Answer: Local Max = (-1, 0)
Local Min = (1, -8)
Step-by-step explanation:
f(x) = (x + 1)² (x - 3)
Step 1: Find the zeros
(x + 1)² = 0 --> x = -1 (multiplicity of 2)
(x - 3) = 0 --> x = 3
Step 2: Find the Vertices
x = -1 --> (multiplicity is even which means this is a vertex)
The midpoint between x = -1 and x = 3 is x = 1
Step 3: Find the Local Max and Local Min
Use the x-value above to find the y-values
f(-1) = 0 because it is a zero
f(1) = (1 + 1)² (1 - 3)
= 2²(-2)
= 4(-2)
= -8
Conclusion:
(-1, 0) is the Local Max bigger y-value
(1, -8) is the Local Min smaller y-value
Answer:
f ( x ) = ( x – 3) 2 – 4; the minimum value is –4
Step-by-step explanation:
Given the function f ( x ) = x 2 – 6 x + 5, write an equivalent form of the function that reveals the minimum or maximum value of the function and state the minimum or maximum value.
f ( x ) = ( x – 3) 2 – 4; the minimum value is –4
( This The correct question to answer?) can't deleted..
Find the GCF of 207c^3 and 108c^2
Answer: 9c²
Step-by-step explanation:
To find the Greatest Common Factor of 207c³ and 108c², first factor them down to their primes and see what they have in common.
207c³ 108c²
∧ ∧ ∧ ∧
9·23 c·c·c 9·12 c·c
∧ ∧ ∧
3·3 3·3 3·4
∧
2·2
207c³: 3·3·23 c·c·c
108c²: 2·2·3·3·3·4 c·c
GCF = 3·3 c·c
= 9c²
The GCF of 207c^3 and 108c² is 9c²
Given the expressions [tex]207c^3 \ and \ 108c^2[/tex]
We are to find the GCF of both terms
First, we need to get the factors as shown::
207c³ = 9 * 23 * c² * c
108c² = 9 * 12 * c²
From the factors, we can see that 9 and c² are common to both terms:
The GCF of 207c^3 and 108c² is 9c²
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What is 7/8×3/9 reduced to lowest terms
Answer:
7/24
Step-by-step explanation:
7/8×3/8= 21/72
divide using 3
= 7/24
Five times a number is divided by $7$ more than the number. If the result is $2$, then what was the original number? please help!
Answer:
3
Step-by-step explanation:
Because the number 5 is a number that you get from 7 more than n, and 2 is the other divisor that means n must equal 10 and 7 less than 10 is 3.
When five times a number is divided by 7 more than the number and the result is 2, then the number is 14/3, which is solved using the linear equation in one variable 5x/(x+ 7) = 2, where x is the required number.
What are linear equations in one variable?Linear equations are first-order equations. Lines in the coordinate system are determined by linear equations. A linear equation in one variable is defined as an equation with a homogeneous variable of degree 1 (i.e. only one variable).
How to solve the given question?In the question, we are asked to find a number, which satisfies the statement, "Five times a number is divided by 7 more than the number. The result of this division is 2".
We assume the number to be x.
Now we try to form a linear equation in one variable from the given statement.
Five times a number is 5x.
7 more than a number is x + 7.
We are said that five times a number is divided by 7 more than a number. This can be shown as 5x/(x + 7).
Now, the result is given as 2, which can be shown as:
5x/(x+ 7) = 2, which is the required linear equation in one variable.
To get the number, we solve the equation using the following steps:
5x/(x+ 7) = 2
or, {5x/(x+ 7)}*(x + 7) = 2*(x + 7) (Multiplying both sides by (x + 7))
or, 5x = 2x + 14 (Simplifying)
or, 5x - 2x = 2x + 14 - 2x (Subtracting 2x from both sides)
or, 3x = 14 (Simplifying)
or, 3x/3 = 14/3 (Dividing both sides by 3)
or, x = 14/3 (Simplifying)
∴ When five times a number is divided by 7 more than the number and the result is 2, then the number is 14/3, which is solved using the linear equation in one variable 5x/(x+ 7) = 2, where x is the required number.
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You are looking to invest in several different real estate deals. You have received ceconomic reports that explain the probability of good economic conditions will be .6 and .4 for bad economic conditions. Below is the Payoff Table, and after calculating the expected value for each decision, you determine the best "payoff deal is:
Good Economic Bad Economic
Conditions Condition (.60) Conditions (.40)
Apartment Building 50,000 30,000
Office Building $100,000 $-40,000
Warehouse 30,000 $10,000
A. Apartment Building
B. Office Building
C. Warehouse
D. None of the above.
Answer:
Real Estate Deals
The best "payoff deal:"
B. Office Building
Step-by-step explanation:
A) Payoff Table
Good Economic Bad Economic
Conditions Conditions
Probability (.60) (.40)
Apartment Building $50,000 $30,000
Office Building $100,000 $-40,000
Warehouse $30,000 $10,000
B) Calculation of Expected Values:
Good Economic Bad Economic Expected Values
Conditions Conditions
Probability (.60) (.40)
Apartment Building $30,000 $12,000 $42,000
Office Building $60,000 $-16,000 $44,000
Warehouse $18,000 $4,000 $22,000
b) The expected value for these real estate deals can be derived as the sum of the payoffs under the two economic conditions after they have been weighed with their odds of occurrence. The office building, in this example, showed the best payoff deal as the expected payoff from it results to a payoff of $44,000, which is higher than the expected payoff from the Apartment and Warehouse. However, it is also the riskiest, especially when bad economic conditions occur. This also accords with the general economic risk-return pattern that higher risky investments attract higher returns.
In an episode of the old school version of the game show Family Feud, 43 out of a random sample of 100 people said they pick their noses at red lights. Find a 95% confidence interval of the proportion of all people who pick their noses at red lights.
Answer:
95% of confidence interval of the proportion of all people who pick their noses at red lights
(0.3342 , 0.5258)
Step-by-step explanation:
Step(i):-
Given sample size 'n' = 100
Given data 43 out of a random sample of 100 people said they pick their noses at red lights.
sample proportion
[tex]p^{-} = \frac{x}{n} = \frac{43}{100} = 0.43[/tex]
Level of significance = 0.05
Z₀.₀₅ = 1.96
Step(ii):-
95% of confidence interval of the proportion of all people who pick their noses at red lights
[tex](p^{-} -Z_{\alpha } \sqrt{\frac{p(1-p)}{n} } ,p^{-} +Z_{\alpha } \sqrt{\frac{p(1-p)}{n} })[/tex]
[tex](0.43 -1.96 \sqrt{\frac{0.43(1-0.43)}{100} } ,0.43 +1.96 \sqrt{\frac{0.43(1-0.43)}{100} })[/tex]
( 0.43 - 0.0958 , 0.43 + 0.0958)
(0.3342 , 0.5258)
Conclusion:-
95% of confidence interval of the proportion of all people who pick their noses at red lights
(0.3342 , 0.5258)
Salaries of 43 college graduates who took a statistics course in college have a mean,66,000 , of . Assuming a standard deviation, 18908 , of $, construct a %99 confidence interval for estimating the population mean .
Answer:
$[58543.42; 73456.58]
Step-by-step explanation:
Hello!
For the variable
X: salary of a college graduate that took a statistics course
Out of n= 43 students, the calculated mean is [tex]\frac{}{X}[/tex]= $66000
The population standard deviation is δ= $18908
There is no information about the variable distribution, but since the sample size is big enough (n≥30), you can apply the CLT and approximate the distribution of the sample mean to normal [tex]\frac{}{X}[/tex]≈N(μ;σ²/n)
Then you can apply the approximation of the standard normal distribution to calculate the 99% CI
[tex]\frac{}{X}[/tex] ± [tex]Z_{1-\alpha /2}[/tex] * [tex]\frac{Singma}{\sqrt{n} }[/tex]
[tex]Z_{1-\alpha /2}= Z_{0.995}= 2.586[/tex]
[tex]\frac{Singma}{\sqrt{n} }= \frac{18908}{\sqrt{43} }= 2883.44[/tex]
[66000±2.586*2883.44]
$[58543.42; 73456.58]
With a 99% confidence level you'd expect that the interval $[58543.42; 73456.58] will include the average salary of college graduates that took a course of statistics.
I hope this helps!
if elf =gjh ef=12 and Lf=7.8 find ij
Answer:
IJ= 4.98
Step-by-step explanation:
EF = 12
KF = 6
LF = 7.8
LK = sqrt(7.8^2-6^2) = 4.98
IJ = LK (4.98)
which values will only have one zero??
If it has a single zero that means it has to be just touching the x-axis with its tip.
We know that if it has only one zero, the discriminant equals 0.
So,
[tex]D=b^2-4ac=0\implies (-k)^2-4(1)(9)=0[/tex]
Solving for k,
[tex]k=\pm\sqrt{36}=\boxed{\pm{6}}[/tex].
Hope this helps.
What is the point-slope form of a line that has a slope of 3 and passes through point (1, 4)?
BRE
BE
y-4=3(x-1)
1-y=3(x-4)
Y,-4 = 3(1-x)
1-Y, = 3(4-x,)
Answer:
Option (1)
Step-by-step explanation:
Equation of a line passing through [tex](x_1,y_1)[/tex] having slope 'm' is represented as,
[tex]y-y_1=m(x-x_1)[/tex]
If a line passes through (1, 4) and having slope = 3,
By substituting the values in the equation of the line,
y - 4 = 3(x- 1)
Therefore, equation of the line will be,
y - 4 = 3(x - 1)
Option (1) will be the answer.
What does 20 * 1 * 2 equal?
Answer:
40
Step-by-step explanation:
20 * 1
= 20
20 * 2
= 40
Answer:
40
Step-by-step explanation:
The first step is to multiply 20 by 1. Whenever you multiply something by 1, it will always stay the same no matter what.
20*1=20
The next step is to multiply by 2. When multiplying anything by two, it is the same as adding the same number to itself. so
20*2=40 or 20+20=40
Hope this helps. Feel free to ask any follow-up questions if you are still confused
Have a great day! :)
Dan is helpin Hazard tape needs to be placed all around the edge of the stage. Calculate the perimeter of the stage.6m-300cm-3.5m-12m
The correct answer is 24.5 m. You're given four different values but if you notice closely, not all the units match. Before you can add the values together, you need to get the same units. Because cm (centimeters) is the only one that's out of place, it will be easier to change it to m (meters). I think of centimeters as a century (same prefix) which equals 100. Therefore, to convert 300 cm to m, we will divide 300 by 100 to get 3. After that, add all the values together (6m+3m+3.5m+12m) to get a grand total of 24.5 m. I hope this helps!
The tape required to apply on the edge of the tape is 21.8m.
What is Perimeter?Perimeter is the sum of the length of the outer edges of a two-dimensional object.
A quadrilateral is a two-dimensional shape that is a polygon of four sides, one of the opposite sides of a quadrilateral is parallel.
Dan needs to apply tape on the edges of the stage, the tape required will be calculated by determining the perimeter of the stage.
The stage is in the shape of a quadrilateral.
The sides of the quadrilateral are as follows:
Side 1 = 6m
Side 2 = 300cm
Side 3 = 3.5m
Side 4 = 12m
300 cm will be converted into m
100 cm = 1m
300 cm = 0.3 m
The perimeter = Side 1 + Side 2 + Side 3+ Side 4
Perimeter = 6 + 0.3 +3.5 + 12
Perimeter = 21.8 m
The perimeter of the stage is 21.8m.
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Construct a polynomial function with the stated properties. Reduce all fractions to lowest terms. Second-degree, with zeros of −7 and 6, and goes to −∞ as x→−∞.
Answer:
Step-by-step explanation:
Hello, because of the end behaviour it means that the leading coefficient is negative so we can construct such polynomial function as below.
[tex]\large \boxed{\sf \bf \ \ -(x+7)(x-6) \ \ }[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
The polynomial function will be f ( x ) = - x² - x + 42
What is Quadratic Equation?
A quadratic equation is a second-order polynomial equation in a single variable x , ax²+ bx + c = 0. with a ≠ 0. Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has at least one solution. The solution may be real or complex.
Given data ,
The polynomial function is of second degree with zeros of -7 and 6
So , x = -7 and x = 6
Let the function be f ( x ) where f ( x ) = ( x + 7 ) ( x - 6 )
Now , as x tends to infinity , the negative makes no such difference on the zeros of the function f ( x ) ,
And , f ( x ) = - ( x + 7 ) ( x - 6 )
Therefore , to find the polynomial function , f ( x ) = - ( x + 7 ) ( x - 6 )
f ( x ) = - [ x² - 6 x + 7 x - 42 ]
= - [ x² + x - 42 ]
= - x ² - x + 42
Hence , the polynomial function f ( x ) = - x ² - x + 42
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Which equation is graphed in the figure? A. 7y = 5x + 14 B. 7y = -5x + 14 C. 5y = -7x + 10 D. 5y = 7x + 10
Answer:
The answer is D. You can confirm this from the graph down below
Step-by-step explanation:
Evaluate ƒ(x) = 3|x – 2| + 1 for ƒ(–2) and ƒ(1).
Answer:
ƒ(x) = 3|x – 2| + 1
To find f(-2) substitute - 2 into f(x)
That's
f(-2) = 3| - 2 - 2 | + 1
= 3| - 4| + 1
But absolute value of any number is positive including negative numbers
That's
| - 4 | = 4
So we have
3(4) + 1
12 + 1
f(-2) = 13To find f(1) substitute 1 into f(x)
That's
f(1) = 3 | 1 - 2| + 1
= 3 | - 1| + 1
But | - 1| = 1
= 3(1) + 1
= 3 + 1
f(1) = 4Hope this helps you
Answer:
f(-2) =13
f(-1) = 4
Step-by-step explanation:
ƒ(x) = 3|x – 2| + 1
Let x = -2
ƒ(-2) = 3|-2 – 2| + 1
= 3 | -4| +1
Taking the absolute value
= 3*4 +1
= 12 +1 = 13
Let x = 1
ƒ(1) = 3|1 – 2| + 1
= 3 | -1| +1
Taking the absolute value
= 3*1 +1
= 3 +1 = 4
HELP PLEASE ASAP 20 points
Answer:
Its d [tex]x^{2} -6x+7=0[/tex]
Step-by-step explanation:
A= [tex]2+\sqrt{3\\}[/tex]
B= [tex]3\sqrt{2}[/tex]
C= [tex]-3+\sqrt{2}[/tex]
Answer:
D. x^2 - 6x + 7 = 0.
Step-by-step explanation:
The roots are 3 plus or minus sqrt(2). That means the equation is...
(x - [3 + sqrt(2)]) * (x - [3 - sqrt(2)])
= [x - 3 - sqrt(2)] * [x - 3 + sqrt(2)]
= x^2 - 3x - xsqrt(2) - 3x + 9 + 3sqrt(2) + xsqrt(2) - 3sqrt(2) - (sqrt(2))^2
= x^2 - 3x - 3x + 9 - 2 - xsqrt(2) + xsqrt(2) + 3sqrt(2) - 3sqrt(2)
= x^2 - 6x + 7.
Hope this helps!
1. What is an inequality? Give one example of an inequality? How would you graph this? 2. What is a compound inequality? Give an example of "and" and an "or" inequality. 3. Identify the independent and dependent variables in the following situation: The more hours Beth studies, the higher the GPA she has.
Answer: see below
Step-by-step explanation:
1) An inequality is an equation that uses >, ≥, <, or ≤ instead of an equal sign.
Example: 3x + 2 ≥ 10
2) A compound inequality is when 2 inequalities are combined using either "and" or "or".
And → means it must satisfy both inequalitiesOr → means it must satisfy at least one of the inequalitiesExample: x > -2 and x < 4 rewrite as: -2 < x < 4
Graph: -2 o-----------------o 4 one line segment between the #'s
Example: x < -2 or x > 4
Graph: ←-----------o -2 4 o----------→ two lines in opposite directions
3) The GPA is dependent on the number of hours she studies.
Independent: hours Beth studies
Dependent: GPA
Which of the following is best described as all the points on a plane that are the same distance from a single point called a center?
A.
Ellipse
B.
Circle
C.
Diameter
D.
Chord
Answer:
It would be B. Circle
Please amswere my school is due tommorow and i meed some help
Answer:
88
Step-by-step explanation:
M : R
3 : 7
R : E
1 : 2
So make Ryan equal
1×7=7
2×7=14
tfo R : E
7 : 14
then add all 3forM+7forR+14forE = 24
192/24=8
so for Ethan, 8×14=112and for Marc, 8×3=24
therefore Ethan has 112-24=88 more stickers than Marc
assume that the salaries of elementary school teachers in the united states are normally distributed with a mean of
Which choice is the explicit formula for the following geometric sequence? 0.2, -0.06, 0.018, -0.0054, 0.00162
Answer:
aₙ = 0.2(-0.3)⁽ⁿ⁻¹⁾
Step-by-step explanation:
The geometric sequence with the first term a, a common ratio r has the nth term given as
Tₙ = arⁿ⁻¹
where Tₙ is the nth term
From the given sequence
a = 0.2
r = -0.06/0.2
= -0.3
Hence the nth term
= 0.2 * -0.3ⁿ⁻¹
The right option is E
Answer:
aₙ = 0.2(-0.3)⁽ⁿ⁻¹⁾
Step-by-step explanation:
The five numbers summary for a data set is shown below. What is the range of the data set? 3, 7, 11, 14, 16
Answer:
13
Step-by-step explanation:
The range of a set of data is the difference between the highest and lowest values in the set.
So, in order to find the range, you first order the data from least to greatest. Which it is already.
3, 7, 11, 14, 16
Then subtract the smallest value from the largest value in the set.
16 - 3 = 13
Hope this helps you out! : )
Find the maximum and minimum values by evaluating the equation
Answer:
min = -9
max =3
Step-by-step explanation:
C = x-3y
x ≥0
x≤3
y≥0
y≤3
The minimum will be be when x is smallest and y is at its max
x =0 and y = 3
C = 0 - 3(3)
C = 0-9 = -9
The minimum is -9
The maximum occurs when x is largest and y is smallest
x =3 and y = 0
C = 3 - 3(0)
C = 3-0 = 3
The max is 3
A first number plus twice a second number is 14. Twice the first number plus the second totals 10. Find the numbers.
Answer:
first number(x) = 2 second number(y)= 6
Step-by-step explanation:
This is an example of a simultaneous equation.
First write this word problem as equations, where x is the "first number" that you've mentioned and y is the "second number".
x + 2y = 14 (equation 1)
2x + y = 10 (equation 2)
This is solved using the elimination method.
We need to make one of the coefficients the same - in this case we can make y the same. In order to do this we need to multiply equation 2 by 2, so that y becomes 2y.
2x + y = 10 MULTIPLY BY 2
4x + 2y = 20 (this is now our new equation 2 with the same y coefficient)
Now subtract equation 1 from equation 2.
4x - x + 2y - 2y = 20 - 14 (2y cancels out here)
3x = 6
x = 2
Now we substitute our x value into equation 1 to find the value of y.
2 + 2y = 14
2y = 12
y = 6
Hope this has answered your question.
Answer:
6 and 2
Step-by-step explanation:
Let the first number =a
Let the second number =b
A first number plus twice a second number is 14.
a+2b=14Twice the first number plus the second totals 10.
2a+b=10We solve the two equations simultaneously
[tex]a+2b=14 \implies a=14-2b\\$Substitute into the second equation$\\2(14-2b)+b=10\\28-4b+b=10\\-3b=10-28\\-3b=-18\\b=6[/tex]
Recall:
a=14-2b
=14-2(6)
=14-12
a=2
The two numbers are 6 and 2.
Copy the problem, mark the givens in the diagram, and write a Statement/Reason proof. Given: CS ≅ HR ∠CHS ≅ ∠HCR ∠CSH ≅ ∠HRC Prove: CR ≅ HS
Answer:
Step-by-step explanation:
Given: CS ≅ HR
∠CHS ≅ ∠HCR
∠CSH ≅ ∠HRC
Prove: CR ≅ HS
ΔCHS ≅ ΔHCR (Angle-Angle-Side, AAS, congruence property)
ΔICR ≅ ΔIHS (congruence property)
IS ≅ IR (similarity property)
CS ≅ HR (given)
Thus,
IC = IS + SC (addition property)
IH = IR + RH (addition property)
IC ≅ IH
Then,
CR ≅ HS (similarity property of triangles SCH and RHC)
Suppose that the functions g and h are defined for all real numbers x as follows.
gx = x − 3x
hx = 5x + 2
Write the expressions for (g - h)(x) and (g * h)(x) and evaluate (g + h)(−2).
Answer:
Step-by-step explanation:
Given the functions g(x) = x − 3x and h(x) = 5x + 2, we are to calculatae for the expression;
a) (g - h)(x) an (g * h)(x)
(g - h)(x) = g(x) - h(x)
(g - h)(x) = x − 3x -(5x+2)
(g-h)(x) = x-3x-5x-2
(g-h)(x) =-7x-2
b) (g * h)(x) = g(x) * h(x)
(g * h)(x) = (x − 3x )(5x+2)
(g * h)(x) = 5x²+2x-15x²-6x
(g * h)(x) = 5x²-15x²+2x-6x
(g * h)(x) = -10x²-4x
c) To get (g + h)(−2), we need to first calculate (g + h)(x) as shown;
(g + h)(x) an (g * h)(x)
(g + h)(x) = g(x) +h(x)
(g + h)(x) = x − 3x + (5x+2)
(g+h)(x) = x-3x+5x+2
(g+h)(x) =3x+2
Substituting x = -2 into the resulting function;
(g+h)(-2) = 3(-2)+2
(g+h)(-2) = -6+2
(g+h)(-2) = -4
Which line has a slope of -? 2 x – y = 0 - x + 2 y = 0 x - 2 y = 0 x + 2 y = 0 NEXT
Answer:
Easiest way to do this is to get the X's on one side of the equals sign and the Y's on the other. Then, you can choose the one with the negative sign in it.
When you do that,
First one is 2x=0+y, or y = 2x
Second one is 2y=0+x, or 2y = x (weird right)
Third one is x=0+2y, or 2y = x (again, weird right)
Final one is 2y=0-x, or 2y = -x
The final one is the answer. Cheers, but don't forget to remember this for next time bro.
Someone help me please
Answer:
31Option D is the correct option.
Step-by-step explanation:
Given: 3 boxes with volumes 1331 , 1331 , 729
To find : Height of stacked boxes
[tex]h {1}^{3} = 1331 = h1 = \sqrt[3]{1331} = 11[/tex]
[tex]h {2}^{3} = 1331 = h2 = \sqrt[3]{1331} = 11[/tex]
[tex]h {3}^{3} = 729 = h3 = \sqrt[3]{729} = 9[/tex]
Now,
[tex]h = h1 + h2 + h3[/tex]
[tex] = 11 + 11 + 9[/tex]
[tex] = 31[/tex]
Hope this helps...
Good luck on your assignment...
21.65 to 1 decimal place
Answer:
21.7
Step-by-step explanation:
When anything is 5 or above in a decimal place you round up to the next number for example
2.35 this would round up to be 2.4
21.65
Place value of 1 = ones place
Face value of 1 = 1
Note : The face value of a number will not change at all
Hope it helps you..If it's wrong plz say and I'll try to recorrect it :)
In a simple regression analysis for a given data set, if the null hypothesis β = 0 is rejected, then the null hypothesis ρ = 0 is also rejected. This statement is ___________ true. always
Answer:
Null hypothesis: [tex]\rho =0[/tex]
Alternative hypothesis: [tex]\rho \neq 0[/tex]
The statistic to check the hypothesis is given by:
[tex]t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}[/tex]
And is distributed with n-2 degrees of freedom
And the statistic to check the significance of a coeffcient in a regression is given by:
[tex] t_1 = \frac{\hat{\beta_1} -0}{S.E (\hat{\beta_1})}[/tex]
For this case is importantto remember that t1 and p value for test of slope coefficient is the same test statistic and p value for the correlation test so then the answer would be:
Always
Step-by-step explanation:
In order to test the hypothesis if the correlation coefficient it's significant we have the following hypothesis:
Null hypothesis: [tex]\rho =0[/tex]
Alternative hypothesis: [tex]\rho \neq 0[/tex]
The statistic to check the hypothesis is given by:
[tex]t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}[/tex]
And is distributed with n-2 degrees of freedom
And the statistic to check the significance of a coeffcient in a regression is given by:
[tex] t_1 = \frac{\hat{\beta_1} -0}{S.E (\hat{\beta_1})}[/tex]
For this case is importantto remember that t1 and p value for test of slope coefficient is the same test statistic and p value for the correlation test so then the answer would be:
Always
A square mesaures 80 yd on a side. Bob and Rob begin running from the same corner. Bob runs along a side to an adjacent corner, and Rob runs along a diagonal to an opposite corner. They arrive at their respective corners at the same time. If Bob's speed was 8mi/h, what was Rob's speed? Express your answer as a decimal to the nearest tenth.
Answer:
c = 11.3 mi/h
Step-by-step explanation:
Since Square has all of the same sides, hence bobs speed will be the same for all of the sides.
All of the sides are equal in a square
=> Let's consider the two sides along with the diagonal a right angled triangle
=> [tex]c^2 = a^2 + b^2[/tex]
Where c is the speed of Rob along the diagonal and b and c is the speed of Bob along the side
=> [tex]c^2 = 8^2+8^2[/tex]
=> [tex]c^2 = 64+64[/tex]
=> [tex]c^2 = 128\\[/tex]
Taking sq root on both sides
=> c = 11.3 mi/h