find the common factor between
36y2z2,24yz,30y3z4

The simplified form of the given trigonometric expressions are (sinθ + tanθ)/cos²θ.

Given expressions are

sinθ/(1 - secθ) and (1 + secθ)/(1 - secθ)

To simplify the expressions, we can multiply the numerators and the denominators together,

sinθ × (1 + secθ)/(1 - secθ) × (1 + secθ)

Now simplify the numerator

sinθ × (1 + secθ) = sinθ + sinθ × secθ

Now simplify the denominator

(1 - secθ) × (1 + secθ) = (1 - sec²θ)

We can use the identity (1 - sec²θ) = cos²θ to rewrite the denominator

(1 - secθ) × (1 + secθ) = cos²θ

Putting the simplified numerator and denominator back together, we have

= (sinθ + sinθsecθ)/cos²θ

We can simplify this expression further. Let's factor out a common factor of sinθ from the numerator

= sinθ(1 + secθ)/cos²θ

Use the identity secθ = 1/cosθ, rewrite the numerator as

= sinθ(1 + 1/cosθ)/cos²θ

= (sinθ + sinθ/cosθ)/cos²θ

Use the identity sinθ/cosθ = tanθ

= (sinθ + tanθ)/cos²θ

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Looking at the graph, the correct answer is in option B; An employee would earn $730 if they work for 27 hours on a project.

A scatterplot is a type of graphical representation that displays the relationship between two numerical variables. It is particularly useful for visualizing the correlation or pattern between two sets of data points.

We can see that we can trace the statement that is correct when we try to match each of the points on the graph. When we do that, we can see that 27 hours can be matched with $730 earnings.

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Given,Face value (FV) of the note = $1000Issued date = April 21, 2005Rate of interest (r) = 5.5%Time period (t) = 90 daysNow, we have to find the maturity value of the note.To compute the maturity value, we have to find the interest and then add it to the face value (FV) of the note.

To find the interest, we use the formula,Interest (I) = (FV x r x t) / (100 x 365)where t is in days.Putting the given values in the above formula, we get,I = (1000 x 5.5 x 90) / (100 x 365)= 150.14So, the interest on the note is $150.14.Now, the maturity value (MV) of the note is given by,MV = FV + I= $1000 + $150.14= $1150.14Therefore, the maturity value of the note is $1150.14.

On computing the maturity value of a 90-day note with a face value of $1000 issued on April 21, 2005, at an interest rate of 5.5%, it is found that the maturity value of the note is $1150.14.

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the correct option is (d) {2, 3, 4, 5, 6, 7, 8, 9}.

The given universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9} and A = {1}. We are to find the complement of A.

The complement of A, A' is the set of elements that are not in A but are in the universal set. It is denoted by A'.

Therefore,

A' = {2, 3, 4, 5, 6, 7, 8, 9}

The complement of A is the set of all elements in U that do not belong to A. Since A contains only the element 1, we simply remove this element from U to obtain the complement.

Hence, A' = {2, 3, 4, 5, 6, 7, 8, 9}.

The complement of the set A = {1} is the set of all the remaining elements in the universal set U = {1, 2, 3, 4, 5, 6, 7, 8, 9}.

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The terminal point P(x, y) on the unit circle determined by t = 4π is P(1, 0).

To find the terminal point P(x, y) on the unit circle determined by the value of t, we can use the parametric equations for points on the unit circle:

x = cos(t)

y = sin(t)

In this case, t = 4π. Plugging this value into the equations, we get:

x = cos(4π)

y = sin(4π)

Since cosine and sine are periodic functions with a period of 2π, we can simplify the expressions:

cos(4π) = cos(2π + 2π) = cos(2π) = 1

sin(4π) = sin(2π + 2π) = sin(2π) = 0

Therefore, the terminal point P(x, y) on the unit circle determined by t = 4π is P(1, 0).

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The required solution is,

[tex]\[\frac{d y}{d x}=\frac{2 \sec ^{2} 2 x-x^{3} (2 e^{2 y})}{3 x^{2} e^{2 y}}-\frac{1}{y} \frac{d x}{d y}\][/tex]

The given function is,

[tex]\[ \tan 2 x=x^{3} e^{2 y}+\ln y \][/tex]

In order to find [tex]\(\frac{d y}{d x}\)[/tex]

by Implicit differentiation, we need to differentiate both sides with respect to x, then use the Chain Rule where required. Let's differentiate the given function with respect to x,

[tex]\[\frac{d}{d x}\tan 2 x=\frac{d}{d x}(x^{3} e^{2 y}+\ln y)\][/tex]

By Chain rule, we get

[tex]\[2 \sec ^{2} 2 x=3 x^{2} e^{2 y} \frac{d x}{d y}+x^{3} (2 e^{2 y})+ \frac{1}{y} \frac{d y}{d x}\][/tex]

Let's arrange the terms in terms of

[tex]\(\frac{d y}{d x}\),\[\frac{d y}{d x}=\frac{2 \sec ^{2} 2 x-x^{3} (2 e^{2 y})}{3 x^{2} e^{2 y}}-\frac{1}{y} \frac{d x}{d y}\][/tex]

Hence, the required solution is,

[tex]\[\frac{d y}{d x}=\frac{2 \sec ^{2} 2 x-x^{3} (2 e^{2 y})}{3 x^{2} e^{2 y}}-\frac{1}{y} \frac{d x}{d y}\][/tex]

In order to find[tex]\(\frac{d y}{d x}\)[/tex]

by Implicit differentiation, we need to differentiate both sides with respect to x, then use the Chain Rule where required.

Let's differentiate the given function with respect to x,

[tex]\[\frac{d}{d x}\tan 2 x=\frac{d}{d x}(x^{3} e^{2 y}+\ln y)\][/tex]

By the Chain rule, we get

[tex]\[2 \sec ^{2} 2 x=3 x^{2} e^{2 y} \frac{d x}{d y}+x^{3} (2 e^{2 y})+ \frac{1}{y} \frac{d y}{d x}\][/tex]

Let's arrange the terms in terms of

[tex]\(\frac{d y}{d x}\),\[\frac{d y}{d x}=\frac{2 \sec ^{2} 2 x-x^{3} (2 e^{2 y})}{3 x^{2} e^{2 y}}-\frac{1}{y} \frac{d x}{d y}\]\\[/tex]

Hence, the required solution is, [tex]\[\frac{d y}{d x}=\frac{2 \sec ^{2} 2 x-x^{3} (2 e^{2 y})}{3 x^{2} e^{2 y}}-\frac{1}{y} \frac{d x}{d y}\][/tex]

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(a) 36° is equal to (1/5)π radians.

(b) 15 radians is approximately equal to 859.46°.

(c) The angle coterminal to 25/3 that is between 0 and 27 is approximately 14.616.

(a) To convert 36° to radians, we use the conversion factor that 180° is equal to π radians.

36° = (36/180)π = (1/5)π

(b) To convert 15 radians to degrees, we use the conversion factor that π radians is equal to 180°.

15 radians = 15 * (180/π) = 15 * (180/3.14159) ≈ 859.46°

(c) We must add or remove multiples of 2 to 25/3 in order to get an angle coterminal to 25/3 that is between 0 and 27, then we multiply or divide that angle by the necessary range of angles.

25/3 ≈ 8.333

We can add or subtract 2π to get the coterminal angles:

8.333 + 2π ≈ 8.333 + 6.283 ≈ 14.616

8.333 - 2π ≈ 8.333 - 6.283 ≈ 2.050

The angle coterminal to 25/3 that is between 0 and 27 is approximately Between 0 and 27, the angle coterminal to 25/3 is roughly 14.616 degrees.

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Answer:

Step-by-step explanation:

\begin{align*}

T_{1,1} &= \frac{1}{2} (f(0) + f(1)) \\

&= \frac{1}{2} (1 + \frac{1}{2}) \\

&= \frac{3}{4}

\end{align*}

Now, for two subintervals:

\begin{align*}

T_{2,1} &= \frac{1}{4} (f(0) + 2f(1/2) + f(1)) \\

&= \frac{1}{4} \left(1 + 2 \left(\frac{1}{1 + \left(\frac{1}{2}\right)^2}\right) + \frac{1}{1^2}\right) \\

&= \frac{1}{4} \left(1 + 2 \left(\frac{1}{1 + \frac{1}{4}}\right) + 1\right) \\

&= \frac{1}{4} \left(1 + 2 \left(\frac{1}{\frac{5}{4}}\right) + 1\right) \\

&= \frac{1}{4} \left(1 + 2 \cdot \frac{4}{5} + 1\right) \\

&= \frac{1}{4} \left(1 + \frac{8}{5} + 1\right) \\

&= \frac{1}{4} \left(\frac{5}{5} + \frac{8}{5} + \frac{5}{5}\right)

\end{align*}

Thus, the approximate value of the integral using Romberg's method is T_2,1, and this can also be used to obtain an approximate value of π.

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At this moment, the distance between them is changing at a rate of 6.96 mph.

To find the rate of change of the distance between the biker and the driver, we need to find the derivative of the distance function with respect to time. Let's first use the Pythagorean theorem to find the distance between them at any given time t:

d(t) = sqrt((0.33 + 10t)^2 + (0.25 + 15t)^2)

Taking the derivative of d(t) with respect to time, we get:

d'(t) = [(0.33 + 10t)(20) + (0.25 + 15t)(30)] / sqrt((0.33 + 10t)^2 + (0.25 + 15t)^2)

At the moment when the biker has gone 0.33 miles and the driver has gone 0.25 miles, we can substitute t = 0 into the derivative:

d'(0) = [(0.33)(20) + (0.25)(30)] / sqrt((0.33)^2 + (0.25)^2)

d'(0) = 6.96 mph

Therefore, at this moment, the distance between them is changing at a rate of 6.96 mph.

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The pairs of consecutive integers whose product is 182 are:

Positive set: 13 and 14

Negative set: -14 and -13

To find the pairs of consecutive integers whose product is 182, we can set up the equation:

x(x + 1) = 182

Expanding the equation, we get:

x^2 + x = 182

Rearranging the equation:

x^2 + x - 182 = 0

Now we can solve this quadratic equation to find the values of x.

Step 1: Factorize the quadratic equation (if possible).

The equation does not appear to factorize easily, so we'll move on to Step 2.

Step 2: Use the quadratic formula to find the values of x.

The quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

For our equation, a = 1, b = 1, and c = -182. Plugging these values into the quadratic formula, we get:

x = (-1 ± √(1^2 - 4(1)(-182))) / (2(1))

Simplifying further:

x = (-1 ± √(1 + 728)) / 2

x = (-1 ± √729) / 2

x = (-1 ± 27) / 2

This gives us two possible values for x:

x = (-1 + 27) / 2 = 13

x = (-1 - 27) / 2 = -14

Step 3: Find the consecutive integers.

We have found two possible values for x: 13 and -14. Now we can find the consecutive integers.

For the positive set of integers:

x = 13

x + 1 = 14

For the negative set of integers:

x = -14

x + 1 = -13

So, the pairs of consecutive integers whose product is 182 are:

Positive set: 13 and 14

Negative set: -14 and -13

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The projected revenue from the sale of unit 46 would be $142,508.

To find the marginal revenue, we first take the derivative of the revenue function R(x):

R'(x) = d/dx(66x² + 73x + 2x + 2)

R'(x) = 132x + 73 + 2

Next, we substitute x = 45 into the marginal revenue function:

R'(45) = 132(45) + 73 + 2

R'(45) = 5940 + 73 + 2

R'(45) = 6015

Therefore, the marginal revenue when 45 units are sold is $6,015.

To estimate the projected revenue from the sale of unit 46, we evaluate the revenue function at x = 46:

R(46) = 66(46)² + 73(46) + 2(46) + 2

R(46) = 66(2116) + 73(46) + 92 + 2

R(46) = 139,056 + 3,358 + 92 + 2

R(46) = 142,508

Hence, the projected revenue from the sale of unit 46 would be $142,508.

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The denominator, x²-6x+8, is always positive since its quadratic coefficients result in a positive parabola with no real roots.

To analyze the given function f(x) = x(x²-3x+2)/(x²-6x+8), let's go through each question step by step:

X and Y intercepts:

a) X-intercepts: These occur when the function f(x) crosses the x-axis. To find them, we set f(x) = 0 and solve for x. In this case, we have:

x(x²-3x+2)/(x²-6x+8) = 0

Since the numerator, x(x²-3x+2), will be zero when x = 0 or when the quadratic expression x²-3x+2 = 0 has solutions, we need to find the roots of the quadratic equation:

x²-3x+2 = 0

By factoring or using the quadratic formula, we find that the solutions are x = 1 and x = 2. Therefore, the x-intercepts are (1, 0) and (2, 0).

b) Y-intercept: This occurs when x = 0. Plugging x = 0 into the function, we get:

f(0) = 0(0²-3(0)+2)/(0²-6(0)+8) = 0

Therefore, the y-intercept is (0, 0).

Holes:

To determine if there are any holes in the graph of the function, we need to check if any factors in the numerator and denominator cancel out and create a removable discontinuity.

In this case, the factor (x-1) in both the numerator and denominator cancels out. Thus, the function has a hole at x = 1.

End behavior:

To analyze the end behavior, we observe the highest power term in the numerator and denominator of the function. In this case, the highest power term is x² in both the numerator and denominator.

As x approaches positive or negative infinity, the x² term dominates the function. Therefore, the end behavior of the function is:

As x → ∞, f(x) → x²/x² = 1

As x → -∞, f(x) → x²/x² = 1

Defining intervals:

To determine the intervals where the function is positive or negative, we can analyze the sign of the numerator and denominator separately.

a) Numerator sign:

The sign of the numerator, x(x²-3x+2), depends on the value of x. We can use a sign chart or test points to determine the sign of the numerator in different intervals:

For x < 0:

Test point: x = -1

f(-1) = -1((-1)²-3(-1)+2) = 6 > 0

For 0 < x < 1:

Test point: x = 0.5

f(0.5) = 0.5((0.5)²-3(0.5)+2) = -0.375 < 0

For 1 < x < 2:

Test point: x = 1.5

f(1.5) = 1.5((1.5)²-3(1.5)+2) = 0.75 > 0

For x > 2:

Test point: x = 3

f(3) = 3((3)²-3(3)+2) = -6 < 0

b) Denominator sign:

The denominator, x²-6x+8, is always positive since its quadratic coefficients result in a positive parabola with no real roots.

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To find  [tex]\( a_{1} \)[/tex] , given that [tex]\( S_{14}=168 \)[/tex]  and [tex]\( a_{14}=25 \)[/tex] we can use the formula for the sum of an arithmetic series. By substituting the known values into the formula, we can solve for [tex]a_{1}[/tex].

To find the value of [tex]a_{1}[/tex] we need to determine the formula for the sum of an arithmetic series and then use the given information to solve for [tex]a_{1}[/tex]

The sum of an arithmetic series can be calculated using the formula

[tex]S_{n}[/tex] = [tex]\frac{n}{2} (a_{1} + a_{n} )[/tex] ,  

where [tex]s_{n}[/tex] represents the sum of the first n terms [tex]a_{1}[/tex]  is the first term, and [tex]a_{n}[/tex] is the nth term.

Given that [tex]\( S_{14}=168 \) and \( a_{14}=25 \)[/tex]  we can substitute these values into the formula:

168= (14/2)([tex]a_{1}[/tex] + 25)

Simplifying the equation, we have:

168 = 7([tex]a_{1}[/tex] +25)

Dividing both sides of the equation by 7  

24 = [tex]a_{1}[/tex] + 25

Finally, subtracting 25 from both sides of the equation

[tex]a_{1}[/tex] = -1

Therefore, the first term of the arithmetic series is -1.

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The probability that all four numbers generated by the computer program are greater than 10 is 1/16. This is obtained by multiplying the individual probabilities of each number being greater than 10, which is 1/2. The probability of randomly selecting four balls, one at a time, from a bag containing 20 balls numbered 1 to 20, and having all four of them be numbers greater than 10 is 168/517.

a) For each number generated by the computer program, the probability of it being greater than 10 is 10/20 = 1/2, since there are 10 numbers out of the total 20 that are greater than 10. Since the numbers are generated independently, the probability of all four numbers being greater than 10 is (1/2)^4 = 1/16.

b) When taking out the balls from the bag, the probability of the first ball being greater than 10 is 10/20 = 1/2. After removing one ball, there are 19 balls left in the bag, and the probability of the second ball being greater than 10 is 9/19.

Similarly, the probability of the third ball being greater than 10 is 8/18, and the probability of the fourth ball being greater than 10 is 7/17. Since the events are dependent, we multiply the probabilities together: (1/2) * (9/19) * (8/18) * (7/17) = 168/517.

Note: The probability in part b) assumes sampling without replacement, meaning once a ball is selected, it is not put back into the bag before the next selection.

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The roots of the quadratic equation obtained using the quadratic formula method are [tex]$\frac{4}{3}$ and $\frac{5}{3}$.[/tex]

The method used to factorize the expression -3x² + 8x-5 is completing the square method.

That coefficient is half of the coefficient of the x term squared; in this case, it is (8/(-6))^2 = (4/3)^2 = 16/9.

So, we have -3x² + 8x - 5= -3(x^2 - 8x/3 + 16/9 - 5 - 16/9)= -3[(x - 4/3)^2 - 49/9]

By simplifying the above expression, we get the final answer which is: -3(x - 4/3 + 7/3)(x - 4/3 - 7/3)

Now, we can use another method of factorization to check the answer is correct.

Let's use the quadratic formula.

The quadratic formula is given by:

                    [tex]$$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$$[/tex]

Comparing with our expression, we get a=-3, b=8, c=-5

Putting these values in the quadratic formula and solving it, we get

        [tex]$x=\frac{-8\pm \sqrt{8^2 - 4(-3)(-5)}}{2(-3)}$[/tex]

which simplifies to:

              [tex]$x=\frac{4}{3} \text{ or } x=\frac{5}{3}$[/tex]

Hence, the factors of the given expression are [tex]$(x - 4/3 + 7/3)(x - 4/3 - 7/3)$.[/tex]

The roots of the quadratic equation obtained using the quadratic formula method are [tex]$\frac{4}{3}$ and $\frac{5}{3}$.[/tex]

As we can see, both methods of factorisation gave the same factors, which proves that the answer is correct.

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Answer: x = 8

Step-by-step explanation:

The two lines are of the same length. We can write the equation 11 + 7x = 67 to represent this. We can simplify (solve) this equation by isolating our variable.

11 + 7x = 67 becomes:

7x = 56

We've subtracted 11 from both sides.

We can then isolate x again. By dividing both sides by 7, we get:

x = 8.

Therefore, x = 8.

The area of a triangular region with given side lengths using Heron's formula is 1492 square meters.

To find the area of the triangular region, we can use Heron's formula, which states that the area (A) of a triangle with side lengths a, b, and c is given by the formula:

[tex]A= \sqrt{s(s-a)(s-b)(s-c)}[/tex]

​where s is the semi-perimeter of the triangle, calculated as half the sum of the side lengths: s= (a+b+c)/2.

In this case, the given side lengths of the triangle are 50 meters, 60 meters, and 74 meters.

We can substitute these values into the formula to calculate the area.

First, we find the semi-perimeter:

[tex]s= (50+60+74)/2 =92[/tex]

Then, we substitute the semi-perimeter and side lengths into Heron's formula:

[tex]A= \sqrt{92(92-50)(92-60)(92-74)}[/tex] ≈ 1491.86≈ 1492 square meters.

By evaluating this expression, we can find the area of the triangular region.

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The solution to the differential equation is [tex]$y = \left(\frac{7}{2}\left(-\frac{1}{6}y^{\frac{2}{7}} e^{-6x} - \frac{1}{36}e^{-6x}y^{\frac{6}{7}} + \frac{2}{7}\right)\right)^{\frac{1}{5}}$[/tex]

Given DE : [tex]$y^{\frac{1}{7}} \frac{dy}{dx} + y^{\frac{3}{2}} = 1$[/tex] and the initial value y(0) = 0

This is a Bernoulli differential equation. It can be converted to a linear differential equation by substituting[tex]$v = y^{1-7}$[/tex], we get [tex]$\frac{dv}{dx} + (1-7)v = 1- y^{-\frac{1}{2}}$[/tex]

On simplification, [tex]$\frac{dv}{dx} - 6v = y^{-\frac{1}{2}}$[/tex]

The integrating factor [tex]$I = e^{\int -6 dx} = e^{-6x}$On[/tex] multiplying both sides of the equation by I, we get

[tex]$I\frac{dv}{dx} - 6Iv = y^{-\frac{1}{2}}e^{-6x}$[/tex]

Rewriting the LHS,

[tex]$\frac{d}{dx} (Iv) = y^{-\frac{1}{2}}e^{-6x}$[/tex]

On integrating both sides, we get

[tex]$Iv = \int y^{-\frac{1}{2}}e^{-6x}dx + C_1$[/tex]

On substituting back for v, we get

[tex]$y^{1-7} = \int y^{-\frac{1}{2}}e^{-6x}dx + C_1e^{6x}$[/tex]

On simplification, we get

[tex]$y = \left(\int y^{\frac{5}{7}}e^{-6x}dx + C_1e^{6x}\right)^{\frac{1}{5}}$[/tex]

On integrating, we get

[tex]$I = \int y^{\frac{5}{7}}e^{-6x}dx$[/tex]

For finding I, we can use integration by substitution by letting

[tex]$t = y^{\frac{2}{7}}$ and $dt = \frac{2}{7}y^{-\frac{5}{7}}dy$.[/tex]

Then [tex]$I = \frac{7}{2} \int e^{-6x}t dt = \frac{7}{2}\left(-\frac{1}{6}t e^{-6x} - \frac{1}{36}e^{-6x}t^3 + C_2\right)$[/tex]

On substituting [tex]$t = y^{\frac{2}{7}}$, we get$I = \frac{7}{2}\left(-\frac{1}{6}y^{\frac{2}{7}} e^{-6x} - \frac{1}{36}e^{-6x}y^{\frac{6}{7}} + C_2\right)$[/tex]

Finally, substituting for I in the solution, we get the general solution

[tex]$y = \left(\frac{7}{2}\left(-\frac{1}{6}y^{\frac{2}{7}} e^{-6x} - \frac{1}{36}e^{-6x}y^{\frac{6}{7}} + C_2\right) + C_1e^{6x}\right)^{\frac{1}{5}}$[/tex]

On applying the initial condition [tex]$y(0) = 0$[/tex], we get[tex]$C_1 = 0$[/tex]

On applying the initial condition [tex]$y(0) = 0$, we get$C_2 = \frac{2}{7}$[/tex]

So the solution to the differential equation is

[tex]$y = \left(\frac{7}{2}\left(-\frac{1}{6}y^{\frac{2}{7}} e^{-6x} - \frac{1}{36}e^{-6x}y^{\frac{6}{7}} + \frac{2}{7}\right)\right)^{\frac{1}{5}}$[/tex]

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9.  the number of ways to arrange k men and k women in a group is (2k)!.

a) To determine if the relation R is reflexive, we need to check if (a, a) ∈ R for all elements a ∈ A.

In this case, the relation R does not contain any pairs of the form (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), or (6, 6). Therefore, (a, a) ∈ R is not true for all elements a ∈ A, and thus the relation R is not reflexive.

b) To determine if the relation R is symmetric, we need to check if whenever (a, b) ∈ R, then (b, a) ∈ R.

In this case, we have (1, 2) and (2, 1) ∈ R, but we don't have (2, 1) ∈ R. Therefore, the relation R is not symmetric.

c) To determine if the relation R is transitive, we need to check if whenever (a, b) ∈ R and (b, c) ∈ R, then (a, c) ∈ R.

In this case, we have (1, 2) and (2, 1) ∈ R, but we don't have (1, 1) ∈ R. Therefore, the relation R is not transitive.

To summarize:

a) The relation R is not reflexive.

b) The relation R is not symmetric.

c) The relation R is not transitive.

8. a) To choose 12 individuals from a group of 19 firefighters and 16 police officers, we can use the combination formula. The number of ways to choose 12 individuals from a group of 35 individuals is given by:

C(35, 12) = 35! / (12!(35-12)!)

Simplifying the expression, we find:

C(35, 12) = 35! / (12!23!)

b) To choose a president, vice president, and secretary from the group of 16 police officers, we can use the permutation formula. The number of ways to choose these three positions is given by:

P(16, 3) = 16! / (16-3)!

