Answer:
Sound barrier.
Explanation:
Sound barrier is a sudden increase in drag and other effects when an aircraft travels faster than the speed of sound. Other undesirable effects are experienced in the transonic stage, such as relative air movement creating disruptive shock waves and turbulence. One of the adverse effect of this sound barrier in early plane designs was that at this speed, the weight of the engine required to power the aircraft would be too large for the aircraft to carry. Modern planes have designs that now combat most of these undesirable effects of the sound barrier.
Once the ideas were narrowed down and divided into categories, the group was split into four smaller teams. What phase(s) of the design process was each of these groups responsible for?
A. Shopping
B. Safety
C. Checkout
D. Finding stuff you need
Answer:
Finding stuff you need ( D )
Explanation:
Once an idea is narrowed down and divided into categories, The next line of action would be to create smaller groups that will be brainstorm solutions towards resolving the problem/ implement the idea faced by the team.
The phase of the design process that the smaller teams created will be focused on is to model and build a prototype ( finding stuff you need ) that would help implement the ideas
1. Represent each of the following combinations of units in the correct SI form using the appropriate prefix: (a) μMN, (b) N/μm, (c) MN/ks2, and (d) kN/ms.
2. Represent each of the following quantities in the correct SI form using the appropriate prefix: (a) 0.000431 kg, (b) 35.3(103) N, (c) 0.00532 km.
3. Represent each of the following combinations of units in the correct SI form: (a) Mg/ms, (b) N/nm, and (c) mN/(kg⋅μs).
Answer:
Kindly check explanation
Explanation:
(a) μMN, (b) N/μm, (c) MN/ks2, and (d) kN/ms.
(a) μMN = (10^-6 * 10^6) = 10^(-6 + 6) = 10^0 = N
b) N/μm = N / 10^-6 m = 10^6 * N/m = MN/m
(c) MN/ks2 = 10^6N / (10^3 s)^2
10^6 N / 10^6s^2 = 10^6 * 10^-6 N /s^2 = N/s^2
D) kN/ms = 10^3N / 10^-3 s = 10^3 * 10^3 * N/s = 10^6N / s = MN/s
2)
a) 0.000431kg = 431 × 10^6 kg = 431 * 10^9g = 431Gg
b) 35.3 × 10^3 N
10^3 = kilo(K)
35.3 KN
C) 0.00532km = 5.32 * 10^3 km = 5.32 * 10^3 * 10^3 = 5.32 * 10^6 = 5.32Mm
3) Represent each of the following combinations of units in the correct SI form: (a) Mg/ms, (b) N/nm, and (c) mN/(kg⋅μs).
a) Mg/ms = 10^6g / 10^-3s = 10^6 * 10^3 g/s = 10^9 g/s = Gg/s
b) N/nm = N / 10^-9 m = 10^9 N/m = GN/m
c) mN/(kg⋅μs) = 10^6N / kg(10^-6s) = 10^12N/(kg.s)
= TN/(kg.s)
For the reactions of ketone body metabolism, _______.
A. NADH is produced by catabolism of D‑β‑hydroxybutyrate.
B. Liver lacks thiolase and therefore cannot use ketone bodies as a fuel.
C. Conversion of 2 acetyl-CoA to acetoacetyl-CoA is accompanied by hydrolysis of ATP to AMP and PPi.
D. The enzymes that catalyze biosynthesis of ketone bodies are found in the cytosol of hepatocytes.
Answer:
Is
Explanation:
A concrete column has a diameter of 390 mm and a length of 2.8 m . If the density (mass/volume) of concrete is 2.45 Mg/m3, determine the weight of the column in pounds.
