Complete Question
A grating has 767 lines per centimetre.Find the angles of the first three principal maxima above the central fringe when this grating is illuminated with 672 nm light.
Answer:
The first is
[tex]\theta_1 = 2.92^o[/tex]
The second is
[tex]\theta _2 = 5.93^o[/tex]
The third is
[tex]\theta _3 = 8.92^o[/tex]
Explanation:
From the question we are told that
The number of lines per cm is [tex]I = 767 \ lines/cm = 76700 \ lines / m[/tex]
The wavelength is [tex]\lambda = 672nm = 672 *10^{-9} \ m[/tex]
Generally the condition for constructive interference is
[tex]dsin (\theta ) = n\lambda[/tex]
Here d is the distance of separation of the slit which is mathematically represented as
[tex]d = \frac{1}{l}[/tex]
[tex]d = \frac{1}{76700}[/tex]
[tex]d = 1.30*10^{-5} \ m[/tex]
So
[tex]\theta_1 = sin^{-1} [\frac{ n \lambda }{ d} ][/tex]
For the first angle n = 1
So
[tex]\theta_1 = sin^{-1} [\frac{ 1 * 672 *10^{-9} }{ 1.30 *10^{-5}} ][/tex]
[tex]\theta_1 = 2.92^o[/tex]
For the second angle n = 2
So
[tex]\theta_2 = sin^{-1} [\frac{ 2 * 672 *10^{-9} }{ 1.30 *10^{-5}} ][/tex]
[tex]\theta _2 = 5.93^o[/tex]
For the second angle n = 3
So
[tex]\theta_3 = sin^{-1} [\frac{ 3 * 672 *10^{-9} }{ 1.30 *10^{-5}} ][/tex]
[tex]\theta _3 = 8.92^o[/tex]
A fish in an aquarium with flat sides looks out at a hungry cat. To the fish, the distance to the cat appears to be
Answer:
The distance of the cat will appear farther than it really is
Explanation:
The index of refraction of water is more than that of air. Light rays from the cat are refracted towards the normal at the surface and diverge outwards. This extends the virtual position of the cat, putting in a place farther than it really is.
100 yards from his house. What kind of antenna should he use on the house and barn to get the best signal
Complete question:
a farmer wants to use a wireless camera he has installed in his barn which is about 100 yards from his house. what kind of antenna should he use on the house and barn to get the best signal.
Answer: Unidirectional antenna
Explanation: Based on the description given in the scenario above, the farmer should use a unidirectional antenna in other to get the best signal taking advantage of the fact that he knows where he wants the Transmission to come from. The good transmission signal attributed to unidirectional antennas stems from the fact that, the area covered is relatively small as signal transmission and radiofrequecy energy is focused in a particular direction, meaning that less area is covered using a unidirectional antenna,hiwevwr, it leverages this limitation to provide very good signal within the limited area covered.
As you did above for the gas, now estimate the number of molecules found in a cubic centimeter of a liquid at ordinary pressure and temperature.
Answer:
There are [tex]3.372 \times 10^{22}[/tex] molecules in a cubic centimeter of water at ordinary pressure and temperature.
Explanation:
Let suppose that liquid is water at a pressure of a atmosphere and a temperature of 25 ºC. Due to incompresibility of liquids, water density does not have any change of importance due to changes in pressure and temperature.
Density and molar mass of water are 1 gram per cubic centimeter and 18.015 grams per mole. The mass of water in a cubic centimeter ([tex]m[/tex]), measured in grams, is:
[tex]m = \rho\cdot V[/tex]
Where:
[tex]\rho[/tex] - Density, measured in grams per cubic meter.
[tex]V[/tex] - Volume of the sample, measured in cubic meters.
Given that [tex]\rho = 1\,\frac{g}{cm^{3}}[/tex] and [tex]V = 1\,cm^{3}[/tex], the mass of water is:
[tex]m = \left(1\,\frac{g}{cm^{3}} \right)\cdot (1\,cm^{2})[/tex]
[tex]m = 1\,g[/tex]
The amount of moles ([tex]n[/tex]) inside the sample is:
[tex]n = \frac{m}{M}[/tex]
Where:
[tex]m[/tex] - Mass of the sample, measured in grams.
