Answer:
[tex]-\sqrt{14} < c < \sqrt{14}[/tex]
Step-by-step explanation:
For the function to have a domain of all reals, the denominator cannot have a value of zero. x^2 + 2cx + 14 will not have zero as a root if it has no real solutions. A quadratic equation has no solutions when the discriminant is negative.
b^2 - 4ac < 0
(2c)^2 - 4(1)(14) < 0
4c^2 - 56 < 0
4c^2 < 56
c^2 < 14
[tex]-\sqrt{14} < c < \sqrt{14}[/tex]
The domain of the function, f(x) = (x + 7) / (x^2 + 2cx + 14) is the set of all real numbers for the value of c as [tex]-\sqrt{14} < c < \sqrt{14}[/tex] .
Domain of a function are the values that a function can take that is the set of all possible inputs.
Given the following function:
[tex]f(x)=\dfrac{x+7}{x^2+2cx+14}[/tex]
For the real number domain of the given function, the denominator must be a non-zero term. Because, if the denominator is zero then the function will result in an undefined number which does not lie in the real number domain.
For denominator to be non zero, we have to find the value of x which is not the solution of the equation of denominator.
x²+2cx+14≠0
Such value of x can be determined using discriminant.
d<0, then no real solution exists.
d=b²-4ac
Here a=1, b=2c, c=14
d=4c²-4x14
d=4c²-56
d<0
4c²-56<0
4c²<56
c²<14
[tex]-\sqrt{14} < c < \sqrt{14}[/tex]
Thus, [tex]-\sqrt{14} < c < \sqrt{14}[/tex] is such that the domain of the function is the set of all real numbers.
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please someone help me to prove this.
Answer: see proof below
Step-by-step explanation:
Use the following Power Reducing Identities:
[tex]\sin^3\theta= \dfrac{1+\cos 2\theta}{2}\\\\\\\cos^2\theta=\dfrac{3\sin \theta-\sin 3\theta}{4}[/tex]
Use the following Product to Sum Identity:
[tex]\sin A \cdot \cos B = \dfrac{1}{2}\bigg[\sin (A + B) + \sin (A - B)\bigg][/tex]
Proof LHS → RHS
LHS: cos² Ф · sin³ Ф
[tex]\text{Power Reducing:}\qquad \bigg(\dfrac{1+\cos 2\theta}{2}\bigg)\bigg(\dfrac{3\sin \theta-\sin 3\theta}{4}\bigg)[/tex]
[tex]\text{Expand:}\qquad \qquad \dfrac{1}{8}(3\sin \theta -\sin 3\theta +3\sin \theta\cdot cos 2\theta-\sin 3\theta \cdot \cos 2\theta)[/tex]
[tex]\text{Product to Sum:}\\ \dfrac{1}{8}\bigg[3\sin \theta -\sin 3\theta +\dfrac{3}{2}\bigg(\sin (\theta +2\theta) +\sin(\theta -2\theta)\bigg)-\dfrac{1}{2}\bigg(\sin (3\theta+2\theta) +\sin (3\theta-2\theta)\bigg)\bigg][/tex]
[tex]\text{Simplify:}\quad \dfrac{1}{8}\bigg[3\sin \theta -\sin 3\theta +\dfrac{3}{2}\bigg(\sin 3\theta +\sin(-\theta)\bigg)-\dfrac{1}{2}\bigg(\sin 5\theta +\sin \theta\bigg)\bigg][/tex]
[tex]\text{Cofunction:}\quad \dfrac{1}{8}\bigg[3\sin \theta -\sin 3\theta +\dfrac{3}{2}\bigg(\sin 3\theta -\sin(\theta)\bigg)-\dfrac{1}{2}\bigg(\sin 5\theta +\sin \theta\bigg)\bigg][/tex]
[tex]\text{Simplify:}\qquad \dfrac{1}{16}\bigg(6\sin \theta -2\sin 3\theta +3\sin 3\theta -3\sin(\theta)-2\sin 5\theta -2\sin \theta\bigg)\\\\\\.\qquad \qquad =\dfrac{1}{16}\bigg(2\sin \theta + \sin 3\theta -\sin 5\theta\bigg)[/tex]
[tex]\text{LHS=RHS:}\quad \dfrac{1}{16}\bigg(2\sin \theta + \sin 3\theta -\sin 5\theta\bigg)=\dfrac{1}{16}\bigg(2\sin \theta + \sin 3\theta -\sin 5\theta\bigg)\quad \checkmark[/tex]
Place the vertices of polygon ABCD wherever you wish, and record the coordinates of its vertices. What are the coordinates of the vertices of the reflected polygons when the x-axis and y-axis are used as the lines of reflection? Record the coordinates in the table.
