Factorise: a² - 27a + 180 ​

Answer:

Step-by-step explanation:

b .33

Simplifying this expression, we get the margin of error as approximately 0.042.

(a) The sample proportion is p = 367/500 = 0.734. To find the 99% confidence interval for the true proportion p, we use the formula: p ± zα/2 * sqrt((p(1-p))/n).

where zα/2 is the critical value from the standard normal distribution corresponding to a 99% confidence level, which is approximately 2.576. Substituting the given values, we have:

0.734 ± 2.576 * sqrt((0.734(1-0.734))/500)

Simplifying this expression, we get the 99% confidence interval for p as (0.692, 0.776). (b) The margin of error for this 99% confidence interval is given by: zα/2 * sqrt((p(1-p))/n)

Substituting the given values, we have: 2.576 * sqrt((0.734(1-0.734))/500) Simplifying this expression, we get the margin of error as approximately 0.042.

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Therefore, the simplified expression is m³+3am² -3am² -2a³

We can first simplify the given expression below.

2a²m - 3am² + m³ am² - a²m-2a³​

Lets combine the like terms.

2a²m - 3am² + m³ am² - a²m-2a³​

m³ - 3a²m +3am² + 2a³

m³+3am² -3am² -2a³

Therefore, the simplified expression is m³+3am² -3am² -2a³

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To find the function f, we need to integrate f'(x) with respect to x. Thus, we have found the function f with the given derivative f'(x) and initial condition f(9) = 67.

f'(x) = (1/3)x

Integrating both sides with respect to x, we get:

f(x) = (1/3) * (x^2/2) + C

where C is the constant of integration. To find the value of C, we use the given initial condition that f(9) = 67:

f(9) = (1/3) * (9^2/2) + C = 67

Simplifying the equation, we get:

C = 67 - (1/3) * (81/2) = 67 - 13.5 = 53.5

Therefore, the function f is:

f(x) = (1/3) * (x^2/2) + 53.5

Thus, we have found the function f with the given derivative f'(x) and initial condition f(9) = 67.

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The net profit on the sale of these fruits is Rs 6,050.

To calculate the net profit on the sale of these fruits, we need to determine the total revenue generated from the sales and deduct the total expenses.

First, let's calculate the revenue from each type of fruit:

Revenue from apples: 100 kg × Rs 140/kg = Rs 14,000

Revenue from bananas: 30 dozen × Rs 75/dozen = Rs 2,250

Revenue from grapes: 50 kg × Rs 150/kg = Rs 7,500

Next, let's calculate the total revenue:

Total revenue = Revenue from apples + Revenue from bananas + Revenue from grapes

Total revenue = Rs 14,000 + Rs 2,250 + Rs 7,500

Total revenue = Rs 23,750

Now, let's calculate the total expenses:

Total expenses = Cost of apples + Cost of bananas + Cost of grapes + Transportation cost

Total expenses = Rs 9,000 + Rs 1,800 + Rs 6,000 + Rs 900

Total expenses = Rs 17,700

Finally, let's calculate the net profit:

Net profit = Total revenue - Total expenses

Net profit = Rs 23,750 - Rs 17,700

Net profit = Rs 6,050

Therefore, the net profit on the sale of these fruits is Rs 6,050.

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The answer is (a) 0.8494, to find the probability that the battery fails before the one year warranty expires,

we need to calculate the integral of the given pdf from 0 to 1, as X represents the length of the battery life in years.

So, P(X<1) = ∫(0 to 1) f(x) dx = ∫(0 to 1) (16/49) e^(-8x^2/49) dx ≈ 0.8494

Therefore, the answer is (a) 0.8494.

The given pdf describes the distribution of the length of the battery life, and we are interested in finding the probability that the battery fails before the one year warranty expires.

This can be found by integrating the pdf from 0 to 1, as the warranty lasts for one year.

Using the formula for the probability density function, we calculate the integral of the given pdf from 0 to 1, and get the answer as 0.8494.

This means that the probability of the battery failing before the one year warranty expires is about 84.94%.

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Answer:

7 - 3x

Step-by-step explanation:

Product would cause the 3 and x to combine.

Answer:

7 - 3x

Step-by-step explanation:

the product , multiplication of 3 and x = 3 × x = 3x

now subtract this product from 7 to obtain

7 - 3x

The volume of the pyramid is 1280 cubic units, and the surface area is 800 square units.

To find the volume and surface area of a pyramid, we can use the following formulas:

Volume of a pyramid = (1/3) · base area · height

Surface area of a pyramid = base area + (1/2) · perimeter · slant height

Given that the base of the pyramid is a square with a side length of 16, the base area can be calculated as:

Base area = side length² = 16² = 256 square units

The height of the pyramid is given as 15, and the slant height is given as 17.

Now, let's calculate the volume of the pyramid:

Volume = (1/3) · base area · height

Volume = (1/3) · 256 · 15

Volume = 1280 cubic units

Next, let's calculate the surface area of the pyramid:

Perimeter of the base = 4 · side length = 4 · 16 = 64 units

Surface area = base area + (1/2) · perimeter · slant height

Surface area = 256 + (1/2) · 64 · 17

Surface area = 256 + 544

Surface area = 800 square units

Therefore, the volume of the pyramid is 1280 cubic units, and the surface area is 800 square units.

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The largest diameter particle (in microns) that will pass through the filter is given as follows:

0.756 microns.

The z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is obtained by the equation presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation for this problem are given as follows:

[tex]\mu = 0.5, \sigma = 0.2[/tex]

The largest diameter is the 90th percentile, which is X when Z = 1.28, as 1.28 has a p-value of 0.9, hence:

1.28 = (X - 0.5)/0.2

X - 0.5 = 0.2 x 1.28

X = 0.756 microns.

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To find the Maclaurin expansion of f(x) = -e^x - sin(x), we can use the Maclaurin series of e^x and sin(x) and combine them with appropriate coefficients.

The Maclaurin series of e^x is:

e^x = 1 + x + x^2/2! + x^3/3! + ...

And the Maclaurin series of sin(x) is:

sin(x) = x - x^3/3! + x^5/5! - ...

Using these series, we can write the Maclaurin expansion of f(x) as:

f(x) = -e^x - sin(x) = -1 - x - x^2/2! - x^3/3! - ... - (x - x^3/3! + x^5/5! - ...)

Simplifying this expression, we get:

f(x) = -1 - 2x - 5x^2/2! - 19x^3/3! - 87x^4/4! - ...

Therefore, the first five nonzero terms of the Maclaurin expansion of f(x) are:

f(x) = -1 - 2x - 5x^2/2! - 19x^3/3! - 87x^4/4! + O(x^5)

This means that for small values of x, f(x) can be approximated by the polynomial -1 - 2x - 5x^2/2! - 19x^3/3! - 87x^4/4!, which becomes more accurate as more terms are added. The term O(x^5) represents the error in this approximation and means that the actual value of f(x) is within a certain range of this polynomial for values of x close to zero.

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The statements, reasons, situations that proves the congruence of the triangles are presented as follows;

1. 5. ∠POM ≅ ∠NOM [tex]{}[/tex]        5. Definition of angle bisector

6. ΔPMO ≅ ΔNMO [tex]{}[/tex]           6. SAS Congruence theorem

2. C. III only

3. SAS congruence rule

Triangles are congruent if they have that same size and shape.

The completed two column method to prove the congruence of the triangles can be presented as follows;

Statements        [tex]{}[/tex]                          Reasons

1. [tex]\overrightarrow{MO}[/tex] bisects ∠PMN [tex]{}[/tex]                 1. Given

2. ∠PMO ≅ ∠NMO [tex]{}[/tex]                    2. Definition of angle bisector

3. [tex]\overline{MO}[/tex] ≅ [tex]\overline{MO}[/tex]            [tex]{}[/tex]                  3. Reflexive property

4. [tex]\overrightarrow{OM}[/tex] bisects ∠PON                 4. Given

5. ∠POM ≅ ∠NOM [tex]{}[/tex]                    5. Definition of angle bisector

6. ΔPMO ≅ ΔNMO [tex]{}[/tex]                    6. SAS congruence theorem

2. The leg HL Theorem states that the if the hypotenuse and a leg in one triangle are congruent to a leg and an hypotenuse side in another triangle, then the two triangles are congruent.

The specified dimensions of the triangle that indicates that the hypotenuse of the two triangles are congruent is the option III

The correct option is; C. III Only

3. The three angles in triangle ΔFDG are congruent to the three angles in triangle ΔFDE.

The reflexive property of congruence indicates; The side FD is congruent to itself (reflexive property of congruence)

The triangle ΔFDG is congruent to the triangle ΔFDE by the ASA congruence rule

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So we've shown that every pair of vertices in S is connected by an edge in the subgraph induced by S. Therefore, the subgraph induced by S is a complete graph.

To start with, let's clarify what we mean by some of these terms. A graph is just a collection of vertices (or nodes) and edges connecting them. In this case, we're dealing with the complete graph kn, which means that there are n vertices and every possible edge connecting them is included in the graph. So there are a total of n(n-1)/2 edges in the graph.

Now, we're interested in subgraphs of kn. A subgraph is just a subset of the vertices and edges from the original graph. In this case, we're interested in subgraphs induced by nonempty subsets of the vertex set. So if we take some subset of the n vertices in kn, we can look at the edges connecting them and see if they form a complete graph.

So let's say we take some subset of the vertices and call it S. We want to show that the subgraph induced by S is a complete graph. In other words, every pair of vertices in S is connected by an edge.

To see why this is true, let's consider the complement of S, which we'll call S'. This is just the set of vertices in kn that are not in S. Since S is nonempty, S' is also nonempty.

Now, consider any pair of vertices in S. Call them v and w. Since v and w are both in S, they are not in S'. This means that there is an edge connecting v and w in kn, since kn is a complete graph. But since we're only looking at the vertices in S, this edge is also in the subgraph induced by S.

So we've shown that every pair of vertices in S is connected by an edge in the subgraph induced by S. Therefore, the subgraph induced by S is a complete graph.

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In a regression analysis, the regression equation given is y = 12 - 6x. The correct option for the coefficient of correlation is b. -0.7.

The terms SSE (sum of squared errors) and SST (total sum of squares) are provided, with values 510 and 1000, respectively. To determine the coefficient of correlation (r), we need to first calculate the coefficient of determination (R²), which is given by the formula:
R² = (SST - SSE) / SST
Substituting the given values, we get:

R² = (1000 - 510) / 1000 = 490 / 1000 = 0.49
Now, we need to find the correlation coefficient (r), which is the square root of the coefficient of determination (R²). However, we need to determine the sign (positive or negative) based on the regression equation. Since the slope of the equation (in this case, -6) is negative, the correlation coefficient will also be negative. Therefore, we have:
r = -√0.49 = -0.7

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The simplified rational expressions are given as follows:

The first rational expression is given as follows:

[tex]\sqrt[5]{288p^7}[/tex]

The number 288 can be simplified as follows:

[tex]288 = 2^5 \times 3^2[/tex]

[tex]p^7[/tex], can be simplified as [tex]p^7 = p^5 \times p^2[/tex], hence the simplified expression is given as follows:

[tex]\sqrt[5]{2^5 \times 3^2 \times p^5 \times p^2} = 2p\sqrt[5]{9p^2}[/tex]

(as we simplify the exponents of 5 with the power)

The second expression is given as follows:

[tex](216r^{9})^{\frac{1}{3}}[/tex]

We have that 216 = 6³, hence we can apply the power of power rule to obtain the simplified expression as follows:

Hence the simplified expression is of:

[tex](216r^{9})^{\frac{1}{3}} = 6r^3[/tex]

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Answer:

0.18

Step-by-step explanation:

In the long run, perfectly competitive firms aim to produce at a level of output where their marginal cost (MC) is equal to the market price (P).

This is because in a perfectly competitive market, there are many firms competing with each other, and they cannot charge a price higher than the market price. Therefore, firms must produce at a level where their MC equals P in order to maximize profits.
Therefore, the answer to the question is that perfectly competitive firms produce a level of output such that P = MC. This is because the other options, P = minimum of AC and P > MC, do not accurately reflect the behavior of perfectly competitive firms. In a perfectly competitive market, firms cannot charge a price higher than the market price, so P will not be greater than MC. Additionally, P will not be equal to the minimum of AC because in a perfectly competitive market, there are no barriers to entry, so firms cannot earn economic profits in the long run. Therefore, they must produce at a level where P = MC to break even in the long run.

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The probability that a randomly selected 49- to 54-year-old mother who had a live birth in 2012 has had her fourth live birth is low, as it is rare for women in this age group to have more than three children.

However, the exact probability would depend on various factors, such as the woman's individual fertility, access to contraception, and cultural and social norms regarding family size.

The probability of a woman having a fourth live birth decreases as she gets older and approaches menopause. Women in their late forties and fifties have a higher risk of pregnancy complications and may have more difficulty conceiving than younger women.

Additionally, many women may choose to limit their family size or prioritize their careers and personal goals over having more children. However, there are exceptions, and some women may choose to have a fourth child or have an unplanned pregnancy. Ultimately, the probability of a woman having a fourth live birth is influenced by a variety of factors, and it is difficult to provide a precise estimate without additional information.

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9.172 cm² is the area of the unshaded reason.

It is given that,

From the general formula of the area of the arc of the circle,

Area of the arc = (θ/360) x πr²

where A is the area of the arc, θ is the central angle of the arc (in degrees), and r is the radius of the circle.

The area of the shaded part is given = 56.87 cm²

Angle of the shaded arc = 360-50 = 310

So,

310/360* πr² = 56.87

πr²/360 = 56.87/310

For the 50° part,

Area of the unshaded part = 50/360* πr²

From the above value of the  πr²/360,

Area of the unshaded part = 50*56.87/310

Area of the unshaded part = 9.172 cm²

Therefore, the area of the unshaded reason is 9.172 cm².

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Over the last half-century, time-use data has shown that married American women have significantly reduced their housework time, cutting it roughly in half.

This change can be attributed to various factors such as advancements in home appliances, shifting gender roles, and increased participation of women in the workforce. On the other hand, men have gradually increased their contributions to housework during this period.
This shift in housework responsibilities can be attributed to societal changes that promote a more equitable distribution of domestic tasks between partners. As gender norms have evolved, men are increasingly taking on roles that were once predominantly associated with women, leading to a more balanced approach to housework within households. Additionally, the rise in dual-income families has necessitated a more equal division of domestic responsibilities.
In summary, over the past 50 years, married American women have seen a considerable decrease in housework time, while men have increased their contributions. This change reflects evolving gender roles and societal expectations, promoting a more equal division of labor within households.

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The given series 4^n / 2^n 3^n is convergent.

To see why, we can use the ratio test, which states that if the limit of the ratio of consecutive terms is less than 1, then the series converges. Applying the ratio test to the given series, we get:

lim n→∞ |(4^n+1 / 2^n+1 3^n+1) / (4^n / 2^n 3^n)|

= lim n→∞ |4 / 3(1 + 1/2n+1)|

= 4/3

Since the limit is less than 1, the series converges. To find its sum, we can use the formula for the sum of a convergent geometric series:

S = a / (1 - r)

where a is the first term and r is the common ratio. In this case, a = 4/6 = 2/3 and r = 2/3, so we get:

S = (2/3) / (1 - 2/3) = 2

Therefore, the sum of the series is 2.

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For any n ≥ 1, the factorial function, denoted by n!, is the product of all the positive integers through n, it is proved that for n ≥ 4, n! ≥ 2n.

To prove this statement, we can use mathematical induction. For the base case, n = 4, we have 4! = 24 and 2^4 = 16. Since 24 > 16, the statement holds for n = 4.

Now suppose the statement holds for some integer k ≥ 4, that is, k! ≥ 2k. We need to show that the statement holds for k+1. We have:

(k+1)! = (k+1)k!

≥ (k+1)2k (by the induction hypothesis)

≥ 2·2k (since k+1 > 2 for k ≥ 4)

= 2k+1.

Therefore, the statement holds for k+1. By the principle of mathematical induction, the statement holds for all n ≥ 4. Therefore, we have proved that n! ≥ 2n for n ≥ 4.

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The Taylor polynomial T3(x) for the function f centered at the number a is 1, -1.

To find the slope of the tangent line to the curve at a given point, we need to find the derivative of the curve and evaluate it at that point. So, let's find the derivative of the curve x(t) = cos^3(4t), y(t) = sin^3(4t):

x'(t) = 3cos^2(4t) * (-sin(4t)) * 4 = -12cos^2(4t)sin(4t)

y'(t) = 3sin^2(4t) * cos(4t) * 4 = 12sin^2(4t)cos(4t)

Now, let's evaluate these derivatives at t = pi/6:

x'(pi/6) = -12cos^2(2pi/3)sin(2pi/3) = -6sqrt(3)

y'(pi/6) = 12sin^2(2pi/3)cos(2pi/3) = 6sqrt(3)

So, the slope of the tangent line at t = pi/6 is:

y'(pi/6) / x'(pi/6) = (6sqrt(3)) / (-6sqrt(3)) = -1

Therefore, the answer is option 1, -1.

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The length of the side JL is 55 units.

Given that are two similar triangles, Δ LKJ and Δ TUV, we need to find the missing length,

TU = 14

TL = 22

JL = ?

KL = 35

so,

According to the definition of similar triangles,

Triangles with the same shape but different sizes are known as similar triangles.

Two triangles are said to be similar if their corresponding sides are proportionate and their corresponding angles are congruent.

In other words, two triangles are comparable if they can be changed into one another using a combination of rotations, translations, and uniform scaling (enlarging or decreasing).

TU / TV = KL / JL

14 / 22 = 35 / ?

14 x ? = 22 x 35

? = 55

Hence the length of the side JL is 55 units.

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The coefficient on the intercept would change if the dependent variable, birth weight, was in ounces instead of pounds. It would be equal to 0.00, rounded to two decimal places.

The intercept coefficient represents the value of the dependent variable when all independent variables are equal to zero. In this case, it would represent the birth weight when all predictors are equal to zero. Since birth weight is measured in ounces, the intercept coefficient would represent the weight of a newborn when all predictors are equal to zero, which is not a meaningful or practical value. Therefore, the intercept coefficient would be equal to 0.00.

This result is expected since changing the unit of measurement of the dependent variable does not change the relationship between the dependent variable and the independent variables, only the scale of the coefficients. The regression equation would still provide useful information about the relationship between birth weight and the predictors, but the coefficients would need to be interpreted differently.

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We conclude that there is not enough evidence to suggest that there is a significant difference among the mean meal prices for italian, seafood, and steakhouse restaurants.

to test whether there is a significant difference among the mean meal prices for italian, seafood, and steakhouse restaurants, we can use an analysis of variance (anova) test. the null hypothesis is that there is no significant difference among the means, while the alternative hypothesis is that there is a significant difference among the means.here are the steps to conduct the anova test:1. calculate the sample means for each category of restaurants:- italian: (12 + 16 + 24 + 13 + 18 + 19 + 15 + 17) / 8 = 17.25- seafood: (23 + 21 + 20 + 15 + 22 + 17 + 19 + 27) / 8 = 20.75

- steakhouse: (18 + 31 + 24 + 18) / 4 = 22.752. calculate the overall mean:(12 + 16 + 24 + 13 + 18 + 19 + 15 + 17 + 23 + 17 + 26 + 25 + 18 + 23 + 21 + 20 + 15 + 22 + 17 + 19 + 27 + 24 + 18 + 31) / 24 = 20.3753. calculate the sum of squares between groups (ssb):

ssb = 8 x (17.25 - 20.375)² + 8 x (20.75 - 20.375)² + 4 x (22.75 - 20.375)²    = 38.54. calculate the sum of squares within groups (ssw):ssw = (12 - 17.25)² + (16 - 17.25)² + ... + (18 - 22.75)² + (31 - 22.75)²    = 598.5

5. calculate the degrees of freedom for between groups (dfb):dfb = k - 1 = 3 - 1 = 26. calculate the degrees of freedom for within groups (dfw):dfw = n - k = 24 - 3 = 21

7. calculate the mean square between groups (msb):msb = ssb / dfb = 38.5 / 2 = 19.258. calculate the mean square within groups (msw):msw = ssw / dfw = 598.5 / 21 = 28.5

9. calculate the f-statistic:f = msb / msw = 19.25 / 28.5 = 0.6810. look up the critical f-value from an f-distribution table with dfb = 2 and dfw = 21 and a significance level of 0.05. the critical f-value is 3.10.

11. compare the f-statistic to the critical f-value. since the f-statistic (0.68) is smaller than the critical f-value (3.10), we fail to reject the null hypothesis. the test   statistics    value from our analysis is f = 0.68.

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The number of students at the mariemont middle school in whole number is 360 students.

Exponents refers to the power to which a number, symbol or expression is to be raised.

Number of students at the mariemont middle school = 2³ × 3² × 5

= (2 × 2 × 2) × (3 × 3) × 5

= 8 × 9 × 5

= 360 students

In conclusion, there are 360 total number of students in mariemont middle school.

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The 95% confidence interval centered on the mean that captures 95% of the sample means is (80.96, 85.04).

We can use the formula for the confidence interval for the mean of a normally distributed population:

CI = X ± z(α/2) * (σ/√n)

Where:

X = sample mean

z(α/2) = the z-score associated with the desired confidence level and calculated using the standard normal distribution table. For a 95% confidence level, α/2 = 0.025, and the corresponding z-score is approximately 1.96.

σ = population standard deviation

n = sample size

Substituting the given values, we get:

CI = 83 ± 1.96 * (5.2/√25)

CI = 83 ± 2.04

Therefore, the 95% confidence interval centered on the mean that captures 95% of the sample means is (80.96, 85.04).

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The total cost of the shoes, without tax, after the 5% off sale and the $10 off coupon, is $73.125.

To calculate the total cost of the shoes after the discount and coupon, we follow these steps:

Step 1: Calculate the discount amount.

Discount amount = Regular price * (Discount percentage / 100)

Discount amount = $87.50 * (5 / 100)

Discount amount = $87.50 * 0.05

Discount amount = $4.375

tep 2: Subtract the discount amount from the regular price.

Price after discount = Regular price - Discount amount

Price after discount = $87.50 - $4.375

Price after discount = $83.125

Step 3: Subtract the coupon amount from the price after discount.

Total cost = Price after discount - Coupon amount

Total cost = $83.125 - $10

Total cost = $73.125

Therefore, the total cost of the shoes, without tax, after the 5% off sale and the $10 off coupon, is $73.125.

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The missing values in the triangle are:

∠B = 90°

AB =  20.98

CB = 16.99

First, remember that the sum of the interior angles of any triangle is always equal to 180°, then we can write:

51 + 39 + ∠B = 180

∠B = 180 - 51 - 39 = 90

So we have a right triangle.

Now, to find the values of AB and CB, we can use trigonometric relations, we know that teh hypotenuse is 27 units, then we can use:

cos(51°) = CB/27

27*cos(51°) = CB = 16.99

And:

cos(39°) = AB/27

27*cos(39°) = AB = 20.98

These are the missing values.

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