evaluate 3c + 6y for c=5 and y=6

Answer:

x > 2

Step-by-step explanation:

-1+6(-1-3x)>-39-2x

-1-6 - 18x > -39 - 2x

-7 - 18x + 2x > -39 - 2x + 2x

-7 - 16x + 7 > -39 + 7

16x / 16 > -32 / 16

x > 2

Answer: the answer is b=9

Step-by-step explanation:

Step 1: Subtract 32 from both sides.

104-32= 72

Step 2: Divide both sides by 8.

72 divided by 8 is 9

therefor the answer is 9

Answer:

x = 20

Hope you could get an idea from here.

Doubt clarification - use comment section

Answer: 40

Step-by-step explanation: yes make me brainlist (its the crown)

Answer:

3 vanilla

Step-by-step explanation:

If 75% of the order equates to 9 chocolate, then the remaining of the dozen would leave three.

Unless there is more than 12 in the order. The question is vague

Answer:

Nick will have to pay $63.56 for the shoes.

Step-by-step explanation:

f the original cost of the shoes is $56.75 and the markup is 12% greater than the original price, the final price would be $63.56.

$56.75 • 0.12 = $6.81

$56.75 + $6.81 = $63.56

$56.75 + 12% = $63.56

Answer:

Nick will have to pay $63.56 for the shoes.

The measure of the exterior angle at vertex D is: D. 54°

Recall:

Thus:

In ΔDEF, (8x−2)º is an exterior angle at vertex D.

m∠E = (3x−8)° (interior angle)

m∠F = (4x+13)° (interior angle)

Therefore:

(8x−2)º = (3x−8)° + (4x+13)°

8x - 2 = 3x - 8 + 4x + 13

8x - 2 = 7x + 5

8x - 7x = 2 + 5

x = 7

Exterior angle at vertex D = (8x−2)º

= 8(7) - 2

= 54º (option D)

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Answer: x = 17

Step-by-step explanation:

Hi there!

First, since we know that these two lines are parallel, 3x+14 is going to be congruent to the supplementary side of 7x-4. Given this, we are able to solve for x as we know that the sum of supplementary angles is 180. All you have to do is set up 3x+14+7x-4=180

Now, just use simple order of operations and combining like terms to isolate x. you will end with 17! :)

Hope this helps!

Answer:

pic?

Step-by-step explanation:

send me the picture please

a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have

[tex]\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}[/tex]

so both conditions are met and f(y) is indeed a PDF.

b) The probability P(Y > 4) is given by the integral,

[tex]\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}[/tex]

c) The mean is given by the integral,

[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy[/tex]

Integrate by parts, with

[tex]u = y \implies du = dy[/tex]

[tex]dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}[/tex]

Then

[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)[/tex]

[tex]\displaystyle \cdots = \int_0^\infty e^{-\frac y4} \, dy[/tex]

[tex]\displaystyle \cdots = -4 \left(\lim_{y\to\infty} e^{-\frac y4} - e^0\right) = \boxed{4}[/tex]

Answer:

To find area of the square you'll need to square one side

(3X)^2 = 81

9(X)^2 = 81

(x)^2 = 81/9

x^2 = 9

X = (9)^1/2

X = 3

Answer:

17

Step-by-step explanation:

Let the smaller number = x

Let the larger number = y

y = 2x + 8

y - x = 25                Add x to both sides

y = x + 25               Substitute this into the first equation

x + 25 = 2x + 8       Subtract 8 from both sides

x + 25 - 8 = 2x        Combine

x + 17 = 2x               Subtract x from both sides.

17 = 2x - x                Combine

17 = x

The volume of the bigger sphere is 8 times larger than the volume of the smaller sphere.

The formula of the volume of a sphere is given below

⇒ Formula:

⇒ Where:

From the question, There are two spheres.

If the radius of the bigger sphere is two times the radius of the smaller sphere.

⇒ Where

For the bigger sphere

⇒ Substitute these values into equation 1

  For the smaller sphere,

⇒ Comparing equation 2 and equation 3

Hence, The volume of the bigger sphere is 8 times larger than the volume of the smaller sphere.

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6x+3y=13

6x+3y-13=13--13

6x+3y-13=0

Answer: (-7,-5)

Step-by-step explanation:

Because when you mark point M and A if you mirror point M and A on the x Axis then you will get (-7,-5)

a) The equation is therefore; x³ + 3x² + 2x = 336

b) Solving for the length, we get the length to be; x = 6.

c) All workings are as shown below;

According to the question;

In essence, the volume of the original prism is;

Since, the original prism had a length, width, and height of consecutive integers, increasing in that order.

a) The equation is therefore;

b) Solving for the length, x is as follows;

By testing values and checking;

c) All workings are as shown above.

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Step-by-step explanation:

Volume=length*width*height

V = (3/2)*(4)*(1/2)

= 12/4 = 3cm^3

Answer:

2.8

Step-by-step explanation:

Answer:

Step-by-step explanation:

2.8 units

Answer:

-90

Step-by-step explanation:

it's right

Answer:

The first one.

Step-by-step explanation:

I took the quiz and got a 100, hope this helps :))

Answer:

y=

x

​

−2

y=−

x

​

−2, x≥0

​

y=−

x−2, x≥0

​

Step-by-step explanation:

The Lateral Surface Area of the cylindrical oil storage tank is [tex]2486.9\text{ sq.ft}[/tex]

The Total Surface Area of the cylindrical oil storage tank is [tex]5526.4\text{ sq.ft}[/tex]

If the height and base radius of the cylindrical oil storage tank are represented by [tex]h[/tex] and [tex]r[/tex] respectively, then

The Lateral Surface Area, also known as the Curved Surface Area, of the cylindrical oil storage tank has the formula

[tex]L=2\pi rh[/tex]

The Total Surface Area of the cylindrical oil storage tank has the formula

[tex]T=2\pi rh+2\pi r^2\\T=2\pi r(h+r)[/tex]

The values for the height and base radius are [tex]18ft[/tex] and [tex]22ft[/tex] respectively.

Calculate the Lateral Surface Area

[tex]L=2\pi rh\\=2\times 3.14\times 22\times 18\\\approx 2486.9\text{ sq.ft}[/tex]

Calculate the Total Surface Area

[tex]T=2\pi r(h+r)\\=2\times 3.14\times22(18+22)\\=5526.4\text{ sq.ft}[/tex]

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[tex]\left(3+\sqrt{-16} \right) \left(5-\sqrt{-25} \right)\\\\=\left(3+\sqrt{-1} \cdot \sqrt{16} \right) \left(5- \sqrt{-1} \cdot \sqrt{25} \right)\\\\=(3+4i)(5-5i)~~~~~~~~~~~~~~;\left[i=\sqrt{-1} \right]\\\\=15-15i + 20i - 20i^2\\\\=15+5i -20(-1)~~~~~~~~~~~~;[i^2 =-1]\\\\=15+5i +20\\\\=35+5i[/tex]

EXPLANATION:

Given that

sin θ = 1/2

We know that

sin 3θ = 3 sin θ - 4 sin³ θ

⇛sin 3θ = 3(1/2)-4(1/2)³

⇛sin 3θ = (3/2)-4(1/8)

⇛sin 3θ = (3/2)-(4/8)

⇛sin 3θ = (3/2)-(1/2)

⇛sin 3θ = (3-1)/2

⇛sin 3θ = 2/2

⇛sin 3θ = 1

and

cos 2θ = cos² θ - sin² θ

⇛cos 2θ = 1 - sin² θ - sin² θ

⇛cos 2θ = 1 - 2 sin² θ

Now,

cos 2θ = 1-2(1/2)²

⇛cos 2θ = 1-2(1/4)

⇛cos 2θ = 1-(2/4)

⇛cos 2θ = 1-(1/2)

⇛cos 2θ = (2-1)/2

⇛cos 2θ = 1/2

Now,

The value of sin 3θ /(1+cos 2θ

⇛1/{1+(1/2)}

⇛1/{(2+1)/2}

⇛1/(3/2)

⇛1×(2/3)

⇛(1×2)/3

⇛2/3

Answer : Hence, the req value of sin 3θ /(1+cos 2θ) is 2/3.

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The equation in slope-intercept form that represents the situation is y = 3x + 12

A linear equation is on the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

Let x be the calf's age in month and y be the weight.

A calf weighs 18 lbs. when it is 2 months old, and after 8 months it weighs 36 lbs. Hence it can be represented by:

(2, 18) and (8, 36). The equation is given by:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-18=\frac{36-18}{8-2}(x-2) \\\\y=3x+12[/tex]

The equation in slope-intercept form that represents the situation is y = 3x + 12

Find out more on linear equation at: brainly.com/question/14323743

Answer:

As per graph the rate of Printer A is 15 pages per minute.

Missing words are:

(a) greater than

(b) greater than

(c) 15

The rate for Printer B is greater than the rate for Printer A because the rate of 25 pages per minute is greater than the rate of 15 pages per minute for Printer A.

or

The printing rate for Printer B is 10 pages more than the rate of printer A because the rate of 25 pages per minute is 10 pages more than the rate 15 pages per minute for Block A

Step-by-step explanation: it's either greater than or more than

From the graph of the printing rate of Printer A, we can see that;

At 1 minute, number of pages printed = 15

At 2 minutes, number of pages printed = 30 minutes

At 3 minutes, number of pages printed = 45

Thus printing rate for printer A is; 15/1 = 30/2 = 45/3 = 15 pages per minutes

Since printer B can print 25 pages per minute, we can conclude that;

The printing rate for Printer B is 10 pages more than the rate of printer A because the rate of 25 pages per minute is 10 pages more than the rate 15 pages per minute for Block A

The temperature of the body after 60 minutes is  60.5° F.

Using the Newton's law of cooling;

T(t) =[tex]Ts + (To - Ts)e^-kt[/tex]

T(t) = temperature at time t

Ts = temperature of the surrounding

To = Temperature of object

t = time taken

k = cooling constant

Now;

[tex]T(t) -Ts=(To - Ts)e^-kt\\45 - 67 = (34 - 67)e^-15k\\-22 = -33e^-15k\\-22/-33 = e^-15k\\0.667 = e^-15k\\ln(0.667) = ln( e^-15k)\\-0.405 = -15k\\k = -0.405/ -15\\k = 0.027[/tex]

At t = 60 min

[tex]T(t) = Ts + (To - Ts)e^-ktT(60) = 67 + (34 - 67)e^-( 0.027*60)\\T(60) = \\67 + (-33)e^-( 0.027 * 60)\\T(60) = \\60.5 F[/tex]

T(60) = 60.5° F

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Answer:

T≈169

Step-by-step explanation:

Enter only the final temperature into the input box.

T_a = 67\hspace{50px}T_0=210

T  

a

​

=67T  

0

​

=210

\text{Write Formula:}

Write Formula:

T=67+(210-67)e^{-kt}

T=67+(210−67)e  

−kt

Plug in givens

\color{blue}{T}=67+143e^{-k\color{green}{t}}

T=67+143e  

−kt

Simplify

\text{Plug in given time and temperature:}

Plug in given time and temperature:

\color{blue}{193}=67+143e^{-k(\color{green}{1.5})}

193=67+143e  

−k(1.5)

Simplify

\text{Solve for }k\text{:}

Solve for k:

193=

193=

\,\,67+143e^{-1.5k}

67+143e  

−1.5k

-67\phantom{=}

−67=

\,\,-67

−67

126=

126=

\,\,143e^{-1.5k}

143e  

−1.5k

\frac{126}{143}=

143

126

​

=

\,\,\frac{143e^{-1.5k}}{143}

143

143e  

−1.5k

​

Divide by 143

0.8811189=

0.8811189=

\,\,e^{-1.5k}

e  

−1.5k

\ln\left(0.8811189\right)=

ln(0.8811189)=

\,\,\ln\left(e^{-1.5k}\right)

ln(e  

−1.5k

)

Take ln of both sides

\ln\left(0.8811189\right)=

ln(0.8811189)=

\,\,-1.5k

−1.5k

\frac{\ln\left(0.8811189\right)}{-1.5}=

−1.5

ln(0.8811189)

​

=

\,\,\frac{-1.5k}{-1.5}

−1.5

−1.5k

​

Divide by -1.5

0.0843751=

0.0843751=

\,\,k

k

k\approx

k≈

\,\,\color{blue}{0.084}

0.084

Round k to nearest thousandth

\text{Complete Formula:}

Complete Formula:

T=67+143e^{-\color{blue}{0.084}t}

T=67+143e  

−0.084t

Plug in k

\text{Find temperature after }\color{green}{4}\text{ minutes:}

Find temperature after 4 minutes:

T=67+143e^{-0.084(\color{green}{4})}

T=67+143e  

−0.084(4)

Plug in time

T=67+143e^{-0.336}

T=67+143e  

−0.336

Multiply

T=169.1911041

T=169.1911041

Plug into the calculator

T\approx 169

T≈169