evaluate 3c + 6y for c=5 and y=6

Answer:

To find area of the square you'll need to square one side

(3X)^2 = 81

9(X)^2 = 81

(x)^2 = 81/9

x^2 = 9

X = (9)^1/2

X = 3

Answer:

-90

Step-by-step explanation:

it's right

Answer:

The first one.

Step-by-step explanation:

I took the quiz and got a 100, hope this helps :))

Answer: the answer is b=9

Step-by-step explanation:

Step 1: Subtract 32 from both sides.

104-32= 72

Step 2: Divide both sides by 8.

72 divided by 8 is 9

therefor the answer is 9

Answer:

As per graph the rate of Printer A is 15 pages per minute.

Missing words are:

(a) greater than

(b) greater than

(c) 15

The rate for Printer B is greater than the rate for Printer A because the rate of 25 pages per minute is greater than the rate of 15 pages per minute for Printer A.

or

The printing rate for Printer B is 10 pages more than the rate of printer A because the rate of 25 pages per minute is 10 pages more than the rate 15 pages per minute for Block A

Step-by-step explanation: it's either greater than or more than

From the graph of the printing rate of Printer A, we can see that;

At 1 minute, number of pages printed = 15

At 2 minutes, number of pages printed = 30 minutes

At 3 minutes, number of pages printed = 45

Thus printing rate for printer A is; 15/1 = 30/2 = 45/3 = 15 pages per minutes

Since printer B can print 25 pages per minute, we can conclude that;

The printing rate for Printer B is 10 pages more than the rate of printer A because the rate of 25 pages per minute is 10 pages more than the rate 15 pages per minute for Block A

Answer: x = 17

Step-by-step explanation:

Hi there!

First, since we know that these two lines are parallel, 3x+14 is going to be congruent to the supplementary side of 7x-4. Given this, we are able to solve for x as we know that the sum of supplementary angles is 180. All you have to do is set up 3x+14+7x-4=180

Now, just use simple order of operations and combining like terms to isolate x. you will end with 17! :)

Hope this helps!

Answer:

x > 2

Step-by-step explanation:

-1+6(-1-3x)>-39-2x

-1-6 - 18x > -39 - 2x

-7 - 18x + 2x > -39 - 2x + 2x

-7 - 16x + 7 > -39 + 7

16x / 16 > -32 / 16

x > 2

a) The equation is therefore; x³ + 3x² + 2x = 336

b) Solving for the length, we get the length to be; x = 6.

c) All workings are as shown below;

According to the question;

In essence, the volume of the original prism is;

Since, the original prism had a length, width, and height of consecutive integers, increasing in that order.

a) The equation is therefore;

b) Solving for the length, x is as follows;

By testing values and checking;

c) All workings are as shown above.

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EXPLANATION:

Given that

sin θ = 1/2

We know that

sin 3θ = 3 sin θ - 4 sin³ θ

⇛sin 3θ = 3(1/2)-4(1/2)³

⇛sin 3θ = (3/2)-4(1/8)

⇛sin 3θ = (3/2)-(4/8)

⇛sin 3θ = (3/2)-(1/2)

⇛sin 3θ = (3-1)/2

⇛sin 3θ = 2/2

⇛sin 3θ = 1

and

cos 2θ = cos² θ - sin² θ

⇛cos 2θ = 1 - sin² θ - sin² θ

⇛cos 2θ = 1 - 2 sin² θ

Now,

cos 2θ = 1-2(1/2)²

⇛cos 2θ = 1-2(1/4)

⇛cos 2θ = 1-(2/4)

⇛cos 2θ = 1-(1/2)

⇛cos 2θ = (2-1)/2

⇛cos 2θ = 1/2

Now,

The value of sin 3θ /(1+cos 2θ

⇛1/{1+(1/2)}

⇛1/{(2+1)/2}

⇛1/(3/2)

⇛1×(2/3)

⇛(1×2)/3

⇛2/3

Answer : Hence, the req value of sin 3θ /(1+cos 2θ) is 2/3.

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if cos θ -sin θ =1, find θ cos θ +sin θ?

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Answer:

y=

x

​

−2

y=−

x

​

−2, x≥0

​

y=−

x−2, x≥0

​

Step-by-step explanation:

Answer:

3 vanilla

Step-by-step explanation:

If 75% of the order equates to 9 chocolate, then the remaining of the dozen would leave three.

Unless there is more than 12 in the order. The question is vague

The Lateral Surface Area of the cylindrical oil storage tank is [tex]2486.9\text{ sq.ft}[/tex]

The Total Surface Area of the cylindrical oil storage tank is [tex]5526.4\text{ sq.ft}[/tex]

If the height and base radius of the cylindrical oil storage tank are represented by [tex]h[/tex] and [tex]r[/tex] respectively, then

The Lateral Surface Area, also known as the Curved Surface Area, of the cylindrical oil storage tank has the formula

[tex]L=2\pi rh[/tex]

The Total Surface Area of the cylindrical oil storage tank has the formula

[tex]T=2\pi rh+2\pi r^2\\T=2\pi r(h+r)[/tex]

The values for the height and base radius are [tex]18ft[/tex] and [tex]22ft[/tex] respectively.

Calculate the Lateral Surface Area

[tex]L=2\pi rh\\=2\times 3.14\times 22\times 18\\\approx 2486.9\text{ sq.ft}[/tex]

Calculate the Total Surface Area

[tex]T=2\pi r(h+r)\\=2\times 3.14\times22(18+22)\\=5526.4\text{ sq.ft}[/tex]

Learn more about the surface area of cylinders here https://brainly.com/question/1037971

[tex]\left(3+\sqrt{-16} \right) \left(5-\sqrt{-25} \right)\\\\=\left(3+\sqrt{-1} \cdot \sqrt{16} \right) \left(5- \sqrt{-1} \cdot \sqrt{25} \right)\\\\=(3+4i)(5-5i)~~~~~~~~~~~~~~;\left[i=\sqrt{-1} \right]\\\\=15-15i + 20i - 20i^2\\\\=15+5i -20(-1)~~~~~~~~~~~~;[i^2 =-1]\\\\=15+5i +20\\\\=35+5i[/tex]

Answer:

2.8

Step-by-step explanation:

Answer:

Step-by-step explanation:

2.8 units

6x+3y=13

6x+3y-13=13--13

6x+3y-13=0

Answer:

pic?

Step-by-step explanation:

send me the picture please

Answer: (-7,-5)

Step-by-step explanation:

Because when you mark point M and A if you mirror point M and A on the x Axis then you will get (-7,-5)

The measure of the exterior angle at vertex D is: D. 54°

Recall:

Thus:

In ΔDEF, (8x−2)º is an exterior angle at vertex D.

m∠E = (3x−8)° (interior angle)

m∠F = (4x+13)° (interior angle)

Therefore:

(8x−2)º = (3x−8)° + (4x+13)°

8x - 2 = 3x - 8 + 4x + 13

8x - 2 = 7x + 5

8x - 7x = 2 + 5

x = 7

Exterior angle at vertex D = (8x−2)º

= 8(7) - 2

= 54º (option D)

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Answer: 40

Step-by-step explanation: yes make me brainlist (its the crown)

Step-by-step explanation:

Volume=length*width*height

V = (3/2)*(4)*(1/2)

= 12/4 = 3cm^3

The temperature of the body after 60 minutes is  60.5° F.

Using the Newton's law of cooling;

T(t) =[tex]Ts + (To - Ts)e^-kt[/tex]

T(t) = temperature at time t

Ts = temperature of the surrounding

To = Temperature of object

t = time taken

k = cooling constant

Now;

[tex]T(t) -Ts=(To - Ts)e^-kt\\45 - 67 = (34 - 67)e^-15k\\-22 = -33e^-15k\\-22/-33 = e^-15k\\0.667 = e^-15k\\ln(0.667) = ln( e^-15k)\\-0.405 = -15k\\k = -0.405/ -15\\k = 0.027[/tex]

At t = 60 min

[tex]T(t) = Ts + (To - Ts)e^-ktT(60) = 67 + (34 - 67)e^-( 0.027*60)\\T(60) = \\67 + (-33)e^-( 0.027 * 60)\\T(60) = \\60.5 F[/tex]

T(60) = 60.5° F

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Answer:

T≈169

Step-by-step explanation:

Enter only the final temperature into the input box.

T_a = 67\hspace{50px}T_0=210

T  

a

​

=67T  

0

​

=210

\text{Write Formula:}

Write Formula:

T=67+(210-67)e^{-kt}

T=67+(210−67)e  

−kt

Plug in givens

\color{blue}{T}=67+143e^{-k\color{green}{t}}

T=67+143e  

−kt

Simplify

\text{Plug in given time and temperature:}

Plug in given time and temperature:

\color{blue}{193}=67+143e^{-k(\color{green}{1.5})}

193=67+143e  

−k(1.5)

Simplify

\text{Solve for }k\text{:}

Solve for k:

193=

193=

\,\,67+143e^{-1.5k}

67+143e  

−1.5k

-67\phantom{=}

−67=

\,\,-67

−67

126=

126=

\,\,143e^{-1.5k}

143e  

−1.5k

\frac{126}{143}=

143

126

​

=

\,\,\frac{143e^{-1.5k}}{143}

143

143e  

−1.5k

​

Divide by 143

0.8811189=

0.8811189=

\,\,e^{-1.5k}

e  

−1.5k

\ln\left(0.8811189\right)=

ln(0.8811189)=

\,\,\ln\left(e^{-1.5k}\right)

ln(e  

−1.5k

)

Take ln of both sides

\ln\left(0.8811189\right)=

ln(0.8811189)=

\,\,-1.5k

−1.5k

\frac{\ln\left(0.8811189\right)}{-1.5}=

−1.5

ln(0.8811189)

​

=

\,\,\frac{-1.5k}{-1.5}

−1.5

−1.5k

​

Divide by -1.5

0.0843751=

0.0843751=

\,\,k

k

k\approx

k≈

\,\,\color{blue}{0.084}

0.084

Round k to nearest thousandth

\text{Complete Formula:}

Complete Formula:

T=67+143e^{-\color{blue}{0.084}t}

T=67+143e  

−0.084t

Plug in k

\text{Find temperature after }\color{green}{4}\text{ minutes:}

Find temperature after 4 minutes:

T=67+143e^{-0.084(\color{green}{4})}

T=67+143e  

−0.084(4)

Plug in time

T=67+143e^{-0.336}

T=67+143e  

−0.336

Multiply

T=169.1911041

T=169.1911041

Plug into the calculator

T\approx 169

T≈169

Answer:

Nick will have to pay $63.56 for the shoes.

Step-by-step explanation:

f the original cost of the shoes is $56.75 and the markup is 12% greater than the original price, the final price would be $63.56.

$56.75 • 0.12 = $6.81

$56.75 + $6.81 = $63.56

$56.75 + 12% = $63.56

Answer:

Nick will have to pay $63.56 for the shoes.

The volume of the bigger sphere is 8 times larger than the volume of the smaller sphere.

The formula of the volume of a sphere is given below

⇒ Formula:

⇒ Where:

From the question, There are two spheres.

If the radius of the bigger sphere is two times the radius of the smaller sphere.

⇒ Where

For the bigger sphere

⇒ Substitute these values into equation 1

  For the smaller sphere,

⇒ Comparing equation 2 and equation 3

Hence, The volume of the bigger sphere is 8 times larger than the volume of the smaller sphere.

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Answer:

x = 20

Hope you could get an idea from here.

Doubt clarification - use comment section

a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have

[tex]\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}[/tex]

so both conditions are met and f(y) is indeed a PDF.

b) The probability P(Y > 4) is given by the integral,

[tex]\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}[/tex]

c) The mean is given by the integral,

[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy[/tex]

Integrate by parts, with

[tex]u = y \implies du = dy[/tex]

[tex]dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}[/tex]

Then

[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)[/tex]

[tex]\displaystyle \cdots = \int_0^\infty e^{-\frac y4} \, dy[/tex]

[tex]\displaystyle \cdots = -4 \left(\lim_{y\to\infty} e^{-\frac y4} - e^0\right) = \boxed{4}[/tex]

The equation in slope-intercept form that represents the situation is y = 3x + 12

A linear equation is on the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

Let x be the calf's age in month and y be the weight.

A calf weighs 18 lbs. when it is 2 months old, and after 8 months it weighs 36 lbs. Hence it can be represented by:

(2, 18) and (8, 36). The equation is given by:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-18=\frac{36-18}{8-2}(x-2) \\\\y=3x+12[/tex]

The equation in slope-intercept form that represents the situation is y = 3x + 12

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Answer:

17

Step-by-step explanation:

Let the smaller number = x

Let the larger number = y

y = 2x + 8

y - x = 25                Add x to both sides

y = x + 25               Substitute this into the first equation

x + 25 = 2x + 8       Subtract 8 from both sides

x + 25 - 8 = 2x        Combine

x + 17 = 2x               Subtract x from both sides.

17 = 2x - x                Combine

17 = x