Answer:
Step-by-step explanation:
Well, since it was not given the interval let's use the interval [0,5] with n=10
So now, for the Trapezoidal Rule to approximate the area enclosed by the Integral of: [tex]f(x)=7\pi \sin(x)[/tex]
[tex]T_{10}=\frac{b-a}{2n}[f(a)+2f(x_1)+ ....2f(x_{n-1})+f(b)][/tex] Plugging in:
[tex]T_{10}=\frac{5-0}{2*10}[f(0)+2f(\frac{1}{2})+2f(1)+2f(\frac{3}{2})+2f(2)+2f(5/2)+2f(3)+2f(7/2)+2f(4)+2f(9/2) +f(5)][/tex]
[tex]T_{10}=\frac{1}{4}[0+21.086+37+43.87+39.99+26.322+6.20-15.43-33.285-42.99-21.087][/tex]
[tex]T_{10}\approx 15.419[/tex]
Now the same area according to Simpson rule:
[tex]S_{10}=\frac{b-a}{3n}[f(a)+4f(x_{1})+2f(x_{2})+4f(x_{3} )+2f(x_{4})+4f(x_{5})+2f(x_{6})+4f(x_{7})+2f(x_{8})+4f(x_{9})+f(b)]\\S_{10}=\frac{5}{3*10}[0+74.01+43.87+79.98+26.322+12.413-15.43-66.571-42.99-21.08]\approx 15.085[/tex]
[tex]S_{10}\approx 15.0585[/tex]
A veterinarian is enclosing a rectangular outdoor running area against his building for the dogs he cares for. He needs to maximize the area using 100 feet of fencing. The quadratic function A(x)=x(100−2x) gives the area, A, of the dog run for the length, x, of the building that will border the dog run. Find the length of the building that should border the dog run to give the maximum area, and then find the maximum area of the dog run.
Answer:
a) The length of the building that should border the dog run to give the maximum area = 25feet
b) The maximum area of the dog run = 1250 s q feet²
Step-by-step explanation:
Step(i):-
Given function
A(x) = x (100-2x)
A (x) = 100x - 2x²...(i)
Differentiating equation (i) with respective to 'x'
[tex]\frac{dA}{dx} = 100 (1) - 2 (2x)[/tex]
⇒ [tex]\frac{dA}{dx} = 100 - 4 x[/tex] ...(ii)
Equating zero
⇒ 100 - 4x =0
⇒ 100 = 4x
Dividing '4' on both sides , we get
x = 25
Step(ii):-
Again differentiating equation (ii) with respective to 'x' , we get
[tex]\frac{d^{2} A}{dx^{2} } = -4 (1) < 0[/tex]
Therefore The maximum value at x = 25
The length of the building that should border the dog run to give the maximum area = 25
Step(iii)
Given A (x) = x ( 100 -2 x)
substitute 'x' = 25 feet
A(x) = 25 ( 100 - 2(25))
= 25(50)
= 1250
Conclusion:-
The maximum area of the dog run = 12 50 s q feet²
After scoring a touchdown, a football team may elect to attempt a two-point conversion, by running or passing the ball into the end zone. If successful, the team scores two points. For a certain football team, the probability that this play is successful is 0.40.
a.â Let X =1 if successful, X= 0 if not. Find the mean and variance of X.
b.â If the conversion is successful, the team scores 2 points; if not the team scores 0 points. Let Y be the number of points scored. Does Y have a Bernoulli distribution? If so, find the success probability. If not, explain why not.
c.â Find the mean and variance of Y.
Answer:
a) Mean of X = 0.40
Variance of X = 0.24
b) Y is a Bernoulli's distribution. Check Explanation for reasons.
c) Mean of Y = 0.80 points
Variance of Y = 0.96
Step-by-step explanation:
a) The probability that play is successful is 0.40. Hence, the probability that play isn't successful is then 1 - 0.40 = 0.60.
Random variable X represents when play is successful or not, X = 1 when play is successful and X = 0 when play isn't successful.
