Explain the application of silver halides in darkening effect in industry

Answers

Answer 1

Explanation:

Silver halides are ionic crystals consisting of a regular cubic lattice of Ag and halide ions together with a small proportion of defects, such as Ag ions that have been displaced from their regular lattice position to another “interstitial” position (the Ag ions are much smaller than the halide ions), and the corresponding vacancy in the lattice.

Answer 2

The application of silver halides in darkening effect in industry can be seen in the production of photographic film.

What is Silver halide?

This compound is usually formed when Silver reacts with an halogen under special conditions.

In photography, it is used in the production of photographic film which darkens to produce an image when exposed to light due to the effect of the compound.

Read more about Silver halide here https://brainly.com/question/7341161


Related Questions

C. If an electron is added to the outer shell, how will this affect the charge and volume of the atom?
if an electron is added on the outer shell

Answers

Answer:

An atom that gains or loses an electron becomes an ion. If it gains a negative electron, it becomes a negative ion. If it loses an electron it becomes a positive ion.

Answer:

when an atom gains an electron, it gains a negative charge . it's volume increases as well due to the increase in repulsion between the electrons

Would you expect Nio to dissolve in an aqueous solution of NaNO3?

Answers

Answer:

NiO Does Not Dissolve In An Aqueous Solution Of NaNO3.

Explanation:

Which of the following is NOT a
homogenous mixture?

Answers

this is a black screen. there’s no picture.

Answer:blacks screen. No answers to choose from. Thanks for the points:))

Explanation:

Complete the sentence by using "Direct", "Inverse", or equal. The pressure and volume of a gas change in opposite directions. This can be described as an " upside-down" relationship. We can also say that the relationship between the pressure and volume of a gas is a __________________ relationship

Answers

answer:  

i believe the answer is inverse.

if i'm wrong sorry :(

if i'm right your welcome :)

At his favorite restaurant, Dylan orders a soda with his dinner. The ice in his drink has a mass of 6 g and a volume of 20 cm3. What is the density of the ice? Explain the steps you took to solve this problem, showing your work.

Answers

Answer: d =  0.3 g/cm³ Explanation: Density: Density is equal to the mass of substance divided by its volume. Units: SI unit of density is Kg/m3. Other units are given below, g/cm3, g/mL , kg/L Formula: D=m/v D= density m=mass V=volume Symbol: The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density. Given data: Mass = 6 g Volume = 20 cm³ Density = ? Solution: d = m/v d = 6g/20 cm³ d =  0.3 g/cm³

lab

table b:eyedrop of blue water in cold water

table c:eyedrop of red water in hot water

table d:see how temperature changes on white + black paper with light shining on them
plz help

brainliest for 1st correct answer

Answers

Answer:

lol, I just did this assignment, cold water

0:30: slowly expand

1:00: still expanding

1:30: expanding is continued

2:00: still expanding slowly

2:30: expanding slowly

3:00: expanded twice the size from the first time

hot water

0:30: expanding quickly

1:00: still expanding

1:30: starts to reach the surface and still expanding

2:00: almost all the of the dye reached the top

2:30: the dye reached the top and is starting to split

3:00: the dye split appart and is moving down again

radiation

white paper

0:30: at a low temp. at around 3.3 C

1:00: still at a low temp. around 4.4 C

1:30: slowly rising temp. around 5.5 C

2:00: still slowly rising temp. around 7.2 C

2:30: still at a low temp. around 8.3 C

3:00: ends at a low temp. around 10 C

black paper

0:30: at a resonable temp. at around 6.6 C

1:00: temp. rises quicker at around 13.3 C

1:30: temp. stil rising quickly at around 17.7 C

2:00: temp. is getting hotter at around 21.6 C

2:30: temp. is still getting hotter at around 26.1 C

3:00: temp. ends at a hot temp. at around 30 C

Explanation:

A mixture of propane and butane is burned with pure oxygen. The combustion products contain 46.7 mole% H2O. After all the water is removed from the products, the residual gas contains 69.0 mole% CO2 and the balance O2 a. What is the mole percent of propane in the fuel?

Answers

Answer:

28%

Explanation:

Basically, all o did was write the equations, balance it and solve for them. Also, at the place I stared, I used simultaneous equation to solve it. Multiplying by 8 and also 3.

It's a pretty straightforward question.

At the final step that's missing, I Did

(y)C3H8 = 2.8 / ( 2.8 + 7.1)

(y)C3H8 = 0.28

What is the pH after two solutions are mixed: 1. A 0.155 M H2SO4 solution with a volume of 35.0 mL and 2. A 0.225 M solution of KOH with a volume of 35.0 mL. The volumes are additive.

Answers

Answer:

[tex]pH=1.67[/tex]

Explanation:

Hello.

In this case, since the reaction between the sulfuric acid and the potassium hydroxide is:

[tex]2KOH+H_2SO_4\rightarrow K_2SO_4+2H_2O[/tex]

We can see a 2:1 mole ratio between them, thus, we compute the moles of acid and base that are present in the solution by using the employed volume and its concentration:

[tex]n_{H_2SO_4}=0.155mol/L*0.0350L=0.005425molH_2SO_4\\\\n_{KOH}=0.225mol/L*0.0350L=0.007875molKOH\\[/tex]

Next, we use the 2:1 mole ratio to compute the consumed moles of acid:

[tex]n_{H_2SO_4}^{consumed}=0.007875molKOH*\frac{1molH_2SO_4}{2molKOH}=0.0039375molH_2SO_4[/tex]

It means that the leftover of sulfuric acid is:

[tex]n_{H_2SO_4}^{leftover}=0.005425-0.0039375=0.001488molH_2SO_4[/tex]

Therefore, since sulfuric acid is a strong acid, the pH is defined in terms of its concentration which is actually equal to the concentration of hydrogen ions in solution, which is computed considering the total additive volume:

[tex][H^+]=[H_2SO_4]=\frac{0.001488mol}{0.070L}=0.02125M[/tex]

So the pH turns out:

[tex]pH=-log(0.02125)\\\\pH=1.67[/tex]

Best regards.

Why do we need to identify matter?

Answers

Answer:

It's important for scientists to know the properties of matter because all things are made up of matter. Each type of matter has different physical characteristics and scientists need to know and understand these characteristics to make calculations. ... The main phases of matter are solid, liquid, and gas

Explanation:

^^

If the compound below is oxidized, the resulting product is ___. Select one: a. methane and propane b. butanal c. butanoic acid d. butane

Answers

The complete question is

If the compound below is oxidized, the resulting product is ___.

the compound given is Butanal

Select one:

a. methane and propane

b. butanal

c. butanoic acid

d. butane

Answer:

C. Butanoic Acid

Explanation:

When Butanal is oxidized using reagents like KMnO4, Tollens reagent etc.

When Aldehyde is oxidized corresponding Carboxylic Acid is produced

 Butanal →  Butanoic Acid

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