Answer:
This answer assumes the vertices of the polygon are at A(1, 2), B(2, 3), C(3, 2), and D(2, 1).
Step-by-step explanation:
A (1, 2) Ax (1, −2) Ay (−1, 2)
B (2, 3) Bx (2, −3) By (−2, 3)
C (3, 2) Cx (3, −2) Cy (−3, 2)
D (2, 1) Dx (2, −1) Dy (−2, 1)
Answer:
Vertex Coordinate Vertex Coordinate Vertex Coordinate
A (1, 2) Ax (1, −2) Ay (−1, 2)
B (2, 3) Bx (2, −3) By (−2, 3)
C (3, 2) Cx (3, −2) Cy (−3, 2)
D (2, 1) Dx (2, −1) Dy (−2, 1)
Step-by-step explanation:
Plato Sample Anwser
Write the verbal expression for each algebraic expression.
Can anyone help me with this? Thank you so much if you can!!
Step-by-step explanation:
i hope it helped you a lot. thankyou
C is the midpoint of BD . If CD = 2x and BD = 3x + 5, what is CD?
what is the equation of a horizontal line passing through the point (-3,8)
Answer:
y=8
Step-by-step explanation:
Horizontal equations are of the form
y =
The y coordinate is 8
y=8
Can someone pls help
Answer:
Negative
Step-by-step explanation:
A negative plus a negative (negative minus a positive) will give you a negative. -1.69 + (-1.69) = -3.38
-3.38 is a negative, therefore the answer is negative.
A baseball player hits a pop fly ball toward left field where it is caught by a player at a height of 5 feet. The ball was hit at a height of 3 feet and reached a height of 50 feet. The height of the ball is a function of time. What is the range of this function?
Answer:
The range of the function are the values of height which are from 3, 4, 5, ..., 50
Step-by-step explanation:
The given parameters are;
The height at which the ball is caught = 5 feet
The height at which the ball was hit = 3 feet
The maximum height reached by the ball = 50 feet
The height of the ball given as a function of time is f(t) s = u·t - 1/2·g·t²
Where;
s = 50 feet
g = 9.81 m/s²
Therefore, we have;
50 = u·t - 1/2 × 9.81 × t²
50 = u·t - 4.905 × t²
Therefore, the range are obtainable values for f(t) which range from 3 to 50.
PLEASE HELP AND HURRY!!
is it possible for a rectangle to have rational side lengths and an irrational area?
Yes
For Example :If the rectangle has sides of Square root 8 and square root 2 which are two irrational numbers but when multiplied it gives an area of 4 square units which is a rational number.
No, it is not possible for a rectangle to have rational side lengths and an irrational area, because two rational numbers are always rational.
Given that,
To figure out, is it possible for a rectangle to have rational side lengths and an irrational area.
Rational numbers can be structured in the form of the fraction of integers. Eg- 5/6, 2/3, etc.
Here,
in a rectangle, two sides have rational length and the area of the rectangle is a product of the sides of the rectangle.
Since there is a property of the rational numbers that, when two rational numbers are multiplied together the product of the rational number is always rational.
So the area of the rectangle also would be rational.
Thus, it is not possible for a rectangle to have rational side lengths and an irrational area.
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if x^2-13x+42=(x+A)(x+B), then find the value of 3A-B
Answer:
- 11 or - 15
Step-by-step explanation:
Factorise
x² - 13x + 42
Consider the factors of the constant term (+ 42) which sum to give the coefficient of the x- term (- 13)
The factors are - 6 and - 7, since
- 6 × - 7 = + 42 and - 6 - 7 = - 13, thus
x² - 13x + 42 = (x - 6)(x - 7)
compare to (x + A)(x + B)
A = - 6, B = - 7
thus 3A - B = 3(- 6) - (- 7) = - 18 + 7 = - 11
The factors may also be expressed as (x - 7)(x - 6)
with A = - 7 and B = - 6, then
3A - B = 3(- 7) - (- 6) = - 21 + 6 = - 15
In the complex number z = x + yi, what is the real part?I
Х
Y
Z
Answer:
X is the real part
Step-by-step explanation:
algebra 1 I need help
There's a bit of lack of context but I think the question is just asking what variables to put in for Lucy and Howard. There seems to be no need to answer any math problem.
I suggest using the variables x and y or l for Lucy and h for Howard. Remember to use lowercase letters.
someone help me pls
Answer:
1) x = 0
2) x = 2
Step-by-step explanation:
1)
12 = -4(-6x - 3)
First, we distribute.
12 = 24x + 12
Then, we combine like terms.
12 - 12 = 24x
0 = 24x
Finally, we divide 24 on both sides.
We got 0 = x, or x = 0
-
2)
-20 = -4x - 6x
First, we simplify.
-20 = -10x
Then, we divide -10 on both sides.
We got 2 = x, or x = 2
-
Hope this helps!
-3 3/5 x (-8 1/3)= ;-;just write the answer no need to explain. I'm tryna cheat on I-ready and I'm too lazy to do this in my head ;w;.
the answer is 30( -3 3/5*(-8 1/3
Solve 1/2+3<5 i need help please on this question
Answer:
the second choice
Step-by-step explanation:
[tex] \dfrac{1}{2}n + 3 < 5 [/tex]
Subtract 3 from both sides.
[tex] \dfrac{1}{2}n < 2 [/tex]
Multiply both sides by 2.
[tex] n < 4 [/tex]
To show n < 4 on a number line, you put an open circle on 4, and you color the line to the left of 4.
Answer: the second choice
Use the number line below, where RS = 7y +5. ST = 3y +5, and RT = 70.
a. What is the value of y?
Answer:
Step-by-step explanation:
7y+5+3y+5=70
10y+10=70
10y=60
y=6
7(6)+5= 42+5= 47
3(6)+5= 18 + 5 =23
47+23= 70
Please show all work and not just the answers.
Answer: Answer is in the steps
Step-by-step explanation:
To determine if their are congruent ,find the distance between the points.
In AB it has the points (-6,-4) and (-1,8)
Now to find the distance you will have to find the difference between the x and y values then square them to add them and find the square root.
-4 - 8 = -12
-6 - (-1) = -5
12^2 + 5^2 =d^2 where d is the distance so solve for d
144 + 25 = d^2
169 =d^2
d = [tex]\sqrt{169}[/tex]
d= 13
So we now the distance of AB is 13
now we need to find the distance between CD
(2,5) (14,0) using these points follow the same steps in the first step to find the distance.
5-0= 5
2 -14 = -12
5^2 + 12^2 = d^2
25 + 144 = d^2
169 =d^2
d = [tex]\sqrt{169}[/tex]
d= 13
So using the information we can say the segments are congruent because they have the same distances .
A small family home in tucson arizona has a rooftop area of 1967 square feet, and it is possible to capture rain falling on about 56% of the roof
Answer:
Volume = 36.4 m^3 or 9616.6 gallon
weight = 18025.47 N or 80213.33 lbs
Step-by-step explanation:
The complete question is
A small family home in Tucson, Arizona, has a rooftop area of 1967 square feet, and it is possible to capture rain falling on about 56% of the roof. A typical annual rainfall is about 14 inches. If the family wanted to install a tank to capture the rain for an entire year, without using any of it, what would be the required volume of the tank in m3 and in gallons? How much would the water weigh when the tank was full (in N and in lbf)?
The area of the roof = 1967 ft^2
Area of water to be possibly captured = 56% of 1967 ft^2 = 0.56 x 1967 = 1101.52 ft^2
Rainfall depth = 14 inches = 14/12 ft = 1.167 ft
Volume of water = (area of water) x (depth of water) = 1101.52 ft^2 x 1.167 ft = 1285.47 ft^3
35.315 ft^3 = 1 m^3
1285.47 ft^3 = [tex]x[/tex] m^3
==> 1285.47/35.315 = 36.4 m^3
1 ft^3 = 7.481 gallon
1285.47 ft^3 = [tex]x[/tex] gallon
==> 1285.47 x 7.481 = 9616.6 gallon
Weight of water W = ρv
where ρ is the density of water = 62.4 lbs/ft^3
v is the volume of water = 1285.47 ft^3
substituting values,
W = 62.4 x 1285.47 = 80213.33 lbs
but,
1 lb = 4.45 N
therefore,
80213.33 lbs = 80213.33/4.45 = 18025.47 N
Ali has x cards.
Belinda has twice as many cards as Ali.
Charlie has 5 more cards than Ali.
They have a total of 33 cards.
(a) Show that 4x + 5 = 33
(b) Work out the number of cards Ali has.
━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━
If Ali has x cards, then Belinda has 2x cards.
If Ali has x cards, then Charlie has x+5 cards.
2x (Belinda) + x+5 (Charlie) + x (Ali) = 33 (total)
2x + x+5 + x = 33
Now simplify the equation... x+x+5 can be simplified as 2x+5.
2x+5 plus 2x can become 4x+5.
So their total number is 4x+5.
So 4x+5=33.
You want to isolate the variables and numbers.
To remove the 5 from the left side, subtract 5 from both sides.
4x+5-5=4x - 33-5=28
So the equation now is 4x=28
To remove the 4, divide each side by 4.
4x÷4=x - 28÷4=7
So x equals 7, Ali has 7 cards.
━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━
Which choice shows a function with a domain of {-4,-2,2,4}?
Answer:
It's the third option
Step-by-step explanation:
the domain is all the x values
A football team loses 4 yards on there first play loses 13 on there second play then gains 2 yards on thrid play find the change in yards in three plays
Answer:
Step-by-step explanation:
Play 1 they lose 4y
-4
Play 2 they lose 13y
-13
Total so far we have
-17
play three they gain 2y
-17+2=-15
Over the course of three plays the team loses 15 Yards.
9=7d+8(9-2d)
A d=-1/9
B d=-9
C d=7
D=1/7
[tex]9=7d+8(9-2d)\\9=7d+72-16d\\9=-9d+72\\-72+9=-9d\\-63=-9d\\d=7[/tex]
Also for the 8(9-2d), simplify by multiplying the 8 into the (9-2d) as we get (8*9)-(8*2d) = 72-16d
Therefore, the answer is d = 7 aka C.
.If x2 + kx+ 6 = (x + 2) (x + 3) for all x, then the value of k is
Answer:
k = 5
Step-by-step explanation:
[tex](x + 2)(x + 3) = {x}^{2} + 5x + 6[/tex]
Now comparing left hand side & right hand side ,
[tex] {x}^{2} + kx + 6 = {x}^{2} + 5x + 6[/tex]
Cancelling x^2 & 6 from both left hand side & right hand side ,
kx = 5x
=> k = 5
You are planning to plant a triangular garden in your backyard, as shown. You plan to put up a fence around the garden to keep out animals. Find the length of fencing you need to the nearest meter.
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete has the figure of the triangle is not given.
However, the following steps will guide you.
To solve this question;
you need the lengths of the threes sides of the triangular fields
Represent these lengths with a, b and c
Next;
Sum these lengths together;
This gives the required length of fencing
[tex]Length = a + b + c[/tex]
Take for instance;
[tex]a =4;\ b = 3;\ c = 5[/tex]
The required length of fence would be
[tex]Length = 4 + 3 + 5[/tex]
[tex]Length = 12\ units[/tex]
Apply these steps and you'll get your answer
Can anyone tell me the rules for rounding of digits? plz ASAP
Answer:
u use the closest number to the number u are rounding up to round it up.if it is 0-4 u round it to 0and add to the number while if it is 5-9 u round it up to 1 and add to the number.after all rounding up the number used to round up downwards will be converted to 0s
Answer:
If the ones place has a number less than 4, the tens stay the same with a zero in the ones place. If the ones place has a number more than 5, the tens will have another ten. If the ones place has a number 5 in the ones place, then you round the tens to the next ten.
Examples: 37=40 73=70 65=70
The greatest integer funtion, shown below, is defined to be the greatest ______ less than or equal to x.
f(x)={{x}}
Answer:
Integer
Step-by-step explanation:
The greatest integer function (as known as the floor function), is defined as to be the greatest integer less than or equal to x.
It is the function:
[tex]f(x)=\floor[x][/tex]
For instance, if x is 2, then f(x) is 2. If x is 2.7, then f(x) is still 2. 2 is the greatest integer less than or equal to 2.
You can also see this from the attached graph.
Can someone please help me
Answer:
15.231
Step-by-step explanation:
Why 16 not a perfect cube
A perfect cube is a number that is the cube of an integer. For example, 125 is a perfect cube since 125 = 5 × 5 × 5= [tex]5^{3}[/tex]. Some examples of perfect cubes are 1, 8, 27, 64, 125, 216, 343, ..
16 does not have a perfect cube, but does have a perfect square 4×4=16
A map is created of Maricopa County with a scale factor of 1 inch = 2.5 miles. The distance between Phoenix and Fountain Hills is 2.92 inches on the map. Determine the actual distance between the two cities.
Answer:
The actual distance between Phoenix and Fountain Hills is 7.3 miles
Step-by-step explanation:
We note that the scale factor gives the ratio of the map reading to the actual distance reading
The scale factor of the map is 1 inch = 2.5 miles
The distance between Phoenix and Fountain Hills = 2.92 inches on the map
Let the actual distance between Phoenix and Fountain Hills = D, we have;
D/(2.92 inches) = 2.5 miles/inch
Therefore;
D = 2.92 inches × 2.5 miles/inch = 7.3 miles
D = 7.3 miles
The actual distance between Phoenix and Fountain Hills = D = 7.3 miles.
Develop a formula for finding the midpoint of a segment with endpoints A(0, 0) and B(m, n).
Answer:
(0+m)/2. (0+n)/2
Step-by-step explanation:
U sum both x coordinates and divide by two. U do same to the t values.
The formula used to find the midpoint of a segment with endpoints A(0, 0) and B(m, n) is x = m / 2 and y = n / 2.
What is the midpoint on a given line?
If on a straight line we have two endpoints:
- [tex](x_{1}~,y_{1})[/tex]
- [tex](x_{2},~ y_{2} )[/tex]
and the midpoint is given by ( x, y ).
Then to find the midpoint on a straight line we use the formula:
x = ( [tex]x_{2}[/tex] + [tex]x_{1}[/tex] ) / 2
y = ( [tex]y_{2}+y_{1}[/tex] ) / 2
We have,
[tex](x_{1}~,y_{1})[/tex] = ( 0, 0 )
[tex](x_{2},~ y_{2} )[/tex] = ( m, n )
[tex]x_{1}[/tex] = 0
[tex]x_{2}[/tex] = m
[tex]y_{1}[/tex] = 0
[tex]y_{2}[/tex] = n
We will use the formula :
x = ( [tex]x_{2}[/tex] + [tex]x_{1}[/tex] ) / 2
y = ( [tex]y_{2}+y_{1}[/tex] ) / 2
And substitute the values.
x = ( m + 0 ) / 2
y = ( n + 0 ) / 2
x = m / 2
y = n / 2.
The formula used to find the midpoint of a segment with endpoints A(0, 0) and B(m, n) is x = m / 2 and y = n / 2.
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Can someone just tell me the answer you don’t have to explain it pleaseeeeee for #13 And #15
Answer:
13) (-5,1)
Step-by-step explanation: