Find the complement and supplement of the angle with measure 40 degrees

Answer:

[tex]U = 4\\W = -6\\V = 5\\Z = 1\\x = 3\\y = 2[/tex]

Step-by-step explanation:

Then given expression is:

[tex]20a^3b^3-24a^5b^2+4a^3b^2[/tex]

To express the given expression in the form:

[tex]Ua^xb^y(Wa^2+Vb+Z)[/tex]

and to find the values of [tex]U, W, V, Z, x, y[/tex].

First of all, let us check the maximum common powers of [tex]a, b[/tex] in each term from the given expression.

The maximum common power of [tex]a[/tex] is 3 and

The maximum common power of [tex]b[/tex]  is 2.

So, we can take [tex]a^3b^2[/tex] common out of each term.

And maximum common coefficient that can be taken out common is 4.

Taking 4[tex]a^3b^2[/tex] common from each term of given expression, we get:

[tex]4a^3b^2(-6a^2+5b+1)[/tex]

Now, let us compare the given term with:

[tex]4a^3b^2(-6a^2+5b+1)[/tex] = [tex]Ua^xb^y(Wa^2+Vb+Z)[/tex]

Now, the values that we get the following values:

[tex]U = 4\\W = -6\\V = 5\\Z = 1\\x = 3\\y = 2[/tex]

which is our answer.

Answer:

x = 2

Step-by-step explanation:

19x - 7x + 8x = 48 - 8

20x = 40

20x/20 = 40/20

x =2

Answer:

x=2

Step-by-step explanation:

[tex]19x + 8 - 7x = 48 - 8x \\ ⟹ 12x + 8 = 48 - 8x \\ ⟹ 12x + 8x = 48 - 8 \\ ⟹20x = 40 \\ ⟹ x = \frac{40}{20} \\ ⟹x = 2[/tex]

Answer:

[tex]248 + 18\sqrt{15}[/tex]

Step-by-step explanation:

[tex](9\sqrt{3}+\sqrt{5} )(9\sqrt{3}+\sqrt{5} )=(9\sqrt{3}+\sqrt{5} )^2[/tex]

[tex]81 \cdot 3 + 2\cdot 9\sqrt{3} \cdot \sqrt{5} + 5[/tex]

[tex]243 + 18\sqrt{15} + 5[/tex]

[tex]248 + 18\sqrt{15}[/tex]

Answer:

870

Step-by-step explanation:

you take the calories per serving, 145, and multiply it by the number of servings in the bag, 3. this gives you 435, the number of calories in a bag. then you take the number of calories in a bag times the number of bags. you get 870

Answer:

870

Step-by-step explanation:

Answer:  5/6x + 1y = -5/3   or       5x + 6y = -10

Step-by-step explanation:

First  you need to write an equation in slope intercept form and convert  it to Standard form. To write an equation in slope intercept form using the coordinates we need to find the slope and the y-intercept.

The slope is the change in y over the change in x.

0-5 = -5

-2-(-8) = 6

Slope  is  -5/6  

  Now find the y intercept   using the formula y =mx + b   where m is the slope and b is the y-intercept.

5 = -5/6(-8) + b

5 = 40/6 +b

-40/6   -40/6

b= -5/3

 So now the equation is  y= -5/6x - 5/3

  So now write it in standard form as  ax+by = c  where x is constant.

 y = -5/6x -5/3

       +5/6x

5/6x + 1y = -5/3  now you can multiply it by 6 to get rid of the fractions.

5/6x(6) + y(6) = -5/3(6)

  5x + 6y = -10

Answer:

4x - 2

Step-by-step explanation:

Perimeter of triangle

[tex] =( 2x - 5) + (3x - 2) +( 5 - x) \\ = 2x + 3x - x - 5 - 2 + 5 \\ = 5x - x - 2 \\ = 4x - 2[/tex]

Answer:

32

Step-by-step explanation:

BIDMAS

(5 + 3) = 8

8 x 4 = 32

Answer: 1/2

Step-by-step explanation:

cosine=adjacent/hypotenuse

Cos (-60)=1/2

This is a special triangle

see below as the ratio of each side

Hope this helps!! :)

Please let me know if you have any question

Answer:

60°, 60°, and 60° is the set of interior angles of triangle.

