Solution given:
[tex] \sin( \alpha ) = \frac{\sqrt{5} }{3}[/tex]
so
P=√5
h=3
b=[tex] \sqrt{3 {}^{2} - \sqrt{5} {}^{2} } [/tex]
b=2
so
[tex] \cos( \alpha ) = \frac{b}{h} = \frac{2}{3} [/tex]
Note
[tex] \alpha = 0[/tex]
b:⅔
Perpendicular=√5
Hypotenuse=3
Base
√(3)²-(√5)²√9-5√42CosØ
Base/Hypotenuse2/3Please find the value of this Rectangular Prism
Answer:
168cm^3
Step-by-step explanation:
area of a cube is B*H*L
(6)*(7)*(4) = area
168cm^3 = area
Answer:
168 cm³
Step-by-step explanation:
V = w · h · l
4 · 6 · 7
V = 168
ANSWER PLEASE i need help i will mark brainliest
Answer:
let the two no. be x and y.
their sum
x+y=-11
x=-11-y.....[I]
and difference
x-y=41
x=41+y......[ii]
equating equation I and ii
we get
-11-y=41+y
-11-41=y+y
-52=2y
y=-52/2
y=-26
now
substituting value of y in equation I.
we get
x=-11-(-26)=-11+26=15
The two no. is 15 and -26.
Help me please :) thanks
Answer:
20 and 90
Step-by-step explanation:
Please help me. 20 POINTS
Answer:
could you please also post what the choosing options are and then ill edit this and do it again
Step-by-step explanation:
Does anyone know how to simplify this expression? I know it has to do with properties of summation and special summation rules but I can’t quite figure it out.
============================================================
Explanation:
Let's expand this out up to say n = 6 terms
I'll write the summation in such a way that each (1/(k+1) - 1/k) grouping will get its own row. Each row has the same value of k.
If we plug in k = 1 through k = 6, but not evaluate just yet, we will have this:
1/(1+1) - 1/1
1/(2+1) - 1/2
1/(3+1) - 1/3
1/(4+1) - 1/4
1/(5+1) - 1/5
1/(6+1) - 1/6
All I've done so far is replace k with 1 through 6. Again, each row represents a different k value. Each row has the general format 1/(k+1)-1/k.
Let's simplify everything in the first column.
So the (1+1) turns into 2, the (2+1) turns into 3, and so on.
Doing that leads to...
1/2 - 1/1
1/3 - 1/2
1/4 - 1/3
1/5 - 1/4
1/6 - 1/5
1/7 - 1/6
Then note how we have the cancellations shown in the diagram below. The color coding shows how the terms pair up to cancel out. By "cancel out", I mean specifically that the fractions add up to 0. Eg: 1/2 + (-1/2) = 0.
Nearly everything cancels out. The only things left after the dust settles is the -1/1 in the first row and the 1/7 in the bottom row. This evaluates to 1/7-1/1 = 1/7 - 7/7 = (1-7)/1 = -6/7
If you were to try this with n = 7, then you should find that again nearly everything cancels but the fractions -1/1 and 1/8. Then 1/8 - 1/1 = -7/8.
For n = 8, you should end up with 1/9 - 1/1 = -8/9.
You can probably see the pattern.
A conjecture is that the answer is -n/(n+1). The general proof of this isn't too tricky. Simply follow the same ideas as mentioned above. Expand out a few terms and see how things cancel out. You'll find that everything cancels except for the -1/1 in the first row and the 1/(n+1) just one term before the very end. Then we can say:
1/(n+1) - 1/1
1/(n+1) - (n+1)/(n+1)
(1-(n+1))/(n+1)
(1-n-1)/(n+1)
-n/(n+1)
If we tried n = 6, then we find,
-n/(n+1) = -6/(6+1) = -6/7
which was the result we found earlier when we added the first n = 6 terms of this series. Trying out n = 7 should lead to -n/(n+1) = -7/8, and so on.
According to a recent study, the average American household spends $1,700 on clothing per year, with a standard deviation of $530. What percent of households spend less than $1170 per year, based on this data?
Answer:
$3,220
Step-by-step explanation:
Add
In contrast to cooperative hunting, which are benefits of herding only? Check all that apply.
a. foraging
b. reproduction
c. divison of labor
d. protection
e. aerodynamic efficiency
f. hydrodynamic efficiency
the answer is : a, b, d
PLEAAE HELP Tiffany practices her guitar for hour each day. How many hours does she practice in 7 days? Make an equation to solve the problem.
Answer:
7n
Step-by-step explanation:
Let :
The number of hours of practice per day = n
The number of practice hours in 7 days can be calculated thus :
Number of hours of practice per day * number of days
(n * 7) = 7n
Beth is covering a cylinder can't create a pencil container for a test. The cat is 15 cm tall and has a diameter of 7 cm. How much paper what she need to cover only the sides of the can.
Please help...thx
Answer:
[tex]A = 329.7[/tex]
Step-by-step explanation:
Given
[tex]h = 15[/tex] --- height
[tex]d = 7[/tex] --- diameter
Required
Paper needed to cover the sides
To do this, we simply calculate the surface area of the cylinder (without considering the top and bottom)
This is calculated as:
[tex]A = 2\pi rh[/tex]
Where
[tex]r = \frac{d}{2}[/tex]
[tex]r = \frac{7}{2}= 3.5[/tex]
The formula becomes
[tex]A = 2 * 3.14 *3.5 *15[/tex]
This gives:
[tex]A = 329.7[/tex]
Evaluate - 15.85 + y for the following values of y.
value of y value of expression
-32.1 -47.95
-63.06
-84.703
-8.115
Answer:
-78.91 -100.553 -23.965
Step-by-step explanation:
-15.85 - 63.06 = -78.91
-15.85 -84.703 = -100.553
-15.85 -8.115 = -23.965
Find the equation of the linear function represented by the table below in slope-
intercept form.
9514 1404 393
Answer:
y = -4x -2
Step-by-step explanation:
The slope is given by the formula ...
m = (y2 -y1)/(x2 -x1)
m = (-10 -10)/(2 -(-3)) = -20/5 = -4
__
The y-intercept is given by ...
b = y1 -m(x1)
b = 10 -(-4)(-3) = 10 -12 = -2
Then the slope-intercept equation is ...
y = mx +b
y = -4x -2
HELP QUICK ROUND EACH VALUE TO THE NEAREST TENTH
Solve the following problems. Choose the letter of the correct answer. (Show your complete solutions.)
5.) If the length of the two sides of an isosceles triangle are 3 cm and 7 cm, then what must be the length of the third side?
A. 3cm B. 10 cm C. 14 cm D. 7 cm
:1
i didnt understand the question because of my English sorry
:2
we all know that the total of degrees is 180 so 70+70=140
180-140=40
so the answer is 40
3:
we have a figure with 4 angle so the total of degrees is 360 so the answer is 126
4:
the answer most be 50 becuse we have a Special degree witch always equal 90 if we have recatngle so
x+40=90
X=50 the answer and if you want to try again choose the second one
2x-10=90
2x=100
X=50 same answe you see
5:
in this quastion i searched and find alot of answers any way
its should be 7 or 3 but the correct answer in my opinion its 7
its shows in the picture i sent hopefully its helpful to you i will try to translate the first quastion and sent it to you
A fabric manufacturer believes that the proportion of orders for raw material arriving late isp= 0.6. If a random sample of 10 orders shows that 3 or fewer arrived late, the hypothesis thatp= 0.6 should be rejected in favor of the alternativep <0.6. Use the binomial distribution.(a) Find the probability of committing a type I error if the true proportion isp= 0.6.(b) Find the probability of committing a type II error for the alternative hypothesesp= 0.3,p= 0.4, andp= 0.5
Answer:
a) the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548
b)
- the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504
- the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177
- the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281
Step-by-step explanation:
Given the data in the question;
proportion p = 0.6
sample size n = 10
binomial distribution
let x rep number of orders for raw materials arriving late in the sample.
(a) probability of committing a type I error if the true proportion is p = 0.6;
∝ = P( type I error )
= P( reject null hypothesis when p = 0.6 )
= ³∑[tex]_{x=0[/tex] b( x, n, p )
= ³∑[tex]_{x=0[/tex] b( x, 10, 0.6 )
= ³∑[tex]_{x=0[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.6)^x[/tex][tex]( 1 - 0.6 )^{10-x[/tex]
∝ = 0.0548
Therefore, the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548
b)
the probability of committing a type II error for the alternative hypotheses p = 0.3
β = P( type II error )
= P( accept the null hypothesis when p = 0.3 )
= ¹⁰∑[tex]_{x=4[/tex] b( x, n, p )
= ¹⁰∑[tex]_{x=4[/tex] b( x, 10, 0.3 )
= ¹⁰∑[tex]_{x=4[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.3)^x[/tex][tex]( 1 - 0.3 )^{10-x[/tex]
= 1 - ³∑[tex]_{x=0[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.3)^x[/tex][tex]( 1 - 0.3 )^{10-x[/tex]
= 1 - 0.6496
= 0.3504
Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504
the probability of committing a type II error for the alternative hypotheses p = 0.4
β = P( type II error )
= P( accept the null hypothesis when p = 0.4 )
= ¹⁰∑[tex]_{x=4[/tex] b( x, n, p )
= ¹⁰∑[tex]_{x=4[/tex] b( x, 10, 0.4 )
= ¹⁰∑[tex]_{x=4[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.4)^x[/tex][tex]( 1 - 0.4 )^{10-x[/tex]
= 1 - ³∑[tex]_{x=0[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.4)^x[/tex][tex]( 1 - 0.4 )^{10-x[/tex]
= 1 - 0.3823
= 0.6177
Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177
the probability of committing a type II error for the alternative hypotheses p = 0.5
β = P( type II error )
= P( accept the null hypothesis when p = 0.5 )
= ¹⁰∑[tex]_{x=4[/tex] b( x, n, p )
= ¹⁰∑[tex]_{x=4[/tex] b( x, 10, 0.5 )
= ¹⁰∑[tex]_{x=4[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.5)^x[/tex][tex]( 1 - 0.5 )^{10-x[/tex]
= 1 - ³∑[tex]_{x=0[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.5)^x[/tex][tex]( 1 - 0.5 )^{10-x[/tex]
= 1 - 0.1719
= 0.8281
Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281
The probability of committing a type I is 0.0548, type II error for p = 0.3 is 0.3504, type II error for p = 0.4 is 0.6177, type II error for s p = 0.5 is 0.8281.
The sample size n = 10
What is binomial distribution?Binomial distribution summarizes the number of trials, or observations when each trial has the same probability of attaining one particular value.
[tex]\rm p= \left[\begin{array}{ccc}n\\x\\\end{array}\right] \times p^{x} \times q^{n-x}[/tex]
(a) Probability of committing a type I error if the true proportion is p = 0.6;
∝ = P( type I error )
= P( reject null hypothesis when p = 0.6 )
[tex]\rm p= \left[\begin{array}{ccc}10\\x\\\end{array}\right] \times 0.6^{x} \times 0.6^{10-x}\\[/tex]
∝ = 0.0548
Therefore, the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548
b) The probability of committing a type II error for the alternative hypotheses p = 0.3
β = P( type II error )
= P( accept the null hypothesis when p = 0.3 ) = ¹⁰∑
[tex]\rm p= \left[\begin{array}{ccc}10\\x\\\end{array}\right] \times 0.3^{x} \times 0.3^{10-x}\\[/tex]
= 1 - ³∑
= 1 - 0.6496
= 0.3504
Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504
The probability of committing a type II error for the alternative hypotheses p = 0.4
β = P( type II error )
= P( accept the null hypothesis when p = 0.4 )
[tex]\rm \left[\begin{array}{ccc}10\\x\\\end{array}\right] \times 0.4^{x} \times 0.4^{10-x}\\[/tex] = ¹⁰∑
= 1 - ³∑
= 1 - 0.3823
= 0.6177
Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177
The probability of committing a type II error for the alternative hypotheses p = 0.5
β = P( type II error )
= P( accept the null hypothesis when p = 0.5 )
¹⁰∑ = [tex]\rm \left[\begin{array}{ccc}10\\x\\\end{array}\right] \times 0.5^{x} \times 0.5^{10-x}\\[/tex]
= 1 - ³∑
= 1 - 0.1719
= 0.8281
Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281
Learn more about Binomial distribution here:
https://brainly.com/question/12734585
Which is a pentomino?
ОА
ОВ.
ОС.
OD.
Answer:
B.Step-by-step explanation:
Because A. Is not pentomino C. Is not pentominoD. There are no pentominowhat is the area of the cylinder rounded to the nearest whole number
Answer:
the area is 207
Step-by-step explanation:
The equation to solve the area of a cylinder is A=2πrh+2πr^2
The radius is the length from the outside to the center, 6 is the diameter so we could half that to get the radius, 3 and height is 8
A=2*3.14*3*8+2*3.14*3^2
A=6.28*3*8+6.28*9
A=18.84*8+56.52
A=150.72+56.52
A=207.24
207.24 rounded to the nearest whole number is 207 so your area is 207
help pls what is he surface area measured in square centimeters, of the shape
below do not include units in your answer
Answer:
Solution given:
l=8cm
b=8cm
h=3cm
now
total surface area=2(lb+bh+lh)
=2(8*8+8*3+8*3)=224cm²
224 cm² is a required volume.
ANSWER FAST
DRAW A MODEL IF NECESSARY
1. 4x=44
2. 20x=200
Answer:
1. x=11
2. x=10
Answer:
Step-by-step explanation:
To answer quickly, I would assume that x in the first equation equals 11 since
4 x 11 = 44.
And for the second one, 20 x 10 = 200.
First equation x = 11
Second equation x = 10
Good luck!
HELPPP PLSS
DUE TN
WILL GIVE BRAINLIST
Answer:
49/144
Step-by-step explanation:
Answer:
49/144
Step-by-step explanation:
Ms. Alberta has a rectangular area set aside to plant some fruits and vegetables. The garden has a width of (6x2) cm2 and a length of (11x3) cm2 . If the formula for area is A=l⋅w, what is the area of Ms. Alberta’s garden?
17x5
17x6
66x6
66x5
Answer:
A = 66×6 cm²
Step-by-step explanation:
Given that,
The width of a rectangular garden, w = (6x2) cm
The length of a rectangular garden, l = (11x2) cm
We need to find the area of Ms. Alberta’s garden. The area of a rectangular garden is given by :
A = LW
Put all the values,
A = (6x2) × (11x3)
= (11×6)(2×3)
= 66×6 cm²
Hence, the area of the Ms. Alberta’s garden is 66×6 cm².
In ΔWXY, the measure of ∠Y=90°, YX = 40, XW = 41, and WY = 9. What ratio represents the cosine of ∠W?
Answer:
[tex]\cos{W} = \frac{9}{41}[/tex]
Step-by-step explanation:
Cosine of an angle:
The cosine of an angle, in a right triangle, is the length of the side adjacent to this angle divided by the hypotenuse.
Length of the largest side:
The length of the largest side is 41, that is, the hypotenuse is 41. The hypotenuse is XW.
WY = 9.
This means that the length of the adjacent side to angle W is 9.
What ratio represents the cosine of ∠W?
Adjacent side has length 9, hypotenuse has length 41. So
[tex]\cos{W} = \frac{9}{41}[/tex]
Can someone help??
What is the equation of the blue line?
Answer:
y = 4x - 3
Step-by-step explanation:
Find two point of the line
(0,-3) ; (1,1)
Use this formula
(y - y1)/(y2-y1) = (x-x1)/(x2-x1)
(y-(-3)/(1-(-3) = (x-0)/(1-0)
(y+3)/4 = x
y+3 = 4x
y = 4x -3
Answer:
y = 4x -3
Step-by-step explanation:
The y intercept is (0,-3)
Using another point on the line (1,1), we can find the slope
m = (y2-y1)/(x2-x1)
m = (1 - -3)/(1-0)
= (1+3)/(1-0)
= 4/1
The equation for a line in slope intercept for is
y = mx+b where m is the slope and b is the y intercept
y = 4x -3
NEEEEEEEEED HELPPP step by step
Answer:
Step-by-step explanation:
calculate the area of the parallelogram and explain how to decompose this shape into rectangles and triangles
Can someone answer this please
Answer:
I believe it is 14 mm, hope i helped
According to this diagram, what is tan 62°?
Answer:
12
Step-by-step explanation:
i think that is the answer
What is the approximate lateral surface area of the cylinder?
9 cm
2 cm
Answer:
138 is closest to the Lateral surface which is 113.097
Step-by-step explanation:
NEED HELP Shehuwywbejdckisgw ejeiduxsvbsjebebwe
Answer:
2183475 dont know
Step-by-step explanation:
Answer:
15x = 58y
Step-by-step explanation:
If 2 and 5 are 3 distance apart then 12 and 15 are 3 distance apart.
the difference between 2 and 5 is 5 because 86-81 is 5. So if we subtract 63-5 we will get 58
Hope this helps! Please leave any questions or concerns in the comments byeee <3
) Which expressions are equivalent to 35? Choose ALL that apply.
9.27
81.3
3.5
3.3.3.3.3
9.9
Answer:
[tex](a)\ 9 * 27[/tex]
[tex](b)\ 81 * 3[/tex]
[tex](d)\ 3*3*3*3*3[/tex]
Step-by-step explanation:
Given
[tex]3^5[/tex]
Required
Select equivalent expressions
[tex](a)\ 9 * 27[/tex]
Express as exponents
[tex]9 * 27 = 3^2 * 3^3[/tex]
Apply law of indices
[tex]9 * 27 = 3^{2+3[/tex]
[tex]9 * 27 = 3^{5[/tex]
[tex](b)\ 81 * 3[/tex]
Express as exponents
[tex]81 * 3 = 3^4 * 3[/tex]
Apply law of indices
[tex]81 * 3 = 3^{4+1[/tex]
[tex]81 * 3 = 3^5[/tex]
[tex](c)\ 3*5[/tex]
Solve
[tex]3*5 = 15[/tex]
[tex](d)\ 3*3*3*3*3[/tex]
From calculator, we have
[tex]3*3*3*3*3=243[/tex]
Express as exponents
[tex]3*3*3*3*3=3^5[/tex]
[tex](e) 9 * 9[/tex]
Express as exponents
[tex]9 * 9= 3^2 * 3^2[/tex]
Apply law of indices
[tex]9 * 9= 3^{2+2[/tex]
[tex]9 * 9= 3^4[/tex]
Hence, a, b and d are true
Question 10 (2 points)
A square table 4 feet on each side has two drop leaves, each a semicircle 4 feet in diameter.
Find the area of the table with and without the drop leaves.
1) With Drop Leaves (Semicircles are attached to table) =
ft. 2
2) Without Drop Leaves (Semicircles are not attached to table)
ft 2
4 ft
|4ft
Answer:
Area of table with leaf = 28.56 feet²
Area of table without leaf = 16 feet²
Step-by-step explanation:
Given:
Side of square table = 4 feet
Diameter of side leaf = 4 feet
Number of semicircle leaf = 2
Find:
Area of table without leaf
Area of table with leaf
Computation:
Area of square = Side x Side
Area of table without leaf = 4 x 4
Area of table without leaf = 16 feet²
Radius of side leaf = Diameter of side leaf / 2
Radius of side leaf = 4 / 2
Radius of side leaf = 2 feet
Area of table with leaf = Area of table without leaf + 2[πr²/2]
Area of table with leaf = 16+ 2[πr²/2]
Area of table with leaf = 16+ (3.14)(2)²
Area of table with leaf = 16+ (3.14)(4)
Area of table with leaf = 16+ 12.56
Area of table with leaf = 28.56 feet²