Find the area of this triangle. Round to the nearest tenth. 9.5 yd 23 yd
Please help!
Answers
Answer:
[tex]Area=\frac{ab}{2} \\\\area=\frac{9.5.23}{2} \\\\answer=108.8 yd^{2}[/tex]
Step-by-step explanation:
I hope this helps ^_^
The area of the triangle is 108.7 square yards.
What is the area of the triangle?Let a, b, and c is the sides of the triangle.
The area of the triangle is given as
S = (a + b + c) / 2
[tex]\rm A = \sqrt{s(s - a)(s - b)(s -c )}[/tex]
The third side of the triangle will be
c² = a² + b² - 2ab cos θ
c² = 9.5² + 23² - 2 × 9.5 × 23 × cos 85°
c² = 619.25 - 38.09
c² = 581.16
c = 24.11 yd
Then the area of the triangle will be
S = (9.5 + 23 + 24.11) / 2
S = 56.61 / 2
S = 28.3
Then the area will be
[tex]\rm A = \sqrt{28.3(28.3 - 24.11)(28.3 - 23)(28.3 - 9.5)}[/tex]
Simplify the expression, then the value will be
A = √11815.01
A = 108.7 square yd
The area of the triangle is 108.7 square yards.
More about the area of the triangle link is given below.
https://brainly.com/question/19305981
#SPJ2
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