Find the Area.
help sos I need it please I have 15 minutes left to complete this​

Answer:

Hope this helps!! (x,y)=(6,-5)

Answer:

y=-5

x=6

Step-by-step explanation:

substitute y=4x -29 into the equation x+y=1.

x+ 4x-29 = 1

combine like terms

5x-29=1

add 29 to both sides

5x=30

divide by 5

x=6

plug 6 into x in the original equation

y=4(6) - 29

y=24-29

y= -5

Answer:

32%

Step-by-step explanation:

100 - 68

Answer:

32%

Step-by-step explanation:

subtract 68 from 100 to get your answer

Answer:

It is -0.465 when you add it to the nearest thousandth

Step-by-step explanation:

The equation that has the possible values of b is b² = 4.

The equation that has the possible value of b as -2 and 2 are as follows;

b² = 4

-2² = 4 and 2² = 4 (This is true)

b³ = 8

-2³ = -8 and 2³ = 8(This is false)

Therefore, the equation that has the possible values of b is b² = 4.

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Answer:

Step-by-step explanation:

Here,

<BAC + <BAE = 180° [Since supplementary angles]

=> 52° + <BAE = 180°

=> <BAE = 180° -52°

=> <BAE = 128° (Ans)

Answer:

46

Step-by-step explanation:

Hi there! You still remember the Pythagorean Theorem, right? It's useful when it comes to finding a missing leg or side of a right triangle. If you forget then here it is:

[tex] \large \boxed{ {a}^{2} + {b}^{2} = {c}^{2} }[/tex]

Define c = hypotenuse while a and b can be both adjacent and opposite (because a²+b²=b²+a² via addition property)

Since we are missing the adjacent side. Thus,

We define a = 6 and c = 14.

[tex] \large{ {6}^{2} + {b}^{2} = {14}^{2} } \\ \large{36 + {b}^{2} = 196} \\ \large{ {b}^{2} = 196 - 36} \\ \large{ {b}^{2} = 160} \\ \large{ b = \sqrt{160} \longrightarrow \boxed{b = 4 \sqrt{10} }}[/tex]

Put the value of b in a calculator then round to the nearest tenth and get 12.6

Thus, the value of b ≈ 12.6

Next we are going to find the angle in degree. We now know that b ≈ 12.6 or 4sqrt(10)

We can find the value of angle A by using tan or sin but I will use sin instead. Recall the sine ratio which is opposite to hypotenuse. Thus,

[tex] \large{sinA = \frac{6}{14} }[/tex]

Use arcsin(6/14) and put it in calculator.

Then put the decimal value of arcsin in sin and convert in degree form which we should get 24. 555°. Round to the nearest whole number and we get 25°

Thus, the angle A is 25°

Next is we are finding the value of angle B. We aren't going to use any formula or equation. Recall that three angles add up to 180°.

Thus, 25° + 90° + x = 180°

90° comes from a right angle.

115+x = 180

x = 180-115

x = 65°

Thus, the angle B is 65°

Answer

Answer:

#1

#2

#3

Answer:

5 miles but she did walk part of another mile so that would be 5.35.

Step-by-step explanation:

Answer:

the perimeter 126 cm

Answer:

1. Volume measured in Cubic units (to the third power), Only 3-D objects have volume.

2. Parallel lines have the same slope and will never intersect. The slope of perpendicular lines are the negative reciprocals of each other, they will intersect a 90 degrees

3. Secant is 1/cosX (1 over cosine of x), tangent is sinX/cosX(sine of x over cosine of x)

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

the answer is c because there is more then one y value for 5

Answer:

correct answer is D i think so

Answer:

16x^(2)+40y^(6)

Step-by-step explanation:

Answer:

Area of red triangle =1/2 ×side a*side b

=½×90×120=5400ft²

Answer:

b

Step-by-step explanation:

Answer:

A. 10.4 mph

Step-by-step explanation:

26÷2.5=10.4

Double checking your answer:

If she does 10.4 miles in an hour, she can get 20.8 in two hours

then you add half of how much she can go in an hour which is 5.2 (10.4÷2)

you add it together, and you will get 26 miles in total

(20.8+5.2=26)

Answer:

4 and 5

Step-by-step explanation:

So alternate means there's on different sides of the one line that cuts through both lines, so that would be 1 and 8, 2 and 7, 3 and 6, and 4 and 5. But interior means that it's on the inside, so that would be 3 and 6, and 4 and 5, so 4 and 5 is your answer

hope this helps:)

Answer:

C

Step-by-step explanation:

Area of a square = s² ; where s = side length

Area of square = 88 unit²

88 = s²

Square root of both sides

√88 = s

9.38 = s

Answer:

i dont know im sorry

Step-by-step explanation:

Answer:

there could be three different.

Step-by-step explanation:

it could be a combination of the two genders that can make them different :)

Answer:

7x - 1/9

Step-by-step explanation:

2/3 (6x - 1/6) + 3x

12x/3 - 2/18 + 3x

4x - 1/9 + 3x

7x - 1/9

After simplifying, the value of expression is,

⇒ 7x - 1/9

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

We have to given that;

The expression is,

⇒ 2/3 (6x - 1/6) + 3x

Now, We can solve the expression as;

⇒ 2/3 (6x - 1/6) + 3x

⇒ 2/3 × 6x - 2/3 × 1/6 + 3x

⇒ 4x - 1/9 + 3x

⇒ 7x - 1/9

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Answer:

Option C: n = 32; p^ = 0.4

Step-by-step explanation:

The normal curve can be used in this case if; np ≥ 10 or n(1 - p) ≥ 10

A) For n = 28 and p = 0.3;

np = 28 × 0.3 = 8.4 < 10

Thus, it can't be used.

B) For n = 28 and p = 0.9;

np = 28 × 0.9 = 25.2 > 10 Ok

n(1 - p) = 28(1 - 0.9) = 2.8 Not Ok

Thus, it can't be used

C) For n = 32 and p = 0.4

np = 32 × 0.4 = 12.8 > 10 Ok

n(1 - p) = 32(1 - 0.4) = 19.2 > 10 Ok

Thus, it can be used

D) For n = 32 and p = 0.2

np = 32 × 0.2 = 6.4 < 10 Not Ok

Thus it can't be used.

Answer:

B and E

Step-by-step explanation:

Answer:

Firs property used : Quotient Property

           [tex]log_b(\frac{X}{Y} ) = log_bX -log_bY[/tex]

   [tex]log_b(\frac{\sqrt[3]{x} }{36y^2} ) = log_b(\sqrt[3]{x}) - log_b(36y^2)[/tex]

Second property used : Product Property

          [tex]log_b(XY) = log_bX + log_b Y[/tex]

    [tex]log_b(\sqrt[3]{x}) - log_b(36y^2) = (log_b(\sqrt[3]{x}) - [log_b36 + log_by^2)[/tex]

Third property used : Power Property

                 [tex]log_b \sqrt[n]{X} = log_b(X)^{\frac{1}{n}} = \frac{1}{n} log_b X[/tex]

 [tex](log_b(\sqrt[3]{x}) - [log_b6^2 + log_by^2) = \frac{1}{3} log_bx - 2log_b 6 - 2log_by[/tex]

Fully expanded form:

                   [tex]log_b(\frac{\sqrt[3]{x} }{36y^2} ) = \frac{1}{3} log_b x-2log_b6-2log_by[/tex]

Answer:

green because it sounds like garbage

Step-by-step explanation:

Answer:

the one u want to put em in?

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

d is not true because width and thickness doesn't matter