Simplifying the expression, we find:

P(16, 3) = 16! / 13!

9. To arrange k men and k women in a group, we can consider them as separate entities. The total number of people is 2k.

The number of ways to arrange 2k people is given by the factorial of 2k:

(2k)!

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a. Loan amountThe total cost of the house is $182,000. The down payment is 20% of the cost of the house. Therefore, the down payment is $36,400.

The amount you will take out in a loan is the remaining amount left after you have paid your down payment. The remaining amount can be found by subtracting the down payment from the cost of the house. $182,000 - $36,400 = $145,600The loan amount is $145,600.

b. Monthly paymentsThe formula for calculating monthly payments is: Payment = (Loan amount * Interest rate * (1 + Interest rate) ^ number of payments) / (((1 + Interest rate) ^ number of payments) - 1)The interest rate is 4.3%.

The loan amount is $145,600. The loan term is 30 years or 360 months. Payment = (145600 * 0.043 * (1 + 0.043) ^ 360) / (((1 + 0.043) ^ 360) - 1)Payment = $722.52Therefore, the monthly payment is $722.52.c.

Total interestTo calculate the total interest paid, multiply the monthly payment by the number of payments and subtract the loan amount.Total interest paid = (Monthly payment * Number of payments) - Loan amount Total interest paid = ($722.52 * 360) - $145,600

Total interest paid = $113,707.20Therefore, the total interest paid is $113,707.20.d. Monthly payments for a 15-year loanTo calculate the monthly payments for a 15-year loan, the interest rate, loan amount, and number of payments should be used with the formula above.

Payment = (Loan amount * Interest rate * (1 + Interest rate) ^ number of payments) / (((1 + Interest rate) ^ number of payments) - 1)The interest rate is 4.3%. The loan amount is $145,600.

The loan term is 15 years or 180 months. Payment = (145600 * 0.043 * (1 + 0.043) ^ 180) / (((1 + 0.043) ^ 180) - 1)Payment = $1,100.95Therefore, the monthly payment is $1,100.95. e.

Savings in interest To calculate the savings in interest, subtract the total interest paid on the 15-year loan from the total interest paid on the 30-year loan. Savings in interest = Total interest paid (30-year loan) - Total interest paid (15-year loan)Savings in interest = $113,707.20 - $48,171.00

Savings in interest = $65,536.20Therefore, the savings in interest is $65,536.20.

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To find the compositions of f(x) = 2x and g(x) = x given in the problem, that is fog, gof, and 9°9, we first need to understand what each of them means. Composition of functions is an operation that takes two functions f(x) and g(x) and creates a new function h(x) such that h(x) = f(g(x)).

For example, if f(x) = 2x and g(x) = x + 1, then their composition, h(x) = f(g(x)) = 2(x + 1) = 2x + 2. Here, we have f(x) = 2x and g(x) = x.(a) fog We can find fog as follows: fog(x) = f(g(x)) = f(x) = 2x

Therefore, fog(x) = 2x.(b) gofWe can find gof as follows: gof(x) = g(f(x)) = g(2x) = 2x

Therefore, gof(x) = 2x.(c) 9°9We cannot find 9°9 because it is not a valid composition of functions

. The symbol ° is typically used to denote composition, but in this case, it is unclear what the functions are that are being composed.

Therefore, we cannot find 9°9. We have found that fog(x) = 2x and gof(x) = 2x.

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Answer:

24 meters

Step-by-step explanation:

To find the span of the pitched roof, we can use the given ratio of rise to span. The ratio states that for every 3 units of rise, there are 8 units of span.

Given that the rise of the roof is 9 meters, we can set up a proportion to solve for the span:

(3 units of rise) / (8 units of span) = (9 meters) / (x meters)

Cross-multiplying, we get:

3 * x = 8 * 9

3x = 72

Dividing both sides by 3, we find:

x = 24

Therefore, the span of the pitched roof is 24 meters.

(a) The volume using the Riemann sum:V ≈ Σ[[tex](x_i * y_i)[/tex] * (Δx * Δy)] for i = 1 to m, j = 1 to n

(b) V ≈ Σ[[tex](x_m * y_m)[/tex] * (Δx * Δy)] for i = 1 to m, j = 1 to n

To estimate the volume of the solid that lies below the surface z = xy and above the given rectangle R = (x, y) | 10 ≤ x ≤ 16, 6 ≤ y ≤ 10, we can use the provided methods: (a) Riemann sum with m = 3, n = 2 using the upper right corner of each square, and (b) Midpoint Rule.

(a) Riemann Sum with Upper Right Corners:

First, let's divide the rectangle R into smaller squares. With m = 3 and n = 2, we have 3 squares in the x-direction and 2 squares in the y-direction.

The width of each x-square is Δx = (16 - 10) / 3 = 2/3.

The height of each y-square is Δy = (10 - 6) / 2 = 2.

Next, we'll evaluate the volume of each square by using the upper right corner as the sample point. The volume of each square is given by the height (Δz) multiplied by the area of the square (Δx * Δy).