Step-by-step explanation:

Given:

Set of interior angles

Find:

Set of interior angles of triangle

Computation:

We know that, sum of  interior angles of triangle is 180°

So,

90° + 42° + 58° = 190°

60° + 60° + 60° = 180°

100° + 48° + 42° = 190°

31° + 75° + 70° = 176°

So,

60°, 60°, and 60° is the set of interior angles of triangle.

Answer:

60°, 60°, and 60°

Step-by-step explanation: I took the quiz

Answer:

QC - PB = 6

Step-by-step explanation:

Given PQ is parallel to BC then it divides the sides proportionally, that is

[tex]\frac{AP}{AQ}[/tex] = [tex]\frac{PB}{QC}[/tex] = [tex]\frac{15}{24}[/tex] = [tex]\frac{5}{8}[/tex] , then

[tex]\frac{PB}{QC}[/tex] = [tex]\frac{5}{8}[/tex] ( cross- multiply )

8PB = 5QC → *

Given PB + QC = 26 , then

PB = 26 - QC

Substitute into *

8(26 - QC) = 5QC ← distribute left side

208 - 8QC = 5QC ( subtract 5QC from both sides )

208 - 13QC = 0 ( subtract 208 from both sides )

- 13QC = - 208 ( divide both sides by - 13 )

QC = 16

Thus PB = 26 - QC = 26 - 16 = 10

QC - PB = 16 - 10 = 6

Answer:

12.79/4.89 is $2.62 per gallon

2.62x<=21.44

Step-by-step explanation:

You could buy 8 because 21.44 divided by 2.62 is 8.1832...

Answer:

n-58

Step-by-step explanation:

Answer: n - 58

Step-by-step explanation:

The n goes first. You are subtracting 58 to find the missing value once n is determined.

Answer: C

Positive and between 0.0 and 0.5

Answer:

[tex]2880\ ft^{3}[/tex]

Step-by-step explanation:

The computation of the total amount of water needed could be determined by using the volume formula which is shown below:

[tex]Volume = L \times W \times D[/tex]

where

L = length,

W = width,

and D = depth.

Now putting the values to the above formula

[tex]Volume = (36\ ft) \times (20\ ft) \times (4\ ft) \\\\= 2880\ ft^{3}[/tex]                            

Therefore, the  total amount of water needed is [tex]2880\ ft^{3}[/tex]

We simply applied the above formula

Answer:

280ft3

Step-by-step explanation:

A product has a production cost function ​C(x) =165x + 3630 and a revenue function ​R(x)= 220x. Find and analyze the​ break-even quantity, then find the profit function.

Answer:

the break-even  quantity = 66

the profit function = 55x - 3630

Step-by-step explanation:

Given that:

C(x) = 165x + 3630

R(x) = 220 x

The Break-even quantity is C(x) = R(x)

∴

165x + 3630 = 220x

collecting the like terms, we have:

3630 = 220 x - 165 x

3630 = 55 x

[tex]x = \dfrac{3630}{55}[/tex]

x = 66

Thus, the break-even  quantity = 66

The profit function = R(x) - C(x)

The profit function = 220x - 3630 - 165x

By rearrangement

The profit function = 220x - 165x - 3630

The profit function = 55x - 3630

Answer:

Mr. Doyle has 460000 bees

Step-by-step explanation:

We are told that Mrs. Zhang's bee farm has a population that is about 1 tenth as large as Mr. Doyle's bee farm.

Thus;

Population size of Mrs. Zhang's bee farm = 1/10 × population size of Mr. Doyle's bee farm

Now, we are given that Mrs. Zhang's bee population is about 46,000.

Thus, from the earlier equation, we have;

46000 = 1/10 × population size of Mr. Doyle's bee farm

Thus, when we multiply both sides by 10,we get;

population size of Mr. Doyle's bee farm = 46000 × 10 = 460000 bees

Answer:

2

Step-by-step explanation:

let the number be n, then sum of number and 4 is n + 4 and 3 times the number is 3n, thus

n + 4 = 3n ( subtract n from both sides )

4 = 2n ( divide both sides by 2 )

2 = n

That is the number is 2

Answer:

2

Step-by-step explanation:

1.form an equation

call the number x

x+4=3x

2.solve using inverse operations

x=2

Answer:

12 + 20d

Step-by-step explanation:

OG fare = 12

Ticket price =d

20 Tickets =20d

Answer:

14

Step-by-step explanation:

I tried to put the problem together as best as I could and i got the problem as (6-3x^2-8x^4-2x^3)+(6+7x^2)+(2-7x^3+3x^2)

That means that the constants are 6+6+2.

6+6+2= 14

Answer:

AB = 17 meters

Step-by-step explanation:

Given that the triangle, ∆ABC, has 2 congruent sides that are indicated with a single marking on segment AC and segment AB, both segments would be of equal measure.

Therefore, since the measure of segment C is 17 meters, the measure of segment AB = measure of segment AC = 17 meters.

Segment AB = 17 meters. It is congruent to segment AC.

Answer:

13

Step-by-step explanation:

Answer:

15 bananas

Step-by-step explanation:

If two loaves of bread uses 3 bananas then multiply that by 5 because 10 divided by 2 is 5 and get 15 bananas.

Answer:

q = 42

Step-by-step explanation:

[tex]\frac{q}{7}=6\\\\\frac{q}{7}*7=6*7\\\\ \boxed{q=42}[/tex]

Hope this helps.

Answer:

1310720

Step-by-step explanation:

you multiply (4^9) and get 262144 then multiply (262144)^5 and get 1310720*4^0 and multiply 4*0 and get 0 so 1310720 if that makes sense

Answer:  see proof below

Step-by-step explanation:

Use the following Sum/Difference Identities:

sin(A + B) = sin A · cos B + sin B · cos A

sin(A - B) = sin A · cos B - sin B · cos A

Use the following Half-Angle Identities:

[tex]\sin\bigg(\dfrac{\theta}{2}\bigg)=\dfrac{\sqrt{1-\cos \theta}}{\sqrt2}\\\\\\\cos\bigg(\dfrac{\theta}{2}\bigg)=\dfrac{\sqrt{1+\cos \theta}}{\sqrt2}[/tex]

[tex]\text{Use the Unit circle to evaluate:}\ \cos\dfrac{\pi}{4} = \sin\dfrac{\pi}{4} = \dfrac{\sqrt2}{2}[/tex]

Use the following side work:

[tex]\sin\bigg(\dfrac{\pi}{8}\bigg)=\sin\bigg(\dfrac{\frac{\pi}{4}}{2}\bigg)=\dfrac{\sqrt{1-\cos \frac{\pi}{4}}}{\sqrt2}=\dfrac{\sqrt{2-\sqrt2}}{2}\\\\\\\cos\bigg(\dfrac{\pi}{8}\bigg)=\cos\bigg(\dfrac{\frac{\pi}{4}}{2}\bigg)=\dfrac{\sqrt{1+\cos \frac{\pi}{4}}}{\sqrt2}=\dfrac{\sqrt{2+\sqrt2}}{2}[/tex]

Proof LHS → RHS

[tex]\text{LHS:}\qquad \qquad \qquad \qquad \qquad \sin^2\bigg(\dfrac{\pi}{8}+\dfrac{A}{2}\bigg)-\sin^2\bigg(\dfrac{\pi}{8}-\dfrac{A}{2}\bigg)\\\\\text{Sum/Difference Identity:}\qquad \bigg(\sin\dfrac{\pi}{8}\cdot \cos \dfrac{A}{2}+\sin \dfrac{A}{2}\cdot \cos \dfrac{\pi}{8}\bigg)^2\\\\.\qquad \qquad \qquad\qquad \qquad \quad -\bigg(\sin\dfrac{\pi}{8}\cdot \cos \dfrac{A}{2}-\sin \dfrac{A}{2}\cdot \cos \dfrac{\pi}{8}\bigg)^2[/tex]

[tex]\text{Expand and Simplify:}\qquad \quad 4\sin \dfrac{\pi}{8}\cdot \cos\dfrac{A}{2}\cdot \sin \dfrac{A}{2}\cdot \cos \dfrac{A}{2}\\\\\\\text{Substitute:}\qquad \qquad \qquad 4\bigg(\dfrac{\sqrt{2-\sqrt2}}{2}\bigg)\cdot \cos \dfrac{A}{2}\cdot \sin \dfrac{A}{2}\bigg(\dfrac{\sqrt{2+\sqrt2}}{2}\bigg)\\\\\\\text{Simplify:}\qquad \qquad \qquad \sqrt2\cos \bigg(\dfrac{A}{2}\bigg)\cdot \sin \bigg(\dfrac{A}{2}\bigg)[/tex]

[tex]\text{Half-Angle Identity:} \quad \sqrt2\bigg(\dfrac{\sqrt{1+\cos A}}{\sqrt2}\bigg)\bigg(\dfrac{\sqrt{1-\cos A}}{\sqrt2}\bigg)\\\\\\\text{Simplify:}\qquad \qquad \qquad \dfrac{\sqrt{1-\cos^2 A}}{\sqrt2}\\\\\\.\qquad \qquad \qquad \qquad =\dfrac{\sqrt{\sin^2 A}}{\sqrt2}\\\\\\.\qquad \qquad \qquad \qquad =\dfrac{\sin A}{\sqrt2}[/tex]

[tex]\text{LHS = RHS:}\quad \dfrac{\sin A}{\sqrt2} = \dfrac{\sin A}{\sqrt2}\quad \checkmark[/tex]

Answer:

Step-by-step explanation:

Hello,

You can list the following ones which are correct for a), b) and c)

[tex]\boxed{\sf \bf \ \ 1, \dfrac{1}{2}, \dfrac{1}{3},\dfrac{1}{4},\dfrac{1}{5} \ \ }[/tex]

Thanks

Answer and Step-by-step explanation: Suppose remaining credit is y and time in minutes is x. To determine a value of y corresponding to a value of x, first find the equation for the function.

Since the function is linear, the equation is of the form: y = mx + b. To determine it:

1) Find slope, or inclination, of the line:

slope (m) = [tex]\frac{y_{b}-y_{a}}{x_{b}-x_{a}}[/tex]

where x's and y's are points of the function.

2) Determine the y-intercept, or b: Use a point of the function, replace them at the equation, y = mx + b, and find b.

3) The equation will be: y = mx + b

With the equation, replace x for the minutes the question is asking and calculate to find the remaining credit.

Th result will be a pair (x,y)

Answer:

Step-by-step explanation:

Hello, as alpha and beta are zeroes of

[tex]x^2-x-2[/tex]

it means that their sum is alpha+beta=1 and their product alpha*beta=-2.

The polynomial whose zeroes are 2 alpha + 1 and 2 beta + 1, means that the sum of its zeroes is 2(alpha+beta)+2=2+2=4

and the product is (2alpha+1)(2beta+1)=4 alpha*beta + 2(alpha+beta) + 1 = 4 * (-2) + 2*(1) +1 = -8 + 2 + 1 = -5. so one of these polynomials is

[tex]\Large \boxed{\sf \bf \ \ x^2-4x-5 \ \ }[/tex]

Thank you.

Susan does not have enough money.

20 times 15 will cost $300. Susan only have $250.

I'm not sure if this is correct.