find t 5 ( x ) : taylor polynomial of degree 5 of the function f ( x ) = cos ( x ) at a = 0 .

The data has a range of 21 points, which means that one student had 21 fewer flights than the student with the most flights recorded. Understanding the range of distribution is important for answering the question of what a scatter plot is.

A scatter plot is a graphical representation of the relationship between two variables. It is a useful tool for identifying patterns and trends in data and for exploring the relationship between two variables. In a scatter plot, each point represents the values of two variables, with one variable plotted along the x-axis and the other plotted along the y-axis.

In this context, understanding the range of distribution is important for understanding the data being plotted on a scatter plot. The range is the difference between the highest and lowest values in a data set and gives an indication of how spread out the data is. In this case, the range is 21, which means that there is a 21-point difference between the student with the most flights recorded and the student with the fewest flights recorded.

To create a scatter plot for this data, we would need to identify the two variables that we want to plot against each other. For example, we could plot the number of flights recorded for each student against their grade point average or against their attendance record. By plotting these two variables against each other, we could identify any patterns or trends in the data and determine if there is a relationship between the variables. The scatter plot would help us visualize the data and make it easier to draw conclusions from it.

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The approximation of ∫10sin(t)t dt is 5.000018, rounded to six decimal places.

Using the given approximation, we have:

sin(t) ≈ t − t^3/6 + t^5/120 − t^7/5040

Multiplying both sides by t and integrating from 0 to 10, we get:

∫0^10 sin(t) t dt ≈ ∫0^10 (t^2/1! − t^4/3! + t^6/5! − t^8/7!) dt

Using the power rule of integration, we get:

∫0^10 sin(t) t dt ≈ [t^3/3! − t^5/5! + t^7/7! − t^9/9!]0^10

Substituting the limits of integration and simplifying, we get:

∫0^10 sin(t) t dt ≈ (10^3/3! − 10^5/5! + 10^7/7! − 10^9/9!)/6

Calculating the numerical value using a calculator, we get:

∫0^10 sin(t) t dt ≈ 5.000018

Therefore, the approximation of ∫10sin(t)t dt is 5.000018, rounded to six decimal places.

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Answer: Area of a trapezoid is 1/2 x (b1+b2) x height

Step-by-step explanation:

Therefore, the slope of the curve y = 6x^2 + 6/x at the point (3, 56) is 34.

Let's go through the calculation again to find the correct slope.

To find the slope of the curve at the point (3, 56), we need to take the derivative of the function y = 6x^2 + 6/x and evaluate it at x = 3.

Taking the derivative of y with respect to x, we can differentiate each term separately:

d/dx (6x^2) = 12x

d/dx (6/x) = -6/x^2

Now, combining the derivatives, we have:

y' = 12x - 6/x^2

Substituting x = 3 into the derivative expression:

y'(3) = 12(3) - 6/(3^2)

= 36 - 6/9

= 36 - 2/3

= 34 2/3

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If you take $100 out of your piggy bank and deposit it in your checking account, M1 would not change.

M1 includes currency, demand deposits, traveler's checks, and other checkable deposits. When you move the $100 from the piggy bank to your checking account, you are essentially converting one form of demand deposit (currency) into another form (checking account deposit), which does not affect the overall M1.

However, M2 would increase by $100. M2 includes M1 and several types of near-money, such as savings deposits, money market funds, and small time deposits.

When you deposit the $100 in your checking account, the bank may choose to use a portion of that deposit to create new loans. These loans increase the money supply in the economy,

which in turn increases M2. Thus, while the act of moving money from a piggy bank to a checking account does not directly affect M1, it indirectly affects M2 by increasing the potential for new loans and money creation by the banks.

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Answer: 64.3738

Step-by-step explanation:

for an approximate result, multiply the speed value by 1.609

Answer:

64.374 kph

Step-by-step explanation:

1 mph = 1.6093427125258 kph

40 x 1.6093427125258 = 64.373708501033 kph

The domain and the range of the graph given will be 0 ≤ x ≤ 95 and 0 ≤ y ≤ 20.