[tex]M[/tex] - Molar mass, measured in grams per mole.
If [tex]m = 1\,g[/tex] and [tex]M = 18.015\,\frac{g}{mole}[/tex], then:
[tex]n = \frac{1\,g}{18.015\,\frac{g}{mole} }[/tex]
[tex]n = 0.056\,mole[/tex]
According to the Avogadro's Principle, there are [tex]6.022\times 10^{23}[/tex] molecules per mole. Hence, the number of molecules in a cubic centimeter of water at ordinary pressure and temperature is determined by simple rule of three:
[tex]x = (0.056\,mole)\times\left(6.022\times 10^{23}\,\frac{molecules}{mole} \right)[/tex]
[tex]x = 3.372\times 10^{22}\,molecules[/tex]
There are [tex]3.372 \times 10^{22}[/tex] molecules in a cubic centimeter of water at ordinary pressure and temperature.
the acceleration of a car is 10m/s².if the starts from rest , what will be its speed after 10sec.
Answer:
v = 100 m/s
Explanation:
Given:
v₀ = 0 m/s
a = 10 m/s²
t = 10 s
Find: v
v = at + v₀
v = (10 m/s²) (10 s) + 0 m/s
v = 100 m/s
what would be the behavior of an object that was immersed in a fluid if the object and the fluid had the same density
Answer:
The object will remain where it was placed on the fluid
Explanation:
If an object is immersed in a fluid, with both the object and the fluid having the same density, the force of buoyancy (the force acting upward) will be equal to the gravitational force (the weight pulling the object down) making the object remain in the position it was placed in the fluid. Meaning it will neither sink down or float through the surface.
For practical purpose, it should however be noted that the chances of this happening is very low.
NOTE: When an object is less dense than the liquid/fluid, it will float and when it is more dense than the liquid, it will sink
the density of mercury is 13.6 g/ml. what is its density in lbs/L
Answer
density of mercury is 13.6 g/ml and that 1 lb = 0.45 kg.
g a circular area with a radius of cm lies in the plane. What is the magnitude of 0.250 T in the
Complete Question
A circular area with a radius of 6.60 cm lies in the xy-plane. What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field B = 0.250 T oriented in the following ways?
(a) in the +z-direction
Wb
(b) at an angle of 54
Answer:
a
[tex]\phi = 0.00342 \ Wb[/tex]
b
[tex]\phi = 0.00201 \ Wb[/tex]
Explanation:
From the question we are told that
The radius is [tex]r = 6.60 \ cm = 0.066 \ m[/tex]
The magnitude of the magnetic field is [tex]B = 0.250 \ T[/tex]
Generally the cross -sectional area is mathematically represented as
[tex]A = \pi r^2[/tex]
[tex]A = 3.142 * (0.066)^2[/tex]
[tex]A = 0.01369 \ m^2[/tex]
Generally when the magnetic field is oriented in the +z-direction the magnetic flux is mathematically represented as
[tex]\phi = B* A cos(0)[/tex]
=> [tex]\phi = 0.01369 * 0.250 * cos (0)[/tex]
=> [tex]\phi = 0.00342 \ Wb[/tex]
Now when the magnetic field is oriented at an angle of 54° the magnetic flux is mathematically represented as
[tex]\phi = B* A cos(54)[/tex]
[tex]\phi = 0.01369 * 0.250 * cos (54)[/tex]
[tex]\phi = 0.00201 \ Wb[/tex]
Refer to a long, straight wire carrying constant current I. What can be concluded about the magnitude of the magnetic field at distance a from the wire?
Answer:
"the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"
Explanation:
The magnitude of the magnetic field from a long straight wire (A approximately a finite length of wire at least for close points around the wire.) decreases with distance from the wire. It does not follow the inverse square rule as is the electric field from a point charge. We can then say that "the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"
From the Biot-Savart rule,
B = μI/2πR
where B is the magnitude of the magnetic field
I is the current through the wire
μ is the permeability of free space or vacuum
R is the distance between the point and the wire, in this case is = a
1. Does a fish appear closer or farther from a person wearing swim goggles with an air pocket in front of their eyes than the fish really is
Answer: I believe farther. Correct me if I am wrong
Explanation:
Answer:
Closer.
Explanation:
Due to the refraction of light passing through water and air.
If you ride quickly down a hill on a bicycle your eardrums are pushed in before they pop back. Why is this?
Answer:
This is due to variation bin air pressure at the two different altitudes, so air rushes out through the eustachian tube to hit the eardrum and back when u reach the ground
he Himalayas now reach an elevation of 8.8 km, and radiometric dating suggests that their uplift began about 45 million years ago. Assuming a constant rate of uplift, how fast did the Himalayas rise?
Answer:
v = 6.20 10⁻¹² m / s, v = 1.96 10⁻² cm/year
Explanation:
This is a kinematics problem, specifically of uniform motion
v = d / t
let's reduce the magnitudes to the SI system
d = 8.8 km (1000 m / 1 km) = 8.8 10³ m
t = 45 10⁶ years (365 day / 1 year) (24 h / 1 day) (3600 s / 1h)
t = 1,419 10¹⁵ s
let's calculate the speed
v = 8.8 10³ / 1.1419 10¹⁵
v = 6.20 10⁻¹² m / s
This is the correct unit of the SI system, but it is more common to give the value in centimeters per year, so let's reduce the value
v = 8.8 105 / 45 106
v = 1.96 10⁻² cm/year
If the first-order maximum for monochromatic light falling on a double slit is at an angle of 10.0∘, at what angle is the second-order maximum?
Answer:
The value is [tex]\theta_2 = 20.322^o[/tex]
Explanation:
From the question we are told that
The angle of the first order maximum is [tex]\theta _1 = 10.0^o[/tex]
Generally the condition for constructive interference is
[tex]dsin\theta = n \lambda[/tex]
Here d is the separation between the slit ,
n is the order of maxima with values n = 1, 2 , 3 ... for first , second , third ... order of maxima
Now for first order of maximum
[tex]dsin\theta_1 = \lambda \ \ ... \ \ ( 1)[/tex]
=> [tex]dsin(10) = \lambda \ \ ... \ \ ( 1)[/tex]
Now for second order of maximum
[tex]dsin\theta = 2\lambda \ \ ... \ \ ( 2)[/tex]
dividing equation 1 by 2
[tex]\frac{d sin (10)}{d sin (\theta_2 )} = \frac{\lambda}{2\lambda}[/tex]
[tex]\frac{ sin (10)}{ sin (\theta_2 )} = \frac{1}{2}[/tex]
=> [tex]2sin(10) = sin (\theta_2 )[/tex]
=> [tex]0.3473 = sin(\theta_2)[/tex]
=> [tex]\theta_2 = sin^{-1} [0.3473][/tex]
=> [tex]\theta_2 = 20.322^o[/tex]
A worker is pushing a crate of tools up a ramp into a truck. The crate has a mass of 120 kg and is accelerating at a rate of 1.05 m/s^2. Once he finishes pushing that crate up, he then takes another crate that is 3 times as massive and pushes it up the ramp with an acceleration of 0.71 m/s^2. What is the ratio of the force the worker used on the on the 120 kg crate and the more massive crate? a. 0.218 b. 0.493 c. 1.68 d. 1.07
Answer:
b. 0.493
Explanation:
While flying due east at 33 m/s, an airplane is also being carried due north at 12 m/s by the wind. What is the plane’s resultant velocity?
Answer:
35.11 m/s
Explanation:
While flying due east at 33 meters/second, an airplane is also being carried due north at 12 meters/second by the wind, then the plane’s resultant velocity would be 35.11 meters/second.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity.
the mathematical expression for velocity is given by
velocity = total displacement /total time
As given in the problem , while flying due east at 33 m/s, an airplane is also being carried due north at 12 m/s by the wind and we have to find the resultant velocity of the plane,
Resultant velocity = √( 33² + 12²)
= 35.11 meters/second
Thus, the plane’s resultant velocity would be 35.11 meters/second
Learn more about Velocity here, refer to the link;
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Ondrea could drive a Jetson's flying car at a constant speed of 540.0 km/hr across oceans and space, approximately how long would she take to drive from the Sun to Pluto in years? (Assume Pluto is at its average distance of 5.9 × 109 km from the Sun)
Answer:
The time taken in years is [tex]x = 125 \ years[/tex]
Explanation:
From the question we are told that
The speed is [tex]v = 540.00 \ km /hr = \frac{540 *1000}{3600} = 150\ m/s[/tex]
The distance from the sun to Pluto is [tex]d = 5.9*10^{9} \ k m = 5.9*10^9 * 1000 = 5.9*10^{12} \ m[/tex]
Generally the time taken is mathematically represented as
[tex]t = \frac{d}{v}[/tex]
=> [tex]t = \frac{5.9*10^{11}}{150}[/tex]
=> [tex]t = 3.933*10^{9}[/tex]
Converting to years
[tex]1 year \to 3.154*10^7 \ s[/tex]
[tex]x \ years \to 3.933*10^{9}[/tex]
=> [tex]x = \frac{ 3.933*10^{9} * 1 }{ 3.154 *10^7}[/tex]
=> [tex]x = 125 \ years[/tex]
All Houston Methodist buildings system wide have an emergency power generator that turns on to supply emergency power after normal power shuts down within:__________A. 5 secondsB. 30 secondsC. 60 secondsD. 10 seconds
Answer:
D. 10 seconds
Explanation:
All Houston Methodist Hospital buildings employs the use of EPSS(Emergency Power Supply System). This system employs the use of an emergency power generator that turns on to supply emergency power after normal power shuts down within 10 seconds during power outage.
Due to it being used in a hospital the importance of this emergency power system cannot be overemphasized as it is used to provide power supply to hospital equipment such as life support machines etc.
The constant of proportionality between charge and voltage is the:________.
a) Capacitor
b) Capacitance
c) Farad
d) None of the above
Answer:
The constant of proportionality between charge and voltage is the capacitance.
Explanation:
The capacitance ([tex]C[/tex]), measured in farads, is the ratio of charge to voltage, that is:
[tex]C = \frac{Q}{V}[/tex]
Where:
[tex]Q[/tex] - Charge, measured in coulombs.
[tex]V[/tex] - Voltage, measured in volts.
If charge is clear, it is easy to concluded that capacitante is a constant of direct proportionality.
Hence, the correct answer is B.
A person pulls a box across a floor. Which is the correct analysis of the situation? A. The box moves forward because the person pulls forward slightly harder on the box than the box pulls backward on the person. B. Because action always equals reaction, the person cannot pull the box. The box pulls backward just as hard as the person pulls forward, so there is no motion. C. The person gets the box to move by giving it a tug during which the force on the box is momentarily greater than the force exerted by the box on the person. D. The person's force on the box is as strong as the force of the force of the box on the person, but the frictional force on the person is forward and large while the backward frictional force on the box is small. E. The person can pull the box forward only if it weights more that the box.
Answer:
D. The person's force on the box is as strong as the force of the box on the person, but the frictional force on the person is forward and large while the backward frictional force on the box is small.
Explanation:
When a bag is pulled, then it involves a person’s force on the box meaning there is an opposite force which is equal to the force of the box on the person.
When the box is pulled, there is a forward frictional force on the person which is big when compared to the backward frictional force which is small. This positive difference is responsible for the movement of the box.
A certain automobile is 6.0 m long if at rest. If it is measured to be 4.8 m long while moving, its speed is:
Answer:
1.8*10^8m/s
Explanation:
Using
L= lo√1-v²/c²
So making v subject we have
V= c√1-4.8²/6²
V= 0.6*c
V= 0.6*3E8m/s
V= 1.8*10^8m/s
The electron beam inside an old television picture tube is 0.40 mm in diameter and carries a current of 50 μA. This electron beam impinges on the inside of the picture tube screen.
Part A. What is the current density in the electron beam?
Express your answer with the appropriate units.
Part B. The electrons move with a velocity of 3.8 ×107 m/s. What electric field strength is needed to accelerate electrons from rest to this velocity in a distance of 5.0 mm?
Express your answer with the appropriate units.
Part C. Each electron transfers its kinetic energy to the picture tube screen upon impact. What is the powerdelivered to the screen by the electron beam?
Express your answer with the appropriate units.
Answer:
A) J= 398 A/m²
B) E= 1.6×10⁶ N/C
C) P= ×10⁴ W
Explanation:
My work is in the attachment. Comment with questions or if something seems wrong with my work. (Honestly, they seem little high but it could just be the given numbers being unrealistic.) Below I have explanations of each part to match up with the image as well.
Part A:
Current density (J) is defined as the amount of current in a particular cross-sectional area. To get this, we simply need to divide the current (I) by the cross-sectional area of the electron beam tube (A).
Part B:
This one took the most work for me. I used a kinematic equation (yes they apply to electrons) to find the electric field (E). I used a modified form of the familiar: ∆d=V₀τ+aτ²/2
We can use the fact that τ= V/a, a=(qE/m), and V₀=0 here to rewrite the equation in terms of values we know and/or can look up. From there we solve for E and plug in the values.
Part C:
Power (P) is simply work (W) over time (τ). We know what τ is from before and can take W= mV²/2. Plugging these in and reducing some values gives us an equation for power as well.
An oil tanker took 7.2 hours to travel from city A to city B at an
average speed of 60 mph. If a passenger boat took 18 fewer
hours than the oil tanker to complete the same journey, what
was the average speed of the passenger boat?
Answer: 80
Explanation: 7.2 hours x 60mph = 432 m
7.2 hrs - 1.8 hrs= 5.4 hrs
432m/5.4hrs = 80
Answer: 80 mph
Explanation:
Just is
A flux density of 1.2Wb/m^2 is required in the 1 mm air gap of an electromagnet having an iron path of length 1.5 m. Calculate the mmf required. Given, relative permeability of iron is 1600. Neglect leakage.
Answer:
The mmf required is [tex]1.125[/tex]×[tex]10^{-3}[/tex] A
Explanation:
The Magnetomotive force (mmf) is given by the formula below
[tex]F_{M} = Hl\\[/tex]
where [tex]F_{M}[/tex] is the Magnetomotive force (mmf)
[tex]H[/tex] is the Magnetic field strength
[tex]l[/tex] is the magnetic length
The magnetic permeability μ is given by
μ = [tex]B / H[/tex]
Where [tex]B[/tex] is the Magnetic flux density
and [tex]H[/tex] is the Magnetic field strength
From the question,
[tex]B[/tex] = 1.2Wb/m^2
μ = 1600m
From μ = [tex]B / H[/tex]
∴[tex]H = B/[/tex]μ
[tex]H = 1.2 / 1600\\[/tex]
[tex]H = 7.5[/tex] × [tex]10^{-4}[/tex]A/m
Now, for the Magnetomotive force (mmf)
[tex]F_{M} = Hl\\[/tex]
From the question
[tex]l[/tex] = 1.5 m
∴ [tex]F_{M} = 7.5[/tex]×[tex]10^{-4}[/tex] × [tex]1.5[/tex]
[tex]F_{M} = 1.125[/tex]×[tex]10^{-3} A[/tex]
Hence, The mmf required is [tex]1.125[/tex]×[tex]10^{-3}[/tex] A
what is the difference between temperature and heat
Explanation:
Heat is a form of energy that can transfer from hot body to cold body.Temperature is the degree of hotness and coldness of a body.
Heat is measured in joules, but temp. is measured in Kelvin
Answer:
temperature is the degree of hotness and coldness of the body or an object while heat is the energy transferred from hot to a cooler object as a result if differencein temperature ☺
Why is it beneficial to perform focal point of a convex lens exercises in a dimly-lit room?
What is the focal length of a convex lens that produces an image on a screen 40 cm away with an object placed 10 cm from the lens? What is the magnification? Is the image inverted or upright? Show all calculations in your answer.
Explanation:
It is given that,
The object distance from the lens is 10 cm, u = -10 cm
Image is formed at a distance of 40 cm away from the lens, u = 40 cm
The lens formula is : [tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}[/tex], v is image distance
[tex]\dfrac{1}{40}-\dfrac{1}{-10}=\dfrac{1}{f}\\\\f=8\ cm[/tex]
The focal length is 8 cm
Magnification,
[tex]m=\dfrac{v}{u}\\\\m=\dfrac{40}{-10}\\\\m=-4[/tex]
The magnification is negative, it means that the formed image is inverted.
Calculate the average volume per molecule for an ideal gas at room temperature and atmospheric pressure. Then take the cube root to get an estimate of the average distance between molecules. How does this distance compare to the size of a molecule
Complete Question
Calculate the average volume per molecule for an ideal gas at room temperature and atmospheric pressure. Then take the cube root to get an estimate of the average distance between molecules. How does this distance compare to the size of a molecule like [tex]N_2[/tex]?
Answer:
The average volume per molecule is
[tex]\frac{V}{N} = 4.09 *10^{-26} \ m^3/molecule[/tex]
The average distance between molecules
[tex]d = 3.45 *10^{-9} \ m[/tex]
The size of [tex]N_2[/tex] is 100 times smaller than the obtained value
Explanation:
From the question we can deduce that we are considering an ideal
Generally the ideal gas equation is mathematically represented as
[tex]PV = NkT[/tex]
Here T is the room temperature with value T = 300 \ K
k is the Boltzmann constant with value [tex]k = 1.38 *10^{-23} \ J/K[/tex]
P is the atmospheric pressure with value [tex]P = 1.0 *10^{5} \ N/m^2[/tex]
N is the number of molecules
Now the volume per molecule is mathematically deduced from the above equation as
[tex]\frac{V}{N} = \frac{kT}{P}[/tex]
=> [tex]\frac{V}{N} = \frac{ 1.381 *10^{-23} * 300}{ 1.0*10^{5}}[/tex]
=> [tex]\frac{V}{N} = 4.09 *10^{-26} \ m^3/molecule[/tex]
Now the distance is mathematically evaluated as
[tex]d = \sqrt{\frac{V}{N} }[/tex]
=> [tex]d = \sqrt[3]{4.09*10^{-26}}[/tex]
=> [tex]d = 3.45 *10^{-9} \ m[/tex]
Generally the size of [tex]N_2[/tex] is 115 pm which is 100 times smaller than the obtained value
Generally the size of [tex]H_2O[/tex] is [tex]95.84 \ pm[/tex] which is 10 times smaller than the obtained value
Based on the ideal gas equation, the calculated values are as follows:
the average volume per molecule is 4.09 × 10^-23 m^3/moleculethe average distance between molecules is 3.45 nmthe N2 molecule is about 30 times smaller than the average distance between molecules.How can the average volume per molecule be calculated?The average volume per molecule is calculated using the given formula derived from the ideal gas equation:
V/n = kT/Pwhere:
V = gas volumen = number of molesk is Boltzmann constant = 1.38 × 10^-23 J/KT is temperature, and P is pressureAt room temperature and atmospheric pressure;
T = 300 k
P = 1.0 × 10^5 N/m^2
Substituting the values in the equation above to calculate the average volume per molecule, V/n:
V/n = 1.38 × 10^-23 × 300/1.0 × 10^5 N/m^2
V/n = 4.09 × 10^-23 m^3/molecule
Thus, the average volume per molecule is 4.09 × 10^-23 m^3/molecule
How can the average distance between molecules be determined?The average distance between molecules can be determined by using the formula:
[tex]d = \sqrt[3]{ \frac{v}{n} } [/tex]
Substituting the values for V/n
[tex]d = \sqrt[3]{4.09 \times {10}^{ - 23} } [/tex]
d = 3.45 × 10^-9 m or 3.45 nm
Therefore, the average distance between molecules is 3.45 nm
A molecule of N2 has an average size of 115 pm or 0.115 nm.
Comparing the two values:
3.45/0.115 = 30
Therefore, the N2 molecule is about 30 times smaller than the average distance between molecules.
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If "38 %" of the light passes through this combination of filters, what is the angle between the transmission axes of the filters
Answer:
52°
Explanation:
The initial intensity [tex]I_{0}[/tex] = [tex]I[/tex]
The final intensity [tex]I_{f}[/tex] = 38% of [tex]I[/tex] = 0.38
From the polarizing equation
[tex]I_{f} = I_{0} cos^{2}[/tex]θ
substituting values, we have
[tex]0.38I = I cos^{2}[/tex]θ
0.38 = [tex]cos^2[/tex]θ
cosθ = [tex]\sqrt{0.38}[/tex]
cosθ = 0.6164
θ = [tex]cos^{-1}[/tex] 0.6164
θ = 51.9 ≅ 52°
The highest that George can suck water up a very long straw is 2.0 m . (This is a typical value.) Part APart complete What is the lowest pressure that he can maintain in his mouth
Answer:
81,725 N/m^2
Explanation:
Given the following :
Height of water = 2m
Density of water = 1000kg/m^3
Atmospheric pressure (Pat) = 101325 N/m^2
Lowest pressure (Pl) can be obtained thus ;
Pat - Pl = density × height × acceleration due to gravity
101325 - Pl = 1000 × 2 × 9.8
101325 - Pl = 19600
101325 - 19600 = Pl
Lowest pressure (Pl) = 81,725 N/m^2
81,725 N/m^2 = (81,725/101325) atm
= 0.8065630 = 0.8065 atm
A laser technician measures the wavelength of light from a new semiconductor laser. The wavelength is . What is the wavelength in nanometers
Answer:
The wavelength in nanometers is 849.81 nanometers (nm)
Explanation:
Here is the complete question:
A laser technician measures the wavelength of light from a new semiconductor laser. The wavelength is 8.4981 × 10⁻⁷m . What is the wavelength in nanometers. Write your answer as a decimal.
Explanation:
The given wavelength is 8.4981 × 10⁻⁷m.
To determine the wavelength in nanometers, we will convert the given wavelength from meters (m) to nanometers (nm).
1 nanometer = 1 × 10⁻⁹ meters
∴ 10⁻⁹ meters = 1 nanometer
To convert 8.4981 × 10⁻⁷m to nanometer (nm):
If 10⁻⁹ meters (m) = 1 nanometer (nm)
Then, 8.4981 × 10⁻⁷m = (8.4981 × 10⁻⁷m × 1 nm) / 10⁻⁹ m
8.4981 × 10⁻⁷m = 8.4981 × 10⁻⁷ × 10⁹ nm
= 8.4981 × 10² nm
= 849.81 nm
Hence, the wavelength in nanometers is 849.81 nm
A particle is confined to a one-dimensional box that is 50 pm long. What is the smallest possible uncertainty in momentum for the particle?
Answer:
The smallest possibility is 0.01E-22kgm/s
Explanation:
Using
Momentum= h/4πx
= 6.6x 10^-34Js/ 4(3.142* 50*10-12m)
= 0.01*10^-22kgm/s
If an object is rolling without slipping, how does its linear speed compare to its rotational speed?
Answer:
v = rw
Explanation:
When an object is rolling continuously without slipping, then every angle it rotates through, is equal to a distance the perimeter has rotated.
If the object completes 10 revolutions and takes a particular time, let's say t to complete it. The angular distance would then be 20 π rad, while its angular velocity will be 20 π/t
The circumference will somehow translate to the distance it covers, which is 20πr, this means that the speed is 20πr/t
So, like the question asked, the linear speed compared to angular speed is
v : w
20πr/t : 20πt, which can be simplified to
r : 1
In essence, v = rw