Answer:
,.........................................................
how many different four letter permutations can be formed using four letters out of the first 12 in the alphabet?
Answer:
11,800 different four letter permutations can be formed using four letters out of the first 12 in the alphabet
Step-by-step explanation:
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:
[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]
In this question:
Permutations of four letters from a set of 12 letters. So
[tex]P_{(12,4)} = \frac{12!}{(12-4)!} = 11800[/tex]
11,800 different four letter permutations can be formed using four letters out of the first 12 in the alphabet
Answer: it’s 11,880
not 11800
Overall Assessment Progress
Basic Office Skills
Question 5 of 47
1/4 + 7/8 = ?
Answer:
1 1/8
Step-by-step explanation:
1/4 + 7/8
Make denominators equal.
2/8 + 7/8
Add the fractions.
9/8
Convert to a mixed fraction.
1 1/8
Answer:
1 1/8
Step-by-step explanation:
1/4 + 7/8
Get a common denominator
1/4 * 2/2 + 7/8
2/8 + 7/8
9/8
Change to a mixed number
8/8+ 1/8
1 1/8
Below are the times (in days) it takes for a sample of 17 customers from Andrew's computer store to pay their invoices.
19.15, 43, 39, 35, 31, 27, 34, 34, 30, 30, 26, 26, 26, 21, 21, 17
Draw the histogram for these data using an initial class boundary of 14.5, an ending class boundary of 49.5, and 5 classes of equal width. Note that you can add
or remove classes from the figure. Label each class with its endpoints.
Frequency
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Answer:
Step-by-step explanation:
Hello!
The variable of interest is X: time it takes a customer from Andrew's computer store to pay his invoices.
You have the information of a sample of n= 17 customers
19, 15, 43, 39, 35, 31, 27, 34, 34, 30, 30, 26, 26, 26, 21, 21, 17
To determine the class width of the intervals for the divide the difference between the ending and initial class boundaries by the number of intervals that you want to determine:
Class width: (49.5-14.5)/5= 7
Then, starting from the initial class boundary, you have to add the class width to determine the next boundary, and so on until the ending class boundary:
Initial class boundary: 14.5
14.5 + 5.6= 20.1
1st interval: [14.5; 21.5]
and so on:
[21.5; 28.5]
[28.5; 35.5]
[35.5; 42.5]
[42.5; 49.5]
Once you determined all class intervals, you have to order the values of the data set from least to greatest and then count how many observations correspond to each interval and arrange it in a frequency table.
15, 17, 19, 21, 21, 26, 26, 26, 27, 30, 30, 31, 34, 34, 35, 39, 43
[14.5; 21.5] ⇒ 5
[21.5; 28.5] ⇒ 4
[28.5; 35.5] ⇒ 6
[35.5; 42.5] ⇒ 1
[42.5; 49.5] ⇒ 1
Once you have the data set organized in the table, you can proceed to draw the histogram.
(See attachment)
I hope this helps!
PLS HELP (pic included)
hope it helps uh.......
A car is traveling on Michigan Street towards Ward Street. The car planes to turn right into Ward Street. what is the angle measure of the turn.
Pls help ASAP
A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per pound and cashews cost $6.50 per pound, how many pounds of cashews should he use?
Answer:
3lbs
Step-by-step explanation:
WHO CAN HELP ME WITH MY ACCOUNTING HOMEWORK???
Duran Manufacturing uses a process costing system and manufactures its product in three departments. Which of the following is NOT a way in which Duran can use the cost per unit of each process?
A) Duran can look for ways to cut the costs when actual process costs are more than planned process costs.
B) Duran needs to set the selling price to cover the costs of making the product and provide a profit.
C) Duran can only use the cost per unit of each process if all units are fully completed at the end of the accounting period.
D) Duran needs to know the ending balances in the following accounts: Work-In-Process Inventory, Finished Goods Inventory, and Cost of Goods Sold.
Answer:
C) Duran can only use the cost per unit of each process if all units are fully completed at the end of the accounting period.
Step-by-step explanation:
Duran uses cost accounting technique to identify cost per unit for its products. The costing techniques allows us to identify the cost of unit that are not completely finished. It is not necessary that all unit must be completed in order to find out the cost per unit of the product. The process costing is the best method to identify cost per unit for products that are in process.
find the value of x if (1.1)^x=100
Answer:
x ≈ 48.3177
Step-by-step explanation:
This is what logarithms are for (among other things).
log(1.1^x) = log(100)
x·log(1.1) = 2
x = 2/log(1.1) ≈ 48.3177
Which of the following shows the intersection of the sets? {1, 5, 10, 15} {1, 3, 5, 7}
Answer:
{1,5}
Step-by-step explanation:
The intersection of the sets are all of the numbers that appear in both sets. In this case, the only numbers that appear in both are 1 and 5.
Answer:
{ 1,5}
Step-by-step explanation:
The intersection is what the two sets have in common
{1, 5, 10, 15}∩ {1, 3, 5, 7}
= { 1,5}
Quadrilateral DEFG is rotated 180° about the origin to create quadrilateral D'E'F'G'. In which quadrant does G' lie? A. I B. II C. III D. IV
Answer:
B. II
Step-by-step explanation:
G is in quadrant IV. The quadrant that is across the origin from that is quadrant II.
G' will lie in quadrant II
Answer:
B. 11
Step-by-step explanation:
Evaluate geometric series sigma1^20 4(8/9)^n-1
Answer:
32.5861
Step-by-step explanation:
I interpreted it this way:
20 - stop at n = 20 (inclusive)
1 - start at n = 1
4(8/9)^(n - 1) - geometric expression
Jason has bought a new pool and has already measured some of the sides. Using the figure below and your knowledge of quadrilaterals, solve for x and y.
Answer:
x = 12
y = 12
Step-by-step explanation:
Each triangle is a right angle triangle
5² + x² = 13²
x² = 169 - 25
x = √144
x = 12
The shape is a parallelogram
Therefore
x = y
y = 12
The area of this parallelogram is 120 ft2 find the value of h
Answer: 6
Step-by-step explanation:
A=bh plus 120 for A and 20 for B
120=20b
/20 divide by 20 each side
H=6
Will give brainliest answer
Answer:
Radius = 6.5cm
Diameter = 13cm
Step-by-step explanation:
The diameter is given (13)
Radius is half the diameter (13/2=6.5)
Answer:
Radius = 13 / 2 = 6.5 cmDiameter = 13 cmExplanation
RadiusThe straight line is drawn from the centre of a circle to a point on its circumference is called radius of the circle. The radius of a circle is half of its diameter.
DiameterThe chord that passes through the centre of a circle is called diameter of circle. Diameter is also called the largest chord of any circle. The length of diameter of a circle is two times it's radius.
Hope this helps...
Good luck on your assignment...
Andrea and Helen participated in a donut eating contest. Andrea ate six more than four times the number of donuts that Helen ate. Let d represents the number of donuts Helen ate. Write the expression that gives the number of donuts that Andrea ate.
Answer:
4d + 6
Step-by-step explanation:
Helen ate d donuts.
Andrea ate 6 more than 4 times d.
4d + 6
Find all solutions to the equation.
7 sin2x - 14 sin x + 2 = -5
If yall can help me for Pre-Calc, that would be great.
-Thanks.
If the equation is
[tex]7\sin^2x-14\sin x+2=-5[/tex]
then rewrite the equation as
[tex]7\sin^2x-14\sin x+7=0[/tex]
Divide boths sides by 7:
[tex]\sin^2x-2\sin x+1=0[/tex]
Since [tex]x^2-2x+1=(x-1)^2[/tex], we can factorize this as
[tex](\sin x-1)^2=0[/tex]
Now solve for x :
[tex]\sin x-1=0[/tex]
[tex]\sin x=1[/tex]
[tex]\implies\boxed{x=\dfrac\pi2+2n\pi}[/tex]
where n is any integer.
