1. You borrow $500 from a bank with a 5% annual interest and
the maturity date is in 3 years
a. How much would you pay in interest at the end of the
loan if you pay simple interest
b. How much would you pay in interest at the end of the
loan if you pay in compound interest
Answer:
Step-by-step explanation:
Discussing interest starts with the principal, or amount your account starts with. This could be a starting investment, or the starting amount of a loan. Interest, in its most simple form, is calculated as a percent of the principal. For example, if you borrowed $100 from a friend and agree to repay it with 5% interest, then the amount of interest you would pay would just be 5% of 100: $100(0.05) = $5. The total amount you would repay would be $105, the original principal plus the interest.
Dan is helping to build a stage for a concert.
4 m
3 m
3 m
3.5 m
12 m
He needs to order some non-slip flooring for the stage.
Calculate the area of the stage.
Answer: 37m
Step-by-step explanation:
Convert 300cm into m = 3m
6 + 6 + 3 + 3 + 3.5 + 3.5 + 12 = 37m
What is the volume of the prism, In cubic inches?
Answer:
55 in²
Step-by-step explanation:
Base x Height
In your own words, explain how to factor a quadratic expression
Step-by-step explanation:
With the quadratic equation in this form: [tex]ax^2+bx+c=0[/tex]
Step 1: Find two numbers that multiply to give ac (in other words a times c), and add to give b.
Example: 2x^2 + 7x + 3
ac is 2×3 = 6 and b is 7
So we want two numbers that multiply together to make 6, and add up to 7
In fact 6 and 1 do that (6×1=6, and 6+1=7)
How do we find 6 and 1?
It helps to list the factors of ac=6, and then try adding some to get b=7.
Factors of 6 include 1, 2, 3 and 6.
1 and 6 add to 7, and 6×1=6.
Step 2: Rewrite the middle with those numbers:
Rewrite 7x with 6x and 1x:
2x^2 + 6x + x + 3
Step 3: Factor the first two and last two terms separately:
The first two terms 2x^2 + 6x factor into 2x(x+3)
The last two terms x+3 don't actually change in this case
So we get:
2x(x+3) + (x+3)
Step 4: If we've done this correctly, our two new terms should have a clearly visible common factor.
In this case we can see that (x+3) is common to both terms, so we can go:
Start with: 2x(x+3) + (x+3)
Which is: 2x(x+3) + 1(x+3)
And so: (2x+1)(x+3)
Done!
Check: (2x+1)(x+3) = 2x2 + 6x + x + 3 = 2x2 + 7x + 3 (Yes)
Please Mark As Brainliest
A system of two linear equations is graphed on a coordinate plane. If the system of equations has infinitely many solutions, which statement must be true?
A
The lines are parallel.
B
The lines intersect in one point.
C
The lines are the same.
D
None of the above
Answer:
c
Step-by-step explanation:
Infinite solutions. A system of linear equations has infinite solutions when the graphs are the exact same line.
So C would be the most accurate statement
please give brainiest
-8 is an irrational number.
True
False
Answer:
false
Step-by-step explanation:
can you just please click on this and help
Answer:
i think its b but im not 100 percent sure...
Step-by-step explanation:
Answer:
Step-by-step explanation:
The answer is d
For which quadratic equation are the solutions 6 and -8?
A)
x2 + 2x = 48
B)
**+ 8x - 48
C)
x2 - 2x = 48
D)
x2 + 2x = -48
Answer:
A
Step-by-step explanation:
A) is the right answer.
Answer:
A
Step-by-step explanation:
A) Yes, this is solution
b) No
c) No
d) NO
Based on the number of voids, a ferrite slab is classified as either high, medium, or low. Historically, 5% of the slabs are classified as high, 85% as medium, and 10% as low. A group of 20 slabs that are independent regarding voids is selected for test ing. Let X, Y, and Z denote the number of slabs that are classified as high, medium, and low, respectively.
(a) What are the name and values of the parameters of the joint probability distribution of X, Y , and
Z?
(b) What is the range of the joint probability distribution of X, Y, and Z?
(c) What are the name and the values of the parameters of the marginal probability distribution of X?
(d) Determine E[X] and Var(X).
Determine the following:
(e) P{X = 1, Y = 17, Z = 3}
(f) P{X ? 1, Y = 17, Z = 3}
(g) P{X ? 1}
(h) E[Y ]
Answer:
(a) Name: Multinomial distribution
Parameters: [tex]p_1 = 5\%[/tex] [tex]p_2 = 85\%[/tex] [tex]p_3 = 10\%[/tex] [tex]n = 20[/tex]
(b) Range: [tex]\{(x,y,z)| x + y + z=20\}[/tex]
(c) Name: Binomial distribution
Parameters: [tex]p_1 = 5\%[/tex] [tex]n = 20[/tex]
[tex](d)\ E(x) = 1[/tex] [tex]Var(x) = 0.95[/tex]
[tex](e)\ P(X = 1, Y = 17, Z = 3) = 0[/tex]
[tex](f)\ P(X \le 1, Y = 17, Z = 3) =0.07195[/tex]
[tex](g)\ P(X \le 1) = 0.7359[/tex]
[tex](h)\ E(Y) = 17[/tex]
Step-by-step explanation:
Given
[tex]p_1 = 5\%[/tex]
[tex]p_2 = 85\%[/tex]
[tex]p_3 = 10\%[/tex]
[tex]n = 20[/tex]
[tex]X \to[/tex] High Slabs
[tex]Y \to[/tex] Medium Slabs
[tex]Z \to[/tex] Low Slabs
Solving (a): Names and values of joint pdf of X, Y and Z
Given that:
[tex]X \to[/tex] Number of voids considered as high slabs
[tex]Y \to[/tex] Number of voids considered as medium slabs
[tex]Z \to[/tex] Number of voids considered as low slabs
Since the variables are more than 2 (2 means binomial), then the name is multinomial distribution
The parameters are:
[tex]p_1 = 5\%[/tex] [tex]p_2 = 85\%[/tex] [tex]p_3 = 10\%[/tex] [tex]n = 20[/tex]
And the mass function is:
[tex]f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z[/tex]
Solving (b): The range of the joint pdf of X, Y and Z
Given that:
[tex]n = 20[/tex]
The number of voids (x, y and z) cannot be negative and they must be integers; So:
[tex]x + y + z = n[/tex]
[tex]x + y + z = 20[/tex]
Hence, the range is:
[tex]\{(x,y,z)| x + y + z=20\}[/tex]
Solving (c): Names and values of marginal pdf of X
We have the following parameters attributed to X:
[tex]p_1 = 5\%[/tex] and [tex]n = 20[/tex]
Hence, the name is: Binomial distribution
Solving (d): E(x) and Var(x)
In (c), we have:
[tex]p_1 = 5\%[/tex] and [tex]n = 20[/tex]
[tex]E(x) = p_1* n[/tex]
[tex]E(x) = 5\% * 20[/tex]
[tex]E(x) = 1[/tex]
[tex]Var(x) = E(x) * (1 - p_1)[/tex]
[tex]Var(x) = 1 * (1 - 5\%)[/tex]
[tex]Var(x) = 1 * 0.95[/tex]
[tex]Var(x) = 0.95[/tex]
[tex](e)\ P(X = 1, Y = 17, Z = 3)[/tex]
In (b), we have: [tex]x + y + z = 20[/tex]
However, the given values of x in this question implies that:
[tex]x + y + z = 1 + 17 + 3[/tex]
[tex]x + y + z = 21[/tex]
Hence:
[tex]P(X = 1, Y = 17, Z = 3) = 0[/tex]
[tex](f)\ P{X \le 1, Y = 17, Z = 3)[/tex]
This question implies that:
[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) + P(X = 1, Y = 17, Z = 3)[/tex]
Because
[tex]0, 1 \le 1[/tex] --- for x
In (e), we have:
[tex]P(X = 1, Y = 17, Z = 3) = 0[/tex]
So:
[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) +0[/tex]
[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)[/tex]
In (a), we have:
[tex]f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z[/tex]
So:
[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{0! * 17! * 3!} * (5\%)^0 * (85\%)^{17} * (10\%)^{3}[/tex]
[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{1 * 17! * 3!} * 1 * (85\%)^{17} * (10\%)^{3}[/tex]
[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{17! * 3!} * (85\%)^{17} * (10\%)^{3}[/tex]
Expand
[tex]P(X=0; Y=17; Z = 3) = \frac{20*19*18*17!}{17! * 3*2*1} * (85\%)^{17} * (10\%)^{3}[/tex]
[tex]P(X=0; Y=17; Z = 3) = \frac{20*19*18}{6} * (85\%)^{17} * (10\%)^{3}[/tex]
[tex]P(X=0; Y=17; Z = 3) = 20*19*3 * (85\%)^{17} * (10\%)^{3}[/tex]
Using a calculator, we have:
[tex]P(X=0; Y=17; Z = 3) = 0.07195[/tex]
So:
[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)[/tex]
[tex]P(X \le 1, Y = 17, Z = 3) =0.07195[/tex]
[tex](g)\ P(X \le 1)[/tex]
This implies that:
[tex]P(X \le 1) = P(X = 0) + P(X = 1)[/tex]
In (c), we established that X is a binomial distribution with the following parameters:
[tex]p_1 = 5\%[/tex] [tex]n = 20[/tex]
Such that:
[tex]P(X=x) = ^nC_x * p_1^x * (1 - p_1)^{n - x}[/tex]
So:
[tex]P(X=0) = ^{20}C_0 * (5\%)^0 * (1 - 5\%)^{20 - 0}[/tex]
[tex]P(X=0) = ^{20}C_0 * 1 * (1 - 5\%)^{20}[/tex]
[tex]P(X=0) = 1 * 1 * (95\%)^{20}[/tex]
[tex]P(X=0) = 0.3585[/tex]
[tex]P(X=1) = ^{20}C_1 * (5\%)^1 * (1 - 5\%)^{20 - 1}[/tex]
[tex]P(X=1) = 20 * (5\%)* (1 - 5\%)^{19}[/tex]
[tex]P(X=1) = 0.3774[/tex]
So:
[tex]P(X \le 1) = P(X = 0) + P(X = 1)[/tex]
[tex]P(X \le 1) = 0.3585 + 0.3774[/tex]
[tex]P(X \le 1) = 0.7359[/tex]
[tex](h)\ E(Y)[/tex]
Y has the following parameters
[tex]p_2 = 85\%[/tex] and [tex]n = 20[/tex]
[tex]E(Y) = p_2 * n[/tex]
[tex]E(Y) = 85\% * 20[/tex]
[tex]E(Y) = 17[/tex]
What is the factors of x^2-16x+64
Answer:
(x-8)² or (x-8)(x-8)
Step-by-step explanation:
x^2-16x+64
x^2 -8x -8x +64
x (x-8) - 8(x-8)
(x-8) (x-8)
(x-8)^2
The amount of water consumed each day by a healthy adult follows a normal distribution with a mean of 1.30 liters. A health campaign promotes the consumption of at least 2.0 liters per day. A sample of 10 adults after the campaign shows the following consumption in liters:
1.361.351.331.661.581.321.381.421.901.54
At the 0.050 significance level, can we conclude that water consumption has increased? Calculate and interpret the p-value.
A.) State the null hypothesis and the alternate hypothesis.
H0: μ ≤ _____
H1: μ >_____
B.) State the decision rule for 0.050 significance level. (round to 3 decimal places)
C.) Compute the value of the test statistic. (round to 3 decimal places)
D.) At the 0.050 level, can we conclude that water consumption has increased?
E.) Estimate the p-value.
Answer:
H0: μ ≤ 1.30
H1: μ > 1.30
|Test statistic | > 1.833 ; Reject H0
Test statistic = 3.11
Yes
Pvalue = 0.006
Step-by-step explanation:
H0: μ ≤ 1.30
H1: μ > 1.30
Samples, X ; 1.36,1.35,1.33, 1.66, 1.58, 1.32, 1.38, 1.42, 1.90, 1.54
Xbar = 14.84 / 10 = 1.484
Standard deviation, s = 0.187 (calculator)
Decison rule :
|Test statistic | > TCritical ; reject H0
df = n - 1 = 10 - 1 = 9
Tcritical(0.05; 9) = 1.833
|Test statistic | > 1.833 ; Reject H0
Test statistic :
(xbar - μ) ÷ (s/√(n))
(1.484 - 1.30) ÷ (0.187/√(10))
0.184 / 0.0591345
Test statistic = 3.11
Since ;
|Test statistic | > TCritical ; We reject H0 and conclude that water consumption has increased
Pvalue estimate using the Pvalue calculator :
Pvalue = 0.006
Use slope or the distance formula to determine the most precise name for the figure:
A(-4,-1), B(-2,4), C(4, 5), D(2,0).
Answer:
parallelogram
Step-by-step explanation:
opposite sides are parallel and equal
I need help can someone tell me which choice is correct?
Answer: A, C, D
Step-by-step explanation:
A is correct because Audrey reads 40 pages a day, and David reads 20. When you divide 40 by 20, you get 2. This means that 2 times 20 would be 40, and anything multiplied by 2 is "twice".
40 ÷ 20 = 2
2 × 20 = 40
B is not correct because after 6 days, Audrey reads 240 pages, and David reads only 120. We can figure this out by multiplying the pages read by 6.
Audrey: 40 × 6 = 240
David: 20 × 6 = 120
C is correct because when you subtract 20 from 40, you get 20. Since Audrey reads 40 pages a day and David reads 20, you can use this equation: 40-20 to figure the answer out. Audrey reads 20 more pages every day.
[tex]40-20=20[/tex]
D is correct because after 2 days, Audrey will have read 80 pages, and David will have read 40 pages. When you subtract 40 from 80, you get 40 pages.
40 × 2 = 80
20 × 2 = 40
80 - 40 = 40
E is not correct because, after 3 days, Audrey will have read 120 pages, and David will have read 60 pages. One-third of 120 is 40, not 60. Three times 60 would be 180, not 120. So, This answer is incorrect.
Plz help me well mark brainliest if correct!
Answer:
ok
Step-by-step explanation:
Answer:
The length is 8.
Step-by-step explanation:
If you know the formula for area is LxW. Use this but reverse it. The area is 24 and the width is 3. Now divide 24/3=8. Simple as that!
Formula: A/W=L or A/L= W use this if you need more help! Hope it helps (:(:
the first term of an arithmetic sequence is 10 and the sum of the first five terms is 250,find the sequence
Answer:
The sequence is:
10, 30, 50, 70, 90.....................
Step-by-step explanation:
We have,
First term (a) = 10
Common difference (d) = ?
Sum of first 5 terms ([tex]S_{5}[/tex]) = 250
or, [tex]\frac{n}{2} [{2a+(n-1)d}] = 250[/tex]
or, [tex]\frac{5}{2} [2*10 + 4d]=250[/tex]
or, [tex]\frac{5}{2} * 4[5+d]=250[/tex]
or, 10(5 + d) =250
or, 5 + d = 25
∴ d = 20
Now,
2nd term = a + d = 10 + 20 = 30
3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50
4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70
5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90
HELP ME! Look at the stem-and-leaf plot. What is the mode of the numbers?
Given:
The stem-and-leaf plot or a date set.
To find:
The mode of data set.
Solution:
From the given stem-and-leaf plot, we get the numbers of the data set.
64, 67, 70, 70, 71, 75, 76, 78, 78, 80, 82, 82, 88, 91, 93, 94, 97, 98, 100, 100, 100
Mode of a date set is the most frequent value.
In the given data set the most frequent value is 100 with frequency 3.
Therefore, the mode of data set is 100. Hence, option A is correct.
Answer:it is A: 100
Step-by-step explanation:
i got it right
good luck with your test :)
Determine the angles θ where sin(θ)=12
A)30o and 120o
B)60o and 120o
C)30o and 150o
D)60o and 150o
What is the perimeter of this tile?
in?
4 in
1 in
Answer:
perimeter of tile =2(l+b)
2(4+1)2×510 inhope it helps
stay safe healthy and happy.
What is mZMNP?
A 73
B 107
C 110
D 146
Answer:
zMNP=180-73
=107 IS THE ANSWER
-19x + 32 = -24x - 3
Answer:
x= -7
Step-by-step explanation:
Answer:
-7
Step-by-step explanation:
-19x+32=-24x-3
-19x+24x=-3-32
5x=-35
X=-35/5= -7
From first to last, when did the presidents serve?
Drag the presidents' names into the correct order according to when they served.
Answer:
The answer is Gerald R. Ford, Jimmy Carter, Ronald Reagan, and lastly George H.W Bush
Step-by-step explanation:
Why is it important for a company to create an income statement?
Three quarters of the 12 farms breed cattle. How many farms breed cattle?
Answer:
Your answer is 9 farms breed cattle.
Step-by-step explanation:
(3/4)*12 = 9
or
.75*12 = 9
Answer:
9
Step-by-step explanation:
Three quarter means ¾
¾ of 12
3 × 3
9
What is the volume of the composite figure below? (formula for volume of a prism is 1/3 Bh where B is the area of the base.)
Answer:
Last Option; 84 cu. mm
Step-by-step explanation:
We know that;
Volume = 1/3(Bh)
And that this is figure has a square base, therefore B that represents the area of the base will be: 6 * 6 = 36
And height = 7mm
Therefore we can say;
Volume = (1/3)*(6 x 6)*(7)
Volume = (1/3)*(36)*(7)
Volume = (12)*(7)
Volume = 84
Hope this helps!
Chuck has 20 feet of fencing and wishes to make a rectangular fence for his dog Rover. If he uses his house for one side of the fence what is maximum area?
Answer:
50 square feet.
Step-by-step explanation:
Let x represent the width of the fence and y represent the length of the fence.
One side of the length is already covered by the house. This leaves 2x and y. This must sum to 20. Hence:
[tex]2x+y=20[/tex]
The area of the enclosure will be given by:
[tex]A=xy[/tex]
From the first equation, we can subtract 2x from both sides:
[tex]y=20-2x[/tex]
Substitute:
[tex]A=x(20-2x)[/tex]
This is now a quadratic. Recall that the maximum value of a quadratic always occurs at its vertex. So, find the vertex of the equation. Distribute:
[tex]A=20x-2x^2[/tex]
In this case, a = -2, b = 20, and c = 0.
Hence, the vertex is:
[tex]\displaystyle x=-\frac{b}{2a}=-\frac{(20)}{2(-2)}=5[/tex]
Substitute this value back into the equation and evaluate:
[tex]A(5)=20(5)-2(5)^2=50\text{ ft}^2[/tex]
The maximum area is 50 square feet.
This occurs when the dimensions are 5 feet by 10 feet.
PLEASE HELP ME
Angelique makes beaded jewelry. The graph below shows the number of beads on varying cord lengths. Jewelry  A necklace contains 88 beads. Based on the information above, which is the best estimate for the cord length? 21 inches 26 inches 34 inches 36 inches.
Answer:
please show answer choices
Step-by-step explanation:
Select all the ordered pairs that are solutions of the equation.
A. (-7, 1)
B. (-1,7)
C. (0,5)
D. (2,3)
E. (3, 2)
F. (5,0)
Answer:
B. (-1,7)
C. (0,5)
D. (2,3)
Step-by-step explanation:
We solve this question looking at the graphic.
A. (-7, 1)
When [tex]x = -7, y \rightarrow \infty[/tex], and thus (7,-1) is not solution of the equation.
B. (-1,7)
When [tex]x = -1, y = 7[/tex], and thus (-1,7) is a solution of the equation.
C. (0,5)
When [tex]x = 0, y = 5[/tex], and thus (0,5) is a solution of the equation.
D. (2,3)
When [tex]x = 2, y = 3[/tex], and thus (2,3) is a solution of the equation.
E. (3, 2)
When [tex]x = 3, y \neq 2[/tex], and thus (3,2) is not part of the solution
F. (5,0)
When [tex]x = 5, y \neq 0[/tex], and thus (5,0) is not part of the solution
Question 1 (1 point)
John started with $1,000 in an investment account. Each year the money in the account doubled. If there is currently $16,000 in the
investment account, how many years have passed since the account was opened?
years
Answer:
4 yrs have passed since the account was opened
find the vertex and the x- and y- intercept of the following quadratic equations
y = 5x² +15x+10
Answer:
x int. (-1,0) and (-2,0). y-int,(0,10)
Step-by-step explanation:
y-int. it's 10 because the y-int is always the c value.
x-int.
x=-b±√b²-4ac/2a
x=-15±√15²-4(5)(10)/2(5)
x=-15±√225-200/10
x=-15±√25/10
x= -15+5/10. x=-15-5/10
x=-10/10. x=-20/10
x=-1. x=-2
How would I figure out a linear equation with two plot points with fractions? (1/3(6),3) and (1/2(19),-2) are my two plot points. I was able to graph them on Desmos, but I can't seem to figure out how I would go about figuring out the slope and y-intercept in this case... the fractions are what's throwing me off here. Please help!
Answer: [tex]m=\frac{-30}{79},\ y=5.40[/tex]
Step-by-step explanation:
Given
Points are [tex]\left(6\frac{1}{3},3\right),\ \left(19\frac{1}{2},-2\right)[/tex]
Convert mixed numeral to fraction
[tex]\left(6\frac{1}{3},3\right)\Rightarrow \left(\dfrac{19}{3},3\right)\\\\\left(19\frac{1}{2},-2\right)\Rightarrow \left(\dfrac{39}{2},-2\right)[/tex]
Slope of the line is
[tex]\Rightarrow m=\dfrac{3-(-2)}{\dfrac{19}{3}-\dfrac{39}{2}}\\\\\Rightarrow m=\dfrac{5}{\dfrac{38-117}{6}}\\\\\Rightarrow m=\dfrac{-30}{79}[/tex]
Equation of line
[tex]\Rightarrow \dfrac{y-3}{x-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\text{for y-intercept, put x=0}\\\\\Rightarrow \dfrac{y-3}{0-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\Rightarrow y-3=\dfrac{190}{79}\\\\\Rightarrow y=3+2.40\\\Rightarrow y=5.40[/tex]