explain the process of finishing​

Answer: [tex]K_{eq}[/tex] at  the temperature of the experiment is 0.56.

Explanation:

Moles of  [tex]CO[/tex] = 0.35 mole

Moles of  [tex]H_2O[/tex] = 0.40 mole

Volume of solution = 1.00 L

Initial concentration of [tex]CO[/tex] = [tex]\frac{0.35mol}{1.00L}=0.35M[/tex]

Initial concentration of [tex]H_2O[/tex] = [tex]\frac{0.40mol}{1.00L}=0.40M[/tex]

Equilibrium concentration of [tex]CO[/tex] = [tex]\frac{0.19mol}{1.00L}=0.19M[/tex]

The given balanced equilibrium reaction is,

                      [tex]CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)[/tex]

Initial conc.          0.35 M         0.40 M                  0 M        0M

    At eqm. conc.     (0.35-x) M   (0.40-x) M   (x) M      (x) M

Given:  (0.35-x) = 0.19

x= 0.16 M

The expression for equilibrium constant for this reaction will be,

[tex]K_{eq}=\frac{[CO_2]\times [H_2]}{[CO]\times [H_2O]}[/tex]  

Now put all the given values in this expression, we get :

[tex]K_{eq}=\frac{0.16\times 0.16}{(0.35-0.16)\times (0.40-0.16)}[/tex]

[tex]K_{eq}=\frac{0.16\times 0.16}{(0.19)\times (0.24)}=0.56[/tex]

Thus [tex]K_{eq}[/tex] at  the temperature of the experiment is 0.56.

Answer:

it would be Convection.

Answer:

Any element in group 18 has eight valence electrons (except for helium, which has a total of just two electrons

Answer:

600

Explanation:

there's 1 mole in every nitroglycerin

I think

Answer:

a top predator, fighting

Answer:

a 52 Joules

Explanation:

Specific heat capacity of Au = 0.13 J/g° C

mass = 4 gram

initial temperature = 0° C

final temperature = 100° C

We are to determine the amount of energy absorbed

Using the formula:

Q = mcΔθ

Q = 4 × (0.13) J/g° C ×(100-0)

Q = 52 Joules

Answer:

Difference in temperature

Explanation:

According to thermodynamics, heat transfer occurs when heat from a high temperature reservoir moves to a low temperature reservoir. For heat to be transferred, the two objects should have different temperatures with one having more temperature than the other. Heat transfer in solids is by conduction, in fluids is by convection and by radiation.

Answer:

d.) granulated

Because the granulated sugar has a greater surface area.

Answer:

0.20 moles of Pb(CH3COO)4

Explanation:

89g Pb(CH3COO)4 x 1 mol Pb(CH3COO)4 / 443.376 g Pb(CH3COO)4

= 0.20 moles of Pb(CH3COO)4

One mole of lead acetate weighs 443.29 g. Then, 89 grams of lead acetate contains 0.20 moles of Pb (CH₃COO)₄.

One mole of a substance is its amount containing 6.02 × 10²³  atoms or molecules. This number is called Avogadro number. One mole of every elements contains Avogadro number of atoms.

Similarly one mole of every compound contains 6.02 × 10²³  molecules. The mass of one mole of compound is called its molar mass. The number  of moles of the compound can be determined by dividing the given mass by molar mass.

Molar mass of lead acetate = 443.29 g/mol

given mass  = 89 grams

then , no.of moles = weight/molar mass

n = 89 g/ (443.29 g/mol) = 0.20 moles

Therefore, the number of moles of Pb (CH₃COO)₄ in 89 g is 0.20 moles.

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Answer:

Synthesis or combination.

Explanation:

Hello there!

In this case, according to the given chart containing the types of reactions, it turns out possible for us infer this given reaction:

____ N2+__H2→ __NH3

Is synthesis or combination, because it follows the pattern A + B --> C. Moreover, it can be balanced as shown below:

N2+3H2→ 2NH3

Regards!

Answer:

Answer: Number of moles of KOH present in solution is 3.75.

Explanation:

0.1 moles

There are 0.1 moles of solute in 250 mL of 0.4 M solution.

1 Answer. 1 mol of NaOH

Explanation:

Molarity = (# of moles)/(# of liters)

= 180 mol MgCl2/60 L

= 3.0M MgCl2

Answer:

81.65 g CO2

Explanation:

Answer:

Explanation:

correct me if im wrong

Answer:

The final concentration of the Randyne in grams per milliliter = 0.011 g/mL

Explanation:

As we know

C1V1 = C2V2

C1 and C2 = concentration of solution 1 and 2 respectively

V1 and V2 = Volume of solution 1 and 2 respectively

Substituting the given values, we get -

[tex]50 * 15 = X * (15+50)\\X = 11.54[/tex] mg/mL

The final concentration of the Randyne in grams per milliliter = 0.011 g/mL

The final concentration of the Randyne in this solution is 0.01 g /mL.

It is very important to know the dilution methods in a chemistry lab. The dilution from the stock solution can be prepared by using the formula,

[tex]C_1V_1 = C_2V_2[/tex]

Where,

[tex]C_1[/tex]- concentration of the stock solution

[tex]V_1[/tex] - the volume of the stock solution

[tex]C_2[/tex] - concentration of the diluted solution

[tex]V_2[/tex] - the volume of diluted solution

Put the values in the formula,

[tex]50 \times 15 = C_2 \times 75 \\\\C_2 = \dfrac {750}{75 }\\\\C_2 = 10{\rm \ mg/mL \ \ \ or} \\\\ C_2 = 0.01 \rm \ g/mL[/tex]

Therefore, the final concentration of the Randyne in this solution is 0.01 g /mL.

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Answer:

THERE ANSWER IS C

Explanation:

Answer:

Metals are good conductors of heat. Due to this property metals are used in the preparation of kitchen utensils. Aluminium is good conductor of heat and more over it is corrosion resistent. Due to these properties aluminium is used in making kitchen utensils.

Explanation:

Answer:

1. 1.33 gram of carbon

2. 2.38g of carbon dioxide

Explanation:

From the given information:

Total amount of CO₂ = 4.86 grams

Atomic mass of C = 12 g/mole

molar mass of CO₂ = 44 g/mole

∴

The mass of the Carbon (C) in grams is:

[tex]= Total\ amount \ of \ CO_2 \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]

[tex]= 4.86 \ g \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]

= 1.33 gram of carbon

2.

Here, the total amount of CO₂ = unknown

Atomic mass of O₂ = 32 g/mole

molar mass of CO₂ = 44 g/mole

amount of oxygen = 1.73 g

∴

The mass of CO₂ = [tex]Total \ amount \ of \ O_2 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]

[tex]=1.73 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]

= 2.38 g of carbon dioxide

Answer: The balanced equation is [tex]V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO[/tex].

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, [tex]V_{2}O_{5} + Ca \rightarrow V + CaO[/tex]

Here, number of atoms on reactant side are as follows.

The number of atoms on product side are as follows.

In order to balance this equation, multiply Ca by 5 on reactant side. Multiply V by 2 and CaO by 5 on product side. Therefore, the equation can be rewritten as follows.

[tex]V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO[/tex]

Now here, number of atoms on reactant side are as follows.

The number of atoms on product side are as follows.

Since, there are same number of atoms on both reactant and product side. So, the equation is now balanced.

Thus, we can conclude that the balanced equation is [tex]V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO[/tex].

Answer:

LiCl.

Explanation:

Hello there!

In this case, since it is known that the ionic compounds are specially formed between metals and nonmetals, it is possible for us to discard CO and PCl5 as they have both nonmetals.

On the other hand, since the bonds between nonmetals and transition metals like iron and copper may not be completely ionic due to the electronegativity trend, we infer that the most likely ionic compound is LiCl because of the large electronegativity difference.

Regards!

Answer:

it contains 0.599 g i hope it helps

Answer:

Amines ketones aldehydes and aromatic

Explanation:

my opinion but thats my answer

Answer:

AFAIK

Explanation:

uric acid is much less toxic than ammonia, hence bigger concentrations of it are tolerated in the body. This means you can excrete it while excreting very little water - beneficial wherever water's not abundant.

There's a tradeoff though, uric acid requires more energy to synthesize than ammonia, so pretty much all fish, say, excrete ammonia rather than uric acid - it's no problem to dilute ammonia since there's no water shortage.

Answer:

The first group to contain a non-metal is Group 18.

Answer:

All of the following statements are true regarding wood versus metal except:

c) Under sustained loads wood stops to deform

Explanation:

Wood is known to deform under stress.  It undergoes warping, thereby, losing its original straight shape when its moisture unevenly dries up.  Even concrete deforms under long-time loads.  Similarly, wood, under sustained loads, experiences faster deformation than it ordinarily warps.  To prevent further wood deformation, it must be treated, and its moisture dried up evenly.

Answer:

Branched chain

Cycloalkane

Straight chain

Explanation: