Find the area of the triangle below.

Answer:

no.1 -5040 is the correct answer

Answer:

614

Step-by-step explanation:

15 x 13 = 195    two times   195 x 2 = 390

4 x 15 = 60    two times   60 x 2 = 120

4 x 13 = 52      two times   52 x 2 = 104

104 + 120 + 390 = 614

Answer:

SA = 2(l·w)+2(w·h)+2(l·h)

SA = 614 sq in

Step-by-step explanation:

SA = 2(4x13)+2(13x15)+2(4x15)

= 2(52)+2(195)+2(60)

= 104 + 390 + 120

= 614

Answ  Find the distance between the following pairs of points:

           (i) (2, 3), (4, 1) (ii) (–5, 7), (–1, 3) (iii) (a, b), (–a, –b)Sol. (i) Here x1 = 2, y1 = 3, x2 = 4 and y2 = 1         ∴ The required distance         er:

Step-by-step explanation:

Answer:

You download math apps

Step-by-step explanation:

I don't know, I tried to learn it- even the basics- but I vomited on the kitchen table as soon as I practiced an equation.

I'm allergic to algebra.

Answer:

she eat 10 Strawberries and puts 18 in her basket

Answer: she eats 10 strawberries, and she puts 15 in the basket.

Step-by-step explanation:

Answer: 1.016

Step-by-step explanation: multiply the length value by 2.54

1016

multiply the length value by 2.54

Answer:

8 pounds total

Step-by-step explanation:

first calculate how much she used in total

1/4 + 3/8

need like denominators so multiply 1/4 by 2

2/8 + 3/8 = 5/8

so 5/8 of the total is 5 pounds, now find the total

if 5/8 = 5, then 8/8 = _8_

Answer:

Step-by-step explanation:

V = 1/3 * pi * r^2 * h

d = 12

r = d/2

r = 12/2

r = 6

V = 1/3 * 3.14 * 6^2 * 8

V = 301.44

Answer: C: the Delian problem

Step-by-step explanation: the Delian problem includes doubling a cube which was a famous impossible problem

The most famous impossible problem from Greek antiquity is The Delian problem.

What is Greek antiquity?

The Greek difficulties of antiquity were a collection of geometric issues, and the only tools available to solve them were a compass and a straightedge. The only problems are:

Solution:

The Delian problem, doubling the cube, is considered one of the most famous impossible problems from Greek antiquity. Two others are the trisection of the general angle and squaring of a circle(also a famous problem)

Whereas the other options like the Koch curve, bisecting any angle and playfair's axiom is known for its possibilities.

Hence the Delian problem is the most famous impossible problem from Greek antiquity.

Learn more about "Greek antiquity" here-

brainly.com/question/4231872

#SPJ2

Answer:

The person must kick the ball around 31.62 feet high (They really want an apple!)

Step-by-step explanation:

If you think about it, the diagram will look like a triangle, so using the Pythagorean theorem, (a² + b² = c²), you will get around 31.62.

Have a good ay :)

Answer: 31.62

Step-by-step explanation:

Answer:

at 5 hrs he two company will charge the same amount .

Step-by-step explanation:

let the same hrs be x

now,

50+36x = 35+39x

50-35 =39x-36x

15=3x

x=15/3

x=5

Answer:141.3

Step-by-step explanation:

The volume would be the Cone + Cylinder. So, use 1/3 x pi x r^2 x h and since the height is 6-3=3, you get 9 x 3.14 x 6 x 1/3 which is 56.52. The volume of the cylinder is pi x r^2 x h, which is 9 x 3.14 x 3, is 84.78. Now, add 56.52+84.78 = 141.3. Hope this helps

Answer: 125 mg per serving for orange juice. 90 mg per serving for cranberry

Step-by-step explanation:

Answer:

x = -16 or x = 6

Step-by-step explanation:

To find the roots of a polynomial function, set the polynomial equal to zero and solve for x.

x² + 10x - 96 = 0

We need to factor the left side. The left side is a quadratic polynomial whose first coefficient is 1. We need two numbers whose product is -96 and whose sum is 10. The numbers are 16 and -6.

(x + 16)(x - 6) = 0

If a product of two factors equals zero, then one factor or the other or both must equal zero.

x + 16 = 0  or  x - 6 = 0

x = -16 or x = 6

Answer:

-9

Step-by-step explanation:

Using the sum/difference property of logarithms, we can rewrite the expression given as:

log b^3 + log c^3 - log √(a^3) --> log √(a^3) can also be written as log a^1.5

Next, we can use the power property of logarithms, and rewrite it again as:

3log b + 3log c - 1.5log a

Now, we can substitute the values of log a, log b, and log c:

3(11) + 3(-9) - 1.5(10)

33 - 27 - 15

-9

Simplifying, we get -9 as the answer.

Answer:

$22.95

Step-by-step explanation:

Given data

Value=$22.50.

Percent increase= 2%

Let us find the value of 2% increase

=2/100*22.50

=0.02*22.50

=$0.45

Hence the total value at the end of the day is

=22.50+0.45

=$22.95

Answer:

x = 7; y = 8; z = 5

Step-by-step explanation:

x = 15 - y

y = 13 - z

z = 12 - x

The first equation is solved for x. Substitute x in the third equation with 15 - y from the first equation.

z = 12 - (15 - y)

z = 12 - 15 + y

z = y - 3       (Equation 1)

Now substitute y - 3 for z in the original second equation.

y = 13 - z

y = 13 - (y - 3)

y = 13 - y + 3

2y = 16

y = 8

Substitute 8 for y in Equation 1.

z = y - 3

z = 8 - 3

z = 5

Substitute 5 for z in the original third equation.

5 = 12 - x

-7 = -x

x = 7

Solution: x = 7; y = 8; z = 5

Answer:

A) 0.27

B) 1/4 = 0.25

C) 3/8 = 0.375

D) 2/ 11 = 0.1818

E) 11% = 0.11

E is the correct answer

Step-by-step explanation:

Answer:

E)

Step-by-step explanation:

A) 27.0

B) .25

C) .375

D) .22

E) .11

Answer:

c

Step-by-step explanation:

Because [tex]\frac{c}{c}[/tex] is 1 the equation turns into...

[tex]c^{4-3}[/tex]

which equals...

[tex]c^{1}[/tex]

and [tex]c^{1}[/tex] is just c

Answer:

i got 0.048%

Step-by-step explanation:

Answer:

r=3.54%

Step-by-step explanation:

Answer:

A =30 degrees

angle at circumference is 2x the angle in the centre

Answer:

[tex]7^{\frac{1}{3} }[/tex]

Step-by-step explanation:

Using the rule of exponents

[tex]\sqrt[n]{a^{m} }[/tex] ⇔ [tex]a^{\frac{m}{n} }[/tex] , then

[tex]\sqrt[6]{7^{2} }[/tex] = [tex]7^{\frac{2}{6} }[/tex] = [tex]7^{\frac{1}{3} }[/tex]

Answer:

Yes, because \overline{BC}  

BC

start overline, B, C, end overline is perpendicular to \overline{AB}  

AB

start overline, A, B, end overline, and ABCDABCDA, B, C, D is a parallelogram.

Step-by-step explanation:

I did it on khan academy and I got it right

Answer:

Area of remaining plastic = 36.55 cm² (Approx.)

Step-by-step explanation:

Given:

Diameter of plastic dial of telephone = 8 cm

Diameter of middle hole = 4 cm

Diameter of ten small holes = 1.2 cm

Find:

Area of remaining plastic

Computation;

Radius of plastic dial of telephone = 8/2 = 4 cm

Radius of middle hole = 4/2 = 2 cm

Radius of ten small holes = 1.2/2 = 0.6 cm

Area of remaining plastic = Area of plastic dial - Area of middle hole - 10[Area of small holes]

Area of remaining plastic = π(4)² - π(2)² - π(0.6)²

Area of remaining plastic = π(16) - π(4) - π(0.36)

Area of remaining plastic = π[16 - 4 - 0.36]

Area of remaining plastic = π[11.64]

Area of remaining plastic = (3.14)(11.64)

Area of remaining plastic = 36.5496

Area of remaining plastic = 36.55 cm² (Approx.)

Answer:

14.49

Step-by-step explanation:

Answer:

3 / 8

Step-by-step explanation:

From the tree diagram provided :

Required outcome = atleast two consecutive tails :

(HTT) ; (TTH) ; (TTT) = 3

TOTAL POSSIBLE OUTCOMES = 8

PROBABILITY = REQUIRED OUTCOME / TOTAL POSSIBLE OUTCOMES

HENCE ;

P(ATLEAST TWO TAILS IN A ROW) = 3 / 8

Answer:

look at the picture I have sent

Answer:

D

Step-by-step explanation:

Using the sine ratio or the cosine ratio in the right triangle.

Choosing the sine ratio with the exact value

sin45° = [tex]\frac{\sqrt{2} }{2}[/tex] , then

sin45° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{x}{10}[/tex] = [tex]\frac{\sqrt{2} }{2}[/tex] ( cross- multiply )

2x = 10[tex]\sqrt{2}[/tex] ( divide both sides by 2 )

x = 5[tex]\sqrt{2}[/tex] → D

Answer:

Yes

Hope that this helps!

Answer:

yes -2 is less then 6

Answer:

[tex] \sin( \theta) = \frac{24}{25} \\ \theta = { \sin }^{ - 1} ( \frac{24}{25} ) \\ \theta = 73.7 \degree \\ \\ \tan( \theta) = \tan(73.7 \degree) \\ = 3.4[/tex]