If you meant sin(2x) instead, I'm not sure there's a simple way to get a solution...
A heavy rope, 30 ft long, weighs 0.4 lb/ft and hangs over the edge of a building 80 ft high. Approximate the required work by a Riemann sum, then express the work as an integral and evaluate it.How much work W is done in pulling half the rope to the top of the building
Answer:
180 fb*lb
45 ft*lb
Step-by-step explanation:
We have that the work is equal to:
W = F * d
but when the force is constant and in this case, it is changing.
therefore it would be:
[tex]W = \int\limits^b_ a {F(x)} \, dx[/tex]
Where a = 0 and b = 30.
F (x) = 0.4 * x
Therefore, we replace and we would be left with:
[tex]W = \int\limits^b_a {0.4*x} \, dx[/tex]
We integrate and we have:
W = 0.4 / 2 * x ^ 2
W = 0.2 * (x ^ 2) from 0 to 30, we replace:
W = 0.2 * (30 ^ 2) - 0.2 * (0 ^ 2)
W = 180 ft * lb
Now in the second part it is the same, but the integral would be from 0 to 15.
we replace:
W = 0.2 * (15 ^ 2) - 0.2 * (0 ^ 2)
W = 45 ft * lb
Following are the calculation to the given value:
Given:
[tex]length= 30 \ ft\\\\mass= 0.4 \ \frac{lb}{ft}\\\\edge= 80 \ ft \\\\[/tex]
To find:
work=?
Solution:
Using formula:
[tex]\to W=fd[/tex]
[tex]\to W=\int^{30}_{0} 0.4 \ x\ dx\\\\[/tex]
[tex]= [0.4 \ \frac{x^2}{2}]^{30}_{0} \\\\= [\frac{4}{10} \times \frac{x^2}{2}]^{30}_{0} \\\\= [\frac{2}{10} \times x^2]^{30}_{0} \\\\= [\frac{1}{5} \times x^2]^{30}_{0} \\\\= [\frac{x^2}{5}]^{30}_{0} \\\\= [\frac{30^2}{5}- 0] \\\\= [\frac{900}{5}] \\\\=180[/tex]
Therefore, the final answer is "[tex]180\ \frac{ lb}{ft}[/tex]".
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Which equation represents the line passing through points A and C on the graph below? On a coordinate plane, point A is at (2, 3), point B is at (negative 2, 1), point C is at (negative 4, negative 3), and point D is at (4, negative 5). y= negative x minus 1 y = negative x + 1 y = x minus 1 y = x + 1
The equation that represents the line that passes through the points A and C is y = x + 1
What is a linear equation?A linear equation is an equation that has a constant rate or slope, and is represented by a straight line
The points are given as:
(x,y) = (2,3) and (-4,-3)
Calculate the slope, m using:
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
So, we have:
[tex]m = \frac{-3 -3}{-4 - 2}[/tex]
Evaluate
m = 1
The equation is then calculated as:
y = m *(x - x1) + y1
So, we have:
y = 1 * (x - 2) + 3
Evaluate
y = x - 2 + 3
This gives
y = x + 1
Hence, the equation that represents the line that passes through the points A and C is y = x + 1
Read more about linear equations at:
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Answer:
y = x + 1
Step-by-step explanation:
Edge2020
Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets cost $6 per child and $8 per adult. They plan on spending no more than $80 on the matinee tickets and no more than $100 on the evening tickets.
Complete Question
Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets cost $6 per child and $8 per adult. They plan on spending no more than $80 on the matinee tickets and no more than $100 on the evening tickets. Could they take 9 children and 4 adults to both shows? Show your work. A yes or no answer is not sufficient for credit.
Answer:
Yes it is possible to take the 9 children and 4 adults to both shows
Step-by-step explanation:
From the question we are told that
The cost of the Matinee tickets for a child is z = $4
The cost of the Matinee tickets for an adult is a = $ 4
The cost of the Evening tickets for a child is k = $6
The cost of the Evening tickets for an adult is b = $8
The maximum amount to be spent on Matinee tickets is m = $80
The maximum amount to be spent on Evening tickets is e = $100
The number of child to be taken to the movies is n = 9
The number of adults to be taken to the movies is j = 4
Now the total amount of money that would be spent on Matinee tickets is mathematically evaluated as
[tex]t = 4 n + 4 j[/tex]
substituting values
[tex]t = 4 * 9 + 4* 4[/tex]
[tex]t = 52[/tex]
Now the total amount of money that would be spent on Evening ticket is mathematically evaluated as
[tex]T = 6n + 8j[/tex]
substituting values
[tex]T = 6(9) + 8(4)[/tex]
[tex]T = 86[/tex]
This implies that it is possible to take 9 children and 4 adults to both shows
given that
[tex]t \le m[/tex]
i.e $56 [tex]\le[/tex]$ 80
and
[tex]T \le e[/tex]
i.e $ 86 [tex]\le[/tex] $ 100
The weights of steers in a herd are distributed normally. The standard deviation is 300lbs and the mean steer weight is 1100lbs. Find the probability that the weight of a randomly selected steer is between 920 and 1730lbs round to four decimal places.
Answer:
The probability that the weight of a randomly selected steer is between 920 and 1730 lbs
P(920≤ x≤1730) = 0.7078
Step-by-step explanation:
Step(i):-
Given mean of the Population = 1100 lbs
Standard deviation of the Population = 300 lbs
Let 'X' be the random variable in Normal distribution
Let x₁ = 920
[tex]Z = \frac{x-mean}{S.D} = \frac{920-1100}{300} = - 0.6[/tex]
Let x₂ = 1730
[tex]Z = \frac{x-mean}{S.D} = \frac{1730-1100}{300} = 2.1[/tex]
Step(ii)
The probability that the weight of a randomly selected steer is between 920 and 1730 lbs
P(x₁≤ x≤x₂) = P(Z₁≤ Z≤ Z₂)
= P(-0.6 ≤Z≤2.1)
= P(Z≤2.1) - P(Z≤-0.6)
= 0.5 + A(2.1) - (0.5 - A(-0.6)
= A(2.1) +A(0.6) (∵A(-0.6) = A(0.6)
= 0.4821 + 0.2257
= 0.7078
Conclusion:-
The probability that the weight of a randomly selected steer is between 920 and 1730 lbs
P(920≤ x≤1730) = 0.7078
Answer:
0.7975
Step-by-step explanation:
In a competition, two people will be selected from four finalists to receive the first and second prizes. The prize winners will be selected by drawing names from a hat. The names of the four finalists are Jim, George, Helen, and Maggie. The possible outcomes can be represented as follows: JG JH JM GJ GH GM HJ HG HM MJ MG MH Here, for example, JG represents the outcome that Jim receives the first prize and George receives the second prize. The event A is defined as follows: A = event that Helen gets first prize List the outcomes that comprise the event ~A (not A).
Answer:
1. JG (Jim gets first prize, George gets second prize)
2. JH (Jim gets first prize, Helen gets second prize)
3. JM (Jim gets first prize, Maggie gets second prize)
4. GH (George gets first prize, Helen gets second prize)
5. GJ (George gets first prize, Jim gets second prize)
6. GM (George gets first prize, Maggie gets second prize)
7. MJ (Maggie gets first prize, Jim gets second prize)
8. MG (Maggie gets first prize, George gets second prize)
9. MH (Maggie gets first prize, Helen gets second prize)
Step-by-step explanation:
The question asks for the list of outcomes in the event "Not A". We are looking for the reverse or negative of Event A.
The above given list is the list of outcomes in the event where Helen DOES NOT get first prize.
can anyone help me with this?
Answer: 16y² - x²
Step-by-step explanation: The - sign means a difference, so the choices with + signs are eliminated (though 64x² and 9 are squares)
10 is not a square so that one is eliminated (though the y² and the 4x² are squares)
16 is the square of 4, y² is the square of y, and x² is the square. That expression shows a difference of squares.
pls help me help me
Answer:
A
Step-by-step explanation:
Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one another more frequently than what would be expected under a random mating pattern. Researchers studying this topic collected data on eye colors of 204 Scandinavian men and their female partners. The table below summarizes the results (rows represent male eye color while columns represent female eye color). For simplicity, we only include heterosexual relationships in this exercise.
(please round any numerical answers to 4 decimal places)
Blue Brown Green Total
Blue 78 23 13 114
Brown 19 23 12 54
Green 11 9 16 36
Total 108 55 41 204
a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?
b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?
c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?
d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?
e) Does it appear that the eye colors of male respondents and their partners are independent? Explain.
Answer:
a) P(male=blue or female=blue) = 0.71
b) P(female=blue | male=blue) = 0.68
c) P(female=blue | male=brown) = 0.35
d) P(female=blue | male=green) = 0.31
e) We can conclude that the eye colors of male respondents and their partners are not independent.
Step-by-step explanation:
We are given following information about eye colors of 204 Scandinavian men and their female partners.
Blue Brown Green Total
Blue 78 23 13 114
Brown 19 23 12 54
Green 11 9 16 36
Total 108 55 41 204
a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?
Using the addition rule of probability,
∵ P(A or B) = P(A) + P(B) - P(A and B)
For the given case,
P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)
P(male=blue or female=blue) = 114/204 + 108/204 − 78/204
P(male=blue or female=blue) = 0.71
b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?
As per the rule of conditional probability,
P(female=blue | male=blue) = 78/114
P(female=blue | male=blue) = 0.68
c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?
As per the rule of conditional probability,
P(female=blue | male=brown) = 19/54
P(female=blue | male=brown) = 0.35
d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?
As per the rule of conditional probability,
P(female=blue | male=green) = 11/36
P(female=blue | male=green) = 0.31
e) Does it appear that the eye colors of male respondents and their partners are independent? Explain
If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.
∵ P(B | A) = P(B)
P(female=blue | male=brown) = P(female=blue)
or alternatively, you can also test
P(female=blue | male=green) = P(female=blue)
P(female=blue | male=blue) = P(female=blue)
But
P(female=blue | male=brown) ≠ P(female=blue)
19/54 ≠ 108/204
0.35 ≠ 0.53
Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.
A kite is flying 12 ft off the ground. Its line is pulled taut and casts an 8 -ft shadow. Find the length of the line. If necessary, round your answer to the nearest tenth.
The required length of the line is given as 14.4 feet, as of the given conditions.
As given in the question, A kite is flying 12 ft off the ground. Its line is pulled taut and casts an 8 -ft shadow, to determine the length of the line.
What are Pythagorean triplets?In a right-angled triangle, its side, such as the hypotenuse, is perpendicular, and the base is Pythagorean triplets.
Here,
let the length of the line be x,
The scenario formed is right angle triangle,
Apply Pythagoras' theorem,
x² = 12² + 8²
x = √208
x = 14.4
Thus, the required length of the line is given as 14.4 feet, as of the given conditions.
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The Wall Street Journal recently ran an article indicating differences in perception of sexual harassment on the job between men and women. The article claimed that women perceived the problem to be much more prevalent than did men. One question asked to both men and women was: "Do you think sexual harassment is a major problem in the American workplace?" Some 24% of the men compared to 62% of the women responded "Yes." Suppose that 150 women and 200 men were interviewed. For a 0.01 level of significance, what is the critical value for the rejection region? a. 7.173 b. 2.33 c. 6.635 d. 7.106
Answer:
Critical value: b. 2.33
As the test statistic z=7.17 is greater than the critical value, it falls in the rejection region.
The null hypothesis is rejected.
There is enough evidence to support the claim that the proportion of women who think sexual harassment is a major problem in the American workplace is significantly higher than the proportion of men.
Step-by-step explanation:
This is a hypothesis test for the difference between proportions.
The claim is that the proportion of women who think sexual harassment is a major problem in the American workplace is significantly higher than the proportion of men.
Then, the null and alternative hypothesis are:
[tex]H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0[/tex]
The significance level is 0.01.
The sample 1 (women), of size n1=150 has a proportion of p1=0.62.
The sample 2 (men), of size n2=200 has a proportion of p2=0.24.
The difference between proportions is (p1-p2)=0.38.
[tex]p_d=p_1-p_2=0.62-0.24=0.38[/tex]
The pooled proportion, needed to calculate the standard error, is:
[tex]p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{93+48}{150+200}=\dfrac{141}{350}=0.403[/tex]
The estimated standard error of the difference between means is computed using the formula:
[tex]s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.403*0.597}{150}+\dfrac{0.403*0.597}{200}}\\\\\\s_{p1-p2}=\sqrt{0.001604+0.001203}=\sqrt{0.002807}=0.053[/tex]
Then, we can calculate the z-statistic as:
[tex]z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.38-0}{0.053}=\dfrac{0.38}{0.053}=7.17[/tex]
The critical value for a right-tailed test with a signficance level of 0.01 is zc=2.33 (see picture attached).
As the test statistic z=7.17 is greater than the critical value, it falls in the rejection region.
The null hypothesis is rejected.
There is enough evidence to support the claim that the proportion of women who think sexual harassment is a major problem in the American workplace is significantly higher than the proportion of men.
Toby cuts a pizza into 6 equal slices. He eats half a slice. What fraction of the pizza has he eaten?
The pizza is cut into 6 slices so each slice would be 1/6 of the pizza.
He at 1/2 of a slice:
1/6 x 1/2 = 1/12 of the pizza
. A box contains four red, three yellow, and seven green balls. Three balls are randomly selected from the box without replacement. (a) What is the probability that all three balls are the same colo
Answer:
10/91
Step-by-step explanation:
Number of Red balls = 4
Number of Yellow balls = 3
Number of green balls=7
Total=4+3+7=14
If we pick three balls of the same color, there are three possibilities: (All Red, All Green Or all Yellow).
Therefore:
The probability that all three balls are the same color (note that the selections are without replacement)
=P(RRR)+P(GGG)+P(YYY)
[tex]=(\frac{4}{14} \times \frac{3}{13} \times \frac{2}{12})+(\frac{3}{14} \times \frac{2}{13} \times \frac{1}{12})+(\frac{7}{14} \times \frac{6}{13} \times \frac{5}{12})\\\\=\frac{1}{91} + \frac{1}{364}+ \frac{5}{52}\\\\=\frac{10}{91}[/tex]
The probability that all three balls are the same color is 10/91.
Give the three-letter name of each of the angles in the drawing below. Lines and Angles a. ∠1 b. ∠2 c. ∠3 d. ∠4
Answer:
a. AEB
b. BEC
c. CED
d. AED
Step-by-step explanation:
Each angle is made up of three points. All three points in order is the name of the angle.
Answer:
a. ∠1 = ∠AEB or ∠BEA
b. ∠2 = ∠BEC or ∠CEB
c. ∠3 = ∠CED or ∠DEC
d. ∠4 = ∠DEA or ∠AED
Step-by-step explanation: Penn <3
Which of the following functions is graphed below?
Answer:
C
Step-by-step explanation:
C is the solution
Answer:
Option C
Step-by-step explanation:
The graph is a horizontal translation 4 units left and a vertical translation 2 units down ⇒ y= |x+4|-2