For the upper right corner of each square, the coordinates will be [tex](x_i, y_i),[/tex] where:

[tex]x_1[/tex] = 10 + Δx = 10 + (2/3) = 10 2/3

x₂ = 10 + 2Δx = 10 + (2/3) * 2 = 10 4/3

x₃ = 10 + 3Δx = 10 + (2/3) * 3 = 12

y₁ = 6 + Δy = 6 + 2 = 8

y₂ = 6 + 2Δy = 6 + 2 * 2 = 10

Using these coordinates, we can calculate the volume for each square and sum them up to estimate the total volume.

V = Σ[Δz * (Δx * Δy)] for i = 1 to m, j = 1 to n

To calculate Δz, substitute the coordinates [tex](x_i, y_i)[/tex] into the equation z = xy:

Δz = [tex]x_i * y_i[/tex]

Now we can estimate the volume using the Riemann sum:

V ≈ Σ[[tex](x_i * y_i)[/tex] * (Δx * Δy)] for i = 1 to m, j = 1 to n

(b) Midpoint Rule:

The Midpoint Rule estimates the volume by using the midpoint of each square as the sample point. The volume of each square is calculated similarly to the Riemann sum, but with the coordinates of the midpoint of the square.

For the midpoint of each square, the coordinates will be [tex](x_m, y_m)[/tex], where:

[tex]x_m[/tex] = 10 + (i - 1/2)Δx

[tex]y_m[/tex] = 6 + (j - 1/2)Δy

V ≈ Σ[[tex](x_m * y_m)[/tex] * (Δx * Δy)] for i = 1 to m, j = 1 to n

Now that we have the formulas, we can calculate the estimates for both methods.

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We need to consider the general problem: \[-(ku')' + cu' + bu = f\]If we discretize by the finite element method with four elements.

On the first and last elements, we use linear shape functions, and on the middle two elements, we use quadratic shape functions. The resulting basis functions are given by:The basis functions ϕ1 and ϕ4 are linear while ϕ2 and ϕ3 are quadratic in nature. These basis functions are such that they follow the property of linearity and quadratic nature on each of the elements.

For the structure of the stiffness matrix K, we need to consider the discrete problem given by \[KU=F\]where U is the vector of nodal values of u, K is the stiffness matrix and F is the load vector. Considering the above equation and assuming constant values of k and c on each of the element we can write\[k_{1}\begin{bmatrix}1 & -1\\-1 & 1\end{bmatrix}+k_{2}\begin{bmatrix}2 & -2 & 1\\-2 & 4 & -2\\1 & -2 & 2\end{bmatrix}+k_{3}\begin{bmatrix}2 & -1\\-1 & 1\end{bmatrix}\]Here, the subscripts denote the element number. As we can observe, the resulting stiffness matrix K is symmetric and has a banded structure.

The element [1 1] and [2 2] are common to two elements while all the other elements are present on a single element only. Hence, we have four elements with five degrees of freedom. Thus, the stiffness matrix will be a 5 x 5 matrix and the structure of K is as follows:

$$\begin{bmatrix}k_{1}+2k_{2}& -k_{2}& & &\\-k_{2}&k_{2}+2k_{3} & -k_{3} & & \\ & -k_{3} & k_{1}+2k_{2}&-k_{2}& \\ & &-k_{2}& k_{2}+2k_{3}&-k_{3}\\ & & & -k_{3} & k_{3}+k_{2}\end{bmatrix}$$Conclusion:In this question, we considered the general problem given by -(ku')' + cu' + bu = f. We discretized it by the finite element method with four elements. On the first and last elements, we used linear shape functions, and on the middle two elements, we used quadratic shape functions. We sketched the resulting basis functions. The structure of the stiffness matrix K was then determined by ignoring boundary conditions. We observed that it is symmetric and has a banded structure.

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The mean salary of 5 employees is $34000. The median is $34900. The mode is $36000. If the median paid employee gets a $3800 raise then, a) The new mean is $35,360. b) The new median is $36,000. c) The new mode is a bimodal set of $34,900 and $36,000.

Given that the mean salary of 5 employees is $34000, the median is $34900 and the mode is $36000.

If the median paid employee gets a $3800 raise, the new salaries will be:

$31,200, $34,900, $34,900, $36,000, and $36,000

Since there are two modes, both $36,000, it is a bimodal set.

Now, let's calculate the new mean, median and mode.

a) The new mean:

To find the new mean, we need to add the $3800 raise to the total salaries and divide by 5. So, the new mean is given by:

New Mean = ($31,200 + $34,900 + $34,900 + $36,000 + $36,000 + $3800) / 5

New Mean = $35,360

Therefore, the new mean is $35,360

b) The new median:

To find the new median, we need to arrange the new salaries in order and pick the middle one.

The new order is:$31,200, $34,900, $34,900, $36,000, $36,000 and $38,800

Since the new salaries have an odd number of terms, the median is the middle term, which is $36,000. Therefore, the new median is $36,000.

c) The new mode:

The mode of the new salaries is the value that appears most frequently. In this case, both $36,000 and $34,900 appear twice.

So, the new mode is $34,900 and $36,000. Hence, the new mode is a bimodal set of $34,900 and $36,000.

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The conversion rate of $1 to Chinese yuan is 0.1276. Therefore, to convert $17,000 to yuan, we multiply the amount in dollars by the conversion rate. Thus, $17,000 is equivalent to 2,169,200 yuan.

To convert $17,000 to yuan, we multiply the amount in dollars by the conversion rate. The conversion rate is given as $1 = 0.1276 yuan.

Therefore, the calculation is as follows:

$17,000 * 0.1276 yuan/$1 = 2,169,200 yuan.

So, $17,000 is equivalent to 2,169,200 yuan.

In summary, by multiplying $17,000 by the conversion rate of 0.1276 yuan/$1, we find that $17,000 is equivalent to 2,169,200 yuan.

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The rocket peaks at 906.43 meters above sea-level.

Given: h(t)=-4.9t² + 139t + 346

We know that the rocket will splash down into the ocean means the height of the rocket at splashdown will be 0,

So let's solve the first part of the question to find the time at which splashdown occur.

h(t)=-4.9t² + 139t + 346

Putting h(t) = 0,-4.9t² + 139t + 346 = 0

Multiplying by -10 on both sides,4.9t² - 139t - 346 = 0

Solving the above quadratic equation, we get, t = 28.7 s (approximately)

The rocket will splash down after 28.7 seconds.

Now, to find the height at the peak, we can use the formula t = -b / 2a,

which gives us the time at which the rocket reaches the peak of its flight.

h(t) = -4.9t² + 139t + 346

Differentiating w.r.t t, we get dh/dt = -9.8t + 139

Putting dh/dt = 0 to find the maximum height-9.8t + 139 = 0t = 14.18 s (approximately)

So, the rocket reaches the peak at 14.18 seconds

The height at the peak can be found by putting t = 14.18s in the equation

h(t)=-4.9t² + 139t + 346

h(14.18) = -4.9(14.18)² + 139(14.18) + 346 = 906.43 m

The rocket peaks at 906.43 meters above sea-level.

To find the time at which splashdown occur, we need to put h(t) = 0 in the given function of the height of the rocket, and solve the quadratic equation that results.

The time at which the rocket reaches the peak can be found by calculating the time at which the rate of change of height is 0 (i.e., when the derivative of the height function is 0).

We can then find the height at the peak by plugging in this time into the original height function.

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Answer:  A

Step-by-step explanation:

When multiplying: Numbers multiply with numbers and for the x's, add the exponents

If there is no exponent, you can assume an imaginary 1 is the exponent

2x⁴ (3x³ − x² + 4x)

= 6x⁷ -2x⁶ + 8x⁵

Answer:

A. [tex]6x^{7} - 2x^{6} + 8x^{5}[/tex]

Label the parts of the expression:

Outside the parentheses = [tex]2x^{4}[/tex]

Inside parentheses = [tex]3x^{3} -x^{2} + 4x[/tex]

You must distribute what is outside the parentheses with all the values inside the parentheses. Distribution means that you multiply what is outside the parentheses with each value inside the parentheses

[tex]2x^{4}[/tex] × [tex]3x^{3}[/tex]

[tex]2x^{4}[/tex] × [tex]-x^{2}[/tex]

[tex]2x^{4}[/tex] × [tex]4x[/tex]

First, multiply the whole numbers of each value before the variables

2 x 3 = 6

2 x -1 = -2

2 x 4 = 8

Now you have:

6[tex]x^{4}x^{3}[/tex]

-2[tex]x^{4}x^{2}[/tex]

8[tex]x^{4} x[/tex]

When you multiply exponents together, you multiply the bases as normal and add the exponents together

[tex]6x^{4+3}[/tex] = [tex]6x^{7}[/tex]

[tex]-2x^{4+2}[/tex] = [tex]-2x^{6}[/tex]

[tex]8x^{4+1}[/tex] = [tex]8x^{5}[/tex]

Put the numbers given above into an expression:

[tex]6x^{7} -2x^{6} +8x^{5}[/tex]

distribution

variable

like exponents

Naruto paid an interest of $55.25 to his credit card company for the purchase of his TV.

The interest Naruto paid for the purchase of his TV can be calculated using the simple interest formula:

Interest = Principal × Rate × Time

In this case, the principal is $850, the rate is 13% (or 0.13 as a decimal), and the time is 6 months (or 0.5 years). Plugging these values into the formula, we get:

Interest = $850 × 0.13 × 0.5 = $55.25

Therefore, Naruto paid an interest of $55.25 to his credit card company for the purchase of his TV.

The correct answer is option d. Naruto paid an interest of $55.25.

It's important to note that in this scenario, Naruto paid off the total cost of the TV after six months. Since the interest rate is annual, the interest is calculated based on the principal amount for the duration of six months. If Naruto had taken longer to pay off the TV or had not paid it off within a year, the interest amount would have been higher. However, in this case, Naruto paid off the TV before a year's time, so the interest amount is relatively low.

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