The probability mass function of X is then
X | Probability of X
0 | 0.60
1 | 0.40
The mean is given in terms of the expected value, which is expressed as
E(X) = Σ xᵢpᵢ
xᵢ = each variable
pᵢ = probability of each variable
Mean = E(X) = (0 × 0.60) + (1 × 0.40) = 0.40
Variance = Var(X) = Σx²p − μ²
μ = mean = E(X) = 0.40
Σx²p = (0² × 0.60) + (1² × 0.40) = 0.40
Variance = Var(X) = 0.40 - 0.40² = 0.24
b) If the conversion is successful, the team scores 2 points; if not the team scores 0 points. If Y ia the number of points that team scores.Y can take on values of 2 and 0 only.
A Bernoulli distribution is a discrete distribution with only two possible outcomes in which success occurs with probability of p and failure occurs with probability of (1 - p).
Since the probability of a successful conversion and subsequent 2 points is 0.40 and the probability of failure and subsequent 0 point is 0.60, it is evident that Y is a Bernoulli's distribution.
The probability mass function for Y is then
Y | Probability of Y
0 | 0.60
2 | 0.40
c) Mean and Variance of Y
Mean = E(Y)
E(Y) = Σ yᵢpᵢ
yᵢ = each variable
pᵢ = probability of each variable
E(Y) = (0 × 0.60) + (2 × 0.40) = 0.80 points
Variance = Var(Y) = Σy²p − μ²
μ = mean = E(Y) = 0.80
Σy²p = (0² × 0.60) + (2² × 0.40) = 1.60
Variance = Var(Y) = 1.60 - 0.80² = 0.96
Hope this Helps!!!
One common system for computing a grade point average (GPA) assigns 4 points to an A, 3 points to a B, 2 points to a C, 1 point to a D, and 0 points to an F. What is the GPA of a student who gets an A in a -credit course, a B in each of -credit courses, a C in a -credit course, and a D in a -credit course?
Question Correction
One common system for computing a grade point average (GPA) assigns 4 points to an A, 3 points to a B, 2 points to a C, 1 point to a D, and 0 points to an F. What is the GPA of a student who gets an A in a 3-credit course, a B in each of three 4-credit courses, a C in a 2-credit course, and a D in a 3-credit course?
Answer:
2.75
Step-by-step explanation:
We present the information in the table below.
[tex]\left|\begin{array}{c|c|c|c}$Course Grade&$Grade Point(x)&$Course Credit(y)&$Product(xy)\\---&---&---&---\\A&4&3&12\\B&3&4&12\\B&3&4&12\\B&3&4&12\\C&2&2&4\\D&1&3&3\\---&---&---&---\\$Total&&20&55\end{array}\right|[/tex]
Therefore, the GPA of the student is:
[tex]GPA=\dfrac{55}{20}\\\\ =2.75[/tex]
One of the solutions to x2 − 2x − 15 = 0 is x = −3. What is the other solution?
20 points if you can answer in under 30 minuets
Answer:
x=5 x=-3
Step-by-step explanation:
x^2 − 2x − 15 =0
Factor
What two numbers multiply to -15 and add to -2
-5*3 = -15
-5+3 =-2
(x-5) (x+3)=0
Using the zero product property
x-5 =0 x+3 =0
x=5 x=-3
Answer:
x^2 - 2x - 15 = 0
(x - 5) (x + 3) = 0
x - 5 = 0
x = 5
x + 3 = 0
x = -3
find the solution set x^2+2x-15=0
Answer:
x = 3 or x = -5
Step-by-step explanation:
x² + 2x - 15 = 0
Factor left side of equation.
(x - 3)(x + 5) = 0
Set factors equal to 0
x - 3 = 0
x = 3
x + 5 = 0
x = -5
Suppose that $n, n+1, n+2, n+3, n+4$ are five consecutive integers. Determine a simplified expression for the sum of these five consecutive integers.
Answer:
5n + 10
Step-by-step explanation:
We would like to find the sum of these 5 integers. Simply add them up:
n + (n + 1) + (n + 2) + (n + 3) + (n + 4) = 5n + (1 + 2 + 3 + 4) = 5n + 10
The answer is thus 5n + 10.