Given is a graph, we need to find the domain and the range of the graph given,

So,

The domain is all the input values that mean all the values of x,

Here we see the values of x are lies between 0 to 95, so the domain is 0 ≤ x ≤ 95

And the range is all the output values that mean all the values of y,

Here we see the values of y are lies between 0 to 20, so the range is 0 ≤ x ≤ 20.

Hence the domain and the range of the graph given will be 0 ≤ x ≤ 95 and 0 ≤ y ≤ 20.

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To solve the integral ∫x√(25+x^2)dx, we can make the substitution x=5tanθ. This gives us dx=5sec^2θ dθ, and we can rewrite the integral as ∫5tanθ√(25+25tan^2θ)(5sec^2θ)dθ. Simplifying this expression using trigonometric identities, we get ∫25sec^3θdθ.

To solve this integral, we can use integration by parts, with u=secθ and dv=sec^2θdθ. This gives us v=tanθ and du=secθtanθdθ. Plugging these values into the integration by parts formula, we get:

∫25sec^3θdθ = 25secθtanθ - 25∫tan^2θsecθdθ.

We can simplify the remaining integral using the trigonometric identity tan^2θ+1=sec^2θ, which gives us:

∫tan^2θsecθdθ = ∫(sec^2θ-1)secθdθ = ∫sec^3θdθ - ∫secθdθ.

We can solve the first integral using integration by parts again, and the second integral is a standard integral that can be easily evaluated. After simplifying and substituting back in x, we get the final answer:

∫x√(25+x^2)dx = 1/3(25+x^2)^(3/2) + C.

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The top 10% of professors spend above $125.94 each week on entertainment. To find the z-score for the top 10% of professors, we need to find the z-value that corresponds to the 90th percentile.

To find out the amount of money spent by the top 10% of professors on entertainment each week, we need to use the z-score formula and the standard normal distribution table.

The z-score formula is:

z = (x - μ) / σ

where:

x = the amount spent on entertainment

μ = the mean amount spent on entertainment

σ = the standard deviation

To find the z-score for the top 10% of professors, we need to find the z-value that corresponds to the 90th percentile. The 90th percentile can be calculated as follows:

90th percentile = mean + z-score * standard deviation

From the standard normal distribution table, we can find that the z-score corresponding to the 90th percentile is 1.28.

So,

90th percentile = 95.25 + 1.28 * 27.32 = 125.94

Therefore, the top 10% of professors spend above $125.94 each week on entertainment.

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To find the probability P(x ≤ 1/4) when the probability density function is f(x) = 2(1-x)² on the interval [0, 1], you'll need to integrate the density function over the desired range.

To find p(x ≤ 1/4), we need to integrate the probability density function from 0 to 1/4.

P(x ≤ 1/4)=∫(0 to 1/4) 2(1-x)² dx
P(x ≤ 1/4) = [(-2/3)(1-x)³) from 0 to 1/4
P(x ≤ 1/4) = (-2/3)(1/64)3 + (2/3)(1)3
P(x ≤ 1/4) = 1/12
Therefore, the probability that x is less than or equal to 1/4 is 1/12.

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With regard to the cost of both cars, the option that is True is "I should buy the blue car because by the time five years have passed, I will have saved almost $2,000."  (Option A)

From the graph,

Step 1: Note that by the 5th year  the cost spent on maintenance for the blue car is $9000

Step 2:  while that of the yellow car is $11,000.

Step 3: This means that the owner would have saved $2000 since he or she does not wish to keep both cars beyond 5 years period.

Note that this is called cost analysis.

A cost-benefit analysis, also known as a benefit-cost analysis, is a method for analyzing the strengths and weaknesses of options.

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Answer:

x = 15

Step-by-step explanation:

To solve this problem, isolate x

Original equation:

-10 + x = 5

Add 10 to both sides:

-10 + 10 + x = 5 + 10

Cancel/simplify:

x = 5 + 10

Add:

x = 15

~~~Harsha~~~

Answer:

x=15

Step-by-step explanation:

We are given and we have to isolate the x variable:

-10+x=5

add 10 to both sides

x=15

Hope this helps! :)

a. A and K are independent.

b.[tex]P(A) = (100!/A!(100-A)!)(-1)^A(p^A)\sum[(100 C K)((1-p)^{(100-K)})][/tex] (summing over K) and [tex]PK(K) = (100 C K)((1-p)^{(100-K)})\sum[(100!/A!(100-A)!)(-1)^A(p^A)][/tex] (summing over A)

c. The probability P[<2, K=50].

What is probability?

Probability is a measure of the likelihood or chance of an event occurring. It quantifies the uncertainty associated with an outcome in a specific situation or experiment.

a. To determine if A and K are independent, we need to check if the joint PMF can be expressed as the product of the marginal PMFs.

Given the joint PMF:

[tex]P(A,K) = (100!/A!(100-A)!)(-1)^A(100 C K)(p^A)((1-p)^{(100-K)})[/tex]

If A and K are independent, the joint PMF should be equal to the product of the marginal PMFs:

P(A,K) = P(A)*PK(K)

Let's check if this holds true by calculating the marginal PMFs.

b. Marginal PMFs:

P(A) = ∑PK(A,K) (summing over K)

[tex]P(A) = \sum[(100!/A!(100-A)!)(-1)^A(100 C K)(p^A)((1-p)^{(100-K)})][/tex] (summing over K)

[tex]P(A) = (100!/A!(100-A)!)(-1)^A(p^A)\sum[(100 C K)((1-p)^{(100-K)})][/tex] (summing over K)

PK(K) = ∑P(A,K) (summing over A)

[tex]PK(K) = \sum[(100!/A!(100-A)!)(-1)^A(100 C K)(p^A)((1-p)^{(100-K)})][/tex] (summing over A)

[tex]PK(K) = (100 C K)((1-p)^{(100-K)})\sum[(100!/A!(100-A)!)(-1)^A(p^A)][/tex] (summing over A)

c. To find P[<2, K=50], we need to substitute p = 0.5 and evaluate the joint PMF for A < 2 and K = 50:

P[<2, K=50] = P(0, 50) + P(1, 50)

[tex]P(0, 50) = (100!/0!(100-0)!)(-1)^0(100 C 50)(0.5^0)((1-0.5)^{(100-50)})\\\\P(1, 50) = (100!/1!(100-1)!)(-1)^1(100 C 50)(0.5^1)((1-0.5)^{(100-50)})[/tex]

Simplifying these expressions will give the probability P[<2, K=50].

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The problem you have given me is to solve problem 9.1 using Euler's method. Problem 9.1 involves finding the solution to the differential equation y' = x^2 + y^2 with the initial condition y(0) = 1.

To solve this problem using Euler's method, we will first need to choose a step size h. Let's choose h = 0.1.

Then, we can use the formula y_n+1 = y_n + hf(x_n, y_n), where y_n is the approximation of y at the nth step and f(x_n, y_n) is the slope of the tangent line at (x_n, y_n).

Using this formula, we can calculate the values of y at each step. Starting with y_0 = 1 and x_0 = 0, we have: y_1 = y_0 + hf(x_0, y_0) = 1 + 0.1(0^2 + 1^2) = 1.1 y_2 = y_1 + hf(x_1, y_1) = 1.1 + 0.1(0.1^2 + 1.1^2) = 1.243 y_3 = y_2 + hf(x_2, y_2) = 1.243 + 0.1(0.2^2 + 1.243^2) = 1.430 y_4 = y_3 + hf(x_3, y_3) = 1.430 + 0.1(0.3^2 + 1.430^2) = 1.668 y_5 = y_4 + hf(x_4, y_4) = 1.668 + 0.1(0.4^2 + 1.668^2) = 1.964 We can continue this process to find more approximations of y.

The exact solution to this differential equation is y = tan(x + C), where C is a constant. The value of C can be found using the initial condition y(0) = 1, which gives us C = pi/4. Therefore, the exact solution is y = tan(x + pi/4).

In summary, using Euler's method with a step size of h = 0.1, we have found approximations of y for the differential equation y' = x^2 + y^2 with the initial condition y(0) = 1. The exact solution is y = tan(x + pi/4).

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Answer: The trapezoid's area is 265 [tex]unit^{2}[/tex]

Definition of a trapezoid - A trapezoid, also known as a trapezium, is a flat closed shape having four straight sides, with one pair of parallel sides.

The parallel sides of a trapezium are known as the bases, and its non-parallel sides are called legs. A trapezium can also have parallel legs. The parallel sides can be horizontal, vertical, or slanting.

The perpendicular distance between the parallel sides is called the altitude.

The area of trapezium is given as : [tex]\frac{1}{2}[/tex] × sum of the parallel sides × distance between the parallel sides

Given:  the base lengths of trapezoid are 24 unit and 29 unit and height is 10 unit.

The area of trapezoid = [tex]\frac{1}{2}[/tex] × (24+29) × 10 = 265 [tex]unit^{2}[/tex]

Final answer : The area of trapezoid is 265[tex]unit^{2}[/tex]

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The formula for the area of a parallelogram can be used to derive the formula for the area of a circle. Is A) No. therefore, These are two different geometric shapes with different formulas for finding their areas.

(A) No, the formula for the area of a parallelogram cannot be used to derive the formula for the area of a circle. These are two different geometric shapes with different formulas for finding their areas.

The formula for the area of a parallelogram is A = base x height, while the formula for the area of a circle is A = π[tex]r^2[/tex], where r is the radius of the circle.

There are other methods to derive the formula for the area of a circle, such as using calculus or using approximations with polygons, but using the formula for a parallelogram is not one of them.

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The first partial derivatives of the function f(x, y) = [tex]x^4 - 4xy^9[/tex] are fx(x, y) = 4x³ and fy(x, y) = [tex]-36xy^8[/tex].

To find the first partial derivatives of the function f(x, y) = [tex]x^4 - 4xy^9[/tex], we need to take the partial derivative with respect to each variable separately while treating the other variable as a constant.
The partial derivative of f(x, y) with respect to x (fx) is obtained by differentiating [tex]x^4[/tex] with respect to x, which gives [tex]4x^3[/tex]. The second term [tex]-4xy^9[/tex] does not involve x, so it drops out in the differentiation process. Therefore, fx(x, y) = [tex]4x^3[/tex].
Similarly, the partial derivative of f(x, y) with respect to y (fy) is obtained by differentiating [tex]-4xy^9[/tex] with respect to y, which gives [tex]-36xy^8[/tex]. The first term x^4 does not involve y, so it drops out in the differentiation process. Therefore, fy(x, y) = [tex]-36xy^8[/tex].
In summary, the first partial derivatives of the function f(x, y) = [tex]x^4 - 4xy^9[/tex] are fx(x, y) = 4x³ and fy(x, y) = [tex]-36xy^8[/tex].

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Answer:

i think its 14

Step-by-step explanation:

the tangent line of the curve x = 6t2 + 8, y = t3 − 4 has a slope of 1/2 at the point (2, -2).

we can use the formula for finding the slope of a tangent line to a curve at a given point, which is dy/dx. To find the value of t at which the tangent line has a slope of 1/2, we need to set dy/dx equal to 1/2 and solve for t.

Taking the derivatives of x = 6t2 + 8 and y = t3 − 4, we get dx/dt = 12t and dy/dt = 3t2. Then, using the formula for dy/dx, we have:

dy/dx = (dy/dt) / (dx/dt)
dy/dx = (3t2) / (12t)
dy/dx = 1/4 * t

Setting this equal to 1/2, we have:

1/4 * t = 1/2
t = 2

Therefore, the tangent line has a slope of 1/2 at the point (2, -2) on the curve.

we can find the point on a curve where the tangent line has a given slope by setting the derivative of y with respect to x equal to that slope, solving for t, and then plugging that value of t back into the equations for x and y to find the corresponding point on the curve.

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CORREL determines how two sets of data from a sample vary simultaneously. Option 3, "CORREL", is the correct answer.

The correlation coefficient between two cell ranges is returned by the CORREL function. To ascertain the connection between two properties, use the correlation coefficient.

The measure that determines how two sets of data from a sample vary simultaneously is called correlation.

Option 3, "CORREL", is the correct answer. Correlation measures the strength and direction of the linear relationship between two variables. It indicates how much one variable changes when the other variable changes, and is typically measured using a correlation coefficient, such as Pearson's correlation coefficient.

The other options listed are also measures of the relationship between two variables, but they measure different aspects of this relationship:

- STDEV.P is the population standard deviation, which measures the spread of a population of values around its mean.

- COVARIANCE.S is the sample covariance, which measures how two variables vary together in a sample.

- STDEV.S is the sample standard deviation, which measures the spread of a sample of values around its mean.

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The radius of convergence and interval of converges of the series is [-1, 1).

The series ∑(n=1)^(∞) (x^(n))/√n has a radius of convergence of 1 and an interval of converges of [-1, 1).

To find the radius of converges, we use the root test:

lim_(n→∞) |(x^(n))/√n|^(1/n) = |x| lim_(n→∞) 1/√n = 0

Since the limit is 0 for all x, the radius of convergence is ∞. However, the series only converges for x-values where the absolute value of x is less than 1.

To find the interval of convergence, we need to check the endpoints x=1 and x=-1.

When x=1, we have the series ∑(n=1)^(∞) 1/√n, which diverges by the p-test (since p=1/2 is less than 1).

When x=-1, we have the series ∑(n=1)^(∞) (-1)^(n-1)/√n, which converges by the alternating series test.

Therefore, the interval of converges is [-1, 1).

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For the region under f(x) = 4x^2 on [0, 2], the sum of the areas of the upper approximating rectangle approaches 32/3, or lim n→∞ rn = 32/3.

To show this, we can use the Riemann sum, which approximates the area under the curve by dividing it into a finite number of subintervals and using rectangles to approximate the area of each subinterval. The upper Riemann sum is obtained by using the height of the rectangle with the maximum value of the function in each subinterval.

For this specific function and interval, the width of each subinterval is 2/n, and the height of the upper rectangle in each subinterval is f(i(2/n)), where i is the index of the subinterval. The sum of the areas of the upper rectangles is then given by:

(2/n)Σ[1≤i≤n]f(i(2/n))

Substituting the function f(x) = 4x^2 and simplifying, we get:

(8/n^3)Σ[1≤i≤n]i^2

Using the formula for the sum of squares of the first n natural numbers, Σ[1≤i≤n]i^2 = n(n+1)(2n+1)/6, and simplifying further, we get:

(8/n^3) * n(n+1)(2n+1)/6 = (4/3) * (n+1/2) * (2n+1)/n^2

Taking the limit as n approaches infinity, we get:

lim n→∞ (4/3) * (n+1/2) * (2n+1)/n^2 = 32/3

Therefore, the sum of the areas of the upper approximating rectangles approaches 32/3 as the number of subintervals approaches infinity, or lim n→∞ rn = 32/3.

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To find the radius of convergence, we use the ratio test. The ratio test states that if the limit of the absolute value of the ratio of consecutive terms is less than 1, then the series converges absolutely. If the limit is greater than 1, then the series diverges. If the limit is equal to 1, then the test is inconclusive.

In this case, we have the series (-1)^(n-1)/n5^n. Taking the absolute value of the ratio of consecutive terms, we get |((-1)^n)/(n+1)(5^(n+1))) / ((-1)^(n-1)/n5^n)| = 1/(5(n+1)). Taking the limit as n approaches infinity, we get 1/5. Since the limit is less than 1, the series converges absolutely.

The radius of convergence is equal to the reciprocal of the limit we just found, which is 5. Therefore, the series converges for all x values between -5 and 5.

To find the interval of convergence, we need to test the endpoints. When x=5, the series becomes (-1)^(n-1)/(5n), which is an alternating series. The alternating series test tells us that the series converges if the absolute value of the terms decreases and approaches zero. In this case, the terms are decreasing in absolute value but do not approach zero, so the series diverges at x=5.

When x=-5, the series becomes (-1)^(n-1)/(-5n), which is also an alternating series. The same reasoning as above tells us that the series converges at x=-5.

Therefore, the interval of convergence is [-5,5).

The radius of convergence of the series (-1)^(n-1)/n5^n is 5, and the interval of convergence is [-5,5). To find the radius of convergence, we used the ratio test and found that the limit of the absolute value of the ratio of consecutive terms is 1/5. To find the interval of convergence, we tested the endpoints and found that the series converges at x=-5 and diverges at x=5.

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The interval of convergence is [-5,5). We apply the ratio test to determine the radius of convergence. The ratio test asserts that the series converges absolutely if the limit of the absolute value of the ratio of consecutive terms is smaller than 1.

The series diverges if the limit is bigger than 1. The test is not convincing if the limit is equal to 1.The series in question is (-1)(n-1)/n5n. The result is |((-1)n)/(n+1)(5(n+1))] / ((-1)(n-1)/n5n)| = 1/(5(n+1) when we take the absolute value of the ratio of successive words. When we take the limit as n gets closer to infinity, we get 1/5. Since 1, the limit, the series completely converges.

The radius of convergence is equal to the reciprocal of the limit we just found, which is 5. Therefore, the series converges for all x values between -5 and 5.

To find the interval of convergence, we need to test the endpoints. When x=5, the series becomes (-1)[tex]^(n-1)/(5n)[/tex], which is an alternating series. The alternating series test tells us that the series converges if the absolute value of the terms decreases and approaches zero. In this case, the terms are decreasing in absolute value but do not approach zero, so the series diverges at x=5.

When x=-5, the series becomes (-1)[tex]^(n-1)/(-5n),[/tex]which is also an alternating series. The same reasoning as above tells us that the series converges at x=-5.

Therefore, the interval of convergence is [-5,5).

The radius of convergence of the series (-1)^(n-1)/n[tex]5^n[/tex] is 5, and the interval of convergence is [-5,5). To find the radius of convergence, we used the ratio test and found that the limit of the absolute value of the ratio of consecutive terms is 1/5. To find the interval of convergence, we tested the endpoints and found that the series converges at x=-5 and diverges at x=5.

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The point on the x-axis where the magnetic field is zero when the two currents are in the same direction is midway between the two wires.

The magnetic field produced by a current-carrying wire is directly proportional to the distance from the wire. When two current-carrying wires are placed parallel to each other and the current is in the same direction, the magnetic fields around them combine to produce a magnetic field that cancels out at the midpoint between the two wires. Therefore, the point on the x-axis where the magnetic field is zero is the midway point between the two wires, and this point can be calculated using the distance formula. The appropriate units for this point are the same as the units used for the distance between the wires.

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To get the function g, shift f down by 7 units and to the right by 2 units.

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

Where, we have

f(x) = x²

g(x) = (x - 2)² - 7

From the above equations, we can see that

The function f(x) is translated right by 2 units

The function f(x) is translated down by 7 units

This means that

To get the function g, shift f down by 7 units and to the right by 2 units.

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We need a sample size of at least 97 to estimate the population mean with a margin of error of 2 or less and a .95 probability when the population standard deviation equals 11.

To estimate a population mean with a certain level of confidence and a specific margin of error, we use a formula that requires knowledge of the population standard deviation. In this case, we are given that the population standard deviation is 11. The formula we use is:

n = [(z*σ)/E]^2

Where:

n = sample size needed
z = the z-score corresponding to the desired level of confidence (in this case, .95 corresponds to a z-score of 1.96)
σ = the population standard deviation (in this case, 11)
E = the desired margin of error (in this case, 2)

Substituting in the values given, we get:

n = [(1.96*11)/2]^2
n = 96.04

We round up to the nearest whole number, since we need a whole number of participants. Therefore, we need a sample size of at least 97 to estimate the population mean with a margin of error of 2 or less and a .95 probability when the population standard deviation equals 11.

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Answer:

.7

Step-by-step explanation:

because you see here that under tennis you see 7 and yeah sometimes I am not all right I am sure

Answer: 0.25

Step-by-step explanation:

It's 0.25 because the total is 28 and if you divide 7 from 28, you get 4, to make sure this is correct we should multiply 4 by 7 and that is 28. Since it's asking how many people prefer tennis more than the other sports in decimal form, 7/28 is equivalent to 1/4 and 1/4 is equivalent to 0.25 since 1/4 x 4 is 1 and 0.25 x 4 is also 1.

The 95% confidence interval for the difference in the proportions of white and minority students who support the principal lies between -0.056 and 0.391.  

First, we shall  use the formula for a confidence interval for the difference in proportions:

Let:

p1 = proportion of white students who support the principal

p2 = proportion of minority students who support the principal.

p1 = 45/56 = 0.8036

p2 = 21/33 = 0.6364

Let:

n1 =  number of white students surveyed  

n2 =  number of minority students surveyed.

n1 = 56

n2 = 33

The point estimate for the difference in proportions is:

p1 - p2 = 0.8036 - 0.6364 = 0.1672

The standard error for the difference in proportions is:

SE = [tex]\sqrt{ [p1(1-p1)/n1] + [p2(1-p2)/n2] }[/tex]

SE =[tex]\sqrt{ [(0.8036)(1-0.8036)/56] + [(0.6364)(1-0.6364)/33] }[/tex]

SE = 0.1121

So, the 95% confidence interval for the difference in proportions is:

(p1 - p2) ± (critical value) * (SE)

where the critical value is based on a t-distribution with (n1 + n2 - 2) degrees of freedom at the 0.025 level (two-tailed test).

Using a t-distribution table, with 87 degrees of freedom, the critical value is 1.987.

The 95% confidence interval for the difference in proportions is:

0.1672 ± 1.987 * 0.1121

0.1672 ± 0.223

(−0.056, 0.391)

Thus, we can be 95% confident that the true difference in the proportions of white and minority students who support the principal lies between -0.056 and 0.391.  

Learn more about confidence interval /brainly.com/question/20309162

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Answer: =133.3%

Step-by-step explanation:

Formula for percent change:

[tex]\frac{difference of 2 numbers}{original} *100[/tex]                 >substitute

[tex]\frac{\frac{7}{8} -\frac{3}{8} }{\frac{3}{8} } *100[/tex]                                         >subtract top

[tex]=\frac{\frac{4}{8} }{\frac{3}{8} }*100[/tex]                                         >simplify/reduce top

[tex]=\frac{\frac{1}{2} }{\frac{3}{8} }*100[/tex]                                         >Divide fractions(Keep the first, Change

                                                           the sign, Flip the 2nd fraction

= [tex]\frac{1}{2} *\frac{8}{3} *100\\[/tex]                                     >Reduce fractions and multiply

= [tex]\frac{4}{3} *100[/tex]

=133.3%