Answer: 1804.61 lbs
Explanation:
Given, diameter of concrete column = 390 mm
= 0.390 m [ 1 mm =0.001 m]
⇒ Radius = [tex]\dfrac{0.390}{2}=0.195\ m[/tex]
also, Length = 2.8 m
Volume of column (cylindrical)= [tex]\pi r^2l[/tex]
[tex]=(3.14)(0.195)^2(2.8)[/tex]
[tex]=0.3343158\ m^3[/tex]
Density [tex]=\dfrac{Mass }{Volume}=2.45\ Mg/m^3[/tex]
⇒ Mass = 2.45 x (Volume)
= 2.45 (0.3343158) Mg
= 0.81907371 Mg
⇒ Mass = 819.07271 kg [1 Mg =1000 kg]
Weight = [tex]{mass}\times{gravity}={819.07271}\times{9.8}=8026.91\ N[/tex]
1 N= 0.22482 lb
Then, Weight = [tex]0.22482\times 8026.91=1804.61\ lb[/tex]
Weight of the column in pounds.= 1804.61 lbs (approx)
Weight of the column is 1804.61 lbs.
Given that,
Diameter of column is 390mm or 0.39m.Length (l) of column is 2.8m.Density of column is 2.45 Mg/m3According to the given data, calculation are as follows,
Diameter = 0.39m
So, radius (r) = 0.39 [tex]\div[/tex] 2 = 0.195m
Volume of column = [tex]\pi r^{2}l [/tex]
By putting the value, we get
Volume = [ (3.14)[tex]\times[/tex] [tex](0.195)^{2} [/tex] [tex]\times[/tex] 2.8m ]
= [tex]0.3343158m^{3} [/tex]
Now, as we know that,
Density = Mass [tex]\div[/tex] Volume
Or, Mass (M) = Density [tex]\times[/tex] Volume
= 2.45 [tex]\times[/tex] 0.3343158
= 819.07271 kg
Now Weight = (M [tex]\times[/tex] Gravity ) Value of gravity is 9.8.
Weight = 819.07271 kg [tex]\times[/tex] 9.8
= 8026.91N
Where, 1N = 0.22482 lbs
So, Weight of the column = 1804.61 lbs
Learn more : https://brainly.com/question/21667661
What is the purpose of an engineer?
Answer:
Their purpose is to invent, design, analyze, build and test machines, complex systems, structures, gadgets and materials to fulfill functional objectives and requirements while considering the limitations imposed by practicality, regulation, safety and cost.
Answer:
To make things
Explanation:
Since most architects have at least a bachelor's degree, they do not require on-the-job training.
O True
O False
Answer:
The answer is false, I hope this helps. :3
Answer:
False
Explanation:
I took the quiz and it was correct
Trevor typically works on the highways doing maintenance. Who is most likely his employer? a large private company himself the government a small private company
Answer: The Government.
Explanation: Highways are usually a roads where people travel on. They are usually owned mainly by the government some are owned by private entities. Of the above options the most possible employer of Trevor is the government as majority of the highways are usually owned by the government.
The government provide several services on the highways such as roads maintenance, security, accidents and emergency cares etc
Answer: I think it's C, I hope this helps ;)
Which of the following statement(s) are true?
A. NAND gates output a 1 when each of its inputs is a 1.
B. All circuits can be created using only NOR gates.
C. A circuit with 4 inputs has 16 possible combinations (truth table lines).
D. You should never tie 2 outputs of two distinct circuits together.
Sam constructs a circuit, connects a lead acid battery of 2 V to a lamp of resistance 3 Ω and places an ammeter across it. What must be the reading of the ammeter?
A.
0.66 A
B.
0.5 A
C.
0.54 A
D.
0.61 A
Answer:
A. 0.66 Amps
Explanation:
Using ohms law, we can say that Voltage is equivalent to Current times Resistance. We are given the voltage and the resistance of the circuit, so we simply need to find the current.
V = IR
Solve for I, where V = 2volts and R = 3ohms.
V = IR
V * 1/R = I * R * 1/R
I = V/R
I = 2/3 Amps
Hence, we should choose option A, 0.66 Amps for the current in this simple circuit.
Cheers.
The autorotation spin characteristics of a straight-wing aircraft are induced by Group of answer choices
Answer:
More Drag on the down going wing and More Lift on the up going wing
Explanation:
The autorotation spins of blades used in airborne wind energy technology sectors help drive and move the winds and water propeller-type turbines or shafts of generators to produce electricity at altitude and transmit the electricity to earth through conductive tethers.
Sometimes autorotation takes place in rotating parachutes, kite tails. Etc.
As a result, more Drag usually induces the autorotation spin characteristics of a straight-wing aircraft on the downgoing wing and More Lift on the up-going wing.
5) Calculate the LMC wal thickness of a pipe and tubing with OD as 35 + .05 and ID as 25 + .05 A) 4.95 B) 5.05 C) 10 D) 15.025
Answer:
B) 5.05
Explanation:
The wall thickness of a pipe is the difference between the diameter of outer wall and the diameter of inner wall divided by 2. It is given by:
Thickness of pipe = (Outer wall diameter - Inner wall diameter) / 2
Given that:
Inner diameter = ID = 25 ± 0.05, Outer diameter = OD = 35 ± 0.05
Maximum outer diameter = 35 + 0.05 = 35.05
Minimum inner diameter = 25 - 0.05 = 24.95
Thickness of pipe = (maximum outer wall diameter - minimum inner wall diameter) / 2 = (35.05 - 24.95) / 2 = 5.05
or
Thickness = (35 - 25) / 2 + 0.05 = 10/2 + 0.05 = 5 + 0.05 = 5.05
Therefore the LMC wall thickness is 5.05
How can visual communication enhance the message conveyed with the speaker? Cite with a particular situation where in it is best to use visual communication
Answer:
1) Visual Communication involves the use of images ans symbolism for the exchange of ideas from a source to the intended audience.
Visual Communication can help enhance the message conveyed by the speaker when the message being conveyed is new to the audience, such as instructional or educational presentation by enable the audience to more quickly understand the the point of view of the speaker
2) A particular situation where it is best to use visual communication is in a communication that involves giving of traffic and way finding details to a tourist
Explanation:
Visual communication can improve the message that is transmitted with the speaker through the transmission of additional concepts to the message, such as gestures, body expressions or communicative looks, which add meanings to the words emitted.
Today, visual communication is extremely developed and is designed to perform several tasks at once. Communication through visual images is progressing thanks to the development of new technologies. Visual communication is one of the key components of modern media and social media.
Learn more in https://brainly.com/question/6753854
Copper (Cu) has FCC crystal structure. Atomic mass of Cu is 63.55 gmol-1 and radius of a copper atom is 0.128 nm, mean speed of conduction electrons in Cu is 1.5 × 10^6 m/s and frequency of vibration of the Cu atoms at 27 ° is 4 × 10^12 s-1. Nordheim’s Coefficient of Au in Cu is 5500 nΩ −m. a) Calculate the atomic density of copper b) Estimate the drift mobility of electrons in Cu c) Find the resistivity of pure Cu d) Find the resistivity of Cu if 1 at.% of Au is mixed in Cu. pls solve it
Answer:
First, there are 4 atoms in the FCC unit cell.
The unit volume of the unit can be calculated based on the atomic radii, in which case the hypotenuse of the cube of the unit cell would be 4 X 0.1278
Next, find the weight of one atom by taking (63.55g / mol) X (mols / 6.0221415 x 10 ^ 23 atoms)
So now you have all the numbers you need. Take the weight of the atom X 4 divided by the cube volume taken from the hypotenuse.
Explanation:
10. The repair order is a legal document because
A. the shop owner signs it
B. it's signed by the customer.
C. the manufacturer authorizes it
D. it's paid for by the customer
Steam enters an adiabatic turbine with a mass flow rate of 6 kg/s with a specific enthalpy of h = 3248.4 kJ/kg). It exits the turbine at a pressure of 15 kPa and a quality of 0.9. The power generated by this turbine, in kW, is
Answer:
5318.346
Explanation:
From the question we have
M = 6kg/s
P = 15kpa
h1 = 3248.4kj
x = 0.9
H2 is unknown
From the steam table
hf = 225.85
hg = 2599.36
H2 = HF + x(hg -hf)
h2= 225.85+0.9(2599.36 - 225.85)
= 225.85 + 0.9(2373.51)
= 225.85 + 2136.159
= 2362.009
To find The power generated by this turbine:
We insert all the parameters into the equation below:
m(h1 - h2)
= 6(3248.4 - 2362.009)
= 6 x 886.391
= 5318.346KW
Who is father of Engineer?
John Smeatom, U.K. 18th century, was the first self-proclaimed, civil engineer in the 18th century and IS considered “the father of modern, civil engineering”.
hoped this helped! :)
Answer:
Sir Mokshagundam Visvesvaraya
The Ksp for Ag2CrO4 is 9.0 x 10-12. If 200 mL of 0.0050 M AgNO3 is combined with 300 mL of 0.0020 M K2CrO4, will a precipitate form?
Answer:
Qsp > ksp
Explanation:
given data
Ag2CrO4 = 9.0 × [tex]10^{-12}[/tex]
solution
new [[tex]Ag^+[/tex]] = [tex]\frac{0.005 \times 200}{200+300}[/tex] = 0.002 M .................1
and
new [[tex]CrO^{2-}_4[/tex]] = [tex]\frac{0.002 \times 300}{200+300}[/tex] = 0.0012M ..............2
so here solubility equation will be as
[tex]Ag_2CrO_4(s)[/tex] ⇄ 2[tex]Ag^+[/tex] (aq) + [tex]CrO^{2-}_4[/tex] (aq) ......................3
so
Qsp = [tex][Ag^+]^2[/tex] [ [tex]CrO^{2-}_4[/tex]]
put here value
Qsp = (0.002)² × (0.0012)
Qsp = 4.80 × [tex]10^{-9}[/tex]
so that we can say that Qsp > ksp
Drag each tile to the correct box.
Arrange the types of movie discs in terms of the amount of content they can hold.
DVD
Blu-ray
CD
->
Answer:
Bluray
DVD
CD
Explanation:
Blu ray can hold 25gb per layer
Dvd can hold 4.7GB on a single layer
Cd can hold around 737 mb
Also, dvds can go up to 2 layers
Blu ray can go up to 4
Answer:
CD
↓
DVD
↓
Blu-ray
Explanation:
Pick up the correct statement from the following:
A. The theory of formation of concrete is based on the phenomena of formation of voids
B. The bulking of sand is taken into account while volumetric proportioning of the aggregates
C. The dry sand and the sand completely flooded with water, have practically the same volume
D. All the above
Answer:
D. All the above
Explanation:
A is correct. The theory of formation of concrete is based on this phenomenon of formation of voids because, a coarse aggregate aggregate on its own, contain voids. When a fine aggregate like sand is added, it occupies these voids. Further, when finely powdered cement is added to the mixture, it further occupies the voids between the sand particles.
B is correct. The bulking of sand should be taken into account when volumetric proportioning of the aggregates is adopted. Otherwise, less quantity of concrete per bag of cement will be produced, which naturally will increase the cost of concrete. This is because sand particles when left on their own, do not pack properly near each other due to sand buckling, leaving too many void spaces between the sand particles.
C is correct . The dry sand and the sand completely flooded with water have practically the same volume. This is due to the bulking of sand. When water is added to the sand, up to complete flooding, the sand particles pack near each other and the amount of bulking of sand is decreased. The addition of the volume of water, leads to a decrease in the volume of the sand due to the extra voids. These cancels out to practically leave the dry sand and the flooded sand with the same volume.
A man weighs 145 lb on earth.Part ASpecify his mass in slugs.Express your answer to three significant figures and include the appropriate units.Part BSpecify his mass in kilograms.Express your answer to three significant figures and include the appropriate units.Part CSpecify his weight in newtons.Express your answer to three significant figures and include the appropriate units.Part DIf the man is on the moon, where the acceleration due to gravity is gm = 5.30 ft/s2, determine his weight in pounds.Express your answer to three significant figures and include the appropriate units.Part EDetermine his mass in kilograms.Express your answer to three significant figures and include the appropriate units.
Answer:
a) 4.51 lbf-s^2/ft
b) 65.8 kg
c) 645 N
d) 23.8 lb
e) 65.8 kg
Explanation:
Weight of the man on Earth = 145 lb
a) Mass in slug is...
32.174 pound = 1 slug
145 pound = [tex]x[/tex] slug
[tex]x[/tex] = 145/32.174 = 4.51 lbf-s^2/ft
b) Mass in kg is...
2.205 pounds = 1 kg
145 pounds = [tex]x[/tex] kg
[tex]x[/tex] = 145/2.205 = 65.8 kg
c) Weight in Newton = mg
where
m is mass in kg
g is acceleration due to gravity on Earth = 9.81 m/s^2
Weight in Newton = 65.8 x 9.81 = 645 N
d) If on the moon with acceleration due to gravity of 5.30 ft/s^2,
1 m/s^2 = 3.2808 ft/s^2
[tex]x[/tex] m/s^2 = 5.30 ft/s^2
[tex]x[/tex] = 5.30/3.2808 = 1.6155 m/s^2
weight in Newton = mg = 65.8 x 1.6155 = 106
weight in pounds = 106/4.448 = 23.8 lb
e) The mass of the man does not change on the moon. It will therefore have the same value as his mass here on Earth
mass on the moon = 65.8 kg
The repair and rehabilitation of damaged or spalled concrete is done by removing the:____________A. Loose concreteB. CollapsingC. BreakageD. Bonding
Answer:
A. Loose concrete
Explanation:
Concrete is a solid composite structural material.It is the most used component in setting up a structure. Concrete is known for its very good ability to bear load, but can sometimes fail, or can be damaged. To rehabilitate or repair a concrete, the loose concrete must first be removed, so that the surface can be cleaned and well set before the material used for repair is applied on it.
If a transistor is operating with 5 mA of Collector Current, 100uA of Base Current and VCE = 10 V. What is the power dissipation?
Answer:
well its 31.4226804124
Explanation:
Under the right conditions, it is possible, due to surface tension,to have metal objects float on water. Consider placing a shortlength of a small diameter steel ( γ = 490 lb/ft3)rod on a surface of water. What is the maximum diameter that therod can have before it will sink? Assume that the surface tensionforces act vertically upward. Note: A standard paper cliphas a diameter of 0.036 in. Partially unfold a paper clip and seeif you can get it to float on water. Do the results of thisexperiment support your analysis?
Answer:
A) 0.0614 inches
b) The standard steel paper clip should float on water
Explanation:
The maximum diameter that the rod can have before it will sink
we can calculate this using this formula :
D = [tex](\frac{8\alpha }{\pi y } )^{\frac{1}{2} }[/tex] ----- 1
∝ = value of surface tension of water at 60⁰f = 5.03×10^−3 lb/ft
y = 490 Ib/ft^3
input the given values into equation 1 above
D = [tex](\frac{8*(5.3*10^{-3}) }{\pi *490 } )^{\frac{1}{2} }[/tex]
= 5.11 * 10^-3 ft convert to inches
= 5.11 *10^-3 ( 12 in/ 1 ft ) = 0.0614 inches
B) The diameter of a standard paper Cliphas = 0.036 inches
and the diameter of the rod = 0.0614. Hence the standard steel paper clip should float on water
In a four-stroke engine, the piston rises in the cylinder, which triggers the _______ stroke.
intake
compression
exhaust
power
Answer: It is power stroke
In a voltage-divider biased npn transistor, if the upper voltage-divider resistor (the one connected to VCC) opens:______.
a) the transistor goes into cutoff.
b) the transistor goes into saturation.
c) the transistor burns out.
d) the supply voltage is too high.
Answer:
The transistor goes into cutoff ( A )
Explanation:
In a voltage-divider biased npn transistor, if the upper voltage-divider resistor (the one connected to VCC) opens the transistor goes into cutoff
Voltage-divider biased npn transistor is a transistor that consists of some resistors and this resistors help to divide and distribute the voltage entering the transistor into its correct levels ( this is the most popular means of biasing a BJT transistor )
What would happen if an exposed film was accidentally placed in the fixer before being placed in the developer
the amount of phase shift between input and output signal is important when measuring ____ circuit
Answer:
The amount of phase shift between input and output signal is important when measuring a common emitter amplifier circuit.
Explanation:
the amount of phase shift between input and output signal is important when measuring a common emitter amplifier circuit
In signal processing, phase distortion is change in the shape of the waveform, that occurs when the phase shift introduced by a circuit is not directly proportional to frequency.
In a common emitter amplifier circuit there is an 180-degree phase shift between the input and output waveforms.
The magnitude of the line voltage at the terminals of a balanced Y-connected load is 660 V. The load impedance is 240-j70 Ω/Φ. The load is fed from a line that has an impedance of 0.5 + j4 Ω/Φ.
A) What is the magnitude of the line current?
B) What is the magnitude of the line voltage at the source?
Answer:
A) magnitude of the line current = 15.24 A
B) 6583.94 v
Explanation:
Given data :
magnitude of line voltage at terminal = 6600 v
load impedance = 240 - j70 Ω/∅
impedance of load fed from a line = 0.5 + j4 Ω/∅
attached below is the detailed solution
Ten dollars per hour is about how much income per year
Answer:
see below
Explanation:
10 per hour
example: 37.5 hours in a week
10 x 37.5 hours per week x 52 weeks in a year
19,500 per year.
you can use the above calculation depending on how much you want to work per week.
Represent each of the following combinations ~f units in the correct SI form using an appropriate prefix:______
(a) m/ ms,
(b) µkm,
(c) ks/ mg,
(d) km· µN.
Answer:
(a) km/s
(b) mm
(c) Gs/kg
(d) mmN
Explanation:
(a) Given:
m / ms => the proper SI unit should be m/s
So let's convert to m/s
m / ms = [tex]\frac{m}{ms}[/tex]
The denominator is ms which means milliseconds.
But milli = 10⁻³
∴ [tex]\frac{m}{ms}[/tex] = [tex]\frac{m}{10^{-3}s}[/tex] = [tex]\frac{10^3m}{s}[/tex]
Also 10³ = kilo (k)
[tex]\frac{10^3m}{s}[/tex] = [tex]\frac{km}{s}[/tex]
∴ m / ms = [tex]\frac{km}{s}[/tex] = km/s
(b) Given:
μkm => the proper SI unit should be m
So let's convert to m
μkm = 10⁻⁶ km [since μ = 10⁻⁶]
=> μkm = 10⁻⁶ x 10³ m [since k = 10³]
=> μkm = 10⁻³ m
But 10⁻³ = milli (m)
=> μkm = 10⁻³ m = mm
∴ μkm = mm
(c) Given:
ks/mg => the proper SI unit should be s/kg
So let's convert to s/kg
ks/mg = 10³s / mg [since k = 10³]
=> ks/mg = 10³s / 10⁻³g [since m = 10⁻³]
=> ks/mg = 10³ x 10³ s / g
=> ks/mg = 10⁶ s / g
=> ks/mg = [tex]\frac{10^6 s}{g}[/tex]
Multiply the numerator and denominator by 10³
=> ks/mg = [tex]\frac{10^6 X 10^3s}{10^3 X g}[/tex]
=> ks/mg = [tex]\frac{10^9s}{10^3 X g}[/tex]
=> ks/mg = [tex]\frac{Gs}{10^3 X g}[/tex] [since 10⁹ = Giga (G) ]
=> ks/mg = [tex]\frac{Gs}{kg}[/tex] [since 10³ = Kilo (k) ]
∴ ks/mg = [tex]\frac{Gs}{kg}[/tex] = Gs/kg
(d) Given:
km.μN => the proper SI unit should be mN or Nm
So let's convert to km.μN
km.μN = 10³m.μN [since k = 10³]
=> km.μN = 10³m.10⁻⁶N [since μ = 10⁻⁶]
=> km.μN = 10⁻³ mN
=> km.μN = mmN [since m = milli = 10⁻³]
∴ km.μN = mmN