~ an aesthetics lover
Answer:
5n + 10
Step-by-step explanation:
We need to add the five consecutive integers.
n + n + 1 + n + 2 + n + 3 + n + 4
Rearrange.
n + n + n + n + n + 1 + 2 + 3 + 4
Add.
5n + 10
The height of a certain plant is determined by a dominant allele T corresponding to tall plants, and a recessive allele t corresponding to short (or
dwarf) plants. If both parent plants have genotype Tt, compute the probability that the offspring plants will be tall. Hint: Draw a Punnett square.
(Enter your probability as a fraction.)
Answer:
The probability of the plants being tall is equal to P(TT) + P(Tt)= 1/4+1/2=3/4
Step-by-step explanation:
Hello!
The characteristic "height" of a plant is determined by the alleles "tall" T (dominant) and "short" a (recessive). If both parents are Tt, you have to calculate the probability of the offspring being tall (TT or Tt)
To construct the Punnet square you have to make a table, where the parental alleles will be in the margins, for example: the father's alleles in the columns and the mother's alleles in the rows.
Each parent will produce a haploid gamete that will carry one of the alleles, so the probability for the offspring receiving one of the alleles is 1/2
Father (Tt): gametes will carry either the dominant allele T or the recessive allele t with equal probability 1/2
Mother (Tt): gametes will also carry either the dominant allele T or the recessive allele t with equal probability 1/2
Then you have to cross each allele to determine all possible outcomes for the offsprings. For each cell, the probability of obtaining both alleles will be the product of the probability of each allele (See attachment)
First combination, the offspring will receive one dominant allele from his father and one dominant allele from his mother: TT, the probability of obtaining an offspring with this genotype will be P(T) * P(T) = 1/2*1/2=1/4
Second combination, the offspring will receive the recessive allele from the father and the dominant allele from the mother, then its genotype till be tT with probability: P(t)*P(T)= 1/2*1/2=1/4
Third combination, the offspring will receive one dominant allele from his father and one recessive allele from his mother, the resulting genotype will be Tt with probability: P(T)*P(t)= 1/2*1/2=1/4
Combination, the offspring will receive both recessive alleles from his parents, the resulting genotype will be tt with probability: P(t)*P(t)= 1/2*1/2=1/4
So there are three possible genotypes for the next generation:
TT with probability P(TT)= 1/4
Tt with probability: P(Tt)+P(tT)=1/4+1/4=1/2⇒ This genotype is observed twice so you have to add them.
tt with probability P(tt)= 1/4
Assuming this genotype shows complete dominance, you'll observe the characteristic "Tall" in individuals that carry the dominant allele "T", i.e. individuals with genotype "TT" and "Tt"
So the probability of the plants being tall is equal to P(TT) + P(Tt)= 1/4+1/2=3/4
I hope this helps!
what is the solution for the inequality l2x-6l<4
Answer:
x < 5 or x > 1
Step-by-step explanation:
2x - 6 < 4
2x < 4 + 6
2x < 10
x < 10/2
x < 5
2x - 6 > - 4
2x > - 4 + 6
2x > 2
x > 2/2
x > 1
Create a transformation that is not a similarity transformation. Use coordinate notation .
Answer:
(x, y) ⇒ (2x, y)
Step-by-step explanation:
Any rigid transformation or dilation will be a similarity transformation. A transformation that doesn't preserve similarity will be none of those, so may be non-linear or different in one direction than another.
Several possibilities come to mind:
(x, y) ⇒ (2x, y) . . . . . . stretches x, but not y
(x, y) ⇒ (x+y, y) . . . . . a "shear" transformation
(x, y) ⇒ (x, y^(3/2)) . . . . . a non-linear transformation
These only transform one coordinate. Of course, different transforms or combinations can be used on the different coordinates.
__
The attachment shows the effect of each of these. The red figure is the original icosagon (20-gon). The blue figure shows the horizontal stretch of the first transformation. The green figure shows the diagonal stretch of the shear transformation. The purple figure shows the effect of a non-linear transformation.
x = ? ? ? ? ? ? ? ? ?
