Find EF given E(-7, -2) and F(11, 3). Round your answer to the nearest thousandth (3 decimal places).

Answer:

2,3,5,6,8,9 (i think)

Step-by-step explanation:

Answer:

2,3,5,6,8,9

Step-by-step explanation:

Answer:

c.

Step-by-step explanation:

Answer:

-infinity < x < +infinity

Step-by-step explanation:

the domain of a cube root function is the set of all real numbers. unlike a square root function which is limited to non-negative numbers, a cube root can use all real numbers because it is possible for three negatives to equal a negative.

Answer:

A

Step-by-step explanation:

Edge 2021

Answer: Jayden walked 8 miles on Tuesday

Step-by-step explanation:

Answer:

one

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

Postulate 3: Through any two points, there is exactly one line.

Answer:

Step-by-step explanation:

f(-7)= -3(-7)^2 - 20

f(-7) = -3(49) - 20

       = -147 - 20 = -167

Answer:−2=x that’s the answer

Answer:

  x = 7

Step-by-step explanation:

The sum of the interior angles is 90°, so you have ...

  (7x +8) +(5x -2) = 90

  12x = 84 . . . . subtract 6; next, divide by 12

  x = 7

Answer:

[tex]\bold{cot(t) =\dfrac{12}{5}}[/tex]

Step-by-step explanation:

Given that:

[tex]Cosec (t) = -\frac{13}5[/tex]

for [tex]\pi < t < \frac{3 \pi}2[/tex]

That means, angle [tex]t[/tex] is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

[tex]cosec^2\theta -cot^2\theta =1[/tex]

here, [tex]\theta =t[/tex]

So, [tex]cosec^2t-cot^2t=1[/tex]

[tex]\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}[/tex]

But, angle [tex]t[/tex] is in 3rd quadrant, so value of

[tex]\bold{cot(t) =\dfrac{12}{5}}[/tex]

Answer:

12/5

Step-by-step explanation:

Answer:

(4 * (1 + 2 * 3))^5

Step-by-step explanation:

Try many possibilites and see which one is greater.

The '5' should be an exponent, as it will make the result very large.

Multiplication is usually an operation that makes numbers very big.

Answer:

a. The given equation is d = -75·t + 275 is a function

b. f(t) = -75·t + 275

c.  275 km

d. The situation does not makes sense for t > 11/2 hours.

Step-by-step explanation:

a. Given that a relation is a functional relation if for each input of a member in the relation, there is only one output for the other member, therefore;

The given equation is d = -75·t + 275 is a function

As when t = 1, d = 200 km

b. The equation written in functional notation, f(t) is f(t) = -75·t + 275

c. At the start of the journey, t = 0

Therefore;

f(0) = -75×0 + 275 = 275 km

d. The values of t that do no make sense in the function are given as follows

0 = -75×t + 275

t = 275/75 = 11/3 = 3.67 hours

For times above 3.67, the distance becomes negative

Therefore, the situation does not makes sense for t > 11/2 hours.

Greetings from Brasil...

Solving this equation

Answer:

7.000l is a terminatin decimal.

Step-by-step explanation:

It is an terminating decimal because it stops right at 1, and the one is not repating too. If it was repeating it would be a repating decimal. We know it's not also an integer because we dont see a ngegative sign next to the seven.  

Therefore, 7.0001 is a terminating decimal.

I gave steps in the picture how to solve it was much easier to write it out then type it. hope this helps!

Answer:

87.48

Step-by-step explanation:

First find the area of the square

12^2=144

find area of the 2 circles

9*3.14

but theres 2

18*3.14=56.52

144-56.52=87.48

Answer:

The height of Ara's tree is 50/3 feet while Vartan's tree is 25/3 feet high

Step-by-step explanation:

Represent Ara's tree with A and Vartan's with V

Given

[tex]A = 2V[/tex]

[tex]A + V = 25[/tex]

Required

Determine A and V

[tex]A = 2V[/tex]

[tex]A + V = 25[/tex]

Substitute 2V for A in [tex]A + V = 25[/tex]

[tex]2V + V= 25[/tex]

[tex]3V = 25[/tex]

Divide both sides by 3

[tex]V =\frac{25}{3}\ feet[/tex]

Recall that [tex]A = 2V[/tex]

So:

[tex]A = 2 * \frac{25}{3}\ feet[/tex]

[tex]A = \frac{2 * 25}{3}\ feet[/tex]

[tex]A = \frac{50}{3}\ feet[/tex]

Hence, the height of Ara's tree is 50/3 feet while Vartan's tree is 25/3 feet high

◈ LHS :

[tex]:\implies\tt\:sin60\degree[/tex]

[tex]:\implies\bf\:\dfrac{\sqrt{3}}{2}[/tex]

◈ RHS :

[tex]:\implies\tt\:\dfrac{2tan30\degree}{1+tan^230\degree}[/tex]

[tex]:\implies\tt\:\dfrac{2\times \dfrac{1}{\sqrt{3}}}{1+{\large(}\dfrac{1}{{\sqrt{3}}}{\large)}^2}[/tex]

[tex]:\implies\tt\:\dfrac{2}{\sqrt{3}}\times \dfrac{3}{3+1}[/tex]

[tex]:\implies\tt\:\dfrac{2}{\sqrt{3}}\times \dfrac{3}{4}[/tex]

[tex]:\implies\bf\:\dfrac{\sqrt{3}}{2}[/tex]

Hence Proved !!

Answer:

A) 20+0.6[tex]x[/tex]

B) range is [0, 50] (i.e. both inclusive)

C) 8.33 litres

Step-by-step explanation:

Given that concentration of acid in 50 litre container is 40%.

Amount of acid in the container = 40% of 50 litres

Amount of acid in the container = [tex]\frac{40}{100} \times 50 = 20\ litre[/tex]

[tex]x[/tex] litres are removed.

Amount of acid removed = 40% of [tex]x[/tex] litre.

Now, remaining acid in the container = (20 - 40% of [tex]x[/tex]) litre

Now, replaced with 100% acid.

So, final acid in the container = (20 - 40% of [tex]x[/tex] + 100% of [tex]x[/tex] ) litre

Amount of acid in the final mixture:

[tex]20 - \dfrac{40}{100} \times x + \dfrac{100}{100} \times x\\\Rightarrow 20 +\dfrac{100-40}{100}x\\\Rightarrow 20 +\dfrac{60}{100}x[/tex]

Answer A) Amount of acid in the final mixture = 20+0.6[tex]x[/tex]

Answer B) [tex]x[/tex] can not be greater than 50 litres (initial volume of container) and can not be lesser than 0 litres.

so, range is [0, 50] (i.e. both inclusive)

Answer C)

Given that final mixture is 50% acid.

amount of acid = 50% of 50 litres = 25 litres

Using the equation:

[tex]20+0.6x =25\\\Rightarrow 0.6x =5\\\Rightarrow \bold{x =8.33\ litres}[/tex]

Answer:

Problem 2:

4x - 20 = 4

4x = 24

x = 6

Step-by-step explanation:

Answer:

91 +3409/12500

Step-by-step explanation:

Did you mean simplify as a fraction?

Answer:

D

Step-by-step explanation:

8 hours and 35 minutes can be rewritten as the mixed fraction 8 35/60.

You can reduce this fraction by dividing the numerator and denominator by 5.

35/5 = 7

60/5 = 12

So, 35/60 = 7/12

Now add 8 to your reduced fraction.

8 + 7/12 = 8 7/12

Hope this helped!

Answer:

The answer to this problem is x = 3 and y = -2.

Step-by-step explanation:

To solve this problem, we first have to remember how to solve problems using substitution.  We first solve one equation completely in terms of another variable.  In this case, this has already been done for us - the first equation is in the form y = f(x).  Next, we should substitute this "value" or function for y into the other equation.  This process is modeled below:

y = -4x + 10

y = -6x + 16

If we substitute, we get:

-4x + 10 = -6x + 16

Now this is a simple one variable equation that we can solve easily.  First, we should add 6x to both sides, giving us:

2x + 10 = 16

Then, we should subtract 10 from both sides, yielding:

2x = 6

Finally, we can divide both sides by 2 to get:

x = 3

Now, we must plug in this value for x into one of our original equations (it doesn't matter which one we choose) to solve for the other variable, y.

y = -4x + 10

y = -4(3) + 10

y = -12 + 10

y = -2

Therefore, the answer to this problem is x = 3 and y = -2.

Hope this helps!

Answer:

x = 3

y = -2

Step-by-step explanation:

y = -4x + 10       first equation

y = -6x + 16        second equation

from the second equation:

6x = -y + 16

x = (-y + 16) / 6       third equation

substituying the value of the third equation into the first equation:

y = -4(-y+16)/6 + 10

y - 10 = -4(-y+16(/6

6(y-10) = -4(-y+16)

6*y + 6*-10 = -4*-y -4*16

6y - 60 = 4y - 64

6y - 4y = 60 - 64

2y = -4

y = -4/2

y = -2

from the third equation:

x = (-y + 16) / 6

x = (-(-2) + 16) / 6

x = (2+16)/6

x = 18/6

x = 3

Check:

from the first equation:

y = -4x + 10

-2 = -4*3 + 10

-2 = -12 + 10

Answer:

is that all the context that is given?

Answer:

x=7

Step-by-step explanation:

4x-2(x+3)=8

4x-2x-6=8

2x-6+6=8+6

2x=14

x=7

Proof:

4x-2(x+3)=8

4(7)-2(7+3)=8

28-14-6=8

14-6=8

8=8

Hope this helps ;) ❤❤❤

The value of x in the equation 4x - 2(x+3) = 8 is 7.

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

We need to find the value of x in the equation 4x - 2(x+3) = 8

4x-2(x+3)=8

4x-2x-6=8

2x-6+6=8+6

2x=14

x=7

Proof: 4x-2(x+3)=8

4(7)-2(7+3)=8

28-14-6=8

14-6=8

8=8

Hence, the value of x in the equation 4x - 2(x+3) = 8 is 7.

Learn more about equations here;

https://brainly.com/question/10413253

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Answer:

1/10x+3

Step-by-step explanation:

1/6(3/5x+18)

Multiply 3/5x and 18 by 1/6

1/10x+3

Answer:

1/5

Step-by-step explanation:

5^-1/5^0

=5^-1/1

=1/5

Answer:

1< and 2< are equal to 125

Step-by-step explanation:

The angle of a straight line is 180, so it would be 180° minus 55°, and that equals to 125°

Hi there! :)

Answer:

[tex]\large\boxed {\frac{1}{4}}[/tex] Common difference

[tex]\large\boxed{\frac{3}{2}, \frac{7}{4}, 2}[/tex] Next three terms

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Find the common difference by subtracting the previous term from a term. We can use the terms 1/4 and 1/2:

Convert 1/2 into a fraction over 4:

1/2 · 2/2 = 2/4

Find the common difference by subtracting the fractions:

2/4 - 1/4 = 1/4. This is the common difference.

Find the next 3 terms by adding 1/4:

5/4 + 1/4 = 6/4 (Reduce fraction) = 3/2

6/4 + 1/4 = 7/4

7/4 + 1/4 = 8/4 (Reduce fraction)

Therefore, the next 3 terms are 3/2, 7/4 and 2.