

The null and alternative hypothesis can be written as:

[tex]H_0: \pi=0.1\\\\H_a:\pi>0.1[/tex]

b) Point estimate p=0.13

c) At a significance level of 0.05, there is not enough evidence to support the claim that the proportion of coupons use is significantly higher than 10%.

Eagle should not go national with the  promotion as there is no evidence it has been succesful.

Step-by-step explanation:

The question is incomplete.

The sample data shows that x=13 out of n=100 use the coupons.

This is a hypothesis test for a proportion.

The claim is that the proportion of coupons use is significantly higher than 10%.

Then, the null and alternative hypothesis are:

[tex]H_0: \pi=0.1\\\\H_a:\pi>0.1[/tex]

The significance level is 0.05.

The sample has a size n=100.

The point estimate for the population proportion is the sample proportion and has a value of p=0.13.

[tex]p=X/n=13/100=0.13[/tex]

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.1*0.9}{100}}\\\\\\ \sigma_p=\sqrt{0.0009}=0.03[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.13-0.1-0.5/100}{0.03}=\dfrac{0.025}{0.03}=0.833[/tex]

This test is a right-tailed test, so the P-value for this test is calculated as:

[tex]\text{P-value}=P(z>0.833)=0.202[/tex]

As the P-value (0.202) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the proportion of coupons use is significantly higher than 10%.

pls help me hepl me ​

Answers

Answer:

b at most 199

Step-by-step explanation:so the total was 121 and there is a flat fee of 21.50 so you subtract that out and gat 99.5 since its .5 per mile its going to be divided giving 199 and that is the most she could have driven.

Overall Assessment Progress
Basic Office Skills
Question 5 of 47
1/4 + 7/8 = ?​

Answers

Answer:

1 1/8

Step-by-step explanation:

1/4 + 7/8

Make denominators equal.

2/8 + 7/8

Add the fractions.

9/8

Convert to a mixed fraction.

1 1/8

Answer:

1  1/8

Step-by-step explanation:

1/4 + 7/8

Get a common denominator

1/4 * 2/2 + 7/8

2/8 + 7/8

9/8

Change to a mixed number

8/8+ 1/8

1  1/8

The area of this parallelogram is 120 ft2 find the value of h

Answers

Answer: 6

Step-by-step explanation:

A=bh plus 120 for A and 20 for B

120=20b

/20 divide by 20 each side

H=6

I NEED HELP PLEASE THANKS!
Jenny is sitting on a sled on the side of a hill inclined at 15°. What force is required to keep the sled from sliding down the hill if the combined weight of Jenny and the sled is 90 pounds? (Show work)

Answers

Answer:

  23.29 lbs

Step-by-step explanation:

The force on Jenny due to gravity can be resolved into components perpendicular to the hillside and down the slope. The down-slope force is ...

  (90 lbs)sin(15°) ≈ 23.29 lbs

In order to keep Jenny in position, that force must be balanced by an up-slope force of the same magnitude.

Which equation represents the line passing through points A and C on the graph below? On a coordinate plane, point A is at (2, 3), point B is at (negative 2, 1), point C is at (negative 4, negative 3), and point D is at (4, negative 5). y= negative x minus 1 y = negative x + 1 y = x minus 1 y = x + 1

Answers

The equation that represents the line that passes through the points A and C is y = x + 1

What is a linear equation?

A linear equation is an equation that has a constant rate or slope, and is represented by a straight line

The points are given as:

(x,y) = (2,3) and (-4,-3)

Calculate the slope, m using:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

So, we have:

[tex]m = \frac{-3 -3}{-4 - 2}[/tex]

Evaluate

m = 1

The equation is then calculated as:

y = m *(x - x1) + y1

So, we have:

y = 1 * (x - 2) + 3

Evaluate

y = x - 2 + 3

This gives

y = x + 1

Hence, the equation that represents the line that passes through the points A and C is y = x + 1

Read more about linear equations at:

https://brainly.com/question/14323743

#SPJ2

Answer:

y = x + 1

Step-by-step explanation:

Edge2020

The function f(x) = -x2 + 40x - 336 models the daily profit, in dollars, a shop makes for selling donut
combos, where x is the number of combos sold and f(x) is the amount of profit.
Part A: Determine the vertex. What does this calculation mean in the context of the problem? Show
the work that leads to the answer. (5 points)
Part B: Determine the x-intercepts. What do these values mean in the context of the problem? Show
the work that leads to the answer. (5 points)
(10 points)

Answers

Answer:

This question should be worth atleast 20 points

Step-by-step explanation:

a. For the vertex, input the funtion into the calculator, and see where the turning piont is, that is the vertex.

b. Solve using this vormula.

x= (-b ±[tex]\sqrt{b^2 - 4ac}[/tex])/2a

you will get two asnwrs, both are correct.

PLS HELP (pic included)

Answers

hope it helps uh.......

A kite is flying 12 ft off the ground. Its line is pulled taut and casts an 8 -ft shadow. Find the length of the line. If necessary, round your answer to the nearest tenth.

Answers

Answer

14.4 ft~

Step-by-step explanation

A kite is flying 12 feet off the ground, therefore the height is 12 (assuming the line is tied to the ground if a person is holding the line then the height would be less)

Assuming the sun is positioned in such a way that the shadow represents a horizontal distance. Horizontal distance of shadow = 8

Use Pythagoras Theorem

Where a^2 + b^2 = c^2

8^2 + 12^2 = 208

Square root 208 = 14.4~

~ Hoodini, here to help :)

The required length of the line is given as 14.4 feet, as of the given conditions.

As given in the question, A kite is flying 12 ft off the ground. Its line is pulled taut and casts an 8 -ft shadow, to determine the length of the line.

What are Pythagorean triplets?  

In a right-angled triangle, its side, such as the hypotenuse, is perpendicular, and the base is Pythagorean triplets.

Here,
let the length of the line be x,
The scenario formed is right angle triangle,
Apply Pythagoras' theorem,
x² = 12² + 8²
x = √208
x = 14.4

Thus, the required length of the line is given as 14.4 feet, as of the given conditions.

Learn  more about Pythagorean triplets here:

brainly.com/question/22160915

#SPJ2


The left and right page numbers of an open book are two consecutive integers whose sum is 389.  Find these page numbers

Answers

Step-by-step explanation:

Maybe the page numbers can be 143 and 246

143 + 246 = 389

Answer:

194 and 195

Step-by-step explanation:

x = 1st page

x + 1 = 2nd page

x + x + 1 = 389

2x + 1 = 389

2x = 388

x = 194

x + 1 = 195

Evaluate geometric series sigma1^20 4(8/9)^n-1

Answers

Answer:

32.5861

Step-by-step explanation:

I interpreted it this way:

20 - stop at n = 20 (inclusive)

1 - start at n = 1

4(8/9)^(n - 1) - geometric expression

There is a set of 100 obserations with a mean of 46 and a standard deviation of 0. What is the value of smallest obserstion in a set?

Answers

Answer:

Solution = 46

Step-by-step explanation:

I believe you meant standard deviation. Standard deviation is defined as the variation of the data set, or the differences between the values in this set. In order for the standard deviation to be 0, all values should be the same.

Now if the mean is 46, the smallest possible number of each value in the data set should be 46 as well.  This is considering the mean is the average of the values, and hence any number of values in the data set being 46 will always have a mean of 46. Let me give you a demonstration -

[tex]Ex. [ 46, 46, 46 ], and, [46, 46, 46, 46, 46]\\Average = 46 + 46 + 46 / 3 = 46,\\Average = 46 + 46 + 46 + 46 + 46 / 5 = 46[/tex]

As you can see, the average is 46 in each case. This proves that a data set consisting of n number of values in it, each value being 46, or any constant value for that matter, always has a mean similar to the value inside the set, in this case 46. And, that the value of the smallest standard deviation is 46.

A square with side lengths of 3 cm is reflected vertically over a horizontal line of reflection that is 2 cm below the bottom edge of the square. What is the distance between the points C and C’? cm What is the perpendicular distance between the point B and the line of reflection? cm What is the distance between the points A and A’? cm

Answers

Answer:

a) 4 cm

b) 5 cm

c) 10 cm

Step-by-step explanation:

The side lengths of the reflected square are equal to the original, and the distance from the axis(2) also remains the same.  From there, it is just addition.

Hope it helps <3

Answer:

A) 4

B) 5

C) 10

Step-by-step explanation:

edge2020

Will give brainliest answer

Answers

Answer:

Radius = 6.5cm

Diameter = 13cm

Step-by-step explanation:

The diameter is given (13)

Radius is half the diameter (13/2=6.5)

Answer:

Radius = 13 / 2 = 6.5 cmDiameter = 13 cm

Explanation

Radius

The straight line is drawn from the centre of a circle to a point on its circumference is called radius of the circle. The radius of a circle is half of its diameter.

Diameter

The chord that passes through the centre of a circle is called diameter of circle. Diameter is also called the largest chord of any circle. The length of diameter of a circle is two times it's radius.

Hope this helps...

Good luck on your assignment...

Stuck Right now, Help would be appreciated :)

Answers

Answer:

C. c = (xv - x) / (v - 1).

Step-by-step explanation:

v = (x + c) / (x - c)

(x - c) * v = x + c

vx - vc = x + c

-vc - c = x - vx

vc + c = -x + vx

c(v + 1) = -x + vx

c = (-x + vx) / (v + 1)

c = (-x + xv) / (v + 1)

c = (xv - x) / (v + 1)

So, the answer should be C. c = (xv - x) / (v + 1).

Hope this helps!

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