Answer:
7
Step-by-step explanation:
Answer:
x = 3
Step-by-step explanation:
Two secants drawn to a circle from an external point, then
The product of the measures of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant.
Thus
x × 12 = 4 × 9
12x = 36 ( divide both sides by 12 )
x = 3
Abigail and Liza Work as carpenters for different companies Abigail earns $20 Per hour at her company and Liza Word for a total of 30 hours in together earned a total of 690 how many hours did Liza work last week?
This question was not properly written, hence it is incomplete. The complete question is written below:
Complete Question:
Abigail and Liza work as carpenters for different companies. Abigail earns $20 per hour at her company and Liza earns $25 per hour at her company. Last week, Abigail and Liza worked for a total of 30 hours and together earned a total of $690. How many hours did Liza work last week?
Answer:
Lisa worked for 18 hours last week
Step-by-step explanation:
Let the number of hours Abigail worked last week = A
Let the number of hours Liza worked last week = B
Abigail earns = $20 per hour at her company
Liza earns = $25 per hour at her company
A + B = 30 ........... Equation 1
B = 30 - A
20 × A + 25 × B = 690
20A + 25B = 690 ............... Equation 2
Substitute 30 - A for B in Equation 2
Hence, we have:
20A + 25(30 - A) = 690
20A + 750 - 25A = 690
Collect like terms
20A - 25A = 690 - 750
-5A = -60
A = -60/-5
A = 12
Since A represents the number of hours Abigail worked, Abigail worked for 12 hours last week.
Substitute 12 for A in Equation 1
A + B = 30
12 + B = 30
B = 30 - 12
B = 18
Since B represents the number of hours Liza worked, therefore, Liza worked for 18 hours last week.
Please answer this correctly
Answer:
2/3
Step-by-step explanation:
There are 2 numbers out of 3 that fit the rule, 1 and 3. There is a 2/3 chance picking one of them.
Answer:
2/3Step-by-step explanation:
This is the answer because one number that is select is one. A number greater than 2 is 3. SO it is 2/3.
Don’t understand this, if anyone can help that would be awesome. :)
Answer:
look up the basic rules for sin and cos
Step-by-step explanation:
which of the following has a value less than 0?
A.4
B. |4|
C. |-4|
D. -4
Answer:
D
Step-by-step explanation:
The numbers that are less than 0 are negative. Negative numbers have the "-" sign in front of them so the answer is D.
Answer:
d
Step-by-step explanation:
The other ones will always be positive four
The smaller of two numbers is one-half the larger, and their sum is 27. Find the
numbers.
Answer:
9 and 18
Step-by-step explanation:
The numbers are in the ratio 1 : 2, so the ratio of the smaller to the total is ...
1 : (1+2) = 1 : 3
1/3 of 27 is 9, the value of the smaller number. The larger number is double this, so is 18.
The numbers are 9 and 18.
Answer:
9 and 18
Step-by-step explanation:
you know the explanation since another guy put it
the required condition for using an anova procedure on data from several populations for mean comparison is that the
Answer:
The sampled populations have equal variances
Step-by-step explanation:
ANOVA which is fully known as Analysis of variances can be defined as the collection of statistical models as well as their associated estimation procedures which enables easily and effectively analyzis of the differences among various group means in a sample reason been that ANOVA is a total variance in which the observed variance in a specific variable is been separated into components which are attributable to various sources of variation which is why ANOVA help to provides a statistical test to check whether two or more population means are equal.
Therefore the required condition for using an ANOVA procedure on data from several populations for mean comparison is that THE SAMPLED POPULATION HAVE EQUAL VARIANCE.
For the functions f(x)=3x−1 and g(x)=4x−3, find (f∘g)(x) and (g∘f)(x)
About ____% of the area is between z= -2 and z= 2 (or within 2 standard deviations of the mean)
Answer:
The percentage of area is between Z =-2 and Z=2
P( -2 ≤Z ≤2) = 0.9544 or 95%
Step-by-step explanation:
Explanation:-
Given data Z = -2 and Z =2
The probability that
P( -2 ≤Z ≤2) = P( Z≤2) - P(Z≤-2)
= 0.5 + A(2) - ( 0.5 - A(-2))
= A (2) + A(-2)
= 2 × A(2) (∵ A(-2) = A(2)
= 2×0.4772
= 0.9544
The percentage of area is between Z =-2 and Z=2
P( -2 ≤Z ≤2) = 0.9544 or 95%
Find the 61st term of the following arithmetic sequence.
15, 24, 33, 42,
Answer:
The answer is
555Step-by-step explanation:
For an nth term in an arithmetic sequence
[tex]U(n) = a + (n - 1)d[/tex]
where n is the number of terms
a is the first term
d is the common difference
From the question
a = 15
d = 24 - 15 = 9
n = 61
So the 61st term of the arithmetic sequence is
U(61) = 15 + (61-1)9
= 15 + 9(60)
= 15 + 540
= 555
Hope this helps you.
Identify all the central angles
Answer:
Option 4
Step-by-step explanation:
The central angles are "Angles in the center"
So,
Central Angles are <AOB, <BOC and <AOC
Answer:
<AOB, <BOC and < AOC
Step-by-step explanation:
There are 3 angles at center O . The largest is <AOC ( = 180 degrees). Thn you have 2 more each equal to 90 degrees.
What is the equation of the line which passes through (-0.5,-5) and (2,5)
Answer:
by using distance formula
d=[tex]\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]
by putting the values of coordinates
[tex]d=\sqrt{(2-(-0.5))^2+(5-(-5))^2}[/tex]
[tex]d=\sqrt{(2+0.5)^2+(5+5)^2}[/tex]
[tex]d=\sqrt{(2.5)^2+(10)^2}[/tex]
[tex]d=\sqrt{6.25+100}[/tex]
[tex]d=\sqrt{106.25}[/tex]
[tex]d=10.3[/tex]
Step-by-step explanation:
i hope this will help you :)
The mean height of women in a country (ages 20-29) is 63.5 inches. A random sample of 50 women in this age group is selected. What is the probability that the mean height for the sample is greater than 64 inches? Assume the standard deviation equals 2.96.
Answer:
11.70% probability that the mean height for the sample is greater than 64 inches
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question:
[tex]\mu = 63.5, \sigma = 2.96, n = 50, s = \frac{2.96}{\sqrt{50}} = 0.4186[/tex]
What is the probability that the mean height for the sample is greater than 64 inches?
This is 1 subtracted by the pvalue of Z when X = 64.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{64 - 63.5}{0.4186}[/tex]
[tex]Z = 1.19[/tex]
[tex]Z = 1.19[/tex] has a pvalue of 0.8830
1 - 0.8830 = 0.1170
11.70% probability that the mean height for the sample is greater than 64 inches
x = ?????????????????
Answer:
4
Step-by-step explanation:
A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the true proportion is 0.050.05. If 212212 are sampled, what is the probability that the sample proportion will differ from the population proportion by less than 0.030.03
Answer:
95.44% probability that the sample proportion will differ from the population proportion by less than 0.03.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
In this question:
[tex]p = 0.05, n = 212, \mu = 0.05, s = \sqrt{\frac{0.05*0.95}{212}} = 0.015[/tex]
What is the probability that the sample proportion will differ from the population proportion by less than 0.03?
This is the pvalue of Z when X = 0.03 + 0.05 = 0.08 subtracted by the pvalue of Z when X = 0.05 - 0.03 = 0.02. So
X = 0.08
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.08 - 0.05}{0.015}[/tex]
[tex]Z = 2[/tex]
[tex]Z = 2[/tex] has a pvalue of 0.9772
X = 0.02
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.02 - 0.05}{0.015}[/tex]
[tex]Z = -2[/tex]
[tex]Z = -2[/tex] has a pvalue of 0.0228
0.9772 - 0.0228 = 0.9544
95.44% probability that the sample proportion will differ from the population proportion by less than 0.03.
Given the equation 4x - 3y = 12
1. Write the equation in slope-intercept form.
2. Identify the slope and y-intercept.
3. Graph the line.
4. Identify if it is a positive or negative slope.
Answer:
see below
Step-by-step explanation:
Slope intercept form is y = mx+b where m is the slope and b is the y intercept
4x - 3y = 12
Solve for y
Subtract 4x from each side
4x-4x - 3y =-4x+ 12
-3y = -4x+12
Divide by -3
-3y/-3 = -4x/-3 + 12/-3
y = 4/3x -4
The slope is 4/3 and the y intercept is -4
The slope is Positive
7
х
45
Find x.
x=
V(14)
7
07/2
Answer:
7
Step-by-step explanation:
This a special 90° 45° 45° triangle and is an Isosceles triangle at the same time
Of one of the equal side is 7 than the other one too must be 7
Solve the triangles with the given parts: a=103, c=159, m∠C=104º
Answer:
Sides:
[tex]a= 103[/tex].[tex]b \approx 99[/tex].[tex]c - 159[/tex].Angles:
[tex]\angle A \approx 39^\circ[/tex].[tex]\angle B \approx 37^\circ[/tex].[tex]\angle C = 104^\circ[/tex].Step-by-step explanation:
Angle AApply the law of sines to find the sine of [tex]\angle A[/tex]:
[tex]\displaystyle \frac{\sin{A}}{\sin{C}} = \frac{a}{c}[/tex].
[tex]\displaystyle\sin A = \frac{a}{c} \cdot \sin{C} = \frac{103}{159} \times \left(\sin{104^{\circ}}\right) \approx 0.628556[/tex].
Therefore:
[tex]\angle A = \displaystyle\arcsin (\sin A) \approx \arcsin(0.628556) \approx 38.9^\circ[/tex].
Angle BThe three internal angles of a triangle should add up to [tex]180^\circ[/tex]. In other words:
[tex]\angle A + \angle B + \angle C = 180^\circ[/tex].
The measures of both [tex]\angle A[/tex] and [tex]\angle C[/tex] are now available. Therefore:
[tex]\angle B = 180^\circ - \angle A - \angle C \approx 37.1^\circ[/tex].
Side bApply the law of sines (again) to find the length of side [tex]b[/tex]:
[tex]\displaystyle\frac{b}{c} = \frac{\sin \angle B}{\sin \angle C}[/tex].
[tex]\displaystyle b = c \cdot \left(\frac{\sin \angle B}{\sin \angle C}\right) \approx 159\times \frac{\sin \left(37.1^\circ\right)}{\sin\left(104^\circ\right)} \approx 98.8[/tex].
When a frequency distribution is exhaustive, each individual, object, or measurement from a sample or population must appear in at least one category.
a. True
b. False
Answer:
a. True
Step-by-step explanation:
The frequency distribution is a summary of the gathered data set, in which the interval of values is divided into classes.
A requirement for a frequency distribution is for the classes to be mutually exclusive and exhaustive. That is, each individual, object, or measurement in the data set must belong to one and only one class.
Then, we can conclude that each individual, object, or measurement must appear in at least one (in fact, only in one) category or class.
A child is 2 -1/2 feet tall. The child’s mother is twice as tall as the child. How tall is the child’s mother
Answer:
5 feet
Step-by-step explanation:
"Twice as tall" means "2 times as tall".
2 × (2 1/2 ft) = (2 × 2 ft) +(2 × (1/2 ft)) = 4 ft + 1 ft = 5 ft
The child's mother is 5 feet tall.
Answer:
The mother is 5ft tall
Step-by-step explanation:
2 1/2 + 2 1/2 = 5ft
2ft+2ft = 4ft
1/2+1/2= 1ft
4ft+1ft = 5ft
Question 15 A party rental company has chairs and tables for rent. The total cost to rent 8 chairs and 3 tables is $38 . The total cost to rent 2 chairs and 5 tables is $35 . What is the cost to rent each chair and each table?
Answer:
Each table is $6 and each chair is $2.50
Step